Bouland and Aaronson, Equation (25)

Percentage Accurate: 74.1% → 98.5%
Time: 5.3s
Alternatives: 7
Speedup: 1.2×

Specification

?
\[\begin{array}{l} \\ \left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \end{array} \]
(FPCore (a b)
 :precision binary64
 (-
  (+
   (pow (+ (* a a) (* b b)) 2.0)
   (* 4.0 (+ (* (* a a) (+ 1.0 a)) (* (* b b) (- 1.0 (* 3.0 a))))))
  1.0))
double code(double a, double b) {
	return (pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = ((((a * a) + (b * b)) ** 2.0d0) + (4.0d0 * (((a * a) * (1.0d0 + a)) + ((b * b) * (1.0d0 - (3.0d0 * a)))))) - 1.0d0
end function
public static double code(double a, double b) {
	return (Math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
def code(a, b):
	return (math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0
function code(a, b)
	return Float64(Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(1.0 + a)) + Float64(Float64(b * b) * Float64(1.0 - Float64(3.0 * a)))))) - 1.0)
end
function tmp = code(a, b)
	tmp = ((((a * a) + (b * b)) ^ 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
end
code[a_, b_] := N[(N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(1.0 + a), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 - N[(3.0 * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]
\begin{array}{l}

\\
\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 7 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 74.1% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \end{array} \]
(FPCore (a b)
 :precision binary64
 (-
  (+
   (pow (+ (* a a) (* b b)) 2.0)
   (* 4.0 (+ (* (* a a) (+ 1.0 a)) (* (* b b) (- 1.0 (* 3.0 a))))))
  1.0))
double code(double a, double b) {
	return (pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = ((((a * a) + (b * b)) ** 2.0d0) + (4.0d0 * (((a * a) * (1.0d0 + a)) + ((b * b) * (1.0d0 - (3.0d0 * a)))))) - 1.0d0
end function
public static double code(double a, double b) {
	return (Math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
}
def code(a, b):
	return (math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0
function code(a, b)
	return Float64(Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(1.0 + a)) + Float64(Float64(b * b) * Float64(1.0 - Float64(3.0 * a)))))) - 1.0)
end
function tmp = code(a, b)
	tmp = ((((a * a) + (b * b)) ^ 2.0) + (4.0 * (((a * a) * (1.0 + a)) + ((b * b) * (1.0 - (3.0 * a)))))) - 1.0;
end
code[a_, b_] := N[(N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(1.0 + a), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 - N[(3.0 * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] - 1.0), $MachinePrecision]
\begin{array}{l}

\\
\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1
\end{array}

Alternative 1: 98.5% accurate, 0.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;{\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(4, \mathsf{fma}\left(a, \mathsf{fma}\left(a, a, a\right), b \cdot \left(b \cdot \mathsf{fma}\left(a, -3, 1\right)\right)\right), {\left(\mathsf{hypot}\left(a, b\right)\right)}^{4}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (if (<=
      (+
       (pow (+ (* a a) (* b b)) 2.0)
       (* 4.0 (+ (* (* a a) (+ a 1.0)) (* (* b b) (- 1.0 (* a 3.0))))))
      INFINITY)
   (+
    (fma
     4.0
     (fma a (fma a a a) (* b (* b (fma a -3.0 1.0))))
     (pow (hypot a b) 4.0))
    -1.0)
   (/ (* (pow a 3.0) (- 16.0 (* a a))) (- 4.0 a))))
double code(double a, double b) {
	double tmp;
	if ((pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 - (a * 3.0)))))) <= ((double) INFINITY)) {
		tmp = fma(4.0, fma(a, fma(a, a, a), (b * (b * fma(a, -3.0, 1.0)))), pow(hypot(a, b), 4.0)) + -1.0;
	} else {
		tmp = (pow(a, 3.0) * (16.0 - (a * a))) / (4.0 - a);
	}
	return tmp;
}
function code(a, b)
	tmp = 0.0
	if (Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(a + 1.0)) + Float64(Float64(b * b) * Float64(1.0 - Float64(a * 3.0)))))) <= Inf)
		tmp = Float64(fma(4.0, fma(a, fma(a, a, a), Float64(b * Float64(b * fma(a, -3.0, 1.0)))), (hypot(a, b) ^ 4.0)) + -1.0);
	else
		tmp = Float64(Float64((a ^ 3.0) * Float64(16.0 - Float64(a * a))) / Float64(4.0 - a));
	end
	return tmp
end
code[a_, b_] := If[LessEqual[N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(a + 1.0), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 - N[(a * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], Infinity], N[(N[(4.0 * N[(a * N[(a * a + a), $MachinePrecision] + N[(b * N[(b * N[(a * -3.0 + 1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[Power[N[Sqrt[a ^ 2 + b ^ 2], $MachinePrecision], 4.0], $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision], N[(N[(N[Power[a, 3.0], $MachinePrecision] * N[(16.0 - N[(a * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(4.0 - a), $MachinePrecision]), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;{\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right) \leq \infty:\\
\;\;\;\;\mathsf{fma}\left(4, \mathsf{fma}\left(a, \mathsf{fma}\left(a, a, a\right), b \cdot \left(b \cdot \mathsf{fma}\left(a, -3, 1\right)\right)\right), {\left(\mathsf{hypot}\left(a, b\right)\right)}^{4}\right) + -1\\

