Diagrams.Solve.Polynomial:cubForm from diagrams-solve-0.1, J

Percentage Accurate: 79.3% → 91.6%
Time: 13.3s
Alternatives: 12
Speedup: 0.9×

Specification

?
\[\begin{array}{l} \\ \frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \end{array} \]
(FPCore (x y z t a b c)
 :precision binary64
 (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)))
double code(double x, double y, double z, double t, double a, double b, double c) {
	return ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c);
}
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = ((((x * 9.0d0) * y) - (((z * 4.0d0) * t) * a)) + b) / (z * c)
end function
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	return ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c);
}
def code(x, y, z, t, a, b, c):
	return ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c)
function code(x, y, z, t, a, b, c)
	return Float64(Float64(Float64(Float64(Float64(x * 9.0) * y) - Float64(Float64(Float64(z * 4.0) * t) * a)) + b) / Float64(z * c))
end
function tmp = code(x, y, z, t, a, b, c)
	tmp = ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c);
end
code[x_, y_, z_, t_, a_, b_, c_] := N[(N[(N[(N[(N[(x * 9.0), $MachinePrecision] * y), $MachinePrecision] - N[(N[(N[(z * 4.0), $MachinePrecision] * t), $MachinePrecision] * a), $MachinePrecision]), $MachinePrecision] + b), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 12 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 79.3% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \end{array} \]
(FPCore (x y z t a b c)
 :precision binary64
 (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)))
double code(double x, double y, double z, double t, double a, double b, double c) {
	return ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c);
}
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = ((((x * 9.0d0) * y) - (((z * 4.0d0) * t) * a)) + b) / (z * c)
end function
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	return ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c);
}
def code(x, y, z, t, a, b, c):
	return ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c)
function code(x, y, z, t, a, b, c)
	return Float64(Float64(Float64(Float64(Float64(x * 9.0) * y) - Float64(Float64(Float64(z * 4.0) * t) * a)) + b) / Float64(z * c))
end
function tmp = code(x, y, z, t, a, b, c)
	tmp = ((((x * 9.0) * y) - (((z * 4.0) * t) * a)) + b) / (z * c);
end
code[x_, y_, z_, t_, a_, b_, c_] := N[(N[(N[(N[(N[(x * 9.0), $MachinePrecision] * y), $MachinePrecision] - N[(N[(N[(z * 4.0), $MachinePrecision] * t), $MachinePrecision] * a), $MachinePrecision]), $MachinePrecision] + b), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c}
\end{array}

Alternative 1: 91.6% accurate, 0.2× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;z \leq -4 \cdot 10^{+60} \lor \neg \left(z \leq 1.5 \cdot 10^{-39}\right):\\ \;\;\;\;\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + \left(y \cdot \left(x \cdot 9\right) - a \cdot \left(t \cdot \left(z \cdot 4\right)\right)\right)}{z \cdot c}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (or (<= z -4e+60) (not (<= z 1.5e-39)))
   (/ (+ (/ (fma x (* 9.0 y) b) z) (* t (* a -4.0))) c)
   (/ (+ b (- (* y (* x 9.0)) (* a (* t (* z 4.0))))) (* z c))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((z <= -4e+60) || !(z <= 1.5e-39)) {
		tmp = ((fma(x, (9.0 * y), b) / z) + (t * (a * -4.0))) / c;
	} else {
		tmp = (b + ((y * (x * 9.0)) - (a * (t * (z * 4.0))))) / (z * c);
	}
	return tmp;
}
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if ((z <= -4e+60) || !(z <= 1.5e-39))
		tmp = Float64(Float64(Float64(fma(x, Float64(9.0 * y), b) / z) + Float64(t * Float64(a * -4.0))) / c);
	else
		tmp = Float64(Float64(b + Float64(Float64(y * Float64(x * 9.0)) - Float64(a * Float64(t * Float64(z * 4.0))))) / Float64(z * c));
	end
	return tmp
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[Or[LessEqual[z, -4e+60], N[Not[LessEqual[z, 1.5e-39]], $MachinePrecision]], N[(N[(N[(N[(x * N[(9.0 * y), $MachinePrecision] + b), $MachinePrecision] / z), $MachinePrecision] + N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision], N[(N[(b + N[(N[(y * N[(x * 9.0), $MachinePrecision]), $MachinePrecision] - N[(a * N[(t * N[(z * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;z \leq -4 \cdot 10^{+60} \lor \neg \left(z \leq 1.5 \cdot 10^{-39}\right):\\
\;\;\;\;\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}\\

\mathbf{else}:\\
\;\;\;\;\frac{b + \left(y \cdot \left(x \cdot 9\right) - a \cdot \left(t \cdot \left(z \cdot 4\right)\right)\right)}{z \cdot c}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if z < -3.9999999999999998e60 or 1.50000000000000014e-39 < z

    1. Initial program 73.5%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*78.8%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified94.2%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]

    if -3.9999999999999998e60 < z < 1.50000000000000014e-39

    1. Initial program 93.4%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification93.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -4 \cdot 10^{+60} \lor \neg \left(z \leq 1.5 \cdot 10^{-39}\right):\\ \;\;\;\;\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + \left(y \cdot \left(x \cdot 9\right) - a \cdot \left(t \cdot \left(z \cdot 4\right)\right)\right)}{z \cdot c}\\ \end{array} \]

Alternative 2: 83.5% accurate, 0.8× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;z \leq -2.3 \cdot 10^{+116}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\ \mathbf{elif}\;z \leq 1.15 \cdot 10^{+89}:\\ \;\;\;\;\frac{b + \left(y \cdot \left(x \cdot 9\right) - a \cdot \left(t \cdot \left(z \cdot 4\right)\right)\right)}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + \left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right)}{z \cdot c}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (<= z -2.3e+116)
   (/ (+ (* t (* a -4.0)) (/ b z)) c)
   (if (<= z 1.15e+89)
     (/ (+ b (- (* y (* x 9.0)) (* a (* t (* z 4.0))))) (* z c))
     (/ (+ b (- (* x (* 9.0 y)) (* (* z 4.0) (* t a)))) (* z c)))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if (z <= -2.3e+116) {
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	} else if (z <= 1.15e+89) {
		tmp = (b + ((y * (x * 9.0)) - (a * (t * (z * 4.0))))) / (z * c);
	} else {
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c);
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if (z <= (-2.3d+116)) then
        tmp = ((t * (a * (-4.0d0))) + (b / z)) / c
    else if (z <= 1.15d+89) then
        tmp = (b + ((y * (x * 9.0d0)) - (a * (t * (z * 4.0d0))))) / (z * c)
    else
        tmp = (b + ((x * (9.0d0 * y)) - ((z * 4.0d0) * (t * a)))) / (z * c)
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if (z <= -2.3e+116) {
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	} else if (z <= 1.15e+89) {
		tmp = (b + ((y * (x * 9.0)) - (a * (t * (z * 4.0))))) / (z * c);
	} else {
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c);
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if z <= -2.3e+116:
		tmp = ((t * (a * -4.0)) + (b / z)) / c
	elif z <= 1.15e+89:
		tmp = (b + ((y * (x * 9.0)) - (a * (t * (z * 4.0))))) / (z * c)
	else:
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c)
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if (z <= -2.3e+116)
		tmp = Float64(Float64(Float64(t * Float64(a * -4.0)) + Float64(b / z)) / c);
	elseif (z <= 1.15e+89)
		tmp = Float64(Float64(b + Float64(Float64(y * Float64(x * 9.0)) - Float64(a * Float64(t * Float64(z * 4.0))))) / Float64(z * c));
	else
		tmp = Float64(Float64(b + Float64(Float64(x * Float64(9.0 * y)) - Float64(Float64(z * 4.0) * Float64(t * a)))) / Float64(z * c));
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if (z <= -2.3e+116)
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	elseif (z <= 1.15e+89)
		tmp = (b + ((y * (x * 9.0)) - (a * (t * (z * 4.0))))) / (z * c);
	else
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c);
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[LessEqual[z, -2.3e+116], N[(N[(N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision] + N[(b / z), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision], If[LessEqual[z, 1.15e+89], N[(N[(b + N[(N[(y * N[(x * 9.0), $MachinePrecision]), $MachinePrecision] - N[(a * N[(t * N[(z * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision], N[(N[(b + N[(N[(x * N[(9.0 * y), $MachinePrecision]), $MachinePrecision] - N[(N[(z * 4.0), $MachinePrecision] * N[(t * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;z \leq -2.3 \cdot 10^{+116}:\\
\;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\

\mathbf{elif}\;z \leq 1.15 \cdot 10^{+89}:\\
\;\;\;\;\frac{b + \left(y \cdot \left(x \cdot 9\right) - a \cdot \left(t \cdot \left(z \cdot 4\right)\right)\right)}{z \cdot c}\\

\mathbf{else}:\\
\;\;\;\;\frac{b + \left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right)}{z \cdot c}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if z < -2.29999999999999995e116

