x / (x^2 + 1)

Percentage Accurate: 76.1% → 100.0%

Time: 2.0s

Alternatives: 4

Speedup: 1.0×

Specification

Math

\[\begin{array}{l} \\ \frac{x}{x \cdot x + 1} \end{array} \]

FPCore

(FPCore (x) :precision binary64 (/ x (+ (* x x) 1.0)))

C

double code(double x) {
	return x / ((x * x) + 1.0);
}

Fortran

real(8) function code(x)
    real(8), intent (in) :: x
    code = x / ((x * x) + 1.0d0)
end function

Java

public static double code(double x) {
	return x / ((x * x) + 1.0);
}

Python

def code(x):
	return x / ((x * x) + 1.0)

Julia

function code(x)
	return Float64(x / Float64(Float64(x * x) + 1.0))
end

MATLAB

function tmp = code(x)
	tmp = x / ((x * x) + 1.0);
end

Wolfram

code[x_] := N[(x / N[(N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]

Initial Program: 76.1% accurate, 1.0× speedup

Math

\[\begin{array}{l} \\ \frac{x}{x \cdot x + 1} \end{array} \]

FPCore

(FPCore (x) :precision binary64 (/ x (+ (* x x) 1.0)))

C

double code(double x) {
	return x / ((x * x) + 1.0);
}

Fortran

real(8) function code(x)
    real(8), intent (in) :: x
    code = x / ((x * x) + 1.0d0)
end function

Java

public static double code(double x) {
	return x / ((x * x) + 1.0);
}

Python

def code(x):
	return x / ((x * x) + 1.0)

Julia

function code(x)
	return Float64(x / Float64(Float64(x * x) + 1.0))
end

MATLAB

function tmp = code(x)
	tmp = x / ((x * x) + 1.0);
end

Wolfram

code[x_] := N[(x / N[(N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]

Alternative 1: 100.0% accurate, 0.6× speedup

Math

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -1 \cdot 10^{+25}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 50000000:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]

FPCore

(FPCore (x)
 :precision binary64
 (if (<= x -1e+25)
   (/ 1.0 x)
   (if (<= x 50000000.0) (/ x (+ 1.0 (* x x))) (/ 1.0 x))))

C

double code(double x) {
	double tmp;
	if (x <= -1e+25) {
		tmp = 1.0 / x;
	} else if (x <= 50000000.0) {
		tmp = x / (1.0 + (x * x));
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}

Fortran

real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: tmp
    if (x <= (-1d+25)) then
        tmp = 1.0d0 / x
    else if (x <= 50000000.0d0) then
        tmp = x / (1.0d0 + (x * x))
    else
        tmp = 1.0d0 / x
    end if
    code = tmp
end function

Java

public static double code(double x) {
	double tmp;
	if (x <= -1e+25) {
		tmp = 1.0 / x;
	} else if (x <= 50000000.0) {
		tmp = x / (1.0 + (x * x));
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}

Python

def code(x):
	tmp = 0
	if x <= -1e+25:
		tmp = 1.0 / x
	elif x <= 50000000.0:
		tmp = x / (1.0 + (x * x))
	else:
		tmp = 1.0 / x
	return tmp

Julia

function code(x)
	tmp = 0.0
	if (x <= -1e+25)
		tmp = Float64(1.0 / x);
	elseif (x <= 50000000.0)
		tmp = Float64(x / Float64(1.0 + Float64(x * x)));
	else
		tmp = Float64(1.0 / x);
	end
	return tmp
end

MATLAB

function tmp_2 = code(x)
	tmp = 0.0;
	if (x <= -1e+25)
		tmp = 1.0 / x;
	elseif (x <= 50000000.0)
		tmp = x / (1.0 + (x * x));
	else
		tmp = 1.0 / x;
	end
	tmp_2 = tmp;
end

Wolfram

code[x_] := If[LessEqual[x, -1e+25], N[(1.0 / x), $MachinePrecision], If[LessEqual[x, 50000000.0], N[(x / N[(1.0 + N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(1.0 / x), $MachinePrecision]]]

Derivation

1. Split input into 2 regimes

2. if x < -1.00000000000000009e25 or 5e7 < x

   1. Initial program 50.6%

      \[\frac{x}{x \cdot x + 1} \]

   2. Taylor expanded in x around inf 100.0%

      \[\leadsto \color{blue}{\frac{1}{x}} \]

   if -1.00000000000000009e25 < x < 5e7

   1. Initial program 100.0%

      \[\frac{x}{x \cdot x + 1} \]
3. Recombined 2 regimes into one program.

