NMSE Section 6.1 mentioned, A

Percentage Accurate: 72.7% → 98.9%
Time: 16.0s
Alternatives: 17
Speedup: 2.0×

Specification

?
\[\begin{array}{l} \\ \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \end{array} \]
(FPCore (x eps)
 :precision binary64
 (/
  (-
   (* (+ 1.0 (/ 1.0 eps)) (exp (- (* (- 1.0 eps) x))))
   (* (- (/ 1.0 eps) 1.0) (exp (- (* (+ 1.0 eps) x)))))
  2.0))
double code(double x, double eps) {
	return (((1.0 + (1.0 / eps)) * exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * exp(-((1.0 + eps) * x)))) / 2.0;
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = (((1.0d0 + (1.0d0 / eps)) * exp(-((1.0d0 - eps) * x))) - (((1.0d0 / eps) - 1.0d0) * exp(-((1.0d0 + eps) * x)))) / 2.0d0
end function
public static double code(double x, double eps) {
	return (((1.0 + (1.0 / eps)) * Math.exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * Math.exp(-((1.0 + eps) * x)))) / 2.0;
}
def code(x, eps):
	return (((1.0 + (1.0 / eps)) * math.exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * math.exp(-((1.0 + eps) * x)))) / 2.0
function code(x, eps)
	return Float64(Float64(Float64(Float64(1.0 + Float64(1.0 / eps)) * exp(Float64(-Float64(Float64(1.0 - eps) * x)))) - Float64(Float64(Float64(1.0 / eps) - 1.0) * exp(Float64(-Float64(Float64(1.0 + eps) * x))))) / 2.0)
end
function tmp = code(x, eps)
	tmp = (((1.0 + (1.0 / eps)) * exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * exp(-((1.0 + eps) * x)))) / 2.0;
end
code[x_, eps_] := N[(N[(N[(N[(1.0 + N[(1.0 / eps), $MachinePrecision]), $MachinePrecision] * N[Exp[(-N[(N[(1.0 - eps), $MachinePrecision] * x), $MachinePrecision])], $MachinePrecision]), $MachinePrecision] - N[(N[(N[(1.0 / eps), $MachinePrecision] - 1.0), $MachinePrecision] * N[Exp[(-N[(N[(1.0 + eps), $MachinePrecision] * x), $MachinePrecision])], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 17 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 72.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \end{array} \]
(FPCore (x eps)
 :precision binary64
 (/
  (-
   (* (+ 1.0 (/ 1.0 eps)) (exp (- (* (- 1.0 eps) x))))
   (* (- (/ 1.0 eps) 1.0) (exp (- (* (+ 1.0 eps) x)))))
  2.0))
double code(double x, double eps) {
	return (((1.0 + (1.0 / eps)) * exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * exp(-((1.0 + eps) * x)))) / 2.0;
}
real(8) function code(x, eps)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps
    code = (((1.0d0 + (1.0d0 / eps)) * exp(-((1.0d0 - eps) * x))) - (((1.0d0 / eps) - 1.0d0) * exp(-((1.0d0 + eps) * x)))) / 2.0d0
end function
public static double code(double x, double eps) {
	return (((1.0 + (1.0 / eps)) * Math.exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * Math.exp(-((1.0 + eps) * x)))) / 2.0;
}
def code(x, eps):
	return (((1.0 + (1.0 / eps)) * math.exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * math.exp(-((1.0 + eps) * x)))) / 2.0
function code(x, eps)
	return Float64(Float64(Float64(Float64(1.0 + Float64(1.0 / eps)) * exp(Float64(-Float64(Float64(1.0 - eps) * x)))) - Float64(Float64(Float64(1.0 / eps) - 1.0) * exp(Float64(-Float64(Float64(1.0 + eps) * x))))) / 2.0)
end
function tmp = code(x, eps)
	tmp = (((1.0 + (1.0 / eps)) * exp(-((1.0 - eps) * x))) - (((1.0 / eps) - 1.0) * exp(-((1.0 + eps) * x)))) / 2.0;
end
code[x_, eps_] := N[(N[(N[(N[(1.0 + N[(1.0 / eps), $MachinePrecision]), $MachinePrecision] * N[Exp[(-N[(N[(1.0 - eps), $MachinePrecision] * x), $MachinePrecision])], $MachinePrecision]), $MachinePrecision] - N[(N[(N[(1.0 / eps), $MachinePrecision] - 1.0), $MachinePrecision] * N[Exp[(-N[(N[(1.0 + eps), $MachinePrecision] * x), $MachinePrecision])], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2}
\end{array}

Alternative 1: 98.9% accurate, 1.1× speedup?

\[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{t_0 + e^{x - x \cdot eps_m}}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
eps_m = (fabs.f64 eps)
(FPCore (x eps_m)
 :precision binary64
 (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
   (if (<= x 2.6e-6) (/ (+ t_0 (exp (- x (* x eps_m)))) 2.0) (* t_0 0.5))))
eps_m = fabs(eps);
double code(double x, double eps_m) {
	double t_0 = exp((x * (eps_m + -1.0)));
	double tmp;
	if (x <= 2.6e-6) {
		tmp = (t_0 + exp((x - (x * eps_m)))) / 2.0;
	} else {
		tmp = t_0 * 0.5;
	}
	return tmp;
}
eps_m = abs(eps)
real(8) function code(x, eps_m)
    real(8), intent (in) :: x
    real(8), intent (in) :: eps_m
    real(8) :: t_0
    real(8) :: tmp
    t_0 = exp((x * (eps_m + (-1.0d0))))
    if (x <= 2.6d-6) then
        tmp = (t_0 + exp((x - (x * eps_m)))) / 2.0d0
    else
        tmp = t_0 * 0.5d0
    end if
    code = tmp
end function
eps_m = Math.abs(eps);
public static double code(double x, double eps_m) {
	double t_0 = Math.exp((x * (eps_m + -1.0)));
	double tmp;
	if (x <= 2.6e-6) {
		tmp = (t_0 + Math.exp((x - (x * eps_m)))) / 2.0;
	} else {
		tmp = t_0 * 0.5;
	}
	return tmp;
}
eps_m = math.fabs(eps)
def code(x, eps_m):
	t_0 = math.exp((x * (eps_m + -1.0)))
	tmp = 0
	if x <= 2.6e-6:
		tmp = (t_0 + math.exp((x - (x * eps_m)))) / 2.0
	else:
		tmp = t_0 * 0.5
	return tmp
eps_m = abs(eps)
function code(x, eps_m)
	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
	tmp = 0.0
	if (x <= 2.6e-6)
		tmp = Float64(Float64(t_0 + exp(Float64(x - Float64(x * eps_m)))) / 2.0);
	else
		tmp = Float64(t_0 * 0.5);
	end
	return tmp
end
eps_m = abs(eps);
function tmp_2 = code(x, eps_m)
	t_0 = exp((x * (eps_m + -1.0)));
	tmp = 0.0;
	if (x <= 2.6e-6)
		tmp = (t_0 + exp((x - (x * eps_m)))) / 2.0;
	else
		tmp = t_0 * 0.5;
	end
	tmp_2 = tmp;
end
eps_m = N[Abs[eps], $MachinePrecision]
code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, 2.6e-6], N[(N[(t$95$0 + N[Exp[N[(x - N[(x * eps$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]
\begin{array}{l}
eps_m = \left|\varepsilon\right|

\\
\begin{array}{l}
t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
\mathbf{if}\;x \leq 2.6 \cdot 10^{-6}:\\
\;\;\;\;\frac{t_0 + e^{x - x \cdot eps_m}}{2}\\

\mathbf{else}:\\
\;\;\;\;t_0 \cdot 0.5\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < 2.60000000000000009e-6

    1. Initial program 57.9%

      \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
    2. Step-by-step derivation
      1. Simplified57.9%

        \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
      2. Taylor expanded in eps around inf 99.2%

        \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)} - -1 \cdot e^{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}}{2} \]
      3. Simplified99.2%

        \[\leadsto \frac{\color{blue}{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-x\right) \cdot \left(\varepsilon + 1\right)}\right)}}{2} \]
      4. Step-by-step derivation
        1. neg-mul-199.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot x\right)} \cdot \left(\varepsilon + 1\right)}\right)}{2} \]
        2. +-commutative99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-1 \cdot x\right) \cdot \color{blue}{\left(1 + \varepsilon\right)}}\right)}{2} \]
        3. associate-*r*99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}\right)}{2} \]
        4. distribute-rgt-in99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \color{blue}{\left(1 \cdot x + \varepsilon \cdot x\right)}}\right)}{2} \]
        5. *-un-lft-identity99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \left(\color{blue}{x} + \varepsilon \cdot x\right)}\right)}{2} \]
        6. distribute-lft-in99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
        7. neg-mul-199.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-x\right)} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
        8. add-sqr-sqrt57.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
        9. sqrt-unprod93.6%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
        10. sqr-neg93.6%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\sqrt{\color{blue}{x \cdot x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
        11. sqrt-unprod42.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{x} \cdot \sqrt{x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
        12. add-sqr-sqrt99.7%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
      5. Applied egg-rr99.7%

        \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
      6. Step-by-step derivation
        1. mul-1-neg99.7%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \color{blue}{\left(-\varepsilon \cdot x\right)}}\right)}{2} \]
        2. *-commutative99.7%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \left(-\color{blue}{x \cdot \varepsilon}\right)}\right)}{2} \]
        3. sub-neg99.7%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
      7. Simplified99.7%

        \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]

      if 2.60000000000000009e-6 < x

      1. Initial program 100.0%

        \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
      2. Simplified100.0%

        \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
      3. Taylor expanded in eps around inf 100.0%

        \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
      4. Taylor expanded in x around 0 35.6%

        \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
      5. Taylor expanded in x around inf 79.4%

        \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification94.4%

      \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{e^{x \cdot \left(\varepsilon + -1\right)} + e^{x - x \cdot \varepsilon}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

    Alternative 2: 98.7% accurate, 0.7× speedup?

    \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \frac{\frac{1}{e^{\mathsf{fma}\left(eps_m, x, x\right)}} + e^{x \cdot \left(eps_m + -1\right)}}{2} \end{array} \]
    eps_m = (fabs.f64 eps)
    (FPCore (x eps_m)
     :precision binary64
     (/ (+ (/ 1.0 (exp (fma eps_m x x))) (exp (* x (+ eps_m -1.0)))) 2.0))
    eps_m = fabs(eps);
    double code(double x, double eps_m) {
    	return ((1.0 / exp(fma(eps_m, x, x))) + exp((x * (eps_m + -1.0)))) / 2.0;
    }
    
    eps_m = abs(eps)
    function code(x, eps_m)
    	return Float64(Float64(Float64(1.0 / exp(fma(eps_m, x, x))) + exp(Float64(x * Float64(eps_m + -1.0)))) / 2.0)
    end
    
    eps_m = N[Abs[eps], $MachinePrecision]
    code[x_, eps$95$m_] := N[(N[(N[(1.0 / N[Exp[N[(eps$95$m * x + x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]
    
    \begin{array}{l}
    eps_m = \left|\varepsilon\right|
    
    \\
    \frac{\frac{1}{e^{\mathsf{fma}\left(eps_m, x, x\right)}} + e^{x \cdot \left(eps_m + -1\right)}}{2}
    \end{array}
    
    Derivation
    1. Initial program 68.9%

      \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
    2. Simplified63.6%

      \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
    3. Taylor expanded in eps around inf 99.4%

      \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
    4. Final simplification99.4%

      \[\leadsto \frac{\frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}} + e^{x \cdot \left(\varepsilon + -1\right)}}{2} \]

    Alternative 3: 98.7% accurate, 1.1× speedup?

    \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{t_0 + e^{eps_m \cdot \left(-x\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
    eps_m = (fabs.f64 eps)
    (FPCore (x eps_m)
     :precision binary64
     (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
       (if (<= x 2.6e-6) (/ (+ t_0 (exp (* eps_m (- x)))) 2.0) (* t_0 0.5))))
    eps_m = fabs(eps);
    double code(double x, double eps_m) {
    	double t_0 = exp((x * (eps_m + -1.0)));
    	double tmp;
    	if (x <= 2.6e-6) {
    		tmp = (t_0 + exp((eps_m * -x))) / 2.0;
    	} else {
    		tmp = t_0 * 0.5;
    	}
    	return tmp;
    }
    
    eps_m = abs(eps)
    real(8) function code(x, eps_m)
        real(8), intent (in) :: x
        real(8), intent (in) :: eps_m
        real(8) :: t_0
        real(8) :: tmp
        t_0 = exp((x * (eps_m + (-1.0d0))))
        if (x <= 2.6d-6) then
            tmp = (t_0 + exp((eps_m * -x))) / 2.0d0
        else
            tmp = t_0 * 0.5d0
        end if
        code = tmp
    end function
    
    eps_m = Math.abs(eps);
    public static double code(double x, double eps_m) {
    	double t_0 = Math.exp((x * (eps_m + -1.0)));
    	double tmp;
    	if (x <= 2.6e-6) {
    		tmp = (t_0 + Math.exp((eps_m * -x))) / 2.0;
    	} else {
    		tmp = t_0 * 0.5;
    	}
    	return tmp;
    }
    
    eps_m = math.fabs(eps)
    def code(x, eps_m):
    	t_0 = math.exp((x * (eps_m + -1.0)))
    	tmp = 0
    	if x <= 2.6e-6:
    		tmp = (t_0 + math.exp((eps_m * -x))) / 2.0
    	else:
    		tmp = t_0 * 0.5
    	return tmp
    
    eps_m = abs(eps)
    function code(x, eps_m)
    	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
    	tmp = 0.0
    	if (x <= 2.6e-6)
    		tmp = Float64(Float64(t_0 + exp(Float64(eps_m * Float64(-x)))) / 2.0);
    	else
    		tmp = Float64(t_0 * 0.5);
    	end
    	return tmp
    end
    
    eps_m = abs(eps);
    function tmp_2 = code(x, eps_m)
    	t_0 = exp((x * (eps_m + -1.0)));
    	tmp = 0.0;
    	if (x <= 2.6e-6)
    		tmp = (t_0 + exp((eps_m * -x))) / 2.0;
    	else
    		tmp = t_0 * 0.5;
    	end
    	tmp_2 = tmp;
    end
    
    eps_m = N[Abs[eps], $MachinePrecision]
    code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, 2.6e-6], N[(N[(t$95$0 + N[Exp[N[(eps$95$m * (-x)), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]
    
    \begin{array}{l}
    eps_m = \left|\varepsilon\right|
    
    \\
    \begin{array}{l}
    t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
    \mathbf{if}\;x \leq 2.6 \cdot 10^{-6}:\\
    \;\;\;\;\frac{t_0 + e^{eps_m \cdot \left(-x\right)}}{2}\\
    
    \mathbf{else}:\\
    \;\;\;\;t_0 \cdot 0.5\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if x < 2.60000000000000009e-6

      1. Initial program 57.9%

        \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
      2. Step-by-step derivation
        1. Simplified57.9%

          \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
        2. Taylor expanded in eps around inf 99.2%

