Migdal et al, Equation (51)

Percentage Accurate: 99.4% → 99.4%
Time: 14.6s
Alternatives: 7
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}

Alternative 1: 99.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}}} \end{array} \]
(FPCore (k n)
 :precision binary64
 (/ 1.0 (/ (sqrt k) (pow (* 2.0 (* PI n)) (+ 0.5 (* k -0.5))))))
double code(double k, double n) {
	return 1.0 / (sqrt(k) / pow((2.0 * (((double) M_PI) * n)), (0.5 + (k * -0.5))));
}
public static double code(double k, double n) {
	return 1.0 / (Math.sqrt(k) / Math.pow((2.0 * (Math.PI * n)), (0.5 + (k * -0.5))));
}
def code(k, n):
	return 1.0 / (math.sqrt(k) / math.pow((2.0 * (math.pi * n)), (0.5 + (k * -0.5))))
function code(k, n)
	return Float64(1.0 / Float64(sqrt(k) / (Float64(2.0 * Float64(pi * n)) ^ Float64(0.5 + Float64(k * -0.5)))))
end
function tmp = code(k, n)
	tmp = 1.0 / (sqrt(k) / ((2.0 * (pi * n)) ^ (0.5 + (k * -0.5))));
end
code[k_, n_] := N[(1.0 / N[(N[Sqrt[k], $MachinePrecision] / N[Power[N[(2.0 * N[(Pi * n), $MachinePrecision]), $MachinePrecision], N[(0.5 + N[(k * -0.5), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}}}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. associate-/r/99.6%

      \[\leadsto \color{blue}{\frac{1}{\frac{\sqrt{k}}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}}} \]
    2. *-commutative99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(\color{blue}{\left(\pi \cdot 2\right)} \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
    3. associate-*r*99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\color{blue}{\left(\pi \cdot \left(2 \cdot n\right)\right)}}^{\left(\frac{1 - k}{2}\right)}}} \]
    4. div-sub99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1}{2} - \frac{k}{2}\right)}}}} \]
    5. metadata-eval99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\color{blue}{0.5} - \frac{k}{2}\right)}}} \]
    6. associate-*r*99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\color{blue}{\left(\left(\pi \cdot 2\right) \cdot n\right)}}^{\left(0.5 - \frac{k}{2}\right)}}} \]
    7. *-commutative99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(\color{blue}{\left(2 \cdot \pi\right)} \cdot n\right)}^{\left(0.5 - \frac{k}{2}\right)}}} \]
    8. associate-*l*99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\color{blue}{\left(2 \cdot \left(\pi \cdot n\right)\right)}}^{\left(0.5 - \frac{k}{2}\right)}}} \]
    9. sub-neg99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\color{blue}{\left(0.5 + \left(-\frac{k}{2}\right)\right)}}}} \]
    10. div-inv99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + \left(-\color{blue}{k \cdot \frac{1}{2}}\right)\right)}}} \]
    11. metadata-eval99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + \left(-k \cdot \color{blue}{0.5}\right)\right)}}} \]
    12. distribute-rgt-neg-in99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + \color{blue}{k \cdot \left(-0.5\right)}\right)}}} \]
    13. metadata-eval99.6%

      \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot \color{blue}{-0.5}\right)}}} \]
  4. Applied egg-rr99.6%

    \[\leadsto \color{blue}{\frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}}}} \]
  5. Final simplification99.6%

    \[\leadsto \frac{1}{\frac{\sqrt{k}}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}}} \]
  6. Add Preprocessing

