2-ancestry mixing, positive discriminant

Percentage Accurate: 43.4% → 77.0%
Time: 14.4s
Alternatives: 2
Speedup: 2.0×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 2 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 43.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)}
\end{array}
\end{array}

Alternative 1: 77.0% accurate, 0.3× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ t_2 := t_1 - g\\ t_3 := \sqrt[3]{\frac{1}{2 \cdot a} \cdot t_2} + \sqrt[3]{\left(g + t_1\right) \cdot \frac{-1}{2 \cdot a}}\\ \mathbf{if}\;t_3 \leq -5 \cdot 10^{-105}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \frac{-0.5}{\frac{g}{h \cdot h}}} + t_0\\ \mathbf{elif}\;t_3 \leq 0:\\ \;\;\;\;\sqrt[3]{t_2 \cdot \frac{0.5}{a}} + \sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + g}\\ \mathbf{else}:\\ \;\;\;\;t_0 + \sqrt[3]{\frac{0.5}{a} \cdot \left(g - g\right)}\\ \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (cbrt (* (+ g g) (/ -0.5 a))))
        (t_1 (sqrt (- (* g g) (* h h))))
        (t_2 (- t_1 g))
        (t_3
         (+
          (cbrt (* (/ 1.0 (* 2.0 a)) t_2))
          (cbrt (* (+ g t_1) (/ -1.0 (* 2.0 a)))))))
   (if (<= t_3 -5e-105)
     (+ (cbrt (* (/ 0.5 a) (/ -0.5 (/ g (* h h))))) t_0)
     (if (<= t_3 0.0)
       (+ (cbrt (* t_2 (/ 0.5 a))) (* (cbrt (/ -0.5 a)) (cbrt (+ g g))))
       (+ t_0 (cbrt (* (/ 0.5 a) (- g g))))))))
double code(double g, double h, double a) {
	double t_0 = cbrt(((g + g) * (-0.5 / a)));
	double t_1 = sqrt(((g * g) - (h * h)));
	double t_2 = t_1 - g;
	double t_3 = cbrt(((1.0 / (2.0 * a)) * t_2)) + cbrt(((g + t_1) * (-1.0 / (2.0 * a))));
	double tmp;
	if (t_3 <= -5e-105) {
		tmp = cbrt(((0.5 / a) * (-0.5 / (g / (h * h))))) + t_0;
	} else if (t_3 <= 0.0) {
		tmp = cbrt((t_2 * (0.5 / a))) + (cbrt((-0.5 / a)) * cbrt((g + g)));
	} else {
		tmp = t_0 + cbrt(((0.5 / a) * (g - g)));
	}
	return tmp;
}
public static double code(double g, double h, double a) {
	double t_0 = Math.cbrt(((g + g) * (-0.5 / a)));
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	double t_2 = t_1 - g;
	double t_3 = Math.cbrt(((1.0 / (2.0 * a)) * t_2)) + Math.cbrt(((g + t_1) * (-1.0 / (2.0 * a))));
	double tmp;
	if (t_3 <= -5e-105) {
		tmp = Math.cbrt(((0.5 / a) * (-0.5 / (g / (h * h))))) + t_0;
	} else if (t_3 <= 0.0) {
		tmp = Math.cbrt((t_2 * (0.5 / a))) + (Math.cbrt((-0.5 / a)) * Math.cbrt((g + g)));
	} else {
		tmp = t_0 + Math.cbrt(((0.5 / a) * (g - g)));
	}
	return tmp;
}
function code(g, h, a)
	t_0 = cbrt(Float64(Float64(g + g) * Float64(-0.5 / a)))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	t_2 = Float64(t_1 - g)
	t_3 = Float64(cbrt(Float64(Float64(1.0 / Float64(2.0 * a)) * t_2)) + cbrt(Float64(Float64(g + t_1) * Float64(-1.0 / Float64(2.0 * a)))))
	tmp = 0.0
	if (t_3 <= -5e-105)
		tmp = Float64(cbrt(Float64(Float64(0.5 / a) * Float64(-0.5 / Float64(g / Float64(h * h))))) + t_0);
	elseif (t_3 <= 0.0)
		tmp = Float64(cbrt(Float64(t_2 * Float64(0.5 / a))) + Float64(cbrt(Float64(-0.5 / a)) * cbrt(Float64(g + g))));
	else
		tmp = Float64(t_0 + cbrt(Float64(Float64(0.5 / a) * Float64(g - g))));
	end
	return tmp
end
code[g_, h_, a_] := Block[{t$95$0 = N[Power[N[(N[(g + g), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, Block[{t$95$2 = N[(t$95$1 - g), $MachinePrecision]}, Block[{t$95$3 = N[(N[Power[N[(N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision] * t$95$2), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(g + t$95$1), $MachinePrecision] * N[(-1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$3, -5e-105], N[(N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(-0.5 / N[(g / N[(h * h), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + t$95$0), $MachinePrecision], If[LessEqual[t$95$3, 0.0], N[(N[Power[N[(t$95$2 * N[(0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[(N[Power[N[(-0.5 / a), $MachinePrecision], 1/3], $MachinePrecision] * N[Power[N[(g + g), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(t$95$0 + N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(g - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
t_2 := t_1 - g\\
t_3 := \sqrt[3]{\frac{1}{2 \cdot a} \cdot t_2} + \sqrt[3]{\left(g + t_1\right) \cdot \frac{-1}{2 \cdot a}}\\
\mathbf{if}\;t_3 \leq -5 \cdot 10^{-105}:\\
\;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \frac{-0.5}{\frac{g}{h \cdot h}}} + t_0\\

