Graphics.Rasterific.Shading:$sradialGradientWithFocusShader from Rasterific-0.6.1, B

Percentage Accurate: 91.3% → 95.6%
Time: 7.5s
Alternatives: 8
Speedup: 0.8×

Specification

?
\[\begin{array}{l} \\ x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \end{array} \]
(FPCore (x y z t) :precision binary64 (- (* x x) (* (* y 4.0) (- (* z z) t))))
double code(double x, double y, double z, double t) {
	return (x * x) - ((y * 4.0) * ((z * z) - t));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x * x) - ((y * 4.0d0) * ((z * z) - t))
end function
public static double code(double x, double y, double z, double t) {
	return (x * x) - ((y * 4.0) * ((z * z) - t));
}
def code(x, y, z, t):
	return (x * x) - ((y * 4.0) * ((z * z) - t))
function code(x, y, z, t)
	return Float64(Float64(x * x) - Float64(Float64(y * 4.0) * Float64(Float64(z * z) - t)))
end
function tmp = code(x, y, z, t)
	tmp = (x * x) - ((y * 4.0) * ((z * z) - t));
end
code[x_, y_, z_, t_] := N[(N[(x * x), $MachinePrecision] - N[(N[(y * 4.0), $MachinePrecision] * N[(N[(z * z), $MachinePrecision] - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right)
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 91.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \end{array} \]
(FPCore (x y z t) :precision binary64 (- (* x x) (* (* y 4.0) (- (* z z) t))))
double code(double x, double y, double z, double t) {
	return (x * x) - ((y * 4.0) * ((z * z) - t));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x * x) - ((y * 4.0d0) * ((z * z) - t))
end function
public static double code(double x, double y, double z, double t) {
	return (x * x) - ((y * 4.0) * ((z * z) - t));
}
def code(x, y, z, t):
	return (x * x) - ((y * 4.0) * ((z * z) - t))
function code(x, y, z, t)
	return Float64(Float64(x * x) - Float64(Float64(y * 4.0) * Float64(Float64(z * z) - t)))
end
function tmp = code(x, y, z, t)
	tmp = (x * x) - ((y * 4.0) * ((z * z) - t));
end
code[x_, y_, z_, t_] := N[(N[(x * x), $MachinePrecision] - N[(N[(y * 4.0), $MachinePrecision] * N[(N[(z * z), $MachinePrecision] - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right)
\end{array}

Alternative 1: 95.6% accurate, 0.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z \cdot z \leq 10^{+254}:\\ \;\;\;\;\mathsf{fma}\left(x, x, \left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\right)\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= (* z z) 1e+254)
   (fma x x (* (- (* z z) t) (* y -4.0)))
   (* -4.0 (* z (* z y)))))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((z * z) <= 1e+254) {
		tmp = fma(x, x, (((z * z) - t) * (y * -4.0)));
	} else {
		tmp = -4.0 * (z * (z * y));
	}
	return tmp;
}
function code(x, y, z, t)
	tmp = 0.0
	if (Float64(z * z) <= 1e+254)
		tmp = fma(x, x, Float64(Float64(Float64(z * z) - t) * Float64(y * -4.0)));
	else
		tmp = Float64(-4.0 * Float64(z * Float64(z * y)));
	end
	return tmp
end
code[x_, y_, z_, t_] := If[LessEqual[N[(z * z), $MachinePrecision], 1e+254], N[(x * x + N[(N[(N[(z * z), $MachinePrecision] - t), $MachinePrecision] * N[(y * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-4.0 * N[(z * N[(z * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z \cdot z \leq 10^{+254}:\\
\;\;\;\;\mathsf{fma}\left(x, x, \left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\right)\\

\mathbf{else}:\\
\;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 z z) < 9.9999999999999994e253

