Numeric.SpecFunctions:invErfc from math-functions-0.1.5.2, A

Percentage Accurate: 95.2% → 99.3%
Time: 6.4s
Alternatives: 8
Speedup: 8.5×

Specification

?
\[\begin{array}{l} \\ x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (+ x (/ y (- (* 1.1283791670955126 (exp z)) (* x y)))))
double code(double x, double y, double z) {
	return x + (y / ((1.1283791670955126 * exp(z)) - (x * y)));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (y / ((1.1283791670955126d0 * exp(z)) - (x * y)))
end function
public static double code(double x, double y, double z) {
	return x + (y / ((1.1283791670955126 * Math.exp(z)) - (x * y)));
}
def code(x, y, z):
	return x + (y / ((1.1283791670955126 * math.exp(z)) - (x * y)))
function code(x, y, z)
	return Float64(x + Float64(y / Float64(Float64(1.1283791670955126 * exp(z)) - Float64(x * y))))
end
function tmp = code(x, y, z)
	tmp = x + (y / ((1.1283791670955126 * exp(z)) - (x * y)));
end
code[x_, y_, z_] := N[(x + N[(y / N[(N[(1.1283791670955126 * N[Exp[z], $MachinePrecision]), $MachinePrecision] - N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 95.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (+ x (/ y (- (* 1.1283791670955126 (exp z)) (* x y)))))
double code(double x, double y, double z) {
	return x + (y / ((1.1283791670955126 * exp(z)) - (x * y)));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (y / ((1.1283791670955126d0 * exp(z)) - (x * y)))
end function
public static double code(double x, double y, double z) {
	return x + (y / ((1.1283791670955126 * Math.exp(z)) - (x * y)));
}
def code(x, y, z):
	return x + (y / ((1.1283791670955126 * math.exp(z)) - (x * y)))
function code(x, y, z)
	return Float64(x + Float64(y / Float64(Float64(1.1283791670955126 * exp(z)) - Float64(x * y))))
end
function tmp = code(x, y, z)
	tmp = x + (y / ((1.1283791670955126 * exp(z)) - (x * y)));
end
code[x_, y_, z_] := N[(x + N[(y / N[(N[(1.1283791670955126 * N[Exp[z], $MachinePrecision]), $MachinePrecision] - N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y}
\end{array}

Alternative 1: 99.3% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;e^{z} \leq 0:\\ \;\;\;\;x + \frac{-1}{x}\\ \mathbf{elif}\;e^{z} \leq 1:\\ \;\;\;\;x + \frac{y}{\left(1.1283791670955126 + z \cdot 1.1283791670955126\right) - x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= (exp z) 0.0)
   (+ x (/ -1.0 x))
   (if (<= (exp z) 1.0)
     (+ x (/ y (- (+ 1.1283791670955126 (* z 1.1283791670955126)) (* x y))))
     x)))
double code(double x, double y, double z) {
	double tmp;
	if (exp(z) <= 0.0) {
		tmp = x + (-1.0 / x);
	} else if (exp(z) <= 1.0) {
		tmp = x + (y / ((1.1283791670955126 + (z * 1.1283791670955126)) - (x * y)));
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (exp(z) <= 0.0d0) then
        tmp = x + ((-1.0d0) / x)
    else if (exp(z) <= 1.0d0) then
        tmp = x + (y / ((1.1283791670955126d0 + (z * 1.1283791670955126d0)) - (x * y)))
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (Math.exp(z) <= 0.0) {
		tmp = x + (-1.0 / x);
	} else if (Math.exp(z) <= 1.0) {
		tmp = x + (y / ((1.1283791670955126 + (z * 1.1283791670955126)) - (x * y)));
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if math.exp(z) <= 0.0:
		tmp = x + (-1.0 / x)
	elif math.exp(z) <= 1.0:
		tmp = x + (y / ((1.1283791670955126 + (z * 1.1283791670955126)) - (x * y)))
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (exp(z) <= 0.0)
		tmp = Float64(x + Float64(-1.0 / x));
	elseif (exp(z) <= 1.0)
		tmp = Float64(x + Float64(y / Float64(Float64(1.1283791670955126 + Float64(z * 1.1283791670955126)) - Float64(x * y))));
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (exp(z) <= 0.0)
		tmp = x + (-1.0 / x);
	elseif (exp(z) <= 1.0)
		tmp = x + (y / ((1.1283791670955126 + (z * 1.1283791670955126)) - (x * y)));
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[N[Exp[z], $MachinePrecision], 0.0], N[(x + N[(-1.0 / x), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[Exp[z], $MachinePrecision], 1.0], N[(x + N[(y / N[(N[(1.1283791670955126 + N[(z * 1.1283791670955126), $MachinePrecision]), $MachinePrecision] - N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;e^{z} \leq 0:\\
\;\;\;\;x + \frac{-1}{x}\\

