2-ancestry mixing, positive discriminant

Percentage Accurate: 44.5% → 46.8%
Time: 8.8s
Alternatives: 8
Speedup: 1.3×

Specification

?
\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)}
\end{array}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 8 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 44.5% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \frac{1}{2 \cdot a}\\ t_1 := \sqrt{g \cdot g - h \cdot h}\\ \sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)} \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (/ 1.0 (* 2.0 a))) (t_1 (sqrt (- (* g g) (* h h)))))
   (+ (cbrt (* t_0 (+ (- g) t_1))) (cbrt (* t_0 (- (- g) t_1))))))
double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = sqrt(((g * g) - (h * h)));
	return cbrt((t_0 * (-g + t_1))) + cbrt((t_0 * (-g - t_1)));
}
public static double code(double g, double h, double a) {
	double t_0 = 1.0 / (2.0 * a);
	double t_1 = Math.sqrt(((g * g) - (h * h)));
	return Math.cbrt((t_0 * (-g + t_1))) + Math.cbrt((t_0 * (-g - t_1)));
}
function code(g, h, a)
	t_0 = Float64(1.0 / Float64(2.0 * a))
	t_1 = sqrt(Float64(Float64(g * g) - Float64(h * h)))
	return Float64(cbrt(Float64(t_0 * Float64(Float64(-g) + t_1))) + cbrt(Float64(t_0 * Float64(Float64(-g) - t_1))))
end
code[g_, h_, a_] := Block[{t$95$0 = N[(1.0 / N[(2.0 * a), $MachinePrecision]), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(t$95$0 * N[((-g) + t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(t$95$0 * N[((-g) - t$95$1), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \frac{1}{2 \cdot a}\\
t_1 := \sqrt{g \cdot g - h \cdot h}\\
\sqrt[3]{t_0 \cdot \left(\left(-g\right) + t_1\right)} + \sqrt[3]{t_0 \cdot \left(\left(-g\right) - t_1\right)}
\end{array}
\end{array}

Alternative 1: 46.8% accurate, 0.7× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := h \cdot \left(-h\right)\\ t_1 := \sqrt{\mathsf{fma}\left(g, g, t_0\right)}\\ \mathbf{if}\;h \cdot h \leq 0:\\ \;\;\;\;\sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{-0.5 \cdot \left(g + \mathsf{hypot}\left(g, \sqrt{t_0}\right)\right)}}{\sqrt[3]{a}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(t_1 - g\right)} + \sqrt[3]{\frac{g + t_1}{\frac{a}{-0.5}}}\\ \end{array} \end{array} \]
(FPCore (g h a)
 :precision binary64
 (let* ((t_0 (* h (- h))) (t_1 (sqrt (fma g g t_0))))
   (if (<= (* h h) 0.0)
     (+
      (cbrt (* (- g (sqrt (* (+ h g) (- g h)))) (/ -0.5 a)))
      (/ (cbrt (* -0.5 (+ g (hypot g (sqrt t_0))))) (cbrt a)))
     (+ (cbrt (* (/ 0.5 a) (- t_1 g))) (cbrt (/ (+ g t_1) (/ a -0.5)))))))
double code(double g, double h, double a) {
	double t_0 = h * -h;
	double t_1 = sqrt(fma(g, g, t_0));
	double tmp;
	if ((h * h) <= 0.0) {
		tmp = cbrt(((g - sqrt(((h + g) * (g - h)))) * (-0.5 / a))) + (cbrt((-0.5 * (g + hypot(g, sqrt(t_0))))) / cbrt(a));
	} else {
		tmp = cbrt(((0.5 / a) * (t_1 - g))) + cbrt(((g + t_1) / (a / -0.5)));
	}
	return tmp;
}
function code(g, h, a)
	t_0 = Float64(h * Float64(-h))
	t_1 = sqrt(fma(g, g, t_0))
	tmp = 0.0
	if (Float64(h * h) <= 0.0)
		tmp = Float64(cbrt(Float64(Float64(g - sqrt(Float64(Float64(h + g) * Float64(g - h)))) * Float64(-0.5 / a))) + Float64(cbrt(Float64(-0.5 * Float64(g + hypot(g, sqrt(t_0))))) / cbrt(a)));
	else
		tmp = Float64(cbrt(Float64(Float64(0.5 / a) * Float64(t_1 - g))) + cbrt(Float64(Float64(g + t_1) / Float64(a / -0.5))));
	end
	return tmp
end
code[g_, h_, a_] := Block[{t$95$0 = N[(h * (-h)), $MachinePrecision]}, Block[{t$95$1 = N[Sqrt[N[(g * g + t$95$0), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(h * h), $MachinePrecision], 0.0], N[(N[Power[N[(N[(g - N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[(N[Power[N[(-0.5 * N[(g + N[Sqrt[g ^ 2 + N[Sqrt[t$95$0], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] / N[Power[a, 1/3], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(t$95$1 - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(g + t$95$1), $MachinePrecision] / N[(a / -0.5), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := h \cdot \left(-h\right)\\
t_1 := \sqrt{\mathsf{fma}\left(g, g, t_0\right)}\\
\mathbf{if}\;h \cdot h \leq 0:\\
\;\;\;\;\sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{-0.5 \cdot \left(g + \mathsf{hypot}\left(g, \sqrt{t_0}\right)\right)}}{\sqrt[3]{a}}\\

