Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, G

Percentage Accurate: 85.3% → 99.2%
Time: 7.5s
Alternatives: 6
Speedup: 2.0×

Specification

?
\[\begin{array}{l} \\ x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (+ x (/ (exp (* y (log (/ y (+ z y))))) y)))
double code(double x, double y, double z) {
	return x + (exp((y * log((y / (z + y))))) / y);
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (exp((y * log((y / (z + y))))) / y)
end function
public static double code(double x, double y, double z) {
	return x + (Math.exp((y * Math.log((y / (z + y))))) / y);
}
def code(x, y, z):
	return x + (math.exp((y * math.log((y / (z + y))))) / y)
function code(x, y, z)
	return Float64(x + Float64(exp(Float64(y * log(Float64(y / Float64(z + y))))) / y))
end
function tmp = code(x, y, z)
	tmp = x + (exp((y * log((y / (z + y))))) / y);
end
code[x_, y_, z_] := N[(x + N[(N[Exp[N[(y * N[Log[N[(y / N[(z + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 6 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 85.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (+ x (/ (exp (* y (log (/ y (+ z y))))) y)))
double code(double x, double y, double z) {
	return x + (exp((y * log((y / (z + y))))) / y);
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (exp((y * log((y / (z + y))))) / y)
end function
public static double code(double x, double y, double z) {
	return x + (Math.exp((y * Math.log((y / (z + y))))) / y);
}
def code(x, y, z):
	return x + (math.exp((y * math.log((y / (z + y))))) / y)
function code(x, y, z)
	return Float64(x + Float64(exp(Float64(y * log(Float64(y / Float64(z + y))))) / y))
end
function tmp = code(x, y, z)
	tmp = x + (exp((y * log((y / (z + y))))) / y);
end
code[x_, y_, z_] := N[(x + N[(N[Exp[N[(y * N[Log[N[(y / N[(z + y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y}
\end{array}

Alternative 1: 99.2% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -2 \cdot 10^{+93} \lor \neg \left(y \leq 5 \cdot 10^{-28}\right):\\ \;\;\;\;x + \frac{e^{-z}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -2e+93) (not (<= y 5e-28)))
   (+ x (/ (exp (- z)) y))
   (+ x (/ (pow (exp y) (log (/ y (+ y z)))) y))))
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -2e+93) || !(y <= 5e-28)) {
		tmp = x + (exp(-z) / y);
	} else {
		tmp = x + (pow(exp(y), log((y / (y + z)))) / y);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y <= (-2d+93)) .or. (.not. (y <= 5d-28))) then
        tmp = x + (exp(-z) / y)
    else
        tmp = x + ((exp(y) ** log((y / (y + z)))) / y)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y <= -2e+93) || !(y <= 5e-28)) {
		tmp = x + (Math.exp(-z) / y);
	} else {
		tmp = x + (Math.pow(Math.exp(y), Math.log((y / (y + z)))) / y);
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y <= -2e+93) or not (y <= 5e-28):
		tmp = x + (math.exp(-z) / y)
	else:
		tmp = x + (math.pow(math.exp(y), math.log((y / (y + z)))) / y)
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((y <= -2e+93) || !(y <= 5e-28))
		tmp = Float64(x + Float64(exp(Float64(-z)) / y));
	else
		tmp = Float64(x + Float64((exp(y) ^ log(Float64(y / Float64(y + z)))) / y));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y <= -2e+93) || ~((y <= 5e-28)))
		tmp = x + (exp(-z) / y);
	else
		tmp = x + ((exp(y) ^ log((y / (y + z)))) / y);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[y, -2e+93], N[Not[LessEqual[y, 5e-28]], $MachinePrecision]], N[(x + N[(N[Exp[(-z)], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision], N[(x + N[(N[Power[N[Exp[y], $MachinePrecision], N[Log[N[(y / N[(y + z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -2 \cdot 10^{+93} \lor \neg \left(y \leq 5 \cdot 10^{-28}\right):\\
\;\;\;\;x + \frac{e^{-z}}{y}\\

\mathbf{else}:\\
\;\;\;\;x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -2.00000000000000009e93 or 5.0000000000000002e-28 < y

