jeff quadratic root 2

Percentage Accurate: 71.9% → 90.4%
Time: 16.8s
Alternatives: 5
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}\\ \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - t_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + t_0}{2 \cdot a}\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (let* ((t_0 (sqrt (- (* b b) (* (* 4.0 a) c)))))
   (if (>= b 0.0) (/ (* 2.0 c) (- (- b) t_0)) (/ (+ (- b) t_0) (* 2.0 a)))))
double code(double a, double b, double c) {
	double t_0 = sqrt(((b * b) - ((4.0 * a) * c)));
	double tmp;
	if (b >= 0.0) {
		tmp = (2.0 * c) / (-b - t_0);
	} else {
		tmp = (-b + t_0) / (2.0 * a);
	}
	return tmp;
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_0
    real(8) :: tmp
    t_0 = sqrt(((b * b) - ((4.0d0 * a) * c)))
    if (b >= 0.0d0) then
        tmp = (2.0d0 * c) / (-b - t_0)
    else
        tmp = (-b + t_0) / (2.0d0 * a)
    end if
    code = tmp
end function
public static double code(double a, double b, double c) {
	double t_0 = Math.sqrt(((b * b) - ((4.0 * a) * c)));
	double tmp;
	if (b >= 0.0) {
		tmp = (2.0 * c) / (-b - t_0);
	} else {
		tmp = (-b + t_0) / (2.0 * a);
	}
	return tmp;
}
def code(a, b, c):
	t_0 = math.sqrt(((b * b) - ((4.0 * a) * c)))
	tmp = 0
	if b >= 0.0:
		tmp = (2.0 * c) / (-b - t_0)
	else:
		tmp = (-b + t_0) / (2.0 * a)
	return tmp
function code(a, b, c)
	t_0 = sqrt(Float64(Float64(b * b) - Float64(Float64(4.0 * a) * c)))
	tmp = 0.0
	if (b >= 0.0)
		tmp = Float64(Float64(2.0 * c) / Float64(Float64(-b) - t_0));
	else
		tmp = Float64(Float64(Float64(-b) + t_0) / Float64(2.0 * a));
	end
	return tmp
end
function tmp_2 = code(a, b, c)
	t_0 = sqrt(((b * b) - ((4.0 * a) * c)));
	tmp = 0.0;
	if (b >= 0.0)
		tmp = (2.0 * c) / (-b - t_0);
	else
		tmp = (-b + t_0) / (2.0 * a);
	end
	tmp_2 = tmp;
end
code[a_, b_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(4.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[GreaterEqual[b, 0.0], N[(N[(2.0 * c), $MachinePrecision] / N[((-b) - t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[((-b) + t$95$0), $MachinePrecision] / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}\\
\mathbf{if}\;b \geq 0:\\
\;\;\;\;\frac{2 \cdot c}{\left(-b\right) - t_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{\left(-b\right) + t_0}{2 \cdot a}\\


\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 5 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 71.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}\\ \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - t_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + t_0}{2 \cdot a}\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (let* ((t_0 (sqrt (- (* b b) (* (* 4.0 a) c)))))
   (if (>= b 0.0) (/ (* 2.0 c) (- (- b) t_0)) (/ (+ (- b) t_0) (* 2.0 a)))))
double code(double a, double b, double c) {
	double t_0 = sqrt(((b * b) - ((4.0 * a) * c)));
	double tmp;
	if (b >= 0.0) {
		tmp = (2.0 * c) / (-b - t_0);
	} else {
		tmp = (-b + t_0) / (2.0 * a);
	}
	return tmp;
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_0
    real(8) :: tmp
    t_0 = sqrt(((b * b) - ((4.0d0 * a) * c)))
    if (b >= 0.0d0) then
        tmp = (2.0d0 * c) / (-b - t_0)
    else
        tmp = (-b + t_0) / (2.0d0 * a)
    end if
    code = tmp
end function
public static double code(double a, double b, double c) {
	double t_0 = Math.sqrt(((b * b) - ((4.0 * a) * c)));
	double tmp;
	if (b >= 0.0) {
		tmp = (2.0 * c) / (-b - t_0);
	} else {
		tmp = (-b + t_0) / (2.0 * a);
	}
	return tmp;
}
def code(a, b, c):
	t_0 = math.sqrt(((b * b) - ((4.0 * a) * c)))
	tmp = 0
	if b >= 0.0:
		tmp = (2.0 * c) / (-b - t_0)
	else:
		tmp = (-b + t_0) / (2.0 * a)
	return tmp
function code(a, b, c)
	t_0 = sqrt(Float64(Float64(b * b) - Float64(Float64(4.0 * a) * c)))
	tmp = 0.0
	if (b >= 0.0)
		tmp = Float64(Float64(2.0 * c) / Float64(Float64(-b) - t_0));
	else
		tmp = Float64(Float64(Float64(-b) + t_0) / Float64(2.0 * a));
	end
	return tmp
end
function tmp_2 = code(a, b, c)
	t_0 = sqrt(((b * b) - ((4.0 * a) * c)));
	tmp = 0.0;
	if (b >= 0.0)
		tmp = (2.0 * c) / (-b - t_0);
	else
		tmp = (-b + t_0) / (2.0 * a);
	end
	tmp_2 = tmp;
end
code[a_, b_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(4.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[GreaterEqual[b, 0.0], N[(N[(2.0 * c), $MachinePrecision] / N[((-b) - t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[((-b) + t$95$0), $MachinePrecision] / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}\\
\mathbf{if}\;b \geq 0:\\
\;\;\;\;\frac{2 \cdot c}{\left(-b\right) - t_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{\left(-b\right) + t_0}{2 \cdot a}\\