    1. Initial program 96.5%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Step-by-step derivation
      1. fma-neg97.6%

        \[\leadsto \color{blue}{\mathsf{fma}\left(x, x, -\left(y \cdot 4\right) \cdot \left(z \cdot z - t\right)\right)} \]
      2. *-commutative97.6%

        \[\leadsto \mathsf{fma}\left(x, x, -\color{blue}{\left(z \cdot z - t\right) \cdot \left(y \cdot 4\right)}\right) \]
      3. distribute-rgt-neg-in97.6%

        \[\leadsto \mathsf{fma}\left(x, x, \color{blue}{\left(z \cdot z - t\right) \cdot \left(-y \cdot 4\right)}\right) \]
      4. distribute-rgt-neg-in97.6%

        \[\leadsto \mathsf{fma}\left(x, x, \left(z \cdot z - t\right) \cdot \color{blue}{\left(y \cdot \left(-4\right)\right)}\right) \]
      5. metadata-eval97.6%

        \[\leadsto \mathsf{fma}\left(x, x, \left(z \cdot z - t\right) \cdot \left(y \cdot \color{blue}{-4}\right)\right) \]
    3. Simplified97.6%

      \[\leadsto \color{blue}{\mathsf{fma}\left(x, x, \left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\right)} \]

    if 9.9999999999999994e253 < (*.f64 z z)

    1. Initial program 69.9%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in z around inf 78.3%

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot {z}^{2}\right)} \]
    3. Step-by-step derivation
      1. unpow278.3%

        \[\leadsto -4 \cdot \left(y \cdot \color{blue}{\left(z \cdot z\right)}\right) \]
      2. *-commutative78.3%

        \[\leadsto -4 \cdot \color{blue}{\left(\left(z \cdot z\right) \cdot y\right)} \]
      3. associate-*l*83.6%

        \[\leadsto -4 \cdot \color{blue}{\left(z \cdot \left(z \cdot y\right)\right)} \]
    4. Simplified83.6%

      \[\leadsto \color{blue}{-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification93.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \cdot z \leq 10^{+254}:\\ \;\;\;\;\mathsf{fma}\left(x, x, \left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\right)\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\ \end{array} \]

Alternative 2: 95.2% accurate, 0.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z \cdot z \leq 10^{+254}:\\ \;\;\;\;x \cdot x + \left(y \cdot 4\right) \cdot \left(t - z \cdot z\right)\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= (* z z) 1e+254)
   (+ (* x x) (* (* y 4.0) (- t (* z z))))
   (* -4.0 (* z (* z y)))))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((z * z) <= 1e+254) {
		tmp = (x * x) + ((y * 4.0) * (t - (z * z)));
	} else {
		tmp = -4.0 * (z * (z * y));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((z * z) <= 1d+254) then
        tmp = (x * x) + ((y * 4.0d0) * (t - (z * z)))
    else
        tmp = (-4.0d0) * (z * (z * y))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((z * z) <= 1e+254) {
		tmp = (x * x) + ((y * 4.0) * (t - (z * z)));
	} else {
		tmp = -4.0 * (z * (z * y));
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (z * z) <= 1e+254:
		tmp = (x * x) + ((y * 4.0) * (t - (z * z)))
	else:
		tmp = -4.0 * (z * (z * y))
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (Float64(z * z) <= 1e+254)
		tmp = Float64(Float64(x * x) + Float64(Float64(y * 4.0) * Float64(t - Float64(z * z))));
	else
		tmp = Float64(-4.0 * Float64(z * Float64(z * y)));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((z * z) <= 1e+254)
		tmp = (x * x) + ((y * 4.0) * (t - (z * z)));
	else
		tmp = -4.0 * (z * (z * y));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[N[(z * z), $MachinePrecision], 1e+254], N[(N[(x * x), $MachinePrecision] + N[(N[(y * 4.0), $MachinePrecision] * N[(t - N[(z * z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-4.0 * N[(z * N[(z * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z \cdot z \leq 10^{+254}:\\
\;\;\;\;x \cdot x + \left(y \cdot 4\right) \cdot \left(t - z \cdot z\right)\\

\mathbf{else}:\\
\;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 z z) < 9.9999999999999994e253

    1. Initial program 96.5%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]

    if 9.9999999999999994e253 < (*.f64 z z)

    1. Initial program 69.9%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in z around inf 78.3%

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot {z}^{2}\right)} \]
    3. Step-by-step derivation
      1. unpow278.3%

        \[\leadsto -4 \cdot \left(y \cdot \color{blue}{\left(z \cdot z\right)}\right) \]
      2. *-commutative78.3%

        \[\leadsto -4 \cdot \color{blue}{\left(\left(z \cdot z\right) \cdot y\right)} \]
      3. associate-*l*83.6%

        \[\leadsto -4 \cdot \color{blue}{\left(z \cdot \left(z \cdot y\right)\right)} \]
    4. Simplified83.6%

      \[\leadsto \color{blue}{-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification92.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \cdot z \leq 10^{+254}:\\ \;\;\;\;x \cdot x + \left(y \cdot 4\right) \cdot \left(t - z \cdot z\right)\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\ \end{array} \]

