Migdal et al, Equation (51)

Percentage Accurate: 99.4% → 99.4%
Time: 19.1s
Alternatives: 11
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 99.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return (1.0 / sqrt(k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return (1.0 / Math.sqrt(k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return (1.0 / math.sqrt(k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(Float64(1.0 / sqrt(k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = (1.0 / sqrt(k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[(1.0 / N[Sqrt[k], $MachinePrecision]), $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}

Alternative 1: 99.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{1}{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \end{array} \]
(FPCore (k n)
 :precision binary64
 (* (sqrt (/ 1.0 k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))
double code(double k, double n) {
	return sqrt((1.0 / k)) * pow(((2.0 * ((double) M_PI)) * n), ((1.0 - k) / 2.0));
}
public static double code(double k, double n) {
	return Math.sqrt((1.0 / k)) * Math.pow(((2.0 * Math.PI) * n), ((1.0 - k) / 2.0));
}
def code(k, n):
	return math.sqrt((1.0 / k)) * math.pow(((2.0 * math.pi) * n), ((1.0 - k) / 2.0))
function code(k, n)
	return Float64(sqrt(Float64(1.0 / k)) * (Float64(Float64(2.0 * pi) * n) ^ Float64(Float64(1.0 - k) / 2.0)))
end
function tmp = code(k, n)
	tmp = sqrt((1.0 / k)) * (((2.0 * pi) * n) ^ ((1.0 - k) / 2.0));
end
code[k_, n_] := N[(N[Sqrt[N[(1.0 / k), $MachinePrecision]], $MachinePrecision] * N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(N[(1.0 - k), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}
\end{array}
Derivation
  1. Initial program 99.5%

    \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  2. Add Preprocessing
  3. Step-by-step derivation
    1. add-sqr-sqrt99.4%

      \[\leadsto \color{blue}{\left(\sqrt{\frac{1}{\sqrt{k}}} \cdot \sqrt{\frac{1}{\sqrt{k}}}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. sqrt-unprod99.5%

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\sqrt{k}} \cdot \frac{1}{\sqrt{k}}}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    3. frac-times99.5%

      \[\leadsto \sqrt{\color{blue}{\frac{1 \cdot 1}{\sqrt{k} \cdot \sqrt{k}}}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    4. metadata-eval99.5%

      \[\leadsto \sqrt{\frac{\color{blue}{1}}{\sqrt{k} \cdot \sqrt{k}}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    5. add-sqr-sqrt99.5%

      \[\leadsto \sqrt{\frac{1}{\color{blue}{k}}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  4. Applied egg-rr99.5%

    \[\leadsto \color{blue}{\sqrt{\frac{1}{k}}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  5. Final simplification99.5%

    \[\leadsto \sqrt{\frac{1}{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
  6. Add Preprocessing

Alternative 2: 99.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 4.6 \cdot 10^{-67}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sqrt{\frac{k}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(1 - k\right)}}}}\\ \end{array} \end{array} \]
(FPCore (k n)
 :precision binary64
 (if (<= k 4.6e-67)
   (* (sqrt (/ PI k)) (sqrt (* 2.0 n)))
   (/ 1.0 (sqrt (/ k (pow (* (* 2.0 PI) n) (- 1.0 k)))))))
double code(double k, double n) {
	double tmp;
	if (k <= 4.6e-67) {
		tmp = sqrt((((double) M_PI) / k)) * sqrt((2.0 * n));
	} else {
		tmp = 1.0 / sqrt((k / pow(((2.0 * ((double) M_PI)) * n), (1.0 - k))));
	}
	return tmp;
}
public static double code(double k, double n) {
	double tmp;
	if (k <= 4.6e-67) {
		tmp = Math.sqrt((Math.PI / k)) * Math.sqrt((2.0 * n));
	} else {
		tmp = 1.0 / Math.sqrt((k / Math.pow(((2.0 * Math.PI) * n), (1.0 - k))));
	}
	return tmp;
}
def code(k, n):
	tmp = 0
	if k <= 4.6e-67:
		tmp = math.sqrt((math.pi / k)) * math.sqrt((2.0 * n))
	else:
		tmp = 1.0 / math.sqrt((k / math.pow(((2.0 * math.pi) * n), (1.0 - k))))
	return tmp
function code(k, n)
	tmp = 0.0
	if (k <= 4.6e-67)
		tmp = Float64(sqrt(Float64(pi / k)) * sqrt(Float64(2.0 * n)));
	else
		tmp = Float64(1.0 / sqrt(Float64(k / (Float64(Float64(2.0 * pi) * n) ^ Float64(1.0 - k)))));
	end
	return tmp
end
function tmp_2 = code(k, n)
	tmp = 0.0;
	if (k <= 4.6e-67)
		tmp = sqrt((pi / k)) * sqrt((2.0 * n));
	else
		tmp = 1.0 / sqrt((k / (((2.0 * pi) * n) ^ (1.0 - k))));
	end
	tmp_2 = tmp;
end
code[k_, n_] := If[LessEqual[k, 4.6e-67], N[(N[Sqrt[N[(Pi / k), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(1.0 / N[Sqrt[N[(k / N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(1.0 - k), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 4.6 \cdot 10^{-67}:\\
\;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{\sqrt{\frac{k}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(1 - k\right)}}}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < 4.6000000000000001e-67

    1. Initial program 99.3%

      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
    2. Add Preprocessing
    3. Applied egg-rr74.9%

      \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
    4. Step-by-step derivation
      1. Simplified75.0%

        \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
      2. Taylor expanded in k around 0 75.0%

        \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
      3. Step-by-step derivation
        1. associate-*r*75.0%

          \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
        2. *-commutative75.0%

          \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
        3. associate-*l*75.0%

          \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
      4. Simplified75.0%

        \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
      5. Step-by-step derivation
        1. associate-*r*75.0%

          \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right) \cdot \pi}}{k}} \]
        2. associate-*r/75.0%

          \[\leadsto \sqrt{\color{blue}{\left(n \cdot 2\right) \cdot \frac{\pi}{k}}} \]
        3. sqrt-prod99.5%

          \[\leadsto \color{blue}{\sqrt{n \cdot 2} \cdot \sqrt{\frac{\pi}{k}}} \]
        4. *-commutative99.5%

          \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{n \cdot 2}} \]
        5. *-commutative99.5%