    1. Initial program 59.8%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*67.0%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified93.6%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in x around 0 84.0%

      \[\leadsto \color{blue}{\frac{\frac{b}{z} + -4 \cdot \left(a \cdot t\right)}{c}} \]
    5. Step-by-step derivation
      1. associate-*r*84.1%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative84.1%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative84.1%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified84.1%

      \[\leadsto \color{blue}{\frac{\frac{b}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]

    if -2.29999999999999995e116 < z < 1.1499999999999999e89

    1. Initial program 91.4%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]

    if 1.1499999999999999e89 < z

    1. Initial program 81.8%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*81.9%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*87.1%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified87.1%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification89.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -2.3 \cdot 10^{+116}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\ \mathbf{elif}\;z \leq 1.15 \cdot 10^{+89}:\\ \;\;\;\;\frac{b + \left(y \cdot \left(x \cdot 9\right) - a \cdot \left(t \cdot \left(z \cdot 4\right)\right)\right)}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + \left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right)}{z \cdot c}\\ \end{array} \]

Alternative 3: 49.2% accurate, 0.9× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} t_1 := 9 \cdot \frac{x \cdot y}{z \cdot c}\\ t_2 := -4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \mathbf{if}\;a \leq -3.4 \cdot 10^{-39}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;a \leq 3.9 \cdot 10^{-225}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;a \leq 9.8 \cdot 10^{-172}:\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{elif}\;a \leq 2.9 \cdot 10^{+56}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;a \leq 5.1 \cdot 10^{+158}:\\ \;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\ \mathbf{elif}\;a \leq 2.45 \cdot 10^{+186}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;t_2\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (let* ((t_1 (* 9.0 (/ (* x y) (* z c)))) (t_2 (* -4.0 (* t (/ a c)))))
   (if (<= a -3.4e-39)
     t_2
     (if (<= a 3.9e-225)
       t_1
       (if (<= a 9.8e-172)
         (/ (/ b c) z)
         (if (<= a 2.9e+56)
           t_1
           (if (<= a 5.1e+158)
             (* -4.0 (/ t (/ c a)))
             (if (<= a 2.45e+186) t_1 t_2))))))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = 9.0 * ((x * y) / (z * c));
	double t_2 = -4.0 * (t * (a / c));
	double tmp;
	if (a <= -3.4e-39) {
		tmp = t_2;
	} else if (a <= 3.9e-225) {
		tmp = t_1;
	} else if (a <= 9.8e-172) {
		tmp = (b / c) / z;
	} else if (a <= 2.9e+56) {
		tmp = t_1;
	} else if (a <= 5.1e+158) {
		tmp = -4.0 * (t / (c / a));
	} else if (a <= 2.45e+186) {
		tmp = t_1;
	} else {
		tmp = t_2;
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = 9.0d0 * ((x * y) / (z * c))
    t_2 = (-4.0d0) * (t * (a / c))
    if (a <= (-3.4d-39)) then
        tmp = t_2
    else if (a <= 3.9d-225) then
        tmp = t_1
    else if (a <= 9.8d-172) then
        tmp = (b / c) / z
    else if (a <= 2.9d+56) then
        tmp = t_1
    else if (a <= 5.1d+158) then
        tmp = (-4.0d0) * (t / (c / a))
    else if (a <= 2.45d+186) then
        tmp = t_1
    else
        tmp = t_2
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = 9.0 * ((x * y) / (z * c));
	double t_2 = -4.0 * (t * (a / c));
	double tmp;
	if (a <= -3.4e-39) {
		tmp = t_2;
	} else if (a <= 3.9e-225) {
		tmp = t_1;
	} else if (a <= 9.8e-172) {
		tmp = (b / c) / z;
	} else if (a <= 2.9e+56) {
		tmp = t_1;
	} else if (a <= 5.1e+158) {
		tmp = -4.0 * (t / (c / a));
	} else if (a <= 2.45e+186) {
		tmp = t_1;
	} else {
		tmp = t_2;
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	t_1 = 9.0 * ((x * y) / (z * c))
	t_2 = -4.0 * (t * (a / c))
	tmp = 0
	if a <= -3.4e-39:
		tmp = t_2
	elif a <= 3.9e-225:
		tmp = t_1
	elif a <= 9.8e-172:
		tmp = (b / c) / z
	elif a <= 2.9e+56:
		tmp = t_1
	elif a <= 5.1e+158:
		tmp = -4.0 * (t / (c / a))
	elif a <= 2.45e+186:
		tmp = t_1
	else:
		tmp = t_2
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	t_1 = Float64(9.0 * Float64(Float64(x * y) / Float64(z * c)))
	t_2 = Float64(-4.0 * Float64(t * Float64(a / c)))
	tmp = 0.0
	if (a <= -3.4e-39)
		tmp = t_2;
	elseif (a <= 3.9e-225)
		tmp = t_1;
	elseif (a <= 9.8e-172)
		tmp = Float64(Float64(b / c) / z);
	elseif (a <= 2.9e+56)
		tmp = t_1;
	elseif (a <= 5.1e+158)
		tmp = Float64(-4.0 * Float64(t / Float64(c / a)));
	elseif (a <= 2.45e+186)
		tmp = t_1;
	else
		tmp = t_2;
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	t_1 = 9.0 * ((x * y) / (z * c));
	t_2 = -4.0 * (t * (a / c));
	tmp = 0.0;
	if (a <= -3.4e-39)
		tmp = t_2;
	elseif (a <= 3.9e-225)
		tmp = t_1;
	elseif (a <= 9.8e-172)
		tmp = (b / c) / z;
	elseif (a <= 2.9e+56)
		tmp = t_1;
	elseif (a <= 5.1e+158)
		tmp = -4.0 * (t / (c / a));
	elseif (a <= 2.45e+186)
		tmp = t_1;
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := Block[{t$95$1 = N[(9.0 * N[(N[(x * y), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(t * N[(a / c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[a, -3.4e-39], t$95$2, If[LessEqual[a, 3.9e-225], t$95$1, If[LessEqual[a, 9.8e-172], N[(N[(b / c), $MachinePrecision] / z), $MachinePrecision], If[LessEqual[a, 2.9e+56], t$95$1, If[LessEqual[a, 5.1e+158], N[(-4.0 * N[(t / N[(c / a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[a, 2.45e+186], t$95$1, t$95$2]]]]]]]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
t_1 := 9 \cdot \frac{x \cdot y}{z \cdot c}\\
t_2 := -4 \cdot \left(t \cdot \frac{a}{c}\right)\\
\mathbf{if}\;a \leq -3.4 \cdot 10^{-39}:\\
\;\;\;\;t_2\\

\mathbf{elif}\;a \leq 3.9 \cdot 10^{-225}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;a \leq 9.8 \cdot 10^{-172}:\\
\;\;\;\;\frac{\frac{b}{c}}{z}\\

\mathbf{elif}\;a \leq 2.9 \cdot 10^{+56}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;a \leq 5.1 \cdot 10^{+158}:\\
\;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\

\mathbf{elif}\;a \leq 2.45 \cdot 10^{+186}:\\
\;\;\;\;t_1\\

\mathbf{else}:\\
\;\;\;\;t_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 4 regimes
  2. if a < -3.3999999999999999e-39 or 2.44999999999999986e186 < a

    1. Initial program 83.6%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.6%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*81.7%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified81.7%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in z around inf 51.2%

      \[\leadsto \color{blue}{-4 \cdot \frac{a \cdot t}{c}} \]
    5. Step-by-step derivation
      1. *-commutative51.2%

        \[\leadsto \color{blue}{\frac{a \cdot t}{c} \cdot -4} \]
      2. associate-/l*50.9%

        \[\leadsto \color{blue}{\frac{a}{\frac{c}{t}}} \cdot -4 \]
      3. associate-/r/50.8%

        \[\leadsto \color{blue}{\left(\frac{a}{c} \cdot t\right)} \cdot -4 \]
    6. Simplified50.8%

      \[\leadsto \color{blue}{\left(\frac{a}{c} \cdot t\right) \cdot -4} \]

    if -3.3999999999999999e-39 < a < 3.9e-225 or 9.8000000000000001e-172 < a < 2.90000000000000007e56 or 5.09999999999999987e158 < a < 2.44999999999999986e186

    1. Initial program 83.4%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.4%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*87.6%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified87.6%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in x around inf 49.6%

      \[\leadsto \color{blue}{9 \cdot \frac{y \cdot x}{c \cdot z}} \]

    if 3.9e-225 < a < 9.8000000000000001e-172

    1. Initial program 79.9%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*79.9%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*86.8%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified86.8%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in b around inf 44.6%

      \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]
    5. Step-by-step derivation
      1. associate-/r*50.9%

        \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]
    6. Simplified50.9%

      \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]

    if 2.90000000000000007e56 < a < 5.09999999999999987e158

    1. Initial program 90.2%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*85.5%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified95.0%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in z around inf 75.8%

      \[\leadsto \frac{\color{blue}{-4 \cdot \left(a \cdot t\right)}}{c} \]
    5. Step-by-step derivation
      1. associate-*r*75.8%

        \[\leadsto \frac{\color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative75.8%

        \[\leadsto \frac{\color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative75.8%