\mathbf{else}:\\
\;\;\;\;\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 (pow.f64 (+.f64 (*.f64 a a) (*.f64 b b)) 2) (*.f64 4 (+.f64 (*.f64 (*.f64 a a) (+.f64 1 a)) (*.f64 (*.f64 b b) (-.f64 1 (*.f64 3 a)))))) < +inf.0

    1. Initial program 99.9%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. sub-neg99.9%

        \[\leadsto \color{blue}{\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) + \left(-1\right)} \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{\mathsf{fma}\left(4, \mathsf{fma}\left(a, \mathsf{fma}\left(a, a, a\right), b \cdot \left(b \cdot \mathsf{fma}\left(a, -3, 1\right)\right)\right), {\left(\mathsf{hypot}\left(a, b\right)\right)}^{4}\right) + -1} \]

    if +inf.0 < (+.f64 (pow.f64 (+.f64 (*.f64 a a) (*.f64 b b)) 2) (*.f64 4 (+.f64 (*.f64 (*.f64 a a) (+.f64 1 a)) (*.f64 (*.f64 b b) (-.f64 1 (*.f64 3 a))))))

    1. Initial program 0.0%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+0.0%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def0.0%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified8.0%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 32.6%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+32.6%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*32.6%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow232.6%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified32.6%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
    7. Taylor expanded in a around inf 32.6%

      \[\leadsto \color{blue}{4 \cdot {a}^{3} + {a}^{4}} \]
    8. Step-by-step derivation
      1. *-commutative32.6%

        \[\leadsto \color{blue}{{a}^{3} \cdot 4} + {a}^{4} \]
      2. metadata-eval32.6%

        \[\leadsto {a}^{3} \cdot 4 + {a}^{\color{blue}{\left(3 + 1\right)}} \]
      3. pow-plus32.6%

        \[\leadsto {a}^{3} \cdot 4 + \color{blue}{{a}^{3} \cdot a} \]
      4. distribute-lft-out92.6%

        \[\leadsto \color{blue}{{a}^{3} \cdot \left(4 + a\right)} \]
    9. Simplified92.6%

      \[\leadsto \color{blue}{{a}^{3} \cdot \left(4 + a\right)} \]
    10. Step-by-step derivation
      1. flip-+92.6%

        \[\leadsto {a}^{3} \cdot \color{blue}{\frac{4 \cdot 4 - a \cdot a}{4 - a}} \]
      2. associate-*r/96.2%

        \[\leadsto \color{blue}{\frac{{a}^{3} \cdot \left(4 \cdot 4 - a \cdot a\right)}{4 - a}} \]
      3. metadata-eval96.2%

        \[\leadsto \frac{{a}^{3} \cdot \left(\color{blue}{16} - a \cdot a\right)}{4 - a} \]
    11. Applied egg-rr96.2%

      \[\leadsto \color{blue}{\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.9%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right) \leq \infty:\\ \;\;\;\;\mathsf{fma}\left(4, \mathsf{fma}\left(a, \mathsf{fma}\left(a, a, a\right), b \cdot \left(b \cdot \mathsf{fma}\left(a, -3, 1\right)\right)\right), {\left(\mathsf{hypot}\left(a, b\right)\right)}^{4}\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}\\ \end{array} \]