Alternative 3: 45.4% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := t \cdot \left(y \cdot 4\right)\\ \mathbf{if}\;z \leq 2.75 \cdot 10^{-269}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq 1.55 \cdot 10^{-177}:\\ \;\;\;\;x \cdot x\\ \mathbf{elif}\;z \leq 6.2 \cdot 10^{-26}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq 1.6 \cdot 10^{+27}:\\ \;\;\;\;x \cdot x\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(\left(z \cdot z\right) \cdot y\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* t (* y 4.0))))
   (if (<= z 2.75e-269)
     t_1
     (if (<= z 1.55e-177)
       (* x x)
       (if (<= z 6.2e-26)
         t_1
         (if (<= z 1.6e+27) (* x x) (* -4.0 (* (* z z) y))))))))
double code(double x, double y, double z, double t) {
	double t_1 = t * (y * 4.0);
	double tmp;
	if (z <= 2.75e-269) {
		tmp = t_1;
	} else if (z <= 1.55e-177) {
		tmp = x * x;
	} else if (z <= 6.2e-26) {
		tmp = t_1;
	} else if (z <= 1.6e+27) {
		tmp = x * x;
	} else {
		tmp = -4.0 * ((z * z) * y);
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = t * (y * 4.0d0)
    if (z <= 2.75d-269) then
        tmp = t_1
    else if (z <= 1.55d-177) then
        tmp = x * x
    else if (z <= 6.2d-26) then
        tmp = t_1
    else if (z <= 1.6d+27) then
        tmp = x * x
    else
        tmp = (-4.0d0) * ((z * z) * y)
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = t * (y * 4.0);
	double tmp;
	if (z <= 2.75e-269) {
		tmp = t_1;
	} else if (z <= 1.55e-177) {
		tmp = x * x;
	} else if (z <= 6.2e-26) {
		tmp = t_1;
	} else if (z <= 1.6e+27) {
		tmp = x * x;
	} else {
		tmp = -4.0 * ((z * z) * y);
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = t * (y * 4.0)
	tmp = 0
	if z <= 2.75e-269:
		tmp = t_1
	elif z <= 1.55e-177:
		tmp = x * x
	elif z <= 6.2e-26:
		tmp = t_1
	elif z <= 1.6e+27:
		tmp = x * x
	else:
		tmp = -4.0 * ((z * z) * y)
	return tmp
function code(x, y, z, t)
	t_1 = Float64(t * Float64(y * 4.0))
	tmp = 0.0
	if (z <= 2.75e-269)
		tmp = t_1;
	elseif (z <= 1.55e-177)
		tmp = Float64(x * x);
	elseif (z <= 6.2e-26)
		tmp = t_1;
	elseif (z <= 1.6e+27)
		tmp = Float64(x * x);
	else
		tmp = Float64(-4.0 * Float64(Float64(z * z) * y));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = t * (y * 4.0);
	tmp = 0.0;
	if (z <= 2.75e-269)
		tmp = t_1;
	elseif (z <= 1.55e-177)
		tmp = x * x;
	elseif (z <= 6.2e-26)
		tmp = t_1;
	elseif (z <= 1.6e+27)
		tmp = x * x;
	else
		tmp = -4.0 * ((z * z) * y);
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(t * N[(y * 4.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[z, 2.75e-269], t$95$1, If[LessEqual[z, 1.55e-177], N[(x * x), $MachinePrecision], If[LessEqual[z, 6.2e-26], t$95$1, If[LessEqual[z, 1.6e+27], N[(x * x), $MachinePrecision], N[(-4.0 * N[(N[(z * z), $MachinePrecision] * y), $MachinePrecision]), $MachinePrecision]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := t \cdot \left(y \cdot 4\right)\\
\mathbf{if}\;z \leq 2.75 \cdot 10^{-269}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;z \leq 1.55 \cdot 10^{-177}:\\
\;\;\;\;x \cdot x\\

\mathbf{elif}\;z \leq 6.2 \cdot 10^{-26}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;z \leq 1.6 \cdot 10^{+27}:\\
\;\;\;\;x \cdot x\\

