Linear.V3:$cdot from linear-1.19.1.3, B

Percentage Accurate: 97.6% → 98.9%
Time: 9.9s
Alternatives: 10
Speedup: 0.5×

Specification

?
\[\begin{array}{l} \\ \left(x \cdot y + z \cdot t\right) + a \cdot b \end{array} \]
(FPCore (x y z t a b) :precision binary64 (+ (+ (* x y) (* z t)) (* a b)))
double code(double x, double y, double z, double t, double a, double b) {
	return ((x * y) + (z * t)) + (a * b);
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = ((x * y) + (z * t)) + (a * b)
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	return ((x * y) + (z * t)) + (a * b);
}
def code(x, y, z, t, a, b):
	return ((x * y) + (z * t)) + (a * b)
function code(x, y, z, t, a, b)
	return Float64(Float64(Float64(x * y) + Float64(z * t)) + Float64(a * b))
end
function tmp = code(x, y, z, t, a, b)
	tmp = ((x * y) + (z * t)) + (a * b);
end
code[x_, y_, z_, t_, a_, b_] := N[(N[(N[(x * y), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision] + N[(a * b), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(x \cdot y + z \cdot t\right) + a \cdot b
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 10 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 97.6% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(x \cdot y + z \cdot t\right) + a \cdot b \end{array} \]
(FPCore (x y z t a b) :precision binary64 (+ (+ (* x y) (* z t)) (* a b)))
double code(double x, double y, double z, double t, double a, double b) {
	return ((x * y) + (z * t)) + (a * b);
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = ((x * y) + (z * t)) + (a * b)
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	return ((x * y) + (z * t)) + (a * b);
}
def code(x, y, z, t, a, b):
	return ((x * y) + (z * t)) + (a * b)
function code(x, y, z, t, a, b)
	return Float64(Float64(Float64(x * y) + Float64(z * t)) + Float64(a * b))
end
function tmp = code(x, y, z, t, a, b)
	tmp = ((x * y) + (z * t)) + (a * b);
end
code[x_, y_, z_, t_, a_, b_] := N[(N[(N[(x * y), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision] + N[(a * b), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(x \cdot y + z \cdot t\right) + a \cdot b
\end{array}

Alternative 1: 98.9% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \mathsf{fma}\left(x, y, \mathsf{fma}\left(z, t, a \cdot b\right)\right) \end{array} \]
(FPCore (x y z t a b) :precision binary64 (fma x y (fma z t (* a b))))
double code(double x, double y, double z, double t, double a, double b) {
	return fma(x, y, fma(z, t, (a * b)));
}
function code(x, y, z, t, a, b)
	return fma(x, y, fma(z, t, Float64(a * b)))
end
code[x_, y_, z_, t_, a_, b_] := N[(x * y + N[(z * t + N[(a * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{fma}\left(x, y, \mathsf{fma}\left(z, t, a \cdot b\right)\right)
\end{array}
Derivation
  1. Initial program 97.3%

    \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
  2. Step-by-step derivation
    1. associate-+l+97.3%

      \[\leadsto \color{blue}{x \cdot y + \left(z \cdot t + a \cdot b\right)} \]
    2. fma-def99.2%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, z \cdot t + a \cdot b\right)} \]
    3. fma-def99.2%

      \[\leadsto \mathsf{fma}\left(x, y, \color{blue}{\mathsf{fma}\left(z, t, a \cdot b\right)}\right) \]
  3. Simplified99.2%

    \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, \mathsf{fma}\left(z, t, a \cdot b\right)\right)} \]
  4. Final simplification99.2%

    \[\leadsto \mathsf{fma}\left(x, y, \mathsf{fma}\left(z, t, a \cdot b\right)\right) \]