Alternative 2: 98.4% accurate, 0.5× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := {\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right)\\ \mathbf{if}\;t_0 \leq \infty:\\ \;\;\;\;t_0 + -1\\ \mathbf{else}:\\ \;\;\;\;\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (let* ((t_0
         (+
          (pow (+ (* a a) (* b b)) 2.0)
          (* 4.0 (+ (* (* a a) (+ a 1.0)) (* (* b b) (- 1.0 (* a 3.0))))))))
   (if (<= t_0 INFINITY)
     (+ t_0 -1.0)
     (/ (* (pow a 3.0) (- 16.0 (* a a))) (- 4.0 a)))))
double code(double a, double b) {
	double t_0 = pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 - (a * 3.0)))));
	double tmp;
	if (t_0 <= ((double) INFINITY)) {
		tmp = t_0 + -1.0;
	} else {
		tmp = (pow(a, 3.0) * (16.0 - (a * a))) / (4.0 - a);
	}
	return tmp;
}
public static double code(double a, double b) {
	double t_0 = Math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 - (a * 3.0)))));
	double tmp;
	if (t_0 <= Double.POSITIVE_INFINITY) {
		tmp = t_0 + -1.0;
	} else {
		tmp = (Math.pow(a, 3.0) * (16.0 - (a * a))) / (4.0 - a);
	}
	return tmp;
}
def code(a, b):
	t_0 = math.pow(((a * a) + (b * b)), 2.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 - (a * 3.0)))))
	tmp = 0
	if t_0 <= math.inf:
		tmp = t_0 + -1.0
	else:
		tmp = (math.pow(a, 3.0) * (16.0 - (a * a))) / (4.0 - a)
	return tmp
function code(a, b)
	t_0 = Float64((Float64(Float64(a * a) + Float64(b * b)) ^ 2.0) + Float64(4.0 * Float64(Float64(Float64(a * a) * Float64(a + 1.0)) + Float64(Float64(b * b) * Float64(1.0 - Float64(a * 3.0))))))
	tmp = 0.0
	if (t_0 <= Inf)
		tmp = Float64(t_0 + -1.0);
	else
		tmp = Float64(Float64((a ^ 3.0) * Float64(16.0 - Float64(a * a))) / Float64(4.0 - a));
	end
	return tmp
end
function tmp_2 = code(a, b)
	t_0 = (((a * a) + (b * b)) ^ 2.0) + (4.0 * (((a * a) * (a + 1.0)) + ((b * b) * (1.0 - (a * 3.0)))));
	tmp = 0.0;
	if (t_0 <= Inf)
		tmp = t_0 + -1.0;
	else
		tmp = ((a ^ 3.0) * (16.0 - (a * a))) / (4.0 - a);
	end
	tmp_2 = tmp;
end
code[a_, b_] := Block[{t$95$0 = N[(N[Power[N[(N[(a * a), $MachinePrecision] + N[(b * b), $MachinePrecision]), $MachinePrecision], 2.0], $MachinePrecision] + N[(4.0 * N[(N[(N[(a * a), $MachinePrecision] * N[(a + 1.0), $MachinePrecision]), $MachinePrecision] + N[(N[(b * b), $MachinePrecision] * N[(1.0 - N[(a * 3.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$0, Infinity], N[(t$95$0 + -1.0), $MachinePrecision], N[(N[(N[Power[a, 3.0], $MachinePrecision] * N[(16.0 - N[(a * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / N[(4.0 - a), $MachinePrecision]), $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := {\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right)\\
\mathbf{if}\;t_0 \leq \infty:\\
\;\;\;\;t_0 + -1\\

\mathbf{else}:\\
\;\;\;\;\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if (+.f64 (pow.f64 (+.f64 (*.f64 a a) (*.f64 b b)) 2) (*.f64 4 (+.f64 (*.f64 (*.f64 a a) (+.f64 1 a)) (*.f64 (*.f64 b b) (-.f64 1 (*.f64 3 a)))))) < +inf.0

    1. Initial program 99.9%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]

    if +inf.0 < (+.f64 (pow.f64 (+.f64 (*.f64 a a) (*.f64 b b)) 2) (*.f64 4 (+.f64 (*.f64 (*.f64 a a) (+.f64 1 a)) (*.f64 (*.f64 b b) (-.f64 1 (*.f64 3 a))))))

    1. Initial program 0.0%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+0.0%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def0.0%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified8.0%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 32.6%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+32.6%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*32.6%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow232.6%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified32.6%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
    7. Taylor expanded in a around inf 32.6%

      \[\leadsto \color{blue}{4 \cdot {a}^{3} + {a}^{4}} \]
    8. Step-by-step derivation
      1. *-commutative32.6%

        \[\leadsto \color{blue}{{a}^{3} \cdot 4} + {a}^{4} \]
      2. metadata-eval32.6%

        \[\leadsto {a}^{3} \cdot 4 + {a}^{\color{blue}{\left(3 + 1\right)}} \]
      3. pow-plus32.6%

        \[\leadsto {a}^{3} \cdot 4 + \color{blue}{{a}^{3} \cdot a} \]
      4. distribute-lft-out92.6%

        \[\leadsto \color{blue}{{a}^{3} \cdot \left(4 + a\right)} \]
    9. Simplified92.6%