Alternative 2: 99.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 8 \cdot 10^{-34}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(1 - k\right)}}{k}}\\ \end{array} \end{array} \]
(FPCore (k n)
 :precision binary64
 (if (<= k 8e-34)
   (* (sqrt (/ PI k)) (sqrt (* 2.0 n)))
   (sqrt (/ (pow (* n (* 2.0 PI)) (- 1.0 k)) k))))
double code(double k, double n) {
	double tmp;
	if (k <= 8e-34) {
		tmp = sqrt((((double) M_PI) / k)) * sqrt((2.0 * n));
	} else {
		tmp = sqrt((pow((n * (2.0 * ((double) M_PI))), (1.0 - k)) / k));
	}
	return tmp;
}
public static double code(double k, double n) {
	double tmp;
	if (k <= 8e-34) {
		tmp = Math.sqrt((Math.PI / k)) * Math.sqrt((2.0 * n));
	} else {
		tmp = Math.sqrt((Math.pow((n * (2.0 * Math.PI)), (1.0 - k)) / k));
	}
	return tmp;
}
def code(k, n):
	tmp = 0
	if k <= 8e-34:
		tmp = math.sqrt((math.pi / k)) * math.sqrt((2.0 * n))
	else:
		tmp = math.sqrt((math.pow((n * (2.0 * math.pi)), (1.0 - k)) / k))
	return tmp
function code(k, n)
	tmp = 0.0
	if (k <= 8e-34)
		tmp = Float64(sqrt(Float64(pi / k)) * sqrt(Float64(2.0 * n)));
	else
		tmp = sqrt(Float64((Float64(n * Float64(2.0 * pi)) ^ Float64(1.0 - k)) / k));
	end
	return tmp
end
function tmp_2 = code(k, n)
	tmp = 0.0;
	if (k <= 8e-34)
		tmp = sqrt((pi / k)) * sqrt((2.0 * n));
	else
		tmp = sqrt((((n * (2.0 * pi)) ^ (1.0 - k)) / k));
	end
	tmp_2 = tmp;
end
code[k_, n_] := If[LessEqual[k, 8e-34], N[(N[Sqrt[N[(Pi / k), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[Sqrt[N[(N[Power[N[(n * N[(2.0 * Pi), $MachinePrecision]), $MachinePrecision], N[(1.0 - k), $MachinePrecision]], $MachinePrecision] / k), $MachinePrecision]], $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 8 \cdot 10^{-34}:\\
\;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\

\mathbf{else}:\\
\;\;\;\;\sqrt{\frac{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(1 - k\right)}}{k}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < 7.99999999999999942e-34

    1. Initial program 99.4%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt99.0%

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \cdot \sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
      2. pow299.0%

        \[\leadsto \color{blue}{{\left(\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}\right)}^{2}} \]
    4. Applied egg-rr99.0%

      \[\leadsto \color{blue}{{\left(\frac{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{1 - k}{4}\right)}}{{k}^{0.25}}\right)}^{2}} \]
    5. Taylor expanded in k around 0 69.8%

      \[\leadsto \color{blue}{\sqrt{\frac{n \cdot \pi}{k}} \cdot \sqrt{2}} \]
    6. Step-by-step derivation
      1. *-commutative69.8%

        \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n \cdot \pi}{k}}} \]
      2. associate-/l*69.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-/r/69.8%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{k} \cdot \pi}} \]
    7. Simplified69.8%

      \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n}{k} \cdot \pi}} \]
    8. Step-by-step derivation
      1. sqrt-unprod70.1%

        \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\frac{n}{k} \cdot \pi\right)}} \]
      2. associate-/r/70.1%

        \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-*r/70.1%

        \[\leadsto \sqrt{\color{blue}{\frac{2 \cdot n}{\frac{k}{\pi}}}} \]
      4. div-inv70.0%

        \[\leadsto \sqrt{\color{blue}{\left(2 \cdot n\right) \cdot \frac{1}{\frac{k}{\pi}}}} \]
      5. clear-num70.1%

        \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \color{blue}{\frac{\pi}{k}}} \]
      6. associate-*r*70.1%

        \[\leadsto \sqrt{\color{blue}{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    9. Applied egg-rr70.1%

      \[\leadsto \color{blue}{\sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    10. Step-by-step derivation
      1. pow1/270.1%

        \[\leadsto \color{blue}{{\left(2 \cdot \left(n \cdot \frac{\pi}{k}\right)\right)}^{0.5}} \]
      2. associate-*r*70.1%

        \[\leadsto {\color{blue}{\left(\left(2 \cdot n\right) \cdot \frac{\pi}{k}\right)}}^{0.5} \]
      3. unpow-prod-down99.4%

        \[\leadsto \color{blue}{{\left(2 \cdot n\right)}^{0.5} \cdot {\left(\frac{\pi}{k}\right)}^{0.5}} \]
      4. pow1/299.4%

        \[\leadsto {\left(2 \cdot n\right)}^{0.5} \cdot \color{blue}{\sqrt{\frac{\pi}{k}}} \]
    11. Applied egg-rr99.4%

      \[\leadsto \color{blue}{{\left(2 \cdot n\right)}^{0.5} \cdot \sqrt{\frac{\pi}{k}}} \]
    12. Step-by-step derivation
      1. *-commutative99.4%

        \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot {\left(2 \cdot n\right)}^{0.5}} \]
      2. unpow1/299.4%

        \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \color{blue}{\sqrt{2 \cdot n}} \]
      3. *-commutative99.4%

