Falkner and Boettcher, Appendix A

Percentage Accurate: 90.1% → 97.2%
Time: 9.0s
Alternatives: 15
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 15 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 90.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Alternative 1: 97.2% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 0.255:\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{k} \cdot \frac{\frac{1}{\frac{1}{{k}^{m}}}}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k 0.255) (* a (pow k m)) (* (/ a k) (/ (/ 1.0 (/ 1.0 (pow k m))) k))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= 0.255) {
		tmp = a * pow(k, m);
	} else {
		tmp = (a / k) * ((1.0 / (1.0 / pow(k, m))) / k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= 0.255d0) then
        tmp = a * (k ** m)
    else
        tmp = (a / k) * ((1.0d0 / (1.0d0 / (k ** m))) / k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= 0.255) {
		tmp = a * Math.pow(k, m);
	} else {
		tmp = (a / k) * ((1.0 / (1.0 / Math.pow(k, m))) / k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= 0.255:
		tmp = a * math.pow(k, m)
	else:
		tmp = (a / k) * ((1.0 / (1.0 / math.pow(k, m))) / k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= 0.255)
		tmp = Float64(a * (k ^ m));
	else
		tmp = Float64(Float64(a / k) * Float64(Float64(1.0 / Float64(1.0 / (k ^ m))) / k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= 0.255)
		tmp = a * (k ^ m);
	else
		tmp = (a / k) * ((1.0 / (1.0 / (k ^ m))) / k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, 0.255], N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision], N[(N[(a / k), $MachinePrecision] * N[(N[(1.0 / N[(1.0 / N[Power[k, m], $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / k), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 0.255:\\
\;\;\;\;a \cdot {k}^{m}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{k} \cdot \frac{\frac{1}{\frac{1}{{k}^{m}}}}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < 0.255

    1. Initial program 94.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative94.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified94.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 52.1%

      \[\leadsto \color{blue}{e^{\log k \cdot m} \cdot a} \]
    5. Step-by-step derivation
      1. exp-to-pow99.1%

        \[\leadsto \color{blue}{{k}^{m}} \cdot a \]
      2. *-commutative99.1%

        \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
    6. Simplified99.1%

      \[\leadsto \color{blue}{a \cdot {k}^{m}} \]

    if 0.255 < k

    1. Initial program 75.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*75.7%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+75.7%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. *-commutative75.7%

        \[\leadsto \frac{a}{\frac{1 + \left(\color{blue}{k \cdot 10} + k \cdot k\right)}{{k}^{m}}} \]
    3. Simplified75.7%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + \left(k \cdot 10 + k \cdot k\right)}{{k}^{m}}}} \]
    4. Taylor expanded in k around inf 74.2%

      \[\leadsto \frac{a}{\frac{1 + \color{blue}{{k}^{2}}}{{k}^{m}}} \]
    5. Step-by-step derivation
      1. unpow274.2%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot k}}{{k}^{m}}} \]
    6. Simplified74.2%

      \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot k}}{{k}^{m}}} \]
    7. Taylor expanded in k around inf 74.2%

      \[\leadsto \color{blue}{\frac{a \cdot e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}}{{k}^{2}}} \]
    8. Step-by-step derivation
      1. unpow274.2%

        \[\leadsto \frac{a \cdot e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}}{\color{blue}{k \cdot k}} \]
      2. times-frac94.6%

        \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{e^{-1 \cdot \left(\log \left(\frac{1}{k}\right) \cdot m\right)}}{k}} \]
      3. mul-1-neg94.6%

        \[\leadsto \frac{a}{k} \cdot \frac{e^{\color{blue}{-\log \left(\frac{1}{k}\right) \cdot m}}}{k} \]
      4. exp-neg94.6%

        \[\leadsto \frac{a}{k} \cdot \frac{\color{blue}{\frac{1}{e^{\log \left(\frac{1}{k}\right) \cdot m}}}}{k} \]
      5. log-rec94.6%

        \[\leadsto \frac{a}{k} \cdot \frac{\frac{1}{e^{\color{blue}{\left(-\log k\right)} \cdot m}}}{k} \]
      6. distribute-lft-neg-in94.6%

        \[\leadsto \frac{a}{k} \cdot \frac{\frac{1}{e^{\color{blue}{-\log k \cdot m}}}}{k} \]
      7. rec-exp94.6%

        \[\leadsto \frac{a}{k} \cdot \frac{\frac{1}{\color{blue}{\frac{1}{e^{\log k \cdot m}}}}}{k} \]
      8. exp-to-pow94.6%

        \[\leadsto \frac{a}{k} \cdot \frac{\frac{1}{\frac{1}{\color{blue}{{k}^{m}}}}}{k} \]
    9. Simplified94.6%

