Jmat.Real.erfi, branch x greater than or equal to 5

Percentage Accurate: 100.0% → 100.0%
Time: 8.3s
Alternatives: 8
Speedup: 4.2×

Specification

?
\[x \geq 0.5\]
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{\left|x\right|}\\ t_1 := \left(t_0 \cdot t_0\right) \cdot t_0\\ t_2 := \left(t_1 \cdot t_0\right) \cdot t_0\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t_0 + \frac{1}{2} \cdot t_1\right) + \frac{3}{4} \cdot t_2\right) + \frac{15}{8} \cdot \left(\left(t_2 \cdot t_0\right) \cdot t_0\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ 1.0 (fabs x)))
        (t_1 (* (* t_0 t_0) t_0))
        (t_2 (* (* t_1 t_0) t_0)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (+
     (+ (+ t_0 (* (/ 1.0 2.0) t_1)) (* (/ 3.0 4.0) t_2))
     (* (/ 15.0 8.0) (* (* t_2 t_0) t_0))))))
double code(double x) {
	double t_0 = 1.0 / fabs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
public static double code(double x) {
	double t_0 = 1.0 / Math.abs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
def code(x):
	t_0 = 1.0 / math.fabs(x)
	t_1 = (t_0 * t_0) * t_0
	t_2 = (t_1 * t_0) * t_0
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)))
function code(x)
	t_0 = Float64(1.0 / abs(x))
	t_1 = Float64(Float64(t_0 * t_0) * t_0)
	t_2 = Float64(Float64(t_1 * t_0) * t_0)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(Float64(Float64(t_0 + Float64(Float64(1.0 / 2.0) * t_1)) + Float64(Float64(3.0 / 4.0) * t_2)) + Float64(Float64(15.0 / 8.0) * Float64(Float64(t_2 * t_0) * t_0))))
end
function tmp = code(x)
	t_0 = 1.0 / abs(x);
	t_1 = (t_0 * t_0) * t_0;
	t_2 = (t_1 * t_0) * t_0;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
end
code[x_] := Block[{t$95$0 = N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$1 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(t$95$0 + N[(N[(1.0 / 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 / 4.0), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(15.0 / 8.0), $MachinePrecision] * N[(N[(t$95$2 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{\left|x\right|}\\
t_1 := \left(t_0 \cdot t_0\right) \cdot t_0\\
t_2 := \left(t_1 \cdot t_0\right) \cdot t_0\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t_0 + \frac{1}{2} \cdot t_1\right) + \frac{3}{4} \cdot t_2\right) + \frac{15}{8} \cdot \left(\left(t_2 \cdot t_0\right) \cdot t_0\right)\right)
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 100.0% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{\left|x\right|}\\ t_1 := \left(t_0 \cdot t_0\right) \cdot t_0\\ t_2 := \left(t_1 \cdot t_0\right) \cdot t_0\\ \left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t_0 + \frac{1}{2} \cdot t_1\right) + \frac{3}{4} \cdot t_2\right) + \frac{15}{8} \cdot \left(\left(t_2 \cdot t_0\right) \cdot t_0\right)\right) \end{array} \end{array} \]
(FPCore (x)
 :precision binary64
 (let* ((t_0 (/ 1.0 (fabs x)))
        (t_1 (* (* t_0 t_0) t_0))
        (t_2 (* (* t_1 t_0) t_0)))
   (*
    (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x))))
    (+
     (+ (+ t_0 (* (/ 1.0 2.0) t_1)) (* (/ 3.0 4.0) t_2))
     (* (/ 15.0 8.0) (* (* t_2 t_0) t_0))))))
double code(double x) {
	double t_0 = 1.0 / fabs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / sqrt(((double) M_PI))) * exp((fabs(x) * fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
public static double code(double x) {
	double t_0 = 1.0 / Math.abs(x);
	double t_1 = (t_0 * t_0) * t_0;
	double t_2 = (t_1 * t_0) * t_0;
	return ((1.0 / Math.sqrt(Math.PI)) * Math.exp((Math.abs(x) * Math.abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
}
def code(x):
	t_0 = 1.0 / math.fabs(x)
	t_1 = (t_0 * t_0) * t_0
	t_2 = (t_1 * t_0) * t_0
	return ((1.0 / math.sqrt(math.pi)) * math.exp((math.fabs(x) * math.fabs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)))
function code(x)
	t_0 = Float64(1.0 / abs(x))
	t_1 = Float64(Float64(t_0 * t_0) * t_0)
	t_2 = Float64(Float64(t_1 * t_0) * t_0)
	return Float64(Float64(Float64(1.0 / sqrt(pi)) * exp(Float64(abs(x) * abs(x)))) * Float64(Float64(Float64(t_0 + Float64(Float64(1.0 / 2.0) * t_1)) + Float64(Float64(3.0 / 4.0) * t_2)) + Float64(Float64(15.0 / 8.0) * Float64(Float64(t_2 * t_0) * t_0))))
end
function tmp = code(x)
	t_0 = 1.0 / abs(x);
	t_1 = (t_0 * t_0) * t_0;
	t_2 = (t_1 * t_0) * t_0;
	tmp = ((1.0 / sqrt(pi)) * exp((abs(x) * abs(x)))) * (((t_0 + ((1.0 / 2.0) * t_1)) + ((3.0 / 4.0) * t_2)) + ((15.0 / 8.0) * ((t_2 * t_0) * t_0)));
end
code[x_] := Block[{t$95$0 = N[(1.0 / N[Abs[x], $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, Block[{t$95$2 = N[(N[(t$95$1 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]}, N[(N[(N[(1.0 / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[Exp[N[(N[Abs[x], $MachinePrecision] * N[Abs[x], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(N[(N[(t$95$0 + N[(N[(1.0 / 2.0), $MachinePrecision] * t$95$1), $MachinePrecision]), $MachinePrecision] + N[(N[(3.0 / 4.0), $MachinePrecision] * t$95$2), $MachinePrecision]), $MachinePrecision] + N[(N[(15.0 / 8.0), $MachinePrecision] * N[(N[(t$95$2 * t$95$0), $MachinePrecision] * t$95$0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{\left|x\right|}\\
t_1 := \left(t_0 \cdot t_0\right) \cdot t_0\\
t_2 := \left(t_1 \cdot t_0\right) \cdot t_0\\
\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(t_0 + \frac{1}{2} \cdot t_1\right) + \frac{3}{4} \cdot t_2\right) + \frac{15}{8} \cdot \left(\left(t_2 \cdot t_0\right) \cdot t_0\right)\right)
\end{array}
\end{array}