      \[\leadsto \color{blue}{{a}^{3} \cdot \left(4 + a\right)} \]
    10. Step-by-step derivation
      1. flip-+92.6%

        \[\leadsto {a}^{3} \cdot \color{blue}{\frac{4 \cdot 4 - a \cdot a}{4 - a}} \]
      2. associate-*r/96.2%

        \[\leadsto \color{blue}{\frac{{a}^{3} \cdot \left(4 \cdot 4 - a \cdot a\right)}{4 - a}} \]
      3. metadata-eval96.2%

        \[\leadsto \frac{{a}^{3} \cdot \left(\color{blue}{16} - a \cdot a\right)}{4 - a} \]
    11. Applied egg-rr96.2%

      \[\leadsto \color{blue}{\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification98.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;{\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right) \leq \infty:\\ \;\;\;\;\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(a + 1\right) + \left(b \cdot b\right) \cdot \left(1 - a \cdot 3\right)\right)\right) + -1\\ \mathbf{else}:\\ \;\;\;\;\frac{{a}^{3} \cdot \left(16 - a \cdot a\right)}{4 - a}\\ \end{array} \]

Alternative 3: 84.3% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} t_0 := \mathsf{fma}\left(4, a \cdot a, -1\right)\\ t_1 := {a}^{4} + \left(-1 + \left(a + 1\right) \cdot \left(\left(a \cdot a\right) \cdot 4\right)\right)\\ \mathbf{if}\;b \leq -1.15 \cdot 10^{+15}:\\ \;\;\;\;{b}^{4}\\ \mathbf{elif}\;b \leq -2.1 \cdot 10^{-172}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;b \leq -1.45 \cdot 10^{-258}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;b \leq 2.8 \cdot 10^{-88}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;b \leq 2.3 \cdot 10^{+38}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;{b}^{4}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (let* ((t_0 (fma 4.0 (* a a) -1.0))
        (t_1 (+ (pow a 4.0) (+ -1.0 (* (+ a 1.0) (* (* a a) 4.0))))))
   (if (<= b -1.15e+15)
     (pow b 4.0)
     (if (<= b -2.1e-172)
       t_1
       (if (<= b -1.45e-258)
         t_0
         (if (<= b 2.8e-88) t_1 (if (<= b 2.3e+38) t_0 (pow b 4.0))))))))
double code(double a, double b) {
	double t_0 = fma(4.0, (a * a), -1.0);
	double t_1 = pow(a, 4.0) + (-1.0 + ((a + 1.0) * ((a * a) * 4.0)));
	double tmp;
	if (b <= -1.15e+15) {
		tmp = pow(b, 4.0);
	} else if (b <= -2.1e-172) {
		tmp = t_1;
	} else if (b <= -1.45e-258) {
		tmp = t_0;
	} else if (b <= 2.8e-88) {
		tmp = t_1;
	} else if (b <= 2.3e+38) {
		tmp = t_0;
	} else {
		tmp = pow(b, 4.0);
	}
	return tmp;
}
function code(a, b)
	t_0 = fma(4.0, Float64(a * a), -1.0)
	t_1 = Float64((a ^ 4.0) + Float64(-1.0 + Float64(Float64(a + 1.0) * Float64(Float64(a * a) * 4.0))))
	tmp = 0.0
	if (b <= -1.15e+15)
		tmp = b ^ 4.0;
	elseif (b <= -2.1e-172)
		tmp = t_1;
	elseif (b <= -1.45e-258)
		tmp = t_0;
	elseif (b <= 2.8e-88)
		tmp = t_1;
	elseif (b <= 2.3e+38)
		tmp = t_0;
	else
		tmp = b ^ 4.0;
	end
	return tmp
end
code[a_, b_] := Block[{t$95$0 = N[(4.0 * N[(a * a), $MachinePrecision] + -1.0), $MachinePrecision]}, Block[{t$95$1 = N[(N[Power[a, 4.0], $MachinePrecision] + N[(-1.0 + N[(N[(a + 1.0), $MachinePrecision] * N[(N[(a * a), $MachinePrecision] * 4.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[b, -1.15e+15], N[Power[b, 4.0], $MachinePrecision], If[LessEqual[b, -2.1e-172], t$95$1, If[LessEqual[b, -1.45e-258], t$95$0, If[LessEqual[b, 2.8e-88], t$95$1, If[LessEqual[b, 2.3e+38], t$95$0, N[Power[b, 4.0], $MachinePrecision]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
t_0 := \mathsf{fma}\left(4, a \cdot a, -1\right)\\
t_1 := {a}^{4} + \left(-1 + \left(a + 1\right) \cdot \left(\left(a \cdot a\right) \cdot 4\right)\right)\\
\mathbf{if}\;b \leq -1.15 \cdot 10^{+15}:\\
\;\;\;\;{b}^{4}\\