\end{array}
\end{array}

Alternative 1: 90.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}\\ \mathbf{if}\;b \leq -1 \cdot 10^{+154} \lor \neg \left(b \leq 2 \cdot 10^{+115}\right):\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{c \cdot 2}{\left(-b\right) - t_0}\\ \mathbf{else}:\\ \;\;\;\;\frac{t_0 - b}{a \cdot 2}\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (let* ((t_0 (sqrt (- (* b b) (* c (* a 4.0))))))
   (if (or (<= b -1e+154) (not (<= b 2e+115)))
     (if (>= b 0.0) (/ (- c) b) (- (/ b a)))
     (if (>= b 0.0) (/ (* c 2.0) (- (- b) t_0)) (/ (- t_0 b) (* a 2.0))))))
double code(double a, double b, double c) {
	double t_0 = sqrt(((b * b) - (c * (a * 4.0))));
	double tmp_1;
	if ((b <= -1e+154) || !(b <= 2e+115)) {
		double tmp_2;
		if (b >= 0.0) {
			tmp_2 = -c / b;
		} else {
			tmp_2 = -(b / a);
		}
		tmp_1 = tmp_2;
	} else if (b >= 0.0) {
		tmp_1 = (c * 2.0) / (-b - t_0);
	} else {
		tmp_1 = (t_0 - b) / (a * 2.0);
	}
	return tmp_1;
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_0
    real(8) :: tmp
    real(8) :: tmp_1
    real(8) :: tmp_2
    t_0 = sqrt(((b * b) - (c * (a * 4.0d0))))
    if ((b <= (-1d+154)) .or. (.not. (b <= 2d+115))) then
        if (b >= 0.0d0) then
            tmp_2 = -c / b
        else
            tmp_2 = -(b / a)
        end if
        tmp_1 = tmp_2
    else if (b >= 0.0d0) then
        tmp_1 = (c * 2.0d0) / (-b - t_0)
    else
        tmp_1 = (t_0 - b) / (a * 2.0d0)
    end if
    code = tmp_1
end function
public static double code(double a, double b, double c) {
	double t_0 = Math.sqrt(((b * b) - (c * (a * 4.0))));
	double tmp_1;
	if ((b <= -1e+154) || !(b <= 2e+115)) {
		double tmp_2;
		if (b >= 0.0) {
			tmp_2 = -c / b;
		} else {
			tmp_2 = -(b / a);
		}
		tmp_1 = tmp_2;
	} else if (b >= 0.0) {
		tmp_1 = (c * 2.0) / (-b - t_0);
	} else {
		tmp_1 = (t_0 - b) / (a * 2.0);
	}
	return tmp_1;
}
def code(a, b, c):
	t_0 = math.sqrt(((b * b) - (c * (a * 4.0))))
	tmp_1 = 0
	if (b <= -1e+154) or not (b <= 2e+115):
		tmp_2 = 0
		if b >= 0.0:
			tmp_2 = -c / b
		else:
			tmp_2 = -(b / a)
		tmp_1 = tmp_2
	elif b >= 0.0:
		tmp_1 = (c * 2.0) / (-b - t_0)
	else:
		tmp_1 = (t_0 - b) / (a * 2.0)
	return tmp_1
function code(a, b, c)
	t_0 = sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 4.0))))
	tmp_1 = 0.0
	if ((b <= -1e+154) || !(b <= 2e+115))
		tmp_2 = 0.0
		if (b >= 0.0)
			tmp_2 = Float64(Float64(-c) / b);
		else
			tmp_2 = Float64(-Float64(b / a));
		end
		tmp_1 = tmp_2;
	elseif (b >= 0.0)
		tmp_1 = Float64(Float64(c * 2.0) / Float64(Float64(-b) - t_0));
	else
		tmp_1 = Float64(Float64(t_0 - b) / Float64(a * 2.0));
	end
	return tmp_1
end
function tmp_4 = code(a, b, c)
	t_0 = sqrt(((b * b) - (c * (a * 4.0))));
	tmp_2 = 0.0;
	if ((b <= -1e+154) || ~((b <= 2e+115)))
		tmp_3 = 0.0;
		if (b >= 0.0)
			tmp_3 = -c / b;
		else
			tmp_3 = -(b / a);
		end
		tmp_2 = tmp_3;
	elseif (b >= 0.0)
		tmp_2 = (c * 2.0) / (-b - t_0);
	else
		tmp_2 = (t_0 - b) / (a * 2.0);
	end
	tmp_4 = tmp_2;
end
code[a_, b_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[Or[LessEqual[b, -1e+154], N[Not[LessEqual[b, 2e+115]], $MachinePrecision]], If[GreaterEqual[b, 0.0], N[((-c) / b), $MachinePrecision], (-N[(b / a), $MachinePrecision])], If[GreaterEqual[b, 0.0], N[(N[(c * 2.0), $MachinePrecision] / N[((-b) - t$95$0), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}\\
\mathbf{if}\;b \leq -1 \cdot 10^{+154} \lor \neg \left(b \leq 2 \cdot 10^{+115}\right):\\
\;\;\;\;\begin{array}{l}
\mathbf{if}\;b \geq 0:\\
\;\;\;\;\frac{-c}{b}\\

\mathbf{else}:\\
\;\;\;\;-\frac{b}{a}\\


\end{array}\\

\mathbf{elif}\;b \geq 0:\\
\;\;\;\;\frac{c \cdot 2}{\left(-b\right) - t_0}\\

\mathbf{else}:\\
\;\;\;\;\frac{t_0 - b}{a \cdot 2}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < -1.00000000000000004e154 or 2e115 < b

    1. Initial program 48.6%

      \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
    2. Step-by-step derivation
      1. Simplified48.5%

        \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\left(-b\right) - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}} \cdot c\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ } \end{array}} \]
      2. Taylor expanded in b around inf 80.3%