          \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)} - -1 \cdot e^{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}}{2} \]
        3. Simplified99.2%

          \[\leadsto \frac{\color{blue}{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-x\right) \cdot \left(\varepsilon + 1\right)}\right)}}{2} \]
        4. Step-by-step derivation
          1. neg-mul-199.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot x\right)} \cdot \left(\varepsilon + 1\right)}\right)}{2} \]
          2. +-commutative99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-1 \cdot x\right) \cdot \color{blue}{\left(1 + \varepsilon\right)}}\right)}{2} \]
          3. associate-*r*99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}\right)}{2} \]
          4. distribute-rgt-in99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \color{blue}{\left(1 \cdot x + \varepsilon \cdot x\right)}}\right)}{2} \]
          5. *-un-lft-identity99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \left(\color{blue}{x} + \varepsilon \cdot x\right)}\right)}{2} \]
          6. distribute-lft-in99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
          7. neg-mul-199.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-x\right)} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
          8. add-sqr-sqrt57.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
          9. sqrt-unprod93.6%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
          10. sqr-neg93.6%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\sqrt{\color{blue}{x \cdot x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
          11. sqrt-unprod42.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{x} \cdot \sqrt{x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
          12. add-sqr-sqrt99.7%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
        5. Applied egg-rr99.7%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
        6. Step-by-step derivation
          1. mul-1-neg99.7%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \color{blue}{\left(-\varepsilon \cdot x\right)}}\right)}{2} \]
          2. *-commutative99.7%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \left(-\color{blue}{x \cdot \varepsilon}\right)}\right)}{2} \]
          3. sub-neg99.7%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
        7. Simplified99.7%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
        8. Taylor expanded in eps around inf 99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
        9. Step-by-step derivation
          1. associate-*r*99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot \varepsilon\right) \cdot x}}\right)}{2} \]
          2. neg-mul-199.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-\varepsilon\right)} \cdot x}\right)}{2} \]
          3. *-commutative99.2%

            \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
        10. Simplified99.2%

          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
        11. Taylor expanded in x around inf 99.2%

          \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(\varepsilon \cdot x\right)} + e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)}}}{2} \]
        12. Step-by-step derivation
          1. associate-*r*99.2%

            \[\leadsto \frac{e^{\color{blue}{\left(-1 \cdot \varepsilon\right) \cdot x}} + e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)}}{2} \]
          2. mul-1-neg99.2%

            \[\leadsto \frac{e^{\color{blue}{\left(-\varepsilon\right)} \cdot x} + e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)}}{2} \]
          3. associate-*r*99.2%

            \[\leadsto \frac{e^{\left(-\varepsilon\right) \cdot x} + e^{\color{blue}{\left(-1 \cdot x\right) \cdot \left(1 - \varepsilon\right)}}}{2} \]
          4. neg-mul-199.2%

            \[\leadsto \frac{e^{\left(-\varepsilon\right) \cdot x} + e^{\color{blue}{\left(-x\right)} \cdot \left(1 - \varepsilon\right)}}{2} \]
        13. Simplified99.2%

          \[\leadsto \frac{\color{blue}{e^{\left(-\varepsilon\right) \cdot x} + e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)}}}{2} \]

        if 2.60000000000000009e-6 < x

        1. Initial program 100.0%

          \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
        2. Simplified100.0%

          \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
        3. Taylor expanded in eps around inf 100.0%

          \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
        4. Taylor expanded in x around 0 35.6%

          \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
        5. Taylor expanded in x around inf 79.4%

          \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification94.0%

        \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{e^{x \cdot \left(\varepsilon + -1\right)} + e^{\varepsilon \cdot \left(-x\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

      Alternative 4: 98.7% accurate, 1.1× speedup?

      \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \frac{e^{x \cdot \left(eps_m + -1\right)} + e^{x \cdot \left(-1 - eps_m\right)}}{2} \end{array} \]
      eps_m = (fabs.f64 eps)
      (FPCore (x eps_m)
       :precision binary64
       (/ (+ (exp (* x (+ eps_m -1.0))) (exp (* x (- -1.0 eps_m)))) 2.0))
      eps_m = fabs(eps);
      double code(double x, double eps_m) {
      	return (exp((x * (eps_m + -1.0))) + exp((x * (-1.0 - eps_m)))) / 2.0;
      }
      
      eps_m = abs(eps)
      real(8) function code(x, eps_m)
          real(8), intent (in) :: x
          real(8), intent (in) :: eps_m
          code = (exp((x * (eps_m + (-1.0d0)))) + exp((x * ((-1.0d0) - eps_m)))) / 2.0d0
      end function
      
      eps_m = Math.abs(eps);
      public static double code(double x, double eps_m) {
      	return (Math.exp((x * (eps_m + -1.0))) + Math.exp((x * (-1.0 - eps_m)))) / 2.0;
      }
      
      eps_m = math.fabs(eps)
      def code(x, eps_m):
      	return (math.exp((x * (eps_m + -1.0))) + math.exp((x * (-1.0 - eps_m)))) / 2.0
      
      eps_m = abs(eps)
      function code(x, eps_m)
      	return Float64(Float64(exp(Float64(x * Float64(eps_m + -1.0))) + exp(Float64(x * Float64(-1.0 - eps_m)))) / 2.0)
      end
      
      eps_m = abs(eps);
      function tmp = code(x, eps_m)
      	tmp = (exp((x * (eps_m + -1.0))) + exp((x * (-1.0 - eps_m)))) / 2.0;
      end
      
      eps_m = N[Abs[eps], $MachinePrecision]
      code[x_, eps$95$m_] := N[(N[(N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + N[Exp[N[(x * N[(-1.0 - eps$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]
      
      \begin{array}{l}
      eps_m = \left|\varepsilon\right|
      
      \\
      \frac{e^{x \cdot \left(eps_m + -1\right)} + e^{x \cdot \left(-1 - eps_m\right)}}{2}
      \end{array}
      
      Derivation
      1. Initial program 68.9%

        \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
      2. Step-by-step derivation
        1. Simplified68.9%

          \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
        2. Taylor expanded in eps around inf 99.4%

          \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)} - -1 \cdot e^{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}}{2} \]
        3. Simplified99.4%

          \[\leadsto \frac{\color{blue}{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-x\right) \cdot \left(\varepsilon + 1\right)}\right)}}{2} \]
        4. Final simplification99.4%

          \[\leadsto \frac{e^{x \cdot \left(\varepsilon + -1\right)} + e^{x \cdot \left(-1 - \varepsilon\right)}}{2} \]

        Alternative 5: 98.0% accurate, 1.1× speedup?

        \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq -5 \cdot 10^{-273}:\\ \;\;\;\;\frac{1 + \frac{1}{e^{\mathsf{fma}\left(eps_m, x, x\right)}}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{t_0 + \frac{1}{1 + x \cdot \left(eps_m + 1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
        eps_m = (fabs.f64 eps)
        (FPCore (x eps_m)
         :precision binary64
         (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
           (if (<= x -5e-273)
             (/ (+ 1.0 (/ 1.0 (exp (fma eps_m x x)))) 2.0)
             (if (<= x 2.6e-6)
               (/ (+ t_0 (/ 1.0 (+ 1.0 (* x (+ eps_m 1.0))))) 2.0)
               (* t_0 0.5)))))
        eps_m = fabs(eps);
        double code(double x, double eps_m) {
        	double t_0 = exp((x * (eps_m + -1.0)));
        	double tmp;
        	if (x <= -5e-273) {
        		tmp = (1.0 + (1.0 / exp(fma(eps_m, x, x)))) / 2.0;
        	} else if (x <= 2.6e-6) {
        		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0;
        	} else {
        		tmp = t_0 * 0.5;
        	}
        	return tmp;
        }
        
        eps_m = abs(eps)
        function code(x, eps_m)
        	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
        	tmp = 0.0
        	if (x <= -5e-273)
        		tmp = Float64(Float64(1.0 + Float64(1.0 / exp(fma(eps_m, x, x)))) / 2.0);
        	elseif (x <= 2.6e-6)
        		tmp = Float64(Float64(t_0 + Float64(1.0 / Float64(1.0 + Float64(x * Float64(eps_m + 1.0))))) / 2.0);
        	else
        		tmp = Float64(t_0 * 0.5);
        	end
        	return tmp
        end
        
        eps_m = N[Abs[eps], $MachinePrecision]
        code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, -5e-273], N[(N[(1.0 + N[(1.0 / N[Exp[N[(eps$95$m * x + x), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 2.6e-6], N[(N[(t$95$0 + N[(1.0 / N[(1.0 + N[(x * N[(eps$95$m + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]]
        
        \begin{array}{l}
        eps_m = \left|\varepsilon\right|
        
        \\
        \begin{array}{l}
        t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
        \mathbf{if}\;x \leq -5 \cdot 10^{-273}:\\
        \;\;\;\;\frac{1 + \frac{1}{e^{\mathsf{fma}\left(eps_m, x, x\right)}}}{2}\\
        
        \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
        \;\;\;\;\frac{t_0 + \frac{1}{1 + x \cdot \left(eps_m + 1\right)}}{2}\\
        
        \mathbf{else}:\\
        \;\;\;\;t_0 \cdot 0.5\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 3 regimes
        2. if x < -4.99999999999999965e-273

          1. Initial program 69.5%

            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
          2. Simplified64.2%

            \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
          3. Taylor expanded in eps around inf 99.0%

            \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
          4. Taylor expanded in x around 0 69.1%

            \[\leadsto \frac{\color{blue}{1} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}{2} \]

          if -4.99999999999999965e-273 < x < 2.60000000000000009e-6

          1. Initial program 44.3%

            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
          2. Simplified34.9%

            \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
          3. Taylor expanded in eps around inf 99.3%

            \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
          4. Taylor expanded in x around 0 87.8%

            \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]

          if 2.60000000000000009e-6 < x

          1. Initial program 100.0%

            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
          2. Simplified100.0%

            \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
          3. Taylor expanded in eps around inf 100.0%

            \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
          4. Taylor expanded in x around 0 35.6%

            \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
          5. Taylor expanded in x around inf 79.4%

            \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
        3. Recombined 3 regimes into one program.
        4. Final simplification78.2%

          \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -5 \cdot 10^{-273}:\\ \;\;\;\;\frac{1 + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{e^{x \cdot \left(\varepsilon + -1\right)} + \frac{1}{1 + x \cdot \left(\varepsilon + 1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

        Alternative 6: 98.1% accurate, 1.8× speedup?

        \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq -55000000:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\ \mathbf{elif}\;x \leq -2 \cdot 10^{-267}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) + e^{eps_m \cdot \left(-x\right)}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{t_0 + \frac{1}{1 + x \cdot \left(eps_m + 1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
        eps_m = (fabs.f64 eps)
        (FPCore (x eps_m)
         :precision binary64
         (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
           (if (<= x -55000000.0)
             (/ (/ (expm1 (- x)) eps_m) 2.0)
             (if (<= x -2e-267)
               (/ (+ (- 1.0 (* x (- 1.0 eps_m))) (exp (* eps_m (- x)))) 2.0)
               (if (<= x 2.6e-6)
                 (/ (+ t_0 (/ 1.0 (+ 1.0 (* x (+ eps_m 1.0))))) 2.0)
                 (* t_0 0.5))))))
        eps_m = fabs(eps);
        double code(double x, double eps_m) {
        	double t_0 = exp((x * (eps_m + -1.0)));
        	double tmp;
        	if (x <= -55000000.0) {
        		tmp = (expm1(-x) / eps_m) / 2.0;
        	} else if (x <= -2e-267) {
        		tmp = ((1.0 - (x * (1.0 - eps_m))) + exp((eps_m * -x))) / 2.0;
        	} else if (x <= 2.6e-6) {
        		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0;
        	} else {
        		tmp = t_0 * 0.5;
        	}
        	return tmp;
        }
        
        eps_m = Math.abs(eps);
        public static double code(double x, double eps_m) {
        	double t_0 = Math.exp((x * (eps_m + -1.0)));
        	double tmp;
        	if (x <= -55000000.0) {
        		tmp = (Math.expm1(-x) / eps_m) / 2.0;
        	} else if (x <= -2e-267) {
        		tmp = ((1.0 - (x * (1.0 - eps_m))) + Math.exp((eps_m * -x))) / 2.0;
        	} else if (x <= 2.6e-6) {
        		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0;
        	} else {
        		tmp = t_0 * 0.5;
        	}
        	return tmp;
        }
        
        eps_m = math.fabs(eps)
        def code(x, eps_m):
        	t_0 = math.exp((x * (eps_m + -1.0)))
        	tmp = 0
        	if x <= -55000000.0:
        		tmp = (math.expm1(-x) / eps_m) / 2.0
        	elif x <= -2e-267:
        		tmp = ((1.0 - (x * (1.0 - eps_m))) + math.exp((eps_m * -x))) / 2.0
        	elif x <= 2.6e-6:
        		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0
        	else:
        		tmp = t_0 * 0.5
        	return tmp
        
        eps_m = abs(eps)
        function code(x, eps_m)
        	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
        	tmp = 0.0
        	if (x <= -55000000.0)
        		tmp = Float64(Float64(expm1(Float64(-x)) / eps_m) / 2.0);
        	elseif (x <= -2e-267)
        		tmp = Float64(Float64(Float64(1.0 - Float64(x * Float64(1.0 - eps_m))) + exp(Float64(eps_m * Float64(-x)))) / 2.0);
        	elseif (x <= 2.6e-6)
        		tmp = Float64(Float64(t_0 + Float64(1.0 / Float64(1.0 + Float64(x * Float64(eps_m + 1.0))))) / 2.0);
        	else
        		tmp = Float64(t_0 * 0.5);
        	end
        	return tmp
        end
        
        eps_m = N[Abs[eps], $MachinePrecision]
        code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, -55000000.0], N[(N[(N[(Exp[(-x)] - 1), $MachinePrecision] / eps$95$m), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, -2e-267], N[(N[(N[(1.0 - N[(x * N[(1.0 - eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[Exp[N[(eps$95$m * (-x)), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 2.6e-6], N[(N[(t$95$0 + N[(1.0 / N[(1.0 + N[(x * N[(eps$95$m + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]]]
        
        \begin{array}{l}
        eps_m = \left|\varepsilon\right|
        
        \\
        \begin{array}{l}
        t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
        \mathbf{if}\;x \leq -55000000:\\
        \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\
        
        \mathbf{elif}\;x \leq -2 \cdot 10^{-267}:\\
        \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) + e^{eps_m \cdot \left(-x\right)}}{2}\\
        
        \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
        \;\;\;\;\frac{t_0 + \frac{1}{1 + x \cdot \left(eps_m + 1\right)}}{2}\\
        
        \mathbf{else}:\\
        \;\;\;\;t_0 \cdot 0.5\\
        
        
        \end{array}
        \end{array}
        
        Derivation
        1. Split input into 4 regimes
        2. if x < -5.5e7

          1. Initial program 100.0%

            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
          2. Step-by-step derivation
            1. Simplified100.0%

              \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
            2. Taylor expanded in x around 0 59.8%

              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
            3. Taylor expanded in eps around 0 41.5%

              \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot x} - 1}{\varepsilon}}}{2} \]
            4. Step-by-step derivation
              1. expm1-def41.5%

                \[\leadsto \frac{\frac{\color{blue}{\mathsf{expm1}\left(-1 \cdot x\right)}}{\varepsilon}}{2} \]
              2. mul-1-neg41.5%

                \[\leadsto \frac{\frac{\mathsf{expm1}\left(\color{blue}{-x}\right)}{\varepsilon}}{2} \]
            5. Simplified41.5%

              \[\leadsto \frac{\color{blue}{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}}{2} \]

            if -5.5e7 < x < -2e-267

            1. Initial program 49.0%

              \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
            2. Step-by-step derivation
              1. Simplified49.0%

