ab-angle->ABCF C

Percentage Accurate: 79.2% → 79.1%
Time: 52.6s
Alternatives: 11
Speedup: N/A×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \pi \cdot \frac{angle}{180}\\ {\left(a \cdot \cos t_0\right)}^{2} + {\left(b \cdot \sin t_0\right)}^{2} \end{array} \end{array} \]
(FPCore (a b angle)
 :precision binary64
 (let* ((t_0 (* PI (/ angle 180.0))))
   (+ (pow (* a (cos t_0)) 2.0) (pow (* b (sin t_0)) 2.0))))
double code(double a, double b, double angle) {
	double t_0 = ((double) M_PI) * (angle / 180.0);
	return pow((a * cos(t_0)), 2.0) + pow((b * sin(t_0)), 2.0);
}
public static double code(double a, double b, double angle) {
	double t_0 = Math.PI * (angle / 180.0);
	return Math.pow((a * Math.cos(t_0)), 2.0) + Math.pow((b * Math.sin(t_0)), 2.0);
}
def code(a, b, angle):
	t_0 = math.pi * (angle / 180.0)
	return math.pow((a * math.cos(t_0)), 2.0) + math.pow((b * math.sin(t_0)), 2.0)
function code(a, b, angle)
	t_0 = Float64(pi * Float64(angle / 180.0))
	return Float64((Float64(a * cos(t_0)) ^ 2.0) + (Float64(b * sin(t_0)) ^ 2.0))
end
function tmp = code(a, b, angle)
	t_0 = pi * (angle / 180.0);
	tmp = ((a * cos(t_0)) ^ 2.0) + ((b * sin(t_0)) ^ 2.0);
end
code[a_, b_, angle_] := Block[{t$95$0 = N[(Pi * N[(angle / 180.0), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[N[(a * N[Cos[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \pi \cdot \frac{angle}{180}\\
{\left(a \cdot \cos t_0\right)}^{2} + {\left(b \cdot \sin t_0\right)}^{2}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \pi \cdot \frac{angle}{180}\\ {\left(a \cdot \cos t_0\right)}^{2} + {\left(b \cdot \sin t_0\right)}^{2} \end{array} \end{array} \]
(FPCore (a b angle)
 :precision binary64
 (let* ((t_0 (* PI (/ angle 180.0))))
   (+ (pow (* a (cos t_0)) 2.0) (pow (* b (sin t_0)) 2.0))))
double code(double a, double b, double angle) {
	double t_0 = ((double) M_PI) * (angle / 180.0);
	return pow((a * cos(t_0)), 2.0) + pow((b * sin(t_0)), 2.0);
}
public static double code(double a, double b, double angle) {
	double t_0 = Math.PI * (angle / 180.0);
	return Math.pow((a * Math.cos(t_0)), 2.0) + Math.pow((b * Math.sin(t_0)), 2.0);
}
def code(a, b, angle):
	t_0 = math.pi * (angle / 180.0)
	return math.pow((a * math.cos(t_0)), 2.0) + math.pow((b * math.sin(t_0)), 2.0)
function code(a, b, angle)
	t_0 = Float64(pi * Float64(angle / 180.0))
	return Float64((Float64(a * cos(t_0)) ^ 2.0) + (Float64(b * sin(t_0)) ^ 2.0))
end
function tmp = code(a, b, angle)
	t_0 = pi * (angle / 180.0);
	tmp = ((a * cos(t_0)) ^ 2.0) + ((b * sin(t_0)) ^ 2.0);
end
code[a_, b_, angle_] := Block[{t$95$0 = N[(Pi * N[(angle / 180.0), $MachinePrecision]), $MachinePrecision]}, N[(N[Power[N[(a * N[Cos[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[t$95$0], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \pi \cdot \frac{angle}{180}\\
{\left(a \cdot \cos t_0\right)}^{2} + {\left(b \cdot \sin t_0\right)}^{2}
\end{array}
\end{array}