          \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{\color{blue}{2 \cdot n}} \]
      6. Applied egg-rr99.5%

        \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}} \]

      if 4.6000000000000001e-67 < k

      1. Initial program 99.6%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Step-by-step derivation
        1. associate-*l/99.6%

          \[\leadsto \color{blue}{\frac{1 \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}{\sqrt{k}}} \]
        2. *-lft-identity99.6%

          \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}}{\sqrt{k}} \]
        3. sqr-pow98.9%

          \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\frac{1 - k}{2}}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
        4. pow-sqr99.6%

          \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
        5. *-commutative99.6%

          \[\leadsto \frac{{\left(\color{blue}{\left(\pi \cdot 2\right)} \cdot n\right)}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}{\sqrt{k}} \]
        6. associate-*l*99.6%

          \[\leadsto \frac{{\color{blue}{\left(\pi \cdot \left(2 \cdot n\right)\right)}}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}{\sqrt{k}} \]
        7. associate-*r/99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{2 \cdot \frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
        8. *-commutative99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\frac{\color{blue}{\frac{1 - k}{2} \cdot 2}}{2}\right)}}{\sqrt{k}} \]
        9. associate-/l*99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{\frac{1 - k}{2}}{\frac{2}{2}}\right)}}}{\sqrt{k}} \]
        10. metadata-eval99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\frac{\frac{1 - k}{2}}{\color{blue}{1}}\right)}}{\sqrt{k}} \]
        11. /-rgt-identity99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1 - k}{2}\right)}}}{\sqrt{k}} \]
        12. div-sub99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1}{2} - \frac{k}{2}\right)}}}{\sqrt{k}} \]
        13. metadata-eval99.6%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\color{blue}{0.5} - \frac{k}{2}\right)}}{\sqrt{k}} \]
      3. Simplified99.6%

        \[\leadsto \color{blue}{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}}} \]
      4. Add Preprocessing
      5. Step-by-step derivation
        1. div-inv99.6%

          \[\leadsto \color{blue}{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)} \cdot \frac{1}{\sqrt{k}}} \]
        2. associate-*r*99.6%

          \[\leadsto {\color{blue}{\left(\left(\pi \cdot 2\right) \cdot n\right)}}^{\left(0.5 - \frac{k}{2}\right)} \cdot \frac{1}{\sqrt{k}} \]
        3. *-commutative99.6%

          \[\leadsto {\left(\color{blue}{\left(2 \cdot \pi\right)} \cdot n\right)}^{\left(0.5 - \frac{k}{2}\right)} \cdot \frac{1}{\sqrt{k}} \]
        4. associate-*l*99.6%

          \[\leadsto {\color{blue}{\left(2 \cdot \left(\pi \cdot n\right)\right)}}^{\left(0.5 - \frac{k}{2}\right)} \cdot \frac{1}{\sqrt{k}} \]
        5. sub-neg99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\color{blue}{\left(0.5 + \left(-\frac{k}{2}\right)\right)}} \cdot \frac{1}{\sqrt{k}} \]
        6. div-inv99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + \left(-\color{blue}{k \cdot \frac{1}{2}}\right)\right)} \cdot \frac{1}{\sqrt{k}} \]
        7. metadata-eval99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + \left(-k \cdot \color{blue}{0.5}\right)\right)} \cdot \frac{1}{\sqrt{k}} \]
        8. distribute-rgt-neg-in99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + \color{blue}{k \cdot \left(-0.5\right)}\right)} \cdot \frac{1}{\sqrt{k}} \]
        9. metadata-eval99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot \color{blue}{-0.5}\right)} \cdot \frac{1}{\sqrt{k}} \]
        10. inv-pow99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)} \cdot \color{blue}{{\left(\sqrt{k}\right)}^{-1}} \]
        11. sqrt-pow299.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)} \cdot \color{blue}{{k}^{\left(\frac{-1}{2}\right)}} \]
        12. metadata-eval99.6%

          \[\leadsto {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)} \cdot {k}^{\color{blue}{-0.5}} \]
      6. Applied egg-rr99.6%

        \[\leadsto \color{blue}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)} \cdot {k}^{-0.5}} \]
      7. Step-by-step derivation
        1. sqr-pow98.9%

          \[\leadsto \color{blue}{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{0.5 + k \cdot -0.5}{2}\right)} \cdot {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\frac{0.5 + k \cdot -0.5}{2}\right)}\right)} \cdot {k}^{-0.5} \]
        2. pow-prod-down91.3%

          \[\leadsto \color{blue}{{\left(\left(2 \cdot \left(\pi \cdot n\right)\right) \cdot \left(2 \cdot \left(\pi \cdot n\right)\right)\right)}^{\left(\frac{0.5 + k \cdot -0.5}{2}\right)}} \cdot {k}^{-0.5} \]
        3. sqrt-pow191.3%

          \[\leadsto \color{blue}{\sqrt{{\left(\left(2 \cdot \left(\pi \cdot n\right)\right) \cdot \left(2 \cdot \left(\pi \cdot n\right)\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}}} \cdot {k}^{-0.5} \]
        4. pow-prod-down99.0%

          \[\leadsto \sqrt{\color{blue}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)} \cdot {\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}}} \cdot {k}^{-0.5} \]
        5. pow299.0%

          \[\leadsto \sqrt{\color{blue}{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}} \cdot {k}^{-0.5} \]
        6. pow-unpow99.0%

          \[\leadsto \sqrt{\color{blue}{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(\left(0.5 + k \cdot -0.5\right) \cdot 2\right)}}} \cdot {k}^{-0.5} \]
        7. *-commutative99.0%

          \[\leadsto \sqrt{{\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\color{blue}{\left(2 \cdot \left(0.5 + k \cdot -0.5\right)\right)}}} \cdot {k}^{-0.5} \]
        8. associate-*r*99.0%

          \[\leadsto \sqrt{{\color{blue}{\left(\left(2 \cdot \pi\right) \cdot n\right)}}^{\left(2 \cdot \left(0.5 + k \cdot -0.5\right)\right)}} \cdot {k}^{-0.5} \]
        9. +-commutative99.0%

          \[\leadsto \sqrt{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(2 \cdot \color{blue}{\left(k \cdot -0.5 + 0.5\right)}\right)}} \cdot {k}^{-0.5} \]
        10. fma-udef99.0%

