Quadratic roots, narrow range

Percentage Accurate: 55.3% → 90.8%
Time: 12.2s
Alternatives: 7
Speedup: 29.0×

Specification

?
\[\left(\left(1.0536712127723509 \cdot 10^{-8} < a \land a < 94906265.62425156\right) \land \left(1.0536712127723509 \cdot 10^{-8} < b \land b < 94906265.62425156\right)\right) \land \left(1.0536712127723509 \cdot 10^{-8} < c \land c < 94906265.62425156\right)\]
\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 4.0 a) c)))) (* 2.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((4.0d0 * a) * c)))) / (2.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(4.0 * a) * c)))) / Float64(2.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(4.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 55.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (/ (+ (- b) (sqrt (- (* b b) (* (* 4.0 a) c)))) (* 2.0 a)))
double code(double a, double b, double c) {
	return (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
real(8) function code(a, b, c)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = (-b + sqrt(((b * b) - ((4.0d0 * a) * c)))) / (2.0d0 * a)
end function
public static double code(double a, double b, double c) {
	return (-b + Math.sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
}
def code(a, b, c):
	return (-b + math.sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a)
function code(a, b, c)
	return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(4.0 * a) * c)))) / Float64(2.0 * a))
end
function tmp = code(a, b, c)
	tmp = (-b + sqrt(((b * b) - ((4.0 * a) * c)))) / (2.0 * a);
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(4.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a}
\end{array}

Alternative 1: 90.8% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \frac{a}{b \cdot b} \cdot \frac{c \cdot c}{b}\right) - \frac{c}{b}\right) \end{array} \]
(FPCore (a b c)
 :precision binary64
 (fma
  -2.0
  (* (/ (* a a) (pow b 5.0)) (pow c 3.0))
  (-
   (-
    (/ (* (* -5.0 (pow c 4.0)) (pow a 3.0)) (pow b 7.0))
    (* (/ a (* b b)) (/ (* c c) b)))
   (/ c b))))
double code(double a, double b, double c) {
	return fma(-2.0, (((a * a) / pow(b, 5.0)) * pow(c, 3.0)), (((((-5.0 * pow(c, 4.0)) * pow(a, 3.0)) / pow(b, 7.0)) - ((a / (b * b)) * ((c * c) / b))) - (c / b)));
}
function code(a, b, c)
	return fma(-2.0, Float64(Float64(Float64(a * a) / (b ^ 5.0)) * (c ^ 3.0)), Float64(Float64(Float64(Float64(Float64(-5.0 * (c ^ 4.0)) * (a ^ 3.0)) / (b ^ 7.0)) - Float64(Float64(a / Float64(b * b)) * Float64(Float64(c * c) / b))) - Float64(c / b)))
end
code[a_, b_, c_] := N[(-2.0 * N[(N[(N[(a * a), $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision] * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision] + N[(N[(N[(N[(N[(-5.0 * N[Power[c, 4.0], $MachinePrecision]), $MachinePrecision] * N[Power[a, 3.0], $MachinePrecision]), $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision] - N[(N[(a / N[(b * b), $MachinePrecision]), $MachinePrecision] * N[(N[(c * c), $MachinePrecision] / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(c / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \frac{a}{b \cdot b} \cdot \frac{c \cdot c}{b}\right) - \frac{c}{b}\right)
\end{array}
Derivation
  1. Initial program 52.1%

    \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
  2. Taylor expanded in a around 0 92.0%

    \[\leadsto \color{blue}{-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} + \left(-1 \cdot \frac{c}{b} + \left(-1 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}} + -0.25 \cdot \frac{{a}^{3} \cdot \left(16 \cdot \frac{{c}^{4}}{{b}^{6}} + {\left(-2 \cdot \frac{{c}^{2}}{{b}^{3}}\right)}^{2}\right)}{b}\right)\right)} \]
  3. Simplified92.0%

    \[\leadsto \color{blue}{\mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{-0.25 \cdot {a}^{3}}{\frac{b}{\mathsf{fma}\left(16, \frac{{c}^{4}}{{b}^{6}}, 4 \cdot \frac{{c}^{4}}{{b}^{6}}\right)}} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)\right) - \frac{c}{b}\right)} \]
  4. Taylor expanded in c around 0 92.0%