\mathbf{else}:\\
\;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(t_1 - g\right)} + \sqrt[3]{\frac{g + t_1}{\frac{a}{-0.5}}}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (*.f64 h h) < 0.0

    1. Initial program 57.0%

      \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
    2. Step-by-step derivation
      1. Simplified57.0%

        \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
      2. Step-by-step derivation
        1. associate-*r/57.0%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\color{blue}{\frac{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot -0.5}{a}}} \]
        2. cbrt-div61.6%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\frac{\sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot -0.5}}{\sqrt[3]{a}}} \]
        3. difference-of-squares61.6%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \sqrt{\color{blue}{g \cdot g - h \cdot h}}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
        4. sub-neg61.6%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \sqrt{\color{blue}{g \cdot g + \left(-h \cdot h\right)}}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
        5. add-sqr-sqrt61.6%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \sqrt{g \cdot g + \color{blue}{\sqrt{-h \cdot h} \cdot \sqrt{-h \cdot h}}}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
        6. hypot-def63.0%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \color{blue}{\mathsf{hypot}\left(g, \sqrt{-h \cdot h}\right)}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
        7. distribute-rgt-neg-in63.0%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \mathsf{hypot}\left(g, \sqrt{\color{blue}{h \cdot \left(-h\right)}}\right)\right) \cdot -0.5}}{\sqrt[3]{a}} \]
      3. Applied egg-rr63.0%

        \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\frac{\sqrt[3]{\left(g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)\right) \cdot -0.5}}{\sqrt[3]{a}}} \]

      if 0.0 < (*.f64 h h)

      1. Initial program 32.6%

        \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
      2. Step-by-step derivation
        1. associate-/r*32.6%

          \[\leadsto \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        2. metadata-eval32.6%

          \[\leadsto \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        3. +-commutative32.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} + \left(-g\right)\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        4. unsub-neg32.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} - g\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        5. fma-neg32.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\color{blue}{\mathsf{fma}\left(g, g, -h \cdot h\right)}} - g\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        6. sub-neg32.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\mathsf{fma}\left(g, g, -h \cdot h\right)} - g\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \color{blue}{\left(\left(-g\right) + \left(-\sqrt{g \cdot g - h \cdot h}\right)\right)}} \]
        7. distribute-neg-out32.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\mathsf{fma}\left(g, g, -h \cdot h\right)} - g\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \color{blue}{\left(-\left(g + \sqrt{g \cdot g - h \cdot h}\right)\right)}} \]
        8. neg-mul-132.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\mathsf{fma}\left(g, g, -h \cdot h\right)} - g\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \color{blue}{\left(-1 \cdot \left(g + \sqrt{g \cdot g - h \cdot h}\right)\right)}} \]
        9. associate-*r*32.6%

