Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\left(x + y\right) \cdot \left(1 - z\right)
\]
↓
\[\left(1 - z\right) \cdot \left(x + y\right)
\]
(FPCore (x y z) :precision binary64 (* (+ x y) (- 1.0 z))) ↓
(FPCore (x y z) :precision binary64 (* (- 1.0 z) (+ x y))) double code(double x, double y, double z) {
return (x + y) * (1.0 - z);
}
↓
double code(double x, double y, double z) {
return (1.0 - z) * (x + y);
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = (x + y) * (1.0d0 - z)
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = (1.0d0 - z) * (x + y)
end function
public static double code(double x, double y, double z) {
return (x + y) * (1.0 - z);
}
↓
public static double code(double x, double y, double z) {
return (1.0 - z) * (x + y);
}
def code(x, y, z):
return (x + y) * (1.0 - z)
↓
def code(x, y, z):
return (1.0 - z) * (x + y)
function code(x, y, z)
return Float64(Float64(x + y) * Float64(1.0 - z))
end
↓
function code(x, y, z)
return Float64(Float64(1.0 - z) * Float64(x + y))
end
function tmp = code(x, y, z)
tmp = (x + y) * (1.0 - z);
end
↓
function tmp = code(x, y, z)
tmp = (1.0 - z) * (x + y);
end
code[x_, y_, z_] := N[(N[(x + y), $MachinePrecision] * N[(1.0 - z), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := N[(N[(1.0 - z), $MachinePrecision] * N[(x + y), $MachinePrecision]), $MachinePrecision]
\left(x + y\right) \cdot \left(1 - z\right)
↓
\left(1 - z\right) \cdot \left(x + y\right)
Alternatives Alternative 1 Accuracy 100.0% Cost 448
\[\left(1 - z\right) \cdot \left(x + y\right)
\]
Alternative 2 Accuracy 74.9% Cost 1816
\[\begin{array}{l}
t_0 := x \cdot \left(-z\right)\\
t_1 := z \cdot \left(-y\right)\\
\mathbf{if}\;1 - z \leq -1 \cdot 10^{+179}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;1 - z \leq -1 \cdot 10^{+127}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;1 - z \leq -0.4:\\
\;\;\;\;t_0\\
\mathbf{elif}\;1 - z \leq 1:\\
\;\;\;\;x + y\\
\mathbf{elif}\;1 - z \leq 10^{+140}:\\
\;\;\;\;y \cdot \left(1 - z\right)\\
\mathbf{elif}\;1 - z \leq 5 \cdot 10^{+184}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;t_1\\
\end{array}
\]
Alternative 3 Accuracy 74.6% Cost 1314
\[\begin{array}{l}
t_0 := z \cdot \left(-y\right)\\
t_1 := x \cdot \left(-z\right)\\
\mathbf{if}\;z \leq -4.3 \cdot 10^{+189}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;z \leq -1 \cdot 10^{+140}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;z \leq -29000000000000:\\
\;\;\;\;t_0\\
\mathbf{elif}\;z \leq 1:\\
\;\;\;\;x + y\\
\mathbf{elif}\;z \leq 8.6 \cdot 10^{+126} \lor \neg \left(z \leq 9.2 \cdot 10^{+178} \lor \neg \left(z \leq 2.25 \cdot 10^{+222}\right) \land z \leq 3.8 \cdot 10^{+294}\right):\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 4 Accuracy 97.8% Cost 905
\[\begin{array}{l}
\mathbf{if}\;1 - z \leq -0.4 \lor \neg \left(1 - z \leq 2\right):\\
\;\;\;\;\left(x + y\right) \cdot \left(-z\right)\\
\mathbf{else}:\\
\;\;\;\;x + y\\
\end{array}
\]
Alternative 5 Accuracy 74.8% Cost 521
\[\begin{array}{l}
\mathbf{if}\;z \leq -29000000000000 \lor \neg \left(z \leq 1\right):\\
\;\;\;\;z \cdot \left(-y\right)\\
\mathbf{else}:\\
\;\;\;\;x + y\\
\end{array}
\]
Alternative 6 Accuracy 64.4% Cost 452
\[\begin{array}{l}
\mathbf{if}\;y \leq 4.4 \cdot 10^{-50}:\\
\;\;\;\;x - x \cdot z\\
\mathbf{else}:\\
\;\;\;\;y \cdot \left(1 - z\right)\\
\end{array}
\]
Alternative 7 Accuracy 50.9% Cost 192
\[x + y
\]
Alternative 8 Accuracy 26.8% Cost 64
\[x
\]