Math FPCore C Java Python Julia MATLAB Wolfram TeX \[0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}
\]
↓
\[\begin{array}{l}
\mathbf{if}\;re \leq 2.6 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot \left(\mathsf{hypot}\left(re, im\right) - re\right)}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(im \cdot {re}^{-0.5}\right)\\
\end{array}
\]
(FPCore (re im)
:precision binary64
(* 0.5 (sqrt (* 2.0 (- (sqrt (+ (* re re) (* im im))) re))))) ↓
(FPCore (re im)
:precision binary64
(if (<= re 2.6e-39)
(* 0.5 (sqrt (* 2.0 (- (hypot re im) re))))
(* 0.5 (* im (pow re -0.5))))) double code(double re, double im) {
return 0.5 * sqrt((2.0 * (sqrt(((re * re) + (im * im))) - re)));
}
↓
double code(double re, double im) {
double tmp;
if (re <= 2.6e-39) {
tmp = 0.5 * sqrt((2.0 * (hypot(re, im) - re)));
} else {
tmp = 0.5 * (im * pow(re, -0.5));
}
return tmp;
}
public static double code(double re, double im) {
return 0.5 * Math.sqrt((2.0 * (Math.sqrt(((re * re) + (im * im))) - re)));
}
↓
public static double code(double re, double im) {
double tmp;
if (re <= 2.6e-39) {
tmp = 0.5 * Math.sqrt((2.0 * (Math.hypot(re, im) - re)));
} else {
tmp = 0.5 * (im * Math.pow(re, -0.5));
}
return tmp;
}
def code(re, im):
return 0.5 * math.sqrt((2.0 * (math.sqrt(((re * re) + (im * im))) - re)))
↓
def code(re, im):
tmp = 0
if re <= 2.6e-39:
tmp = 0.5 * math.sqrt((2.0 * (math.hypot(re, im) - re)))
else:
tmp = 0.5 * (im * math.pow(re, -0.5))
return tmp
function code(re, im)
return Float64(0.5 * sqrt(Float64(2.0 * Float64(sqrt(Float64(Float64(re * re) + Float64(im * im))) - re))))
end
↓
function code(re, im)
tmp = 0.0
if (re <= 2.6e-39)
tmp = Float64(0.5 * sqrt(Float64(2.0 * Float64(hypot(re, im) - re))));
else
tmp = Float64(0.5 * Float64(im * (re ^ -0.5)));
end
return tmp
end
function tmp = code(re, im)
tmp = 0.5 * sqrt((2.0 * (sqrt(((re * re) + (im * im))) - re)));
end
↓
function tmp_2 = code(re, im)
tmp = 0.0;
if (re <= 2.6e-39)
tmp = 0.5 * sqrt((2.0 * (hypot(re, im) - re)));
else
tmp = 0.5 * (im * (re ^ -0.5));
end
tmp_2 = tmp;
end
code[re_, im_] := N[(0.5 * N[Sqrt[N[(2.0 * N[(N[Sqrt[N[(N[(re * re), $MachinePrecision] + N[(im * im), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - re), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[re_, im_] := If[LessEqual[re, 2.6e-39], N[(0.5 * N[Sqrt[N[(2.0 * N[(N[Sqrt[re ^ 2 + im ^ 2], $MachinePrecision] - re), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(0.5 * N[(im * N[Power[re, -0.5], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
0.5 \cdot \sqrt{2 \cdot \left(\sqrt{re \cdot re + im \cdot im} - re\right)}
↓
\begin{array}{l}
\mathbf{if}\;re \leq 2.6 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot \left(\mathsf{hypot}\left(re, im\right) - re\right)}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(im \cdot {re}^{-0.5}\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 87.6% Cost 13444
\[\begin{array}{l}
\mathbf{if}\;re \leq 2.6 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot \left(\mathsf{hypot}\left(re, im\right) - re\right)}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(im \cdot {re}^{-0.5}\right)\\
\end{array}
\]
Alternative 2 Accuracy 76.6% Cost 7236
\[\begin{array}{l}
\mathbf{if}\;re \leq -43000000000000:\\
\;\;\;\;0.5 \cdot \sqrt{re \cdot -4 - \frac{im}{\frac{re}{im}}}\\
\mathbf{elif}\;re \leq 1.5 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot \left(im - re\right)}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(im \cdot {re}^{-0.5}\right)\\
\end{array}
\]
Alternative 3 Accuracy 76.6% Cost 7112
\[\begin{array}{l}
\mathbf{if}\;re \leq -2.9 \cdot 10^{+15}:\\
\;\;\;\;0.5 \cdot \sqrt{re \cdot -4}\\
\mathbf{elif}\;re \leq 1.85 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot \left(im - re\right)}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(im \cdot {re}^{-0.5}\right)\\
\end{array}
\]
Alternative 4 Accuracy 75.9% Cost 7048
\[\begin{array}{l}
\mathbf{if}\;re \leq -1.9 \cdot 10^{+15}:\\
\;\;\;\;0.5 \cdot \sqrt{re \cdot -4}\\
\mathbf{elif}\;re \leq 2.6 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot im}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \left(im \cdot {re}^{-0.5}\right)\\
\end{array}
\]
Alternative 5 Accuracy 75.9% Cost 6984
\[\begin{array}{l}
\mathbf{if}\;re \leq -22000000000000:\\
\;\;\;\;0.5 \cdot \sqrt{re \cdot -4}\\
\mathbf{elif}\;re \leq 2.4 \cdot 10^{-39}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot im}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \frac{im}{\sqrt{re}}\\
\end{array}
\]
Alternative 6 Accuracy 64.5% Cost 6852
\[\begin{array}{l}
\mathbf{if}\;re \leq -8.6 \cdot 10^{+15}:\\
\;\;\;\;0.5 \cdot \sqrt{re \cdot -4}\\
\mathbf{else}:\\
\;\;\;\;0.5 \cdot \sqrt{2 \cdot im}\\
\end{array}
\]
Alternative 7 Accuracy 53.0% Cost 6720
\[0.5 \cdot \sqrt{2 \cdot im}
\]