\mathbf{elif}\;e^{z} \leq 1:\\
\;\;\;\;x + \frac{y}{\left(1.1283791670955126 + z \cdot 1.1283791670955126\right) - x \cdot y}\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (exp.f64 z) < 0.0

    1. Initial program 92.4%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified98.5%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 100.0%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]

    if 0.0 < (exp.f64 z) < 1

    1. Initial program 99.9%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Taylor expanded in z around 0 99.9%

      \[\leadsto x + \frac{y}{\color{blue}{\left(1.1283791670955126 + 1.1283791670955126 \cdot z\right)} - x \cdot y} \]
    3. Step-by-step derivation
      1. *-commutative99.9%

        \[\leadsto x + \frac{y}{\left(1.1283791670955126 + \color{blue}{z \cdot 1.1283791670955126}\right) - x \cdot y} \]
    4. Simplified99.9%

      \[\leadsto x + \frac{y}{\color{blue}{\left(1.1283791670955126 + z \cdot 1.1283791670955126\right)} - x \cdot y} \]

    if 1 < (exp.f64 z)

    1. Initial program 90.9%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified100.0%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 52.8%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]
    4. Taylor expanded in x around inf 100.0%

      \[\leadsto \color{blue}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification100.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;e^{z} \leq 0:\\ \;\;\;\;x + \frac{-1}{x}\\ \mathbf{elif}\;e^{z} \leq 1:\\ \;\;\;\;x + \frac{y}{\left(1.1283791670955126 + z \cdot 1.1283791670955126\right) - x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 2: 98.3% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := x + \frac{y}{e^{z} \cdot 1.1283791670955126 - x \cdot y}\\ \mathbf{if}\;t_0 \leq 5 \cdot 10^{+248}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;x + \frac{-1}{x}\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (let* ((t_0 (+ x (/ y (- (* (exp z) 1.1283791670955126) (* x y))))))
   (if (<= t_0 5e+248) t_0 (+ x (/ -1.0 x)))))
double code(double x, double y, double z) {
	double t_0 = x + (y / ((exp(z) * 1.1283791670955126) - (x * y)));
	double tmp;
	if (t_0 <= 5e+248) {
		tmp = t_0;
	} else {
		tmp = x + (-1.0 / x);
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: t_0
    real(8) :: tmp
    t_0 = x + (y / ((exp(z) * 1.1283791670955126d0) - (x * y)))
    if (t_0 <= 5d+248) then
        tmp = t_0
    else
        tmp = x + ((-1.0d0) / x)
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double t_0 = x + (y / ((Math.exp(z) * 1.1283791670955126) - (x * y)));
	double tmp;
	if (t_0 <= 5e+248) {
		tmp = t_0;
	} else {
		tmp = x + (-1.0 / x);
	}
	return tmp;
}
def code(x, y, z):
	t_0 = x + (y / ((math.exp(z) * 1.1283791670955126) - (x * y)))
	tmp = 0
	if t_0 <= 5e+248:
		tmp = t_0
	else:
		tmp = x + (-1.0 / x)
	return tmp
function code(x, y, z)
	t_0 = Float64(x + Float64(y / Float64(Float64(exp(z) * 1.1283791670955126) - Float64(x * y))))
	tmp = 0.0
	if (t_0 <= 5e+248)
		tmp = t_0;
	else
		tmp = Float64(x + Float64(-1.0 / x));
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	t_0 = x + (y / ((exp(z) * 1.1283791670955126) - (x * y)));
	tmp = 0.0;
	if (t_0 <= 5e+248)
		tmp = t_0;
	else
		tmp = x + (-1.0 / x);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := Block[{t$95$0 = N[(x + N[(y / N[(N[(N[Exp[z], $MachinePrecision] * 1.1283791670955126), $MachinePrecision] - N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, 5e+248], t$95$0, N[(x + N[(-1.0 / x), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := x + \frac{y}{e^{z} \cdot 1.1283791670955126 - x \cdot y}\\
\mathbf{if}\;t_0 \leq 5 \cdot 10^{+248}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;x + \frac{-1}{x}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 x (/.f64 y (-.f64 (*.f64 5641895835477563/5000000000000000 (exp.f64 z)) (*.f64 x y)))) < 4.9999999999999996e248

