Falkner and Boettcher, Appendix A

Percentage Accurate: 90.5% → 97.0%
Time: 11.1s
Alternatives: 12
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 12 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 90.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Alternative 1: 97.0% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq 5.4 \cdot 10^{-36}:\\ \;\;\;\;\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m 5.4e-36)
   (* (/ (pow k m) (fma k (+ k 10.0) 1.0)) a)
   (/ a (pow k (- m)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= 5.4e-36) {
		tmp = (pow(k, m) / fma(k, (k + 10.0), 1.0)) * a;
	} else {
		tmp = a / pow(k, -m);
	}
	return tmp;
}
function code(a, k, m)
	tmp = 0.0
	if (m <= 5.4e-36)
		tmp = Float64(Float64((k ^ m) / fma(k, Float64(k + 10.0), 1.0)) * a);
	else
		tmp = Float64(a / (k ^ Float64(-m)));
	end
	return tmp
end
code[a_, k_, m_] := If[LessEqual[m, 5.4e-36], N[(N[(N[Power[k, m], $MachinePrecision] / N[(k * N[(k + 10.0), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision] * a), $MachinePrecision], N[(a / N[Power[k, (-m)], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq 5.4 \cdot 10^{-36}:\\
\;\;\;\;\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < 5.40000000000000015e-36

    1. Initial program 97.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/97.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative97.5%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+97.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative97.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out97.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def97.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative97.5%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified97.5%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]

    if 5.40000000000000015e-36 < m

    1. Initial program 80.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*80.7%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+80.7%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. distribute-rgt-out80.7%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot \left(10 + k\right)}}{{k}^{m}}} \]
    3. Simplified80.7%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + k \cdot \left(10 + k\right)}{{k}^{m}}}} \]
    4. Taylor expanded in k around 0 100.0%

      \[\leadsto \frac{a}{\color{blue}{\frac{1}{{k}^{m}}}} \]
    5. Step-by-step derivation
      1. pow-neg100.0%

        \[\leadsto \frac{a}{\color{blue}{{k}^{\left(-m\right)}}} \]
      2. neg-mul-1100.0%

        \[\leadsto \frac{a}{{k}^{\color{blue}{\left(-1 \cdot m\right)}}} \]
      3. pow-unpow100.0%

        \[\leadsto \frac{a}{\color{blue}{{\left({k}^{-1}\right)}^{m}}} \]
    6. Applied egg-rr100.0%

      \[\leadsto \frac{a}{\color{blue}{{\left({k}^{-1}\right)}^{m}}} \]
    7. Step-by-step derivation
      1. unpow-1100.0%

        \[\leadsto \frac{a}{{\color{blue}{\left(\frac{1}{k}\right)}}^{m}} \]
    8. Simplified100.0%

      \[\leadsto \frac{a}{\color{blue}{{\left(\frac{1}{k}\right)}^{m}}} \]
    9. Step-by-step derivation
      1. expm1-log1p-u74.9%

        \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{a}{{\left(\frac{1}{k}\right)}^{m}}\right)\right)} \]
      2. expm1-udef72.8%

        \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{a}{{\left(\frac{1}{k}\right)}^{m}}\right)} - 1} \]
      3. inv-pow72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{\color{blue}{\left({k}^{-1}\right)}}^{m}}\right)} - 1 \]
      4. metadata-eval72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{\left({k}^{\color{blue}{\left(-1\right)}}\right)}^{m}}\right)} - 1 \]
      5. pow-pow72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{\color{blue}{{k}^{\left(\left(-1\right) \cdot m\right)}}}\right)} - 1 \]
      6. metadata-eval72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{k}^{\left(\color{blue}{-1} \cdot m\right)}}\right)} - 1 \]
    10. Applied egg-rr72.8%

      \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{a}{{k}^{\left(-1 \cdot m\right)}}\right)} - 1} \]
    11. Step-by-step derivation
      1. expm1-def74.9%