        \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{\color{blue}{n \cdot 2}} \]
    13. Simplified99.4%

      \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{n \cdot 2}} \]

    if 7.99999999999999942e-34 < k

    1. Initial program 99.6%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Add Preprocessing
    3. Applied egg-rr99.0%

      \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
    4. Step-by-step derivation
      1. Simplified99.0%

        \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\mathsf{fma}\left(2, k \cdot -0.5, 1\right)\right)}}{k}}} \]
      2. Taylor expanded in n around 0 98.4%

        \[\leadsto \color{blue}{\sqrt{\frac{e^{\left(1 + -1 \cdot k\right) \cdot \left(\log n + \log \left(2 \cdot \pi\right)\right)}}{k}}} \]
      3. Step-by-step derivation
        1. exp-prod98.3%

          \[\leadsto \sqrt{\frac{\color{blue}{{\left(e^{1 + -1 \cdot k}\right)}^{\left(\log n + \log \left(2 \cdot \pi\right)\right)}}}{k}} \]
        2. remove-double-neg98.3%

          \[\leadsto \sqrt{\frac{{\left(e^{1 + -1 \cdot k}\right)}^{\left(\color{blue}{\left(-\left(-\log n\right)\right)} + \log \left(2 \cdot \pi\right)\right)}}{k}} \]
        3. log-rec98.3%

          \[\leadsto \sqrt{\frac{{\left(e^{1 + -1 \cdot k}\right)}^{\left(\left(-\color{blue}{\log \left(\frac{1}{n}\right)}\right) + \log \left(2 \cdot \pi\right)\right)}}{k}} \]
        4. mul-1-neg98.3%

          \[\leadsto \sqrt{\frac{{\left(e^{1 + -1 \cdot k}\right)}^{\left(\color{blue}{-1 \cdot \log \left(\frac{1}{n}\right)} + \log \left(2 \cdot \pi\right)\right)}}{k}} \]
        5. +-commutative98.3%

          \[\leadsto \sqrt{\frac{{\left(e^{1 + -1 \cdot k}\right)}^{\color{blue}{\left(\log \left(2 \cdot \pi\right) + -1 \cdot \log \left(\frac{1}{n}\right)\right)}}}{k}} \]
        6. exp-prod98.4%

          \[\leadsto \sqrt{\frac{\color{blue}{e^{\left(1 + -1 \cdot k\right) \cdot \left(\log \left(2 \cdot \pi\right) + -1 \cdot \log \left(\frac{1}{n}\right)\right)}}}{k}} \]
      4. Simplified99.0%

        \[\leadsto \color{blue}{\sqrt{\frac{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(1 - k\right)}}{k}}} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification99.2%

      \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 8 \cdot 10^{-34}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(1 - k\right)}}{k}}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 3: 53.2% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 1.45 \cdot 10^{+186}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;{\left({\left(n \cdot \frac{\pi}{k}\right)}^{2} \cdot 4\right)}^{0.25}\\ \end{array} \end{array} \]
    (FPCore (k n)
     :precision binary64
     (if (<= k 1.45e+186)
       (* (sqrt (/ PI k)) (sqrt (* 2.0 n)))
       (pow (* (pow (* n (/ PI k)) 2.0) 4.0) 0.25)))
    double code(double k, double n) {
    	double tmp;
    	if (k <= 1.45e+186) {
    		tmp = sqrt((((double) M_PI) / k)) * sqrt((2.0 * n));
    	} else {
    		tmp = pow((pow((n * (((double) M_PI) / k)), 2.0) * 4.0), 0.25);
    	}
    	return tmp;
    }
    
    public static double code(double k, double n) {
    	double tmp;
    	if (k <= 1.45e+186) {
    		tmp = Math.sqrt((Math.PI / k)) * Math.sqrt((2.0 * n));
    	} else {
    		tmp = Math.pow((Math.pow((n * (Math.PI / k)), 2.0) * 4.0), 0.25);
    	}
    	return tmp;
    }
    
    def code(k, n):
    	tmp = 0
    	if k <= 1.45e+186:
    		tmp = math.sqrt((math.pi / k)) * math.sqrt((2.0 * n))
    	else:
    		tmp = math.pow((math.pow((n * (math.pi / k)), 2.0) * 4.0), 0.25)
    	return tmp
    
    function code(k, n)
    	tmp = 0.0
    	if (k <= 1.45e+186)
    		tmp = Float64(sqrt(Float64(pi / k)) * sqrt(Float64(2.0 * n)));
    	else
    		tmp = Float64((Float64(n * Float64(pi / k)) ^ 2.0) * 4.0) ^ 0.25;
    	end
    	return tmp
    end
    