    1. Initial program 99.1%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]

    if 4.9999999999999996e248 < (+.f64 x (/.f64 y (-.f64 (*.f64 5641895835477563/5000000000000000 (exp.f64 z)) (*.f64 x y))))

    1. Initial program 57.4%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified100.0%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 100.0%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification99.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x + \frac{y}{e^{z} \cdot 1.1283791670955126 - x \cdot y} \leq 5 \cdot 10^{+248}:\\ \;\;\;\;x + \frac{y}{e^{z} \cdot 1.1283791670955126 - x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;x + \frac{-1}{x}\\ \end{array} \]

Alternative 3: 99.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (- x (/ -1.0 (- (* (exp z) (/ 1.1283791670955126 y)) x))))
double code(double x, double y, double z) {
	return x - (-1.0 / ((exp(z) * (1.1283791670955126 / y)) - x));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x - ((-1.0d0) / ((exp(z) * (1.1283791670955126d0 / y)) - x))
end function
public static double code(double x, double y, double z) {
	return x - (-1.0 / ((Math.exp(z) * (1.1283791670955126 / y)) - x));
}
def code(x, y, z):
	return x - (-1.0 / ((math.exp(z) * (1.1283791670955126 / y)) - x))
function code(x, y, z)
	return Float64(x - Float64(-1.0 / Float64(Float64(exp(z) * Float64(1.1283791670955126 / y)) - x)))
end
function tmp = code(x, y, z)
	tmp = x - (-1.0 / ((exp(z) * (1.1283791670955126 / y)) - x));
end
code[x_, y_, z_] := N[(x - N[(-1.0 / N[(N[(N[Exp[z], $MachinePrecision] * N[(1.1283791670955126 / y), $MachinePrecision]), $MachinePrecision] - x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}
\end{array}
Derivation
  1. Initial program 95.7%

    \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
  2. Simplified99.5%

    \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
  3. Final simplification99.5%

    \[\leadsto x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x} \]