\mathbf{elif}\;b \leq -2.1 \cdot 10^{-172}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;b \leq -1.45 \cdot 10^{-258}:\\
\;\;\;\;t_0\\

\mathbf{elif}\;b \leq 2.8 \cdot 10^{-88}:\\
\;\;\;\;t_1\\

\mathbf{elif}\;b \leq 2.3 \cdot 10^{+38}:\\
\;\;\;\;t_0\\

\mathbf{else}:\\
\;\;\;\;{b}^{4}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if b < -1.15e15 or 2.3000000000000001e38 < b

    1. Initial program 59.5%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+59.5%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def59.5%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified64.2%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around inf 94.1%

      \[\leadsto \color{blue}{{b}^{4}} \]

    if -1.15e15 < b < -2.0999999999999999e-172 or -1.45e-258 < b < 2.79999999999999976e-88

    1. Initial program 89.3%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+89.2%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def89.2%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified89.2%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 89.4%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+89.3%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*89.3%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow289.3%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified89.3%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]

    if -2.0999999999999999e-172 < b < -1.45e-258 or 2.79999999999999976e-88 < b < 2.3000000000000001e38

    1. Initial program 61.1%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+61.1%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def61.1%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified61.1%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 60.0%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+60.0%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*60.0%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow260.0%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified60.0%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
    7. Taylor expanded in a around 0 85.9%

      \[\leadsto \color{blue}{4 \cdot {a}^{2} - 1} \]
    8. Step-by-step derivation
      1. fma-neg85.9%

        \[\leadsto \color{blue}{\mathsf{fma}\left(4, {a}^{2}, -1\right)} \]
      2. unpow285.9%

        \[\leadsto \mathsf{fma}\left(4, \color{blue}{a \cdot a}, -1\right) \]
      3. metadata-eval85.9%

        \[\leadsto \mathsf{fma}\left(4, a \cdot a, \color{blue}{-1}\right) \]
    9. Simplified85.9%

      \[\leadsto \color{blue}{\mathsf{fma}\left(4, a \cdot a, -1\right)} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification91.2%

    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -1.15 \cdot 10^{+15}:\\ \;\;\;\;{b}^{4}\\ \mathbf{elif}\;b \leq -2.1 \cdot 10^{-172}:\\ \;\;\;\;{a}^{4} + \left(-1 + \left(a + 1\right) \cdot \left(\left(a \cdot a\right) \cdot 4\right)\right)\\ \mathbf{elif}\;b \leq -1.45 \cdot 10^{-258}:\\ \;\;\;\;\mathsf{fma}\left(4, a \cdot a, -1\right)\\ \mathbf{elif}\;b \leq 2.8 \cdot 10^{-88}:\\ \;\;\;\;{a}^{4} + \left(-1 + \left(a + 1\right) \cdot \left(\left(a \cdot a\right) \cdot 4\right)\right)\\ \mathbf{elif}\;b \leq 2.3 \cdot 10^{+38}:\\ \;\;\;\;\mathsf{fma}\left(4, a \cdot a, -1\right)\\ \mathbf{else}:\\ \;\;\;\;{b}^{4}\\ \end{array} \]