Alternative 1: 100.0% accurate, 3.5× speedup?

\[\begin{array}{l} \\ \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt[3]{{\pi}^{1.5}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (/ (/ (exp (* x x)) (fabs x)) (cbrt (pow PI 1.5)))
  (+ 1.0 (+ (/ 1.875 (pow x 6.0)) (/ (+ 0.5 (/ 0.75 (* x x))) (* x x))))))
double code(double x) {
	return ((exp((x * x)) / fabs(x)) / cbrt(pow(((double) M_PI), 1.5))) * (1.0 + ((1.875 / pow(x, 6.0)) + ((0.5 + (0.75 / (x * x))) / (x * x))));
}
public static double code(double x) {
	return ((Math.exp((x * x)) / Math.abs(x)) / Math.cbrt(Math.pow(Math.PI, 1.5))) * (1.0 + ((1.875 / Math.pow(x, 6.0)) + ((0.5 + (0.75 / (x * x))) / (x * x))));
}
function code(x)
	return Float64(Float64(Float64(exp(Float64(x * x)) / abs(x)) / cbrt((pi ^ 1.5))) * Float64(1.0 + Float64(Float64(1.875 / (x ^ 6.0)) + Float64(Float64(0.5 + Float64(0.75 / Float64(x * x))) / Float64(x * x)))))
end
code[x_] := N[(N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] / N[Power[N[Power[Pi, 1.5], $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision] * N[(1.0 + N[(N[(1.875 / N[Power[x, 6.0], $MachinePrecision]), $MachinePrecision] + N[(N[(0.5 + N[(0.75 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt[3]{{\pi}^{1.5}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Step-by-step derivation
    1. add-cbrt-cube100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\color{blue}{\sqrt[3]{\left(\sqrt{\pi} \cdot \sqrt{\pi}\right) \cdot \sqrt{\pi}}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
    2. pow1/3100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\color{blue}{{\left(\left(\sqrt{\pi} \cdot \sqrt{\pi}\right) \cdot \sqrt{\pi}\right)}^{0.3333333333333333}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
    3. add-sqr-sqrt100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{{\left(\color{blue}{\pi} \cdot \sqrt{\pi}\right)}^{0.3333333333333333}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
    4. pow1100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{{\left(\color{blue}{{\pi}^{1}} \cdot \sqrt{\pi}\right)}^{0.3333333333333333}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
    5. pow1/2100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{{\left({\pi}^{1} \cdot \color{blue}{{\pi}^{0.5}}\right)}^{0.3333333333333333}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
    6. pow-prod-up100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{{\color{blue}{\left({\pi}^{\left(1 + 0.5\right)}\right)}}^{0.3333333333333333}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
    7. metadata-eval100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{{\left({\pi}^{\color{blue}{1.5}}\right)}^{0.3333333333333333}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
  4. Applied egg-rr100.0%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\color{blue}{{\left({\pi}^{1.5}\right)}^{0.3333333333333333}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
  5. Step-by-step derivation
    1. unpow1/3100.0%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\color{blue}{\sqrt[3]{{\pi}^{1.5}}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
  6. Simplified100.0%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\color{blue}{\sqrt[3]{{\pi}^{1.5}}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]
  7. Final simplification100.0%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt[3]{{\pi}^{1.5}}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \]