        \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified75.8%

      \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    7. Taylor expanded in t around 0 75.8%

      \[\leadsto \color{blue}{-4 \cdot \frac{a \cdot t}{c}} \]
    8. Step-by-step derivation
      1. *-commutative75.8%

        \[\leadsto -4 \cdot \frac{\color{blue}{t \cdot a}}{c} \]
      2. associate-/l*66.5%

        \[\leadsto -4 \cdot \color{blue}{\frac{t}{\frac{c}{a}}} \]
    9. Simplified66.5%

      \[\leadsto \color{blue}{-4 \cdot \frac{t}{\frac{c}{a}}} \]
  3. Recombined 4 regimes into one program.
  4. Final simplification51.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -3.4 \cdot 10^{-39}:\\ \;\;\;\;-4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \mathbf{elif}\;a \leq 3.9 \cdot 10^{-225}:\\ \;\;\;\;9 \cdot \frac{x \cdot y}{z \cdot c}\\ \mathbf{elif}\;a \leq 9.8 \cdot 10^{-172}:\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{elif}\;a \leq 2.9 \cdot 10^{+56}:\\ \;\;\;\;9 \cdot \frac{x \cdot y}{z \cdot c}\\ \mathbf{elif}\;a \leq 5.1 \cdot 10^{+158}:\\ \;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\ \mathbf{elif}\;a \leq 2.45 \cdot 10^{+186}:\\ \;\;\;\;9 \cdot \frac{x \cdot y}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \end{array} \]

Alternative 4: 49.2% accurate, 0.9× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} t_1 := 9 \cdot \frac{x \cdot y}{z \cdot c}\\ t_2 := -4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \mathbf{if}\;a \leq -4.1 \cdot 10^{-39}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;a \leq 1.05 \cdot 10^{-224}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;a \leq 2.1 \cdot 10^{-174}:\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{elif}\;a \leq 1.7 \cdot 10^{+56}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;a \leq 5.2 \cdot 10^{+158}:\\ \;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\ \mathbf{elif}\;a \leq 2.45 \cdot 10^{+186}:\\ \;\;\;\;\frac{9}{\frac{c}{x \cdot \frac{y}{z}}}\\ \mathbf{else}:\\ \;\;\;\;t_2\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (let* ((t_1 (* 9.0 (/ (* x y) (* z c)))) (t_2 (* -4.0 (* t (/ a c)))))
   (if (<= a -4.1e-39)
     t_2
     (if (<= a 1.05e-224)
       t_1
       (if (<= a 2.1e-174)
         (/ (/ b c) z)
         (if (<= a 1.7e+56)
           t_1
           (if (<= a 5.2e+158)
             (* -4.0 (/ t (/ c a)))
             (if (<= a 2.45e+186) (/ 9.0 (/ c (* x (/ y z)))) t_2))))))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = 9.0 * ((x * y) / (z * c));
	double t_2 = -4.0 * (t * (a / c));
	double tmp;
	if (a <= -4.1e-39) {
		tmp = t_2;
	} else if (a <= 1.05e-224) {
		tmp = t_1;
	} else if (a <= 2.1e-174) {
		tmp = (b / c) / z;
	} else if (a <= 1.7e+56) {
		tmp = t_1;
	} else if (a <= 5.2e+158) {
		tmp = -4.0 * (t / (c / a));
	} else if (a <= 2.45e+186) {
		tmp = 9.0 / (c / (x * (y / z)));
	} else {
		tmp = t_2;
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = 9.0d0 * ((x * y) / (z * c))
    t_2 = (-4.0d0) * (t * (a / c))
    if (a <= (-4.1d-39)) then
        tmp = t_2
    else if (a <= 1.05d-224) then
        tmp = t_1
    else if (a <= 2.1d-174) then
        tmp = (b / c) / z
    else if (a <= 1.7d+56) then
        tmp = t_1
    else if (a <= 5.2d+158) then
        tmp = (-4.0d0) * (t / (c / a))
    else if (a <= 2.45d+186) then
        tmp = 9.0d0 / (c / (x * (y / z)))
    else
        tmp = t_2
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = 9.0 * ((x * y) / (z * c));
	double t_2 = -4.0 * (t * (a / c));
	double tmp;
	if (a <= -4.1e-39) {
		tmp = t_2;
	} else if (a <= 1.05e-224) {
		tmp = t_1;
	} else if (a <= 2.1e-174) {
		tmp = (b / c) / z;
	} else if (a <= 1.7e+56) {
		tmp = t_1;
	} else if (a <= 5.2e+158) {
		tmp = -4.0 * (t / (c / a));
	} else if (a <= 2.45e+186) {
		tmp = 9.0 / (c / (x * (y / z)));
	} else {
		tmp = t_2;
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	t_1 = 9.0 * ((x * y) / (z * c))
	t_2 = -4.0 * (t * (a / c))
	tmp = 0
	if a <= -4.1e-39:
		tmp = t_2
	elif a <= 1.05e-224:
		tmp = t_1
	elif a <= 2.1e-174:
		tmp = (b / c) / z
	elif a <= 1.7e+56:
		tmp = t_1
	elif a <= 5.2e+158:
		tmp = -4.0 * (t / (c / a))
	elif a <= 2.45e+186:
		tmp = 9.0 / (c / (x * (y / z)))
	else:
		tmp = t_2
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	t_1 = Float64(9.0 * Float64(Float64(x * y) / Float64(z * c)))
	t_2 = Float64(-4.0 * Float64(t * Float64(a / c)))
	tmp = 0.0
	if (a <= -4.1e-39)
		tmp = t_2;
	elseif (a <= 1.05e-224)
		tmp = t_1;
	elseif (a <= 2.1e-174)
		tmp = Float64(Float64(b / c) / z);
	elseif (a <= 1.7e+56)
		tmp = t_1;
	elseif (a <= 5.2e+158)
		tmp = Float64(-4.0 * Float64(t / Float64(c / a)));
	elseif (a <= 2.45e+186)
		tmp = Float64(9.0 / Float64(c / Float64(x * Float64(y / z))));
	else
		tmp = t_2;
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	t_1 = 9.0 * ((x * y) / (z * c));
	t_2 = -4.0 * (t * (a / c));
	tmp = 0.0;
	if (a <= -4.1e-39)
		tmp = t_2;
	elseif (a <= 1.05e-224)
		tmp = t_1;
	elseif (a <= 2.1e-174)
		tmp = (b / c) / z;
	elseif (a <= 1.7e+56)
		tmp = t_1;
	elseif (a <= 5.2e+158)
		tmp = -4.0 * (t / (c / a));
	elseif (a <= 2.45e+186)
		tmp = 9.0 / (c / (x * (y / z)));
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := Block[{t$95$1 = N[(9.0 * N[(N[(x * y), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(t * N[(a / c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[a, -4.1e-39], t$95$2, If[LessEqual[a, 1.05e-224], t$95$1, If[LessEqual[a, 2.1e-174], N[(N[(b / c), $MachinePrecision] / z), $MachinePrecision], If[LessEqual[a, 1.7e+56], t$95$1, If[LessEqual[a, 5.2e+158], N[(-4.0 * N[(t / N[(c / a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[a, 2.45e+186], N[(9.0 / N[(c / N[(x * N[(y / z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$2]]]]]]]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
t_1 := 9 \cdot \frac{x \cdot y}{z \cdot c}\\
t_2 := -4 \cdot \left(t \cdot \frac{a}{c}\right)\\
\mathbf{if}\;a \leq -4.1 \cdot 10^{-39}:\\
\;\;\;\;t_2\\

\mathbf{elif}\;a \leq 1.05 \cdot 10^{-224}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;a \leq 2.1 \cdot 10^{-174}:\\
\;\;\;\;\frac{\frac{b}{c}}{z}\\

\mathbf{elif}\;a \leq 1.7 \cdot 10^{+56}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;a \leq 5.2 \cdot 10^{+158}:\\
\;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\

\mathbf{elif}\;a \leq 2.45 \cdot 10^{+186}:\\
\;\;\;\;\frac{9}{\frac{c}{x \cdot \frac{y}{z}}}\\

\mathbf{else}:\\
\;\;\;\;t_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 5 regimes
  2. if a < -4.1e-39 or 2.44999999999999986e186 < a

    1. Initial program 83.6%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.6%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*81.7%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified81.7%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in z around inf 51.2%

      \[\leadsto \color{blue}{-4 \cdot \frac{a \cdot t}{c}} \]
    5. Step-by-step derivation
      1. *-commutative51.2%

        \[\leadsto \color{blue}{\frac{a \cdot t}{c} \cdot -4} \]
      2. associate-/l*50.9%

        \[\leadsto \color{blue}{\frac{a}{\frac{c}{t}}} \cdot -4 \]
      3. associate-/r/50.8%

        \[\leadsto \color{blue}{\left(\frac{a}{c} \cdot t\right)} \cdot -4 \]
    6. Simplified50.8%

      \[\leadsto \color{blue}{\left(\frac{a}{c} \cdot t\right) \cdot -4} \]

    if -4.1e-39 < a < 1.05000000000000003e-224 or 2.1000000000000001e-174 < a < 1.7e56

    1. Initial program 84.3%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*84.3%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*90.3%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified90.3%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in x around inf 50.7%

      \[\leadsto \color{blue}{9 \cdot \frac{y \cdot x}{c \cdot z}} \]

    if 1.05000000000000003e-224 < a < 2.1000000000000001e-174

    1. Initial program 78.3%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*78.3%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*85.8%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified85.8%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in b around inf 47.9%