Alternative 2: 98.8% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \mathsf{fma}\left(a, b, \mathsf{fma}\left(x, y, z \cdot t\right)\right) \end{array} \]
(FPCore (x y z t a b) :precision binary64 (fma a b (fma x y (* z t))))
double code(double x, double y, double z, double t, double a, double b) {
	return fma(a, b, fma(x, y, (z * t)));
}
function code(x, y, z, t, a, b)
	return fma(a, b, fma(x, y, Float64(z * t)))
end
code[x_, y_, z_, t_, a_, b_] := N[(a * b + N[(x * y + N[(z * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{fma}\left(a, b, \mathsf{fma}\left(x, y, z \cdot t\right)\right)
\end{array}
Derivation
  1. Initial program 97.3%

    \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
  2. Step-by-step derivation
    1. +-commutative97.3%

      \[\leadsto \color{blue}{a \cdot b + \left(x \cdot y + z \cdot t\right)} \]
    2. fma-def98.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(a, b, x \cdot y + z \cdot t\right)} \]
    3. fma-def99.2%

      \[\leadsto \mathsf{fma}\left(a, b, \color{blue}{\mathsf{fma}\left(x, y, z \cdot t\right)}\right) \]
  3. Simplified99.2%

    \[\leadsto \color{blue}{\mathsf{fma}\left(a, b, \mathsf{fma}\left(x, y, z \cdot t\right)\right)} \]
  4. Final simplification99.2%

    \[\leadsto \mathsf{fma}\left(a, b, \mathsf{fma}\left(x, y, z \cdot t\right)\right) \]

Alternative 3: 98.0% accurate, 0.1× speedup?

\[\begin{array}{l} \\ a \cdot b + \mathsf{fma}\left(x, y, z \cdot t\right) \end{array} \]
(FPCore (x y z t a b) :precision binary64 (+ (* a b) (fma x y (* z t))))
double code(double x, double y, double z, double t, double a, double b) {
	return (a * b) + fma(x, y, (z * t));
}
function code(x, y, z, t, a, b)
	return Float64(Float64(a * b) + fma(x, y, Float64(z * t)))
end
code[x_, y_, z_, t_, a_, b_] := N[(N[(a * b), $MachinePrecision] + N[(x * y + N[(z * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
a \cdot b + \mathsf{fma}\left(x, y, z \cdot t\right)
\end{array}
Derivation
  1. Initial program 97.3%

    \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
  2. Step-by-step derivation
    1. fma-def98.4%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, z \cdot t\right)} + a \cdot b \]
  3. Simplified98.4%

    \[\leadsto \color{blue}{\mathsf{fma}\left(x, y, z \cdot t\right) + a \cdot b} \]
  4. Final simplification98.4%

    \[\leadsto a \cdot b + \mathsf{fma}\left(x, y, z \cdot t\right) \]