        \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{a}{{k}^{\left(-1 \cdot m\right)}}\right)\right)} \]
      2. expm1-log1p100.0%

        \[\leadsto \color{blue}{\frac{a}{{k}^{\left(-1 \cdot m\right)}}} \]
      3. mul-1-neg100.0%

        \[\leadsto \frac{a}{{k}^{\color{blue}{\left(-m\right)}}} \]
    12. Simplified100.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{\left(-m\right)}}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq 5.4 \cdot 10^{-36}:\\ \;\;\;\;\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \end{array} \]

Alternative 2: 97.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq 5.4 \cdot 10^{-36}:\\ \;\;\;\;\frac{a}{\frac{1 + k \cdot \left(k + 10\right)}{{k}^{m}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m 5.4e-36)
   (/ a (/ (+ 1.0 (* k (+ k 10.0))) (pow k m)))
   (/ a (pow k (- m)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= 5.4e-36) {
		tmp = a / ((1.0 + (k * (k + 10.0))) / pow(k, m));
	} else {
		tmp = a / pow(k, -m);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= 5.4d-36) then
        tmp = a / ((1.0d0 + (k * (k + 10.0d0))) / (k ** m))
    else
        tmp = a / (k ** -m)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= 5.4e-36) {
		tmp = a / ((1.0 + (k * (k + 10.0))) / Math.pow(k, m));
	} else {
		tmp = a / Math.pow(k, -m);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= 5.4e-36:
		tmp = a / ((1.0 + (k * (k + 10.0))) / math.pow(k, m))
	else:
		tmp = a / math.pow(k, -m)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= 5.4e-36)
		tmp = Float64(a / Float64(Float64(1.0 + Float64(k * Float64(k + 10.0))) / (k ^ m)));
	else
		tmp = Float64(a / (k ^ Float64(-m)));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= 5.4e-36)
		tmp = a / ((1.0 + (k * (k + 10.0))) / (k ^ m));
	else
		tmp = a / (k ^ -m);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, 5.4e-36], N[(a / N[(N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[Power[k, m], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a / N[Power[k, (-m)], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq 5.4 \cdot 10^{-36}:\\
\;\;\;\;\frac{a}{\frac{1 + k \cdot \left(k + 10\right)}{{k}^{m}}}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < 5.40000000000000015e-36

    1. Initial program 97.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*97.5%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+97.5%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. distribute-rgt-out97.5%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot \left(10 + k\right)}}{{k}^{m}}} \]
    3. Simplified97.5%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + k \cdot \left(10 + k\right)}{{k}^{m}}}} \]

    if 5.40000000000000015e-36 < m

    1. Initial program 80.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*80.7%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+80.7%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. distribute-rgt-out80.7%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot \left(10 + k\right)}}{{k}^{m}}} \]
    3. Simplified80.7%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + k \cdot \left(10 + k\right)}{{k}^{m}}}} \]
    4. Taylor expanded in k around 0 100.0%

      \[\leadsto \frac{a}{\color{blue}{\frac{1}{{k}^{m}}}} \]
    5. Step-by-step derivation
      1. pow-neg100.0%

        \[\leadsto \frac{a}{\color{blue}{{k}^{\left(-m\right)}}} \]
      2. neg-mul-1100.0%

        \[\leadsto \frac{a}{{k}^{\color{blue}{\left(-1 \cdot m\right)}}} \]
      3. pow-unpow100.0%

        \[\leadsto \frac{a}{\color{blue}{{\left({k}^{-1}\right)}^{m}}} \]
    6. Applied egg-rr100.0%

      \[\leadsto \frac{a}{\color{blue}{{\left({k}^{-1}\right)}^{m}}} \]
    7. Step-by-step derivation
      1. unpow-1100.0%

        \[\leadsto \frac{a}{{\color{blue}{\left(\frac{1}{k}\right)}}^{m}} \]
    8. Simplified100.0%

      \[\leadsto \frac{a}{\color{blue}{{\left(\frac{1}{k}\right)}^{m}}} \]
    9. Step-by-step derivation
      1. expm1-log1p-u74.9%

        \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{a}{{\left(\frac{1}{k}\right)}^{m}}\right)\right)} \]
      2. expm1-udef72.8%