Alternative 4: 69.7% accurate, 1.1× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq -2 \cdot 10^{+15}:\\ \;\;\;\;{b}^{4}\\ \mathbf{elif}\;b \leq -7.2 \cdot 10^{-258}:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;b \leq 4 \cdot 10^{-225}:\\ \;\;\;\;-1\\ \mathbf{elif}\;b \leq 3.8 \cdot 10^{-133}:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;b \leq 1.42 \cdot 10^{-95}:\\ \;\;\;\;-1\\ \mathbf{elif}\;b \leq 2.4 \cdot 10^{-49}:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;b \leq 2.75 \cdot 10^{-5}:\\ \;\;\;\;-1\\ \mathbf{elif}\;b \leq 4.4 \cdot 10^{+38}:\\ \;\;\;\;{a}^{4}\\ \mathbf{else}:\\ \;\;\;\;{b}^{4}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (if (<= b -2e+15)
   (pow b 4.0)
   (if (<= b -7.2e-258)
     (pow a 4.0)
     (if (<= b 4e-225)
       -1.0
       (if (<= b 3.8e-133)
         (pow a 4.0)
         (if (<= b 1.42e-95)
           -1.0
           (if (<= b 2.4e-49)
             (pow a 4.0)
             (if (<= b 2.75e-5)
               -1.0
               (if (<= b 4.4e+38) (pow a 4.0) (pow b 4.0))))))))))
double code(double a, double b) {
	double tmp;
	if (b <= -2e+15) {
		tmp = pow(b, 4.0);
	} else if (b <= -7.2e-258) {
		tmp = pow(a, 4.0);
	} else if (b <= 4e-225) {
		tmp = -1.0;
	} else if (b <= 3.8e-133) {
		tmp = pow(a, 4.0);
	} else if (b <= 1.42e-95) {
		tmp = -1.0;
	} else if (b <= 2.4e-49) {
		tmp = pow(a, 4.0);
	} else if (b <= 2.75e-5) {
		tmp = -1.0;
	} else if (b <= 4.4e+38) {
		tmp = pow(a, 4.0);
	} else {
		tmp = pow(b, 4.0);
	}
	return tmp;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (b <= (-2d+15)) then
        tmp = b ** 4.0d0
    else if (b <= (-7.2d-258)) then
        tmp = a ** 4.0d0
    else if (b <= 4d-225) then
        tmp = -1.0d0
    else if (b <= 3.8d-133) then
        tmp = a ** 4.0d0
    else if (b <= 1.42d-95) then
        tmp = -1.0d0
    else if (b <= 2.4d-49) then
        tmp = a ** 4.0d0
    else if (b <= 2.75d-5) then
        tmp = -1.0d0
    else if (b <= 4.4d+38) then
        tmp = a ** 4.0d0
    else
        tmp = b ** 4.0d0
    end if
    code = tmp
end function
public static double code(double a, double b) {
	double tmp;
	if (b <= -2e+15) {
		tmp = Math.pow(b, 4.0);
	} else if (b <= -7.2e-258) {
		tmp = Math.pow(a, 4.0);
	} else if (b <= 4e-225) {
		tmp = -1.0;
	} else if (b <= 3.8e-133) {
		tmp = Math.pow(a, 4.0);
	} else if (b <= 1.42e-95) {
		tmp = -1.0;
	} else if (b <= 2.4e-49) {
		tmp = Math.pow(a, 4.0);
	} else if (b <= 2.75e-5) {
		tmp = -1.0;
	} else if (b <= 4.4e+38) {
		tmp = Math.pow(a, 4.0);
	} else {
		tmp = Math.pow(b, 4.0);
	}
	return tmp;
}
def code(a, b):
	tmp = 0
	if b <= -2e+15:
		tmp = math.pow(b, 4.0)
	elif b <= -7.2e-258:
		tmp = math.pow(a, 4.0)
	elif b <= 4e-225:
		tmp = -1.0
	elif b <= 3.8e-133:
		tmp = math.pow(a, 4.0)
	elif b <= 1.42e-95:
		tmp = -1.0
	elif b <= 2.4e-49:
		tmp = math.pow(a, 4.0)
	elif b <= 2.75e-5:
		tmp = -1.0
	elif b <= 4.4e+38:
		tmp = math.pow(a, 4.0)
	else:
		tmp = math.pow(b, 4.0)
	return tmp
function code(a, b)
	tmp = 0.0
	if (b <= -2e+15)
		tmp = b ^ 4.0;
	elseif (b <= -7.2e-258)
		tmp = a ^ 4.0;
	elseif (b <= 4e-225)
		tmp = -1.0;
	elseif (b <= 3.8e-133)
		tmp = a ^ 4.0;
	elseif (b <= 1.42e-95)
		tmp = -1.0;
	elseif (b <= 2.4e-49)
		tmp = a ^ 4.0;
	elseif (b <= 2.75e-5)
		tmp = -1.0;
	elseif (b <= 4.4e+38)
		tmp = a ^ 4.0;
	else
		tmp = b ^ 4.0;
	end
	return tmp
end
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (b <= -2e+15)
		tmp = b ^ 4.0;
	elseif (b <= -7.2e-258)
		tmp = a ^ 4.0;
	elseif (b <= 4e-225)
		tmp = -1.0;
	elseif (b <= 3.8e-133)
		tmp = a ^ 4.0;
	elseif (b <= 1.42e-95)
		tmp = -1.0;
	elseif (b <= 2.4e-49)
		tmp = a ^ 4.0;
	elseif (b <= 2.75e-5)
		tmp = -1.0;
	elseif (b <= 4.4e+38)
		tmp = a ^ 4.0;
	else
		tmp = b ^ 4.0;
	end
	tmp_2 = tmp;
end
code[a_, b_] := If[LessEqual[b, -2e+15], N[Power[b, 4.0], $MachinePrecision], If[LessEqual[b, -7.2e-258], N[Power[a, 4.0], $MachinePrecision], If[LessEqual[b, 4e-225], -1.0, If[LessEqual[b, 3.8e-133], N[Power[a, 4.0], $MachinePrecision], If[LessEqual[b, 1.42e-95], -1.0, If[LessEqual[b, 2.4e-49], N[Power[a, 4.0], $MachinePrecision], If[LessEqual[b, 2.75e-5], -1.0, If[LessEqual[b, 4.4e+38], N[Power[a, 4.0], $MachinePrecision], N[Power[b, 4.0], $MachinePrecision]]]]]]]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;b \leq -2 \cdot 10^{+15}:\\
\;\;\;\;{b}^{4}\\