          \[\leadsto \sqrt{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(2 \cdot \color{blue}{\mathsf{fma}\left(k, -0.5, 0.5\right)}\right)}} \cdot {k}^{-0.5} \]
        11. *-commutative99.0%

          \[\leadsto \sqrt{{\left(\color{blue}{\left(\pi \cdot 2\right)} \cdot n\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}} \cdot {k}^{-0.5} \]
        12. associate-*r*99.0%

          \[\leadsto \sqrt{{\color{blue}{\left(\pi \cdot \left(2 \cdot n\right)\right)}}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}} \cdot {k}^{-0.5} \]
      8. Applied egg-rr99.0%

        \[\leadsto \color{blue}{\frac{1}{\sqrt{\frac{k}{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}}}} \]
      9. Step-by-step derivation
        1. *-commutative99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\color{blue}{\left(\left(2 \cdot n\right) \cdot \pi\right)}}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}}} \]
        2. *-commutative99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(\color{blue}{\left(n \cdot 2\right)} \cdot \pi\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}}} \]
        3. associate-*l*99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\color{blue}{\left(n \cdot \left(2 \cdot \pi\right)\right)}}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}}} \]
        4. fma-udef99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(2 \cdot \color{blue}{\left(k \cdot -0.5 + 0.5\right)}\right)}}}} \]
        5. distribute-lft-in99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\color{blue}{\left(2 \cdot \left(k \cdot -0.5\right) + 2 \cdot 0.5\right)}}}}} \]
        6. *-commutative99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(2 \cdot \color{blue}{\left(-0.5 \cdot k\right)} + 2 \cdot 0.5\right)}}}} \]
        7. associate-*r*99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(\color{blue}{\left(2 \cdot -0.5\right) \cdot k} + 2 \cdot 0.5\right)}}}} \]
        8. metadata-eval99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(\color{blue}{-1} \cdot k + 2 \cdot 0.5\right)}}}} \]
        9. neg-mul-199.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(\color{blue}{\left(-k\right)} + 2 \cdot 0.5\right)}}}} \]
        10. metadata-eval99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(\left(-k\right) + \color{blue}{1}\right)}}}} \]
        11. +-commutative99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\color{blue}{\left(1 + \left(-k\right)\right)}}}}} \]
        12. sub-neg99.0%

          \[\leadsto \frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\color{blue}{\left(1 - k\right)}}}}} \]
      10. Simplified99.0%

        \[\leadsto \color{blue}{\frac{1}{\sqrt{\frac{k}{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(1 - k\right)}}}}} \]
    5. Recombined 2 regimes into one program.
    6. Final simplification99.2%

      \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 4.6 \cdot 10^{-67}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{\sqrt{\frac{k}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(1 - k\right)}}}}\\ \end{array} \]
    7. Add Preprocessing

    Alternative 3: 98.4% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 1.35 \cdot 10^{-96}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(1 - k\right)}}{k}}\\ \end{array} \end{array} \]
    (FPCore (k n)
     :precision binary64
     (if (<= k 1.35e-96)
       (* (sqrt (/ PI k)) (sqrt (* 2.0 n)))
       (sqrt (/ (pow (* (* 2.0 PI) n) (- 1.0 k)) k))))
    double code(double k, double n) {
    	double tmp;
    	if (k <= 1.35e-96) {
    		tmp = sqrt((((double) M_PI) / k)) * sqrt((2.0 * n));
    	} else {
    		tmp = sqrt((pow(((2.0 * ((double) M_PI)) * n), (1.0 - k)) / k));
    	}
    	return tmp;
    }
    
    public static double code(double k, double n) {
    	double tmp;
    	if (k <= 1.35e-96) {
    		tmp = Math.sqrt((Math.PI / k)) * Math.sqrt((2.0 * n));
    	} else {
    		tmp = Math.sqrt((Math.pow(((2.0 * Math.PI) * n), (1.0 - k)) / k));
    	}
    	return tmp;
    }
    
    def code(k, n):
    	tmp = 0
    	if k <= 1.35e-96:
    		tmp = math.sqrt((math.pi / k)) * math.sqrt((2.0 * n))
    	else:
    		tmp = math.sqrt((math.pow(((2.0 * math.pi) * n), (1.0 - k)) / k))
    	return tmp
    
    function code(k, n)
    	tmp = 0.0
    	if (k <= 1.35e-96)
    		tmp = Float64(sqrt(Float64(pi / k)) * sqrt(Float64(2.0 * n)));
    	else
    		tmp = sqrt(Float64((Float64(Float64(2.0 * pi) * n) ^ Float64(1.0 - k)) / k));
    	end
    	return tmp
    end
    
    function tmp_2 = code(k, n)
    	tmp = 0.0;
    	if (k <= 1.35e-96)
    		tmp = sqrt((pi / k)) * sqrt((2.0 * n));
    	else
    		tmp = sqrt(((((2.0 * pi) * n) ^ (1.0 - k)) / k));
    	end
    	tmp_2 = tmp;
    end
    
    code[k_, n_] := If[LessEqual[k, 1.35e-96], N[(N[Sqrt[N[(Pi / k), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[Sqrt[N[(N[Power[N[(N[(2.0 * Pi), $MachinePrecision] * n), $MachinePrecision], N[(1.0 - k), $MachinePrecision]], $MachinePrecision] / k), $MachinePrecision]], $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;k \leq 1.35 \cdot 10^{-96}:\\
    \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\
    
    \mathbf{else}:\\
    \;\;\;\;\sqrt{\frac{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(1 - k\right)}}{k}}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if k < 1.35e-96

      1. Initial program 99.3%

        \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
      2. Add Preprocessing
      3. Applied egg-rr72.5%

        \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
      4. Step-by-step derivation
        1. Simplified72.5%

          \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
        2. Taylor expanded in k around 0 72.5%

          \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
        3. Step-by-step derivation
          1. associate-*r*72.5%

            \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
          2. *-commutative72.5%

            \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
          3. associate-*l*72.5%

            \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
        4. Simplified72.5%

          \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
        5. Step-by-step derivation
          1. associate-*r*72.5%

