Quotient of products

Percentage Accurate: 85.9% → 96.5%
Time: 3.4s
Alternatives: 4
Speedup: 1.0×

Specification

?
\[\begin{array}{l} \\ \frac{a1 \cdot a2}{b1 \cdot b2} \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (/ (* a1 a2) (* b1 b2)))
double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
real(8) function code(a1, a2, b1, b2)
    real(8), intent (in) :: a1
    real(8), intent (in) :: a2
    real(8), intent (in) :: b1
    real(8), intent (in) :: b2
    code = (a1 * a2) / (b1 * b2)
end function
public static double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
def code(a1, a2, b1, b2):
	return (a1 * a2) / (b1 * b2)
function code(a1, a2, b1, b2)
	return Float64(Float64(a1 * a2) / Float64(b1 * b2))
end
function tmp = code(a1, a2, b1, b2)
	tmp = (a1 * a2) / (b1 * b2);
end
code[a1_, a2_, b1_, b2_] := N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a1 \cdot a2}{b1 \cdot b2}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 4 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 85.9% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a1 \cdot a2}{b1 \cdot b2} \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (/ (* a1 a2) (* b1 b2)))
double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
real(8) function code(a1, a2, b1, b2)
    real(8), intent (in) :: a1
    real(8), intent (in) :: a2
    real(8), intent (in) :: b1
    real(8), intent (in) :: b2
    code = (a1 * a2) / (b1 * b2)
end function
public static double code(double a1, double a2, double b1, double b2) {
	return (a1 * a2) / (b1 * b2);
}
def code(a1, a2, b1, b2):
	return (a1 * a2) / (b1 * b2)
function code(a1, a2, b1, b2)
	return Float64(Float64(a1 * a2) / Float64(b1 * b2))
end
function tmp = code(a1, a2, b1, b2)
	tmp = (a1 * a2) / (b1 * b2);
end
code[a1_, a2_, b1_, b2_] := N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a1 \cdot a2}{b1 \cdot b2}
\end{array}

Alternative 1: 96.5% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{if}\;t_0 \leq -\infty:\\ \;\;\;\;\frac{a1 \cdot \frac{a2}{b2}}{b1}\\ \mathbf{elif}\;t_0 \leq -1 \cdot 10^{-284} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 4 \cdot 10^{+257}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array} \end{array} \]
(FPCore (a1 a2 b1 b2)
 :precision binary64
 (let* ((t_0 (/ (* a1 a2) (* b1 b2))))
   (if (<= t_0 (- INFINITY))
     (/ (* a1 (/ a2 b2)) b1)
     (if (or (<= t_0 -1e-284) (and (not (<= t_0 0.0)) (<= t_0 4e+257)))
       t_0
       (* (/ a2 b2) (/ a1 b1))))))
double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -((double) INFINITY)) {
		tmp = (a1 * (a2 / b2)) / b1;
	} else if ((t_0 <= -1e-284) || (!(t_0 <= 0.0) && (t_0 <= 4e+257))) {
		tmp = t_0;
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}
public static double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -Double.POSITIVE_INFINITY) {
		tmp = (a1 * (a2 / b2)) / b1;
	} else if ((t_0 <= -1e-284) || (!(t_0 <= 0.0) && (t_0 <= 4e+257))) {
		tmp = t_0;
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}
def code(a1, a2, b1, b2):
	t_0 = (a1 * a2) / (b1 * b2)
	tmp = 0
	if t_0 <= -math.inf:
		tmp = (a1 * (a2 / b2)) / b1
	elif (t_0 <= -1e-284) or (not (t_0 <= 0.0) and (t_0 <= 4e+257)):
		tmp = t_0
	else:
		tmp = (a2 / b2) * (a1 / b1)
	return tmp
function code(a1, a2, b1, b2)
	t_0 = Float64(Float64(a1 * a2) / Float64(b1 * b2))
	tmp = 0.0
	if (t_0 <= Float64(-Inf))
		tmp = Float64(Float64(a1 * Float64(a2 / b2)) / b1);
	elseif ((t_0 <= -1e-284) || (!(t_0 <= 0.0) && (t_0 <= 4e+257)))
		tmp = t_0;
	else
		tmp = Float64(Float64(a2 / b2) * Float64(a1 / b1));
	end
	return tmp
end
function tmp_2 = code(a1, a2, b1, b2)
	t_0 = (a1 * a2) / (b1 * b2);
	tmp = 0.0;
	if (t_0 <= -Inf)
		tmp = (a1 * (a2 / b2)) / b1;
	elseif ((t_0 <= -1e-284) || (~((t_0 <= 0.0)) && (t_0 <= 4e+257)))
		tmp = t_0;
	else
		tmp = (a2 / b2) * (a1 / b1);
	end
	tmp_2 = tmp;
end
code[a1_, a2_, b1_, b2_] := Block[{t$95$0 = N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, (-Infinity)], N[(N[(a1 * N[(a2 / b2), $MachinePrecision]), $MachinePrecision] / b1), $MachinePrecision], If[Or[LessEqual[t$95$0, -1e-284], And[N[Not[LessEqual[t$95$0, 0.0]], $MachinePrecision], LessEqual[t$95$0, 4e+257]]], t$95$0, N[(N[(a2 / b2), $MachinePrecision] * N[(a1 / b1), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\
\mathbf{if}\;t_0 \leq -\infty:\\
\;\;\;\;\frac{a1 \cdot \frac{a2}{b2}}{b1}\\