Alternative 1: 79.1% accurate, 0.8× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ \begin{array}{l} t_0 := \sqrt{\frac{180}{angle_m}}\\ {\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\frac{\pi}{t_0}}{t_0}\right)\right)}^{2} \end{array} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (let* ((t_0 (sqrt (/ 180.0 angle_m))))
   (+
    (pow (* a (cos (* PI (/ angle_m 180.0)))) 2.0)
    (pow (* b (sin (/ (/ PI t_0) t_0))) 2.0))))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	double t_0 = sqrt((180.0 / angle_m));
	return pow((a * cos((((double) M_PI) * (angle_m / 180.0)))), 2.0) + pow((b * sin(((((double) M_PI) / t_0) / t_0))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	double t_0 = Math.sqrt((180.0 / angle_m));
	return Math.pow((a * Math.cos((Math.PI * (angle_m / 180.0)))), 2.0) + Math.pow((b * Math.sin(((Math.PI / t_0) / t_0))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	t_0 = math.sqrt((180.0 / angle_m))
	return math.pow((a * math.cos((math.pi * (angle_m / 180.0)))), 2.0) + math.pow((b * math.sin(((math.pi / t_0) / t_0))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	t_0 = sqrt(Float64(180.0 / angle_m))
	return Float64((Float64(a * cos(Float64(pi * Float64(angle_m / 180.0)))) ^ 2.0) + (Float64(b * sin(Float64(Float64(pi / t_0) / t_0))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	t_0 = sqrt((180.0 / angle_m));
	tmp = ((a * cos((pi * (angle_m / 180.0)))) ^ 2.0) + ((b * sin(((pi / t_0) / t_0))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := Block[{t$95$0 = N[Sqrt[N[(180.0 / angle$95$m), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(a * N[Cos[N[(Pi * N[(angle$95$m / 180.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(N[(Pi / t$95$0), $MachinePrecision] / t$95$0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
angle_m = \left|angle\right|

\\
\begin{array}{l}
t_0 := \sqrt{\frac{180}{angle_m}}\\
{\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\frac{\pi}{t_0}}{t_0}\right)\right)}^{2}
\end{array}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Step-by-step derivation
    1. clear-num80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\frac{1}{\frac{180}{angle}}}\right)\right)}^{2} \]
    2. un-div-inv80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  3. Applied egg-rr80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  4. Step-by-step derivation
    1. *-un-lft-identity80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\color{blue}{1 \cdot \pi}}{\frac{180}{angle}}\right)\right)}^{2} \]
    2. add-sqr-sqrt40.0%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{1 \cdot \pi}{\color{blue}{\sqrt{\frac{180}{angle}} \cdot \sqrt{\frac{180}{angle}}}}\right)\right)}^{2} \]
    3. times-frac40.1%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{1}{\sqrt{\frac{180}{angle}}} \cdot \frac{\pi}{\sqrt{\frac{180}{angle}}}\right)}\right)}^{2} \]
  5. Applied egg-rr40.1%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{1}{\sqrt{\frac{180}{angle}}} \cdot \frac{\pi}{\sqrt{\frac{180}{angle}}}\right)}\right)}^{2} \]
  6. Step-by-step derivation
    1. associate-*l/40.1%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{1 \cdot \frac{\pi}{\sqrt{\frac{180}{angle}}}}{\sqrt{\frac{180}{angle}}}\right)}\right)}^{2} \]
    2. *-lft-identity40.1%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\color{blue}{\frac{\pi}{\sqrt{\frac{180}{angle}}}}}{\sqrt{\frac{180}{angle}}}\right)\right)}^{2} \]
  7. Simplified40.1%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\frac{\pi}{\sqrt{\frac{180}{angle}}}}{\sqrt{\frac{180}{angle}}}\right)}\right)}^{2} \]
  8. Final simplification40.1%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\frac{\pi}{\sqrt{\frac{180}{angle}}}}{\sqrt{\frac{180}{angle}}}\right)\right)}^{2} \]