        \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{a}{{\left(\frac{1}{k}\right)}^{m}}\right)} - 1} \]
      3. inv-pow72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{\color{blue}{\left({k}^{-1}\right)}}^{m}}\right)} - 1 \]
      4. metadata-eval72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{\left({k}^{\color{blue}{\left(-1\right)}}\right)}^{m}}\right)} - 1 \]
      5. pow-pow72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{\color{blue}{{k}^{\left(\left(-1\right) \cdot m\right)}}}\right)} - 1 \]
      6. metadata-eval72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{k}^{\left(\color{blue}{-1} \cdot m\right)}}\right)} - 1 \]
    10. Applied egg-rr72.8%

      \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{a}{{k}^{\left(-1 \cdot m\right)}}\right)} - 1} \]
    11. Step-by-step derivation
      1. expm1-def74.9%

        \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{a}{{k}^{\left(-1 \cdot m\right)}}\right)\right)} \]
      2. expm1-log1p100.0%

        \[\leadsto \color{blue}{\frac{a}{{k}^{\left(-1 \cdot m\right)}}} \]
      3. mul-1-neg100.0%

        \[\leadsto \frac{a}{{k}^{\color{blue}{\left(-m\right)}}} \]
    12. Simplified100.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{\left(-m\right)}}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq 5.4 \cdot 10^{-36}:\\ \;\;\;\;\frac{a}{\frac{1 + k \cdot \left(k + 10\right)}{{k}^{m}}}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \end{array} \]

Alternative 3: 96.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -1.45 \cdot 10^{-5}:\\ \;\;\;\;{k}^{m} \cdot a\\ \mathbf{elif}\;m \leq 5.4 \cdot 10^{-36}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -1.45e-5)
   (* (pow k m) a)
   (if (<= m 5.4e-36)
     (* a (/ 1.0 (+ 1.0 (* k (+ k 10.0)))))
     (/ a (pow k (- m))))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -1.45e-5) {
		tmp = pow(k, m) * a;
	} else if (m <= 5.4e-36) {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	} else {
		tmp = a / pow(k, -m);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-1.45d-5)) then
        tmp = (k ** m) * a
    else if (m <= 5.4d-36) then
        tmp = a * (1.0d0 / (1.0d0 + (k * (k + 10.0d0))))
    else
        tmp = a / (k ** -m)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -1.45e-5) {
		tmp = Math.pow(k, m) * a;
	} else if (m <= 5.4e-36) {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	} else {
		tmp = a / Math.pow(k, -m);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -1.45e-5:
		tmp = math.pow(k, m) * a
	elif m <= 5.4e-36:
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))))
	else:
		tmp = a / math.pow(k, -m)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -1.45e-5)
		tmp = Float64((k ^ m) * a);
	elseif (m <= 5.4e-36)
		tmp = Float64(a * Float64(1.0 / Float64(1.0 + Float64(k * Float64(k + 10.0)))));
	else
		tmp = Float64(a / (k ^ Float64(-m)));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -1.45e-5)
		tmp = (k ^ m) * a;
	elseif (m <= 5.4e-36)
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	else
		tmp = a / (k ^ -m);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -1.45e-5], N[(N[Power[k, m], $MachinePrecision] * a), $MachinePrecision], If[LessEqual[m, 5.4e-36], N[(a * N[(1.0 / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a / N[Power[k, (-m)], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -1.45 \cdot 10^{-5}:\\
\;\;\;\;{k}^{m} \cdot a\\

\mathbf{elif}\;m \leq 5.4 \cdot 10^{-36}:\\
\;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -1.45e-5

