Falkner and Boettcher, Appendix A

Percentage Accurate: 90.0% → 97.0%
Time: 8.8s
Alternatives: 13
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 13 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 90.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Alternative 1: 97.0% accurate, 0.4× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := a \cdot {k}^{m}\\ \mathbf{if}\;\frac{t_0}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 5 \cdot 10^{+44}:\\ \;\;\;\;a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (let* ((t_0 (* a (pow k m))))
   (if (<= (/ t_0 (+ (+ 1.0 (* k 10.0)) (* k k))) 5e+44)
     (* a (/ (pow k m) (fma k (+ k 10.0) 1.0)))
     t_0)))
double code(double a, double k, double m) {
	double t_0 = a * pow(k, m);
	double tmp;
	if ((t_0 / ((1.0 + (k * 10.0)) + (k * k))) <= 5e+44) {
		tmp = a * (pow(k, m) / fma(k, (k + 10.0), 1.0));
	} else {
		tmp = t_0;
	}
	return tmp;
}
function code(a, k, m)
	t_0 = Float64(a * (k ^ m))
	tmp = 0.0
	if (Float64(t_0 / Float64(Float64(1.0 + Float64(k * 10.0)) + Float64(k * k))) <= 5e+44)
		tmp = Float64(a * Float64((k ^ m) / fma(k, Float64(k + 10.0), 1.0)));
	else
		tmp = t_0;
	end
	return tmp
end
code[a_, k_, m_] := Block[{t$95$0 = N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(t$95$0 / N[(N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 5e+44], N[(a * N[(N[Power[k, m], $MachinePrecision] / N[(k * N[(k + 10.0), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := a \cdot {k}^{m}\\
\mathbf{if}\;\frac{t_0}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 5 \cdot 10^{+44}:\\
\;\;\;\;a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}\\

\mathbf{else}:\\
\;\;\;\;t_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (*.f64 a (pow.f64 k m)) (+.f64 (+.f64 1 (*.f64 10 k)) (*.f64 k k))) < 4.9999999999999996e44

    1. Initial program 97.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/97.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+97.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative97.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out97.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def97.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative97.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified97.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]

    if 4.9999999999999996e44 < (/.f64 (*.f64 a (pow.f64 k m)) (+.f64 (+.f64 1 (*.f64 10 k)) (*.f64 k k)))

    1. Initial program 71.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/71.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified71.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 69.4%

      \[\leadsto a \cdot \color{blue}{e^{\log k \cdot m}} \]
    5. Step-by-step derivation
      1. exp-to-pow100.0%

        \[\leadsto a \cdot \color{blue}{{k}^{m}} \]
    6. Simplified100.0%

      \[\leadsto a \cdot \color{blue}{{k}^{m}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification97.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 5 \cdot 10^{+44}:\\ \;\;\;\;a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \]

Alternative 2: 97.0% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := a \cdot {k}^{m}\\ t_1 := \frac{t_0}{\left(1 + k \cdot 10\right) + k \cdot k}\\ \mathbf{if}\;t_1 \leq 5 \cdot 10^{+44}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (let* ((t_0 (* a (pow k m))) (t_1 (/ t_0 (+ (+ 1.0 (* k 10.0)) (* k k)))))
   (if (<= t_1 5e+44) t_1 t_0)))
double code(double a, double k, double m) {
	double t_0 = a * pow(k, m);
	double t_1 = t_0 / ((1.0 + (k * 10.0)) + (k * k));
	double tmp;
	if (t_1 <= 5e+44) {
		tmp = t_1;
	} else {
		tmp = t_0;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: t_0
    real(8) :: t_1
    real(8) :: tmp
    t_0 = a * (k ** m)
    t_1 = t_0 / ((1.0d0 + (k * 10.0d0)) + (k * k))
    if (t_1 <= 5d+44) then
        tmp = t_1
    else
        tmp = t_0
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double t_0 = a * Math.pow(k, m);
	double t_1 = t_0 / ((1.0 + (k * 10.0)) + (k * k));
	double tmp;
	if (t_1 <= 5e+44) {
		tmp = t_1;
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(a, k, m):
	t_0 = a * math.pow(k, m)
	t_1 = t_0 / ((1.0 + (k * 10.0)) + (k * k))
	tmp = 0
	if t_1 <= 5e+44:
		tmp = t_1
	else:
		tmp = t_0
	return tmp
function code(a, k, m)
	t_0 = Float64(a * (k ^ m))
	t_1 = Float64(t_0 / Float64(Float64(1.0 + Float64(k * 10.0)) + Float64(k * k)))
	tmp = 0.0
	if (t_1 <= 5e+44)
		tmp = t_1;
	else
		tmp = t_0;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	t_0 = a * (k ^ m);
	t_1 = t_0 / ((1.0 + (k * 10.0)) + (k * k));
	tmp = 0.0;
	if (t_1 <= 5e+44)
		tmp = t_1;
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := Block[{t$95$0 = N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(t$95$0 / N[(N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, 5e+44], t$95$1, t$95$0]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := a \cdot {k}^{m}\\
t_1 := \frac{t_0}{\left(1 + k \cdot 10\right) + k \cdot k}\\
\mathbf{if}\;t_1 \leq 5 \cdot 10^{+44}:\\
\;\;\;\;t_1\\