    \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\color{blue}{-5 \cdot \frac{{a}^{3} \cdot {c}^{4}}{{b}^{7}}} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)\right) - \frac{c}{b}\right) \]
  5. Step-by-step derivation
    1. associate-*r/92.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\color{blue}{\frac{-5 \cdot \left({a}^{3} \cdot {c}^{4}\right)}{{b}^{7}}} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)\right) - \frac{c}{b}\right) \]
    2. *-commutative92.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{-5 \cdot \color{blue}{\left({c}^{4} \cdot {a}^{3}\right)}}{{b}^{7}} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)\right) - \frac{c}{b}\right) \]
    3. associate-*r*92.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\color{blue}{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}}{{b}^{7}} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)\right) - \frac{c}{b}\right) \]
  6. Simplified92.0%

    \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\color{blue}{\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}}} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)\right) - \frac{c}{b}\right) \]
  7. Step-by-step derivation
    1. add-log-exp82.7%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \color{blue}{\log \left(e^{\frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)}\right)}\right) - \frac{c}{b}\right) \]
  8. Applied egg-rr82.7%

    \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \color{blue}{\log \left(e^{\frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)}\right)}\right) - \frac{c}{b}\right) \]
  9. Step-by-step derivation
    1. add-log-exp92.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \color{blue}{\frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)}\right) - \frac{c}{b}\right) \]
    2. associate-*l/92.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \color{blue}{\frac{a \cdot \left(c \cdot c\right)}{{b}^{3}}}\right) - \frac{c}{b}\right) \]
    3. unpow392.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \frac{a \cdot \left(c \cdot c\right)}{\color{blue}{\left(b \cdot b\right) \cdot b}}\right) - \frac{c}{b}\right) \]
    4. times-frac92.0%

      \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \color{blue}{\frac{a}{b \cdot b} \cdot \frac{c \cdot c}{b}}\right) - \frac{c}{b}\right) \]
  10. Applied egg-rr92.0%

    \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \color{blue}{\frac{a}{b \cdot b} \cdot \frac{c \cdot c}{b}}\right) - \frac{c}{b}\right) \]
  11. Final simplification92.0%

    \[\leadsto \mathsf{fma}\left(-2, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \left(\frac{\left(-5 \cdot {c}^{4}\right) \cdot {a}^{3}}{{b}^{7}} - \frac{a}{b \cdot b} \cdot \frac{c \cdot c}{b}\right) - \frac{c}{b}\right) \]

Alternative 2: 89.1% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 22:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) + \left(c \cdot c\right) \cdot \left(\frac{a}{b} \cdot \frac{-1}{b \cdot b}\right)\\ \end{array} \end{array} \]
(FPCore (a b c)
 :precision binary64
 (if (<= b 22.0)
   (/ (- (sqrt (fma b b (* c (* a -4.0)))) b) (* a 2.0))
   (+
    (- (/ (* -2.0 (* a a)) (/ (pow b 5.0) (pow c 3.0))) (/ c b))
    (* (* c c) (* (/ a b) (/ -1.0 (* b b)))))))
double code(double a, double b, double c) {
	double tmp;
	if (b <= 22.0) {
		tmp = (sqrt(fma(b, b, (c * (a * -4.0)))) - b) / (a * 2.0);
	} else {
		tmp = (((-2.0 * (a * a)) / (pow(b, 5.0) / pow(c, 3.0))) - (c / b)) + ((c * c) * ((a / b) * (-1.0 / (b * b))));
	}
	return tmp;
}
function code(a, b, c)
	tmp = 0.0
	if (b <= 22.0)
		tmp = Float64(Float64(sqrt(fma(b, b, Float64(c * Float64(a * -4.0)))) - b) / Float64(a * 2.0));
	else
		tmp = Float64(Float64(Float64(Float64(-2.0 * Float64(a * a)) / Float64((b ^ 5.0) / (c ^ 3.0))) - Float64(c / b)) + Float64(Float64(c * c) * Float64(Float64(a / b) * Float64(-1.0 / Float64(b * b)))));
	end
	return tmp
end
code[a_, b_, c_] := If[LessEqual[b, 22.0], N[(N[(N[Sqrt[N[(b * b + N[(c * N[(a * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision], N[(N[(N[(N[(-2.0 * N[(a * a), $MachinePrecision]), $MachinePrecision] / N[(N[Power[b, 5.0], $MachinePrecision] / N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - N[(c / b), $MachinePrecision]), $MachinePrecision] + N[(N[(c * c), $MachinePrecision] * N[(N[(a / b), $MachinePrecision] * N[(-1.0 / N[(b * b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;b \leq 22:\\
\;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}\\