      \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{\frac{1}{\frac{1}{{k}^{m}}}}{k}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification97.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 0.255:\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{k} \cdot \frac{\frac{1}{\frac{1}{{k}^{m}}}}{k}\\ \end{array} \]

Alternative 2: 96.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq 2.8:\\ \;\;\;\;\frac{a}{\frac{1 + k \cdot k}{{k}^{m}}}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m 2.8) (/ a (/ (+ 1.0 (* k k)) (pow k m))) (* a (pow k m))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= 2.8) {
		tmp = a / ((1.0 + (k * k)) / pow(k, m));
	} else {
		tmp = a * pow(k, m);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= 2.8d0) then
        tmp = a / ((1.0d0 + (k * k)) / (k ** m))
    else
        tmp = a * (k ** m)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= 2.8) {
		tmp = a / ((1.0 + (k * k)) / Math.pow(k, m));
	} else {
		tmp = a * Math.pow(k, m);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= 2.8:
		tmp = a / ((1.0 + (k * k)) / math.pow(k, m))
	else:
		tmp = a * math.pow(k, m)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= 2.8)
		tmp = Float64(a / Float64(Float64(1.0 + Float64(k * k)) / (k ^ m)));
	else
		tmp = Float64(a * (k ^ m));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= 2.8)
		tmp = a / ((1.0 + (k * k)) / (k ^ m));
	else
		tmp = a * (k ^ m);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, 2.8], N[(a / N[(N[(1.0 + N[(k * k), $MachinePrecision]), $MachinePrecision] / N[Power[k, m], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq 2.8:\\
\;\;\;\;\frac{a}{\frac{1 + k \cdot k}{{k}^{m}}}\\

\mathbf{else}:\\
\;\;\;\;a \cdot {k}^{m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < 2.7999999999999998

    1. Initial program 94.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*94.9%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+95.0%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. *-commutative95.0%

        \[\leadsto \frac{a}{\frac{1 + \left(\color{blue}{k \cdot 10} + k \cdot k\right)}{{k}^{m}}} \]
    3. Simplified95.0%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + \left(k \cdot 10 + k \cdot k\right)}{{k}^{m}}}} \]
    4. Taylor expanded in k around inf 93.3%

      \[\leadsto \frac{a}{\frac{1 + \color{blue}{{k}^{2}}}{{k}^{m}}} \]
    5. Step-by-step derivation
      1. unpow293.3%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot k}}{{k}^{m}}} \]
    6. Simplified93.3%

      \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot k}}{{k}^{m}}} \]

    if 2.7999999999999998 < m

    1. Initial program 70.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/70.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified70.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 56.3%

      \[\leadsto \color{blue}{e^{\log k \cdot m} \cdot a} \]
    5. Step-by-step derivation
      1. exp-to-pow100.0%

        \[\leadsto \color{blue}{{k}^{m}} \cdot a \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
    6. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification95.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq 2.8:\\ \;\;\;\;\frac{a}{\frac{1 + k \cdot k}{{k}^{m}}}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \]

Alternative 3: 96.9% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -1.5 \cdot 10^{-9} \lor \neg \left(m \leq 2.7 \cdot 10^{-11}\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= m -1.5e-9) (not (<= m 2.7e-11)))
   (* a (pow k m))
   (/ a (+ 1.0 (* k (+ k 10.0))))))
double code(double a, double k, double m) {
	double tmp;
	if ((m <= -1.5e-9) || !(m <= 2.7e-11)) {
		tmp = a * pow(k, m);
	} else {
		tmp = a / (1.0 + (k * (k + 10.0)));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((m <= (-1.5d-9)) .or. (.not. (m <= 2.7d-11))) then
        tmp = a * (k ** m)
    else
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((m <= -1.5e-9) || !(m <= 2.7e-11)) {
		tmp = a * Math.pow(k, m);
	} else {
		tmp = a / (1.0 + (k * (k + 10.0)));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (m <= -1.5e-9) or not (m <= 2.7e-11):
		tmp = a * math.pow(k, m)
	else:
		tmp = a / (1.0 + (k * (k + 10.0)))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((m <= -1.5e-9) || !(m <= 2.7e-11))
		tmp = Float64(a * (k ^ m));
	else
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((m <= -1.5e-9) || ~((m <= 2.7e-11)))
		tmp = a * (k ^ m);
	else
		tmp = a / (1.0 + (k * (k + 10.0)));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[m, -1.5e-9], N[Not[LessEqual[m, 2.7e-11]], $MachinePrecision]], N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -1.5 \cdot 10^{-9} \lor \neg \left(m \leq 2.7 \cdot 10^{-11}\right):\\
\;\;\;\;a \cdot {k}^{m}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -1.49999999999999999e-9 or 2.70000000000000005e-11 < m