Alternative 4: 54.1% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \cdot y \leq -4.5 \cdot 10^{+132}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;x \cdot y \leq -2.15 \cdot 10^{-99}:\\ \;\;\;\;z \cdot t\\ \mathbf{elif}\;x \cdot y \leq -3.3 \cdot 10^{-195}:\\ \;\;\;\;a \cdot b\\ \mathbf{elif}\;x \cdot y \leq 2 \cdot 10^{-313}:\\ \;\;\;\;z \cdot t\\ \mathbf{elif}\;x \cdot y \leq 9500000000000:\\ \;\;\;\;a \cdot b\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
(FPCore (x y z t a b)
 :precision binary64
 (if (<= (* x y) -4.5e+132)
   (* x y)
   (if (<= (* x y) -2.15e-99)
     (* z t)
     (if (<= (* x y) -3.3e-195)
       (* a b)
       (if (<= (* x y) 2e-313)
         (* z t)
         (if (<= (* x y) 9500000000000.0) (* a b) (* x y)))))))
double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if ((x * y) <= -4.5e+132) {
		tmp = x * y;
	} else if ((x * y) <= -2.15e-99) {
		tmp = z * t;
	} else if ((x * y) <= -3.3e-195) {
		tmp = a * b;
	} else if ((x * y) <= 2e-313) {
		tmp = z * t;
	} else if ((x * y) <= 9500000000000.0) {
		tmp = a * b;
	} else {
		tmp = x * y;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if ((x * y) <= (-4.5d+132)) then
        tmp = x * y
    else if ((x * y) <= (-2.15d-99)) then
        tmp = z * t
    else if ((x * y) <= (-3.3d-195)) then
        tmp = a * b
    else if ((x * y) <= 2d-313) then
        tmp = z * t
    else if ((x * y) <= 9500000000000.0d0) then
        tmp = a * b
    else
        tmp = x * y
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if ((x * y) <= -4.5e+132) {
		tmp = x * y;
	} else if ((x * y) <= -2.15e-99) {
		tmp = z * t;
	} else if ((x * y) <= -3.3e-195) {
		tmp = a * b;
	} else if ((x * y) <= 2e-313) {
		tmp = z * t;
	} else if ((x * y) <= 9500000000000.0) {
		tmp = a * b;
	} else {
		tmp = x * y;
	}
	return tmp;
}
def code(x, y, z, t, a, b):
	tmp = 0
	if (x * y) <= -4.5e+132:
		tmp = x * y
	elif (x * y) <= -2.15e-99:
		tmp = z * t
	elif (x * y) <= -3.3e-195:
		tmp = a * b
	elif (x * y) <= 2e-313:
		tmp = z * t
	elif (x * y) <= 9500000000000.0:
		tmp = a * b
	else:
		tmp = x * y
	return tmp
function code(x, y, z, t, a, b)
	tmp = 0.0
	if (Float64(x * y) <= -4.5e+132)
		tmp = Float64(x * y);
	elseif (Float64(x * y) <= -2.15e-99)
		tmp = Float64(z * t);
	elseif (Float64(x * y) <= -3.3e-195)
		tmp = Float64(a * b);
	elseif (Float64(x * y) <= 2e-313)
		tmp = Float64(z * t);
	elseif (Float64(x * y) <= 9500000000000.0)
		tmp = Float64(a * b);
	else
		tmp = Float64(x * y);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b)
	tmp = 0.0;
	if ((x * y) <= -4.5e+132)
		tmp = x * y;
	elseif ((x * y) <= -2.15e-99)
		tmp = z * t;
	elseif ((x * y) <= -3.3e-195)
		tmp = a * b;
	elseif ((x * y) <= 2e-313)
		tmp = z * t;
	elseif ((x * y) <= 9500000000000.0)
		tmp = a * b;
	else
		tmp = x * y;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_] := If[LessEqual[N[(x * y), $MachinePrecision], -4.5e+132], N[(x * y), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], -2.15e-99], N[(z * t), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], -3.3e-195], N[(a * b), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], 2e-313], N[(z * t), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], 9500000000000.0], N[(a * b), $MachinePrecision], N[(x * y), $MachinePrecision]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \cdot y \leq -4.5 \cdot 10^{+132}:\\
\;\;\;\;x \cdot y\\

\mathbf{elif}\;x \cdot y \leq -2.15 \cdot 10^{-99}:\\
\;\;\;\;z \cdot t\\

\mathbf{elif}\;x \cdot y \leq -3.3 \cdot 10^{-195}:\\
\;\;\;\;a \cdot b\\

\mathbf{elif}\;x \cdot y \leq 2 \cdot 10^{-313}:\\
\;\;\;\;z \cdot t\\

\mathbf{elif}\;x \cdot y \leq 9500000000000:\\
\;\;\;\;a \cdot b\\

\mathbf{else}:\\
\;\;\;\;x \cdot y\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 x y) < -4.49999999999999972e132 or 9.5e12 < (*.f64 x y)

    1. Initial program 93.2%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in x around inf 70.4%

      \[\leadsto \color{blue}{x \cdot y} \]

    if -4.49999999999999972e132 < (*.f64 x y) < -2.1499999999999999e-99 or -3.3e-195 < (*.f64 x y) < 1.99999999998e-313

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in z around inf 56.7%

      \[\leadsto \color{blue}{t \cdot z} \]

    if -2.1499999999999999e-99 < (*.f64 x y) < -3.3e-195 or 1.99999999998e-313 < (*.f64 x y) < 9.5e12

