Math FPCore C Java Python Julia MATLAB Wolfram TeX \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
\]
↓
\[\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
\mathbf{if}\;t_0 \leq -0.5 \lor \neg \left(t_0 \leq 0\right):\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
\end{array}
\]
(FPCore (A B C)
:precision binary64
(*
180.0
(/
(atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
PI))) ↓
(FPCore (A B C)
:precision binary64
(let* ((t_0
(* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))))
(if (or (<= t_0 -0.5) (not (<= t_0 0.0)))
(* 180.0 (/ (atan (/ (- (- C A) (hypot B (- A C))) B)) PI))
(/ (* 180.0 (atan (/ (* B -0.5) C))) PI)))) double code(double A, double B, double C) {
return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}
↓
double code(double A, double B, double C) {
double t_0 = (1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0))));
double tmp;
if ((t_0 <= -0.5) || !(t_0 <= 0.0)) {
tmp = 180.0 * (atan((((C - A) - hypot(B, (A - C))) / B)) / ((double) M_PI));
} else {
tmp = (180.0 * atan(((B * -0.5) / C))) / ((double) M_PI);
}
return tmp;
}
public static double code(double A, double B, double C) {
return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}
↓
public static double code(double A, double B, double C) {
double t_0 = (1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0))));
double tmp;
if ((t_0 <= -0.5) || !(t_0 <= 0.0)) {
tmp = 180.0 * (Math.atan((((C - A) - Math.hypot(B, (A - C))) / B)) / Math.PI);
} else {
tmp = (180.0 * Math.atan(((B * -0.5) / C))) / Math.PI;
}
return tmp;
}
def code(A, B, C):
return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)
↓
def code(A, B, C):
t_0 = (1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0))))
tmp = 0
if (t_0 <= -0.5) or not (t_0 <= 0.0):
tmp = 180.0 * (math.atan((((C - A) - math.hypot(B, (A - C))) / B)) / math.pi)
else:
tmp = (180.0 * math.atan(((B * -0.5) / C))) / math.pi
return tmp
function code(A, B, C)
return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end
↓
function code(A, B, C)
t_0 = Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))
tmp = 0.0
if ((t_0 <= -0.5) || !(t_0 <= 0.0))
tmp = Float64(180.0 * Float64(atan(Float64(Float64(Float64(C - A) - hypot(B, Float64(A - C))) / B)) / pi));
else
tmp = Float64(Float64(180.0 * atan(Float64(Float64(B * -0.5) / C))) / pi);
end
return tmp
end
function tmp = code(A, B, C)
tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end
↓
function tmp_2 = code(A, B, C)
t_0 = (1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0))));
tmp = 0.0;
if ((t_0 <= -0.5) || ~((t_0 <= 0.0)))
tmp = 180.0 * (atan((((C - A) - hypot(B, (A - C))) / B)) / pi);
else
tmp = (180.0 * atan(((B * -0.5) / C))) / pi;
end
tmp_2 = tmp;
end
code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]
↓
code[A_, B_, C_] := Block[{t$95$0 = N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[Or[LessEqual[t$95$0, -0.5], N[Not[LessEqual[t$95$0, 0.0]], $MachinePrecision]], N[(180.0 * N[(N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - N[Sqrt[B ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision], N[(N[(180.0 * N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / Pi), $MachinePrecision]]]
180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}
↓
\begin{array}{l}
t_0 := \frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\\
\mathbf{if}\;t_0 \leq -0.5 \lor \neg \left(t_0 \leq 0\right):\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
\end{array}
Alternatives Alternative 1 Error 22.4 Cost 14348
\[\begin{array}{l}
\mathbf{if}\;B \leq 4.8 \cdot 10^{-203}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(B + C\right) - A}{B}\right)}{\pi}\\
\mathbf{elif}\;B \leq 5.2 \cdot 10^{-156}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
\mathbf{elif}\;B \leq 7 \cdot 10^{-124}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot -0.5}{A - C} + \frac{\left(C - A\right) \cdot 2}{B}\right)}{\pi}\\
\mathbf{elif}\;B \leq 5.5 \cdot 10^{-87}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{-\pi} \cdot \left(\tan^{-1} \left(\frac{C - A}{B} + -1\right) \cdot -180\right)\\
\end{array}
\]
Alternative 2 Error 27.5 Cost 14236
\[\begin{array}{l}
t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
\mathbf{if}\;A \leq -1.42 \cdot 10^{+60}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
\mathbf{elif}\;A \leq -4.7 \cdot 10^{-11}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;A \leq -4.4 \cdot 10^{-86}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{elif}\;A \leq 3 \cdot 10^{-173}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;A \leq 6.5 \cdot 10^{-123}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
\mathbf{elif}\;A \leq 1.6 \cdot 10^{-44}:\\
\;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{B + C}{B}\right)\\
\mathbf{elif}\;A \leq 2.1 \cdot 10^{+54}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B - A}{B}\right)}{\pi}\\
\end{array}
\]
Alternative 3 Error 31.9 Cost 14105
\[\begin{array}{l}
t_0 := \frac{180 \cdot \tan^{-1} 1}{\pi}\\
\mathbf{if}\;B \leq -1 \cdot 10^{+54}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;B \leq -4.2 \cdot 10^{-9}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\
\mathbf{elif}\;B \leq -5.6 \cdot 10^{-24}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;B \leq -1.45 \cdot 10^{-281} \lor \neg \left(B \leq 2.9 \cdot 10^{-210}\right) \land B \leq 1.2 \cdot 10^{-31}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
