Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
\]
↓
\[\frac{1}{\sin B} - \frac{x}{\tan B}
\]
(FPCore (B x)
:precision binary64
(+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B)))) ↓
(FPCore (B x) :precision binary64 (- (/ 1.0 (sin B)) (/ x (tan B)))) double code(double B, double x) {
return -(x * (1.0 / tan(B))) + (1.0 / sin(B));
}
↓
double code(double B, double x) {
return (1.0 / sin(B)) - (x / tan(B));
}
real(8) function code(b, x)
real(8), intent (in) :: b
real(8), intent (in) :: x
code = -(x * (1.0d0 / tan(b))) + (1.0d0 / sin(b))
end function
↓
real(8) function code(b, x)
real(8), intent (in) :: b
real(8), intent (in) :: x
code = (1.0d0 / sin(b)) - (x / tan(b))
end function
public static double code(double B, double x) {
return -(x * (1.0 / Math.tan(B))) + (1.0 / Math.sin(B));
}
↓
public static double code(double B, double x) {
return (1.0 / Math.sin(B)) - (x / Math.tan(B));
}
def code(B, x):
return -(x * (1.0 / math.tan(B))) + (1.0 / math.sin(B))
↓
def code(B, x):
return (1.0 / math.sin(B)) - (x / math.tan(B))
function code(B, x)
return Float64(Float64(-Float64(x * Float64(1.0 / tan(B)))) + Float64(1.0 / sin(B)))
end
↓
function code(B, x)
return Float64(Float64(1.0 / sin(B)) - Float64(x / tan(B)))
end
function tmp = code(B, x)
tmp = -(x * (1.0 / tan(B))) + (1.0 / sin(B));
end
↓
function tmp = code(B, x)
tmp = (1.0 / sin(B)) - (x / tan(B));
end
code[B_, x_] := N[((-N[(x * N[(1.0 / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) + N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[B_, x_] := N[(N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision] - N[(x / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
↓
\frac{1}{\sin B} - \frac{x}{\tan B}
Alternatives Alternative 1 Accuracy 99.8% Cost 13248
\[\frac{1}{\sin B} - \frac{x}{\tan B}
\]
Alternative 2 Accuracy 98.3% Cost 13449
\[\begin{array}{l}
\mathbf{if}\;x \leq -1800 \lor \neg \left(x \leq 38000000000\right):\\
\;\;\;\;\frac{-\cos B}{\frac{\sin B}{x}}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B} - x \cdot \frac{1}{B}\\
\end{array}
\]
Alternative 3 Accuracy 98.4% Cost 13449
\[\begin{array}{l}
\mathbf{if}\;x \leq -2000 \lor \neg \left(x \leq 38000000000\right):\\
\;\;\;\;\cos B \cdot \frac{-x}{\sin B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B} - x \cdot \frac{1}{B}\\
\end{array}
\]
Alternative 4 Accuracy 86.7% Cost 7369
\[\begin{array}{l}
\mathbf{if}\;x \leq -1850000000000 \lor \neg \left(x \leq 3.5 \cdot 10^{+69}\right):\\
\;\;\;\;\left(\frac{1}{B} + B \cdot 0.16666666666666666\right) - \frac{x}{\tan B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1 - x}{\sin B}\\
\end{array}
\]
Alternative 5 Accuracy 76.9% Cost 6985
\[\begin{array}{l}
\mathbf{if}\;B \leq -1850 \lor \neg \left(B \leq 0.0034\right):\\
\;\;\;\;\frac{1 + x}{\sin B}\\
\mathbf{else}:\\
\;\;\;\;B \cdot \left(0.16666666666666666 + x \cdot 0.3333333333333333\right) + \frac{1 - x}{B}\\
\end{array}
\]
Alternative 6 Accuracy 74.9% Cost 6857
\[\begin{array}{l}
\mathbf{if}\;B \leq -1850 \lor \neg \left(B \leq 0.0034\right):\\
\;\;\;\;\frac{1}{\sin B}\\
\mathbf{else}:\\
\;\;\;\;B \cdot \left(0.16666666666666666 + x \cdot 0.3333333333333333\right) + \frac{1 - x}{B}\\
\end{array}
\]
Alternative 7 Accuracy 75.5% Cost 6856
\[\begin{array}{l}
\mathbf{if}\;x \leq -2050:\\
\;\;\;\;\frac{-x}{\sin B}\\
\mathbf{elif}\;x \leq 0.00105:\\
\;\;\;\;\frac{1}{\sin B}\\
\mathbf{else}:\\
\;\;\;\;B \cdot \left(0.16666666666666666 + x \cdot 0.3333333333333333\right) + \frac{1 - x}{B}\\
\end{array}
\]
Alternative 8 Accuracy 77.0% Cost 6720
\[\frac{1 - x}{\sin B}
\]
Alternative 9 Accuracy 50.8% Cost 832
\[B \cdot \left(0.16666666666666666 + x \cdot 0.3333333333333333\right) + \frac{1 - x}{B}
\]
Alternative 10 Accuracy 50.7% Cost 704
\[B \cdot 0.16666666666666666 + \left(\frac{1}{B} - \frac{x}{B}\right)
\]
Alternative 11 Accuracy 48.8% Cost 585
\[\begin{array}{l}
\mathbf{if}\;x \leq -4800 \lor \neg \left(x \leq 5 \cdot 10^{-22}\right):\\
\;\;\;\;\frac{-x}{B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1 + x}{B}\\
\end{array}
\]
Alternative 12 Accuracy 48.8% Cost 521
\[\begin{array}{l}
\mathbf{if}\;x \leq -4800 \lor \neg \left(x \leq 5 \cdot 10^{-22}\right):\\
\;\;\;\;\frac{-x}{B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{B}\\
\end{array}
\]
Alternative 13 Accuracy 50.6% Cost 320
\[\frac{1 - x}{B}
\]
Alternative 14 Accuracy 26.3% Cost 192
\[\frac{1}{B}
\]