    1. Initial program 84.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.5%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 57.2%

      \[\leadsto \color{blue}{e^{\log k \cdot m} \cdot a} \]
    5. Step-by-step derivation
      1. exp-to-pow99.4%

        \[\leadsto \color{blue}{{k}^{m}} \cdot a \]
      2. *-commutative99.4%

        \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
    6. Simplified99.4%

      \[\leadsto \color{blue}{a \cdot {k}^{m}} \]

    if -1.49999999999999999e-9 < m < 2.70000000000000005e-11

    1. Initial program 90.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/90.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified90.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 90.3%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification96.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -1.5 \cdot 10^{-9} \lor \neg \left(m \leq 2.7 \cdot 10^{-11}\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \]

Alternative 4: 96.9% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -2 \cdot 10^{-7}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \mathbf{elif}\;m \leq 2.7 \cdot 10^{-11}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -2e-7)
   (/ a (pow k (- m)))
   (if (<= m 2.7e-11) (/ a (+ 1.0 (* k (+ k 10.0)))) (* a (pow k m)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -2e-7) {
		tmp = a / pow(k, -m);
	} else if (m <= 2.7e-11) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = a * pow(k, m);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-2d-7)) then
        tmp = a / (k ** -m)
    else if (m <= 2.7d-11) then
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    else
        tmp = a * (k ** m)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -2e-7) {
		tmp = a / Math.pow(k, -m);
	} else if (m <= 2.7e-11) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = a * Math.pow(k, m);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -2e-7:
		tmp = a / math.pow(k, -m)
	elif m <= 2.7e-11:
		tmp = a / (1.0 + (k * (k + 10.0)))
	else:
		tmp = a * math.pow(k, m)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -2e-7)
		tmp = Float64(a / (k ^ Float64(-m)));
	elseif (m <= 2.7e-11)
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	else
		tmp = Float64(a * (k ^ m));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -2e-7)
		tmp = a / (k ^ -m);
	elseif (m <= 2.7e-11)
		tmp = a / (1.0 + (k * (k + 10.0)));
	else
		tmp = a * (k ^ m);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -2e-7], N[(a / N[Power[k, (-m)], $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 2.7e-11], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -2 \cdot 10^{-7}:\\
\;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\

\mathbf{elif}\;m \leq 2.7 \cdot 10^{-11}:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;a \cdot {k}^{m}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -1.9999999999999999e-7

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*100.0%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+100.0%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. *-commutative100.0%

        \[\leadsto \frac{a}{\frac{1 + \left(\color{blue}{k \cdot 10} + k \cdot k\right)}{{k}^{m}}} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + \left(k \cdot 10 + k \cdot k\right)}{{k}^{m}}}} \]
    4. Taylor expanded in k around 0 100.0%

      \[\leadsto \frac{a}{\frac{1 + \color{blue}{10 \cdot k}}{{k}^{m}}} \]
    5. Step-by-step derivation
      1. *-commutative100.0%

        \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot 10}}{{k}^{m}}} \]
    6. Simplified100.0%

      \[\leadsto \frac{a}{\frac{1 + \color{blue}{k \cdot 10}}{{k}^{m}}} \]
    7. Taylor expanded in k around 0 100.0%

      \[\leadsto \frac{a}{\frac{\color{blue}{1}}{{k}^{m}}} \]
    8. Taylor expanded in k around 0 57.7%

      \[\leadsto \frac{a}{\color{blue}{\frac{1}{e^{\log k \cdot m}}}} \]
    9. Step-by-step derivation
      1. rec-exp57.7%

        \[\leadsto \frac{a}{\color{blue}{e^{-\log k \cdot m}}} \]
      2. distribute-rgt-neg-out57.7%

        \[\leadsto \frac{a}{e^{\color{blue}{\log k \cdot \left(-m\right)}}} \]
      3. exp-to-pow100.0%

        \[\leadsto \frac{a}{\color{blue}{{k}^{\left(-m\right)}}} \]
    10. Simplified100.0%

      \[\leadsto \frac{a}{\color{blue}{{k}^{\left(-m\right)}}} \]

    if -1.9999999999999999e-7 < m < 2.70000000000000005e-11

    1. Initial program 90.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/90.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative90.3%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified90.3%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 90.3%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]

    if 2.70000000000000005e-11 < m

    1. Initial program 71.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/71.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+71.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative71.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out71.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def71.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative71.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified71.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 56.7%

      \[\leadsto \color{blue}{e^{\log k \cdot m} \cdot a} \]
    5. Step-by-step derivation
      1. exp-to-pow99.0%

        \[\leadsto \color{blue}{{k}^{m}} \cdot a \]
      2. *-commutative99.0%

        \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
    6. Simplified99.0%

      \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification96.3%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -2 \cdot 10^{-7}:\\ \;\;\;\;\frac{a}{{k}^{\left(-m\right)}}\\ \mathbf{elif}\;m \leq 2.7 \cdot 10^{-11}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \]