    function tmp_2 = code(k, n)
    	tmp = 0.0;
    	if (k <= 1.45e+186)
    		tmp = sqrt((pi / k)) * sqrt((2.0 * n));
    	else
    		tmp = (((n * (pi / k)) ^ 2.0) * 4.0) ^ 0.25;
    	end
    	tmp_2 = tmp;
    end
    
    code[k_, n_] := If[LessEqual[k, 1.45e+186], N[(N[Sqrt[N[(Pi / k), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[Power[N[(N[Power[N[(n * N[(Pi / k), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] * 4.0), $MachinePrecision], 0.25], $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;k \leq 1.45 \cdot 10^{+186}:\\
    \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\
    
    \mathbf{else}:\\
    \;\;\;\;{\left({\left(n \cdot \frac{\pi}{k}\right)}^{2} \cdot 4\right)}^{0.25}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if k < 1.45e186

      1. Initial program 99.4%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. add-sqr-sqrt99.1%

          \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \cdot \sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
        2. pow299.1%

          \[\leadsto \color{blue}{{\left(\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}\right)}^{2}} \]
      4. Applied egg-rr99.1%

        \[\leadsto \color{blue}{{\left(\frac{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{1 - k}{4}\right)}}{{k}^{0.25}}\right)}^{2}} \]
      5. Taylor expanded in k around 0 45.8%

        \[\leadsto \color{blue}{\sqrt{\frac{n \cdot \pi}{k}} \cdot \sqrt{2}} \]
      6. Step-by-step derivation
        1. *-commutative45.8%

          \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n \cdot \pi}{k}}} \]
        2. associate-/l*45.8%

          \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
        3. associate-/r/45.8%

          \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{k} \cdot \pi}} \]
      7. Simplified45.8%

        \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n}{k} \cdot \pi}} \]
      8. Step-by-step derivation
        1. sqrt-unprod45.9%

          \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\frac{n}{k} \cdot \pi\right)}} \]
        2. associate-/r/45.9%

          \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
        3. associate-*r/45.9%

          \[\leadsto \sqrt{\color{blue}{\frac{2 \cdot n}{\frac{k}{\pi}}}} \]
        4. div-inv45.9%

          \[\leadsto \sqrt{\color{blue}{\left(2 \cdot n\right) \cdot \frac{1}{\frac{k}{\pi}}}} \]
        5. clear-num45.9%

          \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \color{blue}{\frac{\pi}{k}}} \]
        6. associate-*r*45.9%

          \[\leadsto \sqrt{\color{blue}{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
      9. Applied egg-rr45.9%

        \[\leadsto \color{blue}{\sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
      10. Step-by-step derivation
        1. pow1/245.9%

          \[\leadsto \color{blue}{{\left(2 \cdot \left(n \cdot \frac{\pi}{k}\right)\right)}^{0.5}} \]
        2. associate-*r*45.9%

          \[\leadsto {\color{blue}{\left(\left(2 \cdot n\right) \cdot \frac{\pi}{k}\right)}}^{0.5} \]
        3. unpow-prod-down62.4%

          \[\leadsto \color{blue}{{\left(2 \cdot n\right)}^{0.5} \cdot {\left(\frac{\pi}{k}\right)}^{0.5}} \]
        4. pow1/262.4%

          \[\leadsto {\left(2 \cdot n\right)}^{0.5} \cdot \color{blue}{\sqrt{\frac{\pi}{k}}} \]
      11. Applied egg-rr62.4%

        \[\leadsto \color{blue}{{\left(2 \cdot n\right)}^{0.5} \cdot \sqrt{\frac{\pi}{k}}} \]
      12. Step-by-step derivation
        1. *-commutative62.4%

          \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot {\left(2 \cdot n\right)}^{0.5}} \]
        2. unpow1/262.4%

          \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \color{blue}{\sqrt{2 \cdot n}} \]
        3. *-commutative62.4%

          \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{\color{blue}{n \cdot 2}} \]
      13. Simplified62.4%

        \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{n \cdot 2}} \]

      if 1.45e186 < k

      1. Initial program 100.0%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Add Preprocessing
      3. Step-by-step derivation
        1. add-sqr-sqrt100.0%