\mathbf{elif}\;t_0 \leq -1 \cdot 10^{-284} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 4 \cdot 10^{+257}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -inf.0

    1. Initial program 84.9%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Step-by-step derivation
      1. times-frac97.1%

        \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
      2. *-commutative97.1%

        \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    3. Simplified97.1%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    4. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{\frac{\frac{a2}{b2} \cdot a1}{b1}} \]
    5. Applied egg-rr100.0%

      \[\leadsto \color{blue}{\frac{\frac{a2}{b2} \cdot a1}{b1}} \]

    if -inf.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -1.00000000000000004e-284 or -0.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 4.00000000000000012e257

    1. Initial program 99.2%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]

    if -1.00000000000000004e-284 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -0.0 or 4.00000000000000012e257 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2))

    1. Initial program 79.7%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Step-by-step derivation
      1. times-frac98.1%

        \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
      2. *-commutative98.1%

        \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    3. Simplified98.1%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification98.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -\infty:\\ \;\;\;\;\frac{a1 \cdot \frac{a2}{b2}}{b1}\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -1 \cdot 10^{-284} \lor \neg \left(\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0\right) \land \frac{a1 \cdot a2}{b1 \cdot b2} \leq 4 \cdot 10^{+257}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array} \]

Alternative 2: 95.3% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{if}\;t_0 \leq -2 \cdot 10^{+174}:\\ \;\;\;\;\frac{a1}{b1 \cdot \frac{b2}{a2}}\\ \mathbf{elif}\;t_0 \leq -1 \cdot 10^{-284} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 4 \cdot 10^{+257}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array} \end{array} \]
(FPCore (a1 a2 b1 b2)
 :precision binary64
 (let* ((t_0 (/ (* a1 a2) (* b1 b2))))
   (if (<= t_0 -2e+174)
     (/ a1 (* b1 (/ b2 a2)))
     (if (or (<= t_0 -1e-284) (and (not (<= t_0 0.0)) (<= t_0 4e+257)))
       t_0
       (* (/ a2 b2) (/ a1 b1))))))
double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -2e+174) {
		tmp = a1 / (b1 * (b2 / a2));
	} else if ((t_0 <= -1e-284) || (!(t_0 <= 0.0) && (t_0 <= 4e+257))) {