\mathbf{elif}\;t_3 \leq 0:\\
\;\;\;\;\sqrt[3]{t_2 \cdot \frac{0.5}{a}} + \sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + g}\\

\mathbf{else}:\\
\;\;\;\;t_0 + \sqrt[3]{\frac{0.5}{a} \cdot \left(g - g\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (+.f64 (cbrt.f64 (*.f64 (/.f64 1 (*.f64 2 a)) (+.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))) (cbrt.f64 (*.f64 (/.f64 1 (*.f64 2 a)) (-.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h))))))) < -4.99999999999999963e-105

    1. Initial program 84.3%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Simplified84.3%

      \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \sqrt{g \cdot g - h \cdot h}\right) \cdot \frac{-0.5}{a}}} \]
    3. Taylor expanded in g around inf 54.4%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \color{blue}{g}\right) \cdot \frac{-0.5}{a}} \]
    4. Taylor expanded in g around inf 91.3%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-0.5 \cdot \frac{{h}^{2}}{g}\right)}} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]
    5. Step-by-step derivation
      1. associate-*r/91.3%

        \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\frac{-0.5 \cdot {h}^{2}}{g}}} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]
      2. associate-/l*91.3%

        \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\frac{-0.5}{\frac{g}{{h}^{2}}}}} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]
      3. unpow291.3%

        \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \frac{-0.5}{\frac{g}{\color{blue}{h \cdot h}}}} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]
    6. Simplified91.3%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\frac{-0.5}{\frac{g}{h \cdot h}}}} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]

    if -4.99999999999999963e-105 < (+.f64 (cbrt.f64 (*.f64 (/.f64 1 (*.f64 2 a)) (+.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))) (cbrt.f64 (*.f64 (/.f64 1 (*.f64 2 a)) (-.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h))))))) < -0.0

    1. Initial program 4.3%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Simplified4.3%

      \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \sqrt{g \cdot g - h \cdot h}\right) \cdot \frac{-0.5}{a}}} \]
    3. Taylor expanded in g around inf 4.3%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \color{blue}{g}\right) \cdot \frac{-0.5}{a}} \]
    4. Step-by-step derivation
      1. cbrt-prod93.1%