\mathbf{else}:\\
\;\;\;\;t_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (*.f64 a (pow.f64 k m)) (+.f64 (+.f64 1 (*.f64 10 k)) (*.f64 k k))) < 4.9999999999999996e44

    1. Initial program 97.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]

    if 4.9999999999999996e44 < (/.f64 (*.f64 a (pow.f64 k m)) (+.f64 (+.f64 1 (*.f64 10 k)) (*.f64 k k)))

    1. Initial program 71.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/71.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative71.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified71.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 69.4%

      \[\leadsto a \cdot \color{blue}{e^{\log k \cdot m}} \]
    5. Step-by-step derivation
      1. exp-to-pow100.0%

        \[\leadsto a \cdot \color{blue}{{k}^{m}} \]
    6. Simplified100.0%

      \[\leadsto a \cdot \color{blue}{{k}^{m}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification97.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 5 \cdot 10^{+44}:\\ \;\;\;\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \]

Alternative 3: 96.9% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -8.6 \cdot 10^{-17} \lor \neg \left(m \leq 1.6 \cdot 10^{-23}\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= m -8.6e-17) (not (<= m 1.6e-23)))
   (* a (pow k m))
   (* a (/ 1.0 (+ 1.0 (* k (+ k 10.0)))))))
double code(double a, double k, double m) {
	double tmp;
	if ((m <= -8.6e-17) || !(m <= 1.6e-23)) {
		tmp = a * pow(k, m);
	} else {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((m <= (-8.6d-17)) .or. (.not. (m <= 1.6d-23))) then
        tmp = a * (k ** m)
    else
        tmp = a * (1.0d0 / (1.0d0 + (k * (k + 10.0d0))))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((m <= -8.6e-17) || !(m <= 1.6e-23)) {
		tmp = a * Math.pow(k, m);
	} else {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (m <= -8.6e-17) or not (m <= 1.6e-23):
		tmp = a * math.pow(k, m)
	else:
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((m <= -8.6e-17) || !(m <= 1.6e-23))
		tmp = Float64(a * (k ^ m));
	else
		tmp = Float64(a * Float64(1.0 / Float64(1.0 + Float64(k * Float64(k + 10.0)))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((m <= -8.6e-17) || ~((m <= 1.6e-23)))
		tmp = a * (k ^ m);
	else
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[m, -8.6e-17], N[Not[LessEqual[m, 1.6e-23]], $MachinePrecision]], N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision], N[(a * N[(1.0 / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -8.6 \cdot 10^{-17} \lor \neg \left(m \leq 1.6 \cdot 10^{-23}\right):\\
\;\;\;\;a \cdot {k}^{m}\\

\mathbf{else}:\\
\;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -8.60000000000000046e-17 or 1.59999999999999988e-23 < m

    1. Initial program 89.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/89.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+89.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative89.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out89.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def89.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative89.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified89.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 61.2%

      \[\leadsto a \cdot \color{blue}{e^{\log k \cdot m}} \]
    5. Step-by-step derivation
      1. exp-to-pow100.0%

        \[\leadsto a \cdot \color{blue}{{k}^{m}} \]
    6. Simplified100.0%

      \[\leadsto a \cdot \color{blue}{{k}^{m}} \]

    if -8.60000000000000046e-17 < m < 1.59999999999999988e-23

    1. Initial program 93.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/93.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+93.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative93.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out93.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def93.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative93.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified93.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 93.4%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification97.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -8.6 \cdot 10^{-17} \lor \neg \left(m \leq 1.6 \cdot 10^{-23}\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \]