Alternative 2: 79.2% accurate, 1.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(a \cdot \cos \left(\left(\pi \cdot angle_m\right) \cdot -0.005555555555555556\right)\right)}^{2} + {\left(b \cdot \sin \left(angle_m \cdot \frac{\pi}{-180}\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+
  (pow (* a (cos (* (* PI angle_m) -0.005555555555555556))) 2.0)
  (pow (* b (sin (* angle_m (/ PI -180.0)))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((a * cos(((((double) M_PI) * angle_m) * -0.005555555555555556))), 2.0) + pow((b * sin((angle_m * (((double) M_PI) / -180.0)))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((a * Math.cos(((Math.PI * angle_m) * -0.005555555555555556))), 2.0) + Math.pow((b * Math.sin((angle_m * (Math.PI / -180.0)))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((a * math.cos(((math.pi * angle_m) * -0.005555555555555556))), 2.0) + math.pow((b * math.sin((angle_m * (math.pi / -180.0)))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(a * cos(Float64(Float64(pi * angle_m) * -0.005555555555555556))) ^ 2.0) + (Float64(b * sin(Float64(angle_m * Float64(pi / -180.0)))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((a * cos(((pi * angle_m) * -0.005555555555555556))) ^ 2.0) + ((b * sin((angle_m * (pi / -180.0)))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(a * N[Cos[N[(N[(Pi * angle$95$m), $MachinePrecision] * -0.005555555555555556), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(angle$95$m * N[(Pi / -180.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(a \cdot \cos \left(\left(\pi \cdot angle_m\right) \cdot -0.005555555555555556\right)\right)}^{2} + {\left(b \cdot \sin \left(angle_m \cdot \frac{\pi}{-180}\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Simplified80.2%

    \[\leadsto \color{blue}{{\left(a \cdot \cos \left(\frac{\pi}{-180} \cdot angle\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{-180} \cdot angle\right)\right)}^{2}} \]
  3. Taylor expanded in angle around inf 80.1%

    \[\leadsto {\left(a \cdot \color{blue}{\cos \left(-0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{-180} \cdot angle\right)\right)}^{2} \]
  4. Final simplification80.1%

    \[\leadsto {\left(a \cdot \cos \left(\left(\pi \cdot angle\right) \cdot -0.005555555555555556\right)\right)}^{2} + {\left(b \cdot \sin \left(angle \cdot \frac{\pi}{-180}\right)\right)}^{2} \]

Alternative 3: 79.1% accurate, 1.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle_m}}\right)\right)}^{2} + {\left(a \cdot \cos \left(0.005555555555555556 \cdot \left(\pi \cdot angle_m\right)\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+
  (pow (* b (sin (/ PI (/ 180.0 angle_m)))) 2.0)
  (pow (* a (cos (* 0.005555555555555556 (* PI angle_m)))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((b * sin((((double) M_PI) / (180.0 / angle_m)))), 2.0) + pow((a * cos((0.005555555555555556 * (((double) M_PI) * angle_m)))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((b * Math.sin((Math.PI / (180.0 / angle_m)))), 2.0) + Math.pow((a * Math.cos((0.005555555555555556 * (Math.PI * angle_m)))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((b * math.sin((math.pi / (180.0 / angle_m)))), 2.0) + math.pow((a * math.cos((0.005555555555555556 * (math.pi * angle_m)))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(b * sin(Float64(pi / Float64(180.0 / angle_m)))) ^ 2.0) + (Float64(a * cos(Float64(0.005555555555555556 * Float64(pi * angle_m)))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((b * sin((pi / (180.0 / angle_m)))) ^ 2.0) + ((a * cos((0.005555555555555556 * (pi * angle_m)))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(b * N[Sin[N[(Pi / N[(180.0 / angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(a * N[Cos[N[(0.005555555555555556 * N[(Pi * angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle_m}}\right)\right)}^{2} + {\left(a \cdot \cos \left(0.005555555555555556 \cdot \left(\pi \cdot angle_m\right)\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Step-by-step derivation
    1. clear-num80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\frac{1}{\frac{180}{angle}}}\right)\right)}^{2} \]
    2. un-div-inv80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  3. Applied egg-rr80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  4. Taylor expanded in angle around inf 80.1%

    \[\leadsto {\left(a \cdot \color{blue}{\cos \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle}}\right)\right)}^{2} \]
  5. Final simplification80.1%

    \[\leadsto {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle}}\right)\right)}^{2} + {\left(a \cdot \cos \left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)\right)}^{2} \]