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in a around inf 61.9%

      \[\leadsto \color{blue}{a \cdot b} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification63.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \cdot y \leq -4.5 \cdot 10^{+132}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;x \cdot y \leq -2.15 \cdot 10^{-99}:\\ \;\;\;\;z \cdot t\\ \mathbf{elif}\;x \cdot y \leq -3.3 \cdot 10^{-195}:\\ \;\;\;\;a \cdot b\\ \mathbf{elif}\;x \cdot y \leq 2 \cdot 10^{-313}:\\ \;\;\;\;z \cdot t\\ \mathbf{elif}\;x \cdot y \leq 9500000000000:\\ \;\;\;\;a \cdot b\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]

Alternative 5: 98.4% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := a \cdot b + \left(x \cdot y + z \cdot t\right)\\ \mathbf{if}\;t_1 \leq \infty:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \end{array} \end{array} \]
(FPCore (x y z t a b)
 :precision binary64
 (let* ((t_1 (+ (* a b) (+ (* x y) (* z t)))))
   (if (<= t_1 INFINITY) t_1 (+ (* a b) (* z t)))))
double code(double x, double y, double z, double t, double a, double b) {
	double t_1 = (a * b) + ((x * y) + (z * t));
	double tmp;
	if (t_1 <= ((double) INFINITY)) {
		tmp = t_1;
	} else {
		tmp = (a * b) + (z * t);
	}
	return tmp;
}
public static double code(double x, double y, double z, double t, double a, double b) {
	double t_1 = (a * b) + ((x * y) + (z * t));
	double tmp;
	if (t_1 <= Double.POSITIVE_INFINITY) {
		tmp = t_1;
	} else {
		tmp = (a * b) + (z * t);
	}
	return tmp;
}
def code(x, y, z, t, a, b):
	t_1 = (a * b) + ((x * y) + (z * t))
	tmp = 0
	if t_1 <= math.inf:
		tmp = t_1
	else:
		tmp = (a * b) + (z * t)
	return tmp
function code(x, y, z, t, a, b)
	t_1 = Float64(Float64(a * b) + Float64(Float64(x * y) + Float64(z * t)))
	tmp = 0.0
	if (t_1 <= Inf)
		tmp = t_1;
	else
		tmp = Float64(Float64(a * b) + Float64(z * t));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b)
	t_1 = (a * b) + ((x * y) + (z * t));
	tmp = 0.0;
	if (t_1 <= Inf)
		tmp = t_1;
	else
		tmp = (a * b) + (z * t);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_] := Block[{t$95$1 = N[(N[(a * b), $MachinePrecision] + N[(N[(x * y), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, Infinity], t$95$1, N[(N[(a * b), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := a \cdot b + \left(x \cdot y + z \cdot t\right)\\
\mathbf{if}\;t_1 \leq \infty:\\
\;\;\;\;t_1\\

\mathbf{else}:\\
\;\;\;\;a \cdot b + z \cdot t\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 (+.f64 (*.f64 x y) (*.f64 z t)) (*.f64 a b)) < +inf.0

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]

    if +inf.0 < (+.f64 (+.f64 (*.f64 x y) (*.f64 z t)) (*.f64 a b))

    1. Initial program 0.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in x around 0 71.4%

      \[\leadsto \color{blue}{a \cdot b + t \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification99.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot b + \left(x \cdot y + z \cdot t\right) \leq \infty:\\ \;\;\;\;a \cdot b + \left(x \cdot y + z \cdot t\right)\\ \mathbf{else}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \end{array} \]

