Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\left(3 \cdot \sqrt{x}\right) \cdot \left(\left(y + \frac{1}{x \cdot 9}\right) - 1\right)
\]
↓
\[\left(3 \cdot \sqrt{x}\right) \cdot \left(\left(y + \frac{1}{x \cdot 9}\right) + -1\right)
\]
(FPCore (x y)
:precision binary64
(* (* 3.0 (sqrt x)) (- (+ y (/ 1.0 (* x 9.0))) 1.0))) ↓
(FPCore (x y)
:precision binary64
(* (* 3.0 (sqrt x)) (+ (+ y (/ 1.0 (* x 9.0))) -1.0))) double code(double x, double y) {
return (3.0 * sqrt(x)) * ((y + (1.0 / (x * 9.0))) - 1.0);
}
↓
double code(double x, double y) {
return (3.0 * sqrt(x)) * ((y + (1.0 / (x * 9.0))) + -1.0);
}
real(8) function code(x, y)
real(8), intent (in) :: x
real(8), intent (in) :: y
code = (3.0d0 * sqrt(x)) * ((y + (1.0d0 / (x * 9.0d0))) - 1.0d0)
end function
↓
real(8) function code(x, y)
real(8), intent (in) :: x
real(8), intent (in) :: y
code = (3.0d0 * sqrt(x)) * ((y + (1.0d0 / (x * 9.0d0))) + (-1.0d0))
end function
public static double code(double x, double y) {
return (3.0 * Math.sqrt(x)) * ((y + (1.0 / (x * 9.0))) - 1.0);
}
↓
public static double code(double x, double y) {
return (3.0 * Math.sqrt(x)) * ((y + (1.0 / (x * 9.0))) + -1.0);
}
def code(x, y):
return (3.0 * math.sqrt(x)) * ((y + (1.0 / (x * 9.0))) - 1.0)
↓
def code(x, y):
return (3.0 * math.sqrt(x)) * ((y + (1.0 / (x * 9.0))) + -1.0)
function code(x, y)
return Float64(Float64(3.0 * sqrt(x)) * Float64(Float64(y + Float64(1.0 / Float64(x * 9.0))) - 1.0))
end
↓
function code(x, y)
return Float64(Float64(3.0 * sqrt(x)) * Float64(Float64(y + Float64(1.0 / Float64(x * 9.0))) + -1.0))
end
function tmp = code(x, y)
tmp = (3.0 * sqrt(x)) * ((y + (1.0 / (x * 9.0))) - 1.0);
end
↓
function tmp = code(x, y)
tmp = (3.0 * sqrt(x)) * ((y + (1.0 / (x * 9.0))) + -1.0);
end
code[x_, y_] := N[(N[(3.0 * N[Sqrt[x], $MachinePrecision]), $MachinePrecision] * N[(N[(y + N[(1.0 / N[(x * 9.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_] := N[(N[(3.0 * N[Sqrt[x], $MachinePrecision]), $MachinePrecision] * N[(N[(y + N[(1.0 / N[(x * 9.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision]
\left(3 \cdot \sqrt{x}\right) \cdot \left(\left(y + \frac{1}{x \cdot 9}\right) - 1\right)
↓
\left(3 \cdot \sqrt{x}\right) \cdot \left(\left(y + \frac{1}{x \cdot 9}\right) + -1\right)
Alternatives Alternative 1 Accuracy 99.4% Cost 7232
\[\left(3 \cdot \sqrt{x}\right) \cdot \left(\left(y + \frac{1}{x \cdot 9}\right) + -1\right)
\]
Alternative 2 Accuracy 63.1% Cost 7382
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.8 \cdot 10^{-29}:\\
\;\;\;\;\sqrt{x} \cdot \frac{0.3333333333333333}{x}\\
\mathbf{elif}\;x \leq 6.5 \cdot 10^{+114} \lor \neg \left(x \leq 1.3 \cdot 10^{+140}\right) \land \left(x \leq 1.45 \cdot 10^{+158} \lor \neg \left(x \leq 1.46 \cdot 10^{+243}\right)\right):\\