Alternative 4: 79.1% accurate, 1.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle_m\right)\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+
  (pow (* a (cos (* PI (/ angle_m 180.0)))) 2.0)
  (pow (* b (sin (* 0.005555555555555556 (* PI angle_m)))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((a * cos((((double) M_PI) * (angle_m / 180.0)))), 2.0) + pow((b * sin((0.005555555555555556 * (((double) M_PI) * angle_m)))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((a * Math.cos((Math.PI * (angle_m / 180.0)))), 2.0) + Math.pow((b * Math.sin((0.005555555555555556 * (Math.PI * angle_m)))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((a * math.cos((math.pi * (angle_m / 180.0)))), 2.0) + math.pow((b * math.sin((0.005555555555555556 * (math.pi * angle_m)))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(a * cos(Float64(pi * Float64(angle_m / 180.0)))) ^ 2.0) + (Float64(b * sin(Float64(0.005555555555555556 * Float64(pi * angle_m)))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((a * cos((pi * (angle_m / 180.0)))) ^ 2.0) + ((b * sin((0.005555555555555556 * (pi * angle_m)))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(a * N[Cos[N[(Pi * N[(angle$95$m / 180.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(0.005555555555555556 * N[(Pi * angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle_m\right)\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Taylor expanded in angle around inf 80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
  3. Final simplification80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)\right)}^{2} \]

Alternative 5: 79.2% accurate, 1.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle_m \cdot 0.005555555555555556\right)\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+
  (pow (* a (cos (* PI (/ angle_m 180.0)))) 2.0)
  (pow (* b (sin (* PI (* angle_m 0.005555555555555556)))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((a * cos((((double) M_PI) * (angle_m / 180.0)))), 2.0) + pow((b * sin((((double) M_PI) * (angle_m * 0.005555555555555556)))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((a * Math.cos((Math.PI * (angle_m / 180.0)))), 2.0) + Math.pow((b * Math.sin((Math.PI * (angle_m * 0.005555555555555556)))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((a * math.cos((math.pi * (angle_m / 180.0)))), 2.0) + math.pow((b * math.sin((math.pi * (angle_m * 0.005555555555555556)))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(a * cos(Float64(pi * Float64(angle_m / 180.0)))) ^ 2.0) + (Float64(b * sin(Float64(pi * Float64(angle_m * 0.005555555555555556)))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((a * cos((pi * (angle_m / 180.0)))) ^ 2.0) + ((b * sin((pi * (angle_m * 0.005555555555555556)))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(a * N[Cos[N[(Pi * N[(angle$95$m / 180.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle_m \cdot 0.005555555555555556\right)\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Taylor expanded in angle around inf 80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
  3. Step-by-step derivation
    1. associate-*r*80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\left(0.005555555555555556 \cdot angle\right) \cdot \pi\right)}\right)}^{2} \]
    2. *-commutative80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\color{blue}{\left(angle \cdot 0.005555555555555556\right)} \cdot \pi\right)\right)}^{2} \]
    3. *-commutative80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)}\right)}^{2} \]
    4. *-commutative80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\left(0.005555555555555556 \cdot angle\right)}\right)\right)}^{2} \]
  4. Simplified80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(\pi \cdot \left(0.005555555555555556 \cdot angle\right)\right)}\right)}^{2} \]
  5. Final simplification80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} \]

Alternative 6: 79.1% accurate, 1.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle_m}}\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+
  (pow (* a (cos (* PI (/ angle_m 180.0)))) 2.0)
  (pow (* b (sin (/ PI (/ 180.0 angle_m)))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((a * cos((((double) M_PI) * (angle_m / 180.0)))), 2.0) + pow((b * sin((((double) M_PI) / (180.0 / angle_m)))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((a * Math.cos((Math.PI * (angle_m / 180.0)))), 2.0) + Math.pow((b * Math.sin((Math.PI / (180.0 / angle_m)))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((a * math.cos((math.pi * (angle_m / 180.0)))), 2.0) + math.pow((b * math.sin((math.pi / (180.0 / angle_m)))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(a * cos(Float64(pi * Float64(angle_m / 180.0)))) ^ 2.0) + (Float64(b * sin(Float64(pi / Float64(180.0 / angle_m)))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((a * cos((pi * (angle_m / 180.0)))) ^ 2.0) + ((b * sin((pi / (180.0 / angle_m)))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(a * N[Cos[N[(Pi * N[(angle$95$m / 180.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[N[(b * N[Sin[N[(Pi / N[(180.0 / angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(a \cdot \cos \left(\pi \cdot \frac{angle_m}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle_m}}\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Step-by-step derivation
    1. clear-num80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\frac{1}{\frac{180}{angle}}}\right)\right)}^{2} \]
    2. un-div-inv80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  3. Applied egg-rr80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  4. Final simplification80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle}}\right)\right)}^{2} \]

