Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\log \left(x + \sqrt{x \cdot x + 1}\right)
\]
↓
\[\begin{array}{l}
\mathbf{if}\;x \leq -0.00095:\\
\;\;\;\;\log \left(\frac{-1}{x - \mathsf{hypot}\left(1, x\right)}\right)\\
\mathbf{elif}\;x \leq 0.96:\\
\;\;\;\;x + -0.16666666666666666 \cdot {x}^{3}\\
\mathbf{else}:\\
\;\;\;\;\log \left(x \cdot 2 + 0.5 \cdot \frac{1}{x}\right)\\
\end{array}
\]
(FPCore (x) :precision binary64 (log (+ x (sqrt (+ (* x x) 1.0))))) ↓
(FPCore (x)
:precision binary64
(if (<= x -0.00095)
(log (/ -1.0 (- x (hypot 1.0 x))))
(if (<= x 0.96)
(+ x (* -0.16666666666666666 (pow x 3.0)))
(log (+ (* x 2.0) (* 0.5 (/ 1.0 x))))))) double code(double x) {
return log((x + sqrt(((x * x) + 1.0))));
}
↓
double code(double x) {
double tmp;
if (x <= -0.00095) {
tmp = log((-1.0 / (x - hypot(1.0, x))));
} else if (x <= 0.96) {
tmp = x + (-0.16666666666666666 * pow(x, 3.0));
} else {
tmp = log(((x * 2.0) + (0.5 * (1.0 / x))));
}
return tmp;
}
public static double code(double x) {
return Math.log((x + Math.sqrt(((x * x) + 1.0))));
}
↓
public static double code(double x) {
double tmp;
if (x <= -0.00095) {
tmp = Math.log((-1.0 / (x - Math.hypot(1.0, x))));
} else if (x <= 0.96) {
tmp = x + (-0.16666666666666666 * Math.pow(x, 3.0));
} else {
tmp = Math.log(((x * 2.0) + (0.5 * (1.0 / x))));
}
return tmp;
}
def code(x):
return math.log((x + math.sqrt(((x * x) + 1.0))))
↓
def code(x):
tmp = 0
if x <= -0.00095:
tmp = math.log((-1.0 / (x - math.hypot(1.0, x))))
elif x <= 0.96:
tmp = x + (-0.16666666666666666 * math.pow(x, 3.0))
else:
tmp = math.log(((x * 2.0) + (0.5 * (1.0 / x))))
return tmp
function code(x)
return log(Float64(x + sqrt(Float64(Float64(x * x) + 1.0))))
end
↓
function code(x)
tmp = 0.0
if (x <= -0.00095)
tmp = log(Float64(-1.0 / Float64(x - hypot(1.0, x))));
elseif (x <= 0.96)
tmp = Float64(x + Float64(-0.16666666666666666 * (x ^ 3.0)));
else
tmp = log(Float64(Float64(x * 2.0) + Float64(0.5 * Float64(1.0 / x))));
end
return tmp
end
function tmp = code(x)
tmp = log((x + sqrt(((x * x) + 1.0))));
end
↓
function tmp_2 = code(x)
tmp = 0.0;
if (x <= -0.00095)
tmp = log((-1.0 / (x - hypot(1.0, x))));
elseif (x <= 0.96)
tmp = x + (-0.16666666666666666 * (x ^ 3.0));
else
tmp = log(((x * 2.0) + (0.5 * (1.0 / x))));
end
tmp_2 = tmp;
end
code[x_] := N[Log[N[(x + N[Sqrt[N[(N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
↓
code[x_] := If[LessEqual[x, -0.00095], N[Log[N[(-1.0 / N[(x - N[Sqrt[1.0 ^ 2 + x ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], If[LessEqual[x, 0.96], N[(x + N[(-0.16666666666666666 * N[Power[x, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[Log[N[(N[(x * 2.0), $MachinePrecision] + N[(0.5 * N[(1.0 / x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]]]
\log \left(x + \sqrt{x \cdot x + 1}\right)
↓
\begin{array}{l}
\mathbf{if}\;x \leq -0.00095:\\
\;\;\;\;\log \left(\frac{-1}{x - \mathsf{hypot}\left(1, x\right)}\right)\\
\mathbf{elif}\;x \leq 0.96:\\
\;\;\;\;x + -0.16666666666666666 \cdot {x}^{3}\\
\mathbf{else}:\\
\;\;\;\;\log \left(x \cdot 2 + 0.5 \cdot \frac{1}{x}\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 99.7% Cost 13316
\[\begin{array}{l}
\mathbf{if}\;x \leq -0.00095:\\
\;\;\;\;\log \left(\frac{-1}{x - \mathsf{hypot}\left(1, x\right)}\right)\\
\mathbf{elif}\;x \leq 0.96:\\
\;\;\;\;x + -0.16666666666666666 \cdot {x}^{3}\\
\mathbf{else}:\\
\;\;\;\;\log \left(x \cdot 2 + 0.5 \cdot \frac{1}{x}\right)\\
\end{array}
\]
Alternative 2 Accuracy 99.3% Cost 7240
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.25:\\
\;\;\;\;\log \left(\frac{-0.5}{x}\right)\\
\mathbf{elif}\;x \leq 0.96:\\
\;\;\;\;x + -0.16666666666666666 \cdot {x}^{3}\\
\mathbf{else}:\\
\;\;\;\;\log \left(x \cdot 2 + 0.5 \cdot \frac{1}{x}\right)\\
\end{array}
\]
Alternative 3 Accuracy 99.2% Cost 7048
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.25:\\
\;\;\;\;\log \left(\frac{-0.5}{x}\right)\\
\mathbf{elif}\;x \leq 1.3:\\
\;\;\;\;x + -0.16666666666666666 \cdot {x}^{3}\\
\mathbf{else}:\\
\;\;\;\;\log \left(x + x\right)\\
\end{array}
\]
Alternative 4 Accuracy 98.9% Cost 6856
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.25:\\
\;\;\;\;\log \left(\frac{-0.5}{x}\right)\\
\mathbf{elif}\;x \leq 1.25:\\
\;\;\;\;x\\
\mathbf{else}:\\
\;\;\;\;\log \left(x + x\right)\\
\end{array}
\]
Alternative 5 Accuracy 75.6% Cost 6724
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.25:\\
\;\;\;\;x\\
\mathbf{else}:\\
\;\;\;\;\log \left(x + x\right)\\
\end{array}
\]
Alternative 6 Accuracy 52.6% Cost 64
\[x
\]