Alternative 5: 61.7% accurate, 6.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -59000000000:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.95:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot -10 + k \cdot \left(k \cdot 100\right)\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -59000000000.0)
   (/ a (* k k))
   (if (<= m 1.95)
     (/ a (+ 1.0 (* k (+ k 10.0))))
     (+ a (* a (+ (* k -10.0) (* k (* k 100.0))))))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -59000000000.0) {
		tmp = a / (k * k);
	} else if (m <= 1.95) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = a + (a * ((k * -10.0) + (k * (k * 100.0))));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-59000000000.0d0)) then
        tmp = a / (k * k)
    else if (m <= 1.95d0) then
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    else
        tmp = a + (a * ((k * (-10.0d0)) + (k * (k * 100.0d0))))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -59000000000.0) {
		tmp = a / (k * k);
	} else if (m <= 1.95) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = a + (a * ((k * -10.0) + (k * (k * 100.0))));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -59000000000.0:
		tmp = a / (k * k)
	elif m <= 1.95:
		tmp = a / (1.0 + (k * (k + 10.0)))
	else:
		tmp = a + (a * ((k * -10.0) + (k * (k * 100.0))))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -59000000000.0)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 1.95)
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	else
		tmp = Float64(a + Float64(a * Float64(Float64(k * -10.0) + Float64(k * Float64(k * 100.0)))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -59000000000.0)
		tmp = a / (k * k);
	elseif (m <= 1.95)
		tmp = a / (1.0 + (k * (k + 10.0)));
	else
		tmp = a + (a * ((k * -10.0) + (k * (k * 100.0))));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -59000000000.0], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 1.95], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a + N[(a * N[(N[(k * -10.0), $MachinePrecision] + N[(k * N[(k * 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -59000000000:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 1.95:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;a + a \cdot \left(k \cdot -10 + k \cdot \left(k \cdot 100\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -5.9e10

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 35.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 59.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow259.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified59.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -5.9e10 < m < 1.94999999999999996

    1. Initial program 90.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/90.8%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+90.9%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative90.9%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out90.9%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def90.9%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative90.9%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified90.9%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 88.0%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]

    if 1.94999999999999996 < m

    1. Initial program 70.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/70.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative70.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified70.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 2.8%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative2.8%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified2.8%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around 0 29.1%

      \[\leadsto \color{blue}{a + \left(-10 \cdot \left(k \cdot a\right) + 100 \cdot \left({k}^{2} \cdot a\right)\right)} \]
    9. Step-by-step derivation
      1. associate-*r*29.1%

        \[\leadsto a + \left(\color{blue}{\left(-10 \cdot k\right) \cdot a} + 100 \cdot \left({k}^{2} \cdot a\right)\right) \]
      2. associate-*r*29.1%

        \[\leadsto a + \left(\left(-10 \cdot k\right) \cdot a + \color{blue}{\left(100 \cdot {k}^{2}\right) \cdot a}\right) \]
      3. *-commutative29.1%

        \[\leadsto a + \left(\left(-10 \cdot k\right) \cdot a + \color{blue}{\left({k}^{2} \cdot 100\right)} \cdot a\right) \]
      4. distribute-rgt-out39.5%

        \[\leadsto a + \color{blue}{a \cdot \left(-10 \cdot k + {k}^{2} \cdot 100\right)} \]
      5. *-commutative39.5%

        \[\leadsto a + a \cdot \left(\color{blue}{k \cdot -10} + {k}^{2} \cdot 100\right) \]
      6. unpow239.5%

        \[\leadsto a + a \cdot \left(k \cdot -10 + \color{blue}{\left(k \cdot k\right)} \cdot 100\right) \]
      7. associate-*l*39.5%

        \[\leadsto a + a \cdot \left(k \cdot -10 + \color{blue}{k \cdot \left(k \cdot 100\right)}\right) \]
    10. Simplified39.5%

      \[\leadsto \color{blue}{a + a \cdot \left(k \cdot -10 + k \cdot \left(k \cdot 100\right)\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification63.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -59000000000:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1.95:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot -10 + k \cdot \left(k \cdot 100\right)\right)\\ \end{array} \]

Alternative 6: 57.8% accurate, 8.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -59000000000:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 700000000:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -59000000000.0)
   (/ a (* k k))
   (if (<= m 700000000.0) (/ a (+ 1.0 (* k (+ k 10.0)))) (* -10.0 (* k a)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -59000000000.0) {
		tmp = a / (k * k);
	} else if (m <= 700000000.0) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-59000000000.0d0)) then
        tmp = a / (k * k)
    else if (m <= 700000000.0d0) then
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    else
        tmp = (-10.0d0) * (k * a)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -59000000000.0) {
		tmp = a / (k * k);
	} else if (m <= 700000000.0) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -59000000000.0:
		tmp = a / (k * k)
	elif m <= 700000000.0:
		tmp = a / (1.0 + (k * (k + 10.0)))
	else:
		tmp = -10.0 * (k * a)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -59000000000.0)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 700000000.0)
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	else
		tmp = Float64(-10.0 * Float64(k * a));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -59000000000.0)
		tmp = a / (k * k);
	elseif (m <= 700000000.0)
		tmp = a / (1.0 + (k * (k + 10.0)));
	else
		tmp = -10.0 * (k * a);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -59000000000.0], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 700000000.0], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(k * a), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -59000000000:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 700000000:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(k \cdot a\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -5.9e10

