Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{x \cdot 2}{y \cdot z - t \cdot z}
\]
↓
\[\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -5 \cdot 10^{-206}:\\
\;\;\;\;x \cdot \frac{2}{z \cdot \left(y - t\right)}\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{-279}:\\
\;\;\;\;\frac{\frac{2}{y - t}}{\frac{z}{x}}\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{+194}:\\
\;\;\;\;\frac{x \cdot 2}{t_1}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\frac{z}{2} \cdot \frac{y - t}{x}}\\
\end{array}
\]
(FPCore (x y z t) :precision binary64 (/ (* x 2.0) (- (* y z) (* t z)))) ↓
(FPCore (x y z t)
:precision binary64
(let* ((t_1 (- (* y z) (* z t))))
(if (<= t_1 -5e-206)
(* x (/ 2.0 (* z (- y t))))
(if (<= t_1 5e-279)
(/ (/ 2.0 (- y t)) (/ z x))
(if (<= t_1 5e+194)
(/ (* x 2.0) t_1)
(/ 1.0 (* (/ z 2.0) (/ (- y t) x)))))))) double code(double x, double y, double z, double t) {
return (x * 2.0) / ((y * z) - (t * z));
}
↓
double code(double x, double y, double z, double t) {
double t_1 = (y * z) - (z * t);
double tmp;
if (t_1 <= -5e-206) {
tmp = x * (2.0 / (z * (y - t)));
} else if (t_1 <= 5e-279) {
tmp = (2.0 / (y - t)) / (z / x);
} else if (t_1 <= 5e+194) {
tmp = (x * 2.0) / t_1;
} else {
tmp = 1.0 / ((z / 2.0) * ((y - t) / x));
}
return tmp;
}
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = (x * 2.0d0) / ((y * z) - (t * z))
end function
↓
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
real(8) :: t_1
real(8) :: tmp
t_1 = (y * z) - (z * t)
if (t_1 <= (-5d-206)) then
tmp = x * (2.0d0 / (z * (y - t)))
else if (t_1 <= 5d-279) then
tmp = (2.0d0 / (y - t)) / (z / x)
else if (t_1 <= 5d+194) then
tmp = (x * 2.0d0) / t_1
else
tmp = 1.0d0 / ((z / 2.0d0) * ((y - t) / x))
end if
code = tmp
end function
public static double code(double x, double y, double z, double t) {
return (x * 2.0) / ((y * z) - (t * z));
}
↓
public static double code(double x, double y, double z, double t) {
double t_1 = (y * z) - (z * t);
double tmp;
if (t_1 <= -5e-206) {
tmp = x * (2.0 / (z * (y - t)));
} else if (t_1 <= 5e-279) {
tmp = (2.0 / (y - t)) / (z / x);
} else if (t_1 <= 5e+194) {
tmp = (x * 2.0) / t_1;
} else {
tmp = 1.0 / ((z / 2.0) * ((y - t) / x));
}
return tmp;
}
def code(x, y, z, t):
return (x * 2.0) / ((y * z) - (t * z))
↓
def code(x, y, z, t):
t_1 = (y * z) - (z * t)
tmp = 0
if t_1 <= -5e-206:
tmp = x * (2.0 / (z * (y - t)))
elif t_1 <= 5e-279:
tmp = (2.0 / (y - t)) / (z / x)
elif t_1 <= 5e+194:
tmp = (x * 2.0) / t_1
else:
tmp = 1.0 / ((z / 2.0) * ((y - t) / x))
return tmp
function code(x, y, z, t)
return Float64(Float64(x * 2.0) / Float64(Float64(y * z) - Float64(t * z)))
end
↓
function code(x, y, z, t)
t_1 = Float64(Float64(y * z) - Float64(z * t))
tmp = 0.0
if (t_1 <= -5e-206)
tmp = Float64(x * Float64(2.0 / Float64(z * Float64(y - t))));
elseif (t_1 <= 5e-279)
tmp = Float64(Float64(2.0 / Float64(y - t)) / Float64(z / x));
elseif (t_1 <= 5e+194)
tmp = Float64(Float64(x * 2.0) / t_1);
else
tmp = Float64(1.0 / Float64(Float64(z / 2.0) * Float64(Float64(y - t) / x)));
end
return tmp
end
function tmp = code(x, y, z, t)
tmp = (x * 2.0) / ((y * z) - (t * z));
end
↓
function tmp_2 = code(x, y, z, t)
t_1 = (y * z) - (z * t);
tmp = 0.0;
if (t_1 <= -5e-206)
tmp = x * (2.0 / (z * (y - t)));
elseif (t_1 <= 5e-279)
tmp = (2.0 / (y - t)) / (z / x);
elseif (t_1 <= 5e+194)
tmp = (x * 2.0) / t_1;
else
tmp = 1.0 / ((z / 2.0) * ((y - t) / x));
end
tmp_2 = tmp;
end