\;\;\;\;3 \cdot \left(\sqrt{x} \cdot y\right)\\
\mathbf{else}:\\
\;\;\;\;\sqrt{x} \cdot -3\\
\end{array}
\]
Alternative 3 Accuracy 63.1% Cost 7381
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.7 \cdot 10^{-29}:\\
\;\;\;\;\sqrt{x} \cdot \frac{0.3333333333333333}{x}\\
\mathbf{elif}\;x \leq 4.25 \cdot 10^{+114}:\\
\;\;\;\;\left(3 \cdot \sqrt{x}\right) \cdot y\\
\mathbf{elif}\;x \leq 1.3 \cdot 10^{+140} \lor \neg \left(x \leq 7 \cdot 10^{+157}\right) \land x \leq 2 \cdot 10^{+243}:\\
\;\;\;\;\sqrt{x} \cdot -3\\
\mathbf{else}:\\
\;\;\;\;3 \cdot \left(\sqrt{x} \cdot y\right)\\
\end{array}
\]
Alternative 4 Accuracy 86.3% Cost 7112
\[\begin{array}{l}
\mathbf{if}\;y \leq -9 \cdot 10^{+23}:\\
\;\;\;\;3 \cdot \left(\sqrt{x} \cdot y\right)\\
\mathbf{elif}\;y \leq 7.2 \cdot 10^{+46}:\\
\;\;\;\;\sqrt{x} \cdot \left(\frac{0.3333333333333333}{x} + -3\right)\\
\mathbf{else}:\\
\;\;\;\;\left(3 \cdot \sqrt{x}\right) \cdot y\\
\end{array}
\]
Alternative 5 Accuracy 87.0% Cost 7108
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.25 \cdot 10^{-5}:\\
\;\;\;\;\sqrt{x} \cdot \left(\frac{1}{3 \cdot x} - 3\right)\\
\mathbf{else}:\\
\;\;\;\;\left(3 \cdot \sqrt{x}\right) \cdot \left(y + -1\right)\\
\end{array}
\]
Alternative 6 Accuracy 99.4% Cost 7104
\[3 \cdot \left(\sqrt{x} \cdot \left(y + \left(\frac{0.1111111111111111}{x} + -1\right)\right)\right)
\]
Alternative 7 Accuracy 99.4% Cost 7104
\[\sqrt{x} \cdot \left(3 \cdot y + \left(\frac{0.3333333333333333}{x} + -3\right)\right)
\]
Alternative 8 Accuracy 99.4% Cost 7104
\[\left(3 \cdot \sqrt{x}\right) \cdot \left(\frac{0.1111111111111111}{x} + \left(y + -1\right)\right)
\]
Alternative 9 Accuracy 60.3% Cost 6985
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.5 \cdot 10^{-7} \lor \neg \left(y \leq 1\right):\\
\;\;\;\;3 \cdot \left(\sqrt{x} \cdot y\right)\\
\mathbf{else}:\\
\;\;\;\;\sqrt{x} \cdot -3\\
\end{array}
\]
Alternative 10 Accuracy 87.0% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.35 \cdot 10^{-5}:\\
\;\;\;\;\sqrt{x} \cdot \left(\frac{0.3333333333333333}{x} + -3\right)\\
\mathbf{else}:\\
\;\;\;\;\sqrt{x} \cdot \left(3 \cdot y - 3\right)\\
\end{array}
\]
Alternative 11 Accuracy 87.0% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;x \leq 1.3 \cdot 10^{-5}:\\
\;\;\;\;\sqrt{x} \cdot \left(\frac{0.3333333333333333}{x} + -3\right)\\
\mathbf{else}:\\
\;\;\;\;\left(3 \cdot \sqrt{x}\right) \cdot \left(y + -1\right)\\
\end{array}
\]
Alternative 12 Accuracy 3.3% Cost 6592
\[\sqrt{x \cdot 9}
\]
Alternative 13 Accuracy 3.3% Cost 6592
\[3 \cdot \sqrt{x}
\]
Alternative 14 Accuracy 25.8% Cost 6592
\[\sqrt{x} \cdot -3
\]