2-ancestry mixing, positive discriminant

Percentage Accurate: 43.5% → 46.1%
Time: 9.0s
Alternatives: 7
Speedup: 1.3×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 43.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)}
\end{array}
\end{array}

Alternative 1: 46.1% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\ \mathbf{if}\;h \cdot h \leq 0:\\ \;\;\;\;\sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)}\\ \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (sqrt (* (+ h g) (- g h)))))
   (if (<= (* h h) 0.0)
     (+
      (cbrt (* (- g t_0) (/ -0.5 a)))
      (* (cbrt (/ -0.5 a)) (cbrt (+ g (hypot g (sqrt (* h (- h))))))))
     (+
      (cbrt (* (/ -0.5 a) (- g (sqrt (- (* g g) (* h h))))))
      (cbrt (* (/ -0.5 a) (+ g t_0)))))))
double code(double g, double h, double a) {
	double t_0 = sqrt(((h + g) * (g - h)));
	double tmp;
	if ((h * h) <= 0.0) {
		tmp = cbrt(((g - t_0) * (-0.5 / a))) + (cbrt((-0.5 / a)) * cbrt((g + hypot(g, sqrt((h * -h))))));
	} else {
		tmp = cbrt(((-0.5 / a) * (g - sqrt(((g * g) - (h * h)))))) + cbrt(((-0.5 / a) * (g + t_0)));
	}
	return tmp;
}
public static double code(double g, double h, double a) {
	double t_0 = Math.sqrt(((h + g) * (g - h)));
	double tmp;
	if ((h * h) <= 0.0) {
		tmp = Math.cbrt(((g - t_0) * (-0.5 / a))) + (Math.cbrt((-0.5 / a)) * Math.cbrt((g + Math.hypot(g, Math.sqrt((h * -h))))));
	} else {
		tmp = Math.cbrt(((-0.5 / a) * (g - Math.sqrt(((g * g) - (h * h)))))) + Math.cbrt(((-0.5 / a) * (g + t_0)));
	}
	return tmp;
}
function code(g, h, a)
	t_0 = sqrt(Float64(Float64(h + g) * Float64(g - h)))
	tmp = 0.0
	if (Float64(h * h) <= 0.0)
		tmp = Float64(cbrt(Float64(Float64(g - t_0) * Float64(-0.5 / a))) + Float64(cbrt(Float64(-0.5 / a)) * cbrt(Float64(g + hypot(g, sqrt(Float64(h * Float64(-h))))))));
	else
		tmp = Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g - sqrt(Float64(Float64(g * g) - Float64(h * h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + t_0))));
	end
	return tmp
end
code[g_, h_, a_] := Block[{t$95$0 = N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(h * h), $MachinePrecision], 0.0], N[(N[Power[N[(N[(g - t$95$0), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[(N[Power[N[(-0.5 / a), $MachinePrecision], 1/3], $MachinePrecision] * N[Power[N[(g + N[Sqrt[g ^ 2 + N[Sqrt[N[(h * (-h)), $MachinePrecision]], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + t$95$0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\
\mathbf{if}\;h \cdot h \leq 0:\\
\;\;\;\;\sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)}\\

\mathbf{else}:\\
\;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 h h) < 0.0

    1. Initial program 47.5%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Step-by-step derivation
      1. Simplified47.5%

        \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
      2. Step-by-step derivation
        1. cbrt-prod52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\sqrt[3]{g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}} \cdot \sqrt[3]{\frac{-0.5}{a}}} \]
        2. difference-of-squares52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{\color{blue}{g \cdot g - h \cdot h}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        3. fma-neg52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{\color{blue}{\mathsf{fma}\left(g, g, -h \cdot h\right)}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        4. fma-neg52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{\color{blue}{g \cdot g - h \cdot h}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        5. difference-of-squares52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{\color{blue}{\left(g + h\right) \cdot \left(g - h\right)}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        6. difference-of-squares52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{\color{blue}{g \cdot g - h \cdot h}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        7. sub-neg52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{\color{blue}{g \cdot g + \left(-h \cdot h\right)}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        8. add-sqr-sqrt52.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \sqrt{g \cdot g + \color{blue}{\sqrt{-h \cdot h} \cdot \sqrt{-h \cdot h}}}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        9. hypot-def53.5%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \color{blue}{\mathsf{hypot}\left(g, \sqrt{-h \cdot h}\right)}} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
        10. distribute-rgt-neg-in53.5%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{\color{blue}{h \cdot \left(-h\right)}}\right)} \cdot \sqrt[3]{\frac{-0.5}{a}} \]
      3. Applied egg-rr53.5%