      \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]
    5. Step-by-step derivation
      1. associate-/r*54.6%

        \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]
    6. Simplified54.6%

      \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]

    if 1.7e56 < a < 5.2e158

    1. Initial program 90.2%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*85.5%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified95.0%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in z around inf 75.8%

      \[\leadsto \frac{\color{blue}{-4 \cdot \left(a \cdot t\right)}}{c} \]
    5. Step-by-step derivation
      1. associate-*r*75.8%

        \[\leadsto \frac{\color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative75.8%

        \[\leadsto \frac{\color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative75.8%

        \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified75.8%

      \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    7. Taylor expanded in t around 0 75.8%

      \[\leadsto \color{blue}{-4 \cdot \frac{a \cdot t}{c}} \]
    8. Step-by-step derivation
      1. *-commutative75.8%

        \[\leadsto -4 \cdot \frac{\color{blue}{t \cdot a}}{c} \]
      2. associate-/l*66.5%

        \[\leadsto -4 \cdot \color{blue}{\frac{t}{\frac{c}{a}}} \]
    9. Simplified66.5%

      \[\leadsto \color{blue}{-4 \cdot \frac{t}{\frac{c}{a}}} \]

    if 5.2e158 < a < 2.44999999999999986e186

    1. Initial program 67.6%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*68.1%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified51.4%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in x around inf 51.6%

      \[\leadsto \frac{\color{blue}{9 \cdot \frac{y \cdot x}{z}} + t \cdot \left(a \cdot -4\right)}{c} \]
    5. Taylor expanded in y around inf 35.1%

      \[\leadsto \frac{\color{blue}{9 \cdot \frac{y \cdot x}{z}}}{c} \]
    6. Step-by-step derivation
      1. *-un-lft-identity35.1%

        \[\leadsto \color{blue}{1 \cdot \frac{9 \cdot \frac{y \cdot x}{z}}{c}} \]
      2. associate-/l*34.9%

        \[\leadsto 1 \cdot \color{blue}{\frac{9}{\frac{c}{\frac{y \cdot x}{z}}}} \]
      3. associate-/l*35.1%

        \[\leadsto 1 \cdot \frac{9}{\frac{c}{\color{blue}{\frac{y}{\frac{z}{x}}}}} \]
      4. associate-/r/35.1%

        \[\leadsto 1 \cdot \frac{9}{\frac{c}{\color{blue}{\frac{y}{z} \cdot x}}} \]
    7. Applied egg-rr35.1%

      \[\leadsto \color{blue}{1 \cdot \frac{9}{\frac{c}{\frac{y}{z} \cdot x}}} \]
  3. Recombined 5 regimes into one program.
  4. Final simplification51.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -4.1 \cdot 10^{-39}:\\ \;\;\;\;-4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \mathbf{elif}\;a \leq 1.05 \cdot 10^{-224}:\\ \;\;\;\;9 \cdot \frac{x \cdot y}{z \cdot c}\\ \mathbf{elif}\;a \leq 2.1 \cdot 10^{-174}:\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{elif}\;a \leq 1.7 \cdot 10^{+56}:\\ \;\;\;\;9 \cdot \frac{x \cdot y}{z \cdot c}\\ \mathbf{elif}\;a \leq 5.2 \cdot 10^{+158}:\\ \;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\ \mathbf{elif}\;a \leq 2.45 \cdot 10^{+186}:\\ \;\;\;\;\frac{9}{\frac{c}{x \cdot \frac{y}{z}}}\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \end{array} \]

Alternative 5: 82.5% accurate, 0.9× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;z \leq -5 \cdot 10^{+112}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + \left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right)}{z \cdot c}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (<= z -5e+112)
   (/ (+ (* t (* a -4.0)) (/ b z)) c)
   (/ (+ b (- (* x (* 9.0 y)) (* (* z 4.0) (* t a)))) (* z c))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if (z <= -5e+112) {
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	} else {
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c);
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if (z <= (-5d+112)) then
        tmp = ((t * (a * (-4.0d0))) + (b / z)) / c
    else
        tmp = (b + ((x * (9.0d0 * y)) - ((z * 4.0d0) * (t * a)))) / (z * c)
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if (z <= -5e+112) {
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	} else {
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c);
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if z <= -5e+112:
		tmp = ((t * (a * -4.0)) + (b / z)) / c
	else:
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c)
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if (z <= -5e+112)
		tmp = Float64(Float64(Float64(t * Float64(a * -4.0)) + Float64(b / z)) / c);
	else
		tmp = Float64(Float64(b + Float64(Float64(x * Float64(9.0 * y)) - Float64(Float64(z * 4.0) * Float64(t * a)))) / Float64(z * c));
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if (z <= -5e+112)
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	else
		tmp = (b + ((x * (9.0 * y)) - ((z * 4.0) * (t * a)))) / (z * c);
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[LessEqual[z, -5e+112], N[(N[(N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision] + N[(b / z), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision], N[(N[(b + N[(N[(x * N[(9.0 * y), $MachinePrecision]), $MachinePrecision] - N[(N[(z * 4.0), $MachinePrecision] * N[(t * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;z \leq -5 \cdot 10^{+112}:\\
\;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\

\mathbf{else}:\\
\;\;\;\;\frac{b + \left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right)}{z \cdot c}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if z < -5e112

    1. Initial program 59.8%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*67.0%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified93.6%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in x around 0 84.0%

      \[\leadsto \color{blue}{\frac{\frac{b}{z} + -4 \cdot \left(a \cdot t\right)}{c}} \]
    5. Step-by-step derivation
      1. associate-*r*84.1%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative84.1%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative84.1%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified84.1%

      \[\leadsto \color{blue}{\frac{\frac{b}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]

    if -5e112 < z

    1. Initial program 89.6%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*89.6%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*88.7%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified88.7%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification87.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq -5 \cdot 10^{+112}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + \left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right)}{z \cdot c}\\ \end{array} \]

Alternative 6: 70.4% accurate, 1.0× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;a \leq -1.08 \cdot 10^{-41} \lor \neg \left(a \leq 1.72 \cdot 10^{+59} \lor \neg \left(a \leq 3.2 \cdot 10^{+148}\right) \land a \leq 2.45 \cdot 10^{+186}\right):\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (or (<= a -1.08e-41)
         (not
          (or (<= a 1.72e+59) (and (not (<= a 3.2e+148)) (<= a 2.45e+186)))))
   (/ (+ (* t (* a -4.0)) (/ b z)) c)
   (/ (+ b (* 9.0 (* x y))) (* z c))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((a <= -1.08e-41) || !((a <= 1.72e+59) || (!(a <= 3.2e+148) && (a <= 2.45e+186)))) {
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	} else {
		tmp = (b + (9.0 * (x * y))) / (z * c);
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if ((a <= (-1.08d-41)) .or. (.not. (a <= 1.72d+59) .or. (.not. (a <= 3.2d+148)) .and. (a <= 2.45d+186))) then
        tmp = ((t * (a * (-4.0d0))) + (b / z)) / c
    else
        tmp = (b + (9.0d0 * (x * y))) / (z * c)
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((a <= -1.08e-41) || !((a <= 1.72e+59) || (!(a <= 3.2e+148) && (a <= 2.45e+186)))) {
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	} else {
		tmp = (b + (9.0 * (x * y))) / (z * c);
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if (a <= -1.08e-41) or not ((a <= 1.72e+59) or (not (a <= 3.2e+148) and (a <= 2.45e+186))):
		tmp = ((t * (a * -4.0)) + (b / z)) / c
	else:
		tmp = (b + (9.0 * (x * y))) / (z * c)
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if ((a <= -1.08e-41) || !((a <= 1.72e+59) || (!(a <= 3.2e+148) && (a <= 2.45e+186))))
		tmp = Float64(Float64(Float64(t * Float64(a * -4.0)) + Float64(b / z)) / c);
	else
		tmp = Float64(Float64(b + Float64(9.0 * Float64(x * y))) / Float64(z * c));
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if ((a <= -1.08e-41) || ~(((a <= 1.72e+59) || (~((a <= 3.2e+148)) && (a <= 2.45e+186)))))
		tmp = ((t * (a * -4.0)) + (b / z)) / c;
	else
		tmp = (b + (9.0 * (x * y))) / (z * c);
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[Or[LessEqual[a, -1.08e-41], N[Not[Or[LessEqual[a, 1.72e+59], And[N[Not[LessEqual[a, 3.2e+148]], $MachinePrecision], LessEqual[a, 2.45e+186]]]], $MachinePrecision]], N[(N[(N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision] + N[(b / z), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision], N[(N[(b + N[(9.0 * N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;a \leq -1.08 \cdot 10^{-41} \lor \neg \left(a \leq 1.72 \cdot 10^{+59} \lor \neg \left(a \leq 3.2 \cdot 10^{+148}\right) \land a \leq 2.45 \cdot 10^{+186}\right):\\
\;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\

\mathbf{else}:\\
\;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -1.08e-41 or 1.71999999999999996e59 < a < 3.1999999999999999e148 or 2.44999999999999986e186 < a