\mathbf{else}:\\
\;\;\;\;-4 \cdot \left(\left(z \cdot z\right) \cdot y\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if z < 2.75000000000000005e-269 or 1.55000000000000009e-177 < z < 6.19999999999999966e-26

    1. Initial program 91.0%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in t around inf 42.5%

      \[\leadsto \color{blue}{4 \cdot \left(y \cdot t\right)} \]
    3. Step-by-step derivation
      1. associate-*r*42.5%

        \[\leadsto \color{blue}{\left(4 \cdot y\right) \cdot t} \]
    4. Simplified42.5%

      \[\leadsto \color{blue}{\left(4 \cdot y\right) \cdot t} \]

    if 2.75000000000000005e-269 < z < 1.55000000000000009e-177 or 6.19999999999999966e-26 < z < 1.60000000000000008e27

    1. Initial program 95.2%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in x around inf 67.5%

      \[\leadsto \color{blue}{{x}^{2}} \]
    3. Step-by-step derivation
      1. unpow267.5%

        \[\leadsto \color{blue}{x \cdot x} \]
    4. Simplified67.5%

      \[\leadsto \color{blue}{x \cdot x} \]

    if 1.60000000000000008e27 < z

    1. Initial program 78.8%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in z around inf 68.7%

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot {z}^{2}\right)} \]
    3. Step-by-step derivation
      1. unpow268.7%

        \[\leadsto -4 \cdot \left(y \cdot \color{blue}{\left(z \cdot z\right)}\right) \]
    4. Simplified68.7%

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot \left(z \cdot z\right)\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification52.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq 2.75 \cdot 10^{-269}:\\ \;\;\;\;t \cdot \left(y \cdot 4\right)\\ \mathbf{elif}\;z \leq 1.55 \cdot 10^{-177}:\\ \;\;\;\;x \cdot x\\ \mathbf{elif}\;z \leq 6.2 \cdot 10^{-26}:\\ \;\;\;\;t \cdot \left(y \cdot 4\right)\\ \mathbf{elif}\;z \leq 1.6 \cdot 10^{+27}:\\ \;\;\;\;x \cdot x\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(\left(z \cdot z\right) \cdot y\right)\\ \end{array} \]

Alternative 4: 47.0% accurate, 0.9× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := t \cdot \left(y \cdot 4\right)\\ \mathbf{if}\;z \leq 2.42 \cdot 10^{-269}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq 7.8 \cdot 10^{-177}:\\ \;\;\;\;x \cdot x\\ \mathbf{elif}\;z \leq 4.8 \cdot 10^{-25}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;z \leq 1.75 \cdot 10^{+26}:\\ \;\;\;\;x \cdot x\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (let* ((t_1 (* t (* y 4.0))))
   (if (<= z 2.42e-269)
     t_1
     (if (<= z 7.8e-177)
       (* x x)
       (if (<= z 4.8e-25)
         t_1
         (if (<= z 1.75e+26) (* x x) (* -4.0 (* z (* z y)))))))))
double code(double x, double y, double z, double t) {
	double t_1 = t * (y * 4.0);
	double tmp;
	if (z <= 2.42e-269) {
		tmp = t_1;
	} else if (z <= 7.8e-177) {
		tmp = x * x;
	} else if (z <= 4.8e-25) {
		tmp = t_1;
	} else if (z <= 1.75e+26) {
		tmp = x * x;
	} else {
		tmp = -4.0 * (z * (z * y));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: t_1
    real(8) :: tmp
    t_1 = t * (y * 4.0d0)
    if (z <= 2.42d-269) then
        tmp = t_1
    else if (z <= 7.8d-177) then
        tmp = x * x
    else if (z <= 4.8d-25) then
        tmp = t_1
    else if (z <= 1.75d+26) then
        tmp = x * x
    else
        tmp = (-4.0d0) * (z * (z * y))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double t_1 = t * (y * 4.0);
	double tmp;
	if (z <= 2.42e-269) {
		tmp = t_1;
	} else if (z <= 7.8e-177) {
		tmp = x * x;
	} else if (z <= 4.8e-25) {
		tmp = t_1;
	} else if (z <= 1.75e+26) {
		tmp = x * x;
	} else {
		tmp = -4.0 * (z * (z * y));
	}
	return tmp;
}
def code(x, y, z, t):
	t_1 = t * (y * 4.0)
	tmp = 0
	if z <= 2.42e-269:
		tmp = t_1
	elif z <= 7.8e-177:
		tmp = x * x
	elif z <= 4.8e-25:
		tmp = t_1
	elif z <= 1.75e+26:
		tmp = x * x
	else:
		tmp = -4.0 * (z * (z * y))
	return tmp
function code(x, y, z, t)
	t_1 = Float64(t * Float64(y * 4.0))
	tmp = 0.0
	if (z <= 2.42e-269)
		tmp = t_1;
	elseif (z <= 7.8e-177)
		tmp = Float64(x * x);
	elseif (z <= 4.8e-25)
		tmp = t_1;
	elseif (z <= 1.75e+26)
		tmp = Float64(x * x);
	else
		tmp = Float64(-4.0 * Float64(z * Float64(z * y)));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	t_1 = t * (y * 4.0);
	tmp = 0.0;
	if (z <= 2.42e-269)
		tmp = t_1;
	elseif (z <= 7.8e-177)
		tmp = x * x;
	elseif (z <= 4.8e-25)
		tmp = t_1;
	elseif (z <= 1.75e+26)
		tmp = x * x;
	else
		tmp = -4.0 * (z * (z * y));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := Block[{t$95$1 = N[(t * N[(y * 4.0), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[z, 2.42e-269], t$95$1, If[LessEqual[z, 7.8e-177], N[(x * x), $MachinePrecision], If[LessEqual[z, 4.8e-25], t$95$1, If[LessEqual[z, 1.75e+26], N[(x * x), $MachinePrecision], N[(-4.0 * N[(z * N[(z * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := t \cdot \left(y \cdot 4\right)\\
\mathbf{if}\;z \leq 2.42 \cdot 10^{-269}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;z \leq 7.8 \cdot 10^{-177}:\\
\;\;\;\;x \cdot x\\