\mathbf{else}:\\
\;\;\;\;\left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) + \left(c \cdot c\right) \cdot \left(\frac{a}{b} \cdot \frac{-1}{b \cdot b}\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < 22

    1. Initial program 81.7%

      \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
    2. Step-by-step derivation
      1. Simplified81.8%

        \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}} \]

      if 22 < b

      1. Initial program 41.1%

        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
      2. Taylor expanded in b around inf 95.1%

        \[\leadsto \color{blue}{-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} + \left(-1 \cdot \frac{c}{b} + -1 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}\right)} \]
      3. Step-by-step derivation
        1. associate-+r+95.1%

          \[\leadsto \color{blue}{\left(-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} + -1 \cdot \frac{c}{b}\right) + -1 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
        2. mul-1-neg95.1%

          \[\leadsto \left(-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} + -1 \cdot \frac{c}{b}\right) + \color{blue}{\left(-\frac{a \cdot {c}^{2}}{{b}^{3}}\right)} \]
        3. unsub-neg95.1%

          \[\leadsto \color{blue}{\left(-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} + -1 \cdot \frac{c}{b}\right) - \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
        4. mul-1-neg95.1%

          \[\leadsto \left(-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} + \color{blue}{\left(-\frac{c}{b}\right)}\right) - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
        5. unsub-neg95.1%

          \[\leadsto \color{blue}{\left(-2 \cdot \frac{{a}^{2} \cdot {c}^{3}}{{b}^{5}} - \frac{c}{b}\right)} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
        6. associate-/l*95.1%

          \[\leadsto \left(-2 \cdot \color{blue}{\frac{{a}^{2}}{\frac{{b}^{5}}{{c}^{3}}}} - \frac{c}{b}\right) - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
        7. associate-*r/95.1%

          \[\leadsto \left(\color{blue}{\frac{-2 \cdot {a}^{2}}{\frac{{b}^{5}}{{c}^{3}}}} - \frac{c}{b}\right) - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
        8. unpow295.1%

          \[\leadsto \left(\frac{-2 \cdot \color{blue}{\left(a \cdot a\right)}}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
        9. associate-/l*95.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\frac{a}{\frac{{b}^{3}}{{c}^{2}}}} \]
        10. associate-/r/95.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\frac{a}{{b}^{3}} \cdot {c}^{2}} \]
        11. unpow295.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \frac{a}{{b}^{3}} \cdot \color{blue}{\left(c \cdot c\right)} \]
      4. Simplified95.1%

        \[\leadsto \color{blue}{\left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)} \]
      5. Step-by-step derivation
        1. add-log-exp85.9%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\log \left(e^{\frac{a}{{b}^{3}}}\right)} \cdot \left(c \cdot c\right) \]
      6. Applied egg-rr85.9%

        \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\log \left(e^{\frac{a}{{b}^{3}}}\right)} \cdot \left(c \cdot c\right) \]
      7. Step-by-step derivation
        1. add-log-exp95.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\frac{a}{{b}^{3}}} \cdot \left(c \cdot c\right) \]
        2. *-un-lft-identity95.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \frac{\color{blue}{1 \cdot a}}{{b}^{3}} \cdot \left(c \cdot c\right) \]
        3. unpow395.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \frac{1 \cdot a}{\color{blue}{\left(b \cdot b\right) \cdot b}} \cdot \left(c \cdot c\right) \]
        4. times-frac95.1%

          \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\left(\frac{1}{b \cdot b} \cdot \frac{a}{b}\right)} \cdot \left(c \cdot c\right) \]
      8. Applied egg-rr95.1%

        \[\leadsto \left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) - \color{blue}{\left(\frac{1}{b \cdot b} \cdot \frac{a}{b}\right)} \cdot \left(c \cdot c\right) \]
    3. Recombined 2 regimes into one program.
    4. Final simplification91.5%