    1. Initial program 84.5%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*81.2%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified88.9%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in x around 0 75.0%

      \[\leadsto \color{blue}{\frac{\frac{b}{z} + -4 \cdot \left(a \cdot t\right)}{c}} \]
    5. Step-by-step derivation
      1. associate-*r*75.0%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative75.0%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative75.0%

        \[\leadsto \frac{\frac{b}{z} + \color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified75.0%

      \[\leadsto \color{blue}{\frac{\frac{b}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]

    if -1.08e-41 < a < 1.71999999999999996e59 or 3.1999999999999999e148 < a < 2.44999999999999986e186

    1. Initial program 83.3%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.3%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*87.7%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified87.7%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in x around inf 77.9%

      \[\leadsto \frac{\color{blue}{9 \cdot \left(y \cdot x\right)} + b}{z \cdot c} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification76.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -1.08 \cdot 10^{-41} \lor \neg \left(a \leq 1.72 \cdot 10^{+59} \lor \neg \left(a \leq 3.2 \cdot 10^{+148}\right) \land a \leq 2.45 \cdot 10^{+186}\right):\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + \frac{b}{z}}{c}\\ \mathbf{else}:\\ \;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ \end{array} \]

Alternative 7: 66.5% accurate, 1.0× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} t_1 := \frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ t_2 := -4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \mathbf{if}\;a \leq -5.8 \cdot 10^{-39}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;a \leq 1.55 \cdot 10^{+58}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;a \leq 4 \cdot 10^{+145}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right)}{c}\\ \mathbf{elif}\;a \leq 5.8 \cdot 10^{+186}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;t_2\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (let* ((t_1 (/ (+ b (* 9.0 (* x y))) (* z c))) (t_2 (* -4.0 (* t (/ a c)))))
   (if (<= a -5.8e-39)
     t_2
     (if (<= a 1.55e+58)
       t_1
       (if (<= a 4e+145)
         (/ (* t (* a -4.0)) c)
         (if (<= a 5.8e+186) t_1 t_2))))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = (b + (9.0 * (x * y))) / (z * c);
	double t_2 = -4.0 * (t * (a / c));
	double tmp;
	if (a <= -5.8e-39) {
		tmp = t_2;
	} else if (a <= 1.55e+58) {
		tmp = t_1;
	} else if (a <= 4e+145) {
		tmp = (t * (a * -4.0)) / c;
	} else if (a <= 5.8e+186) {
		tmp = t_1;
	} else {
		tmp = t_2;
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: tmp
    t_1 = (b + (9.0d0 * (x * y))) / (z * c)
    t_2 = (-4.0d0) * (t * (a / c))
    if (a <= (-5.8d-39)) then
        tmp = t_2
    else if (a <= 1.55d+58) then
        tmp = t_1
    else if (a <= 4d+145) then
        tmp = (t * (a * (-4.0d0))) / c
    else if (a <= 5.8d+186) then
        tmp = t_1
    else
        tmp = t_2
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = (b + (9.0 * (x * y))) / (z * c);
	double t_2 = -4.0 * (t * (a / c));
	double tmp;
	if (a <= -5.8e-39) {
		tmp = t_2;
	} else if (a <= 1.55e+58) {
		tmp = t_1;
	} else if (a <= 4e+145) {
		tmp = (t * (a * -4.0)) / c;
	} else if (a <= 5.8e+186) {
		tmp = t_1;
	} else {
		tmp = t_2;
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	t_1 = (b + (9.0 * (x * y))) / (z * c)
	t_2 = -4.0 * (t * (a / c))
	tmp = 0
	if a <= -5.8e-39:
		tmp = t_2
	elif a <= 1.55e+58:
		tmp = t_1
	elif a <= 4e+145:
		tmp = (t * (a * -4.0)) / c
	elif a <= 5.8e+186:
		tmp = t_1
	else:
		tmp = t_2
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	t_1 = Float64(Float64(b + Float64(9.0 * Float64(x * y))) / Float64(z * c))
	t_2 = Float64(-4.0 * Float64(t * Float64(a / c)))
	tmp = 0.0
	if (a <= -5.8e-39)
		tmp = t_2;
	elseif (a <= 1.55e+58)
		tmp = t_1;
	elseif (a <= 4e+145)
		tmp = Float64(Float64(t * Float64(a * -4.0)) / c);
	elseif (a <= 5.8e+186)
		tmp = t_1;
	else
		tmp = t_2;
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	t_1 = (b + (9.0 * (x * y))) / (z * c);
	t_2 = -4.0 * (t * (a / c));
	tmp = 0.0;
	if (a <= -5.8e-39)
		tmp = t_2;
	elseif (a <= 1.55e+58)
		tmp = t_1;
	elseif (a <= 4e+145)
		tmp = (t * (a * -4.0)) / c;
	elseif (a <= 5.8e+186)
		tmp = t_1;
	else
		tmp = t_2;
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := Block[{t$95$1 = N[(N[(b + N[(9.0 * N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(-4.0 * N[(t * N[(a / c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[a, -5.8e-39], t$95$2, If[LessEqual[a, 1.55e+58], t$95$1, If[LessEqual[a, 4e+145], N[(N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision], If[LessEqual[a, 5.8e+186], t$95$1, t$95$2]]]]]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
t_1 := \frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\
t_2 := -4 \cdot \left(t \cdot \frac{a}{c}\right)\\
\mathbf{if}\;a \leq -5.8 \cdot 10^{-39}:\\
\;\;\;\;t_2\\

\mathbf{elif}\;a \leq 1.55 \cdot 10^{+58}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;a \leq 4 \cdot 10^{+145}:\\
\;\;\;\;\frac{t \cdot \left(a \cdot -4\right)}{c}\\

\mathbf{elif}\;a \leq 5.8 \cdot 10^{+186}:\\
\;\;\;\;t_1\\

\mathbf{else}:\\
\;\;\;\;t_2\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if a < -5.79999999999999975e-39 or 5.8e186 < a

    1. Initial program 83.6%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.6%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*81.7%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified81.7%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in z around inf 51.2%

      \[\leadsto \color{blue}{-4 \cdot \frac{a \cdot t}{c}} \]
    5. Step-by-step derivation
      1. *-commutative51.2%

        \[\leadsto \color{blue}{\frac{a \cdot t}{c} \cdot -4} \]
      2. associate-/l*50.9%

        \[\leadsto \color{blue}{\frac{a}{\frac{c}{t}}} \cdot -4 \]
      3. associate-/r/50.8%

        \[\leadsto \color{blue}{\left(\frac{a}{c} \cdot t\right)} \cdot -4 \]
    6. Simplified50.8%

      \[\leadsto \color{blue}{\left(\frac{a}{c} \cdot t\right) \cdot -4} \]

    if -5.79999999999999975e-39 < a < 1.55e58 or 4e145 < a < 5.8e186

    1. Initial program 83.3%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.3%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*87.7%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified87.7%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in x around inf 77.9%

      \[\leadsto \frac{\color{blue}{9 \cdot \left(y \cdot x\right)} + b}{z \cdot c} \]

    if 1.55e58 < a < 4e145

    1. Initial program 89.1%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*89.3%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified99.8%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in z around inf 78.3%

      \[\leadsto \frac{\color{blue}{-4 \cdot \left(a \cdot t\right)}}{c} \]
    5. Step-by-step derivation
      1. associate-*r*78.3%

        \[\leadsto \frac{\color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative78.3%

        \[\leadsto \frac{\color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative78.3%

        \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified78.3%

      \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification68.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -5.8 \cdot 10^{-39}:\\ \;\;\;\;-4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \mathbf{elif}\;a \leq 1.55 \cdot 10^{+58}:\\ \;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ \mathbf{elif}\;a \leq 4 \cdot 10^{+145}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right)}{c}\\ \mathbf{elif}\;a \leq 5.8 \cdot 10^{+186}:\\ \;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \left(t \cdot \frac{a}{c}\right)\\ \end{array} \]

Alternative 8: 73.1% accurate, 1.0× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;b \leq -2.6 \cdot 10^{+42} \lor \neg \left(b \leq 7.5 \cdot 10^{-75}\right):\\ \;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + 9 \cdot \frac{x \cdot y}{z}}{c}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (or (<= b -2.6e+42) (not (<= b 7.5e-75)))
   (/ (+ b (* 9.0 (* x y))) (* z c))
   (/ (+ (* t (* a -4.0)) (* 9.0 (/ (* x y) z))) c)))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((b <= -2.6e+42) || !(b <= 7.5e-75)) {
		tmp = (b + (9.0 * (x * y))) / (z * c);
	} else {
		tmp = ((t * (a * -4.0)) + (9.0 * ((x * y) / z))) / c;
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if ((b <= (-2.6d+42)) .or. (.not. (b <= 7.5d-75))) then
        tmp = (b + (9.0d0 * (x * y))) / (z * c)
    else
        tmp = ((t * (a * (-4.0d0))) + (9.0d0 * ((x * y) / z))) / c
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((b <= -2.6e+42) || !(b <= 7.5e-75)) {
		tmp = (b + (9.0 * (x * y))) / (z * c);
	} else {
		tmp = ((t * (a * -4.0)) + (9.0 * ((x * y) / z))) / c;
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if (b <= -2.6e+42) or not (b <= 7.5e-75):
		tmp = (b + (9.0 * (x * y))) / (z * c)
	else:
		tmp = ((t * (a * -4.0)) + (9.0 * ((x * y) / z))) / c
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if ((b <= -2.6e+42) || !(b <= 7.5e-75))
		tmp = Float64(Float64(b + Float64(9.0 * Float64(x * y))) / Float64(z * c));
	else
		tmp = Float64(Float64(Float64(t * Float64(a * -4.0)) + Float64(9.0 * Float64(Float64(x * y) / z))) / c);
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if ((b <= -2.6e+42) || ~((b <= 7.5e-75)))
		tmp = (b + (9.0 * (x * y))) / (z * c);
	else
		tmp = ((t * (a * -4.0)) + (9.0 * ((x * y) / z))) / c;
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[Or[LessEqual[b, -2.6e+42], N[Not[LessEqual[b, 7.5e-75]], $MachinePrecision]], N[(N[(b + N[(9.0 * N[(x * y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision], N[(N[(N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision] + N[(9.0 * N[(N[(x * y), $MachinePrecision] / z), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;b \leq -2.6 \cdot 10^{+42} \lor \neg \left(b \leq 7.5 \cdot 10^{-75}\right):\\
\;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\