Alternative 4: 74.1% accurate, 8.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z \leq -3.3 \cdot 10^{-26}:\\ \;\;\;\;x\\ \mathbf{elif}\;z \leq -7.5 \cdot 10^{-123} \lor \neg \left(z \leq -9.8 \cdot 10^{-191}\right) \land z \leq 2.2 \cdot 10^{-19}:\\ \;\;\;\;x - y \cdot -0.8862269254527579\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= z -3.3e-26)
   x
   (if (or (<= z -7.5e-123) (and (not (<= z -9.8e-191)) (<= z 2.2e-19)))
     (- x (* y -0.8862269254527579))
     x)))
double code(double x, double y, double z) {
	double tmp;
	if (z <= -3.3e-26) {
		tmp = x;
	} else if ((z <= -7.5e-123) || (!(z <= -9.8e-191) && (z <= 2.2e-19))) {
		tmp = x - (y * -0.8862269254527579);
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (z <= (-3.3d-26)) then
        tmp = x
    else if ((z <= (-7.5d-123)) .or. (.not. (z <= (-9.8d-191))) .and. (z <= 2.2d-19)) then
        tmp = x - (y * (-0.8862269254527579d0))
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (z <= -3.3e-26) {
		tmp = x;
	} else if ((z <= -7.5e-123) || (!(z <= -9.8e-191) && (z <= 2.2e-19))) {
		tmp = x - (y * -0.8862269254527579);
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if z <= -3.3e-26:
		tmp = x
	elif (z <= -7.5e-123) or (not (z <= -9.8e-191) and (z <= 2.2e-19)):
		tmp = x - (y * -0.8862269254527579)
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (z <= -3.3e-26)
		tmp = x;
	elseif ((z <= -7.5e-123) || (!(z <= -9.8e-191) && (z <= 2.2e-19)))
		tmp = Float64(x - Float64(y * -0.8862269254527579));
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z <= -3.3e-26)
		tmp = x;
	elseif ((z <= -7.5e-123) || (~((z <= -9.8e-191)) && (z <= 2.2e-19)))
		tmp = x - (y * -0.8862269254527579);
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[z, -3.3e-26], x, If[Or[LessEqual[z, -7.5e-123], And[N[Not[LessEqual[z, -9.8e-191]], $MachinePrecision], LessEqual[z, 2.2e-19]]], N[(x - N[(y * -0.8862269254527579), $MachinePrecision]), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z \leq -3.3 \cdot 10^{-26}:\\
\;\;\;\;x\\

\mathbf{elif}\;z \leq -7.5 \cdot 10^{-123} \lor \neg \left(z \leq -9.8 \cdot 10^{-191}\right) \land z \leq 2.2 \cdot 10^{-19}:\\
\;\;\;\;x - y \cdot -0.8862269254527579\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if z < -3.2999999999999998e-26 or -7.50000000000000011e-123 < z < -9.7999999999999999e-191 or 2.1999999999999998e-19 < z

    1. Initial program 92.8%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified99.3%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 75.6%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]
    4. Taylor expanded in x around inf 78.6%

      \[\leadsto \color{blue}{x} \]

    if -3.2999999999999998e-26 < z < -7.50000000000000011e-123 or -9.7999999999999999e-191 < z < 2.1999999999999998e-19

    1. Initial program 99.9%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified99.9%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in z around 0 99.7%

      \[\leadsto x - \color{blue}{\frac{-1}{1.1283791670955126 \cdot \frac{1}{y} - x}} \]
    4. Taylor expanded in y around 0 82.1%

      \[\leadsto x - \color{blue}{-0.8862269254527579 \cdot y} \]
    5. Step-by-step derivation
      1. *-commutative82.1%

        \[\leadsto x - \color{blue}{y \cdot -0.8862269254527579} \]
    6. Simplified82.1%