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in k around 0 100.0%

      \[\leadsto \color{blue}{{k}^{m}} \cdot a \]

    if -1.45e-5 < m < 5.40000000000000015e-36

    1. Initial program 94.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative94.6%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative94.6%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified94.6%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 94.1%

      \[\leadsto \color{blue}{\frac{1}{1 + k \cdot \left(10 + k\right)}} \cdot a \]

    if 5.40000000000000015e-36 < m

    1. Initial program 80.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*80.7%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+80.7%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. distribute-rgt-out80.7%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot \left(10 + k\right)}}{{k}^{m}}} \]
    3. Simplified80.7%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + k \cdot \left(10 + k\right)}{{k}^{m}}}} \]
    4. Taylor expanded in k around 0 100.0%

      \[\leadsto \frac{a}{\color{blue}{\frac{1}{{k}^{m}}}} \]
    5. Step-by-step derivation
      1. pow-neg100.0%

        \[\leadsto \frac{a}{\color{blue}{{k}^{\left(-m\right)}}} \]
      2. neg-mul-1100.0%

        \[\leadsto \frac{a}{{k}^{\color{blue}{\left(-1 \cdot m\right)}}} \]
      3. pow-unpow100.0%

        \[\leadsto \frac{a}{\color{blue}{{\left({k}^{-1}\right)}^{m}}} \]
    6. Applied egg-rr100.0%

      \[\leadsto \frac{a}{\color{blue}{{\left({k}^{-1}\right)}^{m}}} \]
    7. Step-by-step derivation
      1. unpow-1100.0%

        \[\leadsto \frac{a}{{\color{blue}{\left(\frac{1}{k}\right)}}^{m}} \]
    8. Simplified100.0%

      \[\leadsto \frac{a}{\color{blue}{{\left(\frac{1}{k}\right)}^{m}}} \]
    9. Step-by-step derivation
      1. expm1-log1p-u74.9%

        \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{a}{{\left(\frac{1}{k}\right)}^{m}}\right)\right)} \]
      2. expm1-udef72.8%

        \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{a}{{\left(\frac{1}{k}\right)}^{m}}\right)} - 1} \]
      3. inv-pow72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{\color{blue}{\left({k}^{-1}\right)}}^{m}}\right)} - 1 \]
      4. metadata-eval72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{\left({k}^{\color{blue}{\left(-1\right)}}\right)}^{m}}\right)} - 1 \]
      5. pow-pow72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{\color{blue}{{k}^{\left(\left(-1\right) \cdot m\right)}}}\right)} - 1 \]
      6. metadata-eval72.8%

        \[\leadsto e^{\mathsf{log1p}\left(\frac{a}{{k}^{\left(\color{blue}{-1} \cdot m\right)}}\right)} - 1 \]
    10. Applied egg-rr72.8%

      \[\leadsto \color{blue}{e^{\mathsf{log1p}\left(\frac{a}{{k}^{\left(-1 \cdot m\right)}}\right)} - 1} \]
    11. Step-by-step derivation
      1. expm1-def74.9%

        \[\leadsto \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\frac{a}{{k}^{\left(-1 \cdot m\right)}}\right)\right)} \]
      2. expm1-log1p100.0%

        \[\leadsto \color{blue}{\frac{a}{{k}^{\left(-1 \cdot m\right)}}} \]
      3. mul-1-neg100.0%

        \[\leadsto \frac{a}{{k}^{\color{blue}{\left(-m\right)}}} \]
    12. Simplified100.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{\left(-m\right)}}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification98.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -1.45 \cdot 10^{-5}:\\ \;\;\;\;{k}^{m} \cdot a\\ \mathbf{elif}\;m \leq 5.4 \cdot 10^{-36}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \end{array} \]

Alternative 4: 96.7% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -4.4 \cdot 10^{-10} \lor \neg \left(m \leq 5.4 \cdot 10^{-36}\right):\\ \;\;\;\;{k}^{m} \cdot a\\ \mathbf{else}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= m -4.4e-10) (not (<= m 5.4e-36)))
   (* (pow k m) a)
   (* a (/ 1.0 (+ 1.0 (* k (+ k 10.0)))))))
double code(double a, double k, double m) {
	double tmp;
	if ((m <= -4.4e-10) || !(m <= 5.4e-36)) {
		tmp = pow(k, m) * a;
	} else {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((m <= (-4.4d-10)) .or. (.not. (m <= 5.4d-36))) then
        tmp = (k ** m) * a
    else
        tmp = a * (1.0d0 / (1.0d0 + (k * (k + 10.0d0))))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((m <= -4.4e-10) || !(m <= 5.4e-36)) {
		tmp = Math.pow(k, m) * a;
	} else {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (m <= -4.4e-10) or not (m <= 5.4e-36):
		tmp = math.pow(k, m) * a
	else:
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((m <= -4.4e-10) || !(m <= 5.4e-36))
		tmp = Float64((k ^ m) * a);
	else
		tmp = Float64(a * Float64(1.0 / Float64(1.0 + Float64(k * Float64(k + 10.0)))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((m <= -4.4e-10) || ~((m <= 5.4e-36)))
		tmp = (k ^ m) * a;
	else
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[m, -4.4e-10], N[Not[LessEqual[m, 5.4e-36]], $MachinePrecision]], N[(N[Power[k, m], $MachinePrecision] * a), $MachinePrecision], N[(a * N[(1.0 / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -4.4 \cdot 10^{-10} \lor \neg \left(m \leq 5.4 \cdot 10^{-36}\right):\\
\;\;\;\;{k}^{m} \cdot a\\