code[x_, y_, z_, t_] := N[(N[(x * 2.0), $MachinePrecision] / N[(N[(y * z), $MachinePrecision] - N[(t * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(N[(y * z), $MachinePrecision] - N[(z * t), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -5e-206], N[(x * N[(2.0 / N[(z * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 5e-279], N[(N[(2.0 / N[(y - t), $MachinePrecision]), $MachinePrecision] / N[(z / x), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 5e+194], N[(N[(x * 2.0), $MachinePrecision] / t$95$1), $MachinePrecision], N[(1.0 / N[(N[(z / 2.0), $MachinePrecision] * N[(N[(y - t), $MachinePrecision] / x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]
\frac{x \cdot 2}{y \cdot z - t \cdot z}
↓
\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -5 \cdot 10^{-206}:\\
\;\;\;\;x \cdot \frac{2}{z \cdot \left(y - t\right)}\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{-279}:\\
\;\;\;\;\frac{\frac{2}{y - t}}{\frac{z}{x}}\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{+194}:\\
\;\;\;\;\frac{x \cdot 2}{t_1}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\frac{z}{2} \cdot \frac{y - t}{x}}\\
\end{array}
Alternatives Alternative 1 Accuracy 96.3% Cost 2252
\[\begin{array}{l}
t_1 := y \cdot z - z \cdot t\\
\mathbf{if}\;t_1 \leq -5 \cdot 10^{-206}:\\
\;\;\;\;x \cdot \frac{2}{z \cdot \left(y - t\right)}\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{-279}:\\
\;\;\;\;\frac{\frac{2}{y - t}}{\frac{z}{x}}\\
\mathbf{elif}\;t_1 \leq 5 \cdot 10^{+194}:\\
\;\;\;\;\frac{x \cdot 2}{t_1}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\frac{z}{2} \cdot \frac{y - t}{x}}\\
\end{array}
\]
Alternative 2 Accuracy 74.1% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -3 \cdot 10^{-55} \lor \neg \left(y \leq 2.6 \cdot 10^{-27}\right):\\
\;\;\;\;x \cdot \frac{2}{y \cdot z}\\
\mathbf{else}:\\
\;\;\;\;-2 \cdot \frac{x}{z \cdot t}\\
\end{array}
\]
Alternative 3 Accuracy 74.7% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.15 \cdot 10^{-55} \lor \neg \left(y \leq 1.18 \cdot 10^{-26}\right):\\
\;\;\;\;x \cdot \frac{2}{y \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{z} \cdot \frac{-2}{t}\\
\end{array}
\]
Alternative 4 Accuracy 74.7% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.16 \cdot 10^{-55} \lor \neg \left(y \leq 2.4 \cdot 10^{-28}\right):\\
\;\;\;\;\frac{x \cdot 2}{y \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{z} \cdot \frac{-2}{t}\\
\end{array}
\]
Alternative 5 Accuracy 74.6% Cost 713
\[\begin{array}{l}
\mathbf{if}\;y \leq -9.6 \cdot 10^{-56} \lor \neg \left(y \leq 2.6 \cdot 10^{-29}\right):\\
\;\;\;\;\frac{x \cdot 2}{y \cdot z}\\
\mathbf{else}:\\
\;\;\;\;\frac{\frac{-2}{\frac{z}{x}}}{t}\\
\end{array}
\]
Alternative 6 Accuracy 93.4% Cost 708
\[\begin{array}{l}
\mathbf{if}\;z \leq -9.2 \cdot 10^{-121}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{2}{z \cdot \left(y - t\right)}\\
\end{array}
\]
Alternative 7 Accuracy 93.8% Cost 708
\[\begin{array}{l}
\mathbf{if}\;z \leq -1.55 \cdot 10^{-121}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{-2}{t - y}}{z}\\
\end{array}
\]
Alternative 8 Accuracy 93.6% Cost 708
\[\begin{array}{l}
\mathbf{if}\;z \leq -5 \cdot 10^{-120}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;\frac{x}{\frac{y - t}{\frac{2}{z}}}\\
\end{array}
\]
Alternative 9 Accuracy 93.7% Cost 708
\[\begin{array}{l}
\mathbf{if}\;z \leq -6.5 \cdot 10^{-120}:\\
\;\;\;\;2 \cdot \frac{\frac{x}{z}}{y - t}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot 2}{z \cdot \left(y - t\right)}\\
\end{array}
\]
Alternative 10 Accuracy 92.0% Cost 576
\[2 \cdot \frac{\frac{x}{z}}{y - t}
\]
Alternative 11 Accuracy 53.0% Cost 448
\[-2 \cdot \frac{x}{z \cdot t}
\]