          \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\mathsf{fma}\left(g, g, -h \cdot h\right)} - g\right)} + \sqrt[3]{\color{blue}{\left(\frac{1}{2 \cdot a} \cdot -1\right) \cdot \left(g + \sqrt{g \cdot g - h \cdot h}\right)}} \]
      3. Simplified32.6%

        \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\mathsf{fma}\left(g, g, -h \cdot h\right)} - g\right)} + \sqrt[3]{\frac{g + \sqrt{\mathsf{fma}\left(g, g, -h \cdot h\right)}}{\frac{a}{-0.5}}}} \]
    3. Recombined 2 regimes into one program.
    4. Final simplification45.5%

      \[\leadsto \begin{array}{l} \mathbf{if}\;h \cdot h \leq 0:\\ \;\;\;\;\sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{-0.5 \cdot \left(g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)\right)}}{\sqrt[3]{a}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{\mathsf{fma}\left(g, g, h \cdot \left(-h\right)\right)} - g\right)} + \sqrt[3]{\frac{g + \sqrt{\mathsf{fma}\left(g, g, h \cdot \left(-h\right)\right)}}{\frac{a}{-0.5}}}\\ \end{array} \]

    Alternative 2: 46.8% accurate, 0.7× speedup?

    \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\ \mathbf{if}\;h \cdot h \leq 0:\\ \;\;\;\;\sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{-0.5 \cdot \left(g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)\right)}}{\sqrt[3]{a}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)}\\ \end{array} \end{array} \]
    (FPCore (g h a)
     :precision binary64
     (let* ((t_0 (sqrt (* (+ h g) (- g h)))))
       (if (<= (* h h) 0.0)
         (+
          (cbrt (* (- g t_0) (/ -0.5 a)))
          (/ (cbrt (* -0.5 (+ g (hypot g (sqrt (* h (- h))))))) (cbrt a)))
         (+
          (cbrt (* (/ -0.5 a) (- g (sqrt (- (* g g) (* h h))))))
          (cbrt (* (/ -0.5 a) (+ g t_0)))))))
    double code(double g, double h, double a) {
    	double t_0 = sqrt(((h + g) * (g - h)));
    	double tmp;
    	if ((h * h) <= 0.0) {
    		tmp = cbrt(((g - t_0) * (-0.5 / a))) + (cbrt((-0.5 * (g + hypot(g, sqrt((h * -h)))))) / cbrt(a));
    	} else {
    		tmp = cbrt(((-0.5 / a) * (g - sqrt(((g * g) - (h * h)))))) + cbrt(((-0.5 / a) * (g + t_0)));
    	}
    	return tmp;
    }
    
    public static double code(double g, double h, double a) {
    	double t_0 = Math.sqrt(((h + g) * (g - h)));
    	double tmp;
    	if ((h * h) <= 0.0) {
    		tmp = Math.cbrt(((g - t_0) * (-0.5 / a))) + (Math.cbrt((-0.5 * (g + Math.hypot(g, Math.sqrt((h * -h)))))) / Math.cbrt(a));
    	} else {
    		tmp = Math.cbrt(((-0.5 / a) * (g - Math.sqrt(((g * g) - (h * h)))))) + Math.cbrt(((-0.5 / a) * (g + t_0)));
    	}
    	return tmp;
    }
    
    function code(g, h, a)
    	t_0 = sqrt(Float64(Float64(h + g) * Float64(g - h)))
    	tmp = 0.0
    	if (Float64(h * h) <= 0.0)
    		tmp = Float64(cbrt(Float64(Float64(g - t_0) * Float64(-0.5 / a))) + Float64(cbrt(Float64(-0.5 * Float64(g + hypot(g, sqrt(Float64(h * Float64(-h))))))) / cbrt(a)));
    	else
    		tmp = Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g - sqrt(Float64(Float64(g * g) - Float64(h * h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + t_0))));
    	end
    	return tmp
    end
    