Alternative 7: 79.1% accurate, 1.5× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle_m\right)\right)\right)}^{2} + {a}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+ (pow (* b (sin (* 0.005555555555555556 (* PI angle_m)))) 2.0) (pow a 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((b * sin((0.005555555555555556 * (((double) M_PI) * angle_m)))), 2.0) + pow(a, 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((b * Math.sin((0.005555555555555556 * (Math.PI * angle_m)))), 2.0) + Math.pow(a, 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((b * math.sin((0.005555555555555556 * (math.pi * angle_m)))), 2.0) + math.pow(a, 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(b * sin(Float64(0.005555555555555556 * Float64(pi * angle_m)))) ^ 2.0) + (a ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((b * sin((0.005555555555555556 * (pi * angle_m)))) ^ 2.0) + (a ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(b * N[Sin[N[(0.005555555555555556 * N[(Pi * angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[a, 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle_m\right)\right)\right)}^{2} + {a}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Taylor expanded in angle around 0 80.0%

    \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  3. Taylor expanded in angle around inf 80.0%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
  4. Final simplification80.0%

    \[\leadsto {\left(b \cdot \sin \left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)\right)}^{2} + {a}^{2} \]

Alternative 8: 79.1% accurate, 1.5× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(b \cdot \sin \left(\pi \cdot \left(angle_m \cdot 0.005555555555555556\right)\right)\right)}^{2} + {a}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+ (pow (* b (sin (* PI (* angle_m 0.005555555555555556)))) 2.0) (pow a 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((b * sin((((double) M_PI) * (angle_m * 0.005555555555555556)))), 2.0) + pow(a, 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((b * Math.sin((Math.PI * (angle_m * 0.005555555555555556)))), 2.0) + Math.pow(a, 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((b * math.sin((math.pi * (angle_m * 0.005555555555555556)))), 2.0) + math.pow(a, 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(b * sin(Float64(pi * Float64(angle_m * 0.005555555555555556)))) ^ 2.0) + (a ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((b * sin((pi * (angle_m * 0.005555555555555556)))) ^ 2.0) + (a ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(b * N[Sin[N[(Pi * N[(angle$95$m * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[a, 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(b \cdot \sin \left(\pi \cdot \left(angle_m \cdot 0.005555555555555556\right)\right)\right)}^{2} + {a}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Taylor expanded in angle around 0 80.0%

    \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  3. Taylor expanded in angle around inf 80.0%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
  4. Step-by-step derivation
    1. associate-*r*80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\left(0.005555555555555556 \cdot angle\right) \cdot \pi\right)}\right)}^{2} \]
    2. *-commutative80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\color{blue}{\left(angle \cdot 0.005555555555555556\right)} \cdot \pi\right)\right)}^{2} \]
    3. *-commutative80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)}\right)}^{2} \]
    4. *-commutative80.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\left(0.005555555555555556 \cdot angle\right)}\right)\right)}^{2} \]
  5. Simplified80.0%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\sin \left(\pi \cdot \left(0.005555555555555556 \cdot angle\right)\right)}\right)}^{2} \]
  6. Final simplification80.0%

    \[\leadsto {\left(b \cdot \sin \left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)\right)}^{2} + {a}^{2} \]

Alternative 9: 79.1% accurate, 1.5× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle_m}}\right)\right)}^{2} + {a}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+ (pow (* b (sin (/ PI (/ 180.0 angle_m)))) 2.0) (pow a 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow((b * sin((((double) M_PI) / (180.0 / angle_m)))), 2.0) + pow(a, 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow((b * Math.sin((Math.PI / (180.0 / angle_m)))), 2.0) + Math.pow(a, 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow((b * math.sin((math.pi / (180.0 / angle_m)))), 2.0) + math.pow(a, 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((Float64(b * sin(Float64(pi / Float64(180.0 / angle_m)))) ^ 2.0) + (a ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = ((b * sin((pi / (180.0 / angle_m)))) ^ 2.0) + (a ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[N[(b * N[Sin[N[(Pi / N[(180.0 / angle$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[a, 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle_m}}\right)\right)}^{2} + {a}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Step-by-step derivation
    1. clear-num80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \color{blue}{\frac{1}{\frac{180}{angle}}}\right)\right)}^{2} \]
    2. un-div-inv80.2%