        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-1 \cdot \frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
      3. Step-by-step derivation
        1. mul-1-neg80.3%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-\frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
        2. distribute-neg-frac80.3%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
      4. Simplified80.3%

        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
      5. Taylor expanded in b around -inf 100.0%

        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \frac{b}{a}\\ \end{array} \]
      6. Step-by-step derivation
        1. mul-1-neg100.0%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]
        2. distribute-frac-neg100.0%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]
      7. Simplified100.0%

        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]

      if -1.00000000000000004e154 < b < 2e115

      1. Initial program 87.2%

        \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification91.8%

      \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -1 \cdot 10^{+154} \lor \neg \left(b \leq 2 \cdot 10^{+115}\right):\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{c \cdot 2}{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\ \end{array} \]

    Alternative 2: 90.3% accurate, 1.0× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ t_1 := \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}\\ \mathbf{if}\;b \leq -7 \cdot 10^{+153}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;b \leq -1 \cdot 10^{-310}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{b \cdot -2}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{t_1 - b}{a \cdot 2}\\ \end{array}\\ \mathbf{elif}\;b \leq 1.35 \cdot 10^{+115}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - t_1}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{2 \cdot \frac{a}{\frac{b}{c}}}{a \cdot 2}\\ \end{array}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \end{array} \]
    (FPCore (a b c)
     :precision binary64
     (let* ((t_0 (if (>= b 0.0) (/ (- c) b) (- (/ b a))))
            (t_1 (sqrt (- (* b b) (* c (* a 4.0))))))
       (if (<= b -7e+153)
         t_0
         (if (<= b -1e-310)
           (if (>= b 0.0) (/ 2.0 (/ (* b -2.0) c)) (/ (- t_1 b) (* a 2.0)))
           (if (<= b 1.35e+115)
             (if (>= b 0.0)
               (/ 2.0 (/ (- (- b) t_1) c))
               (/ (* 2.0 (/ a (/ b c))) (* a 2.0)))
             t_0)))))
    double code(double a, double b, double c) {
    	double tmp;
    	if (b >= 0.0) {
    		tmp = -c / b;
    	} else {
    		tmp = -(b / a);
    	}
    	double t_0 = tmp;
    	double t_1 = sqrt(((b * b) - (c * (a * 4.0))));
    	double tmp_1;
    	if (b <= -7e+153) {
    		tmp_1 = t_0;
    	} else if (b <= -1e-310) {
    		double tmp_2;
    		if (b >= 0.0) {
    			tmp_2 = 2.0 / ((b * -2.0) / c);
    		} else {
    			tmp_2 = (t_1 - b) / (a * 2.0);
    		}
    		tmp_1 = tmp_2;
    	} else if (b <= 1.35e+115) {
    		double tmp_3;
    		if (b >= 0.0) {
    			tmp_3 = 2.0 / ((-b - t_1) / c);
    		} else {
    			tmp_3 = (2.0 * (a / (b / c))) / (a * 2.0);
    		}
    		tmp_1 = tmp_3;
    	} else {
    		tmp_1 = t_0;
    	}
    	return tmp_1;
    }
    
    real(8) function code(a, b, c)
        real(8), intent (in) :: a
        real(8), intent (in) :: b
        real(8), intent (in) :: c
        real(8) :: t_0
        real(8) :: t_1
        real(8) :: tmp
        real(8) :: tmp_1
        real(8) :: tmp_2
        real(8) :: tmp_3
        if (b >= 0.0d0) then
            tmp = -c / b
        else
            tmp = -(b / a)
        end if
        t_0 = tmp
        t_1 = sqrt(((b * b) - (c * (a * 4.0d0))))
        if (b <= (-7d+153)) then
            tmp_1 = t_0
        else if (b <= (-1d-310)) then
            if (b >= 0.0d0) then
                tmp_2 = 2.0d0 / ((b * (-2.0d0)) / c)
            else
                tmp_2 = (t_1 - b) / (a * 2.0d0)
            end if
            tmp_1 = tmp_2
        else if (b <= 1.35d+115) then
            if (b >= 0.0d0) then
                tmp_3 = 2.0d0 / ((-b - t_1) / c)
            else
                tmp_3 = (2.0d0 * (a / (b / c))) / (a * 2.0d0)
            end if
            tmp_1 = tmp_3
        else
            tmp_1 = t_0
        end if
        code = tmp_1
    end function
    
    public static double code(double a, double b, double c) {
    	double tmp;
    	if (b >= 0.0) {
    		tmp = -c / b;
    	} else {
    		tmp = -(b / a);
    	}
    	double t_0 = tmp;
    	double t_1 = Math.sqrt(((b * b) - (c * (a * 4.0))));
    	double tmp_1;
    	if (b <= -7e+153) {
    		tmp_1 = t_0;
    	} else if (b <= -1e-310) {
    		double tmp_2;
    		if (b >= 0.0) {
    			tmp_2 = 2.0 / ((b * -2.0) / c);
    		} else {
    			tmp_2 = (t_1 - b) / (a * 2.0);
    		}
    		tmp_1 = tmp_2;
    	} else if (b <= 1.35e+115) {
    		double tmp_3;
    		if (b >= 0.0) {
    			tmp_3 = 2.0 / ((-b - t_1) / c);
    		} else {
    			tmp_3 = (2.0 * (a / (b / c))) / (a * 2.0);
    		}
    		tmp_1 = tmp_3;
    	} else {
    		tmp_1 = t_0;
    	}
    	return tmp_1;
    }
    