      \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 22:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\left(\frac{-2 \cdot \left(a \cdot a\right)}{\frac{{b}^{5}}{{c}^{3}}} - \frac{c}{b}\right) + \left(c \cdot c\right) \cdot \left(\frac{a}{b} \cdot \frac{-1}{b \cdot b}\right)\\ \end{array} \]

    Alternative 3: 85.4% accurate, 0.5× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 22:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}\\ \end{array} \end{array} \]
    (FPCore (a b c)
     :precision binary64
     (if (<= b 22.0)
       (/ (- (sqrt (fma b b (* c (* a -4.0)))) b) (* a 2.0))
       (- (- (/ c b)) (* (* c c) (/ a (pow b 3.0))))))
    double code(double a, double b, double c) {
    	double tmp;
    	if (b <= 22.0) {
    		tmp = (sqrt(fma(b, b, (c * (a * -4.0)))) - b) / (a * 2.0);
    	} else {
    		tmp = -(c / b) - ((c * c) * (a / pow(b, 3.0)));
    	}
    	return tmp;
    }
    
    function code(a, b, c)
    	tmp = 0.0
    	if (b <= 22.0)
    		tmp = Float64(Float64(sqrt(fma(b, b, Float64(c * Float64(a * -4.0)))) - b) / Float64(a * 2.0));
    	else
    		tmp = Float64(Float64(-Float64(c / b)) - Float64(Float64(c * c) * Float64(a / (b ^ 3.0))));
    	end
    	return tmp
    end
    
    code[a_, b_, c_] := If[LessEqual[b, 22.0], N[(N[(N[Sqrt[N[(b * b + N[(c * N[(a * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision], N[((-N[(c / b), $MachinePrecision]) - N[(N[(c * c), $MachinePrecision] * N[(a / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    \mathbf{if}\;b \leq 22:\\
    \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}\\
    
    \mathbf{else}:\\
    \;\;\;\;\left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if b < 22

      1. Initial program 81.7%

        \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
      2. Step-by-step derivation
        1. Simplified81.8%

          \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}} \]

        if 22 < b

        1. Initial program 41.1%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
        2. Taylor expanded in b around inf 91.0%

          \[\leadsto \color{blue}{-1 \cdot \frac{c}{b} + -1 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
        3. Step-by-step derivation
          1. mul-1-neg91.0%

            \[\leadsto -1 \cdot \frac{c}{b} + \color{blue}{\left(-\frac{a \cdot {c}^{2}}{{b}^{3}}\right)} \]
          2. unsub-neg91.0%

            \[\leadsto \color{blue}{-1 \cdot \frac{c}{b} - \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
          3. mul-1-neg91.0%

            \[\leadsto \color{blue}{\left(-\frac{c}{b}\right)} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
          4. distribute-neg-frac91.0%

            \[\leadsto \color{blue}{\frac{-c}{b}} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
          5. associate-/l*91.0%

            \[\leadsto \frac{-c}{b} - \color{blue}{\frac{a}{\frac{{b}^{3}}{{c}^{2}}}} \]
          6. associate-/r/91.0%

            \[\leadsto \frac{-c}{b} - \color{blue}{\frac{a}{{b}^{3}} \cdot {c}^{2}} \]
          7. unpow291.0%

            \[\leadsto \frac{-c}{b} - \frac{a}{{b}^{3}} \cdot \color{blue}{\left(c \cdot c\right)} \]
        4. Simplified91.0%

          \[\leadsto \color{blue}{\frac{-c}{b} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification88.5%

        \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 22:\\ \;\;\;\;\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}\\ \end{array} \]