            \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right) \cdot \pi}}{k}} \]
          2. associate-*r/72.5%

            \[\leadsto \sqrt{\color{blue}{\left(n \cdot 2\right) \cdot \frac{\pi}{k}}} \]
          3. sqrt-prod99.5%

            \[\leadsto \color{blue}{\sqrt{n \cdot 2} \cdot \sqrt{\frac{\pi}{k}}} \]
          4. *-commutative99.5%

            \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{n \cdot 2}} \]
          5. *-commutative99.5%

            \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{\color{blue}{2 \cdot n}} \]
        6. Applied egg-rr99.5%

          \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}} \]

        if 1.35e-96 < k

        1. Initial program 99.5%

          \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
        2. Add Preprocessing
        3. Applied egg-rr99.0%

          \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
        4. Step-by-step derivation
          1. Simplified99.0%

            \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
          2. Taylor expanded in n around 0 97.9%

            \[\leadsto \color{blue}{\sqrt{\frac{e^{2 \cdot \left(\left(0.5 + -0.5 \cdot k\right) \cdot \left(\log n + \log \left(2 \cdot \pi\right)\right)\right)}}{k}}} \]
          3. Simplified99.0%

            \[\leadsto \color{blue}{\sqrt{\frac{{\left(n \cdot \left(2 \cdot \pi\right)\right)}^{\left(1 - k\right)}}{k}}} \]
        5. Recombined 2 regimes into one program.
        6. Final simplification99.2%

          \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 1.35 \cdot 10^{-96}:\\ \;\;\;\;\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}\\ \mathbf{else}:\\ \;\;\;\;\sqrt{\frac{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(1 - k\right)}}{k}}\\ \end{array} \]
        7. Add Preprocessing

        Alternative 4: 99.4% accurate, 1.0× speedup?

        \[\begin{array}{l} \\ \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}} \end{array} \]
        (FPCore (k n)
         :precision binary64
         (/ (pow (* PI (* 2.0 n)) (- 0.5 (/ k 2.0))) (sqrt k)))
        double code(double k, double n) {
        	return pow((((double) M_PI) * (2.0 * n)), (0.5 - (k / 2.0))) / sqrt(k);
        }
        
        public static double code(double k, double n) {
        	return Math.pow((Math.PI * (2.0 * n)), (0.5 - (k / 2.0))) / Math.sqrt(k);
        }
        
        def code(k, n):
        	return math.pow((math.pi * (2.0 * n)), (0.5 - (k / 2.0))) / math.sqrt(k)
        
        function code(k, n)
        	return Float64((Float64(pi * Float64(2.0 * n)) ^ Float64(0.5 - Float64(k / 2.0))) / sqrt(k))
        end
        
        function tmp = code(k, n)
        	tmp = ((pi * (2.0 * n)) ^ (0.5 - (k / 2.0))) / sqrt(k);
        end
        
        code[k_, n_] := N[(N[Power[N[(Pi * N[(2.0 * n), $MachinePrecision]), $MachinePrecision], N[(0.5 - N[(k / 2.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / N[Sqrt[k], $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}}
        \end{array}
        
        Derivation
        1. Initial program 99.5%

          \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
        2. Step-by-step derivation
          1. associate-*l/99.5%

            \[\leadsto \color{blue}{\frac{1 \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}{\sqrt{k}}} \]
          2. *-lft-identity99.5%

            \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)}}}{\sqrt{k}} \]
          3. sqr-pow98.9%

            \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\frac{1 - k}{2}}{2}\right)} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{\frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
          4. pow-sqr99.5%

            \[\leadsto \frac{\color{blue}{{\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
          5. *-commutative99.5%

            \[\leadsto \frac{{\left(\color{blue}{\left(\pi \cdot 2\right)} \cdot n\right)}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}{\sqrt{k}} \]
          6. associate-*l*99.5%

            \[\leadsto \frac{{\color{blue}{\left(\pi \cdot \left(2 \cdot n\right)\right)}}^{\left(2 \cdot \frac{\frac{1 - k}{2}}{2}\right)}}{\sqrt{k}} \]
          7. associate-*r/99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{2 \cdot \frac{1 - k}{2}}{2}\right)}}}{\sqrt{k}} \]
          8. *-commutative99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\frac{\color{blue}{\frac{1 - k}{2} \cdot 2}}{2}\right)}}{\sqrt{k}} \]
          9. associate-/l*99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{\frac{1 - k}{2}}{\frac{2}{2}}\right)}}}{\sqrt{k}} \]
          10. metadata-eval99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\frac{\frac{1 - k}{2}}{\color{blue}{1}}\right)}}{\sqrt{k}} \]
          11. /-rgt-identity99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1 - k}{2}\right)}}}{\sqrt{k}} \]
          12. div-sub99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\color{blue}{\left(\frac{1}{2} - \frac{k}{2}\right)}}}{\sqrt{k}} \]
          13. metadata-eval99.5%

            \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(\color{blue}{0.5} - \frac{k}{2}\right)}}{\sqrt{k}} \]
        3. Simplified99.5%

          \[\leadsto \color{blue}{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}}} \]
        4. Add Preprocessing
        5. Final simplification99.5%

          \[\leadsto \frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(0.5 - \frac{k}{2}\right)}}{\sqrt{k}} \]
        6. Add Preprocessing

        Alternative 5: 49.6% accurate, 1.0× speedup?

        \[\begin{array}{l} \\ \sqrt{n} \cdot \sqrt{\pi \cdot \frac{2}{k}} \end{array} \]
        (FPCore (k n) :precision binary64 (* (sqrt n) (sqrt (* PI (/ 2.0 k)))))
        double code(double k, double n) {
        	return sqrt(n) * sqrt((((double) M_PI) * (2.0 / k)));
        }
        
        public static double code(double k, double n) {
        	return Math.sqrt(n) * Math.sqrt((Math.PI * (2.0 / k)));
        }
        
        def code(k, n):
        	return math.sqrt(n) * math.sqrt((math.pi * (2.0 / k)))
        
        function code(k, n)
        	return Float64(sqrt(n) * sqrt(Float64(pi * Float64(2.0 / k))))
        end
        
        function tmp = code(k, n)
        	tmp = sqrt(n) * sqrt((pi * (2.0 / k)));
        end
        
        code[k_, n_] := N[(N[Sqrt[n], $MachinePrecision] * N[Sqrt[N[(Pi * N[(2.0 / k), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        \sqrt{n} \cdot \sqrt{\pi \cdot \frac{2}{k}}
        \end{array}
        