    def code(a, b, c):
    	tmp = 0
    	if b >= 0.0:
    		tmp = -c / b
    	else:
    		tmp = -(b / a)
    	t_0 = tmp
    	t_1 = math.sqrt(((b * b) - (c * (a * 4.0))))
    	tmp_1 = 0
    	if b <= -7e+153:
    		tmp_1 = t_0
    	elif b <= -1e-310:
    		tmp_2 = 0
    		if b >= 0.0:
    			tmp_2 = 2.0 / ((b * -2.0) / c)
    		else:
    			tmp_2 = (t_1 - b) / (a * 2.0)
    		tmp_1 = tmp_2
    	elif b <= 1.35e+115:
    		tmp_3 = 0
    		if b >= 0.0:
    			tmp_3 = 2.0 / ((-b - t_1) / c)
    		else:
    			tmp_3 = (2.0 * (a / (b / c))) / (a * 2.0)
    		tmp_1 = tmp_3
    	else:
    		tmp_1 = t_0
    	return tmp_1
    
    function code(a, b, c)
    	tmp = 0.0
    	if (b >= 0.0)
    		tmp = Float64(Float64(-c) / b);
    	else
    		tmp = Float64(-Float64(b / a));
    	end
    	t_0 = tmp
    	t_1 = sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 4.0))))
    	tmp_1 = 0.0
    	if (b <= -7e+153)
    		tmp_1 = t_0;
    	elseif (b <= -1e-310)
    		tmp_2 = 0.0
    		if (b >= 0.0)
    			tmp_2 = Float64(2.0 / Float64(Float64(b * -2.0) / c));
    		else
    			tmp_2 = Float64(Float64(t_1 - b) / Float64(a * 2.0));
    		end
    		tmp_1 = tmp_2;
    	elseif (b <= 1.35e+115)
    		tmp_3 = 0.0
    		if (b >= 0.0)
    			tmp_3 = Float64(2.0 / Float64(Float64(Float64(-b) - t_1) / c));
    		else
    			tmp_3 = Float64(Float64(2.0 * Float64(a / Float64(b / c))) / Float64(a * 2.0));
    		end
    		tmp_1 = tmp_3;
    	else
    		tmp_1 = t_0;
    	end
    	return tmp_1
    end
    
    function tmp_5 = code(a, b, c)
    	tmp = 0.0;
    	if (b >= 0.0)
    		tmp = -c / b;
    	else
    		tmp = -(b / a);
    	end
    	t_0 = tmp;
    	t_1 = sqrt(((b * b) - (c * (a * 4.0))));
    	tmp_2 = 0.0;
    	if (b <= -7e+153)
    		tmp_2 = t_0;
    	elseif (b <= -1e-310)
    		tmp_3 = 0.0;
    		if (b >= 0.0)
    			tmp_3 = 2.0 / ((b * -2.0) / c);
    		else
    			tmp_3 = (t_1 - b) / (a * 2.0);
    		end
    		tmp_2 = tmp_3;
    	elseif (b <= 1.35e+115)
    		tmp_4 = 0.0;
    		if (b >= 0.0)
    			tmp_4 = 2.0 / ((-b - t_1) / c);
    		else
    			tmp_4 = (2.0 * (a / (b / c))) / (a * 2.0);
    		end
    		tmp_2 = tmp_4;
    	else
    		tmp_2 = t_0;
    	end
    	tmp_5 = tmp_2;
    end
    
    code[a_, b_, c_] := Block[{t$95$0 = If[GreaterEqual[b, 0.0], N[((-c) / b), $MachinePrecision], (-N[(b / a), $MachinePrecision])]}, Block[{t$95$1 = N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[b, -7e+153], t$95$0, If[LessEqual[b, -1e-310], If[GreaterEqual[b, 0.0], N[(2.0 / N[(N[(b * -2.0), $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$1 - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]], If[LessEqual[b, 1.35e+115], If[GreaterEqual[b, 0.0], N[(2.0 / N[(N[((-b) - t$95$1), $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision], N[(N[(2.0 * N[(a / N[(b / c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]], t$95$0]]]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \begin{array}{l}
    \mathbf{if}\;b \geq 0:\\
    \;\;\;\;\frac{-c}{b}\\
    
    \mathbf{else}:\\
    \;\;\;\;-\frac{b}{a}\\
    
    
    \end{array}\\
    t_1 := \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}\\
    \mathbf{if}\;b \leq -7 \cdot 10^{+153}:\\
    \;\;\;\;t_0\\
    
    \mathbf{elif}\;b \leq -1 \cdot 10^{-310}:\\
    \;\;\;\;\begin{array}{l}
    \mathbf{if}\;b \geq 0:\\
    \;\;\;\;\frac{2}{\frac{b \cdot -2}{c}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{t_1 - b}{a \cdot 2}\\
    
    
    \end{array}\\
    
    \mathbf{elif}\;b \leq 1.35 \cdot 10^{+115}:\\
    \;\;\;\;\begin{array}{l}
    \mathbf{if}\;b \geq 0:\\
    \;\;\;\;\frac{2}{\frac{\left(-b\right) - t_1}{c}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\frac{2 \cdot \frac{a}{\frac{b}{c}}}{a \cdot 2}\\
    
    
    \end{array}\\
    
    \mathbf{else}:\\
    \;\;\;\;t_0\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 3 regimes
    2. if b < -6.9999999999999998e153 or 1.35000000000000002e115 < b

      1. Initial program 48.6%

        \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
      2. Step-by-step derivation
        1. Simplified48.5%

          \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\left(-b\right) - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}} \cdot c\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ } \end{array}} \]
        2. Taylor expanded in b around inf 80.3%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-1 \cdot \frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
        3. Step-by-step derivation
          1. mul-1-neg80.3%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-\frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
          2. distribute-neg-frac80.3%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
        4. Simplified80.3%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
        5. Taylor expanded in b around -inf 100.0%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \frac{b}{a}\\ \end{array} \]
        6. Step-by-step derivation
          1. mul-1-neg100.0%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]
          2. distribute-frac-neg100.0%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]
        7. Simplified100.0%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]

        if -6.9999999999999998e153 < b < -9.999999999999969e-311

        1. Initial program 87.6%

          \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
        2. Step-by-step derivation
          1. Simplified87.6%