		tmp = t_0;
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}
real(8) function code(a1, a2, b1, b2)
    real(8), intent (in) :: a1
    real(8), intent (in) :: a2
    real(8), intent (in) :: b1
    real(8), intent (in) :: b2
    real(8) :: t_0
    real(8) :: tmp
    t_0 = (a1 * a2) / (b1 * b2)
    if (t_0 <= (-2d+174)) then
        tmp = a1 / (b1 * (b2 / a2))
    else if ((t_0 <= (-1d-284)) .or. (.not. (t_0 <= 0.0d0)) .and. (t_0 <= 4d+257)) then
        tmp = t_0
    else
        tmp = (a2 / b2) * (a1 / b1)
    end if
    code = tmp
end function
public static double code(double a1, double a2, double b1, double b2) {
	double t_0 = (a1 * a2) / (b1 * b2);
	double tmp;
	if (t_0 <= -2e+174) {
		tmp = a1 / (b1 * (b2 / a2));
	} else if ((t_0 <= -1e-284) || (!(t_0 <= 0.0) && (t_0 <= 4e+257))) {
		tmp = t_0;
	} else {
		tmp = (a2 / b2) * (a1 / b1);
	}
	return tmp;
}
def code(a1, a2, b1, b2):
	t_0 = (a1 * a2) / (b1 * b2)
	tmp = 0
	if t_0 <= -2e+174:
		tmp = a1 / (b1 * (b2 / a2))
	elif (t_0 <= -1e-284) or (not (t_0 <= 0.0) and (t_0 <= 4e+257)):
		tmp = t_0
	else:
		tmp = (a2 / b2) * (a1 / b1)
	return tmp
function code(a1, a2, b1, b2)
	t_0 = Float64(Float64(a1 * a2) / Float64(b1 * b2))
	tmp = 0.0
	if (t_0 <= -2e+174)
		tmp = Float64(a1 / Float64(b1 * Float64(b2 / a2)));
	elseif ((t_0 <= -1e-284) || (!(t_0 <= 0.0) && (t_0 <= 4e+257)))
		tmp = t_0;
	else
		tmp = Float64(Float64(a2 / b2) * Float64(a1 / b1));
	end
	return tmp
end
function tmp_2 = code(a1, a2, b1, b2)
	t_0 = (a1 * a2) / (b1 * b2);
	tmp = 0.0;
	if (t_0 <= -2e+174)
		tmp = a1 / (b1 * (b2 / a2));
	elseif ((t_0 <= -1e-284) || (~((t_0 <= 0.0)) && (t_0 <= 4e+257)))
		tmp = t_0;
	else
		tmp = (a2 / b2) * (a1 / b1);
	end
	tmp_2 = tmp;
end
code[a1_, a2_, b1_, b2_] := Block[{t$95$0 = N[(N[(a1 * a2), $MachinePrecision] / N[(b1 * b2), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, -2e+174], N[(a1 / N[(b1 * N[(b2 / a2), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[t$95$0, -1e-284], And[N[Not[LessEqual[t$95$0, 0.0]], $MachinePrecision], LessEqual[t$95$0, 4e+257]]], t$95$0, N[(N[(a2 / b2), $MachinePrecision] * N[(a1 / b1), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{a1 \cdot a2}{b1 \cdot b2}\\
\mathbf{if}\;t_0 \leq -2 \cdot 10^{+174}:\\
\;\;\;\;\frac{a1}{b1 \cdot \frac{b2}{a2}}\\

\mathbf{elif}\;t_0 \leq -1 \cdot 10^{-284} \lor \neg \left(t_0 \leq 0\right) \land t_0 \leq 4 \cdot 10^{+257}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -2.00000000000000014e174

    1. Initial program 87.9%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Step-by-step derivation
      1. times-frac92.8%

        \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
      2. *-commutative92.8%