        \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)} \cdot \sqrt[3]{\frac{-0.5}{a}}} \]
      4. Step-by-step derivation
        1. *-commutative53.5%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)}} \]
      5. Simplified53.5%

        \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)}} \]

      if 0.0 < (*.f64 h h)

      1. Initial program 39.5%

        \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
      2. Step-by-step derivation
        1. Simplified39.5%

          \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
        2. Step-by-step derivation
          1. pow1/239.5%

            \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(\left(g + h\right) \cdot \left(g - h\right)\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          2. difference-of-squares39.5%

            \[\leadsto \sqrt[3]{\left(g - {\color{blue}{\left(g \cdot g - h \cdot h\right)}}^{0.5}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
        3. Applied egg-rr39.5%

          \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(g \cdot g - h \cdot h\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
        4. Step-by-step derivation
          1. unpow1/239.5%

            \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
        5. Simplified39.5%

          \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
      3. Recombined 2 regimes into one program.
      4. Final simplification45.3%

        \[\leadsto \begin{array}{l} \mathbf{if}\;h \cdot h \leq 0:\\ \;\;\;\;\sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a}} \cdot \sqrt[3]{g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)}\\ \end{array} \]

      Alternative 2: 43.5% accurate, 1.0× speedup?

      \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\ \sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)} \end{array} \end{array} \]
      (FPCore (g h a)
       :precision binary64
       (let* ((t_0 (sqrt (* (+ h g) (- g h)))))
         (+ (cbrt (* (- g t_0) (/ -0.5 a))) (cbrt (* (/ -0.5 a) (+ g t_0))))))
      double code(double g, double h, double a) {
      	double t_0 = sqrt(((h + g) * (g - h)));
      	return cbrt(((g - t_0) * (-0.5 / a))) + cbrt(((-0.5 / a) * (g + t_0)));
      }
      
      public static double code(double g, double h, double a) {
      	double t_0 = Math.sqrt(((h + g) * (g - h)));
      	return Math.cbrt(((g - t_0) * (-0.5 / a))) + Math.cbrt(((-0.5 / a) * (g + t_0)));
      }
      
      function code(g, h, a)
      	t_0 = sqrt(Float64(Float64(h + g) * Float64(g - h)))
      	return Float64(cbrt(Float64(Float64(g - t_0) * Float64(-0.5 / a))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + t_0))))
      end
      
      code[g_, h_, a_] := Block[{t$95$0 = N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(N[(g - t$95$0), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + t$95$0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]
      
      \begin{array}{l}
      
      \\
      \begin{array}{l}
      t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\
      \sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)}
      \end{array}
      \end{array}
      
      Derivation
      1. Initial program 42.8%

        \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
      2. Step-by-step derivation
        1. Simplified42.8%

          \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
        2. Final simplification42.8%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} \]

        Alternative 3: 43.5% accurate, 1.0× speedup?

        \[\begin{array}{l} \\ \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} \end{array} \]
        (FPCore (g h a)
         :precision binary64
         (+
          (cbrt (* (/ -0.5 a) (- g (sqrt (- (* g g) (* h h))))))
          (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))))
        double code(double g, double h, double a) {
        	return cbrt(((-0.5 / a) * (g - sqrt(((g * g) - (h * h)))))) + cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h))))));
        }
        
        public static double code(double g, double h, double a) {
        	return Math.cbrt(((-0.5 / a) * (g - Math.sqrt(((g * g) - (h * h)))))) + Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h))))));
        }
        
        function code(g, h, a)
        	return Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g - sqrt(Float64(Float64(g * g) - Float64(h * h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))))
        end
        
        code[g_, h_, a_] := N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
        
        \begin{array}{l}
        
        \\
        \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)}
        \end{array}
        
        Derivation
        1. Initial program 42.8%

          \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        2. Step-by-step derivation
          1. Simplified42.8%

            \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
          2. Step-by-step derivation
            1. pow1/242.8%

              \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(\left(g + h\right) \cdot \left(g - h\right)\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            2. difference-of-squares42.8%

              \[\leadsto \sqrt[3]{\left(g - {\color{blue}{\left(g \cdot g - h \cdot h\right)}}^{0.5}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          3. Applied egg-rr42.8%

            \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(g \cdot g - h \cdot h\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          4. Step-by-step derivation
            1. unpow1/242.8%

              \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          5. Simplified42.8%