            \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ } \end{array}} \]
          2. Taylor expanded in b around inf 87.6%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\color{blue}{-2 \cdot \frac{b}{c}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
          3. Step-by-step derivation
            1. associate-*r/87.6%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\color{blue}{\frac{-2 \cdot b}{c}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
            2. *-commutative87.6%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\color{blue}{b \cdot -2}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
          4. Simplified87.6%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\color{blue}{\frac{b \cdot -2}{c}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]

          if -9.999999999999969e-311 < b < 1.35000000000000002e115

          1. Initial program 86.8%

            \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
          2. Step-by-step derivation
            1. Simplified85.2%

              \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ } \end{array}} \]
            2. Step-by-step derivation
              1. *-commutative85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
              2. flip-+85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\left(-b\right) \cdot \left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c} \cdot \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}}{2 \cdot a}\\ \end{array} \]
              3. add-sqr-sqrt85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\left(-b\right) \cdot \left(-b\right) - \left(b \cdot b - \left(4 \cdot a\right) \cdot c\right)}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}}{2 \cdot a}\\ \end{array} \]
              4. sqr-neg85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{b \cdot b - \left(b \cdot b - \left(4 \cdot a\right) \cdot c\right)}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}}{2 \cdot a}\\ \end{array} \]
              5. div-sub85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{b \cdot b}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}} - \frac{b \cdot b - \left(4 \cdot a\right) \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}}{2 \cdot a}\\ \end{array} \]
            3. Applied egg-rr85.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{b}^{2}}{b - \sqrt{{b}^{2} - c \cdot \left(a \cdot 4\right)}} - \frac{{b}^{2} - c \cdot \left(a \cdot 4\right)}{b - \sqrt{{b}^{2} - c \cdot \left(a \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
            4. Step-by-step derivation
              1. div-sub85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{{b}^{2} - \left({b}^{2} - c \cdot \left(a \cdot 4\right)\right)}{b - \sqrt{{b}^{2} - c \cdot \left(a \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
              2. associate--r-85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{\left({b}^{2} - {b}^{2}\right) + c \cdot \left(a \cdot 4\right)}{b - \sqrt{{b}^{2} - c \cdot \left(a \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
              3. +-inverses85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{{b}^{2} - c \cdot \left(a \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
              4. unpow285.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
              5. fma-neg85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, -c \cdot \left(a \cdot 4\right)\right)}}}{2 \cdot a}\\ \end{array} \]
              6. associate-*r*85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, -\left(c \cdot a\right) \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
              7. *-commutative85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, -\left(a \cdot c\right) \cdot 4\right)}}}{2 \cdot a}\\ \end{array} \]
              8. distribute-rgt-neg-in85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, \left(a \cdot c\right) \cdot \left(-4\right)\right)}}}{2 \cdot a}\\ \end{array} \]
              9. *-commutative85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, \left(c \cdot a\right) \cdot \left(-4\right)\right)}}}{2 \cdot a}\\ \end{array} \]
              10. metadata-eval85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, \left(c \cdot a\right) \cdot -4\right)}}}{2 \cdot a}\\ \end{array} \]
              11. associate-*l*85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}}}{2 \cdot a}\\ \end{array} \]
            5. Simplified85.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{0 + c \cdot \left(a \cdot 4\right)}{b - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}}}{2 \cdot a}\\ \end{array} \]
            6. Taylor expanded in b around -inf 85.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{2 \cdot \frac{a \cdot c}{b}}{2 \cdot a}\\ \end{array} \]
            7. Step-by-step derivation
              1. associate-/l*85.2%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{2 \cdot \frac{a}{\frac{b}{c}}}{2 \cdot a}\\ \end{array} \]
            8. Simplified85.2%

              \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{2 \cdot \frac{a}{\frac{b}{c}}}{2 \cdot a}\\ \end{array} \]
          3. Recombined 3 regimes into one program.
          4. Final simplification91.3%

            \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -7 \cdot 10^{+153}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \leq -1 \cdot 10^{-310}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{b \cdot -2}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\ \end{array}\\ \mathbf{elif}\;b \leq 1.35 \cdot 10^{+115}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{2 \cdot \frac{a}{\frac{b}{c}}}{a \cdot 2}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]

          Alternative 3: 90.3% accurate, 1.0× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}\\ \mathbf{if}\;b \leq -8 \cdot 10^{+153} \lor \neg \left(b \leq 5.4 \cdot 10^{+115}\right):\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - t_0}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{t_0 - b}{a \cdot 2}\\ \end{array} \end{array} \]
          (FPCore (a b c)
           :precision binary64
           (let* ((t_0 (sqrt (- (* b b) (* c (* a 4.0))))))
             (if (or (<= b -8e+153) (not (<= b 5.4e+115)))
               (if (>= b 0.0) (/ (- c) b) (- (/ b a)))
               (if (>= b 0.0) (/ 2.0 (/ (- (- b) t_0) c)) (/ (- t_0 b) (* a 2.0))))))
          double code(double a, double b, double c) {
          	double t_0 = sqrt(((b * b) - (c * (a * 4.0))));
          	double tmp_1;
          	if ((b <= -8e+153) || !(b <= 5.4e+115)) {
          		double tmp_2;
          		if (b >= 0.0) {
          			tmp_2 = -c / b;
          		} else {
          			tmp_2 = -(b / a);
          		}
          		tmp_1 = tmp_2;
          	} else if (b >= 0.0) {
          		tmp_1 = 2.0 / ((-b - t_0) / c);
          	} else {
          		tmp_1 = (t_0 - b) / (a * 2.0);
          	}
          	return tmp_1;
          }
          