    code[g_, h_, a_] := Block[{t$95$0 = N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, If[LessEqual[N[(h * h), $MachinePrecision], 0.0], N[(N[Power[N[(N[(g - t$95$0), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[(N[Power[N[(-0.5 * N[(g + N[Sqrt[g ^ 2 + N[Sqrt[N[(h * (-h)), $MachinePrecision]], $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] / N[Power[a, 1/3], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + t$95$0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]]
    
    \begin{array}{l}
    
    \\
    \begin{array}{l}
    t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\
    \mathbf{if}\;h \cdot h \leq 0:\\
    \;\;\;\;\sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{-0.5 \cdot \left(g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)\right)}}{\sqrt[3]{a}}\\
    
    \mathbf{else}:\\
    \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)}\\
    
    
    \end{array}
    \end{array}
    
    Derivation
    1. Split input into 2 regimes
    2. if (*.f64 h h) < 0.0

      1. Initial program 57.0%

        \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
      2. Step-by-step derivation
        1. Simplified57.0%

          \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
        2. Step-by-step derivation
          1. associate-*r/57.0%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\color{blue}{\frac{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot -0.5}{a}}} \]
          2. cbrt-div61.6%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\frac{\sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot -0.5}}{\sqrt[3]{a}}} \]
          3. difference-of-squares61.6%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \sqrt{\color{blue}{g \cdot g - h \cdot h}}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
          4. sub-neg61.6%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \sqrt{\color{blue}{g \cdot g + \left(-h \cdot h\right)}}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
          5. add-sqr-sqrt61.6%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \sqrt{g \cdot g + \color{blue}{\sqrt{-h \cdot h} \cdot \sqrt{-h \cdot h}}}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
          6. hypot-def63.0%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \color{blue}{\mathsf{hypot}\left(g, \sqrt{-h \cdot h}\right)}\right) \cdot -0.5}}{\sqrt[3]{a}} \]
          7. distribute-rgt-neg-in63.0%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{\left(g + \mathsf{hypot}\left(g, \sqrt{\color{blue}{h \cdot \left(-h\right)}}\right)\right) \cdot -0.5}}{\sqrt[3]{a}} \]
        3. Applied egg-rr63.0%

          \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \color{blue}{\frac{\sqrt[3]{\left(g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)\right) \cdot -0.5}}{\sqrt[3]{a}}} \]

        if 0.0 < (*.f64 h h)

        1. Initial program 32.6%

          \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        2. Step-by-step derivation
          1. Simplified32.6%

            \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
          2. Step-by-step derivation
            1. pow1/232.6%

              \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(\left(g + h\right) \cdot \left(g - h\right)\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            2. difference-of-squares32.6%

              \[\leadsto \sqrt[3]{\left(g - {\color{blue}{\left(g \cdot g - h \cdot h\right)}}^{0.5}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          3. Applied egg-rr32.6%

            \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(g \cdot g - h \cdot h\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          4. Step-by-step derivation
            1. unpow1/232.6%

              \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
          5. Simplified32.6%

            \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
        3. Recombined 2 regimes into one program.
        4. Final simplification45.5%

          \[\leadsto \begin{array}{l} \mathbf{if}\;h \cdot h \leq 0:\\ \;\;\;\;\sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \frac{\sqrt[3]{-0.5 \cdot \left(g + \mathsf{hypot}\left(g, \sqrt{h \cdot \left(-h\right)}\right)\right)}}{\sqrt[3]{a}}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)}\\ \end{array} \]

        Alternative 3: 44.5% accurate, 1.0× speedup?