Alternative 4: 45.1% accurate, 7.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{a}{k \cdot k}\\ \mathbf{if}\;k \leq -9.2 \cdot 10^{-231}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;k \leq 9.8 \cdot 10^{-262}:\\ \;\;\;\;\frac{1}{\frac{1}{a}}\\ \mathbf{elif}\;k \leq 9.5 \cdot 10^{-249}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;k \leq 3.75 \cdot 10^{-6}:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;a \cdot \frac{1}{k \cdot k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (let* ((t_0 (/ a (* k k))))
   (if (<= k -9.2e-231)
     t_0
     (if (<= k 9.8e-262)
       (/ 1.0 (/ 1.0 a))
       (if (<= k 9.5e-249) t_0 (if (<= k 3.75e-6) a (* a (/ 1.0 (* k k)))))))))
double code(double a, double k, double m) {
	double t_0 = a / (k * k);
	double tmp;
	if (k <= -9.2e-231) {
		tmp = t_0;
	} else if (k <= 9.8e-262) {
		tmp = 1.0 / (1.0 / a);
	} else if (k <= 9.5e-249) {
		tmp = t_0;
	} else if (k <= 3.75e-6) {
		tmp = a;
	} else {
		tmp = a * (1.0 / (k * k));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: t_0
    real(8) :: tmp
    t_0 = a / (k * k)
    if (k <= (-9.2d-231)) then
        tmp = t_0
    else if (k <= 9.8d-262) then
        tmp = 1.0d0 / (1.0d0 / a)
    else if (k <= 9.5d-249) then
        tmp = t_0
    else if (k <= 3.75d-6) then
        tmp = a
    else
        tmp = a * (1.0d0 / (k * k))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double t_0 = a / (k * k);
	double tmp;
	if (k <= -9.2e-231) {
		tmp = t_0;
	} else if (k <= 9.8e-262) {
		tmp = 1.0 / (1.0 / a);
	} else if (k <= 9.5e-249) {
		tmp = t_0;
	} else if (k <= 3.75e-6) {
		tmp = a;
	} else {
		tmp = a * (1.0 / (k * k));
	}
	return tmp;
}
def code(a, k, m):
	t_0 = a / (k * k)
	tmp = 0
	if k <= -9.2e-231:
		tmp = t_0
	elif k <= 9.8e-262:
		tmp = 1.0 / (1.0 / a)
	elif k <= 9.5e-249:
		tmp = t_0
	elif k <= 3.75e-6:
		tmp = a
	else:
		tmp = a * (1.0 / (k * k))
	return tmp
function code(a, k, m)
	t_0 = Float64(a / Float64(k * k))
	tmp = 0.0
	if (k <= -9.2e-231)
		tmp = t_0;
	elseif (k <= 9.8e-262)
		tmp = Float64(1.0 / Float64(1.0 / a));
	elseif (k <= 9.5e-249)
		tmp = t_0;
	elseif (k <= 3.75e-6)
		tmp = a;
	else
		tmp = Float64(a * Float64(1.0 / Float64(k * k)));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	t_0 = a / (k * k);
	tmp = 0.0;
	if (k <= -9.2e-231)
		tmp = t_0;
	elseif (k <= 9.8e-262)
		tmp = 1.0 / (1.0 / a);
	elseif (k <= 9.5e-249)
		tmp = t_0;
	elseif (k <= 3.75e-6)
		tmp = a;
	else
		tmp = a * (1.0 / (k * k));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := Block[{t$95$0 = N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[k, -9.2e-231], t$95$0, If[LessEqual[k, 9.8e-262], N[(1.0 / N[(1.0 / a), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 9.5e-249], t$95$0, If[LessEqual[k, 3.75e-6], a, N[(a * N[(1.0 / N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{a}{k \cdot k}\\
\mathbf{if}\;k \leq -9.2 \cdot 10^{-231}:\\
\;\;\;\;t_0\\

\mathbf{elif}\;k \leq 9.8 \cdot 10^{-262}:\\
\;\;\;\;\frac{1}{\frac{1}{a}}\\

\mathbf{elif}\;k \leq 9.5 \cdot 10^{-249}:\\
\;\;\;\;t_0\\

\mathbf{elif}\;k \leq 3.75 \cdot 10^{-6}:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;a \cdot \frac{1}{k \cdot k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if k < -9.2e-231 or 9.8000000000000005e-262 < k < 9.4999999999999997e-249

    1. Initial program 91.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/91.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+91.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative91.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out91.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def91.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative91.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified91.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 23.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 33.4%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow233.4%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified33.4%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -9.2e-231 < k < 9.8000000000000005e-262

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 36.4%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Step-by-step derivation
      1. div-inv36.4%

        \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
      2. clear-num40.0%

        \[\leadsto \color{blue}{\frac{1}{\frac{1 + k \cdot \left(k + 10\right)}{a}}} \]
      3. +-commutative40.0%

        \[\leadsto \frac{1}{\frac{\color{blue}{k \cdot \left(k + 10\right) + 1}}{a}} \]
      4. fma-udef40.0%

        \[\leadsto \frac{1}{\frac{\color{blue}{\mathsf{fma}\left(k, k + 10, 1\right)}}{a}} \]
      5. div-inv40.0%