      \[\leadsto x - \color{blue}{y \cdot -0.8862269254527579} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification80.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -3.3 \cdot 10^{-26}:\\ \;\;\;\;x\\ \mathbf{elif}\;z \leq -7.5 \cdot 10^{-123} \lor \neg \left(z \leq -9.8 \cdot 10^{-191}\right) \land z \leq 2.2 \cdot 10^{-19}:\\ \;\;\;\;x - y \cdot -0.8862269254527579\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 5: 86.4% accurate, 8.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z \leq -1.12 \cdot 10^{-26}:\\ \;\;\;\;x + \frac{-1}{x}\\ \mathbf{elif}\;z \leq -3.2 \cdot 10^{-123} \lor \neg \left(z \leq -1.8 \cdot 10^{-190}\right) \land z \leq 2.05 \cdot 10^{-19}:\\ \;\;\;\;x - y \cdot -0.8862269254527579\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= z -1.12e-26)
   (+ x (/ -1.0 x))
   (if (or (<= z -3.2e-123) (and (not (<= z -1.8e-190)) (<= z 2.05e-19)))
     (- x (* y -0.8862269254527579))
     x)))
double code(double x, double y, double z) {
	double tmp;
	if (z <= -1.12e-26) {
		tmp = x + (-1.0 / x);
	} else if ((z <= -3.2e-123) || (!(z <= -1.8e-190) && (z <= 2.05e-19))) {
		tmp = x - (y * -0.8862269254527579);
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (z <= (-1.12d-26)) then
        tmp = x + ((-1.0d0) / x)
    else if ((z <= (-3.2d-123)) .or. (.not. (z <= (-1.8d-190))) .and. (z <= 2.05d-19)) then
        tmp = x - (y * (-0.8862269254527579d0))
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (z <= -1.12e-26) {
		tmp = x + (-1.0 / x);
	} else if ((z <= -3.2e-123) || (!(z <= -1.8e-190) && (z <= 2.05e-19))) {
		tmp = x - (y * -0.8862269254527579);
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if z <= -1.12e-26:
		tmp = x + (-1.0 / x)
	elif (z <= -3.2e-123) or (not (z <= -1.8e-190) and (z <= 2.05e-19)):
		tmp = x - (y * -0.8862269254527579)
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (z <= -1.12e-26)
		tmp = Float64(x + Float64(-1.0 / x));
	elseif ((z <= -3.2e-123) || (!(z <= -1.8e-190) && (z <= 2.05e-19)))
		tmp = Float64(x - Float64(y * -0.8862269254527579));
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z <= -1.12e-26)
		tmp = x + (-1.0 / x);
	elseif ((z <= -3.2e-123) || (~((z <= -1.8e-190)) && (z <= 2.05e-19)))
		tmp = x - (y * -0.8862269254527579);
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[z, -1.12e-26], N[(x + N[(-1.0 / x), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[z, -3.2e-123], And[N[Not[LessEqual[z, -1.8e-190]], $MachinePrecision], LessEqual[z, 2.05e-19]]], N[(x - N[(y * -0.8862269254527579), $MachinePrecision]), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z \leq -1.12 \cdot 10^{-26}:\\
\;\;\;\;x + \frac{-1}{x}\\

\mathbf{elif}\;z \leq -3.2 \cdot 10^{-123} \lor \neg \left(z \leq -1.8 \cdot 10^{-190}\right) \land z \leq 2.05 \cdot 10^{-19}:\\
\;\;\;\;x - y \cdot -0.8862269254527579\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if z < -1.12e-26

    1. Initial program 93.0%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified98.6%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 97.3%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]

    if -1.12e-26 < z < -3.19999999999999979e-123 or -1.80000000000000003e-190 < z < 2.04999999999999993e-19

    1. Initial program 99.9%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified99.9%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in z around 0 99.7%

      \[\leadsto x - \color{blue}{\frac{-1}{1.1283791670955126 \cdot \frac{1}{y} - x}} \]
    4. Taylor expanded in y around 0 82.1%

      \[\leadsto x - \color{blue}{-0.8862269254527579 \cdot y} \]
    5. Step-by-step derivation
      1. *-commutative82.1%

        \[\leadsto x - \color{blue}{y \cdot -0.8862269254527579} \]
    6. Simplified82.1%

      \[\leadsto x - \color{blue}{y \cdot -0.8862269254527579} \]

    if -3.19999999999999979e-123 < z < -1.80000000000000003e-190 or 2.04999999999999993e-19 < z