4. Final simplification 100.0%

   \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1 \cdot 10^{+25}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 50000000:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]

Alternative 2: 97.8% accurate, 0.0× speedup

Math

\[\begin{array}{l} \\ \frac{{\left(\sqrt[3]{x}\right)}^{2}}{\mathsf{hypot}\left(1, x\right)} \cdot \frac{\sqrt[3]{x}}{\mathsf{hypot}\left(1, x\right)} \end{array} \]

FPCore

(FPCore (x)
 :precision binary64
 (* (/ (pow (cbrt x) 2.0) (hypot 1.0 x)) (/ (cbrt x) (hypot 1.0 x))))

C

double code(double x) {
	return (pow(cbrt(x), 2.0) / hypot(1.0, x)) * (cbrt(x) / hypot(1.0, x));
}

Java

public static double code(double x) {
	return (Math.pow(Math.cbrt(x), 2.0) / Math.hypot(1.0, x)) * (Math.cbrt(x) / Math.hypot(1.0, x));
}

Julia

function code(x)
	return Float64(Float64((cbrt(x) ^ 2.0) / hypot(1.0, x)) * Float64(cbrt(x) / hypot(1.0, x)))
end

Wolfram

code[x_] := N[(N[(N[Power[N[Power[x, 1/3], $MachinePrecision], 2.0], $MachinePrecision] / N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision] * N[(N[Power[x, 1/3], $MachinePrecision] / N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]

Derivation

1. Initial program 75.9%

   \[\frac{x}{x \cdot x + 1} \]
2. Step-by-step derivation

   1. add-cbrt-cube 32.9%

      \[\leadsto \frac{\color{blue}{\sqrt[3]{\left(x \cdot x\right) \cdot x}}}{x \cdot x + 1} \]

   2. cbrt-prod 50.3%

      \[\leadsto \frac{\color{blue}{\sqrt[3]{x \cdot x} \cdot \sqrt[3]{x}}}{x \cdot x + 1} \]

   3. add-sqr-sqrt 50.3%

      \[\leadsto \frac{\sqrt[3]{x \cdot x} \cdot \sqrt[3]{x}}{\color{blue}{\sqrt{x \cdot x + 1} \cdot \sqrt{x \cdot x + 1}}} \]

   4. times-frac 50.3%

      \[\leadsto \color{blue}{\frac{\sqrt[3]{x \cdot x}}{\sqrt{x \cdot x + 1}} \cdot \frac{\sqrt[3]{x}}{\sqrt{x \cdot x + 1}}} \]

   5. cbrt-prod 74.4%

      \[\leadsto \frac{\color{blue}{\sqrt[3]{x} \cdot \sqrt[3]{x}}}{\sqrt{x \cdot x + 1}} \cdot \frac{\sqrt[3]{x}}{\sqrt{x \cdot x + 1}} \]

   6. pow2 74.4%

      \[\leadsto \frac{\color{blue}{{\left(\sqrt[3]{x}\right)}^{2}}}{\sqrt{x \cdot x + 1}} \cdot \frac{\sqrt[3]{x}}{\sqrt{x \cdot x + 1}} \]

   7. +-commutative 74.4%

      \[\leadsto \frac{{\left(\sqrt[3]{x}\right)}^{2}}{\sqrt{\color{blue}{1 + x \cdot x}}} \cdot \frac{\sqrt[3]{x}}{\sqrt{x \cdot x + 1}} \]

   8. hypot-1-def 74.4%

      \[\leadsto \frac{{\left(\sqrt[3]{x}\right)}^{2}}{\color{blue}{\mathsf{hypot}\left(1, x\right)}} \cdot \frac{\sqrt[3]{x}}{\sqrt{x \cdot x + 1}} \]

   9. +-commutative 74.4%

      \[\leadsto \frac{{\left(\sqrt[3]{x}\right)}^{2}}{\mathsf{hypot}\left(1, x\right)} \cdot \frac{\sqrt[3]{x}}{\sqrt{\color{blue}{1 + x \cdot x}}} \]

   10. hypot-1-def 97.9%

       \[\leadsto \frac{{\left(\sqrt[3]{x}\right)}^{2}}{\mathsf{hypot}\left(1, x\right)} \cdot \frac{\sqrt[3]{x}}{\color{blue}{\mathsf{hypot}\left(1, x\right)}} \]

3. Applied egg-rr 97.9%

   \[\leadsto \color{blue}{\frac{{\left(\sqrt[3]{x}\right)}^{2}}{\mathsf{hypot}\left(1, x\right)} \cdot \frac{\sqrt[3]{x}}{\mathsf{hypot}\left(1, x\right)}} \]

4. Final simplification 97.9%

   \[\leadsto \frac{{\left(\sqrt[3]{x}\right)}^{2}}{\mathsf{hypot}\left(1, x\right)} \cdot \frac{\sqrt[3]{x}}{\mathsf{hypot}\left(1, x\right)} \]