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 35.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 59.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow259.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified59.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -5.9e10 < m < 7e8

    1. Initial program 90.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/90.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified90.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 85.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]

    if 7e8 < m

    1. Initial program 70.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/70.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified70.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.9%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative8.7%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 18.4%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification55.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -59000000000:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 700000000:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \]

Alternative 7: 47.1% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 3.9 \cdot 10^{-301}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.26:\\ \;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k 3.9e-301)
   (/ a (* k k))
   (if (<= k 0.26) (* a (+ 1.0 (* k -10.0))) (/ (/ a k) k))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= 3.9e-301) {
		tmp = a / (k * k);
	} else if (k <= 0.26) {
		tmp = a * (1.0 + (k * -10.0));
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= 3.9d-301) then
        tmp = a / (k * k)
    else if (k <= 0.26d0) then
        tmp = a * (1.0d0 + (k * (-10.0d0)))
    else
        tmp = (a / k) / k
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= 3.9e-301) {
		tmp = a / (k * k);
	} else if (k <= 0.26) {
		tmp = a * (1.0 + (k * -10.0));
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= 3.9e-301:
		tmp = a / (k * k)
	elif k <= 0.26:
		tmp = a * (1.0 + (k * -10.0))
	else:
		tmp = (a / k) / k
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= 3.9e-301)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 0.26)
		tmp = Float64(a * Float64(1.0 + Float64(k * -10.0)));
	else
		tmp = Float64(Float64(a / k) / k);
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= 3.9e-301)
		tmp = a / (k * k);
	elseif (k <= 0.26)
		tmp = a * (1.0 + (k * -10.0));
	else
		tmp = (a / k) / k;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, 3.9e-301], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 0.26], N[(a * N[(1.0 + N[(k * -10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(a / k), $MachinePrecision] / k), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 3.9 \cdot 10^{-301}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 0.26:\\
\;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < 3.9000000000000001e-301

    1. Initial program 87.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.7%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified87.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 20.7%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 32.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow232.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified32.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if 3.9000000000000001e-301 < k < 0.26000000000000001

    1. Initial program 99.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/99.9%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 51.5%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative51.5%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified51.5%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]

    if 0.26000000000000001 < k

    1. Initial program 75.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/75.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified75.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 53.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 52.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow252.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified52.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. associate-/r*58.4%

        \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
      2. div-inv58.4%

        \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
    9. Applied egg-rr58.4%

      \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
    10. Step-by-step derivation
      1. un-div-inv58.4%

        \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
    11. Applied egg-rr58.4%

      \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification48.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 3.9 \cdot 10^{-301}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.26:\\ \;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]

Alternative 8: 47.1% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 1.9 \cdot 10^{-300}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.26:\\ \;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{k} \cdot \frac{1}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k 1.9e-300)
   (/ a (* k k))
   (if (<= k 0.26) (* a (+ 1.0 (* k -10.0))) (* (/ a k) (/ 1.0 k)))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= 1.9e-300) {
		tmp = a / (k * k);
	} else if (k <= 0.26) {
		tmp = a * (1.0 + (k * -10.0));
	} else {
		tmp = (a / k) * (1.0 / k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= 1.9d-300) then
        tmp = a / (k * k)
    else if (k <= 0.26d0) then
        tmp = a * (1.0d0 + (k * (-10.0d0)))
    else
        tmp = (a / k) * (1.0d0 / k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= 1.9e-300) {
		tmp = a / (k * k);
	} else if (k <= 0.26) {
		tmp = a * (1.0 + (k * -10.0));
	} else {
		tmp = (a / k) * (1.0 / k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= 1.9e-300:
		tmp = a / (k * k)
	elif k <= 0.26:
		tmp = a * (1.0 + (k * -10.0))
	else:
		tmp = (a / k) * (1.0 / k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= 1.9e-300)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 0.26)
		tmp = Float64(a * Float64(1.0 + Float64(k * -10.0)));
	else
		tmp = Float64(Float64(a / k) * Float64(1.0 / k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= 1.9e-300)
		tmp = a / (k * k);
	elseif (k <= 0.26)
		tmp = a * (1.0 + (k * -10.0));
	else
		tmp = (a / k) * (1.0 / k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, 1.9e-300], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 0.26], N[(a * N[(1.0 + N[(k * -10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(a / k), $MachinePrecision] * N[(1.0 / k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 1.9 \cdot 10^{-300}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 0.26:\\
\;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{k} \cdot \frac{1}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < 1.90000000000000006e-300