    1. Initial program 76.0%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. *-commutative76.0%

        \[\leadsto x + \frac{e^{\color{blue}{\log \left(\frac{y}{z + y}\right) \cdot y}}}{y} \]
      2. exp-prod76.0%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{\log \left(\frac{y}{z + y}\right)}\right)}^{y}}}{y} \]
      3. rem-exp-log76.0%

        \[\leadsto x + \frac{{\color{blue}{\left(\frac{y}{z + y}\right)}}^{y}}{y} \]
      4. +-commutative76.0%

        \[\leadsto x + \frac{{\left(\frac{y}{\color{blue}{y + z}}\right)}^{y}}{y} \]
    3. Simplified76.0%

      \[\leadsto \color{blue}{x + \frac{{\left(\frac{y}{y + z}\right)}^{y}}{y}} \]
    4. Taylor expanded in y around inf 100.0%

      \[\leadsto x + \frac{\color{blue}{e^{-1 \cdot z}}}{y} \]
    5. Step-by-step derivation
      1. mul-1-neg100.0%

        \[\leadsto x + \frac{e^{\color{blue}{-z}}}{y} \]
    6. Simplified100.0%

      \[\leadsto x + \frac{\color{blue}{e^{-z}}}{y} \]

    if -2.00000000000000009e93 < y < 5.0000000000000002e-28

    1. Initial program 82.0%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod99.9%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative99.9%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified99.9%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification100.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -2 \cdot 10^{+93} \lor \neg \left(y \leq 5 \cdot 10^{-28}\right):\\ \;\;\;\;x + \frac{e^{-z}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}\\ \end{array} \]

Alternative 2: 99.4% accurate, 1.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -1.32 \lor \neg \left(y \leq 5 \cdot 10^{-28}\right):\\ \;\;\;\;x + \frac{e^{-z}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{1}{y}\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (or (<= y -1.32) (not (<= y 5e-28)))
   (+ x (/ (exp (- z)) y))
   (+ x (/ 1.0 y))))
double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.32) || !(y <= 5e-28)) {
		tmp = x + (exp(-z) / y);
	} else {
		tmp = x + (1.0 / y);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y <= (-1.32d0)) .or. (.not. (y <= 5d-28))) then
        tmp = x + (exp(-z) / y)
    else
        tmp = x + (1.0d0 / y)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y <= -1.32) || !(y <= 5e-28)) {
		tmp = x + (Math.exp(-z) / y);
	} else {
		tmp = x + (1.0 / y);
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y <= -1.32) or not (y <= 5e-28):
		tmp = x + (math.exp(-z) / y)
	else:
		tmp = x + (1.0 / y)
	return tmp
function code(x, y, z)
	tmp = 0.0
	if ((y <= -1.32) || !(y <= 5e-28))
		tmp = Float64(x + Float64(exp(Float64(-z)) / y));
	else
		tmp = Float64(x + Float64(1.0 / y));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y <= -1.32) || ~((y <= 5e-28)))
		tmp = x + (exp(-z) / y);
	else
		tmp = x + (1.0 / y);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Or[LessEqual[y, -1.32], N[Not[LessEqual[y, 5e-28]], $MachinePrecision]], N[(x + N[(N[Exp[(-z)], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision], N[(x + N[(1.0 / y), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -1.32 \lor \neg \left(y \leq 5 \cdot 10^{-28}\right):\\
\;\;\;\;x + \frac{e^{-z}}{y}\\

\mathbf{else}:\\
\;\;\;\;x + \frac{1}{y}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -1.32000000000000006 or 5.0000000000000002e-28 < y

    1. Initial program 79.4%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. *-commutative79.4%

        \[\leadsto x + \frac{e^{\color{blue}{\log \left(\frac{y}{z + y}\right) \cdot y}}}{y} \]
      2. exp-prod79.4%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{\log \left(\frac{y}{z + y}\right)}\right)}^{y}}}{y} \]
      3. rem-exp-log79.4%

        \[\leadsto x + \frac{{\color{blue}{\left(\frac{y}{z + y}\right)}}^{y}}{y} \]
      4. +-commutative79.4%

        \[\leadsto x + \frac{{\left(\frac{y}{\color{blue}{y + z}}\right)}^{y}}{y} \]
    3. Simplified79.4%

      \[\leadsto \color{blue}{x + \frac{{\left(\frac{y}{y + z}\right)}^{y}}{y}} \]
    4. Taylor expanded in y around inf 100.0%

      \[\leadsto x + \frac{\color{blue}{e^{-1 \cdot z}}}{y} \]
    5. Step-by-step derivation
      1. mul-1-neg100.0%