        \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    3. Simplified92.8%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    4. Step-by-step derivation
      1. clear-num92.8%

        \[\leadsto \color{blue}{\frac{1}{\frac{b2}{a2}}} \cdot \frac{a1}{b1} \]
      2. frac-times99.9%

        \[\leadsto \color{blue}{\frac{1 \cdot a1}{\frac{b2}{a2} \cdot b1}} \]
      3. *-un-lft-identity99.9%

        \[\leadsto \frac{\color{blue}{a1}}{\frac{b2}{a2} \cdot b1} \]
    5. Applied egg-rr99.9%

      \[\leadsto \color{blue}{\frac{a1}{\frac{b2}{a2} \cdot b1}} \]

    if -2.00000000000000014e174 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -1.00000000000000004e-284 or -0.0 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < 4.00000000000000012e257

    1. Initial program 99.1%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]

    if -1.00000000000000004e-284 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2)) < -0.0 or 4.00000000000000012e257 < (/.f64 (*.f64 a1 a2) (*.f64 b1 b2))

    1. Initial program 79.7%

      \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
    2. Step-by-step derivation
      1. times-frac98.1%

        \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
      2. *-commutative98.1%

        \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    3. Simplified98.1%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification98.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -2 \cdot 10^{+174}:\\ \;\;\;\;\frac{a1}{b1 \cdot \frac{b2}{a2}}\\ \mathbf{elif}\;\frac{a1 \cdot a2}{b1 \cdot b2} \leq -1 \cdot 10^{-284} \lor \neg \left(\frac{a1 \cdot a2}{b1 \cdot b2} \leq 0\right) \land \frac{a1 \cdot a2}{b1 \cdot b2} \leq 4 \cdot 10^{+257}:\\ \;\;\;\;\frac{a1 \cdot a2}{b1 \cdot b2}\\ \mathbf{else}:\\ \;\;\;\;\frac{a2}{b2} \cdot \frac{a1}{b1}\\ \end{array} \]

Alternative 3: 86.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ a2 \cdot \frac{\frac{a1}{b1}}{b2} \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (* a2 (/ (/ a1 b1) b2)))
double code(double a1, double a2, double b1, double b2) {
	return a2 * ((a1 / b1) / b2);
}
real(8) function code(a1, a2, b1, b2)
    real(8), intent (in) :: a1
    real(8), intent (in) :: a2
    real(8), intent (in) :: b1
    real(8), intent (in) :: b2
    code = a2 * ((a1 / b1) / b2)
end function
public static double code(double a1, double a2, double b1, double b2) {
	return a2 * ((a1 / b1) / b2);
}
def code(a1, a2, b1, b2):
	return a2 * ((a1 / b1) / b2)
function code(a1, a2, b1, b2)
	return Float64(a2 * Float64(Float64(a1 / b1) / b2))
end
function tmp = code(a1, a2, b1, b2)
	tmp = a2 * ((a1 / b1) / b2);
end
code[a1_, a2_, b1_, b2_] := N[(a2 * N[(N[(a1 / b1), $MachinePrecision] / b2), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
a2 \cdot \frac{\frac{a1}{b1}}{b2}
\end{array}
Derivation
  1. Initial program 89.4%

    \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
  2. Step-by-step derivation
    1. times-frac86.3%

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
    2. *-commutative86.3%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
  3. Simplified86.3%

    \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
  4. Taylor expanded in a2 around 0 89.4%

    \[\leadsto \color{blue}{\frac{a1 \cdot a2}{b1 \cdot b2}} \]
  5. Step-by-step derivation
    1. times-frac86.3%

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
    2. *-commutative86.3%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
    3. associate-*l/89.6%

      \[\leadsto \color{blue}{\frac{a2 \cdot \frac{a1}{b1}}{b2}} \]
    4. associate-*r/89.3%

      \[\leadsto \color{blue}{a2 \cdot \frac{\frac{a1}{b1}}{b2}} \]
  6. Simplified89.3%

    \[\leadsto \color{blue}{a2 \cdot \frac{\frac{a1}{b1}}{b2}} \]
  7. Final simplification89.3%

    \[\leadsto a2 \cdot \frac{\frac{a1}{b1}}{b2} \]