    1. Initial program 87.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.7%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified87.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 20.7%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 32.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow232.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified32.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if 1.90000000000000006e-300 < k < 0.26000000000000001

    1. Initial program 99.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/99.9%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.2%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 51.5%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative51.5%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified51.5%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]

    if 0.26000000000000001 < k

    1. Initial program 75.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/75.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified75.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 53.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 52.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow252.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified52.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. associate-/r*58.4%

        \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
      2. div-inv58.4%

        \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
    9. Applied egg-rr58.4%

      \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification48.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 1.9 \cdot 10^{-300}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.26:\\ \;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{k} \cdot \frac{1}{k}\\ \end{array} \]

Alternative 9: 47.2% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 1.45 \cdot 10^{-300}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 3.2:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{k} \cdot \frac{1}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k 1.45e-300)
   (/ a (* k k))
   (if (<= k 3.2) (/ a (+ 1.0 (* k 10.0))) (* (/ a k) (/ 1.0 k)))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= 1.45e-300) {
		tmp = a / (k * k);
	} else if (k <= 3.2) {
		tmp = a / (1.0 + (k * 10.0));
	} else {
		tmp = (a / k) * (1.0 / k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= 1.45d-300) then
        tmp = a / (k * k)
    else if (k <= 3.2d0) then
        tmp = a / (1.0d0 + (k * 10.0d0))
    else
        tmp = (a / k) * (1.0d0 / k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= 1.45e-300) {
		tmp = a / (k * k);
	} else if (k <= 3.2) {
		tmp = a / (1.0 + (k * 10.0));
	} else {
		tmp = (a / k) * (1.0 / k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= 1.45e-300:
		tmp = a / (k * k)
	elif k <= 3.2:
		tmp = a / (1.0 + (k * 10.0))
	else:
		tmp = (a / k) * (1.0 / k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= 1.45e-300)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 3.2)
		tmp = Float64(a / Float64(1.0 + Float64(k * 10.0)));
	else
		tmp = Float64(Float64(a / k) * Float64(1.0 / k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= 1.45e-300)
		tmp = a / (k * k);
	elseif (k <= 3.2)
		tmp = a / (1.0 + (k * 10.0));
	else
		tmp = (a / k) * (1.0 / k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, 1.45e-300], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 3.2], N[(a / N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(a / k), $MachinePrecision] * N[(1.0 / k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 1.45 \cdot 10^{-300}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 3.2:\\
\;\;\;\;\frac{a}{1 + k \cdot 10}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{k} \cdot \frac{1}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < 1.44999999999999996e-300

    1. Initial program 87.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.7%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified87.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 20.7%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 32.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow232.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified32.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if 1.44999999999999996e-300 < k < 3.2000000000000002

    1. Initial program 99.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/99.9%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.2%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 51.8%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative51.8%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified51.8%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]

    if 3.2000000000000002 < k

    1. Initial program 75.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/75.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative75.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified75.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 53.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 52.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow252.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified52.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. associate-/r*58.4%

        \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
      2. div-inv58.4%

        \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
    9. Applied egg-rr58.4%

      \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification48.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 1.45 \cdot 10^{-300}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 3.2:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{k} \cdot \frac{1}{k}\\ \end{array} \]

Alternative 10: 57.0% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -59000000000:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 80000000000:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -59000000000.0)
   (/ a (* k k))
   (if (<= m 80000000000.0) (/ a (+ 1.0 (* k k))) (* -10.0 (* k a)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -59000000000.0) {
		tmp = a / (k * k);
	} else if (m <= 80000000000.0) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-59000000000.0d0)) then
        tmp = a / (k * k)
    else if (m <= 80000000000.0d0) then
        tmp = a / (1.0d0 + (k * k))
    else
        tmp = (-10.0d0) * (k * a)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -59000000000.0) {
		tmp = a / (k * k);
	} else if (m <= 80000000000.0) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -59000000000.0:
		tmp = a / (k * k)
	elif m <= 80000000000.0:
		tmp = a / (1.0 + (k * k))
	else:
		tmp = -10.0 * (k * a)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -59000000000.0)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 80000000000.0)
		tmp = Float64(a / Float64(1.0 + Float64(k * k)));
	else
		tmp = Float64(-10.0 * Float64(k * a));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -59000000000.0)
		tmp = a / (k * k);
	elseif (m <= 80000000000.0)
		tmp = a / (1.0 + (k * k));
	else
		tmp = -10.0 * (k * a);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -59000000000.0], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 80000000000.0], N[(a / N[(1.0 + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(k * a), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -59000000000:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 80000000000:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(k \cdot a\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -5.9e10