\mathbf{else}:\\
\;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -4.3999999999999998e-10 or 5.40000000000000015e-36 < m

    1. Initial program 90.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/90.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative90.5%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+90.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative90.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out90.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def90.5%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative90.5%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified90.5%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in k around 0 100.0%

      \[\leadsto \color{blue}{{k}^{m}} \cdot a \]

    if -4.3999999999999998e-10 < m < 5.40000000000000015e-36

    1. Initial program 94.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative94.6%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def94.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative94.6%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified94.6%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 94.1%

      \[\leadsto \color{blue}{\frac{1}{1 + k \cdot \left(10 + k\right)}} \cdot a \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -4.4 \cdot 10^{-10} \lor \neg \left(m \leq 5.4 \cdot 10^{-36}\right):\\ \;\;\;\;{k}^{m} \cdot a\\ \mathbf{else}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \]

Alternative 5: 45.4% accurate, 10.4× speedup?

\[\begin{array}{l} \\ a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)} \end{array} \]
(FPCore (a k m) :precision binary64 (* a (/ 1.0 (+ 1.0 (* k (+ k 10.0))))))
double code(double a, double k, double m) {
	return a * (1.0 / (1.0 + (k * (k + 10.0))));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = a * (1.0d0 / (1.0d0 + (k * (k + 10.0d0))))
end function
public static double code(double a, double k, double m) {
	return a * (1.0 / (1.0 + (k * (k + 10.0))));
}
def code(a, k, m):
	return a * (1.0 / (1.0 + (k * (k + 10.0))))
function code(a, k, m)
	return Float64(a * Float64(1.0 / Float64(1.0 + Float64(k * Float64(k + 10.0)))))
end
function tmp = code(a, k, m)
	tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
end
code[a_, k_, m_] := N[(a * N[(1.0 / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}
\end{array}
Derivation
  1. Initial program 91.7%

    \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
  2. Step-by-step derivation
    1. associate-*r/91.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
    2. *-commutative91.7%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
    3. associate-+l+91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
    4. +-commutative91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
    5. distribute-rgt-out91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
    6. fma-def91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
    7. +-commutative91.7%

      \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
  3. Simplified91.7%

    \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
  4. Taylor expanded in m around 0 44.6%

    \[\leadsto \color{blue}{\frac{1}{1 + k \cdot \left(10 + k\right)}} \cdot a \]
  5. Final simplification44.6%

    \[\leadsto a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)} \]

Alternative 6: 28.7% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq -2.3 \cdot 10^{+159} \lor \neg \left(k \leq 0.1\right):\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= k -2.3e+159) (not (<= k 0.1))) (/ 0.1 (/ k a)) a))
double code(double a, double k, double m) {
	double tmp;
	if ((k <= -2.3e+159) || !(k <= 0.1)) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((k <= (-2.3d+159)) .or. (.not. (k <= 0.1d0))) then
        tmp = 0.1d0 / (k / a)
    else
        tmp = a
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((k <= -2.3e+159) || !(k <= 0.1)) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (k <= -2.3e+159) or not (k <= 0.1):
		tmp = 0.1 / (k / a)
	else:
		tmp = a
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((k <= -2.3e+159) || !(k <= 0.1))
		tmp = Float64(0.1 / Float64(k / a));
	else
		tmp = a;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((k <= -2.3e+159) || ~((k <= 0.1)))
		tmp = 0.1 / (k / a);
	else
		tmp = a;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[k, -2.3e+159], N[Not[LessEqual[k, 0.1]], $MachinePrecision]], N[(0.1 / N[(k / a), $MachinePrecision]), $MachinePrecision], a]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq -2.3 \cdot 10^{+159} \lor \neg \left(k \leq 0.1\right):\\
\;\;\;\;\frac{0.1}{\frac{k}{a}}\\