    1. Initial program 92.5%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified100.0%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 56.2%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]
    4. Taylor expanded in x around inf 97.6%

      \[\leadsto \color{blue}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification91.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -1.12 \cdot 10^{-26}:\\ \;\;\;\;x + \frac{-1}{x}\\ \mathbf{elif}\;z \leq -3.2 \cdot 10^{-123} \lor \neg \left(z \leq -1.8 \cdot 10^{-190}\right) \land z \leq 2.05 \cdot 10^{-19}:\\ \;\;\;\;x - y \cdot -0.8862269254527579\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 6: 99.2% accurate, 8.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z \leq -200:\\ \;\;\;\;x + \frac{-1}{x}\\ \mathbf{elif}\;z \leq 2.2 \cdot 10^{-19}:\\ \;\;\;\;x + \frac{y}{1.1283791670955126 - x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= z -200.0)
   (+ x (/ -1.0 x))
   (if (<= z 2.2e-19) (+ x (/ y (- 1.1283791670955126 (* x y)))) x)))
double code(double x, double y, double z) {
	double tmp;
	if (z <= -200.0) {
		tmp = x + (-1.0 / x);
	} else if (z <= 2.2e-19) {
		tmp = x + (y / (1.1283791670955126 - (x * y)));
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (z <= (-200.0d0)) then
        tmp = x + ((-1.0d0) / x)
    else if (z <= 2.2d-19) then
        tmp = x + (y / (1.1283791670955126d0 - (x * y)))
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (z <= -200.0) {
		tmp = x + (-1.0 / x);
	} else if (z <= 2.2e-19) {
		tmp = x + (y / (1.1283791670955126 - (x * y)));
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if z <= -200.0:
		tmp = x + (-1.0 / x)
	elif z <= 2.2e-19:
		tmp = x + (y / (1.1283791670955126 - (x * y)))
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (z <= -200.0)
		tmp = Float64(x + Float64(-1.0 / x));
	elseif (z <= 2.2e-19)
		tmp = Float64(x + Float64(y / Float64(1.1283791670955126 - Float64(x * y))));
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z <= -200.0)
		tmp = x + (-1.0 / x);
	elseif (z <= 2.2e-19)
		tmp = x + (y / (1.1283791670955126 - (x * y)));
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[z, -200.0], N[(x + N[(-1.0 / x), $MachinePrecision]), $MachinePrecision], If[LessEqual[z, 2.2e-19], N[(x + N[(y / N[(1.1283791670955126 - N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z \leq -200:\\
\;\;\;\;x + \frac{-1}{x}\\

\mathbf{elif}\;z \leq 2.2 \cdot 10^{-19}:\\
\;\;\;\;x + \frac{y}{1.1283791670955126 - x \cdot y}\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if z < -200

    1. Initial program 92.4%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified98.5%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 100.0%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]

    if -200 < z < 2.1999999999999998e-19

    1. Initial program 99.9%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Taylor expanded in z around 0 99.9%

      \[\leadsto x + \color{blue}{\frac{y}{1.1283791670955126 - x \cdot y}} \]
    3. Step-by-step derivation
      1. *-commutative99.9%

        \[\leadsto x + \frac{y}{1.1283791670955126 - \color{blue}{y \cdot x}} \]
    4. Simplified99.9%

      \[\leadsto x + \color{blue}{\frac{y}{1.1283791670955126 - y \cdot x}} \]

    if 2.1999999999999998e-19 < z

    1. Initial program 91.0%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified100.0%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 53.5%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]
    4. Taylor expanded in x around inf 100.0%