                \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
              2. Taylor expanded in eps around inf 98.4%

                \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)} - -1 \cdot e^{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}}{2} \]
              3. Simplified98.4%

                \[\leadsto \frac{\color{blue}{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-x\right) \cdot \left(\varepsilon + 1\right)}\right)}}{2} \]
              4. Step-by-step derivation
                1. neg-mul-198.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot x\right)} \cdot \left(\varepsilon + 1\right)}\right)}{2} \]
                2. +-commutative98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-1 \cdot x\right) \cdot \color{blue}{\left(1 + \varepsilon\right)}}\right)}{2} \]
                3. associate-*r*98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}\right)}{2} \]
                4. distribute-rgt-in98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \color{blue}{\left(1 \cdot x + \varepsilon \cdot x\right)}}\right)}{2} \]
                5. *-un-lft-identity98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \left(\color{blue}{x} + \varepsilon \cdot x\right)}\right)}{2} \]
                6. distribute-lft-in98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
                7. neg-mul-198.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-x\right)} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                8. add-sqr-sqrt98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                9. sqrt-unprod98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                10. sqr-neg98.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\sqrt{\color{blue}{x \cdot x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                11. sqrt-unprod0.0%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{x} \cdot \sqrt{x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                12. add-sqr-sqrt99.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
              5. Applied egg-rr99.4%

                \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
              6. Step-by-step derivation
                1. mul-1-neg99.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \color{blue}{\left(-\varepsilon \cdot x\right)}}\right)}{2} \]
                2. *-commutative99.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \left(-\color{blue}{x \cdot \varepsilon}\right)}\right)}{2} \]
                3. sub-neg99.4%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
              7. Simplified99.4%

                \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
              8. Taylor expanded in eps around inf 98.5%

                \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
              9. Step-by-step derivation
                1. associate-*r*98.5%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot \varepsilon\right) \cdot x}}\right)}{2} \]
                2. neg-mul-198.5%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-\varepsilon\right)} \cdot x}\right)}{2} \]
                3. *-commutative98.5%

                  \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
              10. Simplified98.5%

                \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
              11. Taylor expanded in x around 0 86.7%

                \[\leadsto \frac{\color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
              12. Step-by-step derivation
                1. mul-1-neg86.7%

                  \[\leadsto \frac{\left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                2. distribute-lft-neg-out86.7%

                  \[\leadsto \frac{\left(1 + \color{blue}{\left(-x\right) \cdot \left(1 - \varepsilon\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                3. *-commutative86.7%

                  \[\leadsto \frac{\left(1 + \color{blue}{\left(1 - \varepsilon\right) \cdot \left(-x\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
              13. Simplified86.7%

                \[\leadsto \frac{\color{blue}{\left(1 + \left(1 - \varepsilon\right) \cdot \left(-x\right)\right)} - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]

              if -2e-267 < x < 2.60000000000000009e-6

              1. Initial program 44.3%

                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
              2. Simplified34.9%

                \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
              3. Taylor expanded in eps around inf 99.3%

                \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
              4. Taylor expanded in x around 0 87.8%

                \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]

              if 2.60000000000000009e-6 < x

              1. Initial program 100.0%

                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
              2. Simplified100.0%

                \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
              3. Taylor expanded in eps around inf 100.0%

                \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
              4. Taylor expanded in x around 0 35.6%

                \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
              5. Taylor expanded in x around inf 79.4%

                \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
            3. Recombined 4 regimes into one program.
            4. Final simplification77.9%

              \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -55000000:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}{2}\\ \mathbf{elif}\;x \leq -2 \cdot 10^{-267}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - \varepsilon\right)\right) + e^{\varepsilon \cdot \left(-x\right)}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{e^{x \cdot \left(\varepsilon + -1\right)} + \frac{1}{1 + x \cdot \left(\varepsilon + 1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

            Alternative 7: 98.2% accurate, 1.8× speedup?

            \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq -4 \cdot 10^{+16}:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\ \mathbf{elif}\;x \leq -5 \cdot 10^{-271}:\\ \;\;\;\;\frac{e^{x - x \cdot eps_m} + \left(1 - x \cdot \left(1 - eps_m\right)\right)}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{t_0 + \frac{1}{1 + x \cdot \left(eps_m + 1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
            eps_m = (fabs.f64 eps)
            (FPCore (x eps_m)
             :precision binary64
             (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
               (if (<= x -4e+16)
                 (/ (/ (expm1 (- x)) eps_m) 2.0)
                 (if (<= x -5e-271)
                   (/ (+ (exp (- x (* x eps_m))) (- 1.0 (* x (- 1.0 eps_m)))) 2.0)
                   (if (<= x 2.6e-6)
                     (/ (+ t_0 (/ 1.0 (+ 1.0 (* x (+ eps_m 1.0))))) 2.0)
                     (* t_0 0.5))))))
            eps_m = fabs(eps);
            double code(double x, double eps_m) {
            	double t_0 = exp((x * (eps_m + -1.0)));
            	double tmp;
            	if (x <= -4e+16) {
            		tmp = (expm1(-x) / eps_m) / 2.0;
            	} else if (x <= -5e-271) {
            		tmp = (exp((x - (x * eps_m))) + (1.0 - (x * (1.0 - eps_m)))) / 2.0;
            	} else if (x <= 2.6e-6) {
            		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0;
            	} else {
            		tmp = t_0 * 0.5;
            	}
            	return tmp;
            }
            
            eps_m = Math.abs(eps);
            public static double code(double x, double eps_m) {
            	double t_0 = Math.exp((x * (eps_m + -1.0)));
            	double tmp;
            	if (x <= -4e+16) {
            		tmp = (Math.expm1(-x) / eps_m) / 2.0;
            	} else if (x <= -5e-271) {
            		tmp = (Math.exp((x - (x * eps_m))) + (1.0 - (x * (1.0 - eps_m)))) / 2.0;
            	} else if (x <= 2.6e-6) {
            		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0;
            	} else {
            		tmp = t_0 * 0.5;
            	}
            	return tmp;
            }
            
            eps_m = math.fabs(eps)
            def code(x, eps_m):
            	t_0 = math.exp((x * (eps_m + -1.0)))
            	tmp = 0
            	if x <= -4e+16:
            		tmp = (math.expm1(-x) / eps_m) / 2.0
            	elif x <= -5e-271:
            		tmp = (math.exp((x - (x * eps_m))) + (1.0 - (x * (1.0 - eps_m)))) / 2.0
            	elif x <= 2.6e-6:
            		tmp = (t_0 + (1.0 / (1.0 + (x * (eps_m + 1.0))))) / 2.0
            	else:
            		tmp = t_0 * 0.5
            	return tmp
            
            eps_m = abs(eps)
            function code(x, eps_m)
            	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
            	tmp = 0.0
            	if (x <= -4e+16)
            		tmp = Float64(Float64(expm1(Float64(-x)) / eps_m) / 2.0);
            	elseif (x <= -5e-271)
            		tmp = Float64(Float64(exp(Float64(x - Float64(x * eps_m))) + Float64(1.0 - Float64(x * Float64(1.0 - eps_m)))) / 2.0);
            	elseif (x <= 2.6e-6)
            		tmp = Float64(Float64(t_0 + Float64(1.0 / Float64(1.0 + Float64(x * Float64(eps_m + 1.0))))) / 2.0);
            	else
            		tmp = Float64(t_0 * 0.5);
            	end
            	return tmp
            end
            
            eps_m = N[Abs[eps], $MachinePrecision]
            code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, -4e+16], N[(N[(N[(Exp[(-x)] - 1), $MachinePrecision] / eps$95$m), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, -5e-271], N[(N[(N[Exp[N[(x - N[(x * eps$95$m), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] + N[(1.0 - N[(x * N[(1.0 - eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 2.6e-6], N[(N[(t$95$0 + N[(1.0 / N[(1.0 + N[(x * N[(eps$95$m + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]]]
            
            \begin{array}{l}
            eps_m = \left|\varepsilon\right|
            
            \\
            \begin{array}{l}
            t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
            \mathbf{if}\;x \leq -4 \cdot 10^{+16}:\\
            \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\
            
            \mathbf{elif}\;x \leq -5 \cdot 10^{-271}:\\
            \;\;\;\;\frac{e^{x - x \cdot eps_m} + \left(1 - x \cdot \left(1 - eps_m\right)\right)}{2}\\
            
            \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
            \;\;\;\;\frac{t_0 + \frac{1}{1 + x \cdot \left(eps_m + 1\right)}}{2}\\
            
            \mathbf{else}:\\
            \;\;\;\;t_0 \cdot 0.5\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 4 regimes
            2. if x < -4e16

              1. Initial program 100.0%

                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
              2. Step-by-step derivation
                1. Simplified100.0%

                  \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                2. Taylor expanded in x around 0 59.8%

                  \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                3. Taylor expanded in eps around 0 41.5%

                  \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot x} - 1}{\varepsilon}}}{2} \]
                4. Step-by-step derivation
                  1. expm1-def41.5%

                    \[\leadsto \frac{\frac{\color{blue}{\mathsf{expm1}\left(-1 \cdot x\right)}}{\varepsilon}}{2} \]
                  2. mul-1-neg41.5%

                    \[\leadsto \frac{\frac{\mathsf{expm1}\left(\color{blue}{-x}\right)}{\varepsilon}}{2} \]
                5. Simplified41.5%

                  \[\leadsto \frac{\color{blue}{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}}{2} \]

                if -4e16 < x < -5.0000000000000002e-271

                1. Initial program 49.0%

                  \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                2. Step-by-step derivation
                  1. Simplified49.0%

                    \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                  2. Taylor expanded in eps around inf 98.4%

                    \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)} - -1 \cdot e^{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}}{2} \]
                  3. Simplified98.4%

                    \[\leadsto \frac{\color{blue}{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-x\right) \cdot \left(\varepsilon + 1\right)}\right)}}{2} \]
                  4. Step-by-step derivation
                    1. neg-mul-198.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot x\right)} \cdot \left(\varepsilon + 1\right)}\right)}{2} \]
                    2. +-commutative98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-1 \cdot x\right) \cdot \color{blue}{\left(1 + \varepsilon\right)}}\right)}{2} \]
                    3. associate-*r*98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}\right)}{2} \]
                    4. distribute-rgt-in98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \color{blue}{\left(1 \cdot x + \varepsilon \cdot x\right)}}\right)}{2} \]
                    5. *-un-lft-identity98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \left(\color{blue}{x} + \varepsilon \cdot x\right)}\right)}{2} \]
                    6. distribute-lft-in98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
                    7. neg-mul-198.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-x\right)} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                    8. add-sqr-sqrt98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                    9. sqrt-unprod98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                    10. sqr-neg98.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\sqrt{\color{blue}{x \cdot x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                    11. sqrt-unprod0.0%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{x} \cdot \sqrt{x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                    12. add-sqr-sqrt99.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                  5. Applied egg-rr99.4%

                    \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
                  6. Step-by-step derivation
                    1. mul-1-neg99.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \color{blue}{\left(-\varepsilon \cdot x\right)}}\right)}{2} \]
                    2. *-commutative99.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \left(-\color{blue}{x \cdot \varepsilon}\right)}\right)}{2} \]
                    3. sub-neg99.4%

                      \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
                  7. Simplified99.4%

                    \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
                  8. Taylor expanded in x around 0 87.6%

                    \[\leadsto \frac{\color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(-e^{x - x \cdot \varepsilon}\right)}{2} \]
                  9. Step-by-step derivation
                    1. mul-1-neg86.7%

                      \[\leadsto \frac{\left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                    2. distribute-lft-neg-out86.7%

                      \[\leadsto \frac{\left(1 + \color{blue}{\left(-x\right) \cdot \left(1 - \varepsilon\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                    3. *-commutative86.7%

                      \[\leadsto \frac{\left(1 + \color{blue}{\left(1 - \varepsilon\right) \cdot \left(-x\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                  10. Simplified87.6%

                    \[\leadsto \frac{\color{blue}{\left(1 + \left(1 - \varepsilon\right) \cdot \left(-x\right)\right)} - \left(-e^{x - x \cdot \varepsilon}\right)}{2} \]

                  if -5.0000000000000002e-271 < x < 2.60000000000000009e-6

                  1. Initial program 44.3%

                    \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                  2. Simplified34.9%

                    \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                  3. Taylor expanded in eps around inf 99.3%

                    \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                  4. Taylor expanded in x around 0 87.8%

                    \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]

                  if 2.60000000000000009e-6 < x

                  1. Initial program 100.0%

                    \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                  2. Simplified100.0%

                    \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                  3. Taylor expanded in eps around inf 100.0%

                    \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                  4. Taylor expanded in x around 0 35.6%

                    \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
                  5. Taylor expanded in x around inf 79.4%

                    \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
                3. Recombined 4 regimes into one program.
                4. Final simplification78.1%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -4 \cdot 10^{+16}:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}{2}\\ \mathbf{elif}\;x \leq -5 \cdot 10^{-271}:\\ \;\;\;\;\frac{e^{x - x \cdot \varepsilon} + \left(1 - x \cdot \left(1 - \varepsilon\right)\right)}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{e^{x \cdot \left(\varepsilon + -1\right)} + \frac{1}{1 + x \cdot \left(\varepsilon + 1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

                Alternative 8: 97.9% accurate, 1.9× speedup?