          real(8) function code(a, b, c)
              real(8), intent (in) :: a
              real(8), intent (in) :: b
              real(8), intent (in) :: c
              real(8) :: t_0
              real(8) :: tmp
              real(8) :: tmp_1
              real(8) :: tmp_2
              t_0 = sqrt(((b * b) - (c * (a * 4.0d0))))
              if ((b <= (-8d+153)) .or. (.not. (b <= 5.4d+115))) then
                  if (b >= 0.0d0) then
                      tmp_2 = -c / b
                  else
                      tmp_2 = -(b / a)
                  end if
                  tmp_1 = tmp_2
              else if (b >= 0.0d0) then
                  tmp_1 = 2.0d0 / ((-b - t_0) / c)
              else
                  tmp_1 = (t_0 - b) / (a * 2.0d0)
              end if
              code = tmp_1
          end function
          
          public static double code(double a, double b, double c) {
          	double t_0 = Math.sqrt(((b * b) - (c * (a * 4.0))));
          	double tmp_1;
          	if ((b <= -8e+153) || !(b <= 5.4e+115)) {
          		double tmp_2;
          		if (b >= 0.0) {
          			tmp_2 = -c / b;
          		} else {
          			tmp_2 = -(b / a);
          		}
          		tmp_1 = tmp_2;
          	} else if (b >= 0.0) {
          		tmp_1 = 2.0 / ((-b - t_0) / c);
          	} else {
          		tmp_1 = (t_0 - b) / (a * 2.0);
          	}
          	return tmp_1;
          }
          
          def code(a, b, c):
          	t_0 = math.sqrt(((b * b) - (c * (a * 4.0))))
          	tmp_1 = 0
          	if (b <= -8e+153) or not (b <= 5.4e+115):
          		tmp_2 = 0
          		if b >= 0.0:
          			tmp_2 = -c / b
          		else:
          			tmp_2 = -(b / a)
          		tmp_1 = tmp_2
          	elif b >= 0.0:
          		tmp_1 = 2.0 / ((-b - t_0) / c)
          	else:
          		tmp_1 = (t_0 - b) / (a * 2.0)
          	return tmp_1
          
          function code(a, b, c)
          	t_0 = sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 4.0))))
          	tmp_1 = 0.0
          	if ((b <= -8e+153) || !(b <= 5.4e+115))
          		tmp_2 = 0.0
          		if (b >= 0.0)
          			tmp_2 = Float64(Float64(-c) / b);
          		else
          			tmp_2 = Float64(-Float64(b / a));
          		end
          		tmp_1 = tmp_2;
          	elseif (b >= 0.0)
          		tmp_1 = Float64(2.0 / Float64(Float64(Float64(-b) - t_0) / c));
          	else
          		tmp_1 = Float64(Float64(t_0 - b) / Float64(a * 2.0));
          	end
          	return tmp_1
          end
          
          function tmp_4 = code(a, b, c)
          	t_0 = sqrt(((b * b) - (c * (a * 4.0))));
          	tmp_2 = 0.0;
          	if ((b <= -8e+153) || ~((b <= 5.4e+115)))
          		tmp_3 = 0.0;
          		if (b >= 0.0)
          			tmp_3 = -c / b;
          		else
          			tmp_3 = -(b / a);
          		end
          		tmp_2 = tmp_3;
          	elseif (b >= 0.0)
          		tmp_2 = 2.0 / ((-b - t_0) / c);
          	else
          		tmp_2 = (t_0 - b) / (a * 2.0);
          	end
          	tmp_4 = tmp_2;
          end
          
          code[a_, b_, c_] := Block[{t$95$0 = N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[Or[LessEqual[b, -8e+153], N[Not[LessEqual[b, 5.4e+115]], $MachinePrecision]], If[GreaterEqual[b, 0.0], N[((-c) / b), $MachinePrecision], (-N[(b / a), $MachinePrecision])], If[GreaterEqual[b, 0.0], N[(2.0 / N[(N[((-b) - t$95$0), $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision], N[(N[(t$95$0 - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_0 := \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}\\
          \mathbf{if}\;b \leq -8 \cdot 10^{+153} \lor \neg \left(b \leq 5.4 \cdot 10^{+115}\right):\\
          \;\;\;\;\begin{array}{l}
          \mathbf{if}\;b \geq 0:\\
          \;\;\;\;\frac{-c}{b}\\
          
          \mathbf{else}:\\
          \;\;\;\;-\frac{b}{a}\\
          
          
          \end{array}\\
          
          \mathbf{elif}\;b \geq 0:\\
          \;\;\;\;\frac{2}{\frac{\left(-b\right) - t_0}{c}}\\
          
          \mathbf{else}:\\
          \;\;\;\;\frac{t_0 - b}{a \cdot 2}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if b < -8e153 or 5.40000000000000008e115 < b

            1. Initial program 48.6%

              \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
            2. Step-by-step derivation
              1. Simplified48.5%

                \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\left(-b\right) - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}} \cdot c\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ } \end{array}} \]
              2. Taylor expanded in b around inf 80.3%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-1 \cdot \frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
              3. Step-by-step derivation
                1. mul-1-neg80.3%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-\frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                2. distribute-neg-frac80.3%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
              4. Simplified80.3%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
              5. Taylor expanded in b around -inf 100.0%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \frac{b}{a}\\ \end{array} \]
              6. Step-by-step derivation
                1. mul-1-neg100.0%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]
                2. distribute-frac-neg100.0%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]
              7. Simplified100.0%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]

              if -8e153 < b < 5.40000000000000008e115

              1. Initial program 87.2%

                \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
              2. Step-by-step derivation
                1. Simplified86.5%