Alternative 6: 84.4% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := x \cdot y + z \cdot t\\ \mathbf{if}\;x \cdot y \leq -42000000:\\ \;\;\;\;t_1\\ \mathbf{elif}\;x \cdot y \leq 1.85 \cdot 10^{-22}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \mathbf{elif}\;x \cdot y \leq 6.8 \cdot 10^{+56}:\\ \;\;\;\;a \cdot b + x \cdot y\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \end{array} \]
(FPCore (x y z t a b)
 :precision binary64
 (let* ((t_1 (+ (* x y) (* z t))))
   (if (<= (* x y) -42000000.0)
     t_1
     (if (<= (* x y) 1.85e-22)
       (+ (* a b) (* z t))
       (if (<= (* x y) 6.8e+56) (+ (* a b) (* x y)) t_1)))))
double code(double x, double y, double z, double t, double a, double b) {
	double t_1 = (x * y) + (z * t);
	double tmp;
	if ((x * y) <= -42000000.0) {
		tmp = t_1;
	} else if ((x * y) <= 1.85e-22) {
		tmp = (a * b) + (z * t);
	} else if ((x * y) <= 6.8e+56) {
		tmp = (a * b) + (x * y);
	} else {
		tmp = t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: t_1
    real(8) :: tmp
    t_1 = (x * y) + (z * t)
    if ((x * y) <= (-42000000.0d0)) then
        tmp = t_1
    else if ((x * y) <= 1.85d-22) then
        tmp = (a * b) + (z * t)
    else if ((x * y) <= 6.8d+56) then
        tmp = (a * b) + (x * y)
    else
        tmp = t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	double t_1 = (x * y) + (z * t);
	double tmp;
	if ((x * y) <= -42000000.0) {
		tmp = t_1;
	} else if ((x * y) <= 1.85e-22) {
		tmp = (a * b) + (z * t);
	} else if ((x * y) <= 6.8e+56) {
		tmp = (a * b) + (x * y);
	} else {
		tmp = t_1;
	}
	return tmp;
}
def code(x, y, z, t, a, b):
	t_1 = (x * y) + (z * t)
	tmp = 0
	if (x * y) <= -42000000.0:
		tmp = t_1
	elif (x * y) <= 1.85e-22:
		tmp = (a * b) + (z * t)
	elif (x * y) <= 6.8e+56:
		tmp = (a * b) + (x * y)
	else:
		tmp = t_1
	return tmp
function code(x, y, z, t, a, b)
	t_1 = Float64(Float64(x * y) + Float64(z * t))
	tmp = 0.0
	if (Float64(x * y) <= -42000000.0)
		tmp = t_1;
	elseif (Float64(x * y) <= 1.85e-22)
		tmp = Float64(Float64(a * b) + Float64(z * t));
	elseif (Float64(x * y) <= 6.8e+56)
		tmp = Float64(Float64(a * b) + Float64(x * y));
	else
		tmp = t_1;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b)
	t_1 = (x * y) + (z * t);
	tmp = 0.0;
	if ((x * y) <= -42000000.0)
		tmp = t_1;
	elseif ((x * y) <= 1.85e-22)
		tmp = (a * b) + (z * t);
	elseif ((x * y) <= 6.8e+56)
		tmp = (a * b) + (x * y);
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_] := Block[{t$95$1 = N[(N[(x * y), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(x * y), $MachinePrecision], -42000000.0], t$95$1, If[LessEqual[N[(x * y), $MachinePrecision], 1.85e-22], N[(N[(a * b), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], 6.8e+56], N[(N[(a * b), $MachinePrecision] + N[(x * y), $MachinePrecision]), $MachinePrecision], t$95$1]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := x \cdot y + z \cdot t\\
\mathbf{if}\;x \cdot y \leq -42000000:\\
\;\;\;\;t_1\\

\mathbf{elif}\;x \cdot y \leq 1.85 \cdot 10^{-22}:\\
\;\;\;\;a \cdot b + z \cdot t\\

\mathbf{elif}\;x \cdot y \leq 6.8 \cdot 10^{+56}:\\
\;\;\;\;a \cdot b + x \cdot y\\

\mathbf{else}:\\
\;\;\;\;t_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 x y) < -4.2e7 or 6.80000000000000002e56 < (*.f64 x y)

    1. Initial program 93.9%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in a around 0 87.4%

      \[\leadsto \color{blue}{t \cdot z + x \cdot y} \]

    if -4.2e7 < (*.f64 x y) < 1.85e-22

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in x around 0 91.6%

      \[\leadsto \color{blue}{a \cdot b + t \cdot z} \]

    if 1.85e-22 < (*.f64 x y) < 6.80000000000000002e56

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in z around 0 94.4%

      \[\leadsto \color{blue}{a \cdot b + x \cdot y} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification89.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \cdot y \leq -42000000:\\ \;\;\;\;x \cdot y + z \cdot t\\ \mathbf{elif}\;x \cdot y \leq 1.85 \cdot 10^{-22}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \mathbf{elif}\;x \cdot y \leq 6.8 \cdot 10^{+56}:\\ \;\;\;\;a \cdot b + x \cdot y\\ \mathbf{else}:\\ \;\;\;\;x \cdot y + z \cdot t\\ \end{array} \]

Alternative 7: 84.8% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \cdot y \leq -9.5 \cdot 10^{+46} \lor \neg \left(x \cdot y \leq 9.6 \cdot 10^{-23}\right):\\ \;\;\;\;a \cdot b + x \cdot y\\ \mathbf{else}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \end{array} \end{array} \]
(FPCore (x y z t a b)
 :precision binary64
 (if (or (<= (* x y) -9.5e+46) (not (<= (* x y) 9.6e-23)))
   (+ (* a b) (* x y))
   (+ (* a b) (* z t))))
double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if (((x * y) <= -9.5e+46) || !((x * y) <= 9.6e-23)) {
		tmp = (a * b) + (x * y);
	} else {
		tmp = (a * b) + (z * t);
	}
	return tmp;
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (((x * y) <= (-9.5d+46)) .or. (.not. ((x * y) <= 9.6d-23))) then
        tmp = (a * b) + (x * y)
    else
        tmp = (a * b) + (z * t)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if (((x * y) <= -9.5e+46) || !((x * y) <= 9.6e-23)) {
		tmp = (a * b) + (x * y);
	} else {
		tmp = (a * b) + (z * t);
	}
	return tmp;
}
def code(x, y, z, t, a, b):
	tmp = 0
	if ((x * y) <= -9.5e+46) or not ((x * y) <= 9.6e-23):
		tmp = (a * b) + (x * y)
	else:
		tmp = (a * b) + (z * t)
	return tmp
function code(x, y, z, t, a, b)
	tmp = 0.0
	if ((Float64(x * y) <= -9.5e+46) || !(Float64(x * y) <= 9.6e-23))
		tmp = Float64(Float64(a * b) + Float64(x * y));
	else
		tmp = Float64(Float64(a * b) + Float64(z * t));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b)
	tmp = 0.0;
	if (((x * y) <= -9.5e+46) || ~(((x * y) <= 9.6e-23)))
		tmp = (a * b) + (x * y);
	else
		tmp = (a * b) + (z * t);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_] := If[Or[LessEqual[N[(x * y), $MachinePrecision], -9.5e+46], N[Not[LessEqual[N[(x * y), $MachinePrecision], 9.6e-23]], $MachinePrecision]], N[(N[(a * b), $MachinePrecision] + N[(x * y), $MachinePrecision]), $MachinePrecision], N[(N[(a * b), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \cdot y \leq -9.5 \cdot 10^{+46} \lor \neg \left(x \cdot y \leq 9.6 \cdot 10^{-23}\right):\\
\;\;\;\;a \cdot b + x \cdot y\\

\mathbf{else}:\\
\;\;\;\;a \cdot b + z \cdot t\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 x y) < -9.5000000000000008e46 or 9.59999999999999986e-23 < (*.f64 x y)

    1. Initial program 94.5%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in z around 0 78.4%

      \[\leadsto \color{blue}{a \cdot b + x \cdot y} \]

    if -9.5000000000000008e46 < (*.f64 x y) < 9.59999999999999986e-23

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in x around 0 91.2%

      \[\leadsto \color{blue}{a \cdot b + t \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification84.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \cdot y \leq -9.5 \cdot 10^{+46} \lor \neg \left(x \cdot y \leq 9.6 \cdot 10^{-23}\right):\\ \;\;\;\;a \cdot b + x \cdot y\\ \mathbf{else}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \end{array} \]

Alternative 8: 81.1% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \cdot y \leq -2.8 \cdot 10^{+153}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;x \cdot y \leq 9 \cdot 10^{+119}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \end{array} \]
(FPCore (x y z t a b)
 :precision binary64
 (if (<= (* x y) -2.8e+153)
   (* x y)
   (if (<= (* x y) 9e+119) (+ (* a b) (* z t)) (* x y))))
double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if ((x * y) <= -2.8e+153) {
		tmp = x * y;
	} else if ((x * y) <= 9e+119) {
		tmp = (a * b) + (z * t);
	} else {
		tmp = x * y;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if ((x * y) <= (-2.8d+153)) then
        tmp = x * y
    else if ((x * y) <= 9d+119) then
        tmp = (a * b) + (z * t)
    else
        tmp = x * y
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if ((x * y) <= -2.8e+153) {
		tmp = x * y;
	} else if ((x * y) <= 9e+119) {
		tmp = (a * b) + (z * t);
	} else {
		tmp = x * y;
	}
	return tmp;
}
def code(x, y, z, t, a, b):
	tmp = 0
	if (x * y) <= -2.8e+153:
		tmp = x * y
	elif (x * y) <= 9e+119:
		tmp = (a * b) + (z * t)
	else:
		tmp = x * y
	return tmp
function code(x, y, z, t, a, b)
	tmp = 0.0
	if (Float64(x * y) <= -2.8e+153)
		tmp = Float64(x * y);
	elseif (Float64(x * y) <= 9e+119)
		tmp = Float64(Float64(a * b) + Float64(z * t));
	else
		tmp = Float64(x * y);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b)
	tmp = 0.0;
	if ((x * y) <= -2.8e+153)
		tmp = x * y;
	elseif ((x * y) <= 9e+119)
		tmp = (a * b) + (z * t);
	else
		tmp = x * y;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_] := If[LessEqual[N[(x * y), $MachinePrecision], -2.8e+153], N[(x * y), $MachinePrecision], If[LessEqual[N[(x * y), $MachinePrecision], 9e+119], N[(N[(a * b), $MachinePrecision] + N[(z * t), $MachinePrecision]), $MachinePrecision], N[(x * y), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \cdot y \leq -2.8 \cdot 10^{+153}:\\
\;\;\;\;x \cdot y\\

\mathbf{elif}\;x \cdot y \leq 9 \cdot 10^{+119}:\\
\;\;\;\;a \cdot b + z \cdot t\\

\mathbf{else}:\\
\;\;\;\;x \cdot y\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 x y) < -2.79999999999999985e153 or 9.00000000000000039e119 < (*.f64 x y)

    1. Initial program 90.8%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in x around inf 79.4%

      \[\leadsto \color{blue}{x \cdot y} \]

    if -2.79999999999999985e153 < (*.f64 x y) < 9.00000000000000039e119

    1. Initial program 100.0%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in x around 0 82.4%

      \[\leadsto \color{blue}{a \cdot b + t \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification81.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \cdot y \leq -2.8 \cdot 10^{+153}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;x \cdot y \leq 9 \cdot 10^{+119}:\\ \;\;\;\;a \cdot b + z \cdot t\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]

Alternative 9: 54.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \cdot b \leq -3.1 \cdot 10^{+73}:\\ \;\;\;\;a \cdot b\\ \mathbf{elif}\;a \cdot b \leq 7.2 \cdot 10^{+23}:\\ \;\;\;\;z \cdot t\\ \mathbf{else}:\\ \;\;\;\;a \cdot b\\ \end{array} \end{array} \]
(FPCore (x y z t a b)
 :precision binary64
 (if (<= (* a b) -3.1e+73) (* a b) (if (<= (* a b) 7.2e+23) (* z t) (* a b))))
double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if ((a * b) <= -3.1e+73) {
		tmp = a * b;
	} else if ((a * b) <= 7.2e+23) {
		tmp = z * t;
	} else {
		tmp = a * b;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if ((a * b) <= (-3.1d+73)) then
        tmp = a * b
    else if ((a * b) <= 7.2d+23) then
        tmp = z * t
    else
        tmp = a * b
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	double tmp;
	if ((a * b) <= -3.1e+73) {
		tmp = a * b;
	} else if ((a * b) <= 7.2e+23) {
		tmp = z * t;
	} else {
		tmp = a * b;
	}
	return tmp;
}
def code(x, y, z, t, a, b):
	tmp = 0
	if (a * b) <= -3.1e+73:
		tmp = a * b
	elif (a * b) <= 7.2e+23:
		tmp = z * t
	else:
		tmp = a * b
	return tmp
function code(x, y, z, t, a, b)
	tmp = 0.0
	if (Float64(a * b) <= -3.1e+73)
		tmp = Float64(a * b);
	elseif (Float64(a * b) <= 7.2e+23)
		tmp = Float64(z * t);
	else
		tmp = Float64(a * b);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b)
	tmp = 0.0;
	if ((a * b) <= -3.1e+73)
		tmp = a * b;
	elseif ((a * b) <= 7.2e+23)
		tmp = z * t;
	else
		tmp = a * b;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_] := If[LessEqual[N[(a * b), $MachinePrecision], -3.1e+73], N[(a * b), $MachinePrecision], If[LessEqual[N[(a * b), $MachinePrecision], 7.2e+23], N[(z * t), $MachinePrecision], N[(a * b), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;a \cdot b \leq -3.1 \cdot 10^{+73}:\\
\;\;\;\;a \cdot b\\

\mathbf{elif}\;a \cdot b \leq 7.2 \cdot 10^{+23}:\\
\;\;\;\;z \cdot t\\

\mathbf{else}:\\
\;\;\;\;a \cdot b\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 a b) < -3.1e73 or 7.1999999999999997e23 < (*.f64 a b)

    1. Initial program 94.8%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in a around inf 69.0%

      \[\leadsto \color{blue}{a \cdot b} \]

    if -3.1e73 < (*.f64 a b) < 7.1999999999999997e23

    1. Initial program 98.7%

      \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
    2. Taylor expanded in z around inf 48.5%

      \[\leadsto \color{blue}{t \cdot z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification56.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \cdot b \leq -3.1 \cdot 10^{+73}:\\ \;\;\;\;a \cdot b\\ \mathbf{elif}\;a \cdot b \leq 7.2 \cdot 10^{+23}:\\ \;\;\;\;z \cdot t\\ \mathbf{else}:\\ \;\;\;\;a \cdot b\\ \end{array} \]

Alternative 10: 35.5% accurate, 3.7× speedup?

\[\begin{array}{l} \\ a \cdot b \end{array} \]
(FPCore (x y z t a b) :precision binary64 (* a b))
double code(double x, double y, double z, double t, double a, double b) {
	return a * b;
}
real(8) function code(x, y, z, t, a, b)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = a * b
end function
public static double code(double x, double y, double z, double t, double a, double b) {
	return a * b;
}
def code(x, y, z, t, a, b):
	return a * b
function code(x, y, z, t, a, b)
	return Float64(a * b)
end
function tmp = code(x, y, z, t, a, b)
	tmp = a * b;
end
code[x_, y_, z_, t_, a_, b_] := N[(a * b), $MachinePrecision]
\begin{array}{l}

\\
a \cdot b
\end{array}
Derivation
  1. Initial program 97.3%

    \[\left(x \cdot y + z \cdot t\right) + a \cdot b \]
  2. Taylor expanded in a around inf 34.5%

    \[\leadsto \color{blue}{a \cdot b} \]
  3. Final simplification34.5%

    \[\leadsto a \cdot b \]

Reproduce

?
herbie shell --seed 2023275 
(FPCore (x y z t a b)
  :name "Linear.V3:$cdot from linear-1.19.1.3, B"
  :precision binary64
  (+ (+ (* x y) (* z t)) (* a b)))