      \[\leadsto \color{blue}{x} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification99.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -200:\\ \;\;\;\;x + \frac{-1}{x}\\ \mathbf{elif}\;z \leq 2.2 \cdot 10^{-19}:\\ \;\;\;\;x + \frac{y}{1.1283791670955126 - x \cdot y}\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 7: 70.0% accurate, 9.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -2.2 \cdot 10^{-101}:\\ \;\;\;\;x\\ \mathbf{elif}\;x \leq -3.1 \cdot 10^{-144} \lor \neg \left(x \leq -1.1 \cdot 10^{-199}\right) \land x \leq 2 \cdot 10^{-254}:\\ \;\;\;\;y \cdot 0.8862269254527579\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (<= x -2.2e-101)
   x
   (if (or (<= x -3.1e-144) (and (not (<= x -1.1e-199)) (<= x 2e-254)))
     (* y 0.8862269254527579)
     x)))
double code(double x, double y, double z) {
	double tmp;
	if (x <= -2.2e-101) {
		tmp = x;
	} else if ((x <= -3.1e-144) || (!(x <= -1.1e-199) && (x <= 2e-254))) {
		tmp = y * 0.8862269254527579;
	} else {
		tmp = x;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (x <= (-2.2d-101)) then
        tmp = x
    else if ((x <= (-3.1d-144)) .or. (.not. (x <= (-1.1d-199))) .and. (x <= 2d-254)) then
        tmp = y * 0.8862269254527579d0
    else
        tmp = x
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (x <= -2.2e-101) {
		tmp = x;
	} else if ((x <= -3.1e-144) || (!(x <= -1.1e-199) && (x <= 2e-254))) {
		tmp = y * 0.8862269254527579;
	} else {
		tmp = x;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if x <= -2.2e-101:
		tmp = x
	elif (x <= -3.1e-144) or (not (x <= -1.1e-199) and (x <= 2e-254)):
		tmp = y * 0.8862269254527579
	else:
		tmp = x
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (x <= -2.2e-101)
		tmp = x;
	elseif ((x <= -3.1e-144) || (!(x <= -1.1e-199) && (x <= 2e-254)))
		tmp = Float64(y * 0.8862269254527579);
	else
		tmp = x;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (x <= -2.2e-101)
		tmp = x;
	elseif ((x <= -3.1e-144) || (~((x <= -1.1e-199)) && (x <= 2e-254)))
		tmp = y * 0.8862269254527579;
	else
		tmp = x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[LessEqual[x, -2.2e-101], x, If[Or[LessEqual[x, -3.1e-144], And[N[Not[LessEqual[x, -1.1e-199]], $MachinePrecision], LessEqual[x, 2e-254]]], N[(y * 0.8862269254527579), $MachinePrecision], x]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -2.2 \cdot 10^{-101}:\\
\;\;\;\;x\\

\mathbf{elif}\;x \leq -3.1 \cdot 10^{-144} \lor \neg \left(x \leq -1.1 \cdot 10^{-199}\right) \land x \leq 2 \cdot 10^{-254}:\\
\;\;\;\;y \cdot 0.8862269254527579\\

\mathbf{else}:\\
\;\;\;\;x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -2.1999999999999999e-101 or -3.1000000000000001e-144 < x < -1.0999999999999999e-199 or 1.9999999999999998e-254 < x

    1. Initial program 95.6%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified99.5%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in y around inf 74.6%

      \[\leadsto x - \color{blue}{\frac{1}{x}} \]
    4. Taylor expanded in x around inf 82.0%

      \[\leadsto \color{blue}{x} \]

    if -2.1999999999999999e-101 < x < -3.1000000000000001e-144 or -1.0999999999999999e-199 < x < 1.9999999999999998e-254