          \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \cdot \sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
        2. pow2100.0%

          \[\leadsto \color{blue}{{\left(\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}\right)}^{2}} \]
      4. Applied egg-rr100.0%

        \[\leadsto \color{blue}{{\left(\frac{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{1 - k}{4}\right)}}{{k}^{0.25}}\right)}^{2}} \]
      5. Taylor expanded in k around 0 2.8%

        \[\leadsto \color{blue}{\sqrt{\frac{n \cdot \pi}{k}} \cdot \sqrt{2}} \]
      6. Step-by-step derivation
        1. *-commutative2.8%

          \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n \cdot \pi}{k}}} \]
        2. associate-/l*2.8%

          \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
        3. associate-/r/2.8%

          \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{k} \cdot \pi}} \]
      7. Simplified2.8%

        \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n}{k} \cdot \pi}} \]
      8. Step-by-step derivation
        1. sqrt-unprod2.8%

          \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\frac{n}{k} \cdot \pi\right)}} \]
        2. associate-/r/2.8%

          \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
        3. pow1/22.8%

          \[\leadsto \color{blue}{{\left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)}^{0.5}} \]
        4. metadata-eval2.8%

          \[\leadsto {\left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)}^{\color{blue}{\left(0.25 + 0.25\right)}} \]
        5. pow-prod-up2.8%

          \[\leadsto \color{blue}{{\left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)}^{0.25} \cdot {\left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)}^{0.25}} \]
        6. pow-prod-down17.2%

          \[\leadsto \color{blue}{{\left(\left(2 \cdot \frac{n}{\frac{k}{\pi}}\right) \cdot \left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)\right)}^{0.25}} \]
        7. associate-/r/17.2%

          \[\leadsto {\left(\left(2 \cdot \color{blue}{\left(\frac{n}{k} \cdot \pi\right)}\right) \cdot \left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)\right)}^{0.25} \]
        8. *-commutative17.2%

          \[\leadsto {\left(\color{blue}{\left(\left(\frac{n}{k} \cdot \pi\right) \cdot 2\right)} \cdot \left(2 \cdot \frac{n}{\frac{k}{\pi}}\right)\right)}^{0.25} \]
        9. associate-/r/17.2%

          \[\leadsto {\left(\left(\left(\frac{n}{k} \cdot \pi\right) \cdot 2\right) \cdot \left(2 \cdot \color{blue}{\left(\frac{n}{k} \cdot \pi\right)}\right)\right)}^{0.25} \]
        10. *-commutative17.2%

          \[\leadsto {\left(\left(\left(\frac{n}{k} \cdot \pi\right) \cdot 2\right) \cdot \color{blue}{\left(\left(\frac{n}{k} \cdot \pi\right) \cdot 2\right)}\right)}^{0.25} \]
        11. swap-sqr17.2%

          \[\leadsto {\color{blue}{\left(\left(\left(\frac{n}{k} \cdot \pi\right) \cdot \left(\frac{n}{k} \cdot \pi\right)\right) \cdot \left(2 \cdot 2\right)\right)}}^{0.25} \]
        12. pow217.2%

          \[\leadsto {\left(\color{blue}{{\left(\frac{n}{k} \cdot \pi\right)}^{2}} \cdot \left(2 \cdot 2\right)\right)}^{0.25} \]
        13. associate-/r/17.2%

          \[\leadsto {\left({\color{blue}{\left(\frac{n}{\frac{k}{\pi}}\right)}}^{2} \cdot \left(2 \cdot 2\right)\right)}^{0.25} \]
        14. div-inv17.2%

          \[\leadsto {\left({\color{blue}{\left(n \cdot \frac{1}{\frac{k}{\pi}}\right)}}^{2} \cdot \left(2 \cdot 2\right)\right)}^{0.25} \]
        15. clear-num17.2%

          \[\leadsto {\left({\left(n \cdot \color{blue}{\frac{\pi}{k}}\right)}^{2} \cdot \left(2 \cdot 2\right)\right)}^{0.25} \]
        16. metadata-eval17.2%

          \[\leadsto {\left({\left(n \cdot \frac{\pi}{k}\right)}^{2} \cdot \color{blue}{4}\right)}^{0.25} \]
      9. Applied egg-rr17.2%

        \[\leadsto \color{blue}{{\left({\left(n \cdot \frac{\pi}{k}\right)}^{2} \cdot 4\right)}^{0.25}} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification53.0%

      \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 1.45 \cdot 10^{+186}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;{\left({\left(n \cdot \frac{\pi}{k}\right)}^{2} \cdot 4\right)}^{0.25}\\ \end{array} \]
    5. Add Preprocessing