\mathbf{elif}\;z \leq 4.8 \cdot 10^{-25}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;z \leq 1.75 \cdot 10^{+26}:\\
\;\;\;\;x \cdot x\\

\mathbf{else}:\\
\;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if z < 2.42e-269 or 7.80000000000000028e-177 < z < 4.80000000000000018e-25

    1. Initial program 91.0%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in t around inf 42.5%

      \[\leadsto \color{blue}{4 \cdot \left(y \cdot t\right)} \]
    3. Step-by-step derivation
      1. associate-*r*42.5%

        \[\leadsto \color{blue}{\left(4 \cdot y\right) \cdot t} \]
    4. Simplified42.5%

      \[\leadsto \color{blue}{\left(4 \cdot y\right) \cdot t} \]

    if 2.42e-269 < z < 7.80000000000000028e-177 or 4.80000000000000018e-25 < z < 1.75e26

    1. Initial program 95.2%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in x around inf 67.5%

      \[\leadsto \color{blue}{{x}^{2}} \]
    3. Step-by-step derivation
      1. unpow267.5%

        \[\leadsto \color{blue}{x \cdot x} \]
    4. Simplified67.5%

      \[\leadsto \color{blue}{x \cdot x} \]

    if 1.75e26 < z

    1. Initial program 78.8%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in z around inf 68.7%

      \[\leadsto \color{blue}{-4 \cdot \left(y \cdot {z}^{2}\right)} \]
    3. Step-by-step derivation
      1. unpow268.7%

        \[\leadsto -4 \cdot \left(y \cdot \color{blue}{\left(z \cdot z\right)}\right) \]
      2. *-commutative68.7%

        \[\leadsto -4 \cdot \color{blue}{\left(\left(z \cdot z\right) \cdot y\right)} \]
      3. associate-*l*71.0%

        \[\leadsto -4 \cdot \color{blue}{\left(z \cdot \left(z \cdot y\right)\right)} \]
    4. Simplified71.0%

      \[\leadsto \color{blue}{-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification52.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq 2.42 \cdot 10^{-269}:\\ \;\;\;\;t \cdot \left(y \cdot 4\right)\\ \mathbf{elif}\;z \leq 7.8 \cdot 10^{-177}:\\ \;\;\;\;x \cdot x\\ \mathbf{elif}\;z \leq 4.8 \cdot 10^{-25}:\\ \;\;\;\;t \cdot \left(y \cdot 4\right)\\ \mathbf{elif}\;z \leq 1.75 \cdot 10^{+26}:\\ \;\;\;\;x \cdot x\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(z \cdot \left(z \cdot y\right)\right)\\ \end{array} \]

