Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[x \cdot \frac{\sin y}{y}
\]
↓
\[\frac{x}{\frac{y}{\sin y}}
\]
(FPCore (x y) :precision binary64 (* x (/ (sin y) y))) ↓
(FPCore (x y) :precision binary64 (/ x (/ y (sin y)))) double code(double x, double y) {
return x * (sin(y) / y);
}
↓
double code(double x, double y) {
return x / (y / sin(y));
}
real(8) function code(x, y)
real(8), intent (in) :: x
real(8), intent (in) :: y
code = x * (sin(y) / y)
end function
↓
real(8) function code(x, y)
real(8), intent (in) :: x
real(8), intent (in) :: y
code = x / (y / sin(y))
end function
public static double code(double x, double y) {
return x * (Math.sin(y) / y);
}
↓
public static double code(double x, double y) {
return x / (y / Math.sin(y));
}
def code(x, y):
return x * (math.sin(y) / y)
↓
def code(x, y):
return x / (y / math.sin(y))
function code(x, y)
return Float64(x * Float64(sin(y) / y))
end
↓
function code(x, y)
return Float64(x / Float64(y / sin(y)))
end
function tmp = code(x, y)
tmp = x * (sin(y) / y);
end
↓
function tmp = code(x, y)
tmp = x / (y / sin(y));
end
code[x_, y_] := N[(x * N[(N[Sin[y], $MachinePrecision] / y), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_] := N[(x / N[(y / N[Sin[y], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
x \cdot \frac{\sin y}{y}
↓
\frac{x}{\frac{y}{\sin y}}
Alternatives Alternative 1 Accuracy 99.7% Cost 6720
\[\frac{x}{\frac{y}{\sin y}}
\]
Alternative 2 Accuracy 99.8% Cost 6720
\[x \cdot \frac{\sin y}{y}
\]
Alternative 3 Accuracy 63.3% Cost 840
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.1:\\
\;\;\;\;\frac{x}{y} \cdot \frac{-6}{y}\\
\mathbf{elif}\;y \leq 12.5:\\
\;\;\;\;x \cdot \left(1 + \left(y \cdot y\right) \cdot -0.16666666666666666\right)\\
\mathbf{else}:\\
\;\;\;\;6 \cdot \frac{x}{y \cdot y}\\
\end{array}
\]
Alternative 4 Accuracy 63.0% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -2.4 \lor \neg \left(y \leq 2.45\right):\\
\;\;\;\;6 \cdot \frac{x}{y \cdot y}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 5 Accuracy 63.0% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -30000 \lor \neg \left(y \leq 215\right):\\
\;\;\;\;\frac{x}{y} \cdot \frac{-6}{y}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 6 Accuracy 61.6% Cost 585
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.55 \cdot 10^{+60} \lor \neg \left(y \leq 2.45 \cdot 10^{-8}\right):\\
\;\;\;\;y \cdot \frac{x}{y}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 7 Accuracy 62.3% Cost 585
\[\begin{array}{l}
\mathbf{if}\;y \leq -6.6 \cdot 10^{+59} \lor \neg \left(y \leq 10^{-22}\right):\\
\;\;\;\;\frac{y}{\frac{y}{x}}\\
\mathbf{else}:\\
\;\;\;\;x\\
\end{array}
\]
Alternative 8 Accuracy 62.9% Cost 576
\[\frac{x}{1 + \left(y \cdot y\right) \cdot -0.16666666666666666}
\]
Alternative 9 Accuracy 63.3% Cost 576
\[\frac{x}{1 + 0.16666666666666666 \cdot \left(y \cdot y\right)}
\]
Alternative 10 Accuracy 51.6% Cost 64
\[x
\]