                  \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ } \end{array}} \]
              3. Recombined 2 regimes into one program.
              4. Final simplification91.3%

                \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -8 \cdot 10^{+153} \lor \neg \left(b \leq 5.4 \cdot 10^{+115}\right):\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\ \end{array} \]

              Alternative 4: 78.8% accurate, 1.0× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq -6.5 \cdot 10^{+153}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{b \cdot -2}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\ \end{array} \end{array} \]
              (FPCore (a b c)
               :precision binary64
               (if (<= b -6.5e+153)
                 (if (>= b 0.0) (/ (- c) b) (- (/ b a)))
                 (if (>= b 0.0)
                   (/ 2.0 (/ (* b -2.0) c))
                   (/ (- (sqrt (- (* b b) (* c (* a 4.0)))) b) (* a 2.0)))))
              double code(double a, double b, double c) {
              	double tmp_1;
              	if (b <= -6.5e+153) {
              		double tmp_2;
              		if (b >= 0.0) {
              			tmp_2 = -c / b;
              		} else {
              			tmp_2 = -(b / a);
              		}
              		tmp_1 = tmp_2;
              	} else if (b >= 0.0) {
              		tmp_1 = 2.0 / ((b * -2.0) / c);
              	} else {
              		tmp_1 = (sqrt(((b * b) - (c * (a * 4.0)))) - b) / (a * 2.0);
              	}
              	return tmp_1;
              }
              
              real(8) function code(a, b, c)
                  real(8), intent (in) :: a
                  real(8), intent (in) :: b
                  real(8), intent (in) :: c
                  real(8) :: tmp
                  real(8) :: tmp_1
                  real(8) :: tmp_2
                  if (b <= (-6.5d+153)) then
                      if (b >= 0.0d0) then
                          tmp_2 = -c / b
                      else
                          tmp_2 = -(b / a)
                      end if
                      tmp_1 = tmp_2
                  else if (b >= 0.0d0) then
                      tmp_1 = 2.0d0 / ((b * (-2.0d0)) / c)
                  else
                      tmp_1 = (sqrt(((b * b) - (c * (a * 4.0d0)))) - b) / (a * 2.0d0)
                  end if
                  code = tmp_1
              end function
              
              public static double code(double a, double b, double c) {
              	double tmp_1;
              	if (b <= -6.5e+153) {
              		double tmp_2;
              		if (b >= 0.0) {
              			tmp_2 = -c / b;
              		} else {
              			tmp_2 = -(b / a);
              		}
              		tmp_1 = tmp_2;
              	} else if (b >= 0.0) {
              		tmp_1 = 2.0 / ((b * -2.0) / c);
              	} else {
              		tmp_1 = (Math.sqrt(((b * b) - (c * (a * 4.0)))) - b) / (a * 2.0);
              	}
              	return tmp_1;
              }
              
              def code(a, b, c):
              	tmp_1 = 0
              	if b <= -6.5e+153:
              		tmp_2 = 0
              		if b >= 0.0:
              			tmp_2 = -c / b
              		else:
              			tmp_2 = -(b / a)
              		tmp_1 = tmp_2
              	elif b >= 0.0:
              		tmp_1 = 2.0 / ((b * -2.0) / c)
              	else:
              		tmp_1 = (math.sqrt(((b * b) - (c * (a * 4.0)))) - b) / (a * 2.0)
              	return tmp_1
              
              function code(a, b, c)
              	tmp_1 = 0.0
              	if (b <= -6.5e+153)
              		tmp_2 = 0.0
              		if (b >= 0.0)
              			tmp_2 = Float64(Float64(-c) / b);
              		else
              			tmp_2 = Float64(-Float64(b / a));
              		end
              		tmp_1 = tmp_2;
              	elseif (b >= 0.0)
              		tmp_1 = Float64(2.0 / Float64(Float64(b * -2.0) / c));
              	else
              		tmp_1 = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(c * Float64(a * 4.0)))) - b) / Float64(a * 2.0));
              	end
              	return tmp_1
              end
              
              function tmp_4 = code(a, b, c)
              	tmp_2 = 0.0;
              	if (b <= -6.5e+153)
              		tmp_3 = 0.0;
              		if (b >= 0.0)
              			tmp_3 = -c / b;
              		else
              			tmp_3 = -(b / a);
              		end
              		tmp_2 = tmp_3;
              	elseif (b >= 0.0)
              		tmp_2 = 2.0 / ((b * -2.0) / c);
              	else
              		tmp_2 = (sqrt(((b * b) - (c * (a * 4.0)))) - b) / (a * 2.0);
              	end
              	tmp_4 = tmp_2;
              end
              
              code[a_, b_, c_] := If[LessEqual[b, -6.5e+153], If[GreaterEqual[b, 0.0], N[((-c) / b), $MachinePrecision], (-N[(b / a), $MachinePrecision])], If[GreaterEqual[b, 0.0], N[(2.0 / N[(N[(b * -2.0), $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(c * N[(a * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;b \leq -6.5 \cdot 10^{+153}:\\
              \;\;\;\;\begin{array}{l}
              \mathbf{if}\;b \geq 0:\\
              \;\;\;\;\frac{-c}{b}\\
              
              \mathbf{else}:\\
              \;\;\;\;-\frac{b}{a}\\
              
              
              \end{array}\\
              
              \mathbf{elif}\;b \geq 0:\\
              \;\;\;\;\frac{2}{\frac{b \cdot -2}{c}}\\
              
              \mathbf{else}:\\
              \;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if b < -6.49999999999999972e153

                1. Initial program 47.1%

                  \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
                2. Step-by-step derivation
                  1. Simplified47.1%