Alternative 3: 99.1% accurate, 1.0× speedup

Math

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -1:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 1:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \end{array} \]

FPCore

(FPCore (x)
 :precision binary64
 (if (<= x -1.0) (/ 1.0 x) (if (<= x 1.0) x (/ 1.0 x))))

C

double code(double x) {
	double tmp;
	if (x <= -1.0) {
		tmp = 1.0 / x;
	} else if (x <= 1.0) {
		tmp = x;
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}

Fortran

real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: tmp
    if (x <= (-1.0d0)) then
        tmp = 1.0d0 / x
    else if (x <= 1.0d0) then
        tmp = x
    else
        tmp = 1.0d0 / x
    end if
    code = tmp
end function

Java

public static double code(double x) {
	double tmp;
	if (x <= -1.0) {
		tmp = 1.0 / x;
	} else if (x <= 1.0) {
		tmp = x;
	} else {
		tmp = 1.0 / x;
	}
	return tmp;
}

Python

def code(x):
	tmp = 0
	if x <= -1.0:
		tmp = 1.0 / x
	elif x <= 1.0:
		tmp = x
	else:
		tmp = 1.0 / x
	return tmp

Julia

function code(x)
	tmp = 0.0
	if (x <= -1.0)
		tmp = Float64(1.0 / x);
	elseif (x <= 1.0)
		tmp = x;
	else
		tmp = Float64(1.0 / x);
	end
	return tmp
end

MATLAB

function tmp_2 = code(x)
	tmp = 0.0;
	if (x <= -1.0)
		tmp = 1.0 / x;
	elseif (x <= 1.0)
		tmp = x;
	else
		tmp = 1.0 / x;
	end
	tmp_2 = tmp;
end

Wolfram

code[x_] := If[LessEqual[x, -1.0], N[(1.0 / x), $MachinePrecision], If[LessEqual[x, 1.0], x, N[(1.0 / x), $MachinePrecision]]]

Derivation

1. Split input into 2 regimes

2. if x < -1 or 1 < x

   1. Initial program 52.1%

      \[\frac{x}{x \cdot x + 1} \]

   2. Taylor expanded in x around inf 98.9%

      \[\leadsto \color{blue}{\frac{1}{x}} \]

   if -1 < x < 1

   1. Initial program 100.0%

      \[\frac{x}{x \cdot x + 1} \]

   2. Taylor expanded in x around 0 99.0%

      \[\leadsto \color{blue}{x} \]
3. Recombined 2 regimes into one program.

4. Final simplification 98.9%

   \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 1:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]

Alternative 4: 50.6% accurate, 7.0× speedup

Math

\[\begin{array}{l} \\ x \end{array} \]

FPCore

(FPCore (x) :precision binary64 x)

C

double code(double x) {
	return x;
}

Fortran

real(8) function code(x)
    real(8), intent (in) :: x
    code = x
end function

Java

public static double code(double x) {
	return x;
}

Python

def code(x):
	return x

Julia

function code(x)
	return x
end

MATLAB

function tmp = code(x)
	tmp = x;
end

Wolfram

code[x_] := x

Derivation

1. Initial program 75.9%

   \[\frac{x}{x \cdot x + 1} \]

2. Taylor expanded in x around 0 51.0%

   \[\leadsto \color{blue}{x} \]

3. Final simplification 51.0%

   \[\leadsto x \]

Developer target: 99.8% accurate, 1.0× speedup

Math

\[\begin{array}{l} \\ \frac{1}{x + \frac{1}{x}} \end{array} \]

FPCore

(FPCore (x) :precision binary64 (/ 1.0 (+ x (/ 1.0 x))))

C

double code(double x) {
	return 1.0 / (x + (1.0 / x));
}

Fortran

real(8) function code(x)
    real(8), intent (in) :: x
    code = 1.0d0 / (x + (1.0d0 / x))
end function

Java

public static double code(double x) {
	return 1.0 / (x + (1.0 / x));
}

Python

def code(x):
	return 1.0 / (x + (1.0 / x))

Julia

function code(x)
	return Float64(1.0 / Float64(x + Float64(1.0 / x)))
end

MATLAB

function tmp = code(x)
	tmp = 1.0 / (x + (1.0 / x));
end

Wolfram

code[x_] := N[(1.0 / N[(x + N[(1.0 / x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]

Reproduce

herbie shell --seed 2023278 
(FPCore (x)
  :name "x / (x^2 + 1)"
  :precision binary64

  :herbie-target
  (/ 1.0 (+ x (/ 1.0 x)))

  (/ x (+ (* x x) 1.0)))