\mathbf{else}:\\
\;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + 9 \cdot \frac{x \cdot y}{z}}{c}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < -2.5999999999999999e42 or 7.50000000000000017e-75 < b

    1. Initial program 87.2%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*87.2%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*89.4%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified89.4%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in x around inf 81.4%

      \[\leadsto \frac{\color{blue}{9 \cdot \left(y \cdot x\right)} + b}{z \cdot c} \]

    if -2.5999999999999999e42 < b < 7.50000000000000017e-75

    1. Initial program 80.4%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*80.3%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified87.8%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in x around inf 82.1%

      \[\leadsto \frac{\color{blue}{9 \cdot \frac{y \cdot x}{z}} + t \cdot \left(a \cdot -4\right)}{c} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification81.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -2.6 \cdot 10^{+42} \lor \neg \left(b \leq 7.5 \cdot 10^{-75}\right):\\ \;\;\;\;\frac{b + 9 \cdot \left(x \cdot y\right)}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right) + 9 \cdot \frac{x \cdot y}{z}}{c}\\ \end{array} \]

Alternative 9: 49.9% accurate, 1.7× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;b \leq -3.1 \cdot 10^{+40} \lor \neg \left(b \leq 2.5 \cdot 10^{-62}\right):\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (or (<= b -3.1e+40) (not (<= b 2.5e-62)))
   (/ (/ b c) z)
   (* -4.0 (/ t (/ c a)))))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((b <= -3.1e+40) || !(b <= 2.5e-62)) {
		tmp = (b / c) / z;
	} else {
		tmp = -4.0 * (t / (c / a));
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if ((b <= (-3.1d+40)) .or. (.not. (b <= 2.5d-62))) then
        tmp = (b / c) / z
    else
        tmp = (-4.0d0) * (t / (c / a))
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((b <= -3.1e+40) || !(b <= 2.5e-62)) {
		tmp = (b / c) / z;
	} else {
		tmp = -4.0 * (t / (c / a));
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if (b <= -3.1e+40) or not (b <= 2.5e-62):
		tmp = (b / c) / z
	else:
		tmp = -4.0 * (t / (c / a))
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if ((b <= -3.1e+40) || !(b <= 2.5e-62))
		tmp = Float64(Float64(b / c) / z);
	else
		tmp = Float64(-4.0 * Float64(t / Float64(c / a)));
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if ((b <= -3.1e+40) || ~((b <= 2.5e-62)))
		tmp = (b / c) / z;
	else
		tmp = -4.0 * (t / (c / a));
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[Or[LessEqual[b, -3.1e+40], N[Not[LessEqual[b, 2.5e-62]], $MachinePrecision]], N[(N[(b / c), $MachinePrecision] / z), $MachinePrecision], N[(-4.0 * N[(t / N[(c / a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;b \leq -3.1 \cdot 10^{+40} \lor \neg \left(b \leq 2.5 \cdot 10^{-62}\right):\\
\;\;\;\;\frac{\frac{b}{c}}{z}\\

\mathbf{else}:\\
\;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < -3.0999999999999998e40 or 2.5000000000000001e-62 < b

    1. Initial program 87.7%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*87.7%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*90.0%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified90.0%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in b around inf 55.1%

      \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]
    5. Step-by-step derivation
      1. associate-/r*56.5%

        \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]
    6. Simplified56.5%

      \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]

    if -3.0999999999999998e40 < b < 2.5000000000000001e-62

    1. Initial program 80.1%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*80.0%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified88.0%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in z around inf 52.2%

      \[\leadsto \frac{\color{blue}{-4 \cdot \left(a \cdot t\right)}}{c} \]
    5. Step-by-step derivation
      1. associate-*r*52.2%

        \[\leadsto \frac{\color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative52.2%

        \[\leadsto \frac{\color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative52.2%

        \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified52.2%

      \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    7. Taylor expanded in t around 0 52.1%

      \[\leadsto \color{blue}{-4 \cdot \frac{a \cdot t}{c}} \]
    8. Step-by-step derivation
      1. *-commutative52.1%

        \[\leadsto -4 \cdot \frac{\color{blue}{t \cdot a}}{c} \]
      2. associate-/l*48.8%

        \[\leadsto -4 \cdot \color{blue}{\frac{t}{\frac{c}{a}}} \]
    9. Simplified48.8%

      \[\leadsto \color{blue}{-4 \cdot \frac{t}{\frac{c}{a}}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification52.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -3.1 \cdot 10^{+40} \lor \neg \left(b \leq 2.5 \cdot 10^{-62}\right):\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{else}:\\ \;\;\;\;-4 \cdot \frac{t}{\frac{c}{a}}\\ \end{array} \]

Alternative 10: 49.6% accurate, 1.7× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;b \leq -5.2 \cdot 10^{+41} \lor \neg \left(b \leq 3 \cdot 10^{-53}\right):\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right)}{c}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (or (<= b -5.2e+41) (not (<= b 3e-53)))
   (/ (/ b c) z)
   (/ (* t (* a -4.0)) c)))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((b <= -5.2e+41) || !(b <= 3e-53)) {
		tmp = (b / c) / z;
	} else {
		tmp = (t * (a * -4.0)) / c;
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if ((b <= (-5.2d+41)) .or. (.not. (b <= 3d-53))) then
        tmp = (b / c) / z
    else
        tmp = (t * (a * (-4.0d0))) / c
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if ((b <= -5.2e+41) || !(b <= 3e-53)) {
		tmp = (b / c) / z;
	} else {
		tmp = (t * (a * -4.0)) / c;
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if (b <= -5.2e+41) or not (b <= 3e-53):
		tmp = (b / c) / z
	else:
		tmp = (t * (a * -4.0)) / c
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if ((b <= -5.2e+41) || !(b <= 3e-53))
		tmp = Float64(Float64(b / c) / z);
	else
		tmp = Float64(Float64(t * Float64(a * -4.0)) / c);
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if ((b <= -5.2e+41) || ~((b <= 3e-53)))
		tmp = (b / c) / z;
	else
		tmp = (t * (a * -4.0)) / c;
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[Or[LessEqual[b, -5.2e+41], N[Not[LessEqual[b, 3e-53]], $MachinePrecision]], N[(N[(b / c), $MachinePrecision] / z), $MachinePrecision], N[(N[(t * N[(a * -4.0), $MachinePrecision]), $MachinePrecision] / c), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;b \leq -5.2 \cdot 10^{+41} \lor \neg \left(b \leq 3 \cdot 10^{-53}\right):\\
\;\;\;\;\frac{\frac{b}{c}}{z}\\

\mathbf{else}:\\
\;\;\;\;\frac{t \cdot \left(a \cdot -4\right)}{c}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < -5.2000000000000001e41 or 3.0000000000000002e-53 < b

    1. Initial program 87.7%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*87.7%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*90.0%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified90.0%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in b around inf 55.1%

      \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]
    5. Step-by-step derivation
      1. associate-/r*56.5%

        \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]
    6. Simplified56.5%

      \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]

    if -5.2000000000000001e41 < b < 3.0000000000000002e-53

    1. Initial program 80.1%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-/r*80.0%

        \[\leadsto \color{blue}{\frac{\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z}}{c}} \]
    3. Simplified88.0%

      \[\leadsto \color{blue}{\frac{\frac{\mathsf{fma}\left(x, 9 \cdot y, b\right)}{z} + t \cdot \left(a \cdot -4\right)}{c}} \]
    4. Taylor expanded in z around inf 52.2%

      \[\leadsto \frac{\color{blue}{-4 \cdot \left(a \cdot t\right)}}{c} \]
    5. Step-by-step derivation
      1. associate-*r*52.2%

        \[\leadsto \frac{\color{blue}{\left(-4 \cdot a\right) \cdot t}}{c} \]
      2. *-commutative52.2%

        \[\leadsto \frac{\color{blue}{\left(a \cdot -4\right)} \cdot t}{c} \]
      3. *-commutative52.2%