                \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq -4 \cdot 10^{+16}:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\ \mathbf{elif}\;x \leq -5 \cdot 10^{-271}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) + e^{eps_m \cdot \left(-x\right)}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{1 + t_0}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
                eps_m = (fabs.f64 eps)
                (FPCore (x eps_m)
                 :precision binary64
                 (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
                   (if (<= x -4e+16)
                     (/ (/ (expm1 (- x)) eps_m) 2.0)
                     (if (<= x -5e-271)
                       (/ (+ (- 1.0 (* x (- 1.0 eps_m))) (exp (* eps_m (- x)))) 2.0)
                       (if (<= x 2.6e-6) (/ (+ 1.0 t_0) 2.0) (* t_0 0.5))))))
                eps_m = fabs(eps);
                double code(double x, double eps_m) {
                	double t_0 = exp((x * (eps_m + -1.0)));
                	double tmp;
                	if (x <= -4e+16) {
                		tmp = (expm1(-x) / eps_m) / 2.0;
                	} else if (x <= -5e-271) {
                		tmp = ((1.0 - (x * (1.0 - eps_m))) + exp((eps_m * -x))) / 2.0;
                	} else if (x <= 2.6e-6) {
                		tmp = (1.0 + t_0) / 2.0;
                	} else {
                		tmp = t_0 * 0.5;
                	}
                	return tmp;
                }
                
                eps_m = Math.abs(eps);
                public static double code(double x, double eps_m) {
                	double t_0 = Math.exp((x * (eps_m + -1.0)));
                	double tmp;
                	if (x <= -4e+16) {
                		tmp = (Math.expm1(-x) / eps_m) / 2.0;
                	} else if (x <= -5e-271) {
                		tmp = ((1.0 - (x * (1.0 - eps_m))) + Math.exp((eps_m * -x))) / 2.0;
                	} else if (x <= 2.6e-6) {
                		tmp = (1.0 + t_0) / 2.0;
                	} else {
                		tmp = t_0 * 0.5;
                	}
                	return tmp;
                }
                
                eps_m = math.fabs(eps)
                def code(x, eps_m):
                	t_0 = math.exp((x * (eps_m + -1.0)))
                	tmp = 0
                	if x <= -4e+16:
                		tmp = (math.expm1(-x) / eps_m) / 2.0
                	elif x <= -5e-271:
                		tmp = ((1.0 - (x * (1.0 - eps_m))) + math.exp((eps_m * -x))) / 2.0
                	elif x <= 2.6e-6:
                		tmp = (1.0 + t_0) / 2.0
                	else:
                		tmp = t_0 * 0.5
                	return tmp
                
                eps_m = abs(eps)
                function code(x, eps_m)
                	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
                	tmp = 0.0
                	if (x <= -4e+16)
                		tmp = Float64(Float64(expm1(Float64(-x)) / eps_m) / 2.0);
                	elseif (x <= -5e-271)
                		tmp = Float64(Float64(Float64(1.0 - Float64(x * Float64(1.0 - eps_m))) + exp(Float64(eps_m * Float64(-x)))) / 2.0);
                	elseif (x <= 2.6e-6)
                		tmp = Float64(Float64(1.0 + t_0) / 2.0);
                	else
                		tmp = Float64(t_0 * 0.5);
                	end
                	return tmp
                end
                
                eps_m = N[Abs[eps], $MachinePrecision]
                code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, -4e+16], N[(N[(N[(Exp[(-x)] - 1), $MachinePrecision] / eps$95$m), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, -5e-271], N[(N[(N[(1.0 - N[(x * N[(1.0 - eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[Exp[N[(eps$95$m * (-x)), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 2.6e-6], N[(N[(1.0 + t$95$0), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]]]
                
                \begin{array}{l}
                eps_m = \left|\varepsilon\right|
                
                \\
                \begin{array}{l}
                t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
                \mathbf{if}\;x \leq -4 \cdot 10^{+16}:\\
                \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\
                
                \mathbf{elif}\;x \leq -5 \cdot 10^{-271}:\\
                \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) + e^{eps_m \cdot \left(-x\right)}}{2}\\
                
                \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
                \;\;\;\;\frac{1 + t_0}{2}\\
                
                \mathbf{else}:\\
                \;\;\;\;t_0 \cdot 0.5\\
                
                
                \end{array}
                \end{array}
                
                Derivation
                1. Split input into 4 regimes
                2. if x < -4e16

                  1. Initial program 100.0%

                    \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                  2. Step-by-step derivation
                    1. Simplified100.0%

                      \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                    2. Taylor expanded in x around 0 59.8%

                      \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                    3. Taylor expanded in eps around 0 41.5%

                      \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot x} - 1}{\varepsilon}}}{2} \]
                    4. Step-by-step derivation
                      1. expm1-def41.5%

                        \[\leadsto \frac{\frac{\color{blue}{\mathsf{expm1}\left(-1 \cdot x\right)}}{\varepsilon}}{2} \]
                      2. mul-1-neg41.5%

                        \[\leadsto \frac{\frac{\mathsf{expm1}\left(\color{blue}{-x}\right)}{\varepsilon}}{2} \]
                    5. Simplified41.5%

                      \[\leadsto \frac{\color{blue}{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}}{2} \]

                    if -4e16 < x < -5.0000000000000002e-271

                    1. Initial program 49.0%

                      \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                    2. Step-by-step derivation
                      1. Simplified49.0%

                        \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                      2. Taylor expanded in eps around inf 98.4%

                        \[\leadsto \frac{\color{blue}{e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)} - -1 \cdot e^{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}}{2} \]
                      3. Simplified98.4%

                        \[\leadsto \frac{\color{blue}{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-x\right) \cdot \left(\varepsilon + 1\right)}\right)}}{2} \]
                      4. Step-by-step derivation
                        1. neg-mul-198.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot x\right)} \cdot \left(\varepsilon + 1\right)}\right)}{2} \]
                        2. +-commutative98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\left(-1 \cdot x\right) \cdot \color{blue}{\left(1 + \varepsilon\right)}}\right)}{2} \]
                        3. associate-*r*98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)}}\right)}{2} \]
                        4. distribute-rgt-in98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \color{blue}{\left(1 \cdot x + \varepsilon \cdot x\right)}}\right)}{2} \]
                        5. *-un-lft-identity98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{-1 \cdot \left(\color{blue}{x} + \varepsilon \cdot x\right)}\right)}{2} \]
                        6. distribute-lft-in98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
                        7. neg-mul-198.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-x\right)} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                        8. add-sqr-sqrt98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{-x} \cdot \sqrt{-x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                        9. sqrt-unprod98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{\left(-x\right) \cdot \left(-x\right)}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                        10. sqr-neg98.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\sqrt{\color{blue}{x \cdot x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                        11. sqrt-unprod0.0%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\sqrt{x} \cdot \sqrt{x}} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                        12. add-sqr-sqrt99.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x} + -1 \cdot \left(\varepsilon \cdot x\right)}\right)}{2} \]
                      5. Applied egg-rr99.4%

                        \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x + -1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
                      6. Step-by-step derivation
                        1. mul-1-neg99.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \color{blue}{\left(-\varepsilon \cdot x\right)}}\right)}{2} \]
                        2. *-commutative99.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{x + \left(-\color{blue}{x \cdot \varepsilon}\right)}\right)}{2} \]
                        3. sub-neg99.4%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
                      7. Simplified99.4%

                        \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x - x \cdot \varepsilon}}\right)}{2} \]
                      8. Taylor expanded in eps around inf 98.5%

                        \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{-1 \cdot \left(\varepsilon \cdot x\right)}}\right)}{2} \]
                      9. Step-by-step derivation
                        1. associate-*r*98.5%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-1 \cdot \varepsilon\right) \cdot x}}\right)}{2} \]
                        2. neg-mul-198.5%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{\left(-\varepsilon\right)} \cdot x}\right)}{2} \]
                        3. *-commutative98.5%

                          \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
                      10. Simplified98.5%

                        \[\leadsto \frac{e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)} - \left(-e^{\color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
                      11. Taylor expanded in x around 0 86.7%

                        \[\leadsto \frac{\color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                      12. Step-by-step derivation
                        1. mul-1-neg86.7%

                          \[\leadsto \frac{\left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                        2. distribute-lft-neg-out86.7%

                          \[\leadsto \frac{\left(1 + \color{blue}{\left(-x\right) \cdot \left(1 - \varepsilon\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                        3. *-commutative86.7%

                          \[\leadsto \frac{\left(1 + \color{blue}{\left(1 - \varepsilon\right) \cdot \left(-x\right)}\right) - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]
                      13. Simplified86.7%

                        \[\leadsto \frac{\color{blue}{\left(1 + \left(1 - \varepsilon\right) \cdot \left(-x\right)\right)} - \left(-e^{x \cdot \left(-\varepsilon\right)}\right)}{2} \]

                      if -5.0000000000000002e-271 < x < 2.60000000000000009e-6

                      1. Initial program 44.3%

                        \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                      2. Step-by-step derivation
                        1. Simplified44.3%

                          \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                        2. Taylor expanded in x around 0 32.8%

                          \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                        3. Taylor expanded in eps around inf 87.7%

                          \[\leadsto \frac{\color{blue}{1 + e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)}}}{2} \]
                        4. Step-by-step derivation
                          1. sub-neg87.7%

                            \[\leadsto \frac{1 + e^{-1 \cdot \left(x \cdot \color{blue}{\left(1 + \left(-\varepsilon\right)\right)}\right)}}{2} \]
                          2. neg-mul-187.7%

                            \[\leadsto \frac{1 + e^{-1 \cdot \left(x \cdot \left(1 + \color{blue}{-1 \cdot \varepsilon}\right)\right)}}{2} \]
                          3. associate-*r*87.7%

                            \[\leadsto \frac{1 + e^{\color{blue}{\left(-1 \cdot x\right) \cdot \left(1 + -1 \cdot \varepsilon\right)}}}{2} \]
                          4. mul-1-neg87.7%

                            \[\leadsto \frac{1 + e^{\color{blue}{\left(-x\right)} \cdot \left(1 + -1 \cdot \varepsilon\right)}}{2} \]
                          5. neg-mul-187.7%

                            \[\leadsto \frac{1 + e^{\left(-x\right) \cdot \left(1 + \color{blue}{\left(-\varepsilon\right)}\right)}}{2} \]
                          6. sub-neg87.7%

                            \[\leadsto \frac{1 + e^{\left(-x\right) \cdot \color{blue}{\left(1 - \varepsilon\right)}}}{2} \]
                        5. Simplified87.7%

                          \[\leadsto \frac{\color{blue}{1 + e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)}}}{2} \]

                        if 2.60000000000000009e-6 < x

                        1. Initial program 100.0%

                          \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                        2. Simplified100.0%

                          \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                        3. Taylor expanded in eps around inf 100.0%

                          \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                        4. Taylor expanded in x around 0 35.6%

                          \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
                        5. Taylor expanded in x around inf 79.4%

                          \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
                      3. Recombined 4 regimes into one program.
                      4. Final simplification77.9%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -4 \cdot 10^{+16}:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}{2}\\ \mathbf{elif}\;x \leq -5 \cdot 10^{-271}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - \varepsilon\right)\right) + e^{\varepsilon \cdot \left(-x\right)}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{1 + e^{x \cdot \left(\varepsilon + -1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

                      Alternative 9: 84.4% accurate, 2.0× speedup?

                      \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -320:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\ \mathbf{elif}\;x \leq 1.35 \cdot 10^{-97}:\\ \;\;\;\;1\\ \mathbf{elif}\;x \leq 1.7 \cdot 10^{-38} \lor \neg \left(x \leq 6.6 \cdot 10^{-15}\right):\\ \;\;\;\;e^{x \cdot \left(eps_m + -1\right)} \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \end{array} \]
                      eps_m = (fabs.f64 eps)
                      (FPCore (x eps_m)
                       :precision binary64
                       (if (<= x -320.0)
                         (/ (/ (expm1 (- x)) eps_m) 2.0)
                         (if (<= x 1.35e-97)
                           1.0
                           (if (or (<= x 1.7e-38) (not (<= x 6.6e-15)))
                             (* (exp (* x (+ eps_m -1.0))) 0.5)
                             1.0))))
                      eps_m = fabs(eps);
                      double code(double x, double eps_m) {
                      	double tmp;
                      	if (x <= -320.0) {
                      		tmp = (expm1(-x) / eps_m) / 2.0;
                      	} else if (x <= 1.35e-97) {
                      		tmp = 1.0;
                      	} else if ((x <= 1.7e-38) || !(x <= 6.6e-15)) {
                      		tmp = exp((x * (eps_m + -1.0))) * 0.5;
                      	} else {
                      		tmp = 1.0;
                      	}
                      	return tmp;
                      }
                      
                      eps_m = Math.abs(eps);
                      public static double code(double x, double eps_m) {
                      	double tmp;
                      	if (x <= -320.0) {
                      		tmp = (Math.expm1(-x) / eps_m) / 2.0;
                      	} else if (x <= 1.35e-97) {
                      		tmp = 1.0;
                      	} else if ((x <= 1.7e-38) || !(x <= 6.6e-15)) {
                      		tmp = Math.exp((x * (eps_m + -1.0))) * 0.5;
                      	} else {
                      		tmp = 1.0;
                      	}
                      	return tmp;
                      }
                      
                      eps_m = math.fabs(eps)
                      def code(x, eps_m):
                      	tmp = 0
                      	if x <= -320.0:
                      		tmp = (math.expm1(-x) / eps_m) / 2.0
                      	elif x <= 1.35e-97:
                      		tmp = 1.0
                      	elif (x <= 1.7e-38) or not (x <= 6.6e-15):
                      		tmp = math.exp((x * (eps_m + -1.0))) * 0.5
                      	else:
                      		tmp = 1.0
                      	return tmp
                      
                      eps_m = abs(eps)
                      function code(x, eps_m)
                      	tmp = 0.0
                      	if (x <= -320.0)
                      		tmp = Float64(Float64(expm1(Float64(-x)) / eps_m) / 2.0);
                      	elseif (x <= 1.35e-97)
                      		tmp = 1.0;
                      	elseif ((x <= 1.7e-38) || !(x <= 6.6e-15))
                      		tmp = Float64(exp(Float64(x * Float64(eps_m + -1.0))) * 0.5);
                      	else
                      		tmp = 1.0;
                      	end
                      	return tmp
                      end
                      
                      eps_m = N[Abs[eps], $MachinePrecision]
                      code[x_, eps$95$m_] := If[LessEqual[x, -320.0], N[(N[(N[(Exp[(-x)] - 1), $MachinePrecision] / eps$95$m), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 1.35e-97], 1.0, If[Or[LessEqual[x, 1.7e-38], N[Not[LessEqual[x, 6.6e-15]], $MachinePrecision]], N[(N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] * 0.5), $MachinePrecision], 1.0]]]
                      
                      \begin{array}{l}
                      eps_m = \left|\varepsilon\right|
                      
                      \\
                      \begin{array}{l}
                      \mathbf{if}\;x \leq -320:\\
                      \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\
                      
                      \mathbf{elif}\;x \leq 1.35 \cdot 10^{-97}:\\
                      \;\;\;\;1\\
                      
                      \mathbf{elif}\;x \leq 1.7 \cdot 10^{-38} \lor \neg \left(x \leq 6.6 \cdot 10^{-15}\right):\\
                      \;\;\;\;e^{x \cdot \left(eps_m + -1\right)} \cdot 0.5\\
                      
                      \mathbf{else}:\\
                      \;\;\;\;1\\
                      
                      
                      \end{array}
                      \end{array}
                      
                      Derivation
                      1. Split input into 3 regimes
                      2. if x < -320

                        1. Initial program 100.0%

                          \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                        2. Step-by-step derivation
                          1. Simplified100.0%

                            \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                          2. Taylor expanded in x around 0 59.8%

                            \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                          3. Taylor expanded in eps around 0 41.5%

                            \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot x} - 1}{\varepsilon}}}{2} \]
                          4. Step-by-step derivation
                            1. expm1-def41.5%

                              \[\leadsto \frac{\frac{\color{blue}{\mathsf{expm1}\left(-1 \cdot x\right)}}{\varepsilon}}{2} \]
                            2. mul-1-neg41.5%

                              \[\leadsto \frac{\frac{\mathsf{expm1}\left(\color{blue}{-x}\right)}{\varepsilon}}{2} \]
                          5. Simplified41.5%

                            \[\leadsto \frac{\color{blue}{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}}{2} \]

                          if -320 < x < 1.34999999999999993e-97 or 1.7000000000000001e-38 < x < 6.6e-15

                          1. Initial program 43.0%

                            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                          2. Step-by-step derivation
                            1. Simplified43.0%

                              \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                            2. Taylor expanded in x around 0 85.2%

                              \[\leadsto \frac{\color{blue}{2}}{2} \]

                            if 1.34999999999999993e-97 < x < 1.7000000000000001e-38 or 6.6e-15 < x

                            1. Initial program 91.3%

                              \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                            2. Simplified84.8%

                              \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                            3. Taylor expanded in eps around inf 99.4%

                              \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                            4. Taylor expanded in x around 0 43.2%

                              \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
                            5. Taylor expanded in x around inf 69.5%

                              \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
                          3. Recombined 3 regimes into one program.
                          4. Final simplification72.7%

                            \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -320:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}{2}\\ \mathbf{elif}\;x \leq 1.35 \cdot 10^{-97}:\\ \;\;\;\;1\\ \mathbf{elif}\;x \leq 1.7 \cdot 10^{-38} \lor \neg \left(x \leq 6.6 \cdot 10^{-15}\right):\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;1\\ \end{array} \]

                          Alternative 10: 90.8% accurate, 2.0× speedup?