Alternative 4: 86.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a2}{b2 \cdot \frac{b1}{a1}} \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (/ a2 (* b2 (/ b1 a1))))
double code(double a1, double a2, double b1, double b2) {
	return a2 / (b2 * (b1 / a1));
}
real(8) function code(a1, a2, b1, b2)
    real(8), intent (in) :: a1
    real(8), intent (in) :: a2
    real(8), intent (in) :: b1
    real(8), intent (in) :: b2
    code = a2 / (b2 * (b1 / a1))
end function
public static double code(double a1, double a2, double b1, double b2) {
	return a2 / (b2 * (b1 / a1));
}
def code(a1, a2, b1, b2):
	return a2 / (b2 * (b1 / a1))
function code(a1, a2, b1, b2)
	return Float64(a2 / Float64(b2 * Float64(b1 / a1)))
end
function tmp = code(a1, a2, b1, b2)
	tmp = a2 / (b2 * (b1 / a1));
end
code[a1_, a2_, b1_, b2_] := N[(a2 / N[(b2 * N[(b1 / a1), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a2}{b2 \cdot \frac{b1}{a1}}
\end{array}
Derivation
  1. Initial program 89.4%

    \[\frac{a1 \cdot a2}{b1 \cdot b2} \]
  2. Step-by-step derivation
    1. times-frac86.3%

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
    2. *-commutative86.3%

      \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
  3. Simplified86.3%

    \[\leadsto \color{blue}{\frac{a2}{b2} \cdot \frac{a1}{b1}} \]
  4. Step-by-step derivation
    1. *-commutative86.3%

      \[\leadsto \color{blue}{\frac{a1}{b1} \cdot \frac{a2}{b2}} \]
    2. clear-num86.0%

      \[\leadsto \color{blue}{\frac{1}{\frac{b1}{a1}}} \cdot \frac{a2}{b2} \]
    3. frac-times89.4%

      \[\leadsto \color{blue}{\frac{1 \cdot a2}{\frac{b1}{a1} \cdot b2}} \]
    4. *-un-lft-identity89.4%

      \[\leadsto \frac{\color{blue}{a2}}{\frac{b1}{a1} \cdot b2} \]
  5. Applied egg-rr89.4%

    \[\leadsto \color{blue}{\frac{a2}{\frac{b1}{a1} \cdot b2}} \]
  6. Final simplification89.4%

    \[\leadsto \frac{a2}{b2 \cdot \frac{b1}{a1}} \]

Developer target: 86.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a1}{b1} \cdot \frac{a2}{b2} \end{array} \]
(FPCore (a1 a2 b1 b2) :precision binary64 (* (/ a1 b1) (/ a2 b2)))
double code(double a1, double a2, double b1, double b2) {
	return (a1 / b1) * (a2 / b2);
}
real(8) function code(a1, a2, b1, b2)
    real(8), intent (in) :: a1
    real(8), intent (in) :: a2
    real(8), intent (in) :: b1
    real(8), intent (in) :: b2
    code = (a1 / b1) * (a2 / b2)
end function
public static double code(double a1, double a2, double b1, double b2) {
	return (a1 / b1) * (a2 / b2);
}
def code(a1, a2, b1, b2):
	return (a1 / b1) * (a2 / b2)
function code(a1, a2, b1, b2)
	return Float64(Float64(a1 / b1) * Float64(a2 / b2))
end
function tmp = code(a1, a2, b1, b2)
	tmp = (a1 / b1) * (a2 / b2);
end
code[a1_, a2_, b1_, b2_] := N[(N[(a1 / b1), $MachinePrecision] * N[(a2 / b2), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a1}{b1} \cdot \frac{a2}{b2}
\end{array}

Reproduce

?
herbie shell --seed 2023271 
(FPCore (a1 a2 b1 b2)
  :name "Quotient of products"
  :precision binary64

  :herbie-target
  (* (/ a1 b1) (/ a2 b2))

  (/ (* a1 a2) (* b1 b2)))