        \[\begin{array}{l} \\ \begin{array}{l} t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\ \sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)} \end{array} \end{array} \]
        (FPCore (g h a)
         :precision binary64
         (let* ((t_0 (sqrt (* (+ h g) (- g h)))))
           (+ (cbrt (* (- g t_0) (/ -0.5 a))) (cbrt (* (/ -0.5 a) (+ g t_0))))))
        double code(double g, double h, double a) {
        	double t_0 = sqrt(((h + g) * (g - h)));
        	return cbrt(((g - t_0) * (-0.5 / a))) + cbrt(((-0.5 / a) * (g + t_0)));
        }
        
        public static double code(double g, double h, double a) {
        	double t_0 = Math.sqrt(((h + g) * (g - h)));
        	return Math.cbrt(((g - t_0) * (-0.5 / a))) + Math.cbrt(((-0.5 / a) * (g + t_0)));
        }
        
        function code(g, h, a)
        	t_0 = sqrt(Float64(Float64(h + g) * Float64(g - h)))
        	return Float64(cbrt(Float64(Float64(g - t_0) * Float64(-0.5 / a))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + t_0))))
        end
        
        code[g_, h_, a_] := Block[{t$95$0 = N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]}, N[(N[Power[N[(N[(g - t$95$0), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + t$95$0), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]
        
        \begin{array}{l}
        
        \\
        \begin{array}{l}
        t_0 := \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\\
        \sqrt[3]{\left(g - t_0\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + t_0\right)}
        \end{array}
        \end{array}
        
        Derivation
        1. Initial program 42.9%

          \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
        2. Step-by-step derivation
          1. Simplified42.9%

            \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
          2. Final simplification42.9%

            \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} \]

          Alternative 4: 44.5% accurate, 1.0× speedup?

          \[\begin{array}{l} \\ \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} \end{array} \]
          (FPCore (g h a)
           :precision binary64
           (+
            (cbrt (* (/ -0.5 a) (- g (sqrt (- (* g g) (* h h))))))
            (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))))
          double code(double g, double h, double a) {
          	return cbrt(((-0.5 / a) * (g - sqrt(((g * g) - (h * h)))))) + cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h))))));
          }
          
          public static double code(double g, double h, double a) {
          	return Math.cbrt(((-0.5 / a) * (g - Math.sqrt(((g * g) - (h * h)))))) + Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h))))));
          }
          
          function code(g, h, a)
          	return Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g - sqrt(Float64(Float64(g * g) - Float64(h * h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))))
          end
          
          code[g_, h_, a_] := N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
          
          \begin{array}{l}
          
          \\
          \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)}
          \end{array}
          
          Derivation
          1. Initial program 42.9%

            \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
          2. Step-by-step derivation
            1. Simplified42.9%

              \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
            2. Step-by-step derivation
              1. pow1/242.9%

                \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(\left(g + h\right) \cdot \left(g - h\right)\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
              2. difference-of-squares42.9%

                \[\leadsto \sqrt[3]{\left(g - {\color{blue}{\left(g \cdot g - h \cdot h\right)}}^{0.5}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            3. Applied egg-rr42.9%

              \[\leadsto \sqrt[3]{\left(g - \color{blue}{{\left(g \cdot g - h \cdot h\right)}^{0.5}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            4. Step-by-step derivation
              1. unpow1/242.9%

                \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            5. Simplified42.9%

              \[\leadsto \sqrt[3]{\left(g - \color{blue}{\sqrt{g \cdot g - h \cdot h}}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
            6. Final simplification42.9%

              \[\leadsto \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} \]

            Alternative 5: 46.2% accurate, 1.3× speedup?

            \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;g \leq -4 \cdot 10^{-154}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{h \cdot h}{g}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}\\ \end{array} \end{array} \]
            (FPCore (g h a)
             :precision binary64
             (if (<= g -4e-154)
               (+
                (cbrt (* (/ 0.5 a) (- (sqrt (- (* g g) (* h h))) g)))
                (cbrt (* (/ 0.5 a) (* -0.5 (/ (* h h) g)))))
               (+
                (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))
                (cbrt (* (/ -0.5 a) (- g g))))))
            double code(double g, double h, double a) {
            	double tmp;
            	if (g <= -4e-154) {
            		tmp = cbrt(((0.5 / a) * (sqrt(((g * g) - (h * h))) - g))) + cbrt(((0.5 / a) * (-0.5 * ((h * h) / g))));
            	} else {
            		tmp = cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h)))))) + cbrt(((-0.5 / a) * (g - g)));
            	}
            	return tmp;
            }
            