\end{array}
\]
Alternative 4 Error 33.6 Cost 14104
\[\begin{array}{l}
t_0 := \frac{180 \cdot \tan^{-1} 1}{\pi}\\
t_1 := 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{if}\;B \leq -6.8 \cdot 10^{+53}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;B \leq -1.3 \cdot 10^{-7}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\
\mathbf{elif}\;B \leq -5.8 \cdot 10^{-24}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;B \leq -1.42 \cdot 10^{-150}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;B \leq 5.2 \cdot 10^{-217}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
\mathbf{elif}\;B \leq 17500000000000:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\
\end{array}
\]
Alternative 5 Error 26.8 Cost 14104
\[\begin{array}{l}
t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
t_1 := 180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
\mathbf{if}\;C \leq -3.9 \cdot 10^{-60}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;C \leq -1.16 \cdot 10^{-86}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\
\mathbf{elif}\;C \leq -9.6 \cdot 10^{-160}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;C \leq -3 \cdot 10^{-289}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;C \leq 2.2 \cdot 10^{-268}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\
\mathbf{elif}\;C \leq 4 \cdot 10^{-67}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\end{array}
\]
Alternative 6 Error 26.8 Cost 14104
\[\begin{array}{l}
t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
t_1 := 180 \cdot \frac{\tan^{-1} \left(-1 - \frac{A}{B}\right)}{\pi}\\
\mathbf{if}\;C \leq -3.9 \cdot 10^{-60}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;C \leq -1.3 \cdot 10^{-86}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\
\mathbf{elif}\;C \leq -4.3 \cdot 10^{-160}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;C \leq -3.2 \cdot 10^{-289}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;C \leq 1.25 \cdot 10^{-268}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\
\mathbf{elif}\;C \leq 4.6 \cdot 10^{-67}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi}\\
\end{array}
\]
Alternative 7 Error 26.2 Cost 13968
\[\begin{array}{l}
t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
\mathbf{if}\;A \leq -2.9 \cdot 10^{+60}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
\mathbf{elif}\;A \leq -8 \cdot 10^{-11}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;A \leq -6.5 \cdot 10^{-85}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{elif}\;A \leq 4.4 \cdot 10^{-170}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(B + C\right) - A}{B}\right)}{\pi}\\
\end{array}
\]
Alternative 8 Error 26.2 Cost 13968
\[\begin{array}{l}
\mathbf{if}\;A \leq -1.2 \cdot 10^{+62}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
\mathbf{elif}\;A \leq -1.5 \cdot 10^{-11}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{C - A}{B} + -1\right)}{\pi}\\
\mathbf{elif}\;A \leq -9 \cdot 10^{-84}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{elif}\;A \leq 5 \cdot 10^{-178}:\\
\;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(B + C\right) - A}{B}\right)}{\pi}\\
\end{array}
\]
Alternative 9 Error 26.2 Cost 13968
\[\begin{array}{l}
\mathbf{if}\;A \leq -1.65 \cdot 10^{+60}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
\mathbf{elif}\;A \leq -1.6 \cdot 10^{-11}:\\
\;\;\;\;\frac{1}{-\pi} \cdot \left(\tan^{-1} \left(\frac{C - A}{B} + -1\right) \cdot -180\right)\\
\mathbf{elif}\;A \leq -1.6 \cdot 10^{-85}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{elif}\;A \leq 5 \cdot 10^{-168}:\\
\;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(B + C\right) - A}{B}\right)}{\pi}\\
\end{array}
\]
Alternative 10 Error 33.3 Cost 13840
\[\begin{array}{l}
t_0 := 180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{if}\;B \leq -6.2 \cdot 10^{-24}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\
\mathbf{elif}\;B \leq -2.5 \cdot 10^{-146}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;B \leq 5.6 \cdot 10^{-217}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
\mathbf{elif}\;B \leq 5 \cdot 10^{+14}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\
\end{array}
\]
Alternative 11 Error 27.2 Cost 13840
\[\begin{array}{l}
t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\
\mathbf{if}\;A \leq -5.3 \cdot 10^{+60}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{B \cdot 0.5}{A}\right)}{\pi}\\
\mathbf{elif}\;A \leq -3.5 \cdot 10^{-11}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;A \leq -8.5 \cdot 10^{-84}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(-0.5 \cdot \frac{B}{C}\right)}{\pi}\\
\mathbf{elif}\;A \leq 6.4 \cdot 10^{-170}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{B - A}{B}\right)}{\pi}\\
\end{array}
\]
Alternative 12 Error 34.8 Cost 13448
\[\begin{array}{l}
\mathbf{if}\;B \leq -4.5 \cdot 10^{-57}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\
\mathbf{elif}\;B \leq 1.42 \cdot 10^{-158}:\\
\;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\
\end{array}
\]
Alternative 13 Error 37.9 Cost 13188
\[\begin{array}{l}
\mathbf{if}\;B \leq -2 \cdot 10^{-310}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\
\mathbf{else}:\\
\;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\
\end{array}
\]
Alternative 14 Error 50.6 Cost 13056
\[\frac{180 \cdot \tan^{-1} -1}{\pi}
\]