        \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(k, k + 10, 1\right) \cdot \frac{1}{a}}} \]
      6. fma-udef40.0%

        \[\leadsto \frac{1}{\color{blue}{\left(k \cdot \left(k + 10\right) + 1\right)} \cdot \frac{1}{a}} \]
      7. +-commutative40.0%

        \[\leadsto \frac{1}{\color{blue}{\left(1 + k \cdot \left(k + 10\right)\right)} \cdot \frac{1}{a}} \]
      8. associate-/r*40.0%

        \[\leadsto \color{blue}{\frac{\frac{1}{1 + k \cdot \left(k + 10\right)}}{\frac{1}{a}}} \]
      9. +-commutative40.0%

        \[\leadsto \frac{\frac{1}{\color{blue}{k \cdot \left(k + 10\right) + 1}}}{\frac{1}{a}} \]
      10. fma-udef40.0%

        \[\leadsto \frac{\frac{1}{\color{blue}{\mathsf{fma}\left(k, k + 10, 1\right)}}}{\frac{1}{a}} \]
    6. Applied egg-rr40.0%

      \[\leadsto \color{blue}{\frac{\frac{1}{\mathsf{fma}\left(k, k + 10, 1\right)}}{\frac{1}{a}}} \]
    7. Taylor expanded in k around 0 40.0%

      \[\leadsto \frac{\color{blue}{1}}{\frac{1}{a}} \]

    if 9.4999999999999997e-249 < k < 3.7500000000000001e-6

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 58.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 58.4%

      \[\leadsto \color{blue}{a} \]

    if 3.7500000000000001e-6 < k

    1. Initial program 81.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/81.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+81.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative81.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out81.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def81.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative81.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified81.6%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 58.5%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 56.7%

      \[\leadsto a \cdot \color{blue}{\frac{1}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow256.7%

        \[\leadsto a \cdot \frac{1}{\color{blue}{k \cdot k}} \]
    7. Simplified56.7%

      \[\leadsto a \cdot \color{blue}{\frac{1}{k \cdot k}} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification49.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -9.2 \cdot 10^{-231}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 9.8 \cdot 10^{-262}:\\ \;\;\;\;\frac{1}{\frac{1}{a}}\\ \mathbf{elif}\;k \leq 9.5 \cdot 10^{-249}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 3.75 \cdot 10^{-6}:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;a \cdot \frac{1}{k \cdot k}\\ \end{array} \]

Alternative 5: 58.7% accurate, 7.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.26:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.2:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.26)
   (/ a (* k k))
   (if (<= m 1.2) (* a (/ 1.0 (+ 1.0 (* k (+ k 10.0))))) (* -10.0 (* a k)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.26) {
		tmp = a / (k * k);
	} else if (m <= 1.2) {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.26d0)) then
        tmp = a / (k * k)
    else if (m <= 1.2d0) then
        tmp = a * (1.0d0 / (1.0d0 + (k * (k + 10.0d0))))
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.26) {
		tmp = a / (k * k);
	} else if (m <= 1.2) {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.26:
		tmp = a / (k * k)
	elif m <= 1.2:
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))))
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.26)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 1.2)
		tmp = Float64(a * Float64(1.0 / Float64(1.0 + Float64(k * Float64(k + 10.0)))));
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.26)
		tmp = a / (k * k);
	elseif (m <= 1.2)
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.26], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 1.2], N[(a * N[(1.0 / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.26:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 1.2:\\
\;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -0.26000000000000001

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 40.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.4%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.4%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.4%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -0.26000000000000001 < m < 1.19999999999999996

    1. Initial program 93.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified94.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 93.0%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]