                          \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} t_0 := e^{x \cdot \left(eps_m + -1\right)}\\ \mathbf{if}\;x \leq -380:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{1 + t_0}{2}\\ \mathbf{else}:\\ \;\;\;\;t_0 \cdot 0.5\\ \end{array} \end{array} \]
                          eps_m = (fabs.f64 eps)
                          (FPCore (x eps_m)
                           :precision binary64
                           (let* ((t_0 (exp (* x (+ eps_m -1.0)))))
                             (if (<= x -380.0)
                               (/ (/ (expm1 (- x)) eps_m) 2.0)
                               (if (<= x 2.6e-6) (/ (+ 1.0 t_0) 2.0) (* t_0 0.5)))))
                          eps_m = fabs(eps);
                          double code(double x, double eps_m) {
                          	double t_0 = exp((x * (eps_m + -1.0)));
                          	double tmp;
                          	if (x <= -380.0) {
                          		tmp = (expm1(-x) / eps_m) / 2.0;
                          	} else if (x <= 2.6e-6) {
                          		tmp = (1.0 + t_0) / 2.0;
                          	} else {
                          		tmp = t_0 * 0.5;
                          	}
                          	return tmp;
                          }
                          
                          eps_m = Math.abs(eps);
                          public static double code(double x, double eps_m) {
                          	double t_0 = Math.exp((x * (eps_m + -1.0)));
                          	double tmp;
                          	if (x <= -380.0) {
                          		tmp = (Math.expm1(-x) / eps_m) / 2.0;
                          	} else if (x <= 2.6e-6) {
                          		tmp = (1.0 + t_0) / 2.0;
                          	} else {
                          		tmp = t_0 * 0.5;
                          	}
                          	return tmp;
                          }
                          
                          eps_m = math.fabs(eps)
                          def code(x, eps_m):
                          	t_0 = math.exp((x * (eps_m + -1.0)))
                          	tmp = 0
                          	if x <= -380.0:
                          		tmp = (math.expm1(-x) / eps_m) / 2.0
                          	elif x <= 2.6e-6:
                          		tmp = (1.0 + t_0) / 2.0
                          	else:
                          		tmp = t_0 * 0.5
                          	return tmp
                          
                          eps_m = abs(eps)
                          function code(x, eps_m)
                          	t_0 = exp(Float64(x * Float64(eps_m + -1.0)))
                          	tmp = 0.0
                          	if (x <= -380.0)
                          		tmp = Float64(Float64(expm1(Float64(-x)) / eps_m) / 2.0);
                          	elseif (x <= 2.6e-6)
                          		tmp = Float64(Float64(1.0 + t_0) / 2.0);
                          	else
                          		tmp = Float64(t_0 * 0.5);
                          	end
                          	return tmp
                          end
                          
                          eps_m = N[Abs[eps], $MachinePrecision]
                          code[x_, eps$95$m_] := Block[{t$95$0 = N[Exp[N[(x * N[(eps$95$m + -1.0), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[x, -380.0], N[(N[(N[(Exp[(-x)] - 1), $MachinePrecision] / eps$95$m), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 2.6e-6], N[(N[(1.0 + t$95$0), $MachinePrecision] / 2.0), $MachinePrecision], N[(t$95$0 * 0.5), $MachinePrecision]]]]
                          
                          \begin{array}{l}
                          eps_m = \left|\varepsilon\right|
                          
                          \\
                          \begin{array}{l}
                          t_0 := e^{x \cdot \left(eps_m + -1\right)}\\
                          \mathbf{if}\;x \leq -380:\\
                          \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\
                          
                          \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
                          \;\;\;\;\frac{1 + t_0}{2}\\
                          
                          \mathbf{else}:\\
                          \;\;\;\;t_0 \cdot 0.5\\
                          
                          
                          \end{array}
                          \end{array}
                          
                          Derivation
                          1. Split input into 3 regimes
                          2. if x < -380

                            1. Initial program 100.0%

                              \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                            2. Step-by-step derivation
                              1. Simplified100.0%

                                \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                              2. Taylor expanded in x around 0 59.8%

                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                              3. Taylor expanded in eps around 0 41.5%

                                \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot x} - 1}{\varepsilon}}}{2} \]
                              4. Step-by-step derivation
                                1. expm1-def41.5%

                                  \[\leadsto \frac{\frac{\color{blue}{\mathsf{expm1}\left(-1 \cdot x\right)}}{\varepsilon}}{2} \]
                                2. mul-1-neg41.5%

                                  \[\leadsto \frac{\frac{\mathsf{expm1}\left(\color{blue}{-x}\right)}{\varepsilon}}{2} \]
                              5. Simplified41.5%

                                \[\leadsto \frac{\color{blue}{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}}{2} \]

                              if -380 < x < 2.60000000000000009e-6

                              1. Initial program 46.2%

                                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                              2. Step-by-step derivation
                                1. Simplified46.2%

                                  \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                2. Taylor expanded in x around 0 34.9%

                                  \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                                3. Taylor expanded in eps around inf 87.6%

                                  \[\leadsto \frac{\color{blue}{1 + e^{-1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)}}}{2} \]
                                4. Step-by-step derivation
                                  1. sub-neg87.6%

                                    \[\leadsto \frac{1 + e^{-1 \cdot \left(x \cdot \color{blue}{\left(1 + \left(-\varepsilon\right)\right)}\right)}}{2} \]
                                  2. neg-mul-187.6%

                                    \[\leadsto \frac{1 + e^{-1 \cdot \left(x \cdot \left(1 + \color{blue}{-1 \cdot \varepsilon}\right)\right)}}{2} \]
                                  3. associate-*r*87.6%

                                    \[\leadsto \frac{1 + e^{\color{blue}{\left(-1 \cdot x\right) \cdot \left(1 + -1 \cdot \varepsilon\right)}}}{2} \]
                                  4. mul-1-neg87.6%

                                    \[\leadsto \frac{1 + e^{\color{blue}{\left(-x\right)} \cdot \left(1 + -1 \cdot \varepsilon\right)}}{2} \]
                                  5. neg-mul-187.6%

                                    \[\leadsto \frac{1 + e^{\left(-x\right) \cdot \left(1 + \color{blue}{\left(-\varepsilon\right)}\right)}}{2} \]
                                  6. sub-neg87.6%

                                    \[\leadsto \frac{1 + e^{\left(-x\right) \cdot \color{blue}{\left(1 - \varepsilon\right)}}}{2} \]
                                5. Simplified87.6%

                                  \[\leadsto \frac{\color{blue}{1 + e^{\left(-x\right) \cdot \left(1 - \varepsilon\right)}}}{2} \]

                                if 2.60000000000000009e-6 < x

                                1. Initial program 100.0%

                                  \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                2. Simplified100.0%

                                  \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                                3. Taylor expanded in eps around inf 100.0%

                                  \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                                4. Taylor expanded in x around 0 35.6%

                                  \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
                                5. Taylor expanded in x around inf 79.4%

                                  \[\leadsto \color{blue}{0.5 \cdot e^{x \cdot \left(\varepsilon - 1\right)}} \]
                              3. Recombined 3 regimes into one program.
                              4. Final simplification78.1%

                                \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -380:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;\frac{1 + e^{x \cdot \left(\varepsilon + -1\right)}}{2}\\ \mathbf{else}:\\ \;\;\;\;e^{x \cdot \left(\varepsilon + -1\right)} \cdot 0.5\\ \end{array} \]

                              Alternative 11: 69.4% accurate, 2.1× speedup?

                              \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -550:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) \cdot \left(1 + \frac{1}{eps_m}\right) + \frac{x + -1}{eps_m}}{2}\\ \end{array} \end{array} \]
                              eps_m = (fabs.f64 eps)
                              (FPCore (x eps_m)
                               :precision binary64
                               (if (<= x -550.0)
                                 (/ (/ (expm1 (- x)) eps_m) 2.0)
                                 (if (<= x 2.6e-6)
                                   1.0
                                   (/
                                    (+
                                     (* (- 1.0 (* x (- 1.0 eps_m))) (+ 1.0 (/ 1.0 eps_m)))
                                     (/ (+ x -1.0) eps_m))
                                    2.0))))
                              eps_m = fabs(eps);
                              double code(double x, double eps_m) {
                              	double tmp;
                              	if (x <= -550.0) {
                              		tmp = (expm1(-x) / eps_m) / 2.0;
                              	} else if (x <= 2.6e-6) {
                              		tmp = 1.0;
                              	} else {
                              		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0;
                              	}
                              	return tmp;
                              }
                              
                              eps_m = Math.abs(eps);
                              public static double code(double x, double eps_m) {
                              	double tmp;
                              	if (x <= -550.0) {
                              		tmp = (Math.expm1(-x) / eps_m) / 2.0;
                              	} else if (x <= 2.6e-6) {
                              		tmp = 1.0;
                              	} else {
                              		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0;
                              	}
                              	return tmp;
                              }
                              
                              eps_m = math.fabs(eps)
                              def code(x, eps_m):
                              	tmp = 0
                              	if x <= -550.0:
                              		tmp = (math.expm1(-x) / eps_m) / 2.0
                              	elif x <= 2.6e-6:
                              		tmp = 1.0
                              	else:
                              		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0
                              	return tmp
                              
                              eps_m = abs(eps)
                              function code(x, eps_m)
                              	tmp = 0.0
                              	if (x <= -550.0)
                              		tmp = Float64(Float64(expm1(Float64(-x)) / eps_m) / 2.0);
                              	elseif (x <= 2.6e-6)
                              		tmp = 1.0;
                              	else
                              		tmp = Float64(Float64(Float64(Float64(1.0 - Float64(x * Float64(1.0 - eps_m))) * Float64(1.0 + Float64(1.0 / eps_m))) + Float64(Float64(x + -1.0) / eps_m)) / 2.0);
                              	end
                              	return tmp
                              end
                              
                              eps_m = N[Abs[eps], $MachinePrecision]
                              code[x_, eps$95$m_] := If[LessEqual[x, -550.0], N[(N[(N[(Exp[(-x)] - 1), $MachinePrecision] / eps$95$m), $MachinePrecision] / 2.0), $MachinePrecision], If[LessEqual[x, 2.6e-6], 1.0, N[(N[(N[(N[(1.0 - N[(x * N[(1.0 - eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(1.0 + N[(1.0 / eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(x + -1.0), $MachinePrecision] / eps$95$m), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]]]
                              
                              \begin{array}{l}
                              eps_m = \left|\varepsilon\right|
                              
                              \\
                              \begin{array}{l}
                              \mathbf{if}\;x \leq -550:\\
                              \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{eps_m}}{2}\\
                              
                              \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
                              \;\;\;\;1\\
                              
                              \mathbf{else}:\\
                              \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) \cdot \left(1 + \frac{1}{eps_m}\right) + \frac{x + -1}{eps_m}}{2}\\
                              
                              
                              \end{array}
                              \end{array}
                              
                              Derivation
                              1. Split input into 3 regimes
                              2. if x < -550

                                1. Initial program 100.0%

                                  \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                2. Step-by-step derivation
                                  1. Simplified100.0%

                                    \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                  2. Taylor expanded in x around 0 59.8%

                                    \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \color{blue}{\left(\frac{1}{\varepsilon} - 1\right)}}{2} \]
                                  3. Taylor expanded in eps around 0 41.5%

                                    \[\leadsto \frac{\color{blue}{\frac{e^{-1 \cdot x} - 1}{\varepsilon}}}{2} \]
                                  4. Step-by-step derivation
                                    1. expm1-def41.5%

                                      \[\leadsto \frac{\frac{\color{blue}{\mathsf{expm1}\left(-1 \cdot x\right)}}{\varepsilon}}{2} \]
                                    2. mul-1-neg41.5%

                                      \[\leadsto \frac{\frac{\mathsf{expm1}\left(\color{blue}{-x}\right)}{\varepsilon}}{2} \]
                                  5. Simplified41.5%

                                    \[\leadsto \frac{\color{blue}{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}}{2} \]

                                  if -550 < x < 2.60000000000000009e-6

                                  1. Initial program 46.2%

                                    \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                  2. Step-by-step derivation
                                    1. Simplified46.2%

                                      \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                    2. Taylor expanded in x around 0 78.1%

                                      \[\leadsto \frac{\color{blue}{2}}{2} \]

                                    if 2.60000000000000009e-6 < x

                                    1. Initial program 100.0%

                                      \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                    2. Step-by-step derivation
                                      1. Simplified100.0%

                                        \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                      2. Taylor expanded in x around 0 19.4%

                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                      3. Taylor expanded in x around 0 25.7%

                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                      4. Step-by-step derivation
                                        1. mul-1-neg25.7%

                                          \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                        2. unsub-neg25.7%

                                          \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                      5. Simplified25.7%

                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                      6. Taylor expanded in eps around 0 39.5%

                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \color{blue}{\frac{1 + -1 \cdot x}{\varepsilon}}}{2} \]
                                      7. Step-by-step derivation
                                        1. mul-1-neg39.5%

                                          \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \frac{1 + \color{blue}{\left(-x\right)}}{\varepsilon}}{2} \]
                                        2. unsub-neg39.5%

                                          \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \frac{\color{blue}{1 - x}}{\varepsilon}}{2} \]
                                      8. Simplified39.5%

                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \color{blue}{\frac{1 - x}{\varepsilon}}}{2} \]
                                    3. Recombined 3 regimes into one program.
                                    4. Final simplification62.2%

                                      \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -550:\\ \;\;\;\;\frac{\frac{\mathsf{expm1}\left(-x\right)}{\varepsilon}}{2}\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - \varepsilon\right)\right) \cdot \left(1 + \frac{1}{\varepsilon}\right) + \frac{x + -1}{\varepsilon}}{2}\\ \end{array} \]

                                    Alternative 12: 62.6% accurate, 9.0× speedup?