Alternative 2: 100.0% accurate, 4.2× speedup?

\[\begin{array}{l} \\ \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \cdot \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (+ 1.0 (+ (/ 1.875 (pow x 6.0)) (/ (+ 0.5 (/ 0.75 (* x x))) (* x x))))
  (/ (/ (exp (* x x)) (fabs x)) (sqrt PI))))
double code(double x) {
	return (1.0 + ((1.875 / pow(x, 6.0)) + ((0.5 + (0.75 / (x * x))) / (x * x)))) * ((exp((x * x)) / fabs(x)) / sqrt(((double) M_PI)));
}
public static double code(double x) {
	return (1.0 + ((1.875 / Math.pow(x, 6.0)) + ((0.5 + (0.75 / (x * x))) / (x * x)))) * ((Math.exp((x * x)) / Math.abs(x)) / Math.sqrt(Math.PI));
}
def code(x):
	return (1.0 + ((1.875 / math.pow(x, 6.0)) + ((0.5 + (0.75 / (x * x))) / (x * x)))) * ((math.exp((x * x)) / math.fabs(x)) / math.sqrt(math.pi))
function code(x)
	return Float64(Float64(1.0 + Float64(Float64(1.875 / (x ^ 6.0)) + Float64(Float64(0.5 + Float64(0.75 / Float64(x * x))) / Float64(x * x)))) * Float64(Float64(exp(Float64(x * x)) / abs(x)) / sqrt(pi)))
end
function tmp = code(x)
	tmp = (1.0 + ((1.875 / (x ^ 6.0)) + ((0.5 + (0.75 / (x * x))) / (x * x)))) * ((exp((x * x)) / abs(x)) / sqrt(pi));
end
code[x_] := N[(N[(1.0 + N[(N[(1.875 / N[Power[x, 6.0], $MachinePrecision]), $MachinePrecision] + N[(N[(0.5 + N[(0.75 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \cdot \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Final simplification100.0%

    \[\leadsto \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right) \cdot \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \]

Alternative 3: 99.6% accurate, 4.2× speedup?

\[\begin{array}{l} \\ \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{x \cdot x}\right)\right) \end{array} \]
(FPCore (x)
 :precision binary64
 (*
  (/ (/ (exp (* x x)) (fabs x)) (sqrt PI))
  (+ 1.0 (+ (/ 1.875 (pow x 6.0)) (/ 0.5 (* x x))))))
double code(double x) {
	return ((exp((x * x)) / fabs(x)) / sqrt(((double) M_PI))) * (1.0 + ((1.875 / pow(x, 6.0)) + (0.5 / (x * x))));
}
public static double code(double x) {
	return ((Math.exp((x * x)) / Math.abs(x)) / Math.sqrt(Math.PI)) * (1.0 + ((1.875 / Math.pow(x, 6.0)) + (0.5 / (x * x))));
}
def code(x):
	return ((math.exp((x * x)) / math.fabs(x)) / math.sqrt(math.pi)) * (1.0 + ((1.875 / math.pow(x, 6.0)) + (0.5 / (x * x))))
function code(x)
	return Float64(Float64(Float64(exp(Float64(x * x)) / abs(x)) / sqrt(pi)) * Float64(1.0 + Float64(Float64(1.875 / (x ^ 6.0)) + Float64(0.5 / Float64(x * x)))))
end
function tmp = code(x)
	tmp = ((exp((x * x)) / abs(x)) / sqrt(pi)) * (1.0 + ((1.875 / (x ^ 6.0)) + (0.5 / (x * x))));
end
code[x_] := N[(N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / N[Abs[x], $MachinePrecision]), $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[(1.0 + N[(N[(1.875 / N[Power[x, 6.0], $MachinePrecision]), $MachinePrecision] + N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{x \cdot x}\right)\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{{x}^{2}}}\right)\right) \]
  4. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{\color{blue}{x \cdot x}}\right)\right) \]
  5. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{x \cdot x}}\right)\right) \]
  6. Final simplification99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{x \cdot x}\right)\right) \]

Alternative 4: 99.6% accurate, 6.9× speedup?