    if 1.19999999999999996 < m

    1. Initial program 78.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/78.3%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified78.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 3.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative5.4%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification60.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.26:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.2:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 6: 62.2% accurate, 7.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.58:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.6 \cdot 10^{-23}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot \left(-10 + k \cdot 100\right)\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.58)
   (/ a (* k k))
   (if (<= m 1.6e-23)
     (* a (/ 1.0 (+ 1.0 (* k (+ k 10.0)))))
     (+ a (* a (* k (+ -10.0 (* k 100.0))))))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.58) {
		tmp = a / (k * k);
	} else if (m <= 1.6e-23) {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	} else {
		tmp = a + (a * (k * (-10.0 + (k * 100.0))));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.58d0)) then
        tmp = a / (k * k)
    else if (m <= 1.6d-23) then
        tmp = a * (1.0d0 / (1.0d0 + (k * (k + 10.0d0))))
    else
        tmp = a + (a * (k * ((-10.0d0) + (k * 100.0d0))))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.58) {
		tmp = a / (k * k);
	} else if (m <= 1.6e-23) {
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	} else {
		tmp = a + (a * (k * (-10.0 + (k * 100.0))));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.58:
		tmp = a / (k * k)
	elif m <= 1.6e-23:
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))))
	else:
		tmp = a + (a * (k * (-10.0 + (k * 100.0))))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.58)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 1.6e-23)
		tmp = Float64(a * Float64(1.0 / Float64(1.0 + Float64(k * Float64(k + 10.0)))));
	else
		tmp = Float64(a + Float64(a * Float64(k * Float64(-10.0 + Float64(k * 100.0)))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.58)
		tmp = a / (k * k);
	elseif (m <= 1.6e-23)
		tmp = a * (1.0 / (1.0 + (k * (k + 10.0))));
	else
		tmp = a + (a * (k * (-10.0 + (k * 100.0))));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.58], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 1.6e-23], N[(a * N[(1.0 / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a + N[(a * N[(k * N[(-10.0 + N[(k * 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.58:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 1.6 \cdot 10^{-23}:\\
\;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;a + a \cdot \left(k \cdot \left(-10 + k \cdot 100\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -0.57999999999999996

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 40.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.4%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.4%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.4%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -0.57999999999999996 < m < 1.59999999999999988e-23

    1. Initial program 93.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/93.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+93.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative93.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out93.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def93.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative93.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified93.6%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 93.5%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]

    if 1.59999999999999988e-23 < m

    1. Initial program 79.8%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/79.8%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+79.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative79.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out79.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def79.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative79.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified79.8%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 8.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 8.5%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative8.5%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified8.5%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around 0 25.8%

      \[\leadsto \color{blue}{a + \left(-10 \cdot \left(k \cdot a\right) + 100 \cdot \left({k}^{2} \cdot a\right)\right)} \]
    9. Step-by-step derivation
      1. associate-*r*25.8%

        \[\leadsto a + \left(\color{blue}{\left(-10 \cdot k\right) \cdot a} + 100 \cdot \left({k}^{2} \cdot a\right)\right) \]
      2. unpow225.8%

        \[\leadsto a + \left(\left(-10 \cdot k\right) \cdot a + 100 \cdot \left(\color{blue}{\left(k \cdot k\right)} \cdot a\right)\right) \]
      3. associate-*r*26.9%

        \[\leadsto a + \left(\left(-10 \cdot k\right) \cdot a + \color{blue}{\left(100 \cdot \left(k \cdot k\right)\right) \cdot a}\right) \]
      4. *-commutative26.9%

        \[\leadsto a + \left(\left(-10 \cdot k\right) \cdot a + \color{blue}{\left(\left(k \cdot k\right) \cdot 100\right)} \cdot a\right) \]
      5. distribute-rgt-out32.5%

        \[\leadsto a + \color{blue}{a \cdot \left(-10 \cdot k + \left(k \cdot k\right) \cdot 100\right)} \]
      6. *-commutative32.5%

        \[\leadsto a + a \cdot \left(\color{blue}{k \cdot -10} + \left(k \cdot k\right) \cdot 100\right) \]
      7. associate-*l*32.5%

        \[\leadsto a + a \cdot \left(k \cdot -10 + \color{blue}{k \cdot \left(k \cdot 100\right)}\right) \]
      8. distribute-lft-out32.5%

        \[\leadsto a + a \cdot \color{blue}{\left(k \cdot \left(-10 + k \cdot 100\right)\right)} \]
    10. Simplified32.5%

      \[\leadsto \color{blue}{a + a \cdot \left(k \cdot \left(-10 + k \cdot 100\right)\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification63.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.58:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.6 \cdot 10^{-23}:\\ \;\;\;\;a \cdot \frac{1}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot \left(-10 + k \cdot 100\right)\right)\\ \end{array} \]