        \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \color{blue}{\sqrt[3]{g + g} \cdot \sqrt[3]{\frac{-0.5}{a}}} \]
    5. Applied egg-rr93.1%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \color{blue}{\sqrt[3]{g + g} \cdot \sqrt[3]{\frac{-0.5}{a}}} \]
    6. Step-by-step derivation
      1. *-commutative93.1%

        \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \color{blue}{\sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + g}} \]
    7. Simplified93.1%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \color{blue}{\sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + g}} \]

    if -0.0 < (+.f64 (cbrt.f64 (*.f64 (/.f64 1 (*.f64 2 a)) (+.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))) (cbrt.f64 (*.f64 (/.f64 1 (*.f64 2 a)) (-.f64 (neg.f64 g) (sqrt.f64 (-.f64 (*.f64 g g) (*.f64 h h)))))))

    1. Initial program 32.3%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Simplified32.3%

      \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \sqrt{g \cdot g - h \cdot h}\right) \cdot \frac{-0.5}{a}}} \]
    3. Taylor expanded in g around inf 19.1%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \color{blue}{g}\right) \cdot \frac{-0.5}{a}} \]
    4. Taylor expanded in g around inf 70.1%

      \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\color{blue}{g} - g\right)} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification77.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \sqrt{g \cdot g - h \cdot h}\right) \cdot \frac{-1}{2 \cdot a}} \leq -5 \cdot 10^{-105}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \frac{-0.5}{\frac{g}{h \cdot h}}} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}}\\ \mathbf{elif}\;\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \sqrt{g \cdot g - h \cdot h}\right) \cdot \frac{-1}{2 \cdot a}} \leq 0:\\ \;\;\;\;\sqrt[3]{\left(\sqrt{g \cdot g - h \cdot h} - g\right) \cdot \frac{0.5}{a}} + \sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + g}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(g - g\right)}\\ \end{array} \]

Alternative 2: 73.8% accurate, 2.0× speedup?

\[\begin{array}{l} \\ \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(g - g\right)} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (+ (cbrt (* (+ g g) (/ -0.5 a))) (cbrt (* (/ 0.5 a) (- g g)))))
double code(double g, double h, double a) {
	return cbrt(((g + g) * (-0.5 / a))) + cbrt(((0.5 / a) * (g - g)));
}
public static double code(double g, double h, double a) {
	return Math.cbrt(((g + g) * (-0.5 / a))) + Math.cbrt(((0.5 / a) * (g - g)));
}
function code(g, h, a)
	return Float64(cbrt(Float64(Float64(g + g) * Float64(-0.5 / a))) + cbrt(Float64(Float64(0.5 / a) * Float64(g - g))))
end
code[g_, h_, a_] := N[(N[Power[N[(N[(g + g), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(g - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(g - g\right)}
\end{array}
Derivation
  1. Initial program 46.4%

    \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
  2. Simplified46.4%

    \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \sqrt{g \cdot g - h \cdot h}\right) \cdot \frac{-0.5}{a}}} \]
  3. Taylor expanded in g around inf 28.9%

    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\left(g + \color{blue}{g}\right) \cdot \frac{-0.5}{a}} \]
  4. Taylor expanded in g around inf 72.8%

    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\color{blue}{g} - g\right)} + \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} \]
  5. Final simplification72.8%

    \[\leadsto \sqrt[3]{\left(g + g\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(g - g\right)} \]

Reproduce

?
herbie shell --seed 2023271 
(FPCore (g h a)
  :name "2-ancestry mixing, positive discriminant"
  :precision binary64
  (+ (cbrt (* (/ 1.0 (* 2.0 a)) (+ (- g) (sqrt (- (* g g) (* h h)))))) (cbrt (* (/ 1.0 (* 2.0 a)) (- (- g) (sqrt (- (* g g) (* h h))))))))