\[\begin{array}{l} \\ \frac{\frac{e^{x \cdot x}}{x}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \end{array} \]
(FPCore (x)
 :precision binary64
 (* (/ (/ (exp (* x x)) x) (sqrt PI)) (+ 1.0 (/ 0.5 (* x x)))))
double code(double x) {
	return ((exp((x * x)) / x) / sqrt(((double) M_PI))) * (1.0 + (0.5 / (x * x)));
}
public static double code(double x) {
	return ((Math.exp((x * x)) / x) / Math.sqrt(Math.PI)) * (1.0 + (0.5 / (x * x)));
}
def code(x):
	return ((math.exp((x * x)) / x) / math.sqrt(math.pi)) * (1.0 + (0.5 / (x * x)))
function code(x)
	return Float64(Float64(Float64(exp(Float64(x * x)) / x) / sqrt(pi)) * Float64(1.0 + Float64(0.5 / Float64(x * x))))
end
function tmp = code(x)
	tmp = ((exp((x * x)) / x) / sqrt(pi)) * (1.0 + (0.5 / (x * x)));
end
code[x_] := N[(N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision] * N[(1.0 + N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\frac{e^{x \cdot x}}{x}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{{x}^{2}}}\right)\right) \]
  4. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{\color{blue}{x \cdot x}}\right)\right) \]
  5. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{x \cdot x}}\right)\right) \]
  6. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{{x}^{2}}}\right) \]
  7. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{\color{blue}{x \cdot x}}\right) \]
  8. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{x \cdot x}}\right) \]
  9. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\color{blue}{\frac{e^{{x}^{2}}}{\left|x\right|}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  10. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    2. exp-prod99.7%

      \[\leadsto \frac{\frac{\color{blue}{{\left(e^{x}\right)}^{x}}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    3. unpow199.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{{x}^{1}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    4. sqr-pow99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\left(\frac{1}{2}\right)}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    5. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|{x}^{\color{blue}{0.5}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    6. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{\sqrt{x}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    7. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\sqrt{x} \cdot {x}^{\color{blue}{0.5}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    8. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\sqrt{x} \cdot \color{blue}{\sqrt{x}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    9. fabs-sqr99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{\sqrt{x} \cdot \sqrt{x}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    10. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{{x}^{0.5}} \cdot \sqrt{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    11. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{{x}^{\color{blue}{\left(\frac{1}{2}\right)}} \cdot \sqrt{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    12. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{{x}^{\left(\frac{1}{2}\right)} \cdot \color{blue}{{x}^{0.5}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    13. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\color{blue}{\left(\frac{1}{2}\right)}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    14. sqr-pow99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{{x}^{1}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    15. unpow199.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  11. Simplified99.7%

    \[\leadsto \frac{\color{blue}{\frac{{\left(e^{x}\right)}^{x}}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  12. Step-by-step derivation
    1. *-un-lft-identity99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \color{blue}{\left(1 \cdot \frac{{\left(e^{x}\right)}^{x}}{x}\right)} \]
    2. *-commutative99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \color{blue}{\left(\frac{{\left(e^{x}\right)}^{x}}{x} \cdot 1\right)} \]
    3. pow-exp99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \left(\frac{\color{blue}{e^{x \cdot x}}}{x} \cdot 1\right) \]
  13. Applied egg-rr99.7%

    \[\leadsto \frac{\color{blue}{\frac{e^{x \cdot x}}{x} \cdot 1}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  14. Final simplification99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{x}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]

Alternative 5: 99.5% accurate, 7.1× speedup?

\[\begin{array}{l} \\ \frac{e^{x \cdot x}}{x} \cdot \sqrt{\frac{1}{\pi}} \end{array} \]
(FPCore (x) :precision binary64 (* (/ (exp (* x x)) x) (sqrt (/ 1.0 PI))))
double code(double x) {
	return (exp((x * x)) / x) * sqrt((1.0 / ((double) M_PI)));
}
public static double code(double x) {
	return (Math.exp((x * x)) / x) * Math.sqrt((1.0 / Math.PI));
}
def code(x):
	return (math.exp((x * x)) / x) * math.sqrt((1.0 / math.pi))
function code(x)
	return Float64(Float64(exp(Float64(x * x)) / x) * sqrt(Float64(1.0 / pi)))
end
function tmp = code(x)
	tmp = (exp((x * x)) / x) * sqrt((1.0 / pi));
end
code[x_] := N[(N[(N[Exp[N[(x * x), $MachinePrecision]], $MachinePrecision] / x), $MachinePrecision] * N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{e^{x \cdot x}}{x} \cdot \sqrt{\frac{1}{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{{x}^{2}}}\right)\right) \]
  4. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{\color{blue}{x \cdot x}}\right)\right) \]
  5. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{x \cdot x}}\right)\right) \]
  6. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{{x}^{2}}}\right) \]
  7. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{\color{blue}{x \cdot x}}\right) \]
  8. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{x \cdot x}}\right) \]
  9. Taylor expanded in x around inf 99.7%

    \[\leadsto \color{blue}{\frac{e^{{x}^{2}}}{\left|x\right|} \cdot \sqrt{\frac{1}{\pi}}} \]
  10. Step-by-step derivation
    1. *-commutative99.7%