            \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          6. Final simplification42.8%

            \[\leadsto \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} \]

          Alternative 4: 44.6% accurate, 1.3× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\ \mathbf{if}\;g \leq -1.58 \cdot 10^{-162}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(g \cdot -2\right)} + t_0\\ \mathbf{else}:\\ \;\;\;\;t_0 + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{h \cdot h}{g}\right)}\\ \end{array} \end{array} \]
          (FPCore (g h a)
           :precision binary64
           (let* ((t_0 (cbrt (* (/ 0.5 a) (- (- g) (sqrt (- (* g g) (* h h))))))))
             (if (<= g -1.58e-162)
               (+ (cbrt (* (/ 0.5 a) (* g -2.0))) t_0)
               (+ t_0 (cbrt (* (/ 0.5 a) (* -0.5 (/ (* h h) g))))))))
          double code(double g, double h, double a) {
          	double t_0 = cbrt(((0.5 / a) * (-g - sqrt(((g * g) - (h * h))))));
          	double tmp;
          	if (g <= -1.58e-162) {
          		tmp = cbrt(((0.5 / a) * (g * -2.0))) + t_0;
          	} else {
          		tmp = t_0 + cbrt(((0.5 / a) * (-0.5 * ((h * h) / g))));
          	}
          	return tmp;
          }
          
          public static double code(double g, double h, double a) {
          	double t_0 = Math.cbrt(((0.5 / a) * (-g - Math.sqrt(((g * g) - (h * h))))));
          	double tmp;
          	if (g <= -1.58e-162) {
          		tmp = Math.cbrt(((0.5 / a) * (g * -2.0))) + t_0;
          	} else {
          		tmp = t_0 + Math.cbrt(((0.5 / a) * (-0.5 * ((h * h) / g))));
          	}
          	return tmp;
          }
          
          function code(g, h, a)
          	t_0 = cbrt(Float64(Float64(0.5 / a) * Float64(Float64(-g) - sqrt(Float64(Float64(g * g) - Float64(h * h))))))
          	tmp = 0.0
          	if (g <= -1.58e-162)
          		tmp = Float64(cbrt(Float64(Float64(0.5 / a) * Float64(g * -2.0))) + t_0);
          	else
          		tmp = Float64(t_0 + cbrt(Float64(Float64(0.5 / a) * Float64(-0.5 * Float64(Float64(h * h) / g)))));
          	end
          	return tmp
          end
          
          code[g_, h_, a_] := Block[{t$95$0 = N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[((-g) - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]}, If[LessEqual[g, -1.58e-162], N[(N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(g * -2.0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + t$95$0), $MachinePrecision], N[(t$95$0 + N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(-0.5 * N[(N[(h * h), $MachinePrecision] / g), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          t_0 := \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\
          \mathbf{if}\;g \leq -1.58 \cdot 10^{-162}:\\
          \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(g \cdot -2\right)} + t_0\\
          
          \mathbf{else}:\\
          \;\;\;\;t_0 + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{h \cdot h}{g}\right)}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if g < -1.5800000000000001e-162

            1. Initial program 46.2%

              \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            2. Step-by-step derivation
              1. associate-/r*46.2%

                \[\leadsto \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              2. metadata-eval46.2%

                \[\leadsto \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              3. +-commutative46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} + \left(-g\right)\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              4. unsub-neg46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} - g\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              5. associate-/r*46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              6. metadata-eval46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            3. Simplified46.2%

              \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
            4. Taylor expanded in g around -inf 45.1%

              \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-2 \cdot g\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            5. Step-by-step derivation
              1. *-commutative45.1%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(g \cdot -2\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            6. Simplified45.1%

              \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(g \cdot -2\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]

            if -1.5800000000000001e-162 < g

            1. Initial program 40.1%

              \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            2. Step-by-step derivation
              1. associate-/r*40.1%

                \[\leadsto \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              2. metadata-eval40.1%

                \[\leadsto \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              3. +-commutative40.1%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} + \left(-g\right)\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              4. unsub-neg40.1%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} - g\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              5. associate-/r*40.1%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              6. metadata-eval40.1%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            3. Simplified40.1%

              \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
            4. Taylor expanded in g around inf 42.0%

              \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-0.5 \cdot \frac{{h}^{2}}{g}\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            5. Step-by-step derivation
              1. unpow242.0%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{\color{blue}{h \cdot h}}{g}\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            6. Simplified42.0%

              \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-0.5 \cdot \frac{h \cdot h}{g}\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
          3. Recombined 2 regimes into one program.
          4. Final simplification43.4%

            \[\leadsto \begin{array}{l} \mathbf{if}\;g \leq -1.58 \cdot 10^{-162}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(g \cdot -2\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{h \cdot h}{g}\right)}\\ \end{array} \]

          Alternative 5: 44.2% accurate, 1.3× speedup?