      Alternative 4: 85.4% accurate, 1.0× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq 22:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 4 \cdot \left(a \cdot c\right)} - b}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}\\ \end{array} \end{array} \]
      (FPCore (a b c)
       :precision binary64
       (if (<= b 22.0)
         (/ (- (sqrt (- (* b b) (* 4.0 (* a c)))) b) (* a 2.0))
         (- (- (/ c b)) (* (* c c) (/ a (pow b 3.0))))))
      double code(double a, double b, double c) {
      	double tmp;
      	if (b <= 22.0) {
      		tmp = (sqrt(((b * b) - (4.0 * (a * c)))) - b) / (a * 2.0);
      	} else {
      		tmp = -(c / b) - ((c * c) * (a / pow(b, 3.0)));
      	}
      	return tmp;
      }
      
      real(8) function code(a, b, c)
          real(8), intent (in) :: a
          real(8), intent (in) :: b
          real(8), intent (in) :: c
          real(8) :: tmp
          if (b <= 22.0d0) then
              tmp = (sqrt(((b * b) - (4.0d0 * (a * c)))) - b) / (a * 2.0d0)
          else
              tmp = -(c / b) - ((c * c) * (a / (b ** 3.0d0)))
          end if
          code = tmp
      end function
      
      public static double code(double a, double b, double c) {
      	double tmp;
      	if (b <= 22.0) {
      		tmp = (Math.sqrt(((b * b) - (4.0 * (a * c)))) - b) / (a * 2.0);
      	} else {
      		tmp = -(c / b) - ((c * c) * (a / Math.pow(b, 3.0)));
      	}
      	return tmp;
      }
      
      def code(a, b, c):
      	tmp = 0
      	if b <= 22.0:
      		tmp = (math.sqrt(((b * b) - (4.0 * (a * c)))) - b) / (a * 2.0)
      	else:
      		tmp = -(c / b) - ((c * c) * (a / math.pow(b, 3.0)))
      	return tmp
      
      function code(a, b, c)
      	tmp = 0.0
      	if (b <= 22.0)
      		tmp = Float64(Float64(sqrt(Float64(Float64(b * b) - Float64(4.0 * Float64(a * c)))) - b) / Float64(a * 2.0));
      	else
      		tmp = Float64(Float64(-Float64(c / b)) - Float64(Float64(c * c) * Float64(a / (b ^ 3.0))));
      	end
      	return tmp
      end
      
      function tmp_2 = code(a, b, c)
      	tmp = 0.0;
      	if (b <= 22.0)
      		tmp = (sqrt(((b * b) - (4.0 * (a * c)))) - b) / (a * 2.0);
      	else
      		tmp = -(c / b) - ((c * c) * (a / (b ^ 3.0)));
      	end
      	tmp_2 = tmp;
      end
      
      code[a_, b_, c_] := If[LessEqual[b, 22.0], N[(N[(N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(4.0 * N[(a * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision], N[((-N[(c / b), $MachinePrecision]) - N[(N[(c * c), $MachinePrecision] * N[(a / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      \mathbf{if}\;b \leq 22:\\
      \;\;\;\;\frac{\sqrt{b \cdot b - 4 \cdot \left(a \cdot c\right)} - b}{a \cdot 2}\\
      
      \mathbf{else}:\\
      \;\;\;\;\left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}\\
      
      
      \end{array}
      \end{array}
      
      Derivation
      1. Split input into 2 regimes
      2. if b < 22

        1. Initial program 81.7%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
        2. Step-by-step derivation
          1. Simplified81.8%

            \[\leadsto \color{blue}{\frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(a \cdot -4\right)\right)} - b}{a \cdot 2}} \]
          2. Step-by-step derivation
            1. *-commutative81.8%

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \color{blue}{\left(-4 \cdot a\right)}\right)} - b}{a \cdot 2} \]
            2. metadata-eval81.8%

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \left(\color{blue}{\left(-4\right)} \cdot a\right)\right)} - b}{a \cdot 2} \]
            3. distribute-lft-neg-in81.8%

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, c \cdot \color{blue}{\left(-4 \cdot a\right)}\right)} - b}{a \cdot 2} \]
            4. distribute-rgt-neg-in81.8%