\mathbf{elif}\;b \leq -7.2 \cdot 10^{-258}:\\
\;\;\;\;{a}^{4}\\

\mathbf{elif}\;b \leq 4 \cdot 10^{-225}:\\
\;\;\;\;-1\\

\mathbf{elif}\;b \leq 3.8 \cdot 10^{-133}:\\
\;\;\;\;{a}^{4}\\

\mathbf{elif}\;b \leq 1.42 \cdot 10^{-95}:\\
\;\;\;\;-1\\

\mathbf{elif}\;b \leq 2.4 \cdot 10^{-49}:\\
\;\;\;\;{a}^{4}\\

\mathbf{elif}\;b \leq 2.75 \cdot 10^{-5}:\\
\;\;\;\;-1\\

\mathbf{elif}\;b \leq 4.4 \cdot 10^{+38}:\\
\;\;\;\;{a}^{4}\\

\mathbf{else}:\\
\;\;\;\;{b}^{4}\\


\end{array}
\end{array}
Derivation
  1. Split input into 3 regimes
  2. if b < -2e15 or 4.40000000000000013e38 < b

    1. Initial program 59.5%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+59.5%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def59.5%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified64.2%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around inf 94.1%

      \[\leadsto \color{blue}{{b}^{4}} \]

    if -2e15 < b < -7.19999999999999958e-258 or 3.9999999999999998e-225 < b < 3.8000000000000003e-133 or 1.42000000000000007e-95 < b < 2.39999999999999992e-49 or 2.7500000000000001e-5 < b < 4.40000000000000013e38

    1. Initial program 74.6%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+74.6%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def74.6%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified74.6%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in a around inf 62.1%

      \[\leadsto \color{blue}{{a}^{4}} \]

    if -7.19999999999999958e-258 < b < 3.9999999999999998e-225 or 3.8000000000000003e-133 < b < 1.42000000000000007e-95 or 2.39999999999999992e-49 < b < 2.7500000000000001e-5

    1. Initial program 93.6%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+93.6%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def93.6%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified93.6%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 92.7%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+92.7%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*92.7%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow292.7%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified92.7%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
    7. Taylor expanded in a around 0 72.9%

      \[\leadsto \color{blue}{-1} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification79.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -2 \cdot 10^{+15}:\\ \;\;\;\;{b}^{4}\\ \mathbf{elif}\;b \leq -7.2 \cdot 10^{-258}:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;b \leq 4 \cdot 10^{-225}:\\ \;\;\;\;-1\\ \mathbf{elif}\;b \leq 3.8 \cdot 10^{-133}:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;b \leq 1.42 \cdot 10^{-95}:\\ \;\;\;\;-1\\ \mathbf{elif}\;b \leq 2.4 \cdot 10^{-49}:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;b \leq 2.75 \cdot 10^{-5}:\\ \;\;\;\;-1\\ \mathbf{elif}\;b \leq 4.4 \cdot 10^{+38}:\\ \;\;\;\;{a}^{4}\\ \mathbf{else}:\\ \;\;\;\;{b}^{4}\\ \end{array} \]

Alternative 5: 81.9% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;b \leq -1 \cdot 10^{+15} \lor \neg \left(b \leq 2.4 \cdot 10^{+38}\right):\\ \;\;\;\;{b}^{4}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(4, a \cdot a, -1\right)\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (if (or (<= b -1e+15) (not (<= b 2.4e+38)))
   (pow b 4.0)
   (fma 4.0 (* a a) -1.0)))
double code(double a, double b) {
	double tmp;
	if ((b <= -1e+15) || !(b <= 2.4e+38)) {
		tmp = pow(b, 4.0);
	} else {
		tmp = fma(4.0, (a * a), -1.0);
	}
	return tmp;
}
function code(a, b)
	tmp = 0.0
	if ((b <= -1e+15) || !(b <= 2.4e+38))
		tmp = b ^ 4.0;
	else
		tmp = fma(4.0, Float64(a * a), -1.0);
	end
	return tmp
end
code[a_, b_] := If[Or[LessEqual[b, -1e+15], N[Not[LessEqual[b, 2.4e+38]], $MachinePrecision]], N[Power[b, 4.0], $MachinePrecision], N[(4.0 * N[(a * a), $MachinePrecision] + -1.0), $MachinePrecision]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;b \leq -1 \cdot 10^{+15} \lor \neg \left(b \leq 2.4 \cdot 10^{+38}\right):\\
\;\;\;\;{b}^{4}\\