        Derivation
        1. Initial program 99.5%

          \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
        2. Add Preprocessing
        3. Applied egg-rr90.7%

          \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
        4. Step-by-step derivation
          1. Simplified90.7%

            \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
          2. Taylor expanded in k around 0 35.1%

            \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
          3. Step-by-step derivation
            1. associate-*r*35.1%

              \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
            2. *-commutative35.1%

              \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
            3. associate-*l*35.1%

              \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
          4. Simplified35.1%

            \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
          5. Step-by-step derivation
            1. pow1/235.1%

              \[\leadsto \color{blue}{{\left(\frac{n \cdot \left(2 \cdot \pi\right)}{k}\right)}^{0.5}} \]
            2. associate-*r*35.1%

              \[\leadsto {\left(\frac{\color{blue}{\left(n \cdot 2\right) \cdot \pi}}{k}\right)}^{0.5} \]
            3. associate-*r/35.1%

              \[\leadsto {\color{blue}{\left(\left(n \cdot 2\right) \cdot \frac{\pi}{k}\right)}}^{0.5} \]
            4. associate-*l*35.1%

              \[\leadsto {\color{blue}{\left(n \cdot \left(2 \cdot \frac{\pi}{k}\right)\right)}}^{0.5} \]
            5. unpow-prod-down43.5%

              \[\leadsto \color{blue}{{n}^{0.5} \cdot {\left(2 \cdot \frac{\pi}{k}\right)}^{0.5}} \]
            6. pow1/243.5%

              \[\leadsto \color{blue}{\sqrt{n}} \cdot {\left(2 \cdot \frac{\pi}{k}\right)}^{0.5} \]
            7. clear-num43.5%

              \[\leadsto \sqrt{n} \cdot {\left(2 \cdot \color{blue}{\frac{1}{\frac{k}{\pi}}}\right)}^{0.5} \]
            8. un-div-inv43.5%

              \[\leadsto \sqrt{n} \cdot {\color{blue}{\left(\frac{2}{\frac{k}{\pi}}\right)}}^{0.5} \]
          6. Applied egg-rr43.5%

            \[\leadsto \color{blue}{\sqrt{n} \cdot {\left(\frac{2}{\frac{k}{\pi}}\right)}^{0.5}} \]
          7. Step-by-step derivation
            1. unpow1/243.5%

              \[\leadsto \sqrt{n} \cdot \color{blue}{\sqrt{\frac{2}{\frac{k}{\pi}}}} \]
            2. associate-/r/43.5%

              \[\leadsto \sqrt{n} \cdot \sqrt{\color{blue}{\frac{2}{k} \cdot \pi}} \]
          8. Simplified43.5%

            \[\leadsto \color{blue}{\sqrt{n} \cdot \sqrt{\frac{2}{k} \cdot \pi}} \]
          9. Final simplification43.5%

            \[\leadsto \sqrt{n} \cdot \sqrt{\pi \cdot \frac{2}{k}} \]
          10. Add Preprocessing

          Alternative 6: 49.6% accurate, 1.0× speedup?

          \[\begin{array}{l} \\ \sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n} \end{array} \]
          (FPCore (k n) :precision binary64 (* (sqrt (/ PI k)) (sqrt (* 2.0 n))))
          double code(double k, double n) {
          	return sqrt((((double) M_PI) / k)) * sqrt((2.0 * n));
          }
          
          public static double code(double k, double n) {
          	return Math.sqrt((Math.PI / k)) * Math.sqrt((2.0 * n));
          }
          
          def code(k, n):
          	return math.sqrt((math.pi / k)) * math.sqrt((2.0 * n))
          
          function code(k, n)
          	return Float64(sqrt(Float64(pi / k)) * sqrt(Float64(2.0 * n)))
          end
          
          function tmp = code(k, n)
          	tmp = sqrt((pi / k)) * sqrt((2.0 * n));
          end
          
          code[k_, n_] := N[(N[Sqrt[N[(Pi / k), $MachinePrecision]], $MachinePrecision] * N[Sqrt[N[(2.0 * n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}
          \end{array}
          
          Derivation
          1. Initial program 99.5%

            \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
          2. Add Preprocessing
          3. Applied egg-rr90.7%

            \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
          4. Step-by-step derivation
            1. Simplified90.7%

              \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
            2. Taylor expanded in k around 0 35.1%

              \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
            3. Step-by-step derivation
              1. associate-*r*35.1%

                \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
              2. *-commutative35.1%

                \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
              3. associate-*l*35.1%

                \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
            4. Simplified35.1%

              \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
            5. Step-by-step derivation
              1. associate-*r*35.1%

                \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right) \cdot \pi}}{k}} \]
              2. associate-*r/35.1%

                \[\leadsto \sqrt{\color{blue}{\left(n \cdot 2\right) \cdot \frac{\pi}{k}}} \]
              3. sqrt-prod43.5%

                \[\leadsto \color{blue}{\sqrt{n \cdot 2} \cdot \sqrt{\frac{\pi}{k}}} \]
              4. *-commutative43.5%

                \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{n \cdot 2}} \]
              5. *-commutative43.5%

                \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{\color{blue}{2 \cdot n}} \]
            6. Applied egg-rr43.5%

              \[\leadsto \color{blue}{\sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n}} \]
            7. Final simplification43.5%

              \[\leadsto \sqrt{\frac{\pi}{k}} \cdot \sqrt{2 \cdot n} \]
            8. Add Preprocessing

            Alternative 7: 38.2% accurate, 2.0× speedup?

            \[\begin{array}{l} \\ \frac{1}{\sqrt{0.5 \cdot \frac{k}{\pi \cdot n}}} \end{array} \]
            (FPCore (k n) :precision binary64 (/ 1.0 (sqrt (* 0.5 (/ k (* PI n))))))
            double code(double k, double n) {
            	return 1.0 / sqrt((0.5 * (k / (((double) M_PI) * n))));
            }
            
            public static double code(double k, double n) {
            	return 1.0 / Math.sqrt((0.5 * (k / (Math.PI * n))));
            }
            
            def code(k, n):
            	return 1.0 / math.sqrt((0.5 * (k / (math.pi * n))))
            
            function code(k, n)
            	return Float64(1.0 / sqrt(Float64(0.5 * Float64(k / Float64(pi * n)))))
            end
            
            function tmp = code(k, n)
            	tmp = 1.0 / sqrt((0.5 * (k / (pi * n))));
            end
            
            code[k_, n_] := N[(1.0 / N[Sqrt[N[(0.5 * N[(k / N[(Pi * n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            \frac{1}{\sqrt{0.5 \cdot \frac{k}{\pi \cdot n}}}
            \end{array}
            