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{e^{{x}^{2}}}{\left|x\right|}} \]
    2. unpow299.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|} \]
    3. exp-prod99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{\color{blue}{{\left(e^{x}\right)}^{x}}}{\left|x\right|} \]
    4. unpow199.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{{x}^{1}}\right|} \]
    5. sqr-pow99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\left(\frac{1}{2}\right)}}\right|} \]
    6. metadata-eval99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\left|{x}^{\color{blue}{0.5}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|} \]
    7. unpow1/299.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{\sqrt{x}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|} \]
    8. metadata-eval99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\left|\sqrt{x} \cdot {x}^{\color{blue}{0.5}}\right|} \]
    9. unpow1/299.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\left|\sqrt{x} \cdot \color{blue}{\sqrt{x}}\right|} \]
    10. fabs-sqr99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\color{blue}{\sqrt{x} \cdot \sqrt{x}}} \]
    11. unpow1/299.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\color{blue}{{x}^{0.5}} \cdot \sqrt{x}} \]
    12. metadata-eval99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{{x}^{\color{blue}{\left(\frac{1}{2}\right)}} \cdot \sqrt{x}} \]
    13. unpow1/299.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{{x}^{\left(\frac{1}{2}\right)} \cdot \color{blue}{{x}^{0.5}}} \]
    14. metadata-eval99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\color{blue}{\left(\frac{1}{2}\right)}}} \]
    15. sqr-pow99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\color{blue}{{x}^{1}}} \]
    16. unpow199.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{\color{blue}{x}} \]
  11. Simplified99.7%

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \frac{{\left(e^{x}\right)}^{x}}{x}} \]
  12. Step-by-step derivation
    1. *-un-lft-identity99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \color{blue}{\left(1 \cdot \frac{{\left(e^{x}\right)}^{x}}{x}\right)} \]
    2. *-commutative99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \color{blue}{\left(\frac{{\left(e^{x}\right)}^{x}}{x} \cdot 1\right)} \]
    3. pow-exp99.7%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \left(\frac{\color{blue}{e^{x \cdot x}}}{x} \cdot 1\right) \]
  13. Applied egg-rr99.7%

    \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \color{blue}{\left(\frac{e^{x \cdot x}}{x} \cdot 1\right)} \]
  14. Final simplification99.7%

    \[\leadsto \frac{e^{x \cdot x}}{x} \cdot \sqrt{\frac{1}{\pi}} \]

Alternative 6: 5.4% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \left(1 + \frac{0.5}{x \cdot x}\right) \cdot \frac{x + \frac{1}{x}}{\sqrt{\pi}} \end{array} \]
(FPCore (x)
 :precision binary64
 (* (+ 1.0 (/ 0.5 (* x x))) (/ (+ x (/ 1.0 x)) (sqrt PI))))
double code(double x) {
	return (1.0 + (0.5 / (x * x))) * ((x + (1.0 / x)) / sqrt(((double) M_PI)));
}
public static double code(double x) {
	return (1.0 + (0.5 / (x * x))) * ((x + (1.0 / x)) / Math.sqrt(Math.PI));
}
def code(x):
	return (1.0 + (0.5 / (x * x))) * ((x + (1.0 / x)) / math.sqrt(math.pi))
function code(x)
	return Float64(Float64(1.0 + Float64(0.5 / Float64(x * x))) * Float64(Float64(x + Float64(1.0 / x)) / sqrt(pi)))
end
function tmp = code(x)
	tmp = (1.0 + (0.5 / (x * x))) * ((x + (1.0 / x)) / sqrt(pi));
end
code[x_] := N[(N[(1.0 + N[(0.5 / N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] * N[(N[(x + N[(1.0 / x), $MachinePrecision]), $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\left(1 + \frac{0.5}{x \cdot x}\right) \cdot \frac{x + \frac{1}{x}}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{{x}^{2}}}\right)\right) \]
  4. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{\color{blue}{x \cdot x}}\right)\right) \]
  5. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{x \cdot x}}\right)\right) \]
  6. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{{x}^{2}}}\right) \]
  7. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{\color{blue}{x \cdot x}}\right) \]
  8. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{x \cdot x}}\right) \]
  9. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\color{blue}{\frac{e^{{x}^{2}}}{\left|x\right|}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  10. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{\color{blue}{x \cdot x}}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    2. exp-prod99.7%