Alternative 7: 45.1% accurate, 8.6× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{a}{k \cdot k}\\ \mathbf{if}\;k \leq -9.2 \cdot 10^{-231}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;k \leq 3.9 \cdot 10^{-261}:\\ \;\;\;\;\frac{1}{\frac{1}{a}}\\ \mathbf{elif}\;k \leq 1.1 \cdot 10^{-248} \lor \neg \left(k \leq 3.75 \cdot 10^{-6}\right):\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (let* ((t_0 (/ a (* k k))))
   (if (<= k -9.2e-231)
     t_0
     (if (<= k 3.9e-261)
       (/ 1.0 (/ 1.0 a))
       (if (or (<= k 1.1e-248) (not (<= k 3.75e-6))) t_0 a)))))
double code(double a, double k, double m) {
	double t_0 = a / (k * k);
	double tmp;
	if (k <= -9.2e-231) {
		tmp = t_0;
	} else if (k <= 3.9e-261) {
		tmp = 1.0 / (1.0 / a);
	} else if ((k <= 1.1e-248) || !(k <= 3.75e-6)) {
		tmp = t_0;
	} else {
		tmp = a;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: t_0
    real(8) :: tmp
    t_0 = a / (k * k)
    if (k <= (-9.2d-231)) then
        tmp = t_0
    else if (k <= 3.9d-261) then
        tmp = 1.0d0 / (1.0d0 / a)
    else if ((k <= 1.1d-248) .or. (.not. (k <= 3.75d-6))) then
        tmp = t_0
    else
        tmp = a
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double t_0 = a / (k * k);
	double tmp;
	if (k <= -9.2e-231) {
		tmp = t_0;
	} else if (k <= 3.9e-261) {
		tmp = 1.0 / (1.0 / a);
	} else if ((k <= 1.1e-248) || !(k <= 3.75e-6)) {
		tmp = t_0;
	} else {
		tmp = a;
	}
	return tmp;
}
def code(a, k, m):
	t_0 = a / (k * k)
	tmp = 0
	if k <= -9.2e-231:
		tmp = t_0
	elif k <= 3.9e-261:
		tmp = 1.0 / (1.0 / a)
	elif (k <= 1.1e-248) or not (k <= 3.75e-6):
		tmp = t_0
	else:
		tmp = a
	return tmp
function code(a, k, m)
	t_0 = Float64(a / Float64(k * k))
	tmp = 0.0
	if (k <= -9.2e-231)
		tmp = t_0;
	elseif (k <= 3.9e-261)
		tmp = Float64(1.0 / Float64(1.0 / a));
	elseif ((k <= 1.1e-248) || !(k <= 3.75e-6))
		tmp = t_0;
	else
		tmp = a;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	t_0 = a / (k * k);
	tmp = 0.0;
	if (k <= -9.2e-231)
		tmp = t_0;
	elseif (k <= 3.9e-261)
		tmp = 1.0 / (1.0 / a);
	elseif ((k <= 1.1e-248) || ~((k <= 3.75e-6)))
		tmp = t_0;
	else
		tmp = a;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := Block[{t$95$0 = N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[k, -9.2e-231], t$95$0, If[LessEqual[k, 3.9e-261], N[(1.0 / N[(1.0 / a), $MachinePrecision]), $MachinePrecision], If[Or[LessEqual[k, 1.1e-248], N[Not[LessEqual[k, 3.75e-6]], $MachinePrecision]], t$95$0, a]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{a}{k \cdot k}\\
\mathbf{if}\;k \leq -9.2 \cdot 10^{-231}:\\
\;\;\;\;t_0\\

\mathbf{elif}\;k \leq 3.9 \cdot 10^{-261}:\\
\;\;\;\;\frac{1}{\frac{1}{a}}\\

\mathbf{elif}\;k \leq 1.1 \cdot 10^{-248} \lor \neg \left(k \leq 3.75 \cdot 10^{-6}\right):\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;a\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < -9.2e-231 or 3.90000000000000017e-261 < k < 1.1e-248 or 3.7500000000000001e-6 < k

    1. Initial program 85.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/85.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+85.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative85.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out85.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def85.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative85.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified85.5%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 44.2%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 47.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow247.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified47.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -9.2e-231 < k < 3.90000000000000017e-261

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 36.4%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Step-by-step derivation
      1. div-inv36.4%

        \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
      2. clear-num40.0%

        \[\leadsto \color{blue}{\frac{1}{\frac{1 + k \cdot \left(k + 10\right)}{a}}} \]
      3. +-commutative40.0%

        \[\leadsto \frac{1}{\frac{\color{blue}{k \cdot \left(k + 10\right) + 1}}{a}} \]
      4. fma-udef40.0%

        \[\leadsto \frac{1}{\frac{\color{blue}{\mathsf{fma}\left(k, k + 10, 1\right)}}{a}} \]
      5. div-inv40.0%

        \[\leadsto \frac{1}{\color{blue}{\mathsf{fma}\left(k, k + 10, 1\right) \cdot \frac{1}{a}}} \]
      6. fma-udef40.0%

        \[\leadsto \frac{1}{\color{blue}{\left(k \cdot \left(k + 10\right) + 1\right)} \cdot \frac{1}{a}} \]
      7. +-commutative40.0%

        \[\leadsto \frac{1}{\color{blue}{\left(1 + k \cdot \left(k + 10\right)\right)} \cdot \frac{1}{a}} \]
      8. associate-/r*40.0%

        \[\leadsto \color{blue}{\frac{\frac{1}{1 + k \cdot \left(k + 10\right)}}{\frac{1}{a}}} \]
      9. +-commutative40.0%