                                    \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -0.0016:\\ \;\;\;\;\left(x \cdot eps_m\right) \cdot -0.5\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) \cdot \left(1 + \frac{1}{eps_m}\right) + \frac{x + -1}{eps_m}}{2}\\ \end{array} \end{array} \]
                                    eps_m = (fabs.f64 eps)
                                    (FPCore (x eps_m)
                                     :precision binary64
                                     (if (<= x -0.0016)
                                       (* (* x eps_m) -0.5)
                                       (if (<= x 2.6e-6)
                                         1.0
                                         (/
                                          (+
                                           (* (- 1.0 (* x (- 1.0 eps_m))) (+ 1.0 (/ 1.0 eps_m)))
                                           (/ (+ x -1.0) eps_m))
                                          2.0))))
                                    eps_m = fabs(eps);
                                    double code(double x, double eps_m) {
                                    	double tmp;
                                    	if (x <= -0.0016) {
                                    		tmp = (x * eps_m) * -0.5;
                                    	} else if (x <= 2.6e-6) {
                                    		tmp = 1.0;
                                    	} else {
                                    		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0;
                                    	}
                                    	return tmp;
                                    }
                                    
                                    eps_m = abs(eps)
                                    real(8) function code(x, eps_m)
                                        real(8), intent (in) :: x
                                        real(8), intent (in) :: eps_m
                                        real(8) :: tmp
                                        if (x <= (-0.0016d0)) then
                                            tmp = (x * eps_m) * (-0.5d0)
                                        else if (x <= 2.6d-6) then
                                            tmp = 1.0d0
                                        else
                                            tmp = (((1.0d0 - (x * (1.0d0 - eps_m))) * (1.0d0 + (1.0d0 / eps_m))) + ((x + (-1.0d0)) / eps_m)) / 2.0d0
                                        end if
                                        code = tmp
                                    end function
                                    
                                    eps_m = Math.abs(eps);
                                    public static double code(double x, double eps_m) {
                                    	double tmp;
                                    	if (x <= -0.0016) {
                                    		tmp = (x * eps_m) * -0.5;
                                    	} else if (x <= 2.6e-6) {
                                    		tmp = 1.0;
                                    	} else {
                                    		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0;
                                    	}
                                    	return tmp;
                                    }
                                    
                                    eps_m = math.fabs(eps)
                                    def code(x, eps_m):
                                    	tmp = 0
                                    	if x <= -0.0016:
                                    		tmp = (x * eps_m) * -0.5
                                    	elif x <= 2.6e-6:
                                    		tmp = 1.0
                                    	else:
                                    		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0
                                    	return tmp
                                    
                                    eps_m = abs(eps)
                                    function code(x, eps_m)
                                    	tmp = 0.0
                                    	if (x <= -0.0016)
                                    		tmp = Float64(Float64(x * eps_m) * -0.5);
                                    	elseif (x <= 2.6e-6)
                                    		tmp = 1.0;
                                    	else
                                    		tmp = Float64(Float64(Float64(Float64(1.0 - Float64(x * Float64(1.0 - eps_m))) * Float64(1.0 + Float64(1.0 / eps_m))) + Float64(Float64(x + -1.0) / eps_m)) / 2.0);
                                    	end
                                    	return tmp
                                    end
                                    
                                    eps_m = abs(eps);
                                    function tmp_2 = code(x, eps_m)
                                    	tmp = 0.0;
                                    	if (x <= -0.0016)
                                    		tmp = (x * eps_m) * -0.5;
                                    	elseif (x <= 2.6e-6)
                                    		tmp = 1.0;
                                    	else
                                    		tmp = (((1.0 - (x * (1.0 - eps_m))) * (1.0 + (1.0 / eps_m))) + ((x + -1.0) / eps_m)) / 2.0;
                                    	end
                                    	tmp_2 = tmp;
                                    end
                                    
                                    eps_m = N[Abs[eps], $MachinePrecision]
                                    code[x_, eps$95$m_] := If[LessEqual[x, -0.0016], N[(N[(x * eps$95$m), $MachinePrecision] * -0.5), $MachinePrecision], If[LessEqual[x, 2.6e-6], 1.0, N[(N[(N[(N[(1.0 - N[(x * N[(1.0 - eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(1.0 + N[(1.0 / eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(N[(x + -1.0), $MachinePrecision] / eps$95$m), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]]]
                                    
                                    \begin{array}{l}
                                    eps_m = \left|\varepsilon\right|
                                    
                                    \\
                                    \begin{array}{l}
                                    \mathbf{if}\;x \leq -0.0016:\\
                                    \;\;\;\;\left(x \cdot eps_m\right) \cdot -0.5\\
                                    
                                    \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\
                                    \;\;\;\;1\\
                                    
                                    \mathbf{else}:\\
                                    \;\;\;\;\frac{\left(1 - x \cdot \left(1 - eps_m\right)\right) \cdot \left(1 + \frac{1}{eps_m}\right) + \frac{x + -1}{eps_m}}{2}\\
                                    
                                    
                                    \end{array}
                                    \end{array}
                                    
                                    Derivation
                                    1. Split input into 3 regimes
                                    2. if x < -0.00160000000000000008

                                      1. Initial program 100.0%

                                        \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                      2. Step-by-step derivation
                                        1. Simplified100.0%

                                          \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                        2. Taylor expanded in x around 0 52.3%

                                          \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                        3. Taylor expanded in eps around inf 22.1%

                                          \[\leadsto \frac{\color{blue}{-1 \cdot \left(\varepsilon \cdot x\right)}}{2} \]
                                        4. Step-by-step derivation
                                          1. mul-1-neg22.1%

                                            \[\leadsto \frac{\color{blue}{-\varepsilon \cdot x}}{2} \]
                                          2. *-commutative22.1%

                                            \[\leadsto \frac{-\color{blue}{x \cdot \varepsilon}}{2} \]
                                          3. distribute-rgt-neg-in22.1%

                                            \[\leadsto \frac{\color{blue}{x \cdot \left(-\varepsilon\right)}}{2} \]
                                        5. Simplified22.1%

                                          \[\leadsto \frac{\color{blue}{x \cdot \left(-\varepsilon\right)}}{2} \]
                                        6. Taylor expanded in x around 0 22.1%

                                          \[\leadsto \color{blue}{-0.5 \cdot \left(\varepsilon \cdot x\right)} \]
                                        7. Step-by-step derivation
                                          1. *-commutative22.1%

                                            \[\leadsto -0.5 \cdot \color{blue}{\left(x \cdot \varepsilon\right)} \]
                                        8. Simplified22.1%

                                          \[\leadsto \color{blue}{-0.5 \cdot \left(x \cdot \varepsilon\right)} \]

                                        if -0.00160000000000000008 < x < 2.60000000000000009e-6

                                        1. Initial program 45.5%

                                          \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                        2. Step-by-step derivation
                                          1. Simplified45.5%

                                            \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                          2. Taylor expanded in x around 0 79.2%

                                            \[\leadsto \frac{\color{blue}{2}}{2} \]

                                          if 2.60000000000000009e-6 < x

                                          1. Initial program 100.0%

                                            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                          2. Step-by-step derivation
                                            1. Simplified100.0%

                                              \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                            2. Taylor expanded in x around 0 19.4%

                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                            3. Taylor expanded in x around 0 25.7%

                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                            4. Step-by-step derivation
                                              1. mul-1-neg25.7%

                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                              2. unsub-neg25.7%

                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                            5. Simplified25.7%

                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                            6. Taylor expanded in eps around 0 39.5%

                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \color{blue}{\frac{1 + -1 \cdot x}{\varepsilon}}}{2} \]
                                            7. Step-by-step derivation
                                              1. mul-1-neg39.5%

                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \frac{1 + \color{blue}{\left(-x\right)}}{\varepsilon}}{2} \]
                                              2. unsub-neg39.5%

                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \frac{\color{blue}{1 - x}}{\varepsilon}}{2} \]
                                            8. Simplified39.5%

                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 - x \cdot \left(1 - \varepsilon\right)\right) - \color{blue}{\frac{1 - x}{\varepsilon}}}{2} \]
                                          3. Recombined 3 regimes into one program.
                                          4. Final simplification59.2%

                                            \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -0.0016:\\ \;\;\;\;\left(x \cdot \varepsilon\right) \cdot -0.5\\ \mathbf{elif}\;x \leq 2.6 \cdot 10^{-6}:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(1 - x \cdot \left(1 - \varepsilon\right)\right) \cdot \left(1 + \frac{1}{\varepsilon}\right) + \frac{x + -1}{\varepsilon}}{2}\\ \end{array} \]

                                          Alternative 13: 64.5% accurate, 13.2× speedup?

                                          \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -0.0016:\\ \;\;\;\;\left(x \cdot eps_m\right) \cdot -0.5\\ \mathbf{elif}\;x \leq 480:\\ \;\;\;\;1\\ \mathbf{elif}\;x \leq 2.2 \cdot 10^{+253}:\\ \;\;\;\;0\\ \mathbf{else}:\\ \;\;\;\;\frac{x \cdot eps_m + \left(1 + \frac{1}{eps_m}\right)}{2}\\ \end{array} \end{array} \]
                                          eps_m = (fabs.f64 eps)
                                          (FPCore (x eps_m)
                                           :precision binary64
                                           (if (<= x -0.0016)
                                             (* (* x eps_m) -0.5)
                                             (if (<= x 480.0)
                                               1.0
                                               (if (<= x 2.2e+253) 0.0 (/ (+ (* x eps_m) (+ 1.0 (/ 1.0 eps_m))) 2.0)))))
                                          eps_m = fabs(eps);
                                          double code(double x, double eps_m) {
                                          	double tmp;
                                          	if (x <= -0.0016) {
                                          		tmp = (x * eps_m) * -0.5;
                                          	} else if (x <= 480.0) {
                                          		tmp = 1.0;
                                          	} else if (x <= 2.2e+253) {
                                          		tmp = 0.0;
                                          	} else {
                                          		tmp = ((x * eps_m) + (1.0 + (1.0 / eps_m))) / 2.0;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          eps_m = abs(eps)
                                          real(8) function code(x, eps_m)
                                              real(8), intent (in) :: x
                                              real(8), intent (in) :: eps_m
                                              real(8) :: tmp
                                              if (x <= (-0.0016d0)) then
                                                  tmp = (x * eps_m) * (-0.5d0)
                                              else if (x <= 480.0d0) then
                                                  tmp = 1.0d0
                                              else if (x <= 2.2d+253) then
                                                  tmp = 0.0d0
                                              else
                                                  tmp = ((x * eps_m) + (1.0d0 + (1.0d0 / eps_m))) / 2.0d0
                                              end if
                                              code = tmp
                                          end function
                                          
                                          eps_m = Math.abs(eps);
                                          public static double code(double x, double eps_m) {
                                          	double tmp;
                                          	if (x <= -0.0016) {
                                          		tmp = (x * eps_m) * -0.5;
                                          	} else if (x <= 480.0) {
                                          		tmp = 1.0;
                                          	} else if (x <= 2.2e+253) {
                                          		tmp = 0.0;
                                          	} else {
                                          		tmp = ((x * eps_m) + (1.0 + (1.0 / eps_m))) / 2.0;
                                          	}
                                          	return tmp;
                                          }
                                          
                                          eps_m = math.fabs(eps)
                                          def code(x, eps_m):
                                          	tmp = 0
                                          	if x <= -0.0016:
                                          		tmp = (x * eps_m) * -0.5
                                          	elif x <= 480.0:
                                          		tmp = 1.0
                                          	elif x <= 2.2e+253:
                                          		tmp = 0.0
                                          	else:
                                          		tmp = ((x * eps_m) + (1.0 + (1.0 / eps_m))) / 2.0
                                          	return tmp
                                          
                                          eps_m = abs(eps)
                                          function code(x, eps_m)
                                          	tmp = 0.0
                                          	if (x <= -0.0016)
                                          		tmp = Float64(Float64(x * eps_m) * -0.5);
                                          	elseif (x <= 480.0)
                                          		tmp = 1.0;
                                          	elseif (x <= 2.2e+253)
                                          		tmp = 0.0;
                                          	else
                                          		tmp = Float64(Float64(Float64(x * eps_m) + Float64(1.0 + Float64(1.0 / eps_m))) / 2.0);
                                          	end
                                          	return tmp
                                          end
                                          
                                          eps_m = abs(eps);
                                          function tmp_2 = code(x, eps_m)
                                          	tmp = 0.0;
                                          	if (x <= -0.0016)
                                          		tmp = (x * eps_m) * -0.5;
                                          	elseif (x <= 480.0)
                                          		tmp = 1.0;
                                          	elseif (x <= 2.2e+253)
                                          		tmp = 0.0;
                                          	else
                                          		tmp = ((x * eps_m) + (1.0 + (1.0 / eps_m))) / 2.0;
                                          	end
                                          	tmp_2 = tmp;
                                          end
                                          
                                          eps_m = N[Abs[eps], $MachinePrecision]
                                          code[x_, eps$95$m_] := If[LessEqual[x, -0.0016], N[(N[(x * eps$95$m), $MachinePrecision] * -0.5), $MachinePrecision], If[LessEqual[x, 480.0], 1.0, If[LessEqual[x, 2.2e+253], 0.0, N[(N[(N[(x * eps$95$m), $MachinePrecision] + N[(1.0 + N[(1.0 / eps$95$m), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]]]]
                                          
                                          \begin{array}{l}
                                          eps_m = \left|\varepsilon\right|
                                          
                                          \\
                                          \begin{array}{l}
                                          \mathbf{if}\;x \leq -0.0016:\\
                                          \;\;\;\;\left(x \cdot eps_m\right) \cdot -0.5\\
                                          
                                          \mathbf{elif}\;x \leq 480:\\
                                          \;\;\;\;1\\
                                          
                                          \mathbf{elif}\;x \leq 2.2 \cdot 10^{+253}:\\
                                          \;\;\;\;0\\
                                          
                                          \mathbf{else}:\\
                                          \;\;\;\;\frac{x \cdot eps_m + \left(1 + \frac{1}{eps_m}\right)}{2}\\
                                          
                                          
                                          \end{array}
                                          \end{array}
                                          
                                          Derivation
                                          1. Split input into 4 regimes
                                          2. if x < -0.00160000000000000008

                                            1. Initial program 100.0%

                                              \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                            2. Step-by-step derivation
                                              1. Simplified100.0%

                                                \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                              2. Taylor expanded in x around 0 52.3%

                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                              3. Taylor expanded in eps around inf 22.1%

                                                \[\leadsto \frac{\color{blue}{-1 \cdot \left(\varepsilon \cdot x\right)}}{2} \]
                                              4. Step-by-step derivation
                                                1. mul-1-neg22.1%

                                                  \[\leadsto \frac{\color{blue}{-\varepsilon \cdot x}}{2} \]
                                                2. *-commutative22.1%

                                                  \[\leadsto \frac{-\color{blue}{x \cdot \varepsilon}}{2} \]
                                                3. distribute-rgt-neg-in22.1%

                                                  \[\leadsto \frac{\color{blue}{x \cdot \left(-\varepsilon\right)}}{2} \]
                                              5. Simplified22.1%

                                                \[\leadsto \frac{\color{blue}{x \cdot \left(-\varepsilon\right)}}{2} \]
                                              6. Taylor expanded in x around 0 22.1%

                                                \[\leadsto \color{blue}{-0.5 \cdot \left(\varepsilon \cdot x\right)} \]
                                              7. Step-by-step derivation
                                                1. *-commutative22.1%

                                                  \[\leadsto -0.5 \cdot \color{blue}{\left(x \cdot \varepsilon\right)} \]
                                              8. Simplified22.1%

                                                \[\leadsto \color{blue}{-0.5 \cdot \left(x \cdot \varepsilon\right)} \]

                                              if -0.00160000000000000008 < x < 480

                                              1. Initial program 45.9%

                                                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                              2. Step-by-step derivation
                                                1. Simplified45.9%

                                                  \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                2. Taylor expanded in x around 0 78.7%

                                                  \[\leadsto \frac{\color{blue}{2}}{2} \]

                                                if 480 < x < 2.20000000000000006e253

                                                1. Initial program 100.0%

                                                  \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                2. Step-by-step derivation
                                                  1. Simplified100.0%

                                                    \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                  2. Taylor expanded in x around 0 17.7%

                                                    \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                                  3. Taylor expanded in x around 0 34.4%

                                                    \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                  4. Step-by-step derivation
                                                    1. mul-1-neg34.4%

