Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[x - \frac{y}{1 + \frac{x \cdot y}{2}}
\]
↓
\[x - \frac{y}{1 + \frac{x \cdot y}{2}}
\]
(FPCore (x y) :precision binary64 (- x (/ y (+ 1.0 (/ (* x y) 2.0))))) ↓
(FPCore (x y) :precision binary64 (- x (/ y (+ 1.0 (/ (* x y) 2.0))))) double code(double x, double y) {
return x - (y / (1.0 + ((x * y) / 2.0)));
}
↓
double code(double x, double y) {
return x - (y / (1.0 + ((x * y) / 2.0)));
}
real(8) function code(x, y)
real(8), intent (in) :: x
real(8), intent (in) :: y
code = x - (y / (1.0d0 + ((x * y) / 2.0d0)))
end function
↓
real(8) function code(x, y)
real(8), intent (in) :: x
real(8), intent (in) :: y
code = x - (y / (1.0d0 + ((x * y) / 2.0d0)))
end function
public static double code(double x, double y) {
return x - (y / (1.0 + ((x * y) / 2.0)));
}
↓
public static double code(double x, double y) {
return x - (y / (1.0 + ((x * y) / 2.0)));
}
def code(x, y):
return x - (y / (1.0 + ((x * y) / 2.0)))
↓
def code(x, y):
return x - (y / (1.0 + ((x * y) / 2.0)))
function code(x, y)
return Float64(x - Float64(y / Float64(1.0 + Float64(Float64(x * y) / 2.0))))
end
↓
function code(x, y)
return Float64(x - Float64(y / Float64(1.0 + Float64(Float64(x * y) / 2.0))))
end
function tmp = code(x, y)
tmp = x - (y / (1.0 + ((x * y) / 2.0)));
end
↓
function tmp = code(x, y)
tmp = x - (y / (1.0 + ((x * y) / 2.0)));
end
code[x_, y_] := N[(x - N[(y / N[(1.0 + N[(N[(x * y), $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_] := N[(x - N[(y / N[(1.0 + N[(N[(x * y), $MachinePrecision] / 2.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
x - \frac{y}{1 + \frac{x \cdot y}{2}}
↓
x - \frac{y}{1 + \frac{x \cdot y}{2}}
Alternatives Alternative 1 Accuracy 99.9% Cost 704
\[x - \frac{y}{1 + \frac{x \cdot y}{2}}
\]
Alternative 2 Accuracy 86.5% Cost 720
\[\begin{array}{l}
\mathbf{if}\;x \leq -6.5 \cdot 10^{-52}:\\
\;\;\;\;x\\
\mathbf{elif}\;x \leq -3.4 \cdot 10^{-94}:\\
\;\;\;\;\frac{-2}{x}\\
\mathbf{elif}\;x \leq 1.25 \cdot 10^{-44}:\\
\;\;\;\;x - y\\
\mathbf{elif}\;x \leq 2.2 \cdot 10^{-5}:\\
\;\;\;\;\frac{-2}{x}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 3 Accuracy 99.9% Cost 704
\[x - \frac{y}{1 + \frac{x}{\frac{2}{y}}}
\]
Alternative 4 Accuracy 91.1% Cost 585
\[\begin{array}{l}
\mathbf{if}\;y \leq -2.9 \cdot 10^{+65} \lor \neg \left(y \leq 8 \cdot 10^{+110}\right):\\
\;\;\;\;x - \frac{2}{x}\\
\mathbf{else}:\\
\;\;\;\;x - y\\
\end{array}
\]
Alternative 5 Accuracy 87.8% Cost 456
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.42:\\
\;\;\;\;x\\
\mathbf{elif}\;x \leq 1.55 \cdot 10^{-9}:\\
\;\;\;\;x - y\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 6 Accuracy 78.7% Cost 392
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.6 \cdot 10^{-94}:\\
\;\;\;\;x\\
\mathbf{elif}\;x \leq 5.2 \cdot 10^{-160}:\\
\;\;\;\;-y\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 7 Accuracy 63.5% Cost 64
\[x
\]