                    \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\left(-b\right) - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}} \cdot c\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ } \end{array}} \]
                  2. Taylor expanded in b around inf 47.1%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-1 \cdot \frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                  3. Step-by-step derivation
                    1. mul-1-neg47.1%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-\frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                    2. distribute-neg-frac47.1%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                  4. Simplified47.1%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                  5. Taylor expanded in b around -inf 100.0%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \frac{b}{a}\\ \end{array} \]
                  6. Step-by-step derivation
                    1. mul-1-neg100.0%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]
                    2. distribute-frac-neg100.0%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]
                  7. Simplified100.0%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]

                  if -6.49999999999999972e153 < b

                  1. Initial program 77.5%

                    \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
                  2. Step-by-step derivation
                    1. Simplified77.0%

                      \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\left(-b\right) - \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ } \end{array}} \]
                    2. Taylor expanded in b around inf 75.5%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\color{blue}{-2 \cdot \frac{b}{c}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
                    3. Step-by-step derivation
                      1. associate-*r/75.5%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\color{blue}{\frac{-2 \cdot b}{c}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
                      2. *-commutative75.5%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{\color{blue}{b \cdot -2}}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
                    4. Simplified75.5%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\color{blue}{\frac{b \cdot -2}{c}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - c \cdot \left(4 \cdot a\right)}}{2 \cdot a}\\ \end{array} \]
                  3. Recombined 2 regimes into one program.
                  4. Final simplification78.7%

                    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -6.5 \cdot 10^{+153}:\\ \;\;\;\;\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array}\\ \mathbf{elif}\;b \geq 0:\\ \;\;\;\;\frac{2}{\frac{b \cdot -2}{c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(a \cdot 4\right)} - b}{a \cdot 2}\\ \end{array} \]

                  Alternative 5: 67.7% accurate, 19.5× speedup?

                  \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \end{array} \]
                  (FPCore (a b c) :precision binary64 (if (>= b 0.0) (/ (- c) b) (- (/ b a))))
                  double code(double a, double b, double c) {
                  	double tmp;
                  	if (b >= 0.0) {
                  		tmp = -c / b;
                  	} else {
                  		tmp = -(b / a);
                  	}
                  	return tmp;
                  }
                  
                  real(8) function code(a, b, c)
                      real(8), intent (in) :: a
                      real(8), intent (in) :: b
                      real(8), intent (in) :: c
                      real(8) :: tmp
                      if (b >= 0.0d0) then
                          tmp = -c / b
                      else
                          tmp = -(b / a)
                      end if
                      code = tmp
                  end function
                  
                  public static double code(double a, double b, double c) {
                  	double tmp;
                  	if (b >= 0.0) {
                  		tmp = -c / b;
                  	} else {
                  		tmp = -(b / a);
                  	}
                  	return tmp;
                  }
                  
                  def code(a, b, c):
                  	tmp = 0
                  	if b >= 0.0:
                  		tmp = -c / b
                  	else:
                  		tmp = -(b / a)
                  	return tmp
                  
                  function code(a, b, c)
                  	tmp = 0.0
                  	if (b >= 0.0)
                  		tmp = Float64(Float64(-c) / b);
                  	else
                  		tmp = Float64(-Float64(b / a));
                  	end
                  	return tmp
                  end
                  
                  function tmp_2 = code(a, b, c)
                  	tmp = 0.0;
                  	if (b >= 0.0)
                  		tmp = -c / b;
                  	else
                  		tmp = -(b / a);
                  	end
                  	tmp_2 = tmp;
                  end
                  
                  code[a_, b_, c_] := If[GreaterEqual[b, 0.0], N[((-c) / b), $MachinePrecision], (-N[(b / a), $MachinePrecision])]
                  
                  \begin{array}{l}
                  
                  \\
                  \begin{array}{l}
                  \mathbf{if}\;b \geq 0:\\
                  \;\;\;\;\frac{-c}{b}\\
                  
                  \mathbf{else}:\\
                  \;\;\;\;-\frac{b}{a}\\
                  
                  
                  \end{array}
                  \end{array}
                  
                  Derivation
                  1. Initial program 73.5%

                    \[\begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2 \cdot c}{\left(-b\right) - \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}\\ \end{array} \]
                  2. Step-by-step derivation
                    1. Simplified73.5%

                      \[\leadsto \color{blue}{\begin{array}{l} \color{blue}{\mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{2}{\left(-b\right) - \sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)}} \cdot c\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ } \end{array}} \]
                    2. Taylor expanded in b around inf 72.3%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-1 \cdot \frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                    3. Step-by-step derivation
                      1. mul-1-neg72.3%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{-\frac{c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                      2. distribute-neg-frac72.3%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                    4. Simplified72.3%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\color{blue}{\frac{-c}{b}}\\ \mathbf{else}:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{2 \cdot a}\\ \end{array} \]
                    5. Taylor expanded in b around -inf 66.8%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-1 \cdot \frac{b}{a}\\ \end{array} \]
                    6. Step-by-step derivation
                      1. mul-1-neg66.8%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]
                      2. distribute-frac-neg66.8%

                        \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]
                    7. Simplified66.8%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;\frac{-b}{a}\\ \end{array} \]
                    8. Final simplification66.8%

                      \[\leadsto \begin{array}{l} \mathbf{if}\;b \geq 0:\\ \;\;\;\;\frac{-c}{b}\\ \mathbf{else}:\\ \;\;\;\;-\frac{b}{a}\\ \end{array} \]

                    Reproduce

                    ?
                    herbie shell --seed 2023313 
                    (FPCore (a b c)
                      :name "jeff quadratic root 2"
                      :precision binary64
                      (if (>= b 0.0) (/ (* 2.0 c) (- (- b) (sqrt (- (* b b) (* (* 4.0 a) c))))) (/ (+ (- b) (sqrt (- (* b b) (* (* 4.0 a) c)))) (* 2.0 a))))