\mathbf{else}:\\
\;\;\;\;a\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < -2.29999999999999995e159 or 0.10000000000000001 < k

    1. Initial program 82.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/82.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative82.6%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+82.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative82.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out82.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def82.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative82.6%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified82.6%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 62.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 26.7%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative26.7%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified26.7%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 26.7%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]
    9. Step-by-step derivation
      1. associate-*r/26.7%

        \[\leadsto \color{blue}{\frac{0.1 \cdot a}{k}} \]
      2. associate-/l*28.6%

        \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]
    10. Simplified28.6%

      \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]

    if -2.29999999999999995e159 < k < 0.10000000000000001

    1. Initial program 98.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/98.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative98.6%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+98.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative98.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out98.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def98.6%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative98.6%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified98.6%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 31.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 30.1%

      \[\leadsto \color{blue}{a} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification29.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -2.3 \cdot 10^{+159} \lor \neg \left(k \leq 0.1\right):\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \]

Alternative 7: 28.1% accurate, 12.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.0026:\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;a + -10 \cdot \left(k \cdot a\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.0026) (/ 0.1 (/ k a)) (+ a (* -10.0 (* k a)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.0026) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a + (-10.0 * (k * a));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.0026d0)) then
        tmp = 0.1d0 / (k / a)
    else
        tmp = a + ((-10.0d0) * (k * a))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.0026) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a + (-10.0 * (k * a));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.0026:
		tmp = 0.1 / (k / a)
	else:
		tmp = a + (-10.0 * (k * a))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.0026)
		tmp = Float64(0.1 / Float64(k / a));
	else
		tmp = Float64(a + Float64(-10.0 * Float64(k * a)));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.0026)
		tmp = 0.1 / (k / a);
	else
		tmp = a + (-10.0 * (k * a));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.0026], N[(0.1 / N[(k / a), $MachinePrecision]), $MachinePrecision], N[(a + N[(-10.0 * N[(k * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.0026:\\
\;\;\;\;\frac{0.1}{\frac{k}{a}}\\

\mathbf{else}:\\
\;\;\;\;a + -10 \cdot \left(k \cdot a\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -0.0025999999999999999

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 39.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative22.0%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 28.1%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]
    9. Step-by-step derivation
      1. associate-*r/28.1%

        \[\leadsto \color{blue}{\frac{0.1 \cdot a}{k}} \]
      2. associate-/l*29.4%

        \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]
    10. Simplified29.4%

      \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]

    if -0.0025999999999999999 < m

    1. Initial program 87.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative87.2%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified87.2%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 47.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 28.0%

      \[\leadsto \color{blue}{a + -10 \cdot \left(a \cdot k\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification28.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.0026:\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;a + -10 \cdot \left(k \cdot a\right)\\ \end{array} \]

Alternative 8: 28.1% accurate, 12.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.0026:\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;a + k \cdot \left(a \cdot -10\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.0026) (/ 0.1 (/ k a)) (+ a (* k (* a -10.0)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.0026) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a + (k * (a * -10.0));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.0026d0)) then
        tmp = 0.1d0 / (k / a)
    else
        tmp = a + (k * (a * (-10.0d0)))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.0026) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a + (k * (a * -10.0));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.0026:
		tmp = 0.1 / (k / a)
	else:
		tmp = a + (k * (a * -10.0))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.0026)
		tmp = Float64(0.1 / Float64(k / a));
	else
		tmp = Float64(a + Float64(k * Float64(a * -10.0)));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.0026)
		tmp = 0.1 / (k / a);
	else
		tmp = a + (k * (a * -10.0));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.0026], N[(0.1 / N[(k / a), $MachinePrecision]), $MachinePrecision], N[(a + N[(k * N[(a * -10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.0026:\\
\;\;\;\;\frac{0.1}{\frac{k}{a}}\\