Alternative 5: 80.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \cdot x \leq 2.3 \cdot 10^{+118}:\\ \;\;\;\;\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot x\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= (* x x) 2.3e+118) (* (- (* z z) t) (* y -4.0)) (* x x)))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((x * x) <= 2.3e+118) {
		tmp = ((z * z) - t) * (y * -4.0);
	} else {
		tmp = x * x;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((x * x) <= 2.3d+118) then
        tmp = ((z * z) - t) * (y * (-4.0d0))
    else
        tmp = x * x
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((x * x) <= 2.3e+118) {
		tmp = ((z * z) - t) * (y * -4.0);
	} else {
		tmp = x * x;
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (x * x) <= 2.3e+118:
		tmp = ((z * z) - t) * (y * -4.0)
	else:
		tmp = x * x
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (Float64(x * x) <= 2.3e+118)
		tmp = Float64(Float64(Float64(z * z) - t) * Float64(y * -4.0));
	else
		tmp = Float64(x * x);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((x * x) <= 2.3e+118)
		tmp = ((z * z) - t) * (y * -4.0);
	else
		tmp = x * x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[N[(x * x), $MachinePrecision], 2.3e+118], N[(N[(N[(z * z), $MachinePrecision] - t), $MachinePrecision] * N[(y * -4.0), $MachinePrecision]), $MachinePrecision], N[(x * x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \cdot x \leq 2.3 \cdot 10^{+118}:\\
\;\;\;\;\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 x x) < 2.30000000000000016e118

    1. Initial program 96.7%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in x around 0 88.8%

      \[\leadsto \color{blue}{-4 \cdot \left(\left({z}^{2} - t\right) \cdot y\right)} \]
    3. Step-by-step derivation
      1. *-commutative88.8%

        \[\leadsto \color{blue}{\left(\left({z}^{2} - t\right) \cdot y\right) \cdot -4} \]
      2. *-commutative88.8%

        \[\leadsto \color{blue}{\left(y \cdot \left({z}^{2} - t\right)\right)} \cdot -4 \]
      3. unpow288.8%

        \[\leadsto \left(y \cdot \left(\color{blue}{z \cdot z} - t\right)\right) \cdot -4 \]
      4. *-commutative88.8%

        \[\leadsto \color{blue}{\left(\left(z \cdot z - t\right) \cdot y\right)} \cdot -4 \]
      5. associate-*l*88.8%

        \[\leadsto \color{blue}{\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)} \]
    4. Simplified88.8%

      \[\leadsto \color{blue}{\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)} \]

    if 2.30000000000000016e118 < (*.f64 x x)

    1. Initial program 71.6%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in x around inf 78.4%

      \[\leadsto \color{blue}{{x}^{2}} \]
    3. Step-by-step derivation
      1. unpow278.4%

        \[\leadsto \color{blue}{x \cdot x} \]
    4. Simplified78.4%

      \[\leadsto \color{blue}{x \cdot x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification85.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \cdot x \leq 2.3 \cdot 10^{+118}:\\ \;\;\;\;\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot x\\ \end{array} \]