        \[\leadsto x + \frac{e^{\color{blue}{-z}}}{y} \]
    6. Simplified100.0%

      \[\leadsto x + \frac{\color{blue}{e^{-z}}}{y} \]

    if -1.32000000000000006 < y < 5.0000000000000002e-28

    1. Initial program 77.5%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod99.9%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative99.9%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified99.9%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
    4. Taylor expanded in y around inf 99.5%

      \[\leadsto \color{blue}{x + \frac{1}{y}} \]
    5. Step-by-step derivation
      1. +-commutative99.5%

        \[\leadsto \color{blue}{\frac{1}{y} + x} \]
    6. Simplified99.5%

      \[\leadsto \color{blue}{\frac{1}{y} + x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification99.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -1.32 \lor \neg \left(y \leq 5 \cdot 10^{-28}\right):\\ \;\;\;\;x + \frac{e^{-z}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{1}{y}\\ \end{array} \]

Alternative 3: 88.3% accurate, 2.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z \leq -1050:\\ \;\;\;\;\frac{e^{-z}}{y}\\ \mathbf{elif}\;z \leq 10800 \lor \neg \left(z \leq 2.05 \cdot 10^{+139}\right):\\ \;\;\;\;x + \frac{1}{y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= z -1050.0)
   (/ (exp (- z)) y)
   (if (or (<= z 10800.0) (not (<= z 2.05e+139))) (+ x (/ 1.0 y)) x)))
double code(double x, double y, double z) {
	double tmp;
	if (z <= -1050.0) {
		tmp = exp(-z) / y;
	} else if ((z <= 10800.0) || !(z <= 2.05e+139)) {
		tmp = x + (1.0 / y);
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (z <= (-1050.0d0)) then
        tmp = exp(-z) / y
    else if ((z <= 10800.0d0) .or. (.not. (z <= 2.05d+139))) then
        tmp = x + (1.0d0 / y)
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (z <= -1050.0) {
		tmp = Math.exp(-z) / y;
	} else if ((z <= 10800.0) || !(z <= 2.05e+139)) {
		tmp = x + (1.0 / y);
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if z <= -1050.0:
		tmp = math.exp(-z) / y
	elif (z <= 10800.0) or not (z <= 2.05e+139):
		tmp = x + (1.0 / y)
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (z <= -1050.0)
		tmp = Float64(exp(Float64(-z)) / y);
	elseif ((z <= 10800.0) || !(z <= 2.05e+139))
		tmp = Float64(x + Float64(1.0 / y));
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z <= -1050.0)
		tmp = exp(-z) / y;
	elseif ((z <= 10800.0) || ~((z <= 2.05e+139)))
		tmp = x + (1.0 / y);
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[z, -1050.0], N[(N[Exp[(-z)], $MachinePrecision] / y), $MachinePrecision], If[Or[LessEqual[z, 10800.0], N[Not[LessEqual[z, 2.05e+139]], $MachinePrecision]], N[(x + N[(1.0 / y), $MachinePrecision]), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z \leq -1050:\\
\;\;\;\;\frac{e^{-z}}{y}\\

\mathbf{elif}\;z \leq 10800 \lor \neg \left(z \leq 2.05 \cdot 10^{+139}\right):\\
\;\;\;\;x + \frac{1}{y}\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if z < -1050

    1. Initial program 34.0%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod49.1%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative49.1%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified49.1%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
    4. Taylor expanded in x around 0 28.5%

      \[\leadsto \color{blue}{\frac{{\left(\frac{y}{y + z}\right)}^{y}}{y}} \]
    5. Taylor expanded in y around inf 72.4%

      \[\leadsto \frac{\color{blue}{e^{-1 \cdot z}}}{y} \]
    6. Step-by-step derivation
      1. mul-1-neg72.4%

        \[\leadsto x + \frac{e^{\color{blue}{-z}}}{y} \]
    7. Simplified72.4%

      \[\leadsto \frac{\color{blue}{e^{-z}}}{y} \]

    if -1050 < z < 10800 or 2.0500000000000001e139 < z

    1. Initial program 92.4%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod99.1%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative99.1%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified99.1%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
    4. Taylor expanded in y around inf 98.0%

      \[\leadsto \color{blue}{x + \frac{1}{y}} \]
    5. Step-by-step derivation
      1. +-commutative98.0%

        \[\leadsto \color{blue}{\frac{1}{y} + x} \]
    6. Simplified98.0%

      \[\leadsto \color{blue}{\frac{1}{y} + x} \]