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 35.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 59.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow259.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified59.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -5.9e10 < m < 8e10

    1. Initial program 90.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/90.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative90.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified90.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 85.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 82.4%

      \[\leadsto \frac{a}{1 + \color{blue}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow282.4%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]
    7. Simplified82.4%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]

    if 8e10 < m

    1. Initial program 70.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/70.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified70.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.9%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative8.7%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 18.4%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification54.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -59000000000:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 80000000000:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \]

Alternative 11: 46.1% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 1.9 \cdot 10^{-300} \lor \neg \left(k \leq 3.3\right):\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= k 1.9e-300) (not (<= k 3.3))) (/ a (* k k)) a))
double code(double a, double k, double m) {
	double tmp;
	if ((k <= 1.9e-300) || !(k <= 3.3)) {
		tmp = a / (k * k);
	} else {
		tmp = a;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((k <= 1.9d-300) .or. (.not. (k <= 3.3d0))) then
        tmp = a / (k * k)
    else
        tmp = a
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((k <= 1.9e-300) || !(k <= 3.3)) {
		tmp = a / (k * k);
	} else {
		tmp = a;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (k <= 1.9e-300) or not (k <= 3.3):
		tmp = a / (k * k)
	else:
		tmp = a
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((k <= 1.9e-300) || !(k <= 3.3))
		tmp = Float64(a / Float64(k * k));
	else
		tmp = a;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((k <= 1.9e-300) || ~((k <= 3.3)))
		tmp = a / (k * k);
	else
		tmp = a;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[k, 1.9e-300], N[Not[LessEqual[k, 3.3]], $MachinePrecision]], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], a]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 1.9 \cdot 10^{-300} \lor \neg \left(k \leq 3.3\right):\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;a\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < 1.90000000000000006e-300 or 3.2999999999999998 < k

    1. Initial program 80.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/80.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+80.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative80.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out80.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def80.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative80.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified80.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 40.2%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 44.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow244.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified44.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if 1.90000000000000006e-300 < k < 3.2999999999999998

    1. Initial program 99.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/99.9%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 51.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 50.0%

      \[\leadsto \color{blue}{a} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification45.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 1.9 \cdot 10^{-300} \lor \neg \left(k \leq 3.3\right):\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \]

Alternative 12: 30.8% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -6.4 \cdot 10^{-56}:\\ \;\;\;\;\frac{a}{k} \cdot 0.1\\ \mathbf{elif}\;m \leq 41000000000:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -6.4e-56)
   (* (/ a k) 0.1)
   (if (<= m 41000000000.0) a (* -10.0 (* k a)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -6.4e-56) {
		tmp = (a / k) * 0.1;
	} else if (m <= 41000000000.0) {
		tmp = a;
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-6.4d-56)) then
        tmp = (a / k) * 0.1d0
    else if (m <= 41000000000.0d0) then
        tmp = a
    else
        tmp = (-10.0d0) * (k * a)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -6.4e-56) {
		tmp = (a / k) * 0.1;
	} else if (m <= 41000000000.0) {
		tmp = a;
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -6.4e-56:
		tmp = (a / k) * 0.1
	elif m <= 41000000000.0:
		tmp = a
	else:
		tmp = -10.0 * (k * a)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -6.4e-56)
		tmp = Float64(Float64(a / k) * 0.1);
	elseif (m <= 41000000000.0)
		tmp = a;
	else
		tmp = Float64(-10.0 * Float64(k * a));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -6.4e-56)
		tmp = (a / k) * 0.1;
	elseif (m <= 41000000000.0)
		tmp = a;
	else
		tmp = -10.0 * (k * a);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -6.4e-56], N[(N[(a / k), $MachinePrecision] * 0.1), $MachinePrecision], If[LessEqual[m, 41000000000.0], a, N[(-10.0 * N[(k * a), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -6.4 \cdot 10^{-56}:\\
\;\;\;\;\frac{a}{k} \cdot 0.1\\

\mathbf{elif}\;m \leq 41000000000:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(k \cdot a\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -6.39999999999999971e-56

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 43.9%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 21.0%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative21.0%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified21.0%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around inf 24.3%

      \[\leadsto \color{blue}{0.1 \cdot \frac{a}{k}} \]

    if -6.39999999999999971e-56 < m < 4.1e10

    1. Initial program 88.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/88.6%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+88.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative88.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out88.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def88.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative88.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified88.6%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 84.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 46.4%

      \[\leadsto \color{blue}{a} \]

    if 4.1e10 < m

    1. Initial program 70.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/70.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified70.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.9%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative8.7%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 18.4%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification29.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -6.4 \cdot 10^{-56}:\\ \;\;\;\;\frac{a}{k} \cdot 0.1\\ \mathbf{elif}\;m \leq 41000000000:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \]