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, \color{blue}{-c \cdot \left(4 \cdot a\right)}\right)} - b}{a \cdot 2} \]
            5. *-commutative81.8%

              \[\leadsto \frac{\sqrt{\mathsf{fma}\left(b, b, -\color{blue}{\left(4 \cdot a\right) \cdot c}\right)} - b}{a \cdot 2} \]
            6. fma-neg81.7%

              \[\leadsto \frac{\sqrt{\color{blue}{b \cdot b - \left(4 \cdot a\right) \cdot c}} - b}{a \cdot 2} \]
            7. associate-*l*81.7%

              \[\leadsto \frac{\sqrt{b \cdot b - \color{blue}{4 \cdot \left(a \cdot c\right)}} - b}{a \cdot 2} \]
          3. Applied egg-rr81.7%

            \[\leadsto \frac{\sqrt{\color{blue}{b \cdot b - 4 \cdot \left(a \cdot c\right)}} - b}{a \cdot 2} \]

          if 22 < b

          1. Initial program 41.1%

            \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
          2. Taylor expanded in b around inf 91.0%

            \[\leadsto \color{blue}{-1 \cdot \frac{c}{b} + -1 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
          3. Step-by-step derivation
            1. mul-1-neg91.0%

              \[\leadsto -1 \cdot \frac{c}{b} + \color{blue}{\left(-\frac{a \cdot {c}^{2}}{{b}^{3}}\right)} \]
            2. unsub-neg91.0%

              \[\leadsto \color{blue}{-1 \cdot \frac{c}{b} - \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
            3. mul-1-neg91.0%

              \[\leadsto \color{blue}{\left(-\frac{c}{b}\right)} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
            4. distribute-neg-frac91.0%

              \[\leadsto \color{blue}{\frac{-c}{b}} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
            5. associate-/l*91.0%

              \[\leadsto \frac{-c}{b} - \color{blue}{\frac{a}{\frac{{b}^{3}}{{c}^{2}}}} \]
            6. associate-/r/91.0%

              \[\leadsto \frac{-c}{b} - \color{blue}{\frac{a}{{b}^{3}} \cdot {c}^{2}} \]
            7. unpow291.0%

              \[\leadsto \frac{-c}{b} - \frac{a}{{b}^{3}} \cdot \color{blue}{\left(c \cdot c\right)} \]
          4. Simplified91.0%

            \[\leadsto \color{blue}{\frac{-c}{b} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)} \]
        3. Recombined 2 regimes into one program.
        4. Final simplification88.5%

          \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq 22:\\ \;\;\;\;\frac{\sqrt{b \cdot b - 4 \cdot \left(a \cdot c\right)} - b}{a \cdot 2}\\ \mathbf{else}:\\ \;\;\;\;\left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}\\ \end{array} \]

        Alternative 5: 81.6% accurate, 1.0× speedup?

        \[\begin{array}{l} \\ \left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}} \end{array} \]
        (FPCore (a b c)
         :precision binary64
         (- (- (/ c b)) (* (* c c) (/ a (pow b 3.0)))))
        double code(double a, double b, double c) {
        	return -(c / b) - ((c * c) * (a / pow(b, 3.0)));
        }
        
        real(8) function code(a, b, c)
            real(8), intent (in) :: a
            real(8), intent (in) :: b
            real(8), intent (in) :: c
            code = -(c / b) - ((c * c) * (a / (b ** 3.0d0)))
        end function
        
        public static double code(double a, double b, double c) {
        	return -(c / b) - ((c * c) * (a / Math.pow(b, 3.0)));
        }
        
        def code(a, b, c):
        	return -(c / b) - ((c * c) * (a / math.pow(b, 3.0)))
        
        function code(a, b, c)
        	return Float64(Float64(-Float64(c / b)) - Float64(Float64(c * c) * Float64(a / (b ^ 3.0))))
        end
        
        function tmp = code(a, b, c)
        	tmp = -(c / b) - ((c * c) * (a / (b ^ 3.0)));
        end
        
        code[a_, b_, c_] := N[((-N[(c / b), $MachinePrecision]) - N[(N[(c * c), $MachinePrecision] * N[(a / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        \left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}}
        \end{array}
        