    Alternative 4: 99.4% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}} \end{array} \]
    (FPCore (k n)
     :precision binary64
     (/ (pow (* PI (* 2.0 n)) (- 0.5 (/ k 2.0))) (sqrt k)))
    double code(double k, double n) {
    	return pow((((double) M_PI) * (2.0 * n)), (0.5 - (k / 2.0))) / sqrt(k);
    }
    
    public static double code(double k, double n) {
    	return Math.pow((Math.PI * (2.0 * n)), (0.5 - (k / 2.0))) / Math.sqrt(k);
    }
    
    def code(k, n):
    	return math.pow((math.pi * (2.0 * n)), (0.5 - (k / 2.0))) / math.sqrt(k)
    
    function code(k, n)
    	return Float64((Float64(pi * Float64(2.0 * n)) ^ Float64(0.5 - Float64(k / 2.0))) / sqrt(k))
    end
    
    function tmp = code(k, n)
    	tmp = ((pi * (2.0 * n)) ^ (0.5 - (k / 2.0))) / sqrt(k);
    end
    
    code[k_, n_] := N[(N[Power[N[(Pi * N[(2.0 * n), $MachinePrecision]), $MachinePrecision], N[(0.5 - N[(k / 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}}
    \end{array}
    
    Derivation
    1. Initial program 99.5%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Step-by-step derivation
      1. associate-*l/99.6%

        \[\leadsto \color{blue}{\frac{1 \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}{\sqrt{k}}} \]
      2. *-lft-identity99.6%

        \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}}{\sqrt{k}} \]
      3. sqr-pow99.4%

        \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\frac{1 - k}{2}}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
      4. pow-sqr99.6%

        \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
      5. *-commutative99.6%

        \[\leadsto \frac{{\left(\color{blue}{\left(\pi \cdot 2\right)} \cdot n\right)}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}{\sqrt{k}} \]
      6. associate-*l*99.6%

        \[\leadsto \frac{{\color{blue}{\left(\pi \cdot \left(2 \cdot n\right)\right)}}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}{\sqrt{k}} \]
      7. associate-*r/99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{2 \cdot \frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
      8. *-commutative99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\frac{\color{blue}{\frac{1 - k}{2} \cdot 2}}{2}\right)}}{\sqrt{k}} \]
      9. associate-/l*99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{\frac{1 - k}{2}}{\frac{2}{2}}\right)}}}{\sqrt{k}} \]
      10. metadata-eval99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\frac{\frac{1 - k}{2}}{\color{blue}{1}}\right)}}{\sqrt{k}} \]
      11. /-rgt-identity99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1 - k}{2}\right)}}}{\sqrt{k}} \]
      12. div-sub99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1}{2} - \frac{k}{2}\right)}}}{\sqrt{k}} \]
      13. metadata-eval99.6%

        \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\color{blue}{0.5} - \frac{k}{2}\right)}}{\sqrt{k}} \]
    3. Simplified99.6%

      \[\leadsto \color{blue}{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}}} \]
    4. Add Preprocessing
    5. Final simplification99.6%

      \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}} \]
    6. Add Preprocessing

    Alternative 5: 50.7% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n} \end{array} \]
    (FPCore (k n) :precision binary64 (* (sqrt (/ PI k)) (sqrt (* 2.0 n))))
    double code(double k, double n) {
    	return sqrt((((double) M_PI) / k)) * sqrt((2.0 * n));
    }
    
    public static double code(double k, double n) {
    	return Math.sqrt((Math.PI / k)) * Math.sqrt((2.0 * n));
    }
    
    def code(k, n):
    	return math.sqrt((math.pi / k)) * math.sqrt((2.0 * n))
    
    function code(k, n)
    	return Float64(sqrt(Float64(pi / k)) * sqrt(Float64(2.0 * n)))
    end
    
    function tmp = code(k, n)
    	tmp = sqrt((pi / k)) * sqrt((2.0 * n));
    end
    
    code[k_, n_] := N[(N[Sqrt[N[(Pi / k), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}
    \end{array}
    
    Derivation
    1. Initial program 99.5%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt99.3%

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \cdot \sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
      2. pow299.3%

        \[\leadsto \color{blue}{{\left(\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}\right)}^{2}} \]
    4. Applied egg-rr99.3%

      \[\leadsto \color{blue}{{\left(\frac{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{1 - k}{4}\right)}}{{k}^{0.25}}\right)}^{2}} \]
    5. Taylor expanded in k around 0 36.9%

      \[\leadsto \color{blue}{\sqrt{\frac{n \cdot \pi}{k}} \cdot \sqrt{2}} \]
    6. Step-by-step derivation
      1. *-commutative36.9%