          \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;g \leq -1.58 \cdot 10^{-162}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(g \cdot -2\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{0 \cdot \frac{-0.5}{a}}\\ \end{array} \end{array} \]
          (FPCore (g h a)
           :precision binary64
           (if (<= g -1.58e-162)
             (+
              (cbrt (* (/ 0.5 a) (* g -2.0)))
              (cbrt (* (/ 0.5 a) (- (- g) (sqrt (- (* g g) (* h h)))))))
             (+
              (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))
              (cbrt (* 0.0 (/ -0.5 a))))))
          double code(double g, double h, double a) {
          	double tmp;
          	if (g <= -1.58e-162) {
          		tmp = cbrt(((0.5 / a) * (g * -2.0))) + cbrt(((0.5 / a) * (-g - sqrt(((g * g) - (h * h))))));
          	} else {
          		tmp = cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h)))))) + cbrt((0.0 * (-0.5 / a)));
          	}
          	return tmp;
          }
          
          public static double code(double g, double h, double a) {
          	double tmp;
          	if (g <= -1.58e-162) {
          		tmp = Math.cbrt(((0.5 / a) * (g * -2.0))) + Math.cbrt(((0.5 / a) * (-g - Math.sqrt(((g * g) - (h * h))))));
          	} else {
          		tmp = Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h)))))) + Math.cbrt((0.0 * (-0.5 / a)));
          	}
          	return tmp;
          }
          
          function code(g, h, a)
          	tmp = 0.0
          	if (g <= -1.58e-162)
          		tmp = Float64(cbrt(Float64(Float64(0.5 / a) * Float64(g * -2.0))) + cbrt(Float64(Float64(0.5 / a) * Float64(Float64(-g) - sqrt(Float64(Float64(g * g) - Float64(h * h)))))));
          	else
          		tmp = Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))) + cbrt(Float64(0.0 * Float64(-0.5 / a))));
          	end
          	return tmp
          end
          
          code[g_, h_, a_] := If[LessEqual[g, -1.58e-162], N[(N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(g * -2.0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[((-g) - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(0.0 * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]
          
          \begin{array}{l}
          
          \\
          \begin{array}{l}
          \mathbf{if}\;g \leq -1.58 \cdot 10^{-162}:\\
          \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(g \cdot -2\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\
          
          \mathbf{else}:\\
          \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{0 \cdot \frac{-0.5}{a}}\\
          
          
          \end{array}
          \end{array}
          
          Derivation
          1. Split input into 2 regimes
          2. if g < -1.5800000000000001e-162

            1. Initial program 46.2%

              \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            2. Step-by-step derivation
              1. associate-/r*46.2%

                \[\leadsto \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              2. metadata-eval46.2%

                \[\leadsto \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              3. +-commutative46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} + \left(-g\right)\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              4. unsub-neg46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} - g\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              5. associate-/r*46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              6. metadata-eval46.2%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            3. Simplified46.2%

              \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
            4. Taylor expanded in g around -inf 45.1%

              \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-2 \cdot g\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            5. Step-by-step derivation
              1. *-commutative45.1%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(g \cdot -2\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            6. Simplified45.1%

              \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(g \cdot -2\right)}} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]

            if -1.5800000000000001e-162 < g

            1. Initial program 40.1%

              \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            2. Step-by-step derivation
              1. Simplified40.1%

                \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
              2. Taylor expanded in g around inf 41.0%

                \[\leadsto \sqrt[3]{\color{blue}{\left(-0.5 \cdot \left(h + -1 \cdot h\right)\right)} \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
              3. Step-by-step derivation
                1. distribute-rgt1-in41.0%

                  \[\leadsto \sqrt[3]{\left(-0.5 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                2. metadata-eval41.0%

                  \[\leadsto \sqrt[3]{\left(-0.5 \cdot \left(\color{blue}{0} \cdot h\right)\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                3. mul0-lft41.0%

                  \[\leadsto \sqrt[3]{\left(-0.5 \cdot \color{blue}{0}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                4. metadata-eval41.0%

                  \[\leadsto \sqrt[3]{\color{blue}{0} \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
              4. Simplified41.0%

                \[\leadsto \sqrt[3]{\color{blue}{0} \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            3. Recombined 2 regimes into one program.
            4. Final simplification42.9%

              \[\leadsto \begin{array}{l} \mathbf{if}\;g \leq -1.58 \cdot 10^{-162}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(g \cdot -2\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{0 \cdot \frac{-0.5}{a}}\\ \end{array} \]

