Falkner and Boettcher, Appendix A

Percentage Accurate: 89.1% → 97.6%
Time: 10.9s
Alternatives: 11
Speedup: 1.1×

Specification

?
\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 11 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 89.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))
double code(double a, double k, double m) {
	return (a * pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = (a * (k ** m)) / ((1.0d0 + (10.0d0 * k)) + (k * k))
end function
public static double code(double a, double k, double m) {
	return (a * Math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k));
}
def code(a, k, m):
	return (a * math.pow(k, m)) / ((1.0 + (10.0 * k)) + (k * k))
function code(a, k, m)
	return Float64(Float64(a * (k ^ m)) / Float64(Float64(1.0 + Float64(10.0 * k)) + Float64(k * k)))
end
function tmp = code(a, k, m)
	tmp = (a * (k ^ m)) / ((1.0 + (10.0 * k)) + (k * k));
end
code[a_, k_, m_] := N[(N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision] / N[(N[(1.0 + N[(10.0 * k), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\begin{array}{l}

\\
\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}
\end{array}

Alternative 1: 97.6% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := a \cdot {k}^{m}\\ \mathbf{if}\;\frac{t_0}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 10^{+305}:\\ \;\;\;\;\frac{a}{\frac{1 + \left(k \cdot k + k \cdot 10\right)}{{k}^{m}}}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (let* ((t_0 (* a (pow k m))))
   (if (<= (/ t_0 (+ (+ 1.0 (* k 10.0)) (* k k))) 1e+305)
     (/ a (/ (+ 1.0 (+ (* k k) (* k 10.0))) (pow k m)))
     t_0)))
double code(double a, double k, double m) {
	double t_0 = a * pow(k, m);
	double tmp;
	if ((t_0 / ((1.0 + (k * 10.0)) + (k * k))) <= 1e+305) {
		tmp = a / ((1.0 + ((k * k) + (k * 10.0))) / pow(k, m));
	} else {
		tmp = t_0;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: t_0
    real(8) :: tmp
    t_0 = a * (k ** m)
    if ((t_0 / ((1.0d0 + (k * 10.0d0)) + (k * k))) <= 1d+305) then
        tmp = a / ((1.0d0 + ((k * k) + (k * 10.0d0))) / (k ** m))
    else
        tmp = t_0
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double t_0 = a * Math.pow(k, m);
	double tmp;
	if ((t_0 / ((1.0 + (k * 10.0)) + (k * k))) <= 1e+305) {
		tmp = a / ((1.0 + ((k * k) + (k * 10.0))) / Math.pow(k, m));
	} else {
		tmp = t_0;
	}
	return tmp;
}
def code(a, k, m):
	t_0 = a * math.pow(k, m)
	tmp = 0
	if (t_0 / ((1.0 + (k * 10.0)) + (k * k))) <= 1e+305:
		tmp = a / ((1.0 + ((k * k) + (k * 10.0))) / math.pow(k, m))
	else:
		tmp = t_0
	return tmp
function code(a, k, m)
	t_0 = Float64(a * (k ^ m))
	tmp = 0.0
	if (Float64(t_0 / Float64(Float64(1.0 + Float64(k * 10.0)) + Float64(k * k))) <= 1e+305)
		tmp = Float64(a / Float64(Float64(1.0 + Float64(Float64(k * k) + Float64(k * 10.0))) / (k ^ m)));
	else
		tmp = t_0;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	t_0 = a * (k ^ m);
	tmp = 0.0;
	if ((t_0 / ((1.0 + (k * 10.0)) + (k * k))) <= 1e+305)
		tmp = a / ((1.0 + ((k * k) + (k * 10.0))) / (k ^ m));
	else
		tmp = t_0;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := Block[{t$95$0 = N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision]}, If[LessEqual[N[(t$95$0 / N[(N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision] + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1e+305], N[(a / N[(N[(1.0 + N[(N[(k * k), $MachinePrecision] + N[(k * 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[Power[k, m], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], t$95$0]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := a \cdot {k}^{m}\\
\mathbf{if}\;\frac{t_0}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 10^{+305}:\\
\;\;\;\;\frac{a}{\frac{1 + \left(k \cdot k + k \cdot 10\right)}{{k}^{m}}}\\

\mathbf{else}:\\
\;\;\;\;t_0\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (/.f64 (*.f64 a (pow.f64 k m)) (+.f64 (+.f64 1 (*.f64 10 k)) (*.f64 k k))) < 9.9999999999999994e304

    1. Initial program 98.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-/l*98.1%

        \[\leadsto \color{blue}{\frac{a}{\frac{\left(1 + 10 \cdot k\right) + k \cdot k}{{k}^{m}}}} \]
      2. associate-+l+98.1%

        \[\leadsto \frac{a}{\frac{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}}{{k}^{m}}} \]
      3. *-commutative98.1%

        \[\leadsto \frac{a}{\frac{1 + \left(\color{blue}{k \cdot 10} + k \cdot k\right)}{{k}^{m}}} \]
    3. Simplified98.1%

      \[\leadsto \color{blue}{\frac{a}{\frac{1 + \left(k \cdot 10 + k \cdot k\right)}{{k}^{m}}}} \]

    if 9.9999999999999994e304 < (/.f64 (*.f64 a (pow.f64 k m)) (+.f64 (+.f64 1 (*.f64 10 k)) (*.f64 k k)))

    1. Initial program 51.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/51.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+51.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative51.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out51.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def51.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative51.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified51.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 51.1%

      \[\leadsto \color{blue}{e^{\log k \cdot m} \cdot a} \]
    5. Step-by-step derivation
      1. exp-to-pow100.0%

        \[\leadsto \color{blue}{{k}^{m}} \cdot a \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
    6. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{a \cdot {k}^{m}}{\left(1 + k \cdot 10\right) + k \cdot k} \leq 10^{+305}:\\ \;\;\;\;\frac{a}{\frac{1 + \left(k \cdot k + k \cdot 10\right)}{{k}^{m}}}\\ \mathbf{else}:\\ \;\;\;\;a \cdot {k}^{m}\\ \end{array} \]

Alternative 2: 96.8% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -65 \lor \neg \left(m \leq 0.62\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= m -65.0) (not (<= m 0.62)))
   (* a (pow k m))
   (/ a (+ 1.0 (* k (+ k 10.0))))))
double code(double a, double k, double m) {
	double tmp;
	if ((m <= -65.0) || !(m <= 0.62)) {
		tmp = a * pow(k, m);
	} else {
		tmp = a / (1.0 + (k * (k + 10.0)));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((m <= (-65.0d0)) .or. (.not. (m <= 0.62d0))) then
        tmp = a * (k ** m)
    else
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((m <= -65.0) || !(m <= 0.62)) {
		tmp = a * Math.pow(k, m);
	} else {
		tmp = a / (1.0 + (k * (k + 10.0)));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (m <= -65.0) or not (m <= 0.62):
		tmp = a * math.pow(k, m)
	else:
		tmp = a / (1.0 + (k * (k + 10.0)))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((m <= -65.0) || !(m <= 0.62))
		tmp = Float64(a * (k ^ m));
	else
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((m <= -65.0) || ~((m <= 0.62)))
		tmp = a * (k ^ m);
	else
		tmp = a / (1.0 + (k * (k + 10.0)));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[m, -65.0], N[Not[LessEqual[m, 0.62]], $MachinePrecision]], N[(a * N[Power[k, m], $MachinePrecision]), $MachinePrecision], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -65 \lor \neg \left(m \leq 0.62\right):\\
\;\;\;\;a \cdot {k}^{m}\\

\mathbf{else}:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < -65 or 0.619999999999999996 < m

    1. Initial program 85.1%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/85.1%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+85.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative85.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out85.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def85.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative85.1%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified85.1%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in k around 0 56.1%

      \[\leadsto \color{blue}{e^{\log k \cdot m} \cdot a} \]
    5. Step-by-step derivation
      1. exp-to-pow100.0%

        \[\leadsto \color{blue}{{k}^{m}} \cdot a \]
      2. *-commutative100.0%

        \[\leadsto \color{blue}{a \cdot {k}^{m}} \]
    6. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot {k}^{m}} \]

    if -65 < m < 0.619999999999999996

    1. Initial program 96.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/96.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified96.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 95.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -65 \lor \neg \left(m \leq 0.62\right):\\ \;\;\;\;a \cdot {k}^{m}\\ \mathbf{else}:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \end{array} \]

Alternative 3: 62.5% accurate, 8.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -65:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 2.15:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot \left(k \cdot 100\right)\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -65.0)
   (/ a (* k k))
   (if (<= m 2.15) (/ a (+ 1.0 (* k k))) (+ a (* a (* k (* k 100.0)))))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -65.0) {
		tmp = a / (k * k);
	} else if (m <= 2.15) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = a + (a * (k * (k * 100.0)));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-65.0d0)) then
        tmp = a / (k * k)
    else if (m <= 2.15d0) then
        tmp = a / (1.0d0 + (k * k))
    else
        tmp = a + (a * (k * (k * 100.0d0)))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -65.0) {
		tmp = a / (k * k);
	} else if (m <= 2.15) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = a + (a * (k * (k * 100.0)));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -65.0:
		tmp = a / (k * k)
	elif m <= 2.15:
		tmp = a / (1.0 + (k * k))
	else:
		tmp = a + (a * (k * (k * 100.0)))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -65.0)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 2.15)
		tmp = Float64(a / Float64(1.0 + Float64(k * k)));
	else
		tmp = Float64(a + Float64(a * Float64(k * Float64(k * 100.0))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -65.0)
		tmp = a / (k * k);
	elseif (m <= 2.15)
		tmp = a / (1.0 + (k * k));
	else
		tmp = a + (a * (k * (k * 100.0)));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -65.0], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 2.15], N[(a / N[(1.0 + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a + N[(a * N[(k * N[(k * 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -65:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 2.15:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;a + a \cdot \left(k \cdot \left(k \cdot 100\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -65

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 39.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -65 < m < 2.14999999999999991

    1. Initial program 96.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/96.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified96.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 95.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 93.4%

      \[\leadsto \frac{a}{1 + \color{blue}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow293.4%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]
    7. Simplified93.4%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]

    if 2.14999999999999991 < m

    1. Initial program 73.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/73.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified73.5%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.7%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 2.5%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative2.5%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified2.5%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around 0 28.8%

      \[\leadsto \color{blue}{a + \left(-10 \cdot \left(k \cdot a\right) + 100 \cdot \left({k}^{2} \cdot a\right)\right)} \]
    9. Step-by-step derivation
      1. +-commutative28.8%

        \[\leadsto a + \color{blue}{\left(100 \cdot \left({k}^{2} \cdot a\right) + -10 \cdot \left(k \cdot a\right)\right)} \]
      2. unpow228.8%

        \[\leadsto a + \left(100 \cdot \left(\color{blue}{\left(k \cdot k\right)} \cdot a\right) + -10 \cdot \left(k \cdot a\right)\right) \]
      3. associate-*r*28.8%

        \[\leadsto a + \left(\color{blue}{\left(100 \cdot \left(k \cdot k\right)\right) \cdot a} + -10 \cdot \left(k \cdot a\right)\right) \]
      4. *-commutative28.8%

        \[\leadsto a + \left(\color{blue}{\left(\left(k \cdot k\right) \cdot 100\right)} \cdot a + -10 \cdot \left(k \cdot a\right)\right) \]
      5. associate-*r*27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \color{blue}{\left(-10 \cdot k\right) \cdot a}\right) \]
      6. *-commutative27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \color{blue}{\left(k \cdot -10\right)} \cdot a\right) \]
      7. metadata-eval27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \left(k \cdot \color{blue}{\left(-10\right)}\right) \cdot a\right) \]
      8. distribute-rgt-neg-in27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \color{blue}{\left(-k \cdot 10\right)} \cdot a\right) \]
      9. distribute-rgt-out34.8%

        \[\leadsto a + \color{blue}{a \cdot \left(\left(k \cdot k\right) \cdot 100 + \left(-k \cdot 10\right)\right)} \]
      10. associate-*l*34.8%

        \[\leadsto a + a \cdot \left(\color{blue}{k \cdot \left(k \cdot 100\right)} + \left(-k \cdot 10\right)\right) \]
      11. distribute-rgt-neg-in34.8%

        \[\leadsto a + a \cdot \left(k \cdot \left(k \cdot 100\right) + \color{blue}{k \cdot \left(-10\right)}\right) \]
      12. metadata-eval34.8%

        \[\leadsto a + a \cdot \left(k \cdot \left(k \cdot 100\right) + k \cdot \color{blue}{-10}\right) \]
      13. distribute-lft-out36.0%

        \[\leadsto a + a \cdot \color{blue}{\left(k \cdot \left(k \cdot 100 + -10\right)\right)} \]
    10. Simplified36.0%

      \[\leadsto \color{blue}{a + a \cdot \left(k \cdot \left(k \cdot 100 + -10\right)\right)} \]
    11. Taylor expanded in k around inf 36.0%

      \[\leadsto a + \color{blue}{100 \cdot \left({k}^{2} \cdot a\right)} \]
    12. Step-by-step derivation
      1. *-commutative36.0%

        \[\leadsto a + \color{blue}{\left({k}^{2} \cdot a\right) \cdot 100} \]
      2. *-commutative36.0%

        \[\leadsto a + \color{blue}{\left(a \cdot {k}^{2}\right)} \cdot 100 \]
      3. associate-*r*36.0%

        \[\leadsto a + \color{blue}{a \cdot \left({k}^{2} \cdot 100\right)} \]
      4. unpow236.0%

        \[\leadsto a + a \cdot \left(\color{blue}{\left(k \cdot k\right)} \cdot 100\right) \]
      5. associate-*r*36.0%

        \[\leadsto a + a \cdot \color{blue}{\left(k \cdot \left(k \cdot 100\right)\right)} \]
    13. Simplified36.0%

      \[\leadsto a + \color{blue}{a \cdot \left(k \cdot \left(k \cdot 100\right)\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification67.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -65:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 2.15:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot \left(k \cdot 100\right)\right)\\ \end{array} \]

Alternative 4: 63.3% accurate, 8.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -65:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 2.2:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot \left(k \cdot 100\right)\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -65.0)
   (/ a (* k k))
   (if (<= m 2.2)
     (/ a (+ 1.0 (* k (+ k 10.0))))
     (+ a (* a (* k (* k 100.0)))))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -65.0) {
		tmp = a / (k * k);
	} else if (m <= 2.2) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = a + (a * (k * (k * 100.0)));
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-65.0d0)) then
        tmp = a / (k * k)
    else if (m <= 2.2d0) then
        tmp = a / (1.0d0 + (k * (k + 10.0d0)))
    else
        tmp = a + (a * (k * (k * 100.0d0)))
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -65.0) {
		tmp = a / (k * k);
	} else if (m <= 2.2) {
		tmp = a / (1.0 + (k * (k + 10.0)));
	} else {
		tmp = a + (a * (k * (k * 100.0)));
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -65.0:
		tmp = a / (k * k)
	elif m <= 2.2:
		tmp = a / (1.0 + (k * (k + 10.0)))
	else:
		tmp = a + (a * (k * (k * 100.0)))
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -65.0)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 2.2)
		tmp = Float64(a / Float64(1.0 + Float64(k * Float64(k + 10.0))));
	else
		tmp = Float64(a + Float64(a * Float64(k * Float64(k * 100.0))));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -65.0)
		tmp = a / (k * k);
	elseif (m <= 2.2)
		tmp = a / (1.0 + (k * (k + 10.0)));
	else
		tmp = a + (a * (k * (k * 100.0)));
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -65.0], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 2.2], N[(a / N[(1.0 + N[(k * N[(k + 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(a + N[(a * N[(k * N[(k * 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -65:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 2.2:\\
\;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\

\mathbf{else}:\\
\;\;\;\;a + a \cdot \left(k \cdot \left(k \cdot 100\right)\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -65

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 39.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -65 < m < 2.2000000000000002

    1. Initial program 96.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/96.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified96.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 95.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]

    if 2.2000000000000002 < m

    1. Initial program 73.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/73.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified73.5%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.7%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 2.5%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative2.5%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified2.5%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    8. Taylor expanded in k around 0 28.8%

      \[\leadsto \color{blue}{a + \left(-10 \cdot \left(k \cdot a\right) + 100 \cdot \left({k}^{2} \cdot a\right)\right)} \]
    9. Step-by-step derivation
      1. +-commutative28.8%

        \[\leadsto a + \color{blue}{\left(100 \cdot \left({k}^{2} \cdot a\right) + -10 \cdot \left(k \cdot a\right)\right)} \]
      2. unpow228.8%

        \[\leadsto a + \left(100 \cdot \left(\color{blue}{\left(k \cdot k\right)} \cdot a\right) + -10 \cdot \left(k \cdot a\right)\right) \]
      3. associate-*r*28.8%

        \[\leadsto a + \left(\color{blue}{\left(100 \cdot \left(k \cdot k\right)\right) \cdot a} + -10 \cdot \left(k \cdot a\right)\right) \]
      4. *-commutative28.8%

        \[\leadsto a + \left(\color{blue}{\left(\left(k \cdot k\right) \cdot 100\right)} \cdot a + -10 \cdot \left(k \cdot a\right)\right) \]
      5. associate-*r*27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \color{blue}{\left(-10 \cdot k\right) \cdot a}\right) \]
      6. *-commutative27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \color{blue}{\left(k \cdot -10\right)} \cdot a\right) \]
      7. metadata-eval27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \left(k \cdot \color{blue}{\left(-10\right)}\right) \cdot a\right) \]
      8. distribute-rgt-neg-in27.6%

        \[\leadsto a + \left(\left(\left(k \cdot k\right) \cdot 100\right) \cdot a + \color{blue}{\left(-k \cdot 10\right)} \cdot a\right) \]
      9. distribute-rgt-out34.8%

        \[\leadsto a + \color{blue}{a \cdot \left(\left(k \cdot k\right) \cdot 100 + \left(-k \cdot 10\right)\right)} \]
      10. associate-*l*34.8%

        \[\leadsto a + a \cdot \left(\color{blue}{k \cdot \left(k \cdot 100\right)} + \left(-k \cdot 10\right)\right) \]
      11. distribute-rgt-neg-in34.8%

        \[\leadsto a + a \cdot \left(k \cdot \left(k \cdot 100\right) + \color{blue}{k \cdot \left(-10\right)}\right) \]
      12. metadata-eval34.8%

        \[\leadsto a + a \cdot \left(k \cdot \left(k \cdot 100\right) + k \cdot \color{blue}{-10}\right) \]
      13. distribute-lft-out36.0%

        \[\leadsto a + a \cdot \color{blue}{\left(k \cdot \left(k \cdot 100 + -10\right)\right)} \]
    10. Simplified36.0%

      \[\leadsto \color{blue}{a + a \cdot \left(k \cdot \left(k \cdot 100 + -10\right)\right)} \]
    11. Taylor expanded in k around inf 36.0%

      \[\leadsto a + \color{blue}{100 \cdot \left({k}^{2} \cdot a\right)} \]
    12. Step-by-step derivation
      1. *-commutative36.0%

        \[\leadsto a + \color{blue}{\left({k}^{2} \cdot a\right) \cdot 100} \]
      2. *-commutative36.0%

        \[\leadsto a + \color{blue}{\left(a \cdot {k}^{2}\right)} \cdot 100 \]
      3. associate-*r*36.0%

        \[\leadsto a + \color{blue}{a \cdot \left({k}^{2} \cdot 100\right)} \]
      4. unpow236.0%

        \[\leadsto a + a \cdot \left(\color{blue}{\left(k \cdot k\right)} \cdot 100\right) \]
      5. associate-*r*36.0%

        \[\leadsto a + a \cdot \color{blue}{\left(k \cdot \left(k \cdot 100\right)\right)} \]
    13. Simplified36.0%

      \[\leadsto a + \color{blue}{a \cdot \left(k \cdot \left(k \cdot 100\right)\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification68.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -65:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 2.2:\\ \;\;\;\;\frac{a}{1 + k \cdot \left(k + 10\right)}\\ \mathbf{else}:\\ \;\;\;\;a + a \cdot \left(k \cdot \left(k \cdot 100\right)\right)\\ \end{array} \]

Alternative 5: 47.7% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.1:\\ \;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k -4.5e-299)
   (/ a (* k k))
   (if (<= k 0.1) (* a (+ 1.0 (* k -10.0))) (/ (/ a k) k))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= -4.5e-299) {
		tmp = a / (k * k);
	} else if (k <= 0.1) {
		tmp = a * (1.0 + (k * -10.0));
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= (-4.5d-299)) then
        tmp = a / (k * k)
    else if (k <= 0.1d0) then
        tmp = a * (1.0d0 + (k * (-10.0d0)))
    else
        tmp = (a / k) / k
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= -4.5e-299) {
		tmp = a / (k * k);
	} else if (k <= 0.1) {
		tmp = a * (1.0 + (k * -10.0));
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= -4.5e-299:
		tmp = a / (k * k)
	elif k <= 0.1:
		tmp = a * (1.0 + (k * -10.0))
	else:
		tmp = (a / k) / k
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= -4.5e-299)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 0.1)
		tmp = Float64(a * Float64(1.0 + Float64(k * -10.0)));
	else
		tmp = Float64(Float64(a / k) / k);
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= -4.5e-299)
		tmp = a / (k * k);
	elseif (k <= 0.1)
		tmp = a * (1.0 + (k * -10.0));
	else
		tmp = (a / k) / k;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, -4.5e-299], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 0.1], N[(a * N[(1.0 + N[(k * -10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(a / k), $MachinePrecision] / k), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 0.1:\\
\;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < -4.50000000000000003e-299

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 15.3%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 25.3%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow225.3%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified25.3%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -4.50000000000000003e-299 < k < 0.10000000000000001

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.5%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 51.9%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative51.9%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified51.9%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]

    if 0.10000000000000001 < k

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 72.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 71.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow271.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified71.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. *-un-lft-identity71.1%

        \[\leadsto \frac{\color{blue}{1 \cdot a}}{k \cdot k} \]
      2. times-frac71.2%

        \[\leadsto \color{blue}{\frac{1}{k} \cdot \frac{a}{k}} \]
    9. Applied egg-rr71.2%

      \[\leadsto \color{blue}{\frac{1}{k} \cdot \frac{a}{k}} \]
    10. Step-by-step derivation
      1. associate-*l/71.3%

        \[\leadsto \color{blue}{\frac{1 \cdot \frac{a}{k}}{k}} \]
      2. *-un-lft-identity71.3%

        \[\leadsto \frac{\color{blue}{\frac{a}{k}}}{k} \]
    11. Applied egg-rr71.3%

      \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification53.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 0.1:\\ \;\;\;\;a \cdot \left(1 + k \cdot -10\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]

Alternative 6: 47.8% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 10.2:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k -4.5e-299)
   (/ a (* k k))
   (if (<= k 10.2) (/ a (+ 1.0 (* k 10.0))) (/ (/ a k) k))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= -4.5e-299) {
		tmp = a / (k * k);
	} else if (k <= 10.2) {
		tmp = a / (1.0 + (k * 10.0));
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= (-4.5d-299)) then
        tmp = a / (k * k)
    else if (k <= 10.2d0) then
        tmp = a / (1.0d0 + (k * 10.0d0))
    else
        tmp = (a / k) / k
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= -4.5e-299) {
		tmp = a / (k * k);
	} else if (k <= 10.2) {
		tmp = a / (1.0 + (k * 10.0));
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= -4.5e-299:
		tmp = a / (k * k)
	elif k <= 10.2:
		tmp = a / (1.0 + (k * 10.0))
	else:
		tmp = (a / k) / k
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= -4.5e-299)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 10.2)
		tmp = Float64(a / Float64(1.0 + Float64(k * 10.0)));
	else
		tmp = Float64(Float64(a / k) / k);
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= -4.5e-299)
		tmp = a / (k * k);
	elseif (k <= 10.2)
		tmp = a / (1.0 + (k * 10.0));
	else
		tmp = (a / k) / k;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, -4.5e-299], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 10.2], N[(a / N[(1.0 + N[(k * 10.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(a / k), $MachinePrecision] / k), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 10.2:\\
\;\;\;\;\frac{a}{1 + k \cdot 10}\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < -4.50000000000000003e-299

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 15.3%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 25.3%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow225.3%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified25.3%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -4.50000000000000003e-299 < k < 10.199999999999999

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 52.0%

      \[\leadsto \frac{a}{1 + \color{blue}{10 \cdot k}} \]
    6. Step-by-step derivation
      1. *-commutative52.0%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]
    7. Simplified52.0%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot 10}} \]

    if 10.199999999999999 < k

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 72.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 71.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow271.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified71.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. *-un-lft-identity71.1%

        \[\leadsto \frac{\color{blue}{1 \cdot a}}{k \cdot k} \]
      2. times-frac71.2%

        \[\leadsto \color{blue}{\frac{1}{k} \cdot \frac{a}{k}} \]
    9. Applied egg-rr71.2%

      \[\leadsto \color{blue}{\frac{1}{k} \cdot \frac{a}{k}} \]
    10. Step-by-step derivation
      1. associate-*l/71.3%

        \[\leadsto \color{blue}{\frac{1 \cdot \frac{a}{k}}{k}} \]
      2. *-un-lft-identity71.3%

        \[\leadsto \frac{\color{blue}{\frac{a}{k}}}{k} \]
    11. Applied egg-rr71.3%

      \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification53.1%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 10.2:\\ \;\;\;\;\frac{a}{1 + k \cdot 10}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]

Alternative 7: 57.8% accurate, 10.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq -65:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1950:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= m -65.0)
   (/ a (* k k))
   (if (<= m 1950.0) (/ a (+ 1.0 (* k k))) (* -10.0 (* a k)))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= -65.0) {
		tmp = a / (k * k);
	} else if (m <= 1950.0) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= (-65.0d0)) then
        tmp = a / (k * k)
    else if (m <= 1950.0d0) then
        tmp = a / (1.0d0 + (k * k))
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= -65.0) {
		tmp = a / (k * k);
	} else if (m <= 1950.0) {
		tmp = a / (1.0 + (k * k));
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= -65.0:
		tmp = a / (k * k)
	elif m <= 1950.0:
		tmp = a / (1.0 + (k * k))
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= -65.0)
		tmp = Float64(a / Float64(k * k));
	elseif (m <= 1950.0)
		tmp = Float64(a / Float64(1.0 + Float64(k * k)));
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= -65.0)
		tmp = a / (k * k);
	elseif (m <= 1950.0)
		tmp = a / (1.0 + (k * k));
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, -65.0], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[m, 1950.0], N[(a / N[(1.0 + N[(k * k), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq -65:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;m \leq 1950:\\
\;\;\;\;\frac{a}{1 + k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if m < -65

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 39.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 63.0%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow263.0%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified63.0%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -65 < m < 1950

    1. Initial program 96.2%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/96.2%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative96.2%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified96.2%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 95.6%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 93.4%

      \[\leadsto \frac{a}{1 + \color{blue}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow293.4%

        \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]
    7. Simplified93.4%

      \[\leadsto \frac{a}{1 + \color{blue}{k \cdot k}} \]

    if 1950 < m

    1. Initial program 73.5%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/73.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative73.5%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified73.5%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.7%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 9.8%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative9.8%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified9.8%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.0%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification61.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq -65:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;m \leq 1950:\\ \;\;\;\;\frac{a}{1 + k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 8: 46.4% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299} \lor \neg \left(k \leq 1\right):\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (or (<= k -4.5e-299) (not (<= k 1.0))) (/ a (* k k)) a))
double code(double a, double k, double m) {
	double tmp;
	if ((k <= -4.5e-299) || !(k <= 1.0)) {
		tmp = a / (k * k);
	} else {
		tmp = a;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if ((k <= (-4.5d-299)) .or. (.not. (k <= 1.0d0))) then
        tmp = a / (k * k)
    else
        tmp = a
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if ((k <= -4.5e-299) || !(k <= 1.0)) {
		tmp = a / (k * k);
	} else {
		tmp = a;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if (k <= -4.5e-299) or not (k <= 1.0):
		tmp = a / (k * k)
	else:
		tmp = a
	return tmp
function code(a, k, m)
	tmp = 0.0
	if ((k <= -4.5e-299) || !(k <= 1.0))
		tmp = Float64(a / Float64(k * k));
	else
		tmp = a;
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if ((k <= -4.5e-299) || ~((k <= 1.0)))
		tmp = a / (k * k);
	else
		tmp = a;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[Or[LessEqual[k, -4.5e-299], N[Not[LessEqual[k, 1.0]], $MachinePrecision]], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], a]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq -4.5 \cdot 10^{-299} \lor \neg \left(k \leq 1\right):\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{else}:\\
\;\;\;\;a\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if k < -4.50000000000000003e-299 or 1 < k

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 50.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 53.5%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow253.5%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified53.5%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -4.50000000000000003e-299 < k < 1

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 51.4%

      \[\leadsto \color{blue}{a} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification52.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299} \lor \neg \left(k \leq 1\right):\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{else}:\\ \;\;\;\;a\\ \end{array} \]

Alternative 9: 47.6% accurate, 12.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 1:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \end{array} \]
(FPCore (a k m)
 :precision binary64
 (if (<= k -4.5e-299) (/ a (* k k)) (if (<= k 1.0) a (/ (/ a k) k))))
double code(double a, double k, double m) {
	double tmp;
	if (k <= -4.5e-299) {
		tmp = a / (k * k);
	} else if (k <= 1.0) {
		tmp = a;
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (k <= (-4.5d-299)) then
        tmp = a / (k * k)
    else if (k <= 1.0d0) then
        tmp = a
    else
        tmp = (a / k) / k
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (k <= -4.5e-299) {
		tmp = a / (k * k);
	} else if (k <= 1.0) {
		tmp = a;
	} else {
		tmp = (a / k) / k;
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if k <= -4.5e-299:
		tmp = a / (k * k)
	elif k <= 1.0:
		tmp = a
	else:
		tmp = (a / k) / k
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (k <= -4.5e-299)
		tmp = Float64(a / Float64(k * k));
	elseif (k <= 1.0)
		tmp = a;
	else
		tmp = Float64(Float64(a / k) / k);
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (k <= -4.5e-299)
		tmp = a / (k * k);
	elseif (k <= 1.0)
		tmp = a;
	else
		tmp = (a / k) / k;
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[k, -4.5e-299], N[(a / N[(k * k), $MachinePrecision]), $MachinePrecision], If[LessEqual[k, 1.0], a, N[(N[(a / k), $MachinePrecision] / k), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\
\;\;\;\;\frac{a}{k \cdot k}\\

\mathbf{elif}\;k \leq 1:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;\frac{\frac{a}{k}}{k}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if k < -4.50000000000000003e-299

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 15.3%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 25.3%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow225.3%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified25.3%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]

    if -4.50000000000000003e-299 < k < 1

    1. Initial program 100.0%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/100.0%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative100.0%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 52.5%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 51.4%

      \[\leadsto \color{blue}{a} \]

    if 1 < k

    1. Initial program 84.4%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/84.4%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative84.4%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified84.4%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 72.4%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around inf 71.1%

      \[\leadsto \color{blue}{\frac{a}{{k}^{2}}} \]
    6. Step-by-step derivation
      1. unpow271.1%

        \[\leadsto \frac{a}{\color{blue}{k \cdot k}} \]
    7. Simplified71.1%

      \[\leadsto \color{blue}{\frac{a}{k \cdot k}} \]
    8. Step-by-step derivation
      1. *-un-lft-identity71.1%

        \[\leadsto \frac{\color{blue}{1 \cdot a}}{k \cdot k} \]
      2. times-frac71.2%

        \[\leadsto \color{blue}{\frac{1}{k} \cdot \frac{a}{k}} \]
    9. Applied egg-rr71.2%

      \[\leadsto \color{blue}{\frac{1}{k} \cdot \frac{a}{k}} \]
    10. Step-by-step derivation
      1. associate-*l/71.3%

        \[\leadsto \color{blue}{\frac{1 \cdot \frac{a}{k}}{k}} \]
      2. *-un-lft-identity71.3%

        \[\leadsto \frac{\color{blue}{\frac{a}{k}}}{k} \]
    11. Applied egg-rr71.3%

      \[\leadsto \color{blue}{\frac{\frac{a}{k}}{k}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification52.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;k \leq -4.5 \cdot 10^{-299}:\\ \;\;\;\;\frac{a}{k \cdot k}\\ \mathbf{elif}\;k \leq 1:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{a}{k}}{k}\\ \end{array} \]

Alternative 10: 25.5% accurate, 16.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;m \leq 1.25 \cdot 10^{+22}:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \end{array} \]
(FPCore (a k m) :precision binary64 (if (<= m 1.25e+22) a (* -10.0 (* a k))))
double code(double a, double k, double m) {
	double tmp;
	if (m <= 1.25e+22) {
		tmp = a;
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    real(8) :: tmp
    if (m <= 1.25d+22) then
        tmp = a
    else
        tmp = (-10.0d0) * (a * k)
    end if
    code = tmp
end function
public static double code(double a, double k, double m) {
	double tmp;
	if (m <= 1.25e+22) {
		tmp = a;
	} else {
		tmp = -10.0 * (a * k);
	}
	return tmp;
}
def code(a, k, m):
	tmp = 0
	if m <= 1.25e+22:
		tmp = a
	else:
		tmp = -10.0 * (a * k)
	return tmp
function code(a, k, m)
	tmp = 0.0
	if (m <= 1.25e+22)
		tmp = a;
	else
		tmp = Float64(-10.0 * Float64(a * k));
	end
	return tmp
end
function tmp_2 = code(a, k, m)
	tmp = 0.0;
	if (m <= 1.25e+22)
		tmp = a;
	else
		tmp = -10.0 * (a * k);
	end
	tmp_2 = tmp;
end
code[a_, k_, m_] := If[LessEqual[m, 1.25e+22], a, N[(-10.0 * N[(a * k), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;m \leq 1.25 \cdot 10^{+22}:\\
\;\;\;\;a\\

\mathbf{else}:\\
\;\;\;\;-10 \cdot \left(a \cdot k\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if m < 1.2499999999999999e22

    1. Initial program 96.6%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/96.5%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+96.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative96.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out96.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def96.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative96.6%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified96.6%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 72.9%

      \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 28.1%

      \[\leadsto \color{blue}{a} \]

    if 1.2499999999999999e22 < m

    1. Initial program 74.7%

      \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
    2. Step-by-step derivation
      1. associate-*r/74.7%

        \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
      2. associate-+l+74.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
      3. +-commutative74.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
      4. distribute-rgt-out74.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
      5. fma-def74.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
      6. +-commutative74.7%

        \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
    3. Simplified74.7%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
    4. Taylor expanded in m around 0 2.7%

      \[\leadsto a \cdot \color{blue}{\frac{1}{1 + k \cdot \left(k + 10\right)}} \]
    5. Taylor expanded in k around 0 10.2%

      \[\leadsto a \cdot \color{blue}{\left(1 + -10 \cdot k\right)} \]
    6. Step-by-step derivation
      1. *-commutative10.2%

        \[\leadsto a \cdot \left(1 + \color{blue}{k \cdot -10}\right) \]
    7. Simplified10.2%

      \[\leadsto a \cdot \color{blue}{\left(1 + k \cdot -10\right)} \]
    8. Taylor expanded in k around inf 19.8%

      \[\leadsto \color{blue}{-10 \cdot \left(k \cdot a\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification25.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;m \leq 1.25 \cdot 10^{+22}:\\ \;\;\;\;a\\ \mathbf{else}:\\ \;\;\;\;-10 \cdot \left(a \cdot k\right)\\ \end{array} \]

Alternative 11: 20.1% accurate, 114.0× speedup?

\[\begin{array}{l} \\ a \end{array} \]
(FPCore (a k m) :precision binary64 a)
double code(double a, double k, double m) {
	return a;
}
real(8) function code(a, k, m)
    real(8), intent (in) :: a
    real(8), intent (in) :: k
    real(8), intent (in) :: m
    code = a
end function
public static double code(double a, double k, double m) {
	return a;
}
def code(a, k, m):
	return a
function code(a, k, m)
	return a
end
function tmp = code(a, k, m)
	tmp = a;
end
code[a_, k_, m_] := a
\begin{array}{l}

\\
a
\end{array}
Derivation
  1. Initial program 89.8%

    \[\frac{a \cdot {k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k} \]
  2. Step-by-step derivation
    1. associate-*r/89.8%

      \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\left(1 + 10 \cdot k\right) + k \cdot k}} \]
    2. associate-+l+89.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{1 + \left(10 \cdot k + k \cdot k\right)}} \]
    3. +-commutative89.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\left(10 \cdot k + k \cdot k\right) + 1}} \]
    4. distribute-rgt-out89.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{k \cdot \left(10 + k\right)} + 1} \]
    5. fma-def89.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\color{blue}{\mathsf{fma}\left(k, 10 + k, 1\right)}} \]
    6. +-commutative89.8%

      \[\leadsto a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, \color{blue}{k + 10}, 1\right)} \]
  3. Simplified89.8%

    \[\leadsto \color{blue}{a \cdot \frac{{k}^{m}}{\mathsf{fma}\left(k, k + 10, 1\right)}} \]
  4. Taylor expanded in m around 0 51.2%

    \[\leadsto \color{blue}{\frac{a}{1 + k \cdot \left(k + 10\right)}} \]
  5. Taylor expanded in k around 0 20.5%

    \[\leadsto \color{blue}{a} \]
  6. Final simplification20.5%

    \[\leadsto a \]

Reproduce

?
herbie shell --seed 2023202 
(FPCore (a k m)
  :name "Falkner and Boettcher, Appendix A"
  :precision binary64
  (/ (* a (pow k m)) (+ (+ 1.0 (* 10.0 k)) (* k k))))