        \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n \cdot \pi}{k}}} \]
      2. associate-/l*36.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-/r/36.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{k} \cdot \pi}} \]
    7. Simplified36.9%

      \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n}{k} \cdot \pi}} \]
    8. Step-by-step derivation
      1. sqrt-unprod37.0%

        \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\frac{n}{k} \cdot \pi\right)}} \]
      2. associate-/r/37.0%

        \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-*r/37.0%

        \[\leadsto \sqrt{\color{blue}{\frac{2 \cdot n}{\frac{k}{\pi}}}} \]
      4. div-inv37.0%

        \[\leadsto \sqrt{\color{blue}{\left(2 \cdot n\right) \cdot \frac{1}{\frac{k}{\pi}}}} \]
      5. clear-num37.0%

        \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \color{blue}{\frac{\pi}{k}}} \]
      6. associate-*r*37.0%

        \[\leadsto \sqrt{\color{blue}{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    9. Applied egg-rr37.0%

      \[\leadsto \color{blue}{\sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    10. Step-by-step derivation
      1. pow1/237.0%

        \[\leadsto \color{blue}{{\left(2 \cdot \left(n \cdot \frac{\pi}{k}\right)\right)}^{0.5}} \]
      2. associate-*r*37.0%

        \[\leadsto {\color{blue}{\left(\left(2 \cdot n\right) \cdot \frac{\pi}{k}\right)}}^{0.5} \]
      3. unpow-prod-down50.1%

        \[\leadsto \color{blue}{{\left(2 \cdot n\right)}^{0.5} \cdot {\left(\frac{\pi}{k}\right)}^{0.5}} \]
      4. pow1/250.1%

        \[\leadsto {\left(2 \cdot n\right)}^{0.5} \cdot \color{blue}{\sqrt{\frac{\pi}{k}}} \]
    11. Applied egg-rr50.1%

      \[\leadsto \color{blue}{{\left(2 \cdot n\right)}^{0.5} \cdot \sqrt{\frac{\pi}{k}}} \]
    12. Step-by-step derivation
      1. *-commutative50.1%

        \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot {\left(2 \cdot n\right)}^{0.5}} \]
      2. unpow1/250.1%

        \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \color{blue}{\sqrt{2 \cdot n}} \]
      3. *-commutative50.1%

        \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{\color{blue}{n \cdot 2}} \]
    13. Simplified50.1%

      \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{n \cdot 2}} \]
    14. Final simplification50.1%

      \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n} \]
    15. Add Preprocessing

    Alternative 6: 38.6% accurate, 2.0× speedup?

    \[\begin{array}{l} \\ \sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)} \end{array} \]
    (FPCore (k n) :precision binary64 (sqrt (* 2.0 (* n (/ PI k)))))
    double code(double k, double n) {
    	return sqrt((2.0 * (n * (((double) M_PI) / k))));
    }
    
    public static double code(double k, double n) {
    	return Math.sqrt((2.0 * (n * (Math.PI / k))));
    }
    
    def code(k, n):
    	return math.sqrt((2.0 * (n * (math.pi / k))))
    
    function code(k, n)
    	return sqrt(Float64(2.0 * Float64(n * Float64(pi / k))))
    end
    
    function tmp = code(k, n)
    	tmp = sqrt((2.0 * (n * (pi / k))));
    end
    
    code[k_, n_] := N[Sqrt[N[(2.0 * N[(n * N[(Pi / k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}
    \end{array}
    
    Derivation
    1. Initial program 99.5%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt99.3%

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \cdot \sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
      2. pow299.3%

        \[\leadsto \color{blue}{{\left(\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}\right)}^{2}} \]
    4. Applied egg-rr99.3%

      \[\leadsto \color{blue}{{\left(\frac{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{1 - k}{4}\right)}}{{k}^{0.25}}\right)}^{2}} \]
    5. Taylor expanded in k around 0 36.9%

      \[\leadsto \color{blue}{\sqrt{\frac{n \cdot \pi}{k}} \cdot \sqrt{2}} \]
    6. Step-by-step derivation
      1. *-commutative36.9%

        \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n \cdot \pi}{k}}} \]
      2. associate-/l*36.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-/r/36.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{k} \cdot \pi}} \]
    7. Simplified36.9%

      \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n}{k} \cdot \pi}} \]
    8. Step-by-step derivation
      1. sqrt-unprod37.0%

        \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\frac{n}{k} \cdot \pi\right)}} \]
      2. associate-/r/37.0%

        \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-*r/37.0%

        \[\leadsto \sqrt{\color{blue}{\frac{2 \cdot n}{\frac{k}{\pi}}}} \]
      4. div-inv37.0%

        \[\leadsto \sqrt{\color{blue}{\left(2 \cdot n\right) \cdot \frac{1}{\frac{k}{\pi}}}} \]
      5. clear-num37.0%

        \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \color{blue}{\frac{\pi}{k}}} \]
      6. associate-*r*37.0%

        \[\leadsto \sqrt{\color{blue}{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    9. Applied egg-rr37.0%

      \[\leadsto \color{blue}{\sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    10. Final simplification37.0%

      \[\leadsto \sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)} \]
    11. Add Preprocessing

    Alternative 7: 38.6% accurate, 2.0× speedup?

    \[\begin{array}{l} \\ \sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}} \end{array} \]
    (FPCore (k n) :precision binary64 (sqrt (* 2.0 (/ n (/ k PI)))))
    double code(double k, double n) {
    	return sqrt((2.0 * (n / (k / ((double) M_PI)))));
    }
    
    public static double code(double k, double n) {
    	return Math.sqrt((2.0 * (n / (k / Math.PI))));
    }
    
    def code(k, n):
    	return math.sqrt((2.0 * (n / (k / math.pi))))
    
    function code(k, n)
    	return sqrt(Float64(2.0 * Float64(n / Float64(k / pi))))
    end
    
    function tmp = code(k, n)
    	tmp = sqrt((2.0 * (n / (k / pi))));
    end
    
    code[k_, n_] := N[Sqrt[N[(2.0 * N[(n / N[(k / Pi), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
    
    \begin{array}{l}
    
    \\
    \sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}}
    \end{array}
    
    Derivation
    1. Initial program 99.5%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Add Preprocessing
    3. Step-by-step derivation
      1. add-sqr-sqrt99.3%

        \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}} \cdot \sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}} \]
      2. pow299.3%

        \[\leadsto \color{blue}{{\left(\sqrt{\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}\right)}^{2}} \]
    4. Applied egg-rr99.3%

      \[\leadsto \color{blue}{{\left(\frac{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{1 - k}{4}\right)}}{{k}^{0.25}}\right)}^{2}} \]
    5. Taylor expanded in k around 0 36.9%

      \[\leadsto \color{blue}{\sqrt{\frac{n \cdot \pi}{k}} \cdot \sqrt{2}} \]
    6. Step-by-step derivation
      1. *-commutative36.9%

        \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n \cdot \pi}{k}}} \]
      2. associate-/l*36.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-/r/36.9%

        \[\leadsto \sqrt{2} \cdot \sqrt{\color{blue}{\frac{n}{k} \cdot \pi}} \]
    7. Simplified36.9%

      \[\leadsto \color{blue}{\sqrt{2} \cdot \sqrt{\frac{n}{k} \cdot \pi}} \]
    8. Step-by-step derivation
      1. sqrt-unprod37.0%

        \[\leadsto \color{blue}{\sqrt{2 \cdot \left(\frac{n}{k} \cdot \pi\right)}} \]
      2. associate-/r/37.0%

        \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
      3. associate-*r/37.0%

        \[\leadsto \sqrt{\color{blue}{\frac{2 \cdot n}{\frac{k}{\pi}}}} \]
      4. div-inv37.0%

        \[\leadsto \sqrt{\color{blue}{\left(2 \cdot n\right) \cdot \frac{1}{\frac{k}{\pi}}}} \]
      5. clear-num37.0%

        \[\leadsto \sqrt{\left(2 \cdot n\right) \cdot \color{blue}{\frac{\pi}{k}}} \]
      6. associate-*r*37.0%

        \[\leadsto \sqrt{\color{blue}{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    9. Applied egg-rr37.0%

      \[\leadsto \color{blue}{\sqrt{2 \cdot \left(n \cdot \frac{\pi}{k}\right)}} \]
    10. Taylor expanded in n around 0 37.0%

      \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n \cdot \pi}{k}}} \]
    11. Step-by-step derivation
      1. associate-/l*37.0%

        \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
    12. Simplified37.0%

      \[\leadsto \sqrt{2 \cdot \color{blue}{\frac{n}{\frac{k}{\pi}}}} \]
    13. Final simplification37.0%

      \[\leadsto \sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}} \]
    14. Add Preprocessing

    Reproduce

    ?
    herbie shell --seed 2024024 
    (FPCore (k n)
      :name "Migdal et al, Equation (51)"
      :precision binary64
      (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))