        Derivation
        1. Initial program 52.1%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
        2. Taylor expanded in b around inf 82.7%

          \[\leadsto \color{blue}{-1 \cdot \frac{c}{b} + -1 \cdot \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
        3. Step-by-step derivation
          1. mul-1-neg82.7%

            \[\leadsto -1 \cdot \frac{c}{b} + \color{blue}{\left(-\frac{a \cdot {c}^{2}}{{b}^{3}}\right)} \]
          2. unsub-neg82.7%

            \[\leadsto \color{blue}{-1 \cdot \frac{c}{b} - \frac{a \cdot {c}^{2}}{{b}^{3}}} \]
          3. mul-1-neg82.7%

            \[\leadsto \color{blue}{\left(-\frac{c}{b}\right)} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
          4. distribute-neg-frac82.7%

            \[\leadsto \color{blue}{\frac{-c}{b}} - \frac{a \cdot {c}^{2}}{{b}^{3}} \]
          5. associate-/l*82.7%

            \[\leadsto \frac{-c}{b} - \color{blue}{\frac{a}{\frac{{b}^{3}}{{c}^{2}}}} \]
          6. associate-/r/82.7%

            \[\leadsto \frac{-c}{b} - \color{blue}{\frac{a}{{b}^{3}} \cdot {c}^{2}} \]
          7. unpow282.7%

            \[\leadsto \frac{-c}{b} - \frac{a}{{b}^{3}} \cdot \color{blue}{\left(c \cdot c\right)} \]
        4. Simplified82.7%

          \[\leadsto \color{blue}{\frac{-c}{b} - \frac{a}{{b}^{3}} \cdot \left(c \cdot c\right)} \]
        5. Final simplification82.7%

          \[\leadsto \left(-\frac{c}{b}\right) - \left(c \cdot c\right) \cdot \frac{a}{{b}^{3}} \]

        Alternative 6: 81.4% accurate, 4.3× speedup?

        \[\begin{array}{l} \\ \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \left(\frac{c \cdot c}{b \cdot b} \cdot \frac{a \cdot a}{b}\right)}{a \cdot 2} \end{array} \]
        (FPCore (a b c)
         :precision binary64
         (/
          (+ (* -2.0 (/ (* a c) b)) (* -2.0 (* (/ (* c c) (* b b)) (/ (* a a) b))))
          (* a 2.0)))
        double code(double a, double b, double c) {
        	return ((-2.0 * ((a * c) / b)) + (-2.0 * (((c * c) / (b * b)) * ((a * a) / b)))) / (a * 2.0);
        }
        
        real(8) function code(a, b, c)
            real(8), intent (in) :: a
            real(8), intent (in) :: b
            real(8), intent (in) :: c
            code = (((-2.0d0) * ((a * c) / b)) + ((-2.0d0) * (((c * c) / (b * b)) * ((a * a) / b)))) / (a * 2.0d0)
        end function
        
        public static double code(double a, double b, double c) {
        	return ((-2.0 * ((a * c) / b)) + (-2.0 * (((c * c) / (b * b)) * ((a * a) / b)))) / (a * 2.0);
        }
        
        def code(a, b, c):
        	return ((-2.0 * ((a * c) / b)) + (-2.0 * (((c * c) / (b * b)) * ((a * a) / b)))) / (a * 2.0)
        
        function code(a, b, c)
        	return Float64(Float64(Float64(-2.0 * Float64(Float64(a * c) / b)) + Float64(-2.0 * Float64(Float64(Float64(c * c) / Float64(b * b)) * Float64(Float64(a * a) / b)))) / Float64(a * 2.0))
        end
        
        function tmp = code(a, b, c)
        	tmp = ((-2.0 * ((a * c) / b)) + (-2.0 * (((c * c) / (b * b)) * ((a * a) / b)))) / (a * 2.0);
        end
        
        code[a_, b_, c_] := N[(N[(N[(-2.0 * N[(N[(a * c), $MachinePrecision] / b), $MachinePrecision]), $MachinePrecision] + N[(-2.0 * N[(N[(N[(c * c), $MachinePrecision] / N[(b * b), $MachinePrecision]), $MachinePrecision] * N[(N[(a * a), $MachinePrecision] / b), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(a * 2.0), $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \left(\frac{c \cdot c}{b \cdot b} \cdot \frac{a \cdot a}{b}\right)}{a \cdot 2}
        \end{array}
        