                                                      \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                    2. unsub-neg34.4%

                                                      \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                  5. Simplified34.4%

                                                    \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                  6. Taylor expanded in eps around 0 52.8%

                                                    \[\leadsto \frac{\color{blue}{-1 \cdot \frac{x + -1 \cdot x}{\varepsilon}}}{2} \]
                                                  7. Step-by-step derivation
                                                    1. associate-*r/52.8%

                                                      \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(x + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                    2. distribute-rgt1-in52.8%

                                                      \[\leadsto \frac{\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot x\right)}}{\varepsilon}}{2} \]
                                                    3. metadata-eval52.8%

                                                      \[\leadsto \frac{\frac{-1 \cdot \left(\color{blue}{0} \cdot x\right)}{\varepsilon}}{2} \]
                                                    4. mul0-lft52.8%

                                                      \[\leadsto \frac{\frac{-1 \cdot \color{blue}{0}}{\varepsilon}}{2} \]
                                                    5. metadata-eval52.8%

                                                      \[\leadsto \frac{\frac{\color{blue}{0}}{\varepsilon}}{2} \]
                                                    6. +-inverses52.8%

                                                      \[\leadsto \frac{\frac{\color{blue}{-1 \cdot \left(1 + -1 \cdot x\right) - -1 \cdot \left(1 + -1 \cdot x\right)}}{\varepsilon}}{2} \]
                                                    7. div-sub34.8%

                                                      \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon} - \frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                    8. +-inverses52.8%

                                                      \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                  8. Simplified52.8%

                                                    \[\leadsto \frac{\color{blue}{0}}{2} \]

                                                  if 2.20000000000000006e253 < x

                                                  1. Initial program 100.0%

                                                    \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                  2. Step-by-step derivation
                                                    1. Simplified100.0%

                                                      \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                    2. Taylor expanded in x around 0 19.7%

                                                      \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                                    3. Taylor expanded in x around 0 19.7%

                                                      \[\leadsto \frac{\color{blue}{\left(1 + \frac{1}{\varepsilon}\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                    4. Taylor expanded in eps around inf 19.9%

                                                      \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) - \color{blue}{\varepsilon \cdot x}}{2} \]
                                                    5. Step-by-step derivation
                                                      1. *-commutative19.9%

                                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) - \color{blue}{x \cdot \varepsilon}}{2} \]
                                                    6. Simplified19.9%

                                                      \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) - \color{blue}{x \cdot \varepsilon}}{2} \]
                                                    7. Step-by-step derivation
                                                      1. add-log-exp25.5%

                                                        \[\leadsto \frac{\color{blue}{\log \left(e^{\left(1 + \frac{1}{\varepsilon}\right) - x \cdot \varepsilon}\right)}}{2} \]
                                                      2. sub-neg25.5%

                                                        \[\leadsto \frac{\log \left(e^{\color{blue}{\left(1 + \frac{1}{\varepsilon}\right) + \left(-x \cdot \varepsilon\right)}}\right)}{2} \]
                                                      3. distribute-rgt-neg-out25.5%

                                                        \[\leadsto \frac{\log \left(e^{\left(1 + \frac{1}{\varepsilon}\right) + \color{blue}{x \cdot \left(-\varepsilon\right)}}\right)}{2} \]
                                                      4. exp-sum25.0%

                                                        \[\leadsto \frac{\log \color{blue}{\left(e^{1 + \frac{1}{\varepsilon}} \cdot e^{x \cdot \left(-\varepsilon\right)}\right)}}{2} \]
                                                      5. exp-prod25.0%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot \color{blue}{{\left(e^{x}\right)}^{\left(-\varepsilon\right)}}\right)}{2} \]
                                                      6. add-sqr-sqrt25.0%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot {\left(e^{x}\right)}^{\color{blue}{\left(\sqrt{-\varepsilon} \cdot \sqrt{-\varepsilon}\right)}}\right)}{2} \]
                                                      7. sqrt-unprod69.2%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot {\left(e^{x}\right)}^{\color{blue}{\left(\sqrt{\left(-\varepsilon\right) \cdot \left(-\varepsilon\right)}\right)}}\right)}{2} \]
                                                      8. sqr-neg69.2%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot {\left(e^{x}\right)}^{\left(\sqrt{\color{blue}{\varepsilon \cdot \varepsilon}}\right)}\right)}{2} \]
                                                      9. sqrt-unprod44.1%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot {\left(e^{x}\right)}^{\color{blue}{\left(\sqrt{\varepsilon} \cdot \sqrt{\varepsilon}\right)}}\right)}{2} \]
                                                      10. add-sqr-sqrt44.2%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot {\left(e^{x}\right)}^{\color{blue}{\varepsilon}}\right)}{2} \]
                                                      11. exp-prod44.2%

                                                        \[\leadsto \frac{\log \left(e^{1 + \frac{1}{\varepsilon}} \cdot \color{blue}{e^{x \cdot \varepsilon}}\right)}{2} \]
                                                      12. sum-log44.2%

                                                        \[\leadsto \frac{\color{blue}{\log \left(e^{1 + \frac{1}{\varepsilon}}\right) + \log \left(e^{x \cdot \varepsilon}\right)}}{2} \]
                                                      13. add-log-exp44.2%

                                                        \[\leadsto \frac{\color{blue}{\left(1 + \frac{1}{\varepsilon}\right)} + \log \left(e^{x \cdot \varepsilon}\right)}{2} \]
                                                      14. add-log-exp44.4%

                                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) + \color{blue}{x \cdot \varepsilon}}{2} \]
                                                    8. Applied egg-rr44.4%

                                                      \[\leadsto \frac{\color{blue}{\left(1 + \frac{1}{\varepsilon}\right) + x \cdot \varepsilon}}{2} \]
                                                  3. Recombined 4 regimes into one program.
                                                  4. Final simplification62.0%

                                                    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -0.0016:\\ \;\;\;\;\left(x \cdot \varepsilon\right) \cdot -0.5\\ \mathbf{elif}\;x \leq 480:\\ \;\;\;\;1\\ \mathbf{elif}\;x \leq 2.2 \cdot 10^{+253}:\\ \;\;\;\;0\\ \mathbf{else}:\\ \;\;\;\;\frac{x \cdot \varepsilon + \left(1 + \frac{1}{\varepsilon}\right)}{2}\\ \end{array} \]

                                                  Alternative 14: 64.9% accurate, 32.1× speedup?

                                                  \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq -0.0016:\\ \;\;\;\;\left(x \cdot eps_m\right) \cdot -0.5\\ \mathbf{elif}\;x \leq 550:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;0\\ \end{array} \end{array} \]
                                                  eps_m = (fabs.f64 eps)
                                                  (FPCore (x eps_m)
                                                   :precision binary64
                                                   (if (<= x -0.0016) (* (* x eps_m) -0.5) (if (<= x 550.0) 1.0 0.0)))
                                                  eps_m = fabs(eps);
                                                  double code(double x, double eps_m) {
                                                  	double tmp;
                                                  	if (x <= -0.0016) {
                                                  		tmp = (x * eps_m) * -0.5;
                                                  	} else if (x <= 550.0) {
                                                  		tmp = 1.0;
                                                  	} else {
                                                  		tmp = 0.0;
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  eps_m = abs(eps)
                                                  real(8) function code(x, eps_m)
                                                      real(8), intent (in) :: x
                                                      real(8), intent (in) :: eps_m
                                                      real(8) :: tmp
                                                      if (x <= (-0.0016d0)) then
                                                          tmp = (x * eps_m) * (-0.5d0)
                                                      else if (x <= 550.0d0) then
                                                          tmp = 1.0d0
                                                      else
                                                          tmp = 0.0d0
                                                      end if
                                                      code = tmp
                                                  end function
                                                  
                                                  eps_m = Math.abs(eps);
                                                  public static double code(double x, double eps_m) {
                                                  	double tmp;
                                                  	if (x <= -0.0016) {
                                                  		tmp = (x * eps_m) * -0.5;
                                                  	} else if (x <= 550.0) {
                                                  		tmp = 1.0;
                                                  	} else {
                                                  		tmp = 0.0;
                                                  	}
                                                  	return tmp;
                                                  }
                                                  
                                                  eps_m = math.fabs(eps)
                                                  def code(x, eps_m):
                                                  	tmp = 0
                                                  	if x <= -0.0016:
                                                  		tmp = (x * eps_m) * -0.5
                                                  	elif x <= 550.0:
                                                  		tmp = 1.0
                                                  	else:
                                                  		tmp = 0.0
                                                  	return tmp
                                                  
                                                  eps_m = abs(eps)
                                                  function code(x, eps_m)
                                                  	tmp = 0.0
                                                  	if (x <= -0.0016)
                                                  		tmp = Float64(Float64(x * eps_m) * -0.5);
                                                  	elseif (x <= 550.0)
                                                  		tmp = 1.0;
                                                  	else
                                                  		tmp = 0.0;
                                                  	end
                                                  	return tmp
                                                  end
                                                  
                                                  eps_m = abs(eps);
                                                  function tmp_2 = code(x, eps_m)
                                                  	tmp = 0.0;
                                                  	if (x <= -0.0016)
                                                  		tmp = (x * eps_m) * -0.5;
                                                  	elseif (x <= 550.0)
                                                  		tmp = 1.0;
                                                  	else
                                                  		tmp = 0.0;
                                                  	end
                                                  	tmp_2 = tmp;
                                                  end
                                                  
                                                  eps_m = N[Abs[eps], $MachinePrecision]
                                                  code[x_, eps$95$m_] := If[LessEqual[x, -0.0016], N[(N[(x * eps$95$m), $MachinePrecision] * -0.5), $MachinePrecision], If[LessEqual[x, 550.0], 1.0, 0.0]]
                                                  
                                                  \begin{array}{l}
                                                  eps_m = \left|\varepsilon\right|
                                                  
                                                  \\
                                                  \begin{array}{l}
                                                  \mathbf{if}\;x \leq -0.0016:\\
                                                  \;\;\;\;\left(x \cdot eps_m\right) \cdot -0.5\\
                                                  
                                                  \mathbf{elif}\;x \leq 550:\\
                                                  \;\;\;\;1\\
                                                  
                                                  \mathbf{else}:\\
                                                  \;\;\;\;0\\
                                                  
                                                  
                                                  \end{array}
                                                  \end{array}
                                                  
                                                  Derivation
                                                  1. Split input into 3 regimes
                                                  2. if x < -0.00160000000000000008

                                                    1. Initial program 100.0%

                                                      \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                    2. Step-by-step derivation
                                                      1. Simplified100.0%

                                                        \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                      2. Taylor expanded in x around 0 52.3%

                                                        \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                                      3. Taylor expanded in eps around inf 22.1%

                                                        \[\leadsto \frac{\color{blue}{-1 \cdot \left(\varepsilon \cdot x\right)}}{2} \]
                                                      4. Step-by-step derivation
                                                        1. mul-1-neg22.1%

                                                          \[\leadsto \frac{\color{blue}{-\varepsilon \cdot x}}{2} \]
                                                        2. *-commutative22.1%

                                                          \[\leadsto \frac{-\color{blue}{x \cdot \varepsilon}}{2} \]
                                                        3. distribute-rgt-neg-in22.1%

                                                          \[\leadsto \frac{\color{blue}{x \cdot \left(-\varepsilon\right)}}{2} \]
                                                      5. Simplified22.1%

                                                        \[\leadsto \frac{\color{blue}{x \cdot \left(-\varepsilon\right)}}{2} \]
                                                      6. Taylor expanded in x around 0 22.1%

                                                        \[\leadsto \color{blue}{-0.5 \cdot \left(\varepsilon \cdot x\right)} \]
                                                      7. Step-by-step derivation
                                                        1. *-commutative22.1%

                                                          \[\leadsto -0.5 \cdot \color{blue}{\left(x \cdot \varepsilon\right)} \]
                                                      8. Simplified22.1%

                                                        \[\leadsto \color{blue}{-0.5 \cdot \left(x \cdot \varepsilon\right)} \]

                                                      if -0.00160000000000000008 < x < 550

                                                      1. Initial program 45.9%

                                                        \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                      2. Step-by-step derivation
                                                        1. Simplified45.9%

                                                          \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                        2. Taylor expanded in x around 0 78.7%

                                                          \[\leadsto \frac{\color{blue}{2}}{2} \]

                                                        if 550 < x

                                                        1. Initial program 100.0%

                                                          \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                        2. Step-by-step derivation
                                                          1. Simplified100.0%

                                                            \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                          2. Taylor expanded in x around 0 18.2%

                                                            \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                                          3. Taylor expanded in x around 0 26.1%

                                                            \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                          4. Step-by-step derivation
                                                            1. mul-1-neg26.1%

                                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                            2. unsub-neg26.1%

                                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                          5. Simplified26.1%

                                                            \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                          6. Taylor expanded in eps around 0 47.8%

                                                            \[\leadsto \frac{\color{blue}{-1 \cdot \frac{x + -1 \cdot x}{\varepsilon}}}{2} \]
                                                          7. Step-by-step derivation
                                                            1. associate-*r/47.8%

                                                              \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(x + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                            2. distribute-rgt1-in47.8%

                                                              \[\leadsto \frac{\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot x\right)}}{\varepsilon}}{2} \]
                                                            3. metadata-eval47.8%

                                                              \[\leadsto \frac{\frac{-1 \cdot \left(\color{blue}{0} \cdot x\right)}{\varepsilon}}{2} \]
                                                            4. mul0-lft47.8%

                                                              \[\leadsto \frac{\frac{-1 \cdot \color{blue}{0}}{\varepsilon}}{2} \]
                                                            5. metadata-eval47.8%

                                                              \[\leadsto \frac{\frac{\color{blue}{0}}{\varepsilon}}{2} \]
                                                            6. +-inverses47.8%

                                                              \[\leadsto \frac{\frac{\color{blue}{-1 \cdot \left(1 + -1 \cdot x\right) - -1 \cdot \left(1 + -1 \cdot x\right)}}{\varepsilon}}{2} \]
                                                            7. div-sub26.6%

                                                              \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon} - \frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                            8. +-inverses47.8%

                                                              \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                          8. Simplified47.8%

                                                            \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                        3. Recombined 3 regimes into one program.
                                                        4. Final simplification61.2%

                                                          \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -0.0016:\\ \;\;\;\;\left(x \cdot \varepsilon\right) \cdot -0.5\\ \mathbf{elif}\;x \leq 550:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;0\\ \end{array} \]

                                                        Alternative 15: 58.2% accurate, 44.8× speedup?