            Derivation
            1. Initial program 99.5%

              \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
            2. Add Preprocessing
            3. Applied egg-rr90.7%

              \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
            4. Step-by-step derivation
              1. Simplified90.7%

                \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
              2. Taylor expanded in k around 0 35.1%

                \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
              3. Step-by-step derivation
                1. associate-*r*35.1%

                  \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
                2. *-commutative35.1%

                  \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
                3. associate-*l*35.1%

                  \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
              4. Simplified35.1%

                \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
              5. Step-by-step derivation
                1. clear-num35.0%

                  \[\leadsto \sqrt{\color{blue}{\frac{1}{\frac{k}{n \cdot \left(2 \cdot \pi\right)}}}} \]
                2. sqrt-div36.2%

                  \[\leadsto \color{blue}{\frac{\sqrt{1}}{\sqrt{\frac{k}{n \cdot \left(2 \cdot \pi\right)}}}} \]
                3. metadata-eval36.2%

                  \[\leadsto \frac{\color{blue}{1}}{\sqrt{\frac{k}{n \cdot \left(2 \cdot \pi\right)}}} \]
                4. *-un-lft-identity36.2%

                  \[\leadsto \frac{1}{\sqrt{\frac{\color{blue}{1 \cdot k}}{n \cdot \left(2 \cdot \pi\right)}}} \]
                5. *-commutative36.2%

                  \[\leadsto \frac{1}{\sqrt{\frac{1 \cdot k}{\color{blue}{\left(2 \cdot \pi\right) \cdot n}}}} \]
                6. associate-*r*36.2%

                  \[\leadsto \frac{1}{\sqrt{\frac{1 \cdot k}{\color{blue}{2 \cdot \left(\pi \cdot n\right)}}}} \]
                7. *-commutative36.2%

                  \[\leadsto \frac{1}{\sqrt{\frac{1 \cdot k}{2 \cdot \color{blue}{\left(n \cdot \pi\right)}}}} \]
                8. times-frac36.2%

                  \[\leadsto \frac{1}{\sqrt{\color{blue}{\frac{1}{2} \cdot \frac{k}{n \cdot \pi}}}} \]
                9. metadata-eval36.2%

                  \[\leadsto \frac{1}{\sqrt{\color{blue}{0.5} \cdot \frac{k}{n \cdot \pi}}} \]
                10. *-commutative36.2%

                  \[\leadsto \frac{1}{\sqrt{0.5 \cdot \frac{k}{\color{blue}{\pi \cdot n}}}} \]
                11. associate-/r*36.2%

                  \[\leadsto \frac{1}{\sqrt{0.5 \cdot \color{blue}{\frac{\frac{k}{\pi}}{n}}}} \]
              6. Applied egg-rr36.2%

                \[\leadsto \color{blue}{\frac{1}{\sqrt{0.5 \cdot \frac{\frac{k}{\pi}}{n}}}} \]
              7. Step-by-step derivation
                1. associate-/l/36.2%

                  \[\leadsto \frac{1}{\sqrt{0.5 \cdot \color{blue}{\frac{k}{n \cdot \pi}}}} \]
              8. Simplified36.2%

                \[\leadsto \color{blue}{\frac{1}{\sqrt{0.5 \cdot \frac{k}{n \cdot \pi}}}} \]
              9. Final simplification36.2%

                \[\leadsto \frac{1}{\sqrt{0.5 \cdot \frac{k}{\pi \cdot n}}} \]
              10. Add Preprocessing

              Alternative 8: 38.2% accurate, 2.0× speedup?

              \[\begin{array}{l} \\ \frac{1}{\sqrt{0.5 \cdot \frac{\frac{k}{\pi}}{n}}} \end{array} \]
              (FPCore (k n) :precision binary64 (/ 1.0 (sqrt (* 0.5 (/ (/ k PI) n)))))
              double code(double k, double n) {
              	return 1.0 / sqrt((0.5 * ((k / ((double) M_PI)) / n)));
              }
              
              public static double code(double k, double n) {
              	return 1.0 / Math.sqrt((0.5 * ((k / Math.PI) / n)));
              }
              
              def code(k, n):
              	return 1.0 / math.sqrt((0.5 * ((k / math.pi) / n)))
              
              function code(k, n)
              	return Float64(1.0 / sqrt(Float64(0.5 * Float64(Float64(k / pi) / n))))
              end
              
              function tmp = code(k, n)
              	tmp = 1.0 / sqrt((0.5 * ((k / pi) / n)));
              end
              
              code[k_, n_] := N[(1.0 / N[Sqrt[N[(0.5 * N[(N[(k / Pi), $MachinePrecision] / n), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              \frac{1}{\sqrt{0.5 \cdot \frac{\frac{k}{\pi}}{n}}}
              \end{array}
              
              Derivation
              1. Initial program 99.5%

                \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
              2. Add Preprocessing
              3. Applied egg-rr90.7%

                \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
              4. Step-by-step derivation
                1. Simplified90.7%

                  \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
                2. Taylor expanded in k around 0 35.1%

                  \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
                3. Step-by-step derivation
                  1. associate-*r*35.1%

                    \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
                  2. *-commutative35.1%

                    \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
                  3. associate-*l*35.1%

                    \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                4. Simplified35.1%

                  \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                5. Step-by-step derivation
                  1. clear-num35.0%

                    \[\leadsto \sqrt{\color{blue}{\frac{1}{\frac{k}{n \cdot \left(2 \cdot \pi\right)}}}} \]
                  2. sqrt-div36.2%

                    \[\leadsto \color{blue}{\frac{\sqrt{1}}{\sqrt{\frac{k}{n \cdot \left(2 \cdot \pi\right)}}}} \]
                  3. metadata-eval36.2%

                    \[\leadsto \frac{\color{blue}{1}}{\sqrt{\frac{k}{n \cdot \left(2 \cdot \pi\right)}}} \]
                  4. *-un-lft-identity36.2%

                    \[\leadsto \frac{1}{\sqrt{\frac{\color{blue}{1 \cdot k}}{n \cdot \left(2 \cdot \pi\right)}}} \]
                  5. *-commutative36.2%

                    \[\leadsto \frac{1}{\sqrt{\frac{1 \cdot k}{\color{blue}{\left(2 \cdot \pi\right) \cdot n}}}} \]
                  6. associate-*r*36.2%

                    \[\leadsto \frac{1}{\sqrt{\frac{1 \cdot k}{\color{blue}{2 \cdot \left(\pi \cdot n\right)}}}} \]
                  7. *-commutative36.2%

                    \[\leadsto \frac{1}{\sqrt{\frac{1 \cdot k}{2 \cdot \color{blue}{\left(n \cdot \pi\right)}}}} \]
                  8. times-frac36.2%

                    \[\leadsto \frac{1}{\sqrt{\color{blue}{\frac{1}{2} \cdot \frac{k}{n \cdot \pi}}}} \]
                  9. metadata-eval36.2%

                    \[\leadsto \frac{1}{\sqrt{\color{blue}{0.5} \cdot \frac{k}{n \cdot \pi}}} \]
                  10. *-commutative36.2%

                    \[\leadsto \frac{1}{\sqrt{0.5 \cdot \frac{k}{\color{blue}{\pi \cdot n}}}} \]
                  11. associate-/r*36.2%

                    \[\leadsto \frac{1}{\sqrt{0.5 \cdot \color{blue}{\frac{\frac{k}{\pi}}{n}}}} \]
                6. Applied egg-rr36.2%

                  \[\leadsto \color{blue}{\frac{1}{\sqrt{0.5 \cdot \frac{\frac{k}{\pi}}{n}}}} \]
                7. Final simplification36.2%

                  \[\leadsto \frac{1}{\sqrt{0.5 \cdot \frac{\frac{k}{\pi}}{n}}} \]
                8. Add Preprocessing

                Alternative 9: 37.6% accurate, 2.0× speedup?

                \[\begin{array}{l} \\ \sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}} \end{array} \]
                (FPCore (k n) :precision binary64 (sqrt (* 2.0 (/ n (/ k PI)))))
                double code(double k, double n) {
                	return sqrt((2.0 * (n / (k / ((double) M_PI)))));
                }
                
                public static double code(double k, double n) {
                	return Math.sqrt((2.0 * (n / (k / Math.PI))));
                }
                
                def code(k, n):
                	return math.sqrt((2.0 * (n / (k / math.pi))))
                
                function code(k, n)
                	return sqrt(Float64(2.0 * Float64(n / Float64(k / pi))))
                end
                
                function tmp = code(k, n)
                	tmp = sqrt((2.0 * (n / (k / pi))));
                end
                
                code[k_, n_] := N[Sqrt[N[(2.0 * N[(n / N[(k / Pi), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                \sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}}
                \end{array}
                
                Derivation
                1. Initial program 99.5%

                  \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
                2. Add Preprocessing
                3. Applied egg-rr90.7%

                  \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
                4. Step-by-step derivation
                  1. Simplified90.7%

                    \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
                  2. Taylor expanded in k around 0 35.1%

                    \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
                  3. Step-by-step derivation
                    1. associate-*r*35.1%

                      \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
                    2. *-commutative35.1%

                      \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
                    3. associate-*l*35.1%

                      \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                  4. Simplified35.1%

                    \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                  5. Step-by-step derivation
                    1. associate-/l*35.1%

                      \[\leadsto \sqrt{\color{blue}{\frac{n}{\frac{k}{2 \cdot \pi}}}} \]
                    2. sqrt-div43.5%

                      \[\leadsto \color{blue}{\frac{\sqrt{n}}{\sqrt{\frac{k}{2 \cdot \pi}}}} \]
                    3. *-un-lft-identity43.5%

                      \[\leadsto \frac{\sqrt{n}}{\sqrt{\frac{\color{blue}{1 \cdot k}}{2 \cdot \pi}}} \]
                    4. times-frac43.5%

                      \[\leadsto \frac{\sqrt{n}}{\sqrt{\color{blue}{\frac{1}{2} \cdot \frac{k}{\pi}}}} \]
                    5. metadata-eval43.5%

                      \[\leadsto \frac{\sqrt{n}}{\sqrt{\color{blue}{0.5} \cdot \frac{k}{\pi}}} \]
                  6. Applied egg-rr43.5%

                    \[\leadsto \color{blue}{\frac{\sqrt{n}}{\sqrt{0.5 \cdot \frac{k}{\pi}}}} \]
                  7. Step-by-step derivation
                    1. sqrt-undiv35.1%

                      \[\leadsto \color{blue}{\sqrt{\frac{n}{0.5 \cdot \frac{k}{\pi}}}} \]
                    2. *-un-lft-identity35.1%

                      \[\leadsto \sqrt{\frac{\color{blue}{1 \cdot n}}{0.5 \cdot \frac{k}{\pi}}} \]
                    3. times-frac35.1%

                      \[\leadsto \sqrt{\color{blue}{\frac{1}{0.5} \cdot \frac{n}{\frac{k}{\pi}}}} \]
                    4. metadata-eval35.1%

                      \[\leadsto \sqrt{\color{blue}{2} \cdot \frac{n}{\frac{k}{\pi}}} \]
                  8. Applied egg-rr35.1%

                    \[\leadsto \color{blue}{\sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}}} \]
                  9. Final simplification35.1%

                    \[\leadsto \sqrt{2 \cdot \frac{n}{\frac{k}{\pi}}} \]
                  10. Add Preprocessing

                  Alternative 10: 37.6% accurate, 2.0× speedup?