        \[\leadsto \frac{\frac{1}{\color{blue}{k \cdot \left(k + 10\right) + 1}}}{\frac{1}{a}} \]
      10. fma-udef40.0%

        \[\leadsto \frac{\frac{1}{\color{blue}{\mathsf{fma}\left(k, k + 10, 1\right)}}}{\frac{1}{a}} \]
    6. Applied egg-rr40.0%

      \[\leadsto \color{blue}{\frac{\frac{1}{\mathsf{fma}\left(k, k + 10, 1\right)}}{\frac{1}{a}}} \]
    7. Taylor expanded in k around 0 40.0%

      \[\leadsto \frac{\color{blue}{1}}{\frac{1}{a}} \]

    if 1.1e-248 < k < 3.7500000000000001e-6

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 58.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 58.4%

      \[\leadsto \color{blue}{a} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification49.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -9.2 \cdot 10^{-231}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 3.9 \cdot 10^{-261}:\\ \;\;\;\;\frac{1}{\frac{1}{a}}\\ \mathbf{elif}\;k \leq 1.1 \cdot 10^{-248} \lor \neg \left(k \leq 3.75 \cdot 10^{-6}\right):\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \]

Alternative 8: 58.7% accurate, 8.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.24:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 0.31:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.24)
   (/ a (* k k))
   (if (<= m 0.31) (/ a (+ 1.0 (* k (+ k 10.0)))) (* -10.0 (* a k)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.24) {
		tmp = a / (k * k);
	} else if (m <= 0.31) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.24d0)) then
        tmp = a / (k * k)
    else if (m <= 0.31d0) then
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.24) {
		tmp = a / (k * k);
	} else if (m <= 0.31) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.24:
		tmp = a / (k * k)
	elif m <= 0.31:
		tmp = a / (1.0 + (k * (k + 10.0)))
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.24)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 0.31)
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.24)
		tmp = a / (k * k);
	elseif (m <= 0.31)
		tmp = a / (1.0 + (k * (k + 10.0)));
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.24], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 0.31], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.24:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 0.31:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -0.23999999999999999

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 40.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.4%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.4%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.4%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -0.23999999999999999 < m < 0.309999999999999998

    1. Initial program 93.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified94.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 93.0%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]

    if 0.309999999999999998 < m

    1. Initial program 78.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/78.3%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified78.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 3.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative5.4%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification60.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.24:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 0.31:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 9: 48.2% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.116:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.65:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.116)
   (/ a (* k k))
   (if (<= m 1.65) (/ a (+ 1.0 (* k 10.0))) (* -10.0 (* a k)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.116) {
		tmp = a / (k * k);
	} else if (m <= 1.65) {
		tmp = a / (1.0 + (k * 10.0));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.116d0)) then
        tmp = a / (k * k)
    else if (m <= 1.65d0) then
        tmp = a / (1.0d0 + (k * 10.0d0))
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.116) {
		tmp = a / (k * k);
	} else if (m <= 1.65) {
		tmp = a / (1.0 + (k * 10.0));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.116:
		tmp = a / (k * k)
	elif m <= 1.65:
		tmp = a / (1.0 + (k * 10.0))
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.116)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 1.65)
		tmp = Float64(a / Float64(1.0 + Float64(k * 10.0)));
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.116)
		tmp = a / (k * k);
	elseif (m <= 1.65)
		tmp = a / (1.0 + (k * 10.0));
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.116], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 1.65], N[(a / N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.116:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 1.65:\\
\;\;\;\;\frac{a}{1 + k \cdot 10}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -0.116000000000000006

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 40.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.4%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.4%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.4%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -0.116000000000000006 < m < 1.6499999999999999

    1. Initial program 93.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified94.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 93.0%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 68.8%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative68.8%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified68.8%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]

    if 1.6499999999999999 < m

    1. Initial program 78.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/78.3%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified78.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 3.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative5.4%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification51.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.116:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.65:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 10: 57.9% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -0.21:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.3:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -0.21)
   (/ a (* k k))
   (if (<= m 1.3) (/ a (+ 1.0 (* k k))) (* -10.0 (* a k)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.21) {
		tmp = a / (k * k);
	} else if (m <= 1.3) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-0.21d0)) then
        tmp = a / (k * k)
    else if (m <= 1.3d0) then
        tmp = a / (1.0d0 + (k * k))
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -0.21) {
		tmp = a / (k * k);
	} else if (m <= 1.3) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -0.21:
		tmp = a / (k * k)
	elif m <= 1.3:
		tmp = a / (1.0 + (k * k))
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -0.21)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 1.3)
		tmp = Float64(a / Float64(1.0 + Float64(k * k)));
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -0.21)
		tmp = a / (k * k);
	elseif (m <= 1.3)
		tmp = a / (1.0 + (k * k));
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -0.21], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 1.3], N[(a / N[(1.0 + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -0.21:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 1.3:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -0.209999999999999992