Alternative 6: 82.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \cdot x \leq 6 \cdot 10^{+103}:\\ \;\;\;\;\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot x - t \cdot \left(y \cdot -4\right)\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= (* x x) 6e+103)
   (* (- (* z z) t) (* y -4.0))
   (- (* x x) (* t (* y -4.0)))))
double code(double x, double y, double z, double t) {
	double tmp;
	if ((x * x) <= 6e+103) {
		tmp = ((z * z) - t) * (y * -4.0);
	} else {
		tmp = (x * x) - (t * (y * -4.0));
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if ((x * x) <= 6d+103) then
        tmp = ((z * z) - t) * (y * (-4.0d0))
    else
        tmp = (x * x) - (t * (y * (-4.0d0)))
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if ((x * x) <= 6e+103) {
		tmp = ((z * z) - t) * (y * -4.0);
	} else {
		tmp = (x * x) - (t * (y * -4.0));
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if (x * x) <= 6e+103:
		tmp = ((z * z) - t) * (y * -4.0)
	else:
		tmp = (x * x) - (t * (y * -4.0))
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (Float64(x * x) <= 6e+103)
		tmp = Float64(Float64(Float64(z * z) - t) * Float64(y * -4.0));
	else
		tmp = Float64(Float64(x * x) - Float64(t * Float64(y * -4.0)));
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if ((x * x) <= 6e+103)
		tmp = ((z * z) - t) * (y * -4.0);
	else
		tmp = (x * x) - (t * (y * -4.0));
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[N[(x * x), $MachinePrecision], 6e+103], N[(N[(N[(z * z), $MachinePrecision] - t), $MachinePrecision] * N[(y * -4.0), $MachinePrecision]), $MachinePrecision], N[(N[(x * x), $MachinePrecision] - N[(t * N[(y * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \cdot x \leq 6 \cdot 10^{+103}:\\
\;\;\;\;\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot x - t \cdot \left(y \cdot -4\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 x x) < 6e103

    1. Initial program 96.5%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in x around 0 89.6%

      \[\leadsto \color{blue}{-4 \cdot \left(\left({z}^{2} - t\right) \cdot y\right)} \]
    3. Step-by-step derivation
      1. *-commutative89.6%

        \[\leadsto \color{blue}{\left(\left({z}^{2} - t\right) \cdot y\right) \cdot -4} \]
      2. *-commutative89.6%

        \[\leadsto \color{blue}{\left(y \cdot \left({z}^{2} - t\right)\right)} \cdot -4 \]
      3. unpow289.6%

        \[\leadsto \left(y \cdot \left(\color{blue}{z \cdot z} - t\right)\right) \cdot -4 \]
      4. *-commutative89.6%

        \[\leadsto \color{blue}{\left(\left(z \cdot z - t\right) \cdot y\right)} \cdot -4 \]
      5. associate-*l*89.6%

        \[\leadsto \color{blue}{\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)} \]
    4. Simplified89.6%

      \[\leadsto \color{blue}{\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)} \]

    if 6e103 < (*.f64 x x)

    1. Initial program 73.9%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in z around 0 80.9%

      \[\leadsto x \cdot x - \color{blue}{-4 \cdot \left(y \cdot t\right)} \]
    3. Step-by-step derivation
      1. associate-*r*80.9%

        \[\leadsto x \cdot x - \color{blue}{\left(-4 \cdot y\right) \cdot t} \]
    4. Simplified80.9%

      \[\leadsto x \cdot x - \color{blue}{\left(-4 \cdot y\right) \cdot t} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification86.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \cdot x \leq 6 \cdot 10^{+103}:\\ \;\;\;\;\left(z \cdot z - t\right) \cdot \left(y \cdot -4\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot x - t \cdot \left(y \cdot -4\right)\\ \end{array} \]

Alternative 7: 44.8% accurate, 1.8× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;x \leq 1.42 \cdot 10^{+59}:\\ \;\;\;\;t \cdot \left(y \cdot 4\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot x\\ \end{array} \end{array} \]
(FPCore (x y z t)
 :precision binary64
 (if (<= x 1.42e+59) (* t (* y 4.0)) (* x x)))
double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= 1.42e+59) {
		tmp = t * (y * 4.0);
	} else {
		tmp = x * x;
	}
	return tmp;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8) :: tmp
    if (x <= 1.42d+59) then
        tmp = t * (y * 4.0d0)
    else
        tmp = x * x
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t) {
	double tmp;
	if (x <= 1.42e+59) {
		tmp = t * (y * 4.0);
	} else {
		tmp = x * x;
	}
	return tmp;
}
def code(x, y, z, t):
	tmp = 0
	if x <= 1.42e+59:
		tmp = t * (y * 4.0)
	else:
		tmp = x * x
	return tmp
function code(x, y, z, t)
	tmp = 0.0
	if (x <= 1.42e+59)
		tmp = Float64(t * Float64(y * 4.0));
	else
		tmp = Float64(x * x);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t)
	tmp = 0.0;
	if (x <= 1.42e+59)
		tmp = t * (y * 4.0);
	else
		tmp = x * x;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_] := If[LessEqual[x, 1.42e+59], N[(t * N[(y * 4.0), $MachinePrecision]), $MachinePrecision], N[(x * x), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;x \leq 1.42 \cdot 10^{+59}:\\
\;\;\;\;t \cdot \left(y \cdot 4\right)\\