        \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
    6. Simplified52.2%

      \[\leadsto \frac{\color{blue}{t \cdot \left(a \cdot -4\right)}}{c} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification54.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -5.2 \cdot 10^{+41} \lor \neg \left(b \leq 3 \cdot 10^{-53}\right):\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \mathbf{else}:\\ \;\;\;\;\frac{t \cdot \left(a \cdot -4\right)}{c}\\ \end{array} \]

Alternative 11: 34.7% accurate, 2.7× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \begin{array}{l} \mathbf{if}\;x \leq -3.8 \cdot 10^{-180}:\\ \;\;\;\;\frac{b}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \end{array} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c)
 :precision binary64
 (if (<= x -3.8e-180) (/ b (* z c)) (/ (/ b c) z)))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if (x <= -3.8e-180) {
		tmp = b / (z * c);
	} else {
		tmp = (b / c) / z;
	}
	return tmp;
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: tmp
    if (x <= (-3.8d-180)) then
        tmp = b / (z * c)
    else
        tmp = (b / c) / z
    end if
    code = tmp
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double tmp;
	if (x <= -3.8e-180) {
		tmp = b / (z * c);
	} else {
		tmp = (b / c) / z;
	}
	return tmp;
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	tmp = 0
	if x <= -3.8e-180:
		tmp = b / (z * c)
	else:
		tmp = (b / c) / z
	return tmp
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	tmp = 0.0
	if (x <= -3.8e-180)
		tmp = Float64(b / Float64(z * c));
	else
		tmp = Float64(Float64(b / c) / z);
	end
	return tmp
end
t, a = num2cell(sort([t, a])){:}
function tmp_2 = code(x, y, z, t, a, b, c)
	tmp = 0.0;
	if (x <= -3.8e-180)
		tmp = b / (z * c);
	else
		tmp = (b / c) / z;
	end
	tmp_2 = tmp;
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := If[LessEqual[x, -3.8e-180], N[(b / N[(z * c), $MachinePrecision]), $MachinePrecision], N[(N[(b / c), $MachinePrecision] / z), $MachinePrecision]]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\begin{array}{l}
\mathbf{if}\;x \leq -3.8 \cdot 10^{-180}:\\
\;\;\;\;\frac{b}{z \cdot c}\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{b}{c}}{z}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if x < -3.79999999999999999e-180

    1. Initial program 83.8%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.8%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*87.2%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified87.2%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in b around inf 30.8%

      \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]

    if -3.79999999999999999e-180 < x

    1. Initial program 83.8%

      \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. Step-by-step derivation
      1. associate-*l*83.8%

        \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
      2. associate-*l*84.5%

        \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
    3. Simplified84.5%

      \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
    4. Taylor expanded in b around inf 37.1%

      \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]
    5. Step-by-step derivation
      1. associate-/r*37.6%

        \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]
    6. Simplified37.6%

      \[\leadsto \color{blue}{\frac{\frac{b}{c}}{z}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification34.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -3.8 \cdot 10^{-180}:\\ \;\;\;\;\frac{b}{z \cdot c}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{b}{c}}{z}\\ \end{array} \]

Alternative 12: 35.2% accurate, 3.8× speedup?

\[\begin{array}{l} [t, a] = \mathsf{sort}([t, a])\\ \\ \frac{b}{z \cdot c} \end{array} \]
NOTE: t and a should be sorted in increasing order before calling this function.
(FPCore (x y z t a b c) :precision binary64 (/ b (* z c)))
assert(t < a);
double code(double x, double y, double z, double t, double a, double b, double c) {
	return b / (z * c);
}
NOTE: t and a should be sorted in increasing order before calling this function.
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    code = b / (z * c)
end function
assert t < a;
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	return b / (z * c);
}
[t, a] = sort([t, a])
def code(x, y, z, t, a, b, c):
	return b / (z * c)
t, a = sort([t, a])
function code(x, y, z, t, a, b, c)
	return Float64(b / Float64(z * c))
end
t, a = num2cell(sort([t, a])){:}
function tmp = code(x, y, z, t, a, b, c)
	tmp = b / (z * c);
end
NOTE: t and a should be sorted in increasing order before calling this function.
code[x_, y_, z_, t_, a_, b_, c_] := N[(b / N[(z * c), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}
[t, a] = \mathsf{sort}([t, a])\\
\\
\frac{b}{z \cdot c}
\end{array}
Derivation
  1. Initial program 83.8%

    \[\frac{\left(\left(x \cdot 9\right) \cdot y - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
  2. Step-by-step derivation
    1. associate-*l*83.8%

      \[\leadsto \frac{\left(\color{blue}{x \cdot \left(9 \cdot y\right)} - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b}{z \cdot c} \]
    2. associate-*l*85.6%

      \[\leadsto \frac{\left(x \cdot \left(9 \cdot y\right) - \color{blue}{\left(z \cdot 4\right) \cdot \left(t \cdot a\right)}\right) + b}{z \cdot c} \]
  3. Simplified85.6%

    \[\leadsto \color{blue}{\frac{\left(x \cdot \left(9 \cdot y\right) - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}} \]
  4. Taylor expanded in b around inf 34.5%

    \[\leadsto \color{blue}{\frac{b}{c \cdot z}} \]
  5. Final simplification34.5%

    \[\leadsto \frac{b}{z \cdot c} \]