    if 10800 < z < 2.0500000000000001e139

    1. Initial program 80.4%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod83.7%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative83.7%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified83.7%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
    4. Taylor expanded in x around inf 93.2%

      \[\leadsto \color{blue}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification92.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -1050:\\ \;\;\;\;\frac{e^{-z}}{y}\\ \mathbf{elif}\;z \leq 10800 \lor \neg \left(z \leq 2.05 \cdot 10^{+139}\right):\\ \;\;\;\;x + \frac{1}{y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 4: 67.3% accurate, 29.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \leq -3.2 \cdot 10^{+84}:\\ \;\;\;\;x\\ \mathbf{elif}\;y \leq 1.65 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= y -3.2e+84) x (if (<= y 1.65e-5) (/ 1.0 y) x)))
double code(double x, double y, double z) {
	double tmp;
	if (y <= -3.2e+84) {
		tmp = x;
	} else if (y <= 1.65e-5) {
		tmp = 1.0 / y;
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (y <= (-3.2d+84)) then
        tmp = x
    else if (y <= 1.65d-5) then
        tmp = 1.0d0 / y
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (y <= -3.2e+84) {
		tmp = x;
	} else if (y <= 1.65e-5) {
		tmp = 1.0 / y;
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if y <= -3.2e+84:
		tmp = x
	elif y <= 1.65e-5:
		tmp = 1.0 / y
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (y <= -3.2e+84)
		tmp = x;
	elseif (y <= 1.65e-5)
		tmp = Float64(1.0 / y);
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (y <= -3.2e+84)
		tmp = x;
	elseif (y <= 1.65e-5)
		tmp = 1.0 / y;
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[y, -3.2e+84], x, If[LessEqual[y, 1.65e-5], N[(1.0 / y), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \leq -3.2 \cdot 10^{+84}:\\
\;\;\;\;x\\

\mathbf{elif}\;y \leq 1.65 \cdot 10^{-5}:\\
\;\;\;\;\frac{1}{y}\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if y < -3.2000000000000001e84 or 1.6500000000000001e-5 < y

    1. Initial program 75.5%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod75.5%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative75.5%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified75.5%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
    4. Taylor expanded in x around inf 66.6%

      \[\leadsto \color{blue}{x} \]

    if -3.2000000000000001e84 < y < 1.6500000000000001e-5

    1. Initial program 82.4%

      \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
    2. Step-by-step derivation
      1. exp-prod99.9%

        \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
      2. +-commutative99.9%

        \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
    3. Simplified99.9%

      \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
    4. Taylor expanded in y around 0 68.4%

      \[\leadsto \color{blue}{\frac{1}{y}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification67.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \leq -3.2 \cdot 10^{+84}:\\ \;\;\;\;x\\ \mathbf{elif}\;y \leq 1.65 \cdot 10^{-5}:\\ \;\;\;\;\frac{1}{y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 5: 84.5% accurate, 42.2× speedup?

\[\begin{array}{l} \\ x + \frac{1}{y} \end{array} \]
(FPCore (x y z) :precision binary64 (+ x (/ 1.0 y)))
double code(double x, double y, double z) {
	return x + (1.0 / y);
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (1.0d0 / y)
end function
public static double code(double x, double y, double z) {
	return x + (1.0 / y);
}
def code(x, y, z):
	return x + (1.0 / y)
function code(x, y, z)
	return Float64(x + Float64(1.0 / y))
end
function tmp = code(x, y, z)
	tmp = x + (1.0 / y);
end
code[x_, y_, z_] := N[(x + N[(1.0 / y), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + \frac{1}{y}
\end{array}
Derivation
  1. Initial program 78.7%

    \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
  2. Step-by-step derivation
    1. exp-prod86.8%

      \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
    2. +-commutative86.8%

      \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
  3. Simplified86.8%

    \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
  4. Taylor expanded in y around inf 80.6%

    \[\leadsto \color{blue}{x + \frac{1}{y}} \]
  5. Step-by-step derivation
    1. +-commutative80.6%

      \[\leadsto \color{blue}{\frac{1}{y} + x} \]
  6. Simplified80.6%

    \[\leadsto \color{blue}{\frac{1}{y} + x} \]
  7. Final simplification80.6%

    \[\leadsto x + \frac{1}{y} \]

Alternative 6: 49.9% accurate, 211.0× speedup?