            public static double code(double g, double h, double a) {
            	double tmp;
            	if (g <= -4e-154) {
            		tmp = Math.cbrt(((0.5 / a) * (Math.sqrt(((g * g) - (h * h))) - g))) + Math.cbrt(((0.5 / a) * (-0.5 * ((h * h) / g))));
            	} else {
            		tmp = Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h)))))) + Math.cbrt(((-0.5 / a) * (g - g)));
            	}
            	return tmp;
            }
            
            function code(g, h, a)
            	tmp = 0.0
            	if (g <= -4e-154)
            		tmp = Float64(cbrt(Float64(Float64(0.5 / a) * Float64(sqrt(Float64(Float64(g * g) - Float64(h * h))) - g))) + cbrt(Float64(Float64(0.5 / a) * Float64(-0.5 * Float64(Float64(h * h) / g)))));
            	else
            		tmp = Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g - g))));
            	end
            	return tmp
            end
            
            code[g_, h_, a_] := If[LessEqual[g, -4e-154], N[(N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[(-0.5 * N[(N[(h * h), $MachinePrecision] / g), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]
            
            \begin{array}{l}
            
            \\
            \begin{array}{l}
            \mathbf{if}\;g \leq -4 \cdot 10^{-154}:\\
            \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{h \cdot h}{g}\right)}\\
            
            \mathbf{else}:\\
            \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}\\
            
            
            \end{array}
            \end{array}
            
            Derivation
            1. Split input into 2 regimes
            2. if g < -3.9999999999999999e-154

              1. Initial program 36.5%

                \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              2. Step-by-step derivation
                1. associate-/r*36.5%

                  \[\leadsto \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                2. metadata-eval36.5%

                  \[\leadsto \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                3. +-commutative36.5%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} + \left(-g\right)\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                4. unsub-neg36.5%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} - g\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                5. associate-/r*36.5%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                6. metadata-eval36.5%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              3. Simplified36.5%

                \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
              4. Taylor expanded in g around -inf 38.5%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-0.5 \cdot \frac{{h}^{2}}{g}\right)}} \]
              5. Step-by-step derivation
                1. unpow238.5%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{\color{blue}{h \cdot h}}{g}\right)} \]
              6. Simplified38.5%

                \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(-0.5 \cdot \frac{h \cdot h}{g}\right)}} \]

              if -3.9999999999999999e-154 < g

              1. Initial program 48.7%

                \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
              2. Step-by-step derivation
                1. Simplified48.6%

                  \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
                2. Taylor expanded in g around inf 49.7%

                  \[\leadsto \sqrt[3]{\left(g - \color{blue}{g}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
              3. Recombined 2 regimes into one program.
              4. Final simplification44.4%

                \[\leadsto \begin{array}{l} \mathbf{if}\;g \leq -4 \cdot 10^{-154}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(-0.5 \cdot \frac{h \cdot h}{g}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}\\ \end{array} \]

              Alternative 6: 45.3% accurate, 1.3× speedup?

              \[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;g \leq -1.56 \cdot 10^{-162}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}\\ \end{array} \end{array} \]
              (FPCore (g h a)
               :precision binary64
               (if (<= g -1.56e-162)
                 (+
                  (cbrt (* (/ 0.5 a) (- (- g) g)))
                  (cbrt (* (/ 0.5 a) (- (- g) (sqrt (- (* g g) (* h h)))))))
                 (+
                  (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))
                  (cbrt (* (/ -0.5 a) (- g g))))))
              double code(double g, double h, double a) {
              	double tmp;
              	if (g <= -1.56e-162) {
              		tmp = cbrt(((0.5 / a) * (-g - g))) + cbrt(((0.5 / a) * (-g - sqrt(((g * g) - (h * h))))));
              	} else {
              		tmp = cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h)))))) + cbrt(((-0.5 / a) * (g - g)));
              	}
              	return tmp;
              }
              
              public static double code(double g, double h, double a) {
              	double tmp;
              	if (g <= -1.56e-162) {
              		tmp = Math.cbrt(((0.5 / a) * (-g - g))) + Math.cbrt(((0.5 / a) * (-g - Math.sqrt(((g * g) - (h * h))))));
              	} else {
              		tmp = Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h)))))) + Math.cbrt(((-0.5 / a) * (g - g)));
              	}
              	return tmp;
              }
              
              function code(g, h, a)
              	tmp = 0.0
              	if (g <= -1.56e-162)
              		tmp = Float64(cbrt(Float64(Float64(0.5 / a) * Float64(Float64(-g) - g))) + cbrt(Float64(Float64(0.5 / a) * Float64(Float64(-g) - sqrt(Float64(Float64(g * g) - Float64(h * h)))))));
              	else
              		tmp = Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g - g))));
              	end
              	return tmp
              end
              
              code[g_, h_, a_] := If[LessEqual[g, -1.56e-162], N[(N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[((-g) - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(0.5 / a), $MachinePrecision] * N[((-g) - N[Sqrt[N[(N[(g * g), $MachinePrecision] - N[(h * h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision], N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]]
              
              \begin{array}{l}
              
              \\
              \begin{array}{l}
              \mathbf{if}\;g \leq -1.56 \cdot 10^{-162}:\\
              \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\
              
              \mathbf{else}:\\
              \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}\\
              
              
              \end{array}
              \end{array}
              
              Derivation
              1. Split input into 2 regimes
              2. if g < -1.5600000000000001e-162

                1. Initial program 36.5%

                  \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                2. Step-by-step derivation
                  1. associate-/r*36.5%

                    \[\leadsto \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                  2. metadata-eval36.5%

                    \[\leadsto \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                  3. +-commutative36.5%

                    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} + \left(-g\right)\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                  4. unsub-neg36.5%

                    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \color{blue}{\left(\sqrt{g \cdot g - h \cdot h} - g\right)}} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                  5. associate-/r*36.5%

                    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\color{blue}{\frac{\frac{1}{2}}{a}} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                  6. metadata-eval36.5%

                    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{\color{blue}{0.5}}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                3. Simplified36.5%

                  \[\leadsto \color{blue}{\sqrt[3]{\frac{0.5}{a} \cdot \left(\sqrt{g \cdot g - h \cdot h} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}} \]
                4. Taylor expanded in g around -inf 36.2%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\color{blue}{-1 \cdot g} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                5. Step-by-step derivation
                  1. neg-mul-136.2%

                    \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\color{blue}{\left(-g\right)} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                6. Simplified36.2%

                  \[\leadsto \sqrt[3]{\frac{0.5}{a} \cdot \left(\color{blue}{\left(-g\right)} - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]

                if -1.5600000000000001e-162 < g

                1. Initial program 48.7%

                  \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                2. Step-by-step derivation
                  1. Simplified48.6%

                    \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
                  2. Taylor expanded in g around inf 49.7%

                    \[\leadsto \sqrt[3]{\left(g - \color{blue}{g}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                3. Recombined 2 regimes into one program.
                4. Final simplification43.3%

                  \[\leadsto \begin{array}{l} \mathbf{if}\;g \leq -1.56 \cdot 10^{-162}:\\ \;\;\;\;\sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - g\right)} + \sqrt[3]{\frac{0.5}{a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)}\\ \mathbf{else}:\\ \;\;\;\;\sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}\\ \end{array} \]

                Alternative 7: 24.3% accurate, 1.3× speedup?

                \[\begin{array}{l} \\ \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)} \end{array} \]
                (FPCore (g h a)
                 :precision binary64
                 (+
                  (cbrt (* (/ -0.5 a) (+ g (sqrt (* (+ h g) (- g h))))))
                  (cbrt (* (/ -0.5 a) (- g g)))))
                double code(double g, double h, double a) {
                	return cbrt(((-0.5 / a) * (g + sqrt(((h + g) * (g - h)))))) + cbrt(((-0.5 / a) * (g - g)));
                }
                
                public static double code(double g, double h, double a) {
                	return Math.cbrt(((-0.5 / a) * (g + Math.sqrt(((h + g) * (g - h)))))) + Math.cbrt(((-0.5 / a) * (g - g)));
                }
                
                function code(g, h, a)
                	return Float64(cbrt(Float64(Float64(-0.5 / a) * Float64(g + sqrt(Float64(Float64(h + g) * Float64(g - h)))))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g - g))))
                end
                
                code[g_, h_, a_] := N[(N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g - g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
                
                \begin{array}{l}
                
                \\
                \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)}
                \end{array}
                
                Derivation
                1. Initial program 42.9%

                  \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                2. Step-by-step derivation
                  1. Simplified42.9%

                    \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
                  2. Taylor expanded in g around inf 27.0%

                    \[\leadsto \sqrt[3]{\left(g - \color{blue}{g}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} \]
                  3. Final simplification27.0%

                    \[\leadsto \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right)} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g - g\right)} \]

                  Alternative 8: 27.7% accurate, 1.3× speedup?

                  \[\begin{array}{l} \\ \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + g\right)} \end{array} \]
                  (FPCore (g h a)
                   :precision binary64
                   (+
                    (cbrt (* (- g (sqrt (* (+ h g) (- g h)))) (/ -0.5 a)))
                    (cbrt (* (/ -0.5 a) (+ g g)))))
                  double code(double g, double h, double a) {
                  	return cbrt(((g - sqrt(((h + g) * (g - h)))) * (-0.5 / a))) + cbrt(((-0.5 / a) * (g + g)));
                  }
                  
                  public static double code(double g, double h, double a) {
                  	return Math.cbrt(((g - Math.sqrt(((h + g) * (g - h)))) * (-0.5 / a))) + Math.cbrt(((-0.5 / a) * (g + g)));
                  }
                  
                  function code(g, h, a)
                  	return Float64(cbrt(Float64(Float64(g - sqrt(Float64(Float64(h + g) * Float64(g - h)))) * Float64(-0.5 / a))) + cbrt(Float64(Float64(-0.5 / a) * Float64(g + g))))
                  end
                  
                  code[g_, h_, a_] := N[(N[Power[N[(N[(g - N[Sqrt[N[(N[(h + g), $MachinePrecision] * N[(g - h), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * N[(-0.5 / a), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision] + N[Power[N[(N[(-0.5 / a), $MachinePrecision] * N[(g + g), $MachinePrecision]), $MachinePrecision], 1/3], $MachinePrecision]), $MachinePrecision]
                  
                  \begin{array}{l}
                  
                  \\
                  \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + g\right)}
                  \end{array}
                  
                  Derivation
                  1. Initial program 42.9%

                    \[\sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) + \sqrt{g \cdot g - h \cdot h}\right)} + \sqrt[3]{\frac{1}{2 \cdot a} \cdot \left(\left(-g\right) - \sqrt{g \cdot g - h \cdot h}\right)} \]
                  2. Step-by-step derivation
                    1. Simplified42.9%

                      \[\leadsto \color{blue}{\sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}}} \]
                    2. Taylor expanded in g around inf 30.0%

                      \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(g + h\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\left(g + \color{blue}{g}\right) \cdot \frac{-0.5}{a}} \]
                    3. Final simplification30.0%

                      \[\leadsto \sqrt[3]{\left(g - \sqrt{\left(h + g\right) \cdot \left(g - h\right)}\right) \cdot \frac{-0.5}{a}} + \sqrt[3]{\frac{-0.5}{a} \cdot \left(g + g\right)} \]

                    Reproduce

                    ?
                    herbie shell --seed 2023187 
                    (FPCore (g h a)
                      :name "2-ancestry mixing, positive discriminant"
                      :precision binary64
                      (+ (cbrt (* (/ 1.0 (* 2.0 a)) (+ (- g) (sqrt (- (* g g) (* h h)))))) (cbrt (* (/ 1.0 (* 2.0 a)) (- (- g) (sqrt (- (* g g) (* h h))))))))