Alternative 13: 46.9% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq 2.1 \cdot 10^{-300}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 3.3:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k 2.1e-300) (/ a (* k k)) (if (<= k 3.3) a (/ (/ a k) k))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= 2.1e-300) {
		tmp = a / (k * k);
	} else if (k <= 3.3) {
		tmp = a;
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= 2.1d-300) then
        tmp = a / (k * k)
    else if (k <= 3.3d0) then
        tmp = a
    else
        tmp = (a / k) / k
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= 2.1e-300) {
		tmp = a / (k * k);
	} else if (k <= 3.3) {
		tmp = a;
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= 2.1e-300:
		tmp = a / (k * k)
	elif k <= 3.3:
		tmp = a
	else:
		tmp = (a / k) / k
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= 2.1e-300)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 3.3)
		tmp = a;
	else
		tmp = Float64(Float64(a / k) / k);
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= 2.1e-300)
		tmp = a / (k * k);
	elseif (k <= 3.3)
		tmp = a;
	else
		tmp = (a / k) / k;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, 2.1e-300], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 3.3], a, N[(N[(a / k), $MachinePrecision] / k), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq 2.1 \cdot 10^{-300}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 3.3:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < 2.10000000000000004e-300

    1. Initial program 87.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/87.7%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative87.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified87.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 20.7%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 32.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow232.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified32.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if 2.10000000000000004e-300 < k < 3.2999999999999998

    1. Initial program 99.9%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/99.9%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 51.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 50.0%

      \[\leadsto \color{blue}{a} \]

    if 3.2999999999999998 < k

    1. Initial program 75.3%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/75.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+75.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative75.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out75.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def75.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative75.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified75.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 54.1%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 52.6%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow252.6%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified52.6%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. associate-/r*58.9%

        \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
      2. div-inv59.0%

        \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
    9. Applied egg-rr59.0%

      \[\leadsto \color{blue}{\frac{a}{k} \cdot \frac{1}{k}} \]
    10. Step-by-step derivation
      1. un-div-inv58.9%

        \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
    11. Applied egg-rr58.9%

      \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification48.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq 2.1 \cdot 10^{-300}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 3.3:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]

Alternative 14: 25.4% accurate, 16.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq 1900000000:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m 1900000000.0) a (* -10.0 (* k a))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= 1900000000.0) {
		tmp = a;
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= 1900000000.0d0) then
        tmp = a
    else
        tmp = (-10.0d0) * (k * a)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= 1900000000.0) {
		tmp = a;
	} else {
		tmp = -10.0 * (k * a);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= 1900000000.0:
		tmp = a
	else:
		tmp = -10.0 * (k * a)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= 1900000000.0)
		tmp = a;
	else
		tmp = Float64(-10.0 * Float64(k * a));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= 1900000000.0)
		tmp = a;
	else
		tmp = -10.0 * (k * a);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, 1900000000.0], a, N[(-10.0 * N[(k * a), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq 1900000000:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(k \cdot a\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < 1.9e9

    1. Initial program 94.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/94.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+94.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative94.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out94.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def94.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative94.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified94.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 63.8%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 25.8%

      \[\leadsto \color{blue}{a} \]

    if 1.9e9 < m

    1. Initial program 70.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/70.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative70.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified70.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.9%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative8.7%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified8.7%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 18.4%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification23.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq 1900000000:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(k \cdot a\right)\\ \end{array} \]

Alternative 15: 19.8% accurate, 114.0× speedup?

\[\begin{array}{l} \\ a \end{array} \]
(FPCore (a k m) :precision binary64 a)
double code(double a, double k, double m) {
	return a;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = a
end function
public static double code(double a, double k, double m) {
	return a;
}
def code(a, k, m):
	return a
function code(a, k, m)
	return a
end
function tmp = code(a, k, m)
	tmp = a;
end
code[a_, k_, m_] := a
\begin{array}{l}

\\
a
\end{array}
Derivation
  1. Initial program 86.5%

    \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
  2. Step-by-step derivation
    1. associate-*r/86.5%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
    2. associate-+l+86.5%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
    3. +-commutative86.5%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
    4. distribute-rgt-out86.5%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
    5. fma-def86.5%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
    6. +-commutative86.5%

      \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
  3. Simplified86.5%

    \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
  4. Taylor expanded in m around 0 43.8%

    \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
  5. Taylor expanded in k around 0 18.6%

    \[\leadsto \color{blue}{a} \]
  6. Final simplification18.6%

    \[\leadsto a \]

Reproduce

?
herbie shell --seed 2023242 
(FPCore (a k m)
  :name "Falkner and Boettcher, Appendix A"
  :precision binary64
  (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))