\[\begin{array}{l} \\ x \end{array} \]
(FPCore (x y z) :precision binary64 x)
double code(double x, double y, double z) {
	return x;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x
end function
public static double code(double x, double y, double z) {
	return x;
}
def code(x, y, z):
	return x
function code(x, y, z)
	return x
end
function tmp = code(x, y, z)
	tmp = x;
end
code[x_, y_, z_] := x
\begin{array}{l}

\\
x
\end{array}
Derivation
  1. Initial program 78.7%

    \[x + \frac{e^{y \cdot \log \left(\frac{y}{z + y}\right)}}{y} \]
  2. Step-by-step derivation
    1. exp-prod86.8%

      \[\leadsto x + \frac{\color{blue}{{\left(e^{y}\right)}^{\log \left(\frac{y}{z + y}\right)}}}{y} \]
    2. +-commutative86.8%

      \[\leadsto x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{\color{blue}{y + z}}\right)}}{y} \]
  3. Simplified86.8%

    \[\leadsto \color{blue}{x + \frac{{\left(e^{y}\right)}^{\log \left(\frac{y}{y + z}\right)}}{y}} \]
  4. Taylor expanded in x around inf 48.4%

    \[\leadsto \color{blue}{x} \]
  5. Final simplification48.4%

    \[\leadsto x \]

Developer target: 91.3% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;\frac{y}{z + y} < 7.11541576 \cdot 10^{-315}:\\ \;\;\;\;x + \frac{e^{\frac{-1}{z}}}{y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{e^{\log \left({\left(\frac{y}{y + z}\right)}^{y}\right)}}{y}\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (< (/ y (+ z y)) 7.11541576e-315)
   (+ x (/ (exp (/ -1.0 z)) y))
   (+ x (/ (exp (log (pow (/ y (+ y z)) y))) y))))
double code(double x, double y, double z) {
	double tmp;
	if ((y / (z + y)) < 7.11541576e-315) {
		tmp = x + (exp((-1.0 / z)) / y);
	} else {
		tmp = x + (exp(log(pow((y / (y + z)), y))) / y);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if ((y / (z + y)) < 7.11541576d-315) then
        tmp = x + (exp(((-1.0d0) / z)) / y)
    else
        tmp = x + (exp(log(((y / (y + z)) ** y))) / y)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if ((y / (z + y)) < 7.11541576e-315) {
		tmp = x + (Math.exp((-1.0 / z)) / y);
	} else {
		tmp = x + (Math.exp(Math.log(Math.pow((y / (y + z)), y))) / y);
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if (y / (z + y)) < 7.11541576e-315:
		tmp = x + (math.exp((-1.0 / z)) / y)
	else:
		tmp = x + (math.exp(math.log(math.pow((y / (y + z)), y))) / y)
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (Float64(y / Float64(z + y)) < 7.11541576e-315)
		tmp = Float64(x + Float64(exp(Float64(-1.0 / z)) / y));
	else
		tmp = Float64(x + Float64(exp(log((Float64(y / Float64(y + z)) ^ y))) / y));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if ((y / (z + y)) < 7.11541576e-315)
		tmp = x + (exp((-1.0 / z)) / y);
	else
		tmp = x + (exp(log(((y / (y + z)) ^ y))) / y);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Less[N[(y / N[(z + y), $MachinePrecision]), $MachinePrecision], 7.11541576e-315], N[(x + N[(N[Exp[N[(-1.0 / z), $MachinePrecision]], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision], N[(x + N[(N[Exp[N[Log[N[Power[N[(y / N[(y + z), $MachinePrecision]), $MachinePrecision], y], $MachinePrecision]], $MachinePrecision]], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;\frac{y}{z + y} < 7.11541576 \cdot 10^{-315}:\\
\;\;\;\;x + \frac{e^{\frac{-1}{z}}}{y}\\

\mathbf{else}:\\
\;\;\;\;x + \frac{e^{\log \left({\left(\frac{y}{y + z}\right)}^{y}\right)}}{y}\\


\end{array}
\end{array}

Reproduce

?
herbie shell --seed 2023320 
(FPCore (x y z)
  :name "Numeric.SpecFunctions:invIncompleteBetaWorker from math-functions-0.1.5.2, G"
  :precision binary64

  :herbie-target
  (if (< (/ y (+ z y)) 7.11541576e-315) (+ x (/ (exp (/ -1.0 z)) y)) (+ x (/ (exp (log (pow (/ y (+ y z)) y))) y)))

  (+ x (/ (exp (* y (log (/ y (+ z y))))) y)))