\mathbf{else}:\\
\;\;\;\;\mathsf{fma}\left(4, a \cdot a, -1\right)\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if b < -1e15 or 2.40000000000000017e38 < b

    1. Initial program 59.5%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+59.5%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def59.5%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified64.2%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around inf 94.1%

      \[\leadsto \color{blue}{{b}^{4}} \]

    if -1e15 < b < 2.40000000000000017e38

    1. Initial program 81.5%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+81.4%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def81.4%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified81.4%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 81.2%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+81.2%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*81.2%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow281.2%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified81.2%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
    7. Taylor expanded in a around 0 75.6%

      \[\leadsto \color{blue}{4 \cdot {a}^{2} - 1} \]
    8. Step-by-step derivation
      1. fma-neg75.6%

        \[\leadsto \color{blue}{\mathsf{fma}\left(4, {a}^{2}, -1\right)} \]
      2. unpow275.6%

        \[\leadsto \mathsf{fma}\left(4, \color{blue}{a \cdot a}, -1\right) \]
      3. metadata-eval75.6%

        \[\leadsto \mathsf{fma}\left(4, a \cdot a, \color{blue}{-1}\right) \]
    9. Simplified75.6%

      \[\leadsto \color{blue}{\mathsf{fma}\left(4, a \cdot a, -1\right)} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification84.7%

    \[\leadsto \begin{array}{l} \mathbf{if}\;b \leq -1 \cdot 10^{+15} \lor \neg \left(b \leq 2.4 \cdot 10^{+38}\right):\\ \;\;\;\;{b}^{4}\\ \mathbf{else}:\\ \;\;\;\;\mathsf{fma}\left(4, a \cdot a, -1\right)\\ \end{array} \]

Alternative 6: 67.5% accurate, 1.2× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;a \leq -0.98:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;a \leq 1.9 \cdot 10^{-11}:\\ \;\;\;\;-1\\ \mathbf{else}:\\ \;\;\;\;{a}^{4}\\ \end{array} \end{array} \]
(FPCore (a b)
 :precision binary64
 (if (<= a -0.98) (pow a 4.0) (if (<= a 1.9e-11) -1.0 (pow a 4.0))))
double code(double a, double b) {
	double tmp;
	if (a <= -0.98) {
		tmp = pow(a, 4.0);
	} else if (a <= 1.9e-11) {
		tmp = -1.0;
	} else {
		tmp = pow(a, 4.0);
	}
	return tmp;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    real(8) :: tmp
    if (a <= (-0.98d0)) then
        tmp = a ** 4.0d0
    else if (a <= 1.9d-11) then
        tmp = -1.0d0
    else
        tmp = a ** 4.0d0
    end if
    code = tmp
end function
public static double code(double a, double b) {
	double tmp;
	if (a <= -0.98) {
		tmp = Math.pow(a, 4.0);
	} else if (a <= 1.9e-11) {
		tmp = -1.0;
	} else {
		tmp = Math.pow(a, 4.0);
	}
	return tmp;
}
def code(a, b):
	tmp = 0
	if a <= -0.98:
		tmp = math.pow(a, 4.0)
	elif a <= 1.9e-11:
		tmp = -1.0
	else:
		tmp = math.pow(a, 4.0)
	return tmp
function code(a, b)
	tmp = 0.0
	if (a <= -0.98)
		tmp = a ^ 4.0;
	elseif (a <= 1.9e-11)
		tmp = -1.0;
	else
		tmp = a ^ 4.0;
	end
	return tmp
end
function tmp_2 = code(a, b)
	tmp = 0.0;
	if (a <= -0.98)
		tmp = a ^ 4.0;
	elseif (a <= 1.9e-11)
		tmp = -1.0;
	else
		tmp = a ^ 4.0;
	end
	tmp_2 = tmp;
end
code[a_, b_] := If[LessEqual[a, -0.98], N[Power[a, 4.0], $MachinePrecision], If[LessEqual[a, 1.9e-11], -1.0, N[Power[a, 4.0], $MachinePrecision]]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;a \leq -0.98:\\
\;\;\;\;{a}^{4}\\

\mathbf{elif}\;a \leq 1.9 \cdot 10^{-11}:\\
\;\;\;\;-1\\

\mathbