Diagrams.Solve.Polynomial:quartForm from diagrams-solve-0.1, B

Percentage Accurate: 100.0% → 100.0%
Time: 5.4s
Alternatives: 8
Speedup: 1.2×

Specification

?
\[\begin{array}{l} \\ \left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (- (* (/ 1.0 8.0) x) (/ (* y z) 2.0)) t))
double code(double x, double y, double z, double t) {
	return (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (((1.0d0 / 8.0d0) * x) - ((y * z) / 2.0d0)) + t
end function
public static double code(double x, double y, double z, double t) {
	return (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t;
}
def code(x, y, z, t):
	return (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t
function code(x, y, z, t)
	return Float64(Float64(Float64(Float64(1.0 / 8.0) * x) - Float64(Float64(y * z) / 2.0)) + t)
end
function tmp = code(x, y, z, t)
	tmp = (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t;
end
code[x_, y_, z_, t_] := N[(N[(N[(N[(1.0 / 8.0), $MachinePrecision] * x), $MachinePrecision] - N[(N[(y * z), $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision] + t), $MachinePrecision]
\begin{array}{l}

\\
\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (+ (- (* (/ 1.0 8.0) x) (/ (* y z) 2.0)) t))
double code(double x, double y, double z, double t) {
	return (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (((1.0d0 / 8.0d0) * x) - ((y * z) / 2.0d0)) + t
end function
public static double code(double x, double y, double z, double t) {
	return (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t;
}
def code(x, y, z, t):
	return (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t
function code(x, y, z, t)
	return Float64(Float64(Float64(Float64(1.0 / 8.0) * x) - Float64(Float64(y * z) / 2.0)) + t)
end
function tmp = code(x, y, z, t)
	tmp = (((1.0 / 8.0) * x) - ((y * z) / 2.0)) + t;
end
code[x_, y_, z_, t_] := N[(N[(N[(N[(1.0 / 8.0), $MachinePrecision] * x), $MachinePrecision] - N[(N[(y * z), $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision] + t), $MachinePrecision]
\begin{array}{l}

\\
\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t
\end{array}

Alternative 1: 100.0% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{y}{-2}, z, t\right)\right) \end{array} \]
(FPCore (x y z t) :precision binary64 (fma 0.125 x (fma (/ y -2.0) z t)))
double code(double x, double y, double z, double t) {
	return fma(0.125, x, fma((y / -2.0), z, t));
}
function code(x, y, z, t)
	return fma(0.125, x, fma(Float64(y / -2.0), z, t))
end
code[x_, y_, z_, t_] := N[(0.125 * x + N[(N[(y / -2.0), $MachinePrecision] * z + t), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{y}{-2}, z, t\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
  2. Step-by-step derivation
    1. sub-neg100.0%

      \[\leadsto \color{blue}{\left(\frac{1}{8} \cdot x + \left(-\frac{y \cdot z}{2}\right)\right)} + t \]
    2. associate-+l+100.0%

      \[\leadsto \color{blue}{\frac{1}{8} \cdot x + \left(\left(-\frac{y \cdot z}{2}\right) + t\right)} \]
    3. fma-def100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(\frac{1}{8}, x, \left(-\frac{y \cdot z}{2}\right) + t\right)} \]
    4. metadata-eval100.0%

      \[\leadsto \mathsf{fma}\left(\color{blue}{0.125}, x, \left(-\frac{y \cdot z}{2}\right) + t\right) \]
    5. distribute-frac-neg100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \color{blue}{\frac{-y \cdot z}{2}} + t\right) \]
    6. distribute-lft-neg-out100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \frac{\color{blue}{\left(-y\right) \cdot z}}{2} + t\right) \]
    7. associate-*l/100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \color{blue}{\frac{-y}{2} \cdot z} + t\right) \]
    8. fma-def100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \color{blue}{\mathsf{fma}\left(\frac{-y}{2}, z, t\right)}\right) \]
    9. neg-mul-1100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{\color{blue}{-1 \cdot y}}{2}, z, t\right)\right) \]
    10. *-commutative100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{\color{blue}{y \cdot -1}}{2}, z, t\right)\right) \]
    11. associate-/l*100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\color{blue}{\frac{y}{\frac{2}{-1}}}, z, t\right)\right) \]
    12. metadata-eval100.0%

      \[\leadsto \mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{y}{\color{blue}{-2}}, z, t\right)\right) \]
  3. Simplified100.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{y}{-2}, z, t\right)\right)} \]
  4. Final simplification100.0%

    \[\leadsto \mathsf{fma}\left(0.125, x, \mathsf{fma}\left(\frac{y}{-2}, z, t\right)\right) \]

Alternative 2: 55.0% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(y \cdot z\right) \cdot -0.5\\ \mathbf{if}\;y \cdot z \leq -3.8 \cdot 10^{+149}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;y \cdot z \leq -1 \cdot 10^{+60}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;y \cdot z \leq -106000:\\ \;\;\;\;t_1\\ \mathbf{elif}\;y \cdot z \leq -6 \cdot 10^{-96}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;y \cdot z \leq 1.1 \cdot 10^{-256}:\\ \;\;\;\;t\\ \mathbf{elif}\;y \cdot z \leq 1.2 \cdot 10^{-154}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;y \cdot z \leq 7.6 \cdot 10^{+119}:\\ \;\;\;\;t\\ \mathbf{else}:\\ \;\;\;\;t_1\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* (* y z) -0.5)))
   (if (<= (* y z) -3.8e+149)
     t_1
     (if (<= (* y z) -1e+60)
       (* 0.125 x)
       (if (<= (* y z) -106000.0)
         t_1
         (if (<= (* y z) -6e-96)
           (* 0.125 x)
           (if (<= (* y z) 1.1e-256)
             t
             (if (<= (* y z) 1.2e-154)
               (* 0.125 x)
               (if (<= (* y z) 7.6e+119) t t_1)))))))))
double code(double x, double y, double z, double t) {
	double t_1 = (y * z) * -0.5;
	double tmp;
	if ((y * z) <= -3.8e+149) {
		tmp = t_1;
	} else if ((y * z) <= -1e+60) {
		tmp = 0.125 * x;
	} else if ((y * z) <= -106000.0) {
		tmp = t_1;
	} else if ((y * z) <= -6e-96) {
		tmp = 0.125 * x;
	} else if ((y * z) <= 1.1e-256) {
		tmp = t;
	} else if ((y * z) <= 1.2e-154) {
		tmp = 0.125 * x;
	} else if ((y * z) <= 7.6e+119) {
		tmp = t;
	} else {
		tmp = t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = (y * z) * (-0.5d0)
    if ((y * z) <= (-3.8d+149)) then
        tmp = t_1
    else if ((y * z) <= (-1d+60)) then
        tmp = 0.125d0 * x
    else if ((y * z) <= (-106000.0d0)) then
        tmp = t_1
    else if ((y * z) <= (-6d-96)) then
        tmp = 0.125d0 * x
    else if ((y * z) <= 1.1d-256) then
        tmp = t
    else if ((y * z) <= 1.2d-154) then
        tmp = 0.125d0 * x
    else if ((y * z) <= 7.6d+119) then
        tmp = t
    else
        tmp = t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = (y * z) * -0.5;
	double tmp;
	if ((y * z) <= -3.8e+149) {
		tmp = t_1;
	} else if ((y * z) <= -1e+60) {
		tmp = 0.125 * x;
	} else if ((y * z) <= -106000.0) {
		tmp = t_1;
	} else if ((y * z) <= -6e-96) {
		tmp = 0.125 * x;
	} else if ((y * z) <= 1.1e-256) {
		tmp = t;
	} else if ((y * z) <= 1.2e-154) {
		tmp = 0.125 * x;
	} else if ((y * z) <= 7.6e+119) {
		tmp = t;
	} else {
		tmp = t_1;
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = (y * z) * -0.5
	tmp = 0
	if (y * z) <= -3.8e+149:
		tmp = t_1
	elif (y * z) <= -1e+60:
		tmp = 0.125 * x
	elif (y * z) <= -106000.0:
		tmp = t_1
	elif (y * z) <= -6e-96:
		tmp = 0.125 * x
	elif (y * z) <= 1.1e-256:
		tmp = t
	elif (y * z) <= 1.2e-154:
		tmp = 0.125 * x
	elif (y * z) <= 7.6e+119:
		tmp = t
	else:
		tmp = t_1
	return tmp
function code(x, y, z, t)
	t_1 = Float64(Float64(y * z) * -0.5)
	tmp = 0.0
	if (Float64(y * z) <= -3.8e+149)
		tmp = t_1;
	elseif (Float64(y * z) <= -1e+60)
		tmp = Float64(0.125 * x);
	elseif (Float64(y * z) <= -106000.0)
		tmp = t_1;
	elseif (Float64(y * z) <= -6e-96)
		tmp = Float64(0.125 * x);
	elseif (Float64(y * z) <= 1.1e-256)
		tmp = t;
	elseif (Float64(y * z) <= 1.2e-154)
		tmp = Float64(0.125 * x);
	elseif (Float64(y * z) <= 7.6e+119)
		tmp = t;
	else
		tmp = t_1;
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = (y * z) * -0.5;
	tmp = 0.0;
	if ((y * z) <= -3.8e+149)
		tmp = t_1;
	elseif ((y * z) <= -1e+60)
		tmp = 0.125 * x;
	elseif ((y * z) <= -106000.0)
		tmp = t_1;
	elseif ((y * z) <= -6e-96)
		tmp = 0.125 * x;
	elseif ((y * z) <= 1.1e-256)
		tmp = t;
	elseif ((y * z) <= 1.2e-154)
		tmp = 0.125 * x;
	elseif ((y * z) <= 7.6e+119)
		tmp = t;
	else
		tmp = t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y * z), $MachinePrecision] * -0.5), $MachinePrecision]}, If[LessEqual[N[(y * z), $MachinePrecision], -3.8e+149], t$95$1, If[LessEqual[N[(y * z), $MachinePrecision], -1e+60], N[(0.125 * x), $MachinePrecision], If[LessEqual[N[(y * z), $MachinePrecision], -106000.0], t$95$1, If[LessEqual[N[(y * z), $MachinePrecision], -6e-96], N[(0.125 * x), $MachinePrecision], If[LessEqual[N[(y * z), $MachinePrecision], 1.1e-256], t, If[LessEqual[N[(y * z), $MachinePrecision], 1.2e-154], N[(0.125 * x), $MachinePrecision], If[LessEqual[N[(y * z), $MachinePrecision], 7.6e+119], t, t$95$1]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(y \cdot z\right) \cdot -0.5\\
\mathbf{if}\;y \cdot z \leq -3.8 \cdot 10^{+149}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;y \cdot z \leq -1 \cdot 10^{+60}:\\
\;\;\;\;0.125 \cdot x\\