      \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  3. Applied egg-rr80.2%

    \[\leadsto {\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \color{blue}{\left(\frac{\pi}{\frac{180}{angle}}\right)}\right)}^{2} \]
  4. Taylor expanded in angle around 0 80.1%

    \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle}}\right)\right)}^{2} \]
  5. Final simplification80.1%

    \[\leadsto {\left(b \cdot \sin \left(\frac{\pi}{\frac{180}{angle}}\right)\right)}^{2} + {a}^{2} \]

Alternative 10: 74.0% accurate, 2.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {a}^{2} + {\left(angle_m \cdot \left(\pi \cdot \frac{b}{180}\right)\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+ (pow a 2.0) (pow (* angle_m (* PI (/ b 180.0))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow(a, 2.0) + pow((angle_m * (((double) M_PI) * (b / 180.0))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow(a, 2.0) + Math.pow((angle_m * (Math.PI * (b / 180.0))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow(a, 2.0) + math.pow((angle_m * (math.pi * (b / 180.0))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((a ^ 2.0) + (Float64(angle_m * Float64(pi * Float64(b / 180.0))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = (a ^ 2.0) + ((angle_m * (pi * (b / 180.0))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[a, 2.0], $MachinePrecision] + N[Power[N[(angle$95$m * N[(Pi * N[(b / 180.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{a}^{2} + {\left(angle_m \cdot \left(\pi \cdot \frac{b}{180}\right)\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Taylor expanded in angle around 0 80.0%

    \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  3. Taylor expanded in angle around 0 73.9%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
  4. Step-by-step derivation
    1. expm1-log1p-u73.5%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left({\left(b \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)\right)}^{2}\right)\right)} \]
    2. expm1-udef70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(e^{\mathsf{log1p}\left({\left(b \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)\right)}^{2}\right)} - 1\right)} \]
    3. *-commutative70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\color{blue}{\left(\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right) \cdot b\right)}}^{2}\right)} - 1\right) \]
    4. associate-*r*70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\left(\color{blue}{\left(\left(0.005555555555555556 \cdot angle\right) \cdot \pi\right)} \cdot b\right)}^{2}\right)} - 1\right) \]
    5. *-commutative70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\left(\left(\color{blue}{\left(angle \cdot 0.005555555555555556\right)} \cdot \pi\right) \cdot b\right)}^{2}\right)} - 1\right) \]
    6. *-commutative70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\left(\color{blue}{\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)} \cdot b\right)}^{2}\right)} - 1\right) \]
    7. associate-*l*70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\color{blue}{\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}}^{2}\right)} - 1\right) \]
  5. Applied egg-rr70.9%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(e^{\mathsf{log1p}\left({\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}^{2}\right)} - 1\right)} \]
  6. Step-by-step derivation
    1. expm1-def73.5%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left({\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}^{2}\right)\right)} \]
    2. expm1-log1p73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{{\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}^{2}} \]
    3. associate-*r*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot b\right)}}^{2} \]
    4. associate-*r*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\left(\left(\pi \cdot angle\right) \cdot 0.005555555555555556\right)} \cdot b\right)}^{2} \]
    5. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)} \cdot b\right)}^{2} \]
    6. metadata-eval73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\left(\color{blue}{\frac{-1}{-180}} \cdot \left(\pi \cdot angle\right)\right) \cdot b\right)}^{2} \]
    7. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\frac{-1}{\frac{-180}{\pi \cdot angle}}} \cdot b\right)}^{2} \]
    8. associate-*l/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{-1 \cdot b}{\frac{-180}{\pi \cdot angle}}\right)}}^{2} \]
    9. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{-1 \cdot b}{-180} \cdot \left(\pi \cdot angle\right)\right)}}^{2} \]
    10. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\frac{\color{blue}{b \cdot -1}}{-180} \cdot \left(\pi \cdot angle\right)\right)}^{2} \]
    11. associate-/l*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\frac{b}{\frac{-180}{-1}}} \cdot \left(\pi \cdot angle\right)\right)}^{2} \]
    12. metadata-eval73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\frac{b}{\color{blue}{180}} \cdot \left(\pi \cdot angle\right)\right)}^{2} \]
    13. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{b}{\frac{180}{\pi \cdot angle}}\right)}}^{2} \]
    14. associate-/r*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\frac{b}{\color{blue}{\frac{\frac{180}{\pi}}{angle}}}\right)}^{2} \]
    15. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{b}{\frac{180}{\pi}} \cdot angle\right)}}^{2} \]
    16. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(angle \cdot \frac{b}{\frac{180}{\pi}}\right)}}^{2} \]
    17. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(angle \cdot \color{blue}{\left(\frac{b}{180} \cdot \pi\right)}\right)}^{2} \]
  7. Simplified73.9%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{{\left(angle \cdot \left(\frac{b}{180} \cdot \pi\right)\right)}^{2}} \]
  8. Final simplification73.9%