\mathbf{else}:\\
\;\;\;\;x \cdot x\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < 1.42000000000000005e59

    1. Initial program 90.6%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in t around inf 38.6%

      \[\leadsto \color{blue}{4 \cdot \left(y \cdot t\right)} \]
    3. Step-by-step derivation
      1. associate-*r*38.6%

        \[\leadsto \color{blue}{\left(4 \cdot y\right) \cdot t} \]
    4. Simplified38.6%

      \[\leadsto \color{blue}{\left(4 \cdot y\right) \cdot t} \]

    if 1.42000000000000005e59 < x

    1. Initial program 73.6%

      \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
    2. Taylor expanded in x around inf 83.5%

      \[\leadsto \color{blue}{{x}^{2}} \]
    3. Step-by-step derivation
      1. unpow283.5%

        \[\leadsto \color{blue}{x \cdot x} \]
    4. Simplified83.5%

      \[\leadsto \color{blue}{x \cdot x} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification45.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq 1.42 \cdot 10^{+59}:\\ \;\;\;\;t \cdot \left(y \cdot 4\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot x\\ \end{array} \]

Alternative 8: 41.4% accurate, 4.3× speedup?

\[\begin{array}{l} \\ x \cdot x \end{array} \]
(FPCore (x y z t) :precision binary64 (* x x))
double code(double x, double y, double z, double t) {
	return x * x;
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = x * x
end function
public static double code(double x, double y, double z, double t) {
	return x * x;
}
def code(x, y, z, t):
	return x * x
function code(x, y, z, t)
	return Float64(x * x)
end
function tmp = code(x, y, z, t)
	tmp = x * x;
end
code[x_, y_, z_, t_] := N[(x * x), $MachinePrecision]
\begin{array}{l}

\\
x \cdot x
\end{array}
Derivation
  1. Initial program 87.8%

    \[x \cdot x - \left(y \cdot 4\right) \cdot \left(z \cdot z - t\right) \]
  2. Taylor expanded in x around inf 34.9%

    \[\leadsto \color{blue}{{x}^{2}} \]
  3. Step-by-step derivation
    1. unpow234.9%

      \[\leadsto \color{blue}{x \cdot x} \]
  4. Simplified34.9%

    \[\leadsto \color{blue}{x \cdot x} \]
  5. Final simplification34.9%

    \[\leadsto x \cdot x \]

Developer target: 91.4% accurate, 1.0× speedup?

\[\begin{array}{l} \\ x \cdot x - 4 \cdot \left(y \cdot \left(z \cdot z - t\right)\right) \end{array} \]
(FPCore (x y z t) :precision binary64 (- (* x x) (* 4.0 (* y (- (* z z) t)))))
double code(double x, double y, double z, double t) {
	return (x * x) - (4.0 * (y * ((z * z) - t)));
}
real(8) function code(x, y, z, t)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    code = (x * x) - (4.0d0 * (y * ((z * z) - t)))
end function
public static double code(double x, double y, double z, double t) {
	return (x * x) - (4.0 * (y * ((z * z) - t)));
}
def code(x, y, z, t):
	return (x * x) - (4.0 * (y * ((z * z) - t)))
function code(x, y, z, t)
	return Float64(Float64(x * x) - Float64(4.0 * Float64(y * Float64(Float64(z * z) - t))))
end
function tmp = code(x, y, z, t)
	tmp = (x * x) - (4.0 * (y * ((z * z) - t)));
end
code[x_, y_, z_, t_] := N[(N[(x * x), $MachinePrecision] - N[(4.0 * N[(y * N[(N[(z * z), $MachinePrecision] - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
x \cdot x - 4 \cdot \left(y \cdot \left(z \cdot z - t\right)\right)
\end{array}

Reproduce

?
herbie shell --seed 2023258 
(FPCore (x y z t)
  :name "Graphics.Rasterific.Shading:$sradialGradientWithFocusShader from Rasterific-0.6.1, B"
  :precision binary64

  :herbie-target
  (- (* x x) (* 4.0 (* y (- (* z z) t))))

  (- (* x x) (* (* y 4.0) (- (* z z) t))))