\mathbf{else}:\\
\;\;\;\;a + k \cdot \left(a \cdot -10\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -0.0025999999999999999

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 39.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative22.0%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 28.1%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]
    9. Step-by-step derivation
      1. associate-*r/28.1%

        \[\leadsto \color{blue}{\frac{0.1 \cdot a}{k}} \]
      2. associate-/l*29.4%

        \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]
    10. Simplified29.4%

      \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]

    if -0.0025999999999999999 < m

    1. Initial program 87.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative87.2%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified87.2%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 47.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 32.3%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative32.3%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified32.3%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around 0 28.0%

      \[\leadsto \color{blue}{a + -10 \cdot \left(a \cdot k\right)} \]
    9. Step-by-step derivation
      1. *-commutative28.0%

        \[\leadsto a + \color{blue}{\left(a \cdot k\right) \cdot -10} \]
      2. *-commutative28.0%

        \[\leadsto a + \color{blue}{\left(k \cdot a\right)} \cdot -10 \]
      3. associate-*l*28.0%

        \[\leadsto a + \color{blue}{k \cdot \left(a \cdot -10\right)} \]
    10. Simplified28.0%

      \[\leadsto \color{blue}{a + k \cdot \left(a \cdot -10\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification28.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.0026:\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;a + k \cdot \left(a \cdot -10\right)\\ \end{array} \]

Alternative 9: 31.5% accurate, 12.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.25:\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.25) (/ 0.1 (/ k a)) (/ a (+ 1.0 (* k 10.0)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.25) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a / (1.0 + (k * 10.0));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.25d0)) then
        tmp = 0.1d0 / (k / a)
    else
        tmp = a / (1.0d0 + (k * 10.0d0))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.25) {
		tmp = 0.1 / (k / a);
	} else {
		tmp = a / (1.0 + (k * 10.0));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.25:
		tmp = 0.1 / (k / a)
	else:
		tmp = a / (1.0 + (k * 10.0))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.25)
		tmp = Float64(0.1 / Float64(k / a));
	else
		tmp = Float64(a / Float64(1.0 + Float64(k * 10.0)));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.25)
		tmp = 0.1 / (k / a);
	else
		tmp = a / (1.0 + (k * 10.0));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.25], N[(0.1 / N[(k / a), $MachinePrecision]), $MachinePrecision], N[(a / N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.25:\\
\;\;\;\;\frac{0.1}{\frac{k}{a}}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{1 + k \cdot 10}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -0.25

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 39.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative22.0%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 28.1%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]
    9. Step-by-step derivation
      1. associate-*r/28.1%

        \[\leadsto \color{blue}{\frac{0.1 \cdot a}{k}} \]
      2. associate-/l*29.4%

        \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]
    10. Simplified29.4%

      \[\leadsto \color{blue}{\frac{0.1}{\frac{k}{a}}} \]

    if -0.25 < m

    1. Initial program 87.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative87.2%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified87.2%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 47.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 32.3%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative32.3%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified32.3%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification31.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.25:\\ \;\;\;\;\frac{0.1}{\frac{k}{a}}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \end{array} \]

Alternative 10: 45.4% accurate, 12.7× speedup?

\[\begin{array}{l} \\ \frac{a}{1 + k \cdot \left(k + 10\right)} \end{array} \]
(FPCore (a k m) :precision binary64 (/ a (+ 1.0 (* k (+ k 10.0)))))
double code(double a, double k, double m) {
	return a / (1.0 + (k * (k + 10.0)));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = a / (1.0d0 + (k * (k + 10.0d0)))
end function
public static double code(double a, double k, double m) {
	return a / (1.0 + (k * (k + 10.0)));
}
def code(a, k, m):
	return a / (1.0 + (k * (k + 10.0)))
function code(a, k, m)
	return Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))))
end
function tmp = code(a, k, m)
	tmp = a / (1.0 + (k * (k + 10.0)));
end
code[a_, k_, m_] := N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a}{1 + k \cdot \left(k + 10\right)}
\end{array}
Derivation
  1. Initial program 91.7%