                                                        \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq 1:\\ \;\;\;\;1 - x\\ \mathbf{else}:\\ \;\;\;\;0\\ \end{array} \end{array} \]
                                                        eps_m = (fabs.f64 eps)
                                                        (FPCore (x eps_m) :precision binary64 (if (<= x 1.0) (- 1.0 x) 0.0))
                                                        eps_m = fabs(eps);
                                                        double code(double x, double eps_m) {
                                                        	double tmp;
                                                        	if (x <= 1.0) {
                                                        		tmp = 1.0 - x;
                                                        	} else {
                                                        		tmp = 0.0;
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        eps_m = abs(eps)
                                                        real(8) function code(x, eps_m)
                                                            real(8), intent (in) :: x
                                                            real(8), intent (in) :: eps_m
                                                            real(8) :: tmp
                                                            if (x <= 1.0d0) then
                                                                tmp = 1.0d0 - x
                                                            else
                                                                tmp = 0.0d0
                                                            end if
                                                            code = tmp
                                                        end function
                                                        
                                                        eps_m = Math.abs(eps);
                                                        public static double code(double x, double eps_m) {
                                                        	double tmp;
                                                        	if (x <= 1.0) {
                                                        		tmp = 1.0 - x;
                                                        	} else {
                                                        		tmp = 0.0;
                                                        	}
                                                        	return tmp;
                                                        }
                                                        
                                                        eps_m = math.fabs(eps)
                                                        def code(x, eps_m):
                                                        	tmp = 0
                                                        	if x <= 1.0:
                                                        		tmp = 1.0 - x
                                                        	else:
                                                        		tmp = 0.0
                                                        	return tmp
                                                        
                                                        eps_m = abs(eps)
                                                        function code(x, eps_m)
                                                        	tmp = 0.0
                                                        	if (x <= 1.0)
                                                        		tmp = Float64(1.0 - x);
                                                        	else
                                                        		tmp = 0.0;
                                                        	end
                                                        	return tmp
                                                        end
                                                        
                                                        eps_m = abs(eps);
                                                        function tmp_2 = code(x, eps_m)
                                                        	tmp = 0.0;
                                                        	if (x <= 1.0)
                                                        		tmp = 1.0 - x;
                                                        	else
                                                        		tmp = 0.0;
                                                        	end
                                                        	tmp_2 = tmp;
                                                        end
                                                        
                                                        eps_m = N[Abs[eps], $MachinePrecision]
                                                        code[x_, eps$95$m_] := If[LessEqual[x, 1.0], N[(1.0 - x), $MachinePrecision], 0.0]
                                                        
                                                        \begin{array}{l}
                                                        eps_m = \left|\varepsilon\right|
                                                        
                                                        \\
                                                        \begin{array}{l}
                                                        \mathbf{if}\;x \leq 1:\\
                                                        \;\;\;\;1 - x\\
                                                        
                                                        \mathbf{else}:\\
                                                        \;\;\;\;0\\
                                                        
                                                        
                                                        \end{array}
                                                        \end{array}
                                                        
                                                        Derivation
                                                        1. Split input into 2 regimes
                                                        2. if x < 1

                                                          1. Initial program 58.1%

                                                            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                          2. Simplified51.0%

                                                            \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                                                          3. Taylor expanded in eps around inf 99.2%

                                                            \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                                                          4. Taylor expanded in x around 0 81.4%

                                                            \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
                                                          5. Taylor expanded in x around 0 61.5%

                                                            \[\leadsto \color{blue}{1 + -1 \cdot x} \]
                                                          6. Step-by-step derivation
                                                            1. neg-mul-161.5%

                                                              \[\leadsto 1 + \color{blue}{\left(-x\right)} \]
                                                            2. unsub-neg61.5%

                                                              \[\leadsto \color{blue}{1 - x} \]
                                                          7. Simplified61.5%

                                                            \[\leadsto \color{blue}{1 - x} \]

                                                          if 1 < x

                                                          1. Initial program 100.0%

                                                            \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                          2. Step-by-step derivation
                                                            1. Simplified100.0%

                                                              \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                            2. Taylor expanded in x around 0 18.2%

                                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                                            3. Taylor expanded in x around 0 26.1%

                                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                            4. Step-by-step derivation
                                                              1. mul-1-neg26.1%

                                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                              2. unsub-neg26.1%

                                                                \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                            5. Simplified26.1%

                                                              \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                            6. Taylor expanded in eps around 0 47.8%

                                                              \[\leadsto \frac{\color{blue}{-1 \cdot \frac{x + -1 \cdot x}{\varepsilon}}}{2} \]
                                                            7. Step-by-step derivation
                                                              1. associate-*r/47.8%

                                                                \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(x + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                              2. distribute-rgt1-in47.8%

                                                                \[\leadsto \frac{\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot x\right)}}{\varepsilon}}{2} \]
                                                              3. metadata-eval47.8%

                                                                \[\leadsto \frac{\frac{-1 \cdot \left(\color{blue}{0} \cdot x\right)}{\varepsilon}}{2} \]
                                                              4. mul0-lft47.8%

                                                                \[\leadsto \frac{\frac{-1 \cdot \color{blue}{0}}{\varepsilon}}{2} \]
                                                              5. metadata-eval47.8%

                                                                \[\leadsto \frac{\frac{\color{blue}{0}}{\varepsilon}}{2} \]
                                                              6. +-inverses47.8%

                                                                \[\leadsto \frac{\frac{\color{blue}{-1 \cdot \left(1 + -1 \cdot x\right) - -1 \cdot \left(1 + -1 \cdot x\right)}}{\varepsilon}}{2} \]
                                                              7. div-sub26.6%

                                                                \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon} - \frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                              8. +-inverses47.8%

                                                                \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                            8. Simplified47.8%

                                                              \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                          3. Recombined 2 regimes into one program.
                                                          4. Final simplification57.9%

                                                            \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 1:\\ \;\;\;\;1 - x\\ \mathbf{else}:\\ \;\;\;\;0\\ \end{array} \]

                                                          Alternative 16: 58.2% accurate, 74.1× speedup?

                                                          \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ \begin{array}{l} \mathbf{if}\;x \leq 470:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;0\\ \end{array} \end{array} \]
                                                          eps_m = (fabs.f64 eps)
                                                          (FPCore (x eps_m) :precision binary64 (if (<= x 470.0) 1.0 0.0))
                                                          eps_m = fabs(eps);
                                                          double code(double x, double eps_m) {
                                                          	double tmp;
                                                          	if (x <= 470.0) {
                                                          		tmp = 1.0;
                                                          	} else {
                                                          		tmp = 0.0;
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          eps_m = abs(eps)
                                                          real(8) function code(x, eps_m)
                                                              real(8), intent (in) :: x
                                                              real(8), intent (in) :: eps_m
                                                              real(8) :: tmp
                                                              if (x <= 470.0d0) then
                                                                  tmp = 1.0d0
                                                              else
                                                                  tmp = 0.0d0
                                                              end if
                                                              code = tmp
                                                          end function
                                                          
                                                          eps_m = Math.abs(eps);
                                                          public static double code(double x, double eps_m) {
                                                          	double tmp;
                                                          	if (x <= 470.0) {
                                                          		tmp = 1.0;
                                                          	} else {
                                                          		tmp = 0.0;
                                                          	}
                                                          	return tmp;
                                                          }
                                                          
                                                          eps_m = math.fabs(eps)
                                                          def code(x, eps_m):
                                                          	tmp = 0
                                                          	if x <= 470.0:
                                                          		tmp = 1.0
                                                          	else:
                                                          		tmp = 0.0
                                                          	return tmp
                                                          
                                                          eps_m = abs(eps)
                                                          function code(x, eps_m)
                                                          	tmp = 0.0
                                                          	if (x <= 470.0)
                                                          		tmp = 1.0;
                                                          	else
                                                          		tmp = 0.0;
                                                          	end
                                                          	return tmp
                                                          end
                                                          
                                                          eps_m = abs(eps);
                                                          function tmp_2 = code(x, eps_m)
                                                          	tmp = 0.0;
                                                          	if (x <= 470.0)
                                                          		tmp = 1.0;
                                                          	else
                                                          		tmp = 0.0;
                                                          	end
                                                          	tmp_2 = tmp;
                                                          end
                                                          
                                                          eps_m = N[Abs[eps], $MachinePrecision]
                                                          code[x_, eps$95$m_] := If[LessEqual[x, 470.0], 1.0, 0.0]
                                                          
                                                          \begin{array}{l}
                                                          eps_m = \left|\varepsilon\right|
                                                          
                                                          \\
                                                          \begin{array}{l}
                                                          \mathbf{if}\;x \leq 470:\\
                                                          \;\;\;\;1\\
                                                          
                                                          \mathbf{else}:\\
                                                          \;\;\;\;0\\
                                                          
                                                          
                                                          \end{array}
                                                          \end{array}
                                                          
                                                          Derivation
                                                          1. Split input into 2 regimes
                                                          2. if x < 470

                                                            1. Initial program 58.1%

                                                              \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                            2. Step-by-step derivation
                                                              1. Simplified58.1%

                                                                \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                              2. Taylor expanded in x around 0 61.6%

                                                                \[\leadsto \frac{\color{blue}{2}}{2} \]

                                                              if 470 < x

                                                              1. Initial program 100.0%

                                                                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                              2. Step-by-step derivation
                                                                1. Simplified100.0%

                                                                  \[\leadsto \color{blue}{\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot e^{\left(1 + \varepsilon\right) \cdot \left(-x\right)}}{2}} \]
                                                                2. Taylor expanded in x around 0 18.2%

                                                                  \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{\left(1 - \varepsilon\right) \cdot \left(-x\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}}{2} \]
                                                                3. Taylor expanded in x around 0 26.1%

                                                                  \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 + -1 \cdot \left(x \cdot \left(1 - \varepsilon\right)\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                                4. Step-by-step derivation
                                                                  1. mul-1-neg26.1%

                                                                    \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \left(1 + \color{blue}{\left(-x \cdot \left(1 - \varepsilon\right)\right)}\right) - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                                  2. unsub-neg26.1%

                                                                    \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                                5. Simplified26.1%

                                                                  \[\leadsto \frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot \color{blue}{\left(1 - x \cdot \left(1 - \varepsilon\right)\right)} - \left(\frac{1}{\varepsilon} + -1\right) \cdot \left(1 + -1 \cdot \left(x \cdot \left(1 + \varepsilon\right)\right)\right)}{2} \]
                                                                6. Taylor expanded in eps around 0 47.8%

                                                                  \[\leadsto \frac{\color{blue}{-1 \cdot \frac{x + -1 \cdot x}{\varepsilon}}}{2} \]
                                                                7. Step-by-step derivation
                                                                  1. associate-*r/47.8%

                                                                    \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(x + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                                  2. distribute-rgt1-in47.8%

                                                                    \[\leadsto \frac{\frac{-1 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot x\right)}}{\varepsilon}}{2} \]
                                                                  3. metadata-eval47.8%

                                                                    \[\leadsto \frac{\frac{-1 \cdot \left(\color{blue}{0} \cdot x\right)}{\varepsilon}}{2} \]
                                                                  4. mul0-lft47.8%

                                                                    \[\leadsto \frac{\frac{-1 \cdot \color{blue}{0}}{\varepsilon}}{2} \]
                                                                  5. metadata-eval47.8%

                                                                    \[\leadsto \frac{\frac{\color{blue}{0}}{\varepsilon}}{2} \]
                                                                  6. +-inverses47.8%

                                                                    \[\leadsto \frac{\frac{\color{blue}{-1 \cdot \left(1 + -1 \cdot x\right) - -1 \cdot \left(1 + -1 \cdot x\right)}}{\varepsilon}}{2} \]
                                                                  7. div-sub26.6%

                                                                    \[\leadsto \frac{\color{blue}{\frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon} - \frac{-1 \cdot \left(1 + -1 \cdot x\right)}{\varepsilon}}}{2} \]
                                                                  8. +-inverses47.8%

                                                                    \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                                8. Simplified47.8%

                                                                  \[\leadsto \frac{\color{blue}{0}}{2} \]
                                                              3. Recombined 2 regimes into one program.
                                                              4. Final simplification58.0%

                                                                \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 470:\\ \;\;\;\;1\\ \mathbf{else}:\\ \;\;\;\;0\\ \end{array} \]

                                                              Alternative 17: 44.3% accurate, 75.7× speedup?

                                                              \[\begin{array}{l} eps_m = \left|\varepsilon\right| \\ 1 - x \end{array} \]
                                                              eps_m = (fabs.f64 eps)
                                                              (FPCore (x eps_m) :precision binary64 (- 1.0 x))
                                                              eps_m = fabs(eps);
                                                              double code(double x, double eps_m) {
                                                              	return 1.0 - x;
                                                              }
                                                              
                                                              eps_m = abs(eps)
                                                              real(8) function code(x, eps_m)
                                                                  real(8), intent (in) :: x
                                                                  real(8), intent (in) :: eps_m
                                                                  code = 1.0d0 - x
                                                              end function
                                                              
                                                              eps_m = Math.abs(eps);
                                                              public static double code(double x, double eps_m) {
                                                              	return 1.0 - x;
                                                              }
                                                              
                                                              eps_m = math.fabs(eps)
                                                              def code(x, eps_m):
                                                              	return 1.0 - x
                                                              
                                                              eps_m = abs(eps)
                                                              function code(x, eps_m)
                                                              	return Float64(1.0 - x)
                                                              end
                                                              
                                                              eps_m = abs(eps);
                                                              function tmp = code(x, eps_m)
                                                              	tmp = 1.0 - x;
                                                              end
                                                              
                                                              eps_m = N[Abs[eps], $MachinePrecision]
                                                              code[x_, eps$95$m_] := N[(1.0 - x), $MachinePrecision]
                                                              
                                                              \begin{array}{l}
                                                              eps_m = \left|\varepsilon\right|
                                                              
                                                              \\
                                                              1 - x
                                                              \end{array}
                                                              
                                                              Derivation
                                                              1. Initial program 68.9%

                                                                \[\frac{\left(1 + \frac{1}{\varepsilon}\right) \cdot e^{-\left(1 - \varepsilon\right) \cdot x} - \left(\frac{1}{\varepsilon} - 1\right) \cdot e^{-\left(1 + \varepsilon\right) \cdot x}}{2} \]
                                                              2. Simplified63.6%

                                                                \[\leadsto \color{blue}{\frac{\mathsf{fma}\left(1 - \frac{-1}{\varepsilon}, {\left(e^{x}\right)}^{\left(\varepsilon + -1\right)}, \frac{1 + \frac{-1}{\varepsilon}}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}\right)}{2}} \]
                                                              3. Taylor expanded in eps around inf 99.4%

                                                                \[\leadsto \frac{\color{blue}{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{e^{\mathsf{fma}\left(\varepsilon, x, x\right)}}}}{2} \]
                                                              4. Taylor expanded in x around 0 69.4%

                                                                \[\leadsto \frac{e^{x \cdot \left(\varepsilon - 1\right)} + \frac{1}{\color{blue}{1 + x \cdot \left(1 + \varepsilon\right)}}}{2} \]
                                                              5. Taylor expanded in x around 0 45.9%

                                                                \[\leadsto \color{blue}{1 + -1 \cdot x} \]
                                                              6. Step-by-step derivation
                                                                1. neg-mul-145.9%

                                                                  \[\leadsto 1 + \color{blue}{\left(-x\right)} \]
                                                                2. unsub-neg45.9%

                                                                  \[\leadsto \color{blue}{1 - x} \]
                                                              7. Simplified45.9%

                                                                \[\leadsto \color{blue}{1 - x} \]
                                                              8. Final simplification45.9%

                                                                \[\leadsto 1 - x \]

                                                              Reproduce

                                                              ?
                                                              herbie shell --seed 2023334 
                                                              (FPCore (x eps)
                                                                :name "NMSE Section 6.1 mentioned, A"
                                                                :precision binary64
                                                                (/ (- (* (+ 1.0 (/ 1.0 eps)) (exp (- (* (- 1.0 eps) x)))) (* (- (/ 1.0 eps) 1.0) (exp (- (* (+ 1.0 eps) x))))) 2.0))