            Alternative 6: 27.6% accurate, 1.3× speedup?

            \[\begin{array}{l} \\ \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + g\right)} \end{array} \]
            (FPCore (g h a)
             :precision binary64
             (+
              (cbrt (* (- g (sqrt (* (+ h g) (- g h)))) (/ -0.5 a)))
              (cbrt (* (/ -0.5 a) (+ g g)))))
            double code(double g, double h, double a) {
            	return cbrt(((g - sqrt(((h + g) * (g - h)))) * (-0.5 / a))) + cbrt(((-0.5 / a) * (g + g)));
            }
            
            public static double code(double g, double h, double a) {
            	return Math.cbrt(((g - Math.sqrt(((h + g) * (g - h)))) * (-0.5 / a))) + Math.cbrt(((-0.5 / a) * (g + g)));
            }
            
            function code(g, h, a)
            	return Float64(cbrt(Float64(Float64(g - sqrt(Float64(Float64(h + g) * Float64(g - h)))) * Float64(-0.5 / a))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + g))))
            end
            
            code[g_, h_, a_] := N[(N[Power[N[(N[(g - N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
            
            \begin{array}{l}
            
            \\
            \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + g\right)}
            \end{array}
            
            Derivation
            1. Initial program 42.8%

              \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
            2. Step-by-step derivation
              1. Simplified42.8%

                \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
              2. Taylor expanded in g around inf 26.7%

                \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \color{blue}{g}\right) \cdot \frac{-0.5}{a}} \]
              3. Final simplification26.7%

                \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + g\right)} \]

              Alternative 7: 24.3% accurate, 1.4× speedup?

              \[\begin{array}{l} \\ \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{0 \cdot \frac{-0.5}{a}} \end{array} \]
              (FPCore (g h a)
               :precision binary64
               (+
                (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))
                (cbrt (* 0.0 (/ -0.5 a)))))
              double code(double g, double h, double a) {
              	return cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h)))))) + cbrt((0.0 * (-0.5 / a)));
              }
              
              public static double code(double g, double h, double a) {
              	return Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h)))))) + Math.cbrt((0.0 * (-0.5 / a)));
              }
              
              function code(g, h, a)
              	return Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))) + cbrt(Float64(0.0 * Float64(-0.5 / a))))
              end
              
              code[g_, h_, a_] := N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(0.0 * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
              
              \begin{array}{l}
              
              \\
              \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{0 \cdot \frac{-0.5}{a}}
              \end{array}
              
              Derivation
              1. Initial program 42.8%

                \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              2. Step-by-step derivation
                1. Simplified42.8%

                  \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
                2. Taylor expanded in g around inf 23.6%

                  \[\leadsto \sqrt[3]{\color{blue}{\left(-0.5 \cdot \left(h + -1 \cdot h\right)\right)} \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                3. Step-by-step derivation
                  1. distribute-rgt1-in23.6%

                    \[\leadsto \sqrt[3]{\left(-0.5 \cdot \color{blue}{\left(\left(-1 + 1\right) \cdot h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                  2. metadata-eval23.6%

                    \[\leadsto \sqrt[3]{\left(-0.5 \cdot \left(\color{blue}{0} \cdot h\right)\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                  3. mul0-lft23.6%

                    \[\leadsto \sqrt[3]{\left(-0.5 \cdot \color{blue}{0}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                  4. metadata-eval23.6%

                    \[\leadsto \sqrt[3]{\color{blue}{0} \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                4. Simplified23.6%

                  \[\leadsto \sqrt[3]{\color{blue}{0} \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                5. Final simplification23.6%

                  \[\leadsto \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{0 \cdot \frac{-0.5}{a}} \]

                Reproduce

                ?
                herbie shell --seed 2023192 
                (FPCore (g h a)
                  :name "2-ancestry mixing, positive discriminant"
                  :precision binary64
                  (+ (cbrt (* (/ 1.0 (* 2.0 a)) (+ (- g) (sqrt (- (* g g) (* h h)))))) (cbrt (* (/ 1.0 (* 2.0 a)) (- (- g) (sqrt (- (* g g) (* h h))))))))