    \[\leadsto {a}^{2} + {\left(angle \cdot \left(\pi \cdot \frac{b}{180}\right)\right)}^{2} \]

Alternative 11: 74.0% accurate, 2.0× speedup?

\[\begin{array}{l} angle_m = \left|angle\right| \\ {a}^{2} + {\left(angle_m \cdot \frac{\pi}{\frac{180}{b}}\right)}^{2} \end{array} \]
angle_m = (fabs.f64 angle)
(FPCore (a b angle_m)
 :precision binary64
 (+ (pow a 2.0) (pow (* angle_m (/ PI (/ 180.0 b))) 2.0)))
angle_m = fabs(angle);
double code(double a, double b, double angle_m) {
	return pow(a, 2.0) + pow((angle_m * (((double) M_PI) / (180.0 / b))), 2.0);
}
angle_m = Math.abs(angle);
public static double code(double a, double b, double angle_m) {
	return Math.pow(a, 2.0) + Math.pow((angle_m * (Math.PI / (180.0 / b))), 2.0);
}
angle_m = math.fabs(angle)
def code(a, b, angle_m):
	return math.pow(a, 2.0) + math.pow((angle_m * (math.pi / (180.0 / b))), 2.0)
angle_m = abs(angle)
function code(a, b, angle_m)
	return Float64((a ^ 2.0) + (Float64(angle_m * Float64(pi / Float64(180.0 / b))) ^ 2.0))
end
angle_m = abs(angle);
function tmp = code(a, b, angle_m)
	tmp = (a ^ 2.0) + ((angle_m * (pi / (180.0 / b))) ^ 2.0);
end
angle_m = N[Abs[angle], $MachinePrecision]
code[a_, b_, angle$95$m_] := N[(N[Power[a, 2.0], $MachinePrecision] + N[Power[N[(angle$95$m * N[(Pi / N[(180.0 / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
angle_m = \left|angle\right|

\\
{a}^{2} + {\left(angle_m \cdot \frac{\pi}{\frac{180}{b}}\right)}^{2}
\end{array}
Derivation
  1. Initial program 80.2%

    \[{\left(a \cdot \cos \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  2. Taylor expanded in angle around 0 80.0%