    1. Initial program 95.8%

      \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
    2. Simplified99.7%

      \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
    3. Taylor expanded in z around 0 74.3%

      \[\leadsto x - \color{blue}{\frac{-1}{1.1283791670955126 \cdot \frac{1}{y} - x}} \]
    4. Taylor expanded in y around 0 64.6%

      \[\leadsto x - \color{blue}{-0.8862269254527579 \cdot y} \]
    5. Step-by-step derivation
      1. *-commutative64.6%

        \[\leadsto x - \color{blue}{y \cdot -0.8862269254527579} \]
    6. Simplified64.6%

      \[\leadsto x - \color{blue}{y \cdot -0.8862269254527579} \]
    7. Taylor expanded in x around 0 57.2%

      \[\leadsto \color{blue}{0.8862269254527579 \cdot y} \]
    8. Step-by-step derivation
      1. *-commutative57.2%

        \[\leadsto \color{blue}{y \cdot 0.8862269254527579} \]
    9. Simplified57.2%

      \[\leadsto \color{blue}{y \cdot 0.8862269254527579} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification77.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -2.2 \cdot 10^{-101}:\\ \;\;\;\;x\\ \mathbf{elif}\;x \leq -3.1 \cdot 10^{-144} \lor \neg \left(x \leq -1.1 \cdot 10^{-199}\right) \land x \leq 2 \cdot 10^{-254}:\\ \;\;\;\;y \cdot 0.8862269254527579\\ \mathbf{else}:\\ \;\;\;\;x\\ \end{array} \]

Alternative 8: 69.1% accurate, 111.0× speedup?

\[\begin{array}{l} \\ x \end{array} \]
(FPCore (x y z) :precision binary64 x)
double code(double x, double y, double z) {
	return x;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x
end function
public static double code(double x, double y, double z) {
	return x;
}
def code(x, y, z):
	return x
function code(x, y, z)
	return x
end
function tmp = code(x, y, z)
	tmp = x;
end
code[x_, y_, z_] := x
\begin{array}{l}

\\
x
\end{array}
Derivation
  1. Initial program 95.7%

    \[x + \frac{y}{1.1283791670955126 \cdot e^{z} - x \cdot y} \]
  2. Simplified99.5%

    \[\leadsto \color{blue}{x - \frac{-1}{e^{z} \cdot \frac{1.1283791670955126}{y} - x}} \]
  3. Taylor expanded in y around inf 65.1%

    \[\leadsto x - \color{blue}{\frac{1}{x}} \]
  4. Taylor expanded in x around inf 70.1%

    \[\leadsto \color{blue}{x} \]
  5. Final simplification70.1%

    \[\leadsto x \]

Developer target: 99.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x + \frac{1}{\frac{1.1283791670955126}{y} \cdot e^{z} - x} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (+ x (/ 1.0 (- (* (/ 1.1283791670955126 y) (exp z)) x))))
double code(double x, double y, double z) {
	return x + (1.0 / (((1.1283791670955126 / y) * exp(z)) - x));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = x + (1.0d0 / (((1.1283791670955126d0 / y) * exp(z)) - x))
end function
public static double code(double x, double y, double z) {
	return x + (1.0 / (((1.1283791670955126 / y) * Math.exp(z)) - x));
}
def code(x, y, z):
	return x + (1.0 / (((1.1283791670955126 / y) * math.exp(z)) - x))
function code(x, y, z)
	return Float64(x + Float64(1.0 / Float64(Float64(Float64(1.1283791670955126 / y) * exp(z)) - x)))
end
function tmp = code(x, y, z)
	tmp = x + (1.0 / (((1.1283791670955126 / y) * exp(z)) - x));
end
code[x_, y_, z_] := N[(x + N[(1.0 / N[(N[(N[(1.1283791670955126 / y), $MachinePrecision] * N[Exp[z], $MachinePrecision]), $MachinePrecision] - x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x + \frac{1}{\frac{1.1283791670955126}{y} \cdot e^{z} - x}
\end{array}

Reproduce

?
herbie shell --seed 2023311 
(FPCore (x y z)
  :name "Numeric.SpecFunctions:invErfc from math-functions-0.1.5.2, A"
  :precision binary64

  :herbie-target
  (+ x (/ 1.0 (- (* (/ 1.1283791670955126 y) (exp z)) x)))

  (+ x (/ y (- (* 1.1283791670955126 (exp z)) (* x y)))))