        Derivation
        1. Initial program 52.1%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
        2. Taylor expanded in b around inf 82.6%

          \[\leadsto \frac{\color{blue}{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{{a}^{2} \cdot {c}^{2}}{{b}^{3}}}}{2 \cdot a} \]
        3. Step-by-step derivation
          1. pow-prod-down82.6%

            \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{\color{blue}{{\left(a \cdot c\right)}^{2}}}{{b}^{3}}}{2 \cdot a} \]
          2. *-commutative82.6%

            \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{{\color{blue}{\left(c \cdot a\right)}}^{2}}{{b}^{3}}}{2 \cdot a} \]
        4. Applied egg-rr82.6%

          \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{\color{blue}{{\left(c \cdot a\right)}^{2}}}{{b}^{3}}}{2 \cdot a} \]
        5. Step-by-step derivation
          1. unpow282.6%

            \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{\color{blue}{\left(c \cdot a\right) \cdot \left(c \cdot a\right)}}{{b}^{3}}}{2 \cdot a} \]
          2. swap-sqr82.6%

            \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{\color{blue}{\left(c \cdot c\right) \cdot \left(a \cdot a\right)}}{{b}^{3}}}{2 \cdot a} \]
          3. unpow382.6%

            \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \frac{\left(c \cdot c\right) \cdot \left(a \cdot a\right)}{\color{blue}{\left(b \cdot b\right) \cdot b}}}{2 \cdot a} \]
          4. times-frac82.6%

            \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \color{blue}{\left(\frac{c \cdot c}{b \cdot b} \cdot \frac{a \cdot a}{b}\right)}}{2 \cdot a} \]
        6. Applied egg-rr82.6%

          \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \color{blue}{\left(\frac{c \cdot c}{b \cdot b} \cdot \frac{a \cdot a}{b}\right)}}{2 \cdot a} \]
        7. Final simplification82.6%

          \[\leadsto \frac{-2 \cdot \frac{a \cdot c}{b} + -2 \cdot \left(\frac{c \cdot c}{b \cdot b} \cdot \frac{a \cdot a}{b}\right)}{a \cdot 2} \]

        Alternative 7: 64.5% accurate, 29.0× speedup?

        \[\begin{array}{l} \\ -\frac{c}{b} \end{array} \]
        (FPCore (a b c) :precision binary64 (- (/ c b)))
        double code(double a, double b, double c) {
        	return -(c / b);
        }
        
        real(8) function code(a, b, c)
            real(8), intent (in) :: a
            real(8), intent (in) :: b
            real(8), intent (in) :: c
            code = -(c / b)
        end function
        
        public static double code(double a, double b, double c) {
        	return -(c / b);
        }
        
        def code(a, b, c):
        	return -(c / b)
        
        function code(a, b, c)
        	return Float64(-Float64(c / b))
        end
        
        function tmp = code(a, b, c)
        	tmp = -(c / b);
        end
        
        code[a_, b_, c_] := (-N[(c / b), $MachinePrecision])
        
        \begin{array}{l}
        
        \\
        -\frac{c}{b}
        \end{array}
        
        Derivation
        1. Initial program 52.1%

          \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(4 \cdot a\right) \cdot c}}{2 \cdot a} \]
        2. Taylor expanded in b around inf 67.1%

          \[\leadsto \color{blue}{-1 \cdot \frac{c}{b}} \]
        3. Step-by-step derivation
          1. mul-1-neg67.1%

            \[\leadsto \color{blue}{-\frac{c}{b}} \]
          2. distribute-neg-frac67.1%

            \[\leadsto \color{blue}{\frac{-c}{b}} \]
        4. Simplified67.1%

          \[\leadsto \color{blue}{\frac{-c}{b}} \]
        5. Final simplification67.1%

          \[\leadsto -\frac{c}{b} \]

        Reproduce

        ?
        herbie shell --seed 2023272 
        (FPCore (a b c)
          :name "Quadratic roots, narrow range"
          :precision binary64
          :pre (and (and (and (< 1.0536712127723509e-8 a) (< a 94906265.62425156)) (and (< 1.0536712127723509e-8 b) (< b 94906265.62425156))) (and (< 1.0536712127723509e-8 c) (< c 94906265.62425156)))
          (/ (+ (- b) (sqrt (- (* b b) (* (* 4.0 a) c)))) (* 2.0 a)))