    \[\leadsto {\left(a \cdot \color{blue}{1}\right)}^{2} + {\left(b \cdot \sin \left(\pi \cdot \frac{angle}{180}\right)\right)}^{2} \]
  3. Taylor expanded in angle around 0 73.9%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(b \cdot \color{blue}{\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)}\right)}^{2} \]
  4. Step-by-step derivation
    1. expm1-log1p-u73.5%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left({\left(b \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)\right)}^{2}\right)\right)} \]
    2. expm1-udef70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(e^{\mathsf{log1p}\left({\left(b \cdot \left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right)\right)}^{2}\right)} - 1\right)} \]
    3. *-commutative70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\color{blue}{\left(\left(0.005555555555555556 \cdot \left(angle \cdot \pi\right)\right) \cdot b\right)}}^{2}\right)} - 1\right) \]
    4. associate-*r*70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\left(\color{blue}{\left(\left(0.005555555555555556 \cdot angle\right) \cdot \pi\right)} \cdot b\right)}^{2}\right)} - 1\right) \]
    5. *-commutative70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\left(\left(\color{blue}{\left(angle \cdot 0.005555555555555556\right)} \cdot \pi\right) \cdot b\right)}^{2}\right)} - 1\right) \]
    6. *-commutative70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\left(\color{blue}{\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right)} \cdot b\right)}^{2}\right)} - 1\right) \]
    7. associate-*l*70.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \left(e^{\mathsf{log1p}\left({\color{blue}{\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}}^{2}\right)} - 1\right) \]
  5. Applied egg-rr70.9%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\left(e^{\mathsf{log1p}\left({\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}^{2}\right)} - 1\right)} \]
  6. Step-by-step derivation
    1. expm1-def73.5%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left({\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}^{2}\right)\right)} \]
    2. expm1-log1p73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{{\left(\pi \cdot \left(\left(angle \cdot 0.005555555555555556\right) \cdot b\right)\right)}^{2}} \]
    3. associate-*r*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\left(\pi \cdot \left(angle \cdot 0.005555555555555556\right)\right) \cdot b\right)}}^{2} \]
    4. associate-*r*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\left(\left(\pi \cdot angle\right) \cdot 0.005555555555555556\right)} \cdot b\right)}^{2} \]
    5. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\left(0.005555555555555556 \cdot \left(\pi \cdot angle\right)\right)} \cdot b\right)}^{2} \]
    6. metadata-eval73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\left(\color{blue}{\frac{-1}{-180}} \cdot \left(\pi \cdot angle\right)\right) \cdot b\right)}^{2} \]
    7. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\frac{-1}{\frac{-180}{\pi \cdot angle}}} \cdot b\right)}^{2} \]
    8. associate-*l/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{-1 \cdot b}{\frac{-180}{\pi \cdot angle}}\right)}}^{2} \]
    9. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{-1 \cdot b}{-180} \cdot \left(\pi \cdot angle\right)\right)}}^{2} \]
    10. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\frac{\color{blue}{b \cdot -1}}{-180} \cdot \left(\pi \cdot angle\right)\right)}^{2} \]
    11. associate-/l*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\color{blue}{\frac{b}{\frac{-180}{-1}}} \cdot \left(\pi \cdot angle\right)\right)}^{2} \]
    12. metadata-eval73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\frac{b}{\color{blue}{180}} \cdot \left(\pi \cdot angle\right)\right)}^{2} \]
    13. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{b}{\frac{180}{\pi \cdot angle}}\right)}}^{2} \]
    14. associate-/r*73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(\frac{b}{\color{blue}{\frac{\frac{180}{\pi}}{angle}}}\right)}^{2} \]
    15. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(\frac{b}{\frac{180}{\pi}} \cdot angle\right)}}^{2} \]
    16. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\color{blue}{\left(angle \cdot \frac{b}{\frac{180}{\pi}}\right)}}^{2} \]
    17. associate-/r/73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(angle \cdot \color{blue}{\left(\frac{b}{180} \cdot \pi\right)}\right)}^{2} \]
  7. Simplified73.9%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + \color{blue}{{\left(angle \cdot \left(\frac{b}{180} \cdot \pi\right)\right)}^{2}} \]
  8. Step-by-step derivation
    1. *-commutative73.9%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(angle \cdot \color{blue}{\left(\pi \cdot \frac{b}{180}\right)}\right)}^{2} \]
    2. clear-num74.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(angle \cdot \left(\pi \cdot \color{blue}{\frac{1}{\frac{180}{b}}}\right)\right)}^{2} \]
    3. un-div-inv74.0%

      \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(angle \cdot \color{blue}{\frac{\pi}{\frac{180}{b}}}\right)}^{2} \]
  9. Applied egg-rr74.0%

    \[\leadsto {\left(a \cdot 1\right)}^{2} + {\left(angle \cdot \color{blue}{\frac{\pi}{\frac{180}{b}}}\right)}^{2} \]
  10. Final simplification74.0%

    \[\leadsto {a}^{2} + {\left(angle \cdot \frac{\pi}{\frac{180}{b}}\right)}^{2} \]

Reproduce

?
herbie shell --seed 2023337 
(FPCore (a b angle)
  :name "ab-angle->ABCF C"
  :precision binary64
  (+ (pow (* a (cos (* PI (/ angle 180.0)))) 2.0) (pow (* b (sin (* PI (/ angle 180.0)))) 2.0)))