      \[\leadsto \frac{\frac{\color{blue}{{\left(e^{x}\right)}^{x}}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    3. unpow199.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{{x}^{1}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    4. sqr-pow99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\left(\frac{1}{2}\right)}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    5. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|{x}^{\color{blue}{0.5}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    6. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\color{blue}{\sqrt{x}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    7. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\sqrt{x} \cdot {x}^{\color{blue}{0.5}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    8. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\left|\sqrt{x} \cdot \color{blue}{\sqrt{x}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    9. fabs-sqr99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{\sqrt{x} \cdot \sqrt{x}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    10. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{{x}^{0.5}} \cdot \sqrt{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    11. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{{x}^{\color{blue}{\left(\frac{1}{2}\right)}} \cdot \sqrt{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    12. unpow1/299.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{{x}^{\left(\frac{1}{2}\right)} \cdot \color{blue}{{x}^{0.5}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    13. metadata-eval99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\color{blue}{\left(\frac{1}{2}\right)}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    14. sqr-pow99.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{{x}^{1}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    15. unpow199.7%

      \[\leadsto \frac{\frac{{\left(e^{x}\right)}^{x}}{\color{blue}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  11. Simplified99.7%

    \[\leadsto \frac{\color{blue}{\frac{{\left(e^{x}\right)}^{x}}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  12. Taylor expanded in x around 0 5.4%

    \[\leadsto \frac{\color{blue}{\frac{1}{x} + x}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  13. Final simplification5.4%

    \[\leadsto \left(1 + \frac{0.5}{x \cdot x}\right) \cdot \frac{x + \frac{1}{x}}{\sqrt{\pi}} \]

Alternative 7: 5.4% accurate, 10.5× speedup?

\[\begin{array}{l} \\ \sqrt{\frac{1}{\pi}} \cdot \left(x + \frac{1.5}{x}\right) \end{array} \]
(FPCore (x) :precision binary64 (* (sqrt (/ 1.0 PI)) (+ x (/ 1.5 x))))
double code(double x) {
	return sqrt((1.0 / ((double) M_PI))) * (x + (1.5 / x));
}
public static double code(double x) {
	return Math.sqrt((1.0 / Math.PI)) * (x + (1.5 / x));
}
def code(x):
	return math.sqrt((1.0 / math.pi)) * (x + (1.5 / x))
function code(x)
	return Float64(sqrt(Float64(1.0 / pi)) * Float64(x + Float64(1.5 / x)))
end
function tmp = code(x)
	tmp = sqrt((1.0 / pi)) * (x + (1.5 / x));
end
code[x_] := N[(N[Sqrt[N[(1.0 / Pi), $MachinePrecision]], $MachinePrecision] * N[(x + N[(1.5 / x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\frac{1}{\pi}} \cdot \left(x + \frac{1.5}{x}\right)
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{{x}^{2}}}\right)\right) \]
  4. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{\color{blue}{x \cdot x}}\right)\right) \]
  5. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{x \cdot x}}\right)\right) \]
  6. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{{x}^{2}}}\right) \]
  7. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{\color{blue}{x \cdot x}}\right) \]
  8. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{x \cdot x}}\right) \]
  9. Taylor expanded in x around 0 50.5%

    \[\leadsto \frac{\color{blue}{\frac{{x}^{2}}{\left|x\right|} + \frac{1}{\left|x\right|}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  10. Step-by-step derivation
    1. unpow250.5%

      \[\leadsto \frac{\frac{\color{blue}{x \cdot x}}{\left|x\right|} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    2. associate-/l*5.4%

      \[\leadsto \frac{\color{blue}{\frac{x}{\frac{\left|x\right|}{x}}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    3. unpow15.4%

      \[\leadsto \frac{\frac{x}{\frac{\left|\color{blue}{{x}^{1}}\right|}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    4. sqr-pow5.4%

      \[\leadsto \frac{\frac{x}{\frac{\left|\color{blue}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\left(\frac{1}{2}\right)}}\right|}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    5. metadata-eval5.4%

      \[\leadsto \frac{\frac{x}{\frac{\left|{x}^{\color{blue}{0.5}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    6. unpow1/25.4%

      \[\leadsto \frac{\frac{x}{\frac{\left|\color{blue}{\sqrt{x}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    7. metadata-eval5.4%

      \[\leadsto \frac{\frac{x}{\frac{\left|\sqrt{x} \cdot {x}^{\color{blue}{0.5}}\right|}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    8. unpow1/25.4%

      \[\leadsto \frac{\frac{x}{\frac{\left|\sqrt{x} \cdot \color{blue}{\sqrt{x}}\right|}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    9. fabs-sqr5.4%

      \[\leadsto \frac{\frac{x}{\frac{\color{blue}{\sqrt{x} \cdot \sqrt{x}}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    10. unpow1/25.4%

      \[\leadsto \frac{\frac{x}{\frac{\color{blue}{{x}^{0.5}} \cdot \sqrt{x}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    11. metadata-eval5.4%

      \[\leadsto \frac{\frac{x}{\frac{{x}^{\color{blue}{\left(\frac{1}{2}\right)}} \cdot \sqrt{x}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    12. unpow1/25.4%

      \[\leadsto \frac{\frac{x}{\frac{{x}^{\left(\frac{1}{2}\right)} \cdot \color{blue}{{x}^{0.5}}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    13. metadata-eval5.4%

      \[\leadsto \frac{\frac{x}{\frac{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\color{blue}{\left(\frac{1}{2}\right)}}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    14. sqr-pow5.4%

      \[\leadsto \frac{\frac{x}{\frac{\color{blue}{{x}^{1}}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    15. unpow15.4%

      \[\leadsto \frac{\frac{x}{\frac{\color{blue}{x}}{x}} + \frac{1}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    16. unpow15.4%

      \[\leadsto \frac{\frac{x}{\frac{x}{x}} + \frac{1}{\left|\color{blue}{{x}^{1}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    17. sqr-pow5.4%

      \[\leadsto \frac{\frac{x}{\frac{x}{x}} + \frac{1}{\left|\color{blue}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\left(\frac{1}{2}\right)}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    18. metadata-eval5.4%

      \[\leadsto \frac{\frac{x}{\frac{x}{x}} + \frac{1}{\left|{x}^{\color{blue}{0.5}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    19. unpow1/25.4%

      \[\leadsto \frac{\frac{x}{\frac{x}{x}} + \frac{1}{\left|\color{blue}{\sqrt{x}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    20. metadata-eval5.4%

      \[\leadsto \frac{\frac{x}{\frac{x}{x}} + \frac{1}{\left|\sqrt{x} \cdot {x}^{\color{blue}{0.5}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    21. unpow1/25.4%

      \[\leadsto \frac{\frac{x}{\frac{x}{x}} + \frac{1}{\left|\sqrt{x} \cdot \color{blue}{\sqrt{x}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  11. Simplified5.4%

    \[\leadsto \frac{\color{blue}{\frac{x}{\frac{x}{x}} + \frac{1}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  12. Taylor expanded in x around inf 5.4%

    \[\leadsto \color{blue}{1.5 \cdot \left(\frac{1}{x} \cdot \sqrt{\frac{1}{\pi}}\right) + \sqrt{\frac{1}{\pi}} \cdot x} \]
  13. Step-by-step derivation
    1. +-commutative5.4%

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot x + 1.5 \cdot \left(\frac{1}{x} \cdot \sqrt{\frac{1}{\pi}}\right)} \]
    2. *-commutative5.4%

      \[\leadsto \color{blue}{x \cdot \sqrt{\frac{1}{\pi}}} + 1.5 \cdot \left(\frac{1}{x} \cdot \sqrt{\frac{1}{\pi}}\right) \]
    3. associate-*r*5.4%

      \[\leadsto x \cdot \sqrt{\frac{1}{\pi}} + \color{blue}{\left(1.5 \cdot \frac{1}{x}\right) \cdot \sqrt{\frac{1}{\pi}}} \]
    4. distribute-rgt-out5.4%

      \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \left(x + 1.5 \cdot \frac{1}{x}\right)} \]
    5. associate-*r/5.4%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \left(x + \color{blue}{\frac{1.5 \cdot 1}{x}}\right) \]
    6. metadata-eval5.4%

      \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \left(x + \frac{\color{blue}{1.5}}{x}\right) \]
  14. Simplified5.4%

    \[\leadsto \color{blue}{\sqrt{\frac{1}{\pi}} \cdot \left(x + \frac{1.5}{x}\right)} \]
  15. Final simplification5.4%

    \[\leadsto \sqrt{\frac{1}{\pi}} \cdot \left(x + \frac{1.5}{x}\right) \]

Alternative 8: 2.3% accurate, 10.7× speedup?

\[\begin{array}{l} \\ \frac{\frac{1}{x}}{\sqrt{\pi}} \end{array} \]
(FPCore (x) :precision binary64 (/ (/ 1.0 x) (sqrt PI)))
double code(double x) {
	return (1.0 / x) / sqrt(((double) M_PI));
}
public static double code(double x) {
	return (1.0 / x) / Math.sqrt(Math.PI);
}
def code(x):
	return (1.0 / x) / math.sqrt(math.pi)
function code(x)
	return Float64(Float64(1.0 / x) / sqrt(pi))
end
function tmp = code(x)
	tmp = (1.0 / x) / sqrt(pi);
end
code[x_] := N[(N[(1.0 / x), $MachinePrecision] / N[Sqrt[Pi], $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{\frac{1}{x}}{\sqrt{\pi}}
\end{array}
Derivation
  1. Initial program 100.0%

    \[\left(\frac{1}{\sqrt{\pi}} \cdot e^{\left|x\right| \cdot \left|x\right|}\right) \cdot \left(\left(\left(\frac{1}{\left|x\right|} + \frac{1}{2} \cdot \left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{3}{4} \cdot \left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) + \frac{15}{8} \cdot \left(\left(\left(\left(\left(\left(\frac{1}{\left|x\right|} \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right) \cdot \frac{1}{\left|x\right|}\right)\right) \]
  2. Simplified100.0%

    \[\leadsto \color{blue}{\frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5 + \frac{0.75}{x \cdot x}}{x \cdot x}\right)\right)} \]
  3. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{{x}^{2}}}\right)\right) \]
  4. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \frac{0.5}{\color{blue}{x \cdot x}}\right)\right) \]
  5. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \left(\frac{1.875}{{x}^{6}} + \color{blue}{\frac{0.5}{x \cdot x}}\right)\right) \]
  6. Taylor expanded in x around inf 99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{{x}^{2}}}\right) \]
  7. Step-by-step derivation
    1. unpow299.7%

      \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{\color{blue}{x \cdot x}}\right) \]
  8. Simplified99.7%

    \[\leadsto \frac{\frac{e^{x \cdot x}}{\left|x\right|}}{\sqrt{\pi}} \cdot \left(1 + \color{blue}{\frac{0.5}{x \cdot x}}\right) \]
  9. Taylor expanded in x around 0 2.3%

    \[\leadsto \frac{\color{blue}{\frac{1}{\left|x\right|}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  10. Step-by-step derivation
    1. unpow12.3%

      \[\leadsto \frac{\frac{1}{\left|\color{blue}{{x}^{1}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    2. sqr-pow2.3%

      \[\leadsto \frac{\frac{1}{\left|\color{blue}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\left(\frac{1}{2}\right)}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    3. metadata-eval2.3%

      \[\leadsto \frac{\frac{1}{\left|{x}^{\color{blue}{0.5}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    4. unpow1/22.3%

      \[\leadsto \frac{\frac{1}{\left|\color{blue}{\sqrt{x}} \cdot {x}^{\left(\frac{1}{2}\right)}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    5. metadata-eval2.3%

      \[\leadsto \frac{\frac{1}{\left|\sqrt{x} \cdot {x}^{\color{blue}{0.5}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    6. unpow1/22.3%

      \[\leadsto \frac{\frac{1}{\left|\sqrt{x} \cdot \color{blue}{\sqrt{x}}\right|}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    7. fabs-sqr2.3%

      \[\leadsto \frac{\frac{1}{\color{blue}{\sqrt{x} \cdot \sqrt{x}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    8. unpow1/22.3%

      \[\leadsto \frac{\frac{1}{\color{blue}{{x}^{0.5}} \cdot \sqrt{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    9. metadata-eval2.3%

      \[\leadsto \frac{\frac{1}{{x}^{\color{blue}{\left(\frac{1}{2}\right)}} \cdot \sqrt{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    10. unpow1/22.3%

      \[\leadsto \frac{\frac{1}{{x}^{\left(\frac{1}{2}\right)} \cdot \color{blue}{{x}^{0.5}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    11. metadata-eval2.3%

      \[\leadsto \frac{\frac{1}{{x}^{\left(\frac{1}{2}\right)} \cdot {x}^{\color{blue}{\left(\frac{1}{2}\right)}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    12. sqr-pow2.3%

      \[\leadsto \frac{\frac{1}{\color{blue}{{x}^{1}}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
    13. unpow12.3%

      \[\leadsto \frac{\frac{1}{\color{blue}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  11. Simplified2.3%

    \[\leadsto \frac{\color{blue}{\frac{1}{x}}}{\sqrt{\pi}} \cdot \left(1 + \frac{0.5}{x \cdot x}\right) \]
  12. Taylor expanded in x around inf 2.3%

    \[\leadsto \frac{\frac{1}{x}}{\sqrt{\pi}} \cdot \color{blue}{1} \]
  13. Final simplification2.3%

    \[\leadsto \frac{\frac{1}{x}}{\sqrt{\pi}} \]

Reproduce

?
herbie shell --seed 2023228 
(FPCore (x)
  :name "Jmat.Real.erfi, branch x greater than or equal to 5"
  :precision binary64
  :pre (>= x 0.5)
  (* (* (/ 1.0 (sqrt PI)) (exp (* (fabs x) (fabs x)))) (+ (+ (+ (/ 1.0 (fabs x)) (* (/ 1.0 2.0) (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))))) (* (/ 3.0 4.0) (* (* (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))))) (* (/ 15.0 8.0) (* (* (* (* (* (* (/ 1.0 (fabs x)) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x))) (/ 1.0 (fabs x)))))))