\mathbf{elif}\;y \cdot z \leq -106000:\\
\;\;\;\;t_1\\

\mathbf{elif}\;y \cdot z \leq -6 \cdot 10^{-96}:\\
\;\;\;\;0.125 \cdot x\\

\mathbf{elif}\;y \cdot z \leq 1.1 \cdot 10^{-256}:\\
\;\;\;\;t\\

\mathbf{elif}\;y \cdot z \leq 1.2 \cdot 10^{-154}:\\
\;\;\;\;0.125 \cdot x\\

\mathbf{elif}\;y \cdot z \leq 7.6 \cdot 10^{+119}:\\
\;\;\;\;t\\

\mathbf{else}:\\
\;\;\;\;t_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (*.f64 y z) < -3.8000000000000001e149 or -9.9999999999999995e59 < (*.f64 y z) < -106000 or 7.59999999999999979e119 < (*.f64 y z)

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in y around inf 80.1%

      \[\leadsto \color{blue}{-0.5 \cdot \left(y \cdot z\right)} \]
    3. Step-by-step derivation
      1. *-commutative80.1%

        \[\leadsto \color{blue}{\left(y \cdot z\right) \cdot -0.5} \]
    4. Simplified80.1%

      \[\leadsto \color{blue}{\left(y \cdot z\right) \cdot -0.5} \]

    if -3.8000000000000001e149 < (*.f64 y z) < -9.9999999999999995e59 or -106000 < (*.f64 y z) < -6e-96 or 1.10000000000000005e-256 < (*.f64 y z) < 1.19999999999999993e-154

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in x around inf 64.1%

      \[\leadsto \color{blue}{0.125 \cdot x} \]

    if -6e-96 < (*.f64 y z) < 1.10000000000000005e-256 or 1.19999999999999993e-154 < (*.f64 y z) < 7.59999999999999979e119

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in t around inf 58.1%

      \[\leadsto \color{blue}{t} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification66.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z \leq -3.8 \cdot 10^{+149}:\\ \;\;\;\;\left(y \cdot z\right) \cdot -0.5\\ \mathbf{elif}\;y \cdot z \leq -1 \cdot 10^{+60}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;y \cdot z \leq -106000:\\ \;\;\;\;\left(y \cdot z\right) \cdot -0.5\\ \mathbf{elif}\;y \cdot z \leq -6 \cdot 10^{-96}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;y \cdot z \leq 1.1 \cdot 10^{-256}:\\ \;\;\;\;t\\ \mathbf{elif}\;y \cdot z \leq 1.2 \cdot 10^{-154}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;y \cdot z \leq 7.6 \cdot 10^{+119}:\\ \;\;\;\;t\\ \mathbf{else}:\\ \;\;\;\;\left(y \cdot z\right) \cdot -0.5\\ \end{array} \]

Alternative 3: 85.6% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot z \leq -3.9 \cdot 10^{+149} \lor \neg \left(y \cdot z \leq -1.8 \cdot 10^{+61} \lor \neg \left(y \cdot z \leq -102000\right) \land y \cdot z \leq 1.85 \cdot 10^{+130}\right):\\ \;\;\;\;t - \left(y \cdot z\right) \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;t + 0.125 \cdot x\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (or (<= (* y z) -3.9e+149)
         (not
          (or (<= (* y z) -1.8e+61)
              (and (not (<= (* y z) -102000.0)) (<= (* y z) 1.85e+130)))))
   (- t (* (* y z) 0.5))
   (+ t (* 0.125 x))))
double code(double x, double y, double z, double t) {
	double tmp;
	if (((y * z) <= -3.9e+149) || !(((y * z) <= -1.8e+61) || (!((y * z) <= -102000.0) && ((y * z) <= 1.85e+130)))) {
		tmp = t - ((y * z) * 0.5);
	} else {
		tmp = t + (0.125 * x);
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if (((y * z) <= (-3.9d+149)) .or. (.not. ((y * z) <= (-1.8d+61)) .or. (.not. ((y * z) <= (-102000.0d0))) .and. ((y * z) <= 1.85d+130))) then
        tmp = t - ((y * z) * 0.5d0)
    else
        tmp = t + (0.125d0 * x)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if (((y * z) <= -3.9e+149) || !(((y * z) <= -1.8e+61) || (!((y * z) <= -102000.0) && ((y * z) <= 1.85e+130)))) {
		tmp = t - ((y * z) * 0.5);
	} else {
		tmp = t + (0.125 * x);
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if ((y * z) <= -3.9e+149) or not (((y * z) <= -1.8e+61) or (not ((y * z) <= -102000.0) and ((y * z) <= 1.85e+130))):
		tmp = t - ((y * z) * 0.5)
	else:
		tmp = t + (0.125 * x)
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if ((Float64(y * z) <= -3.9e+149) || !((Float64(y * z) <= -1.8e+61) || (!(Float64(y * z) <= -102000.0) && (Float64(y * z) <= 1.85e+130))))
		tmp = Float64(t - Float64(Float64(y * z) * 0.5));
	else
		tmp = Float64(t + Float64(0.125 * x));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if (((y * z) <= -3.9e+149) || ~((((y * z) <= -1.8e+61) || (~(((y * z) <= -102000.0)) && ((y * z) <= 1.85e+130)))))
		tmp = t - ((y * z) * 0.5);
	else
		tmp = t + (0.125 * x);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[Or[LessEqual[N[(y * z), $MachinePrecision], -3.9e+149], N[Not[Or[LessEqual[N[(y * z), $MachinePrecision], -1.8e+61], And[N[Not[LessEqual[N[(y * z), $MachinePrecision], -102000.0]], $MachinePrecision], LessEqual[N[(y * z), $MachinePrecision], 1.85e+130]]]], $MachinePrecision]], N[(t - N[(N[(y * z), $MachinePrecision] * 0.5), $MachinePrecision]), $MachinePrecision], N[(t + N[(0.125 * x), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \cdot z \leq -3.9 \cdot 10^{+149} \lor \neg \left(y \cdot z \leq -1.8 \cdot 10^{+61} \lor \neg \left(y \cdot z \leq -102000\right) \land y \cdot z \leq 1.85 \cdot 10^{+130}\right):\\
\;\;\;\;t - \left(y \cdot z\right) \cdot 0.5\\

\mathbf{else}:\\
\;\;\;\;t + 0.125 \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 y z) < -3.8999999999999999e149 or -1.80000000000000005e61 < (*.f64 y z) < -102000 or 1.8500000000000001e130 < (*.f64 y z)

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in x around 0 94.9%

      \[\leadsto \color{blue}{t - 0.5 \cdot \left(y \cdot z\right)} \]

    if -3.8999999999999999e149 < (*.f64 y z) < -1.80000000000000005e61 or -102000 < (*.f64 y z) < 1.8500000000000001e130

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in y around 0 87.9%

      \[\leadsto \color{blue}{0.125 \cdot x + t} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification90.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z \leq -3.9 \cdot 10^{+149} \lor \neg \left(y \cdot z \leq -1.8 \cdot 10^{+61} \lor \neg \left(y \cdot z \leq -102000\right) \land y \cdot z \leq 1.85 \cdot 10^{+130}\right):\\ \;\;\;\;t - \left(y \cdot z\right) \cdot 0.5\\ \mathbf{else}:\\ \;\;\;\;t + 0.125 \cdot x\\ \end{array} \]

Alternative 4: 82.6% accurate, 0.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;y \cdot z \leq -9.5 \cdot 10^{+155} \lor \neg \left(y \cdot z \leq -1.95 \cdot 10^{+27}\right) \land \left(y \cdot z \leq -160000 \lor \neg \left(y \cdot z \leq 1.32 \cdot 10^{+178}\right)\right):\\ \;\;\;\;\left(y \cdot z\right) \cdot -0.5\\ \mathbf{else}:\\ \;\;\;\;t + 0.125 \cdot x\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (or (<= (* y z) -9.5e+155)
         (and (not (<= (* y z) -1.95e+27))
              (or (<= (* y z) -160000.0) (not (<= (* y z) 1.32e+178)))))
   (* (* y z) -0.5)
   (+ t (* 0.125 x))))
double code(double x, double y, double z, double t) {
	double tmp;
	if (((y * z) <= -9.5e+155) || (!((y * z) <= -1.95e+27) && (((y * z) <= -160000.0) || !((y * z) <= 1.32e+178)))) {
		tmp = (y * z) * -0.5;
	} else {
		tmp = t + (0.125 * x);
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if (((y * z) <= (-9.5d+155)) .or. (.not. ((y * z) <= (-1.95d+27))) .and. ((y * z) <= (-160000.0d0)) .or. (.not. ((y * z) <= 1.32d+178))) then
        tmp = (y * z) * (-0.5d0)
    else
        tmp = t + (0.125d0 * x)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if (((y * z) <= -9.5e+155) || (!((y * z) <= -1.95e+27) && (((y * z) <= -160000.0) || !((y * z) <= 1.32e+178)))) {
		tmp = (y * z) * -0.5;
	} else {
		tmp = t + (0.125 * x);
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if ((y * z) <= -9.5e+155) or (not ((y * z) <= -1.95e+27) and (((y * z) <= -160000.0) or not ((y * z) <= 1.32e+178))):
		tmp = (y * z) * -0.5
	else:
		tmp = t + (0.125 * x)
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if ((Float64(y * z) <= -9.5e+155) || (!(Float64(y * z) <= -1.95e+27) && ((Float64(y * z) <= -160000.0) || !(Float64(y * z) <= 1.32e+178))))
		tmp = Float64(Float64(y * z) * -0.5);
	else
		tmp = Float64(t + Float64(0.125 * x));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if (((y * z) <= -9.5e+155) || (~(((y * z) <= -1.95e+27)) && (((y * z) <= -160000.0) || ~(((y * z) <= 1.32e+178)))))
		tmp = (y * z) * -0.5;
	else
		tmp = t + (0.125 * x);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[Or[LessEqual[N[(y * z), $MachinePrecision], -9.5e+155], And[N[Not[LessEqual[N[(y * z), $MachinePrecision], -1.95e+27]], $MachinePrecision], Or[LessEqual[N[(y * z), $MachinePrecision], -160000.0], N[Not[LessEqual[N[(y * z), $MachinePrecision], 1.32e+178]], $MachinePrecision]]]], N[(N[(y * z), $MachinePrecision] * -0.5), $MachinePrecision], N[(t + N[(0.125 * x), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;y \cdot z \leq -9.5 \cdot 10^{+155} \lor \neg \left(y \cdot z \leq -1.95 \cdot 10^{+27}\right) \land \left(y \cdot z \leq -160000 \lor \neg \left(y \cdot z \leq 1.32 \cdot 10^{+178}\right)\right):\\
\;\;\;\;\left(y \cdot z\right) \cdot -0.5\\

\mathbf{else}:\\
\;\;\;\;t + 0.125 \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 y z) < -9.5000000000000006e155 or -1.9499999999999999e27 < (*.f64 y z) < -1.6e5 or 1.3200000000000001e178 < (*.f64 y z)

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in y around inf 90.7%

      \[\leadsto \color{blue}{-0.5 \cdot \left(y \cdot z\right)} \]
    3. Step-by-step derivation
      1. *-commutative90.7%

        \[\leadsto \color{blue}{\left(y \cdot z\right) \cdot -0.5} \]
    4. Simplified90.7%

      \[\leadsto \color{blue}{\left(y \cdot z\right) \cdot -0.5} \]

    if -9.5000000000000006e155 < (*.f64 y z) < -1.9499999999999999e27 or -1.6e5 < (*.f64 y z) < 1.3200000000000001e178

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in y around 0 86.4%

      \[\leadsto \color{blue}{0.125 \cdot x + t} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification87.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;y \cdot z \leq -9.5 \cdot 10^{+155} \lor \neg \left(y \cdot z \leq -1.95 \cdot 10^{+27}\right) \land \left(y \cdot z \leq -160000 \lor \neg \left(y \cdot z \leq 1.32 \cdot 10^{+178}\right)\right):\\ \;\;\;\;\left(y \cdot z\right) \cdot -0.5\\ \mathbf{else}:\\ \;\;\;\;t + 0.125 \cdot x\\ \end{array} \]

Alternative 5: 84.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \left(y \cdot z\right) \cdot 0.5\\ \mathbf{if}\;x \leq -3.8 \cdot 10^{+167}:\\ \;\;\;\;0.125 \cdot x - t_1\\ \mathbf{elif}\;x \leq -4 \cdot 10^{+72} \lor \neg \left(x \leq 9500000000\right):\\ \;\;\;\;t + 0.125 \cdot x\\ \mathbf{else}:\\ \;\;\;\;t - t_1\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* (* y z) 0.5)))
   (if (<= x -3.8e+167)
     (- (* 0.125 x) t_1)
     (if (or (<= x -4e+72) (not (<= x 9500000000.0)))
       (+ t (* 0.125 x))
       (- t t_1)))))
double code(double x, double y, double z, double t) {
	double t_1 = (y * z) * 0.5;
	double tmp;
	if (x <= -3.8e+167) {
		tmp = (0.125 * x) - t_1;
	} else if ((x <= -4e+72) || !(x <= 9500000000.0)) {
		tmp = t + (0.125 * x);
	} else {
		tmp = t - t_1;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = (y * z) * 0.5d0
    if (x <= (-3.8d+167)) then
        tmp = (0.125d0 * x) - t_1
    else if ((x <= (-4d+72)) .or. (.not. (x <= 9500000000.0d0))) then
        tmp = t + (0.125d0 * x)
    else
        tmp = t - t_1
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = (y * z) * 0.5;
	double tmp;
	if (x <= -3.8e+167) {
		tmp = (0.125 * x) - t_1;
	} else if ((x <= -4e+72) || !(x <= 9500000000.0)) {
		tmp = t + (0.125 * x);
	} else {
		tmp = t - t_1;
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = (y * z) * 0.5
	tmp = 0
	if x <= -3.8e+167:
		tmp = (0.125 * x) - t_1
	elif (x <= -4e+72) or not (x <= 9500000000.0):
		tmp = t + (0.125 * x)
	else:
		tmp = t - t_1
	return tmp
function code(x, y, z, t)
	t_1 = Float64(Float64(y * z) * 0.5)
	tmp = 0.0
	if (x <= -3.8e+167)
		tmp = Float64(Float64(0.125 * x) - t_1);
	elseif ((x <= -4e+72) || !(x <= 9500000000.0))
		tmp = Float64(t + Float64(0.125 * x));
	else
		tmp = Float64(t - t_1);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = (y * z) * 0.5;
	tmp = 0.0;
	if (x <= -3.8e+167)
		tmp = (0.125 * x) - t_1;
	elseif ((x <= -4e+72) || ~((x <= 9500000000.0)))
		tmp = t + (0.125 * x);
	else
		tmp = t - t_1;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y * z), $MachinePrecision] * 0.5), $MachinePrecision]}, If[LessEqual[x, -3.8e+167], N[(N[(0.125 * x), $MachinePrecision] - t$95$1), $MachinePrecision], If[Or[LessEqual[x, -4e+72], N[Not[LessEqual[x, 9500000000.0]], $MachinePrecision]], N[(t + N[(0.125 * x), $MachinePrecision]), $MachinePrecision], N[(t - t$95$1), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \left(y \cdot z\right) \cdot 0.5\\
\mathbf{if}\;x \leq -3.8 \cdot 10^{+167}:\\
\;\;\;\;0.125 \cdot x - t_1\\

\mathbf{elif}\;x \leq -4 \cdot 10^{+72} \lor \neg \left(x \leq 9500000000\right):\\
\;\;\;\;t + 0.125 \cdot x\\

\mathbf{else}:\\
\;\;\;\;t - t_1\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if x < -3.79999999999999994e167

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in t around 0 86.0%

      \[\leadsto \color{blue}{0.125 \cdot x - 0.5 \cdot \left(y \cdot z\right)} \]

    if -3.79999999999999994e167 < x < -3.99999999999999978e72 or 9.5e9 < x

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in y around 0 88.2%

      \[\leadsto \color{blue}{0.125 \cdot x + t} \]

    if -3.99999999999999978e72 < x < 9.5e9

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in x around 0 90.3%

      \[\leadsto \color{blue}{t - 0.5 \cdot \left(y \cdot z\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification89.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.8 \cdot 10^{+167}:\\ \;\;\;\;0.125 \cdot x - \left(y \cdot z\right) \cdot 0.5\\ \mathbf{elif}\;x \leq -4 \cdot 10^{+72} \lor \neg \left(x \leq 9500000000\right):\\ \;\;\;\;t + 0.125 \cdot x\\ \mathbf{else}:\\ \;\;\;\;t - \left(y \cdot z\right) \cdot 0.5\\ \end{array} \]

Alternative 6: 100.0% accurate, 1.2× speedup?

\[\begin{array}{l} \\ t + \left(0.125 \cdot x - \frac{y \cdot z}{2}\right) \end{array} \]
(FPCore (x y z t) :precision binary64 (+ t (- (* 0.125 x) (/ (* y z) 2.0))))
double code(double x, double y, double z, double t) {
	return t + ((0.125 * x) - ((y * z) / 2.0));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = t + ((0.125d0 * x) - ((y * z) / 2.0d0))
end function
public static double code(double x, double y, double z, double t) {
	return t + ((0.125 * x) - ((y * z) / 2.0));
}
def code(x, y, z, t):
	return t + ((0.125 * x) - ((y * z) / 2.0))
function code(x, y, z, t)
	return Float64(t + Float64(Float64(0.125 * x) - Float64(Float64(y * z) / 2.0)))
end
function tmp = code(x, y, z, t)
	tmp = t + ((0.125 * x) - ((y * z) / 2.0));
end
code[x_, y_, z_, t_] := N[(t + N[(N[(0.125 * x), $MachinePrecision] - N[(N[(y * z), $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
t + \left(0.125 \cdot x - \frac{y \cdot z}{2}\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
  2. Final simplification100.0%

    \[\leadsto t + \left(0.125 \cdot x - \frac{y \cdot z}{2}\right) \]

Alternative 7: 51.3% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq -4.7 \cdot 10^{+40}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;x \leq 1.8 \cdot 10^{+118}:\\ \;\;\;\;t\\ \mathbf{else}:\\ \;\;\;\;0.125 \cdot x\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= x -4.7e+40) (* 0.125 x) (if (<= x 1.8e+118) t (* 0.125 x))))
double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= -4.7e+40) {
		tmp = 0.125 * x;
	} else if (x <= 1.8e+118) {
		tmp = t;
	} else {
		tmp = 0.125 * x;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if (x <= (-4.7d+40)) then
        tmp = 0.125d0 * x
    else if (x <= 1.8d+118) then
        tmp = t
    else
        tmp = 0.125d0 * x
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= -4.7e+40) {
		tmp = 0.125 * x;
	} else if (x <= 1.8e+118) {
		tmp = t;
	} else {
		tmp = 0.125 * x;
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if x <= -4.7e+40:
		tmp = 0.125 * x
	elif x <= 1.8e+118:
		tmp = t
	else:
		tmp = 0.125 * x
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (x <= -4.7e+40)
		tmp = Float64(0.125 * x);
	elseif (x <= 1.8e+118)
		tmp = t;
	else
		tmp = Float64(0.125 * x);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if (x <= -4.7e+40)
		tmp = 0.125 * x;
	elseif (x <= 1.8e+118)
		tmp = t;
	else
		tmp = 0.125 * x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[x, -4.7e+40], N[(0.125 * x), $MachinePrecision], If[LessEqual[x, 1.8e+118], t, N[(0.125 * x), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq -4.7 \cdot 10^{+40}:\\
\;\;\;\;0.125 \cdot x\\

\mathbf{elif}\;x \leq 1.8 \cdot 10^{+118}:\\
\;\;\;\;t\\

\mathbf{else}:\\
\;\;\;\;0.125 \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -4.7000000000000004e40 or 1.8e118 < x

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in x around inf 65.1%

      \[\leadsto \color{blue}{0.125 \cdot x} \]

    if -4.7000000000000004e40 < x < 1.8e118

    1. Initial program 100.0%

      \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
    2. Taylor expanded in t around inf 49.9%

      \[\leadsto \color{blue}{t} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification55.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -4.7 \cdot 10^{+40}:\\ \;\;\;\;0.125 \cdot x\\ \mathbf{elif}\;x \leq 1.8 \cdot 10^{+118}:\\ \;\;\;\;t\\ \mathbf{else}:\\ \;\;\;\;0.125 \cdot x\\ \end{array} \]

Alternative 8: 34.2% accurate, 13.0× speedup?

\[\begin{array}{l} \\ t \end{array} \]
(FPCore (x y z t) :precision binary64 t)
double code(double x, double y, double z, double t) {
	return t;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = t
end function
public static double code(double x, double y, double z, double t) {
	return t;
}
def code(x, y, z, t):
	return t
function code(x, y, z, t)
	return t
end
function tmp = code(x, y, z, t)
	tmp = t;
end
code[x_, y_, z_, t_] := t
\begin{array}{l}

\\
t
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{8} \cdot x - \frac{y \cdot z}{2}\right) + t \]
  2. Taylor expanded in t around inf 38.0%

    \[\leadsto \color{blue}{t} \]
  3. Final simplification38.0%

    \[\leadsto t \]

Developer target: 100.0% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \left(\frac{x}{8} + t\right) - \frac{z}{2} \cdot y \end{array} \]
(FPCore (x y z t) :precision binary64 (- (+ (/ x 8.0) t) (* (/ z 2.0) y)))
double code(double x, double y, double z, double t) {
	return ((x / 8.0) + t) - ((z / 2.0) * y);
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = ((x / 8.0d0) + t) - ((z / 2.0d0) * y)
end function
public static double code(double x, double y, double z, double t) {
	return ((x / 8.0) + t) - ((z / 2.0) * y);
}
def code(x, y, z, t):
	return ((x / 8.0) + t) - ((z / 2.0) * y)
function code(x, y, z, t)
	return Float64(Float64(Float64(x / 8.0) + t) - Float64(Float64(z / 2.0) * y))
end
function tmp = code(x, y, z, t)
	tmp = ((x / 8.0) + t) - ((z / 2.0) * y);
end
code[x_, y_, z_, t_] := N[(N[(N[(x / 8.0), $MachinePrecision] + t), $MachinePrecision] - N[(N[(z / 2.0), $MachinePrecision] * y), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(\frac{x}{8} + t\right) - \frac{z}{2} \cdot y
\end{array}

Reproduce

?
herbie shell --seed 2023274 
(FPCore (x y z t)
  :name "Diagrams.Solve.Polynomial:quartForm  from diagrams-solve-0.1, B"
  :precision binary64

  :herbie-target
  (- (+ (/ x 8.0) t) (* (/ z 2.0) y))

  (+ (- (* (/ 1.0 8.0) x) (/ (* y z) 2.0)) t))