    \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
  2. Step-by-step derivation
    1. associate-*r/91.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
    2. *-commutative91.7%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
    3. associate-+l+91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
    4. +-commutative91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
    5. distribute-rgt-out91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
    6. fma-def91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
    7. +-commutative91.7%

      \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
  3. Simplified91.7%

    \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
  4. Taylor expanded in m around 0 44.6%

    \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
  5. Final simplification44.6%

    \[\leadsto \frac{a}{1 + k \cdot \left(k + 10\right)} \]

Alternative 11: 27.0% accurate, 16.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.00052:\\ \;\;\;\;0.1 \cdot \frac{a}{k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \end{array} \]
(FPCore (a k m) :precision binary64 (if (<= m -0.00052) (* 0.1 (/ a k)) a))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.00052) {
		tmp = 0.1 * (a / k);
	} else {
		tmp = a;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.00052d0)) then
        tmp = 0.1d0 * (a / k)
    else
        tmp = a
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.00052) {
		tmp = 0.1 * (a / k);
	} else {
		tmp = a;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.00052:
		tmp = 0.1 * (a / k)
	else:
		tmp = a
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.00052)
		tmp = Float64(0.1 * Float64(a / k));
	else
		tmp = a;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.00052)
		tmp = 0.1 * (a / k);
	else
		tmp = a;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.00052], N[(0.1 * N[(a / k), $MachinePrecision]), $MachinePrecision], a]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.00052:\\
\;\;\;\;0.1 \cdot \frac{a}{k}\\

\mathbf{else}:\\
\;\;\;\;a\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -5.19999999999999954e-4

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def100.0%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative100.0%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 39.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative22.0%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified22.0%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 28.1%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]

    if -5.19999999999999954e-4 < m

    1. Initial program 87.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. *-commutative87.2%

        \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
      3. associate-+l+87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
      4. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
      5. distribute-rgt-out87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
      6. fma-def87.2%

        \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
      7. +-commutative87.2%

        \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
    3. Simplified87.2%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
    4. Taylor expanded in m around 0 47.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
    5. Taylor expanded in k around 0 27.1%

      \[\leadsto \color{blue}{a} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification27.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.00052:\\ \;\;\;\;0.1 \cdot \frac{a}{k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \]

Alternative 12: 20.5% accurate, 114.0× speedup?

\[\begin{array}{l} \\ a \end{array} \]
(FPCore (a k m) :precision binary64 a)
double code(double a, double k, double m) {
	return a;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = a
end function
public static double code(double a, double k, double m) {
	return a;
}
def code(a, k, m):
	return a
function code(a, k, m)
	return a
end
function tmp = code(a, k, m)
	tmp = a;
end
code[a_, k_, m_] := a
\begin{array}{l}

\\
a
\end{array}
Derivation
  1. Initial program 91.7%

    \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
  2. Step-by-step derivation
    1. associate-*r/91.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
    2. *-commutative91.7%

      \[\leadsto \color{blue}{\frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \cdot a} \]
    3. associate-+l+91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \cdot a \]
    4. +-commutative91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \cdot a \]
    5. distribute-rgt-out91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \cdot a \]
    6. fma-def91.7%

      \[\leadsto \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \cdot a \]
    7. +-commutative91.7%

      \[\leadsto \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \cdot a \]
  3. Simplified91.7%

    \[\leadsto \color{blue}{\frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)} \cdot a} \]
  4. Taylor expanded in m around 0 44.6%

    \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(10 + k\right)}} \]
  5. Taylor expanded in k around 0 19.0%

    \[\leadsto \color{blue}{a} \]
  6. Final simplification19.0%

    \[\leadsto a \]

Reproduce

?
herbie shell --seed 2023301 
(FPCore (a k m)
  :name "Falkner and Boettcher, Appendix A"
  :precision binary64
  (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))