                  \[\begin{array}{l} \\ \sqrt{2 \cdot \frac{\pi \cdot n}{k}} \end{array} \]
                  (FPCore (k n) :precision binary64 (sqrt (* 2.0 (/ (* PI n) k))))
                  double code(double k, double n) {
                  	return sqrt((2.0 * ((((double) M_PI) * n) / k)));
                  }
                  
                  public static double code(double k, double n) {
                  	return Math.sqrt((2.0 * ((Math.PI * n) / k)));
                  }
                  
                  def code(k, n):
                  	return math.sqrt((2.0 * ((math.pi * n) / k)))
                  
                  function code(k, n)
                  	return sqrt(Float64(2.0 * Float64(Float64(pi * n) / k)))
                  end
                  
                  function tmp = code(k, n)
                  	tmp = sqrt((2.0 * ((pi * n) / k)));
                  end
                  
                  code[k_, n_] := N[Sqrt[N[(2.0 * N[(N[(Pi * n), $MachinePrecision] / k), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  \sqrt{2 \cdot \frac{\pi \cdot n}{k}}
                  \end{array}
                  
                  Derivation
                  1. Initial program 99.5%

                    \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
                  2. Add Preprocessing
                  3. Applied egg-rr90.7%

                    \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
                  4. Step-by-step derivation
                    1. Simplified90.7%

                      \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
                    2. Taylor expanded in k around 0 35.1%

                      \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
                    3. Step-by-step derivation
                      1. associate-*r*35.1%

                        \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
                      2. *-commutative35.1%

                        \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
                      3. associate-*l*35.1%

                        \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                    4. Simplified35.1%

                      \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                    5. Taylor expanded in n around 0 35.1%

                      \[\leadsto \sqrt{\color{blue}{2 \cdot \frac{n \cdot \pi}{k}}} \]
                    6. Final simplification35.1%

                      \[\leadsto \sqrt{2 \cdot \frac{\pi \cdot n}{k}} \]
                    7. Add Preprocessing

                    Alternative 11: 37.5% accurate, 2.0× speedup?

                    \[\begin{array}{l} \\ \sqrt{n \cdot \left(\pi \cdot \frac{2}{k}\right)} \end{array} \]
                    (FPCore (k n) :precision binary64 (sqrt (* n (* PI (/ 2.0 k)))))
                    double code(double k, double n) {
                    	return sqrt((n * (((double) M_PI) * (2.0 / k))));
                    }
                    
                    public static double code(double k, double n) {
                    	return Math.sqrt((n * (Math.PI * (2.0 / k))));
                    }
                    
                    def code(k, n):
                    	return math.sqrt((n * (math.pi * (2.0 / k))))
                    
                    function code(k, n)
                    	return sqrt(Float64(n * Float64(pi * Float64(2.0 / k))))
                    end
                    
                    function tmp = code(k, n)
                    	tmp = sqrt((n * (pi * (2.0 / k))));
                    end
                    
                    code[k_, n_] := N[Sqrt[N[(n * N[(Pi * N[(2.0 / k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
                    
                    \begin{array}{l}
                    
                    \\
                    \sqrt{n \cdot \left(\pi \cdot \frac{2}{k}\right)}
                    \end{array}
                    
                    Derivation
                    1. Initial program 99.5%

                      \[\frac{1}{\sqrt{k}} \cdot {\left(\left(2 \cdot \pi\right) \cdot n\right)}^{\left(\frac{1 - k}{2}\right)} \]
                    2. Add Preprocessing
                    3. Applied egg-rr90.7%

                      \[\leadsto \color{blue}{\sqrt{\frac{{\left({\left(2 \cdot \left(\pi \cdot n\right)\right)}^{\left(0.5 + k \cdot -0.5\right)}\right)}^{2}}{k}}} \]
                    4. Step-by-step derivation
                      1. Simplified90.7%

                        \[\leadsto \color{blue}{\sqrt{\frac{{\left(\pi \cdot \left(2 \cdot n\right)\right)}^{\left(2 \cdot \mathsf{fma}\left(k, -0.5, 0.5\right)\right)}}{k}}} \]
                      2. Taylor expanded in k around 0 35.1%

                        \[\leadsto \sqrt{\frac{\color{blue}{2 \cdot \left(n \cdot \pi\right)}}{k}} \]
                      3. Step-by-step derivation
                        1. associate-*r*35.1%

                          \[\leadsto \sqrt{\frac{\color{blue}{\left(2 \cdot n\right) \cdot \pi}}{k}} \]
                        2. *-commutative35.1%

                          \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right)} \cdot \pi}{k}} \]
                        3. associate-*l*35.1%

                          \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                      4. Simplified35.1%

                        \[\leadsto \sqrt{\frac{\color{blue}{n \cdot \left(2 \cdot \pi\right)}}{k}} \]
                      5. Step-by-step derivation
                        1. associate-*r*35.1%

                          \[\leadsto \sqrt{\frac{\color{blue}{\left(n \cdot 2\right) \cdot \pi}}{k}} \]
                        2. associate-*r/35.1%

                          \[\leadsto \sqrt{\color{blue}{\left(n \cdot 2\right) \cdot \frac{\pi}{k}}} \]
                        3. expm1-log1p-u33.5%

                          \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\sqrt{\left(n \cdot 2\right) \cdot \frac{\pi}{k}}\right)\right)} \]
                        4. expm1-udef33.8%

                          \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\sqrt{\left(n \cdot 2\right) \cdot \frac{\pi}{k}}\right)} - 1} \]
                      6. Applied egg-rr33.8%

                        \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\sqrt{n \cdot \frac{2}{\frac{k}{\pi}}}\right)} - 1} \]
                      7. Step-by-step derivation
                        1. expm1-def33.5%

                          \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\sqrt{n \cdot \frac{2}{\frac{k}{\pi}}}\right)\right)} \]
                        2. expm1-log1p35.1%

                          \[\leadsto \color{blue}{\sqrt{n \cdot \frac{2}{\frac{k}{\pi}}}} \]
                        3. associate-/r/35.1%

                          \[\leadsto \sqrt{n \cdot \color{blue}{\left(\frac{2}{k} \cdot \pi\right)}} \]
                      8. Simplified35.1%

                        \[\leadsto \color{blue}{\sqrt{n \cdot \left(\frac{2}{k} \cdot \pi\right)}} \]
                      9. Final simplification35.1%

                        \[\leadsto \sqrt{n \cdot \left(\pi \cdot \frac{2}{k}\right)} \]
                      10. Add Preprocessing

                      Reproduce

                      ?
                      herbie shell --seed 2024017 
                      (FPCore (k n)
                        :name "Migdal et al, Equation (51)"
                        :precision binary64
                        (* (/ 1.0 (sqrt k)) (pow (* (* 2.0 PI) n) (/ (- 1.0 k) 2.0))))