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 40.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.4%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.4%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.4%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -0.209999999999999992 < m < 1.30000000000000004

    1. Initial program 93.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified94.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 93.0%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 91.1%

      \[\leadsto \frac{a}{1 + \color{blue}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow291.1%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]
    7. Simplified91.1%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]

    if 1.30000000000000004 < m

    1. Initial program 78.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/78.3%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified78.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 3.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative5.4%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification59.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -0.21:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.3:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 11: 31.5% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -8.5 \cdot 10^{-21}:\\ \;\;\;\;0.1 \cdot \frac{a}{k}\\ \mathbf{elif}\;m \leq 0.27:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -8.5e-21) (* 0.1 (/ a k)) (if (<= m 0.27) a (* -10.0 (* a k)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -8.5e-21) {
		tmp = 0.1 * (a / k);
	} else if (m <= 0.27) {
		tmp = a;
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-8.5d-21)) then
        tmp = 0.1d0 * (a / k)
    else if (m <= 0.27d0) then
        tmp = a
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -8.5e-21) {
		tmp = 0.1 * (a / k);
	} else if (m <= 0.27) {
		tmp = a;
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -8.5e-21:
		tmp = 0.1 * (a / k)
	elif m <= 0.27:
		tmp = a
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -8.5e-21)
		tmp = Float64(0.1 * Float64(a / k));
	elseif (m <= 0.27)
		tmp = a;
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -8.5e-21)
		tmp = 0.1 * (a / k);
	elseif (m <= 0.27)
		tmp = a;
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -8.5e-21], N[(0.1 * N[(a / k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 0.27], a, N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -8.5 \cdot 10^{-21}:\\
\;\;\;\;0.1 \cdot \frac{a}{k}\\

\mathbf{elif}\;m \leq 0.27:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -8.4999999999999993e-21

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 42.2%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 20.7%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative20.7%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified20.7%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 24.3%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]

    if -8.4999999999999993e-21 < m < 0.27000000000000002

    1. Initial program 93.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/93.8%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+93.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative93.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out93.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def93.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative93.8%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified93.8%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 92.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 55.4%

      \[\leadsto \color{blue}{a} \]

    if 0.27000000000000002 < m

    1. Initial program 78.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/78.3%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified78.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 3.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative5.4%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification33.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -8.5 \cdot 10^{-21}:\\ \;\;\;\;0.1 \cdot \frac{a}{k}\\ \mathbf{elif}\;m \leq 0.27:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 12: 25.8% accurate, 16.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq 0.44:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m) :precision binary64 (if (<= m 0.44) a (* -10.0 (* a k))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= 0.44) {
		tmp = a;
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= 0.44d0) then
        tmp = a
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= 0.44) {
		tmp = a;
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= 0.44:
		tmp = a
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= 0.44)
		tmp = a;
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= 0.44)
		tmp = a;
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, 0.44], a, N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq 0.44:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < 0.440000000000000002

    1. Initial program 96.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/96.7%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+96.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative96.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out96.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def96.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative96.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified96.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 68.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 31.3%

      \[\leadsto \color{blue}{a} \]

    if 0.440000000000000002 < m

    1. Initial program 78.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/78.3%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative78.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified78.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 3.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative5.4%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified5.4%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification27.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq 0.44:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 13: 20.0% accurate, 114.0× speedup?

\[\begin{array}{l} \\ a \end{array} \]
(FPCore (a k m) :precision binary64 a)
double code(double a, double k, double m) {
	return a;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = a
end function
public static double code(double a, double k, double m) {
	return a;
}
def code(a, k, m):
	return a
function code(a, k, m)
	return a
end
function tmp = code(a, k, m)
	tmp = a;
end
code[a_, k_, m_] := a
\begin{array}{l}

\\
a
\end{array}
Derivation
  1. Initial program 90.7%

    \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
  2. Step-by-step derivation
    1. associate-*r/90.8%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
    2. associate-+l+90.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
    3. +-commutative90.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
    4. distribute-rgt-out90.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
    5. fma-def90.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
    6. +-commutative90.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
  3. Simplified90.8%

    \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
  4. Taylor expanded in m around 0 47.5%

    \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
  5. Taylor expanded in k around 0 22.4%

    \[\leadsto \color{blue}{a} \]
  6. Final simplification22.4%

    \[\leadsto a \]

Reproduce

?
herbie shell --seed 2023257 
(FPCore (a k m)
  :name "Falkner and Boettcher, Appendix A"
  :precision binary64
  (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))