Developer target: 80.5% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_1 := \frac{b}{c \cdot z}\\ t_2 := 4 \cdot \frac{a \cdot t}{c}\\ t_3 := \left(x \cdot 9\right) \cdot y\\ t_4 := \left(t_3 - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b\\ t_5 := \frac{t_4}{z \cdot c}\\ t_6 := \frac{\left(t_3 - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}\\ \mathbf{if}\;t_5 < -1.100156740804105 \cdot 10^{-171}:\\ \;\;\;\;t_6\\ \mathbf{elif}\;t_5 < 0:\\ \;\;\;\;\frac{\frac{t_4}{z}}{c}\\ \mathbf{elif}\;t_5 < 1.1708877911747488 \cdot 10^{-53}:\\ \;\;\;\;t_6\\ \mathbf{elif}\;t_5 < 2.876823679546137 \cdot 10^{+130}:\\ \;\;\;\;\left(\left(9 \cdot \frac{y}{c}\right) \cdot \frac{x}{z} + t_1\right) - t_2\\ \mathbf{elif}\;t_5 < 1.3838515042456319 \cdot 10^{+158}:\\ \;\;\;\;t_6\\ \mathbf{else}:\\ \;\;\;\;\left(9 \cdot \left(\frac{y}{c \cdot z} \cdot x\right) + t_1\right) - t_2\\ \end{array} \end{array} \]
(FPCore (x y z t a b c)
 :precision binary64
 (let* ((t_1 (/ b (* c z)))
        (t_2 (* 4.0 (/ (* a t) c)))
        (t_3 (* (* x 9.0) y))
        (t_4 (+ (- t_3 (* (* (* z 4.0) t) a)) b))
        (t_5 (/ t_4 (* z c)))
        (t_6 (/ (+ (- t_3 (* (* z 4.0) (* t a))) b) (* z c))))
   (if (< t_5 -1.100156740804105e-171)
     t_6
     (if (< t_5 0.0)
       (/ (/ t_4 z) c)
       (if (< t_5 1.1708877911747488e-53)
         t_6
         (if (< t_5 2.876823679546137e+130)
           (- (+ (* (* 9.0 (/ y c)) (/ x z)) t_1) t_2)
           (if (< t_5 1.3838515042456319e+158)
             t_6
             (- (+ (* 9.0 (* (/ y (* c z)) x)) t_1) t_2))))))))
double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = b / (c * z);
	double t_2 = 4.0 * ((a * t) / c);
	double t_3 = (x * 9.0) * y;
	double t_4 = (t_3 - (((z * 4.0) * t) * a)) + b;
	double t_5 = t_4 / (z * c);
	double t_6 = ((t_3 - ((z * 4.0) * (t * a))) + b) / (z * c);
	double tmp;
	if (t_5 < -1.100156740804105e-171) {
		tmp = t_6;
	} else if (t_5 < 0.0) {
		tmp = (t_4 / z) / c;
	} else if (t_5 < 1.1708877911747488e-53) {
		tmp = t_6;
	} else if (t_5 < 2.876823679546137e+130) {
		tmp = (((9.0 * (y / c)) * (x / z)) + t_1) - t_2;
	} else if (t_5 < 1.3838515042456319e+158) {
		tmp = t_6;
	} else {
		tmp = ((9.0 * ((y / (c * z)) * x)) + t_1) - t_2;
	}
	return tmp;
}
real(8) function code(x, y, z, t, a, b, c)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8), intent (in) :: t
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8), intent (in) :: c
    real(8) :: t_1
    real(8) :: t_2
    real(8) :: t_3
    real(8) :: t_4
    real(8) :: t_5
    real(8) :: t_6
    real(8) :: tmp
    t_1 = b / (c * z)
    t_2 = 4.0d0 * ((a * t) / c)
    t_3 = (x * 9.0d0) * y
    t_4 = (t_3 - (((z * 4.0d0) * t) * a)) + b
    t_5 = t_4 / (z * c)
    t_6 = ((t_3 - ((z * 4.0d0) * (t * a))) + b) / (z * c)
    if (t_5 < (-1.100156740804105d-171)) then
        tmp = t_6
    else if (t_5 < 0.0d0) then
        tmp = (t_4 / z) / c
    else if (t_5 < 1.1708877911747488d-53) then
        tmp = t_6
    else if (t_5 < 2.876823679546137d+130) then
        tmp = (((9.0d0 * (y / c)) * (x / z)) + t_1) - t_2
    else if (t_5 < 1.3838515042456319d+158) then
        tmp = t_6
    else
        tmp = ((9.0d0 * ((y / (c * z)) * x)) + t_1) - t_2
    end if
    code = tmp
end function
public static double code(double x, double y, double z, double t, double a, double b, double c) {
	double t_1 = b / (c * z);
	double t_2 = 4.0 * ((a * t) / c);
	double t_3 = (x * 9.0) * y;
	double t_4 = (t_3 - (((z * 4.0) * t) * a)) + b;
	double t_5 = t_4 / (z * c);
	double t_6 = ((t_3 - ((z * 4.0) * (t * a))) + b) / (z * c);
	double tmp;
	if (t_5 < -1.100156740804105e-171) {
		tmp = t_6;
	} else if (t_5 < 0.0) {
		tmp = (t_4 / z) / c;
	} else if (t_5 < 1.1708877911747488e-53) {
		tmp = t_6;
	} else if (t_5 < 2.876823679546137e+130) {
		tmp = (((9.0 * (y / c)) * (x / z)) + t_1) - t_2;
	} else if (t_5 < 1.3838515042456319e+158) {
		tmp = t_6;
	} else {
		tmp = ((9.0 * ((y / (c * z)) * x)) + t_1) - t_2;
	}
	return tmp;
}
def code(x, y, z, t, a, b, c):
	t_1 = b / (c * z)
	t_2 = 4.0 * ((a * t) / c)
	t_3 = (x * 9.0) * y
	t_4 = (t_3 - (((z * 4.0) * t) * a)) + b
	t_5 = t_4 / (z * c)
	t_6 = ((t_3 - ((z * 4.0) * (t * a))) + b) / (z * c)
	tmp = 0
	if t_5 < -1.100156740804105e-171:
		tmp = t_6
	elif t_5 < 0.0:
		tmp = (t_4 / z) / c
	elif t_5 < 1.1708877911747488e-53:
		tmp = t_6
	elif t_5 < 2.876823679546137e+130:
		tmp = (((9.0 * (y / c)) * (x / z)) + t_1) - t_2
	elif t_5 < 1.3838515042456319e+158:
		tmp = t_6
	else:
		tmp = ((9.0 * ((y / (c * z)) * x)) + t_1) - t_2
	return tmp
function code(x, y, z, t, a, b, c)
	t_1 = Float64(b / Float64(c * z))
	t_2 = Float64(4.0 * Float64(Float64(a * t) / c))
	t_3 = Float64(Float64(x * 9.0) * y)
	t_4 = Float64(Float64(t_3 - Float64(Float64(Float64(z * 4.0) * t) * a)) + b)
	t_5 = Float64(t_4 / Float64(z * c))
	t_6 = Float64(Float64(Float64(t_3 - Float64(Float64(z * 4.0) * Float64(t * a))) + b) / Float64(z * c))
	tmp = 0.0
	if (t_5 < -1.100156740804105e-171)
		tmp = t_6;
	elseif (t_5 < 0.0)
		tmp = Float64(Float64(t_4 / z) / c);
	elseif (t_5 < 1.1708877911747488e-53)
		tmp = t_6;
	elseif (t_5 < 2.876823679546137e+130)
		tmp = Float64(Float64(Float64(Float64(9.0 * Float64(y / c)) * Float64(x / z)) + t_1) - t_2);
	elseif (t_5 < 1.3838515042456319e+158)
		tmp = t_6;
	else
		tmp = Float64(Float64(Float64(9.0 * Float64(Float64(y / Float64(c * z)) * x)) + t_1) - t_2);
	end
	return tmp
end
function tmp_2 = code(x, y, z, t, a, b, c)
	t_1 = b / (c * z);
	t_2 = 4.0 * ((a * t) / c);
	t_3 = (x * 9.0) * y;
	t_4 = (t_3 - (((z * 4.0) * t) * a)) + b;
	t_5 = t_4 / (z * c);
	t_6 = ((t_3 - ((z * 4.0) * (t * a))) + b) / (z * c);
	tmp = 0.0;
	if (t_5 < -1.100156740804105e-171)
		tmp = t_6;
	elseif (t_5 < 0.0)
		tmp = (t_4 / z) / c;
	elseif (t_5 < 1.1708877911747488e-53)
		tmp = t_6;
	elseif (t_5 < 2.876823679546137e+130)
		tmp = (((9.0 * (y / c)) * (x / z)) + t_1) - t_2;
	elseif (t_5 < 1.3838515042456319e+158)
		tmp = t_6;
	else
		tmp = ((9.0 * ((y / (c * z)) * x)) + t_1) - t_2;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_, t_, a_, b_, c_] := Block[{t$95$1 = N[(b / N[(c * z), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$2 = N[(4.0 * N[(N[(a * t), $MachinePrecision] / c), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$3 = N[(N[(x * 9.0), $MachinePrecision] * y), $MachinePrecision]}, Block[{t$95$4 = N[(N[(t$95$3 - N[(N[(N[(z * 4.0), $MachinePrecision] * t), $MachinePrecision] * a), $MachinePrecision]), $MachinePrecision] + b), $MachinePrecision]}, Block[{t$95$5 = N[(t$95$4 / N[(z * c), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$6 = N[(N[(N[(t$95$3 - N[(N[(z * 4.0), $MachinePrecision] * N[(t * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + b), $MachinePrecision] / N[(z * c), $MachinePrecision]), $MachinePrecision]}, If[Less[t$95$5, -1.100156740804105e-171], t$95$6, If[Less[t$95$5, 0.0], N[(N[(t$95$4 / z), $MachinePrecision] / c), $MachinePrecision], If[Less[t$95$5, 1.1708877911747488e-53], t$95$6, If[Less[t$95$5, 2.876823679546137e+130], N[(N[(N[(N[(9.0 * N[(y / c), $MachinePrecision]), $MachinePrecision] * N[(x / z), $MachinePrecision]), $MachinePrecision] + t$95$1), $MachinePrecision] - t$95$2), $MachinePrecision], If[Less[t$95$5, 1.3838515042456319e+158], t$95$6, N[(N[(N[(9.0 * N[(N[(y / N[(c * z), $MachinePrecision]), $MachinePrecision] * x), $MachinePrecision]), $MachinePrecision] + t$95$1), $MachinePrecision] - t$95$2), $MachinePrecision]]]]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_1 := \frac{b}{c \cdot z}\\
t_2 := 4 \cdot \frac{a \cdot t}{c}\\
t_3 := \left(x \cdot 9\right) \cdot y\\
t_4 := \left(t_3 - \left(\left(z \cdot 4\right) \cdot t\right) \cdot a\right) + b\\
t_5 := \frac{t_4}{z \cdot c}\\
t_6 := \frac{\left(t_3 - \left(z \cdot 4\right) \cdot \left(t \cdot a\right)\right) + b}{z \cdot c}\\
\mathbf{if}\;t_5 < -1.100156740804105 \cdot 10^{-171}:\\
\;\;\;\;t_6\\

\mathbf{elif}\;t_5 < 0:\\
\;\;\;\;\frac{\frac{t_4}{z}}{c}\\

\mathbf{elif}\;t_5 < 1.1708877911747488 \cdot 10^{-53}:\\
\;\;\;\;t_6\\

\mathbf{elif}\;t_5 < 2.876823679546137 \cdot 10^{+130}:\\
\;\;\;\;\left(\left(9 \cdot \frac{y}{c}\right) \cdot \frac{x}{z} + t_1\right) - t_2\\

\mathbf{elif}\;t_5 < 1.3838515042456319 \cdot 10^{+158}:\\
\;\;\;\;t_6\\

\mathbf{else}:\\
\;\;\;\;\left(9 \cdot \left(\frac{y}{c \cdot z} \cdot x\right) + t_1\right) - t_2\\


\end{array}
\end{array}

Reproduce

?
herbie shell --seed 2023257 
(FPCore (x y z t a b c)
  :name "Diagrams.Solve.Polynomial:cubForm  from diagrams-solve-0.1, J"
  :precision binary64

  :herbie-target
  (if (< (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)) -1.100156740804105e-171) (/ (+ (- (* (* x 9.0) y) (* (* z 4.0) (* t a))) b) (* z c)) (if (< (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)) 0.0) (/ (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) z) c) (if (< (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)) 1.1708877911747488e-53) (/ (+ (- (* (* x 9.0) y) (* (* z 4.0) (* t a))) b) (* z c)) (if (< (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)) 2.876823679546137e+130) (- (+ (* (* 9.0 (/ y c)) (/ x z)) (/ b (* c z))) (* 4.0 (/ (* a t) c))) (if (< (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)) 1.3838515042456319e+158) (/ (+ (- (* (* x 9.0) y) (* (* z 4.0) (* t a))) b) (* z c)) (- (+ (* 9.0 (* (/ y (* c z)) x)) (/ b (* c z))) (* 4.0 (/ (* a t) c))))))))

  (/ (+ (- (* (* x 9.0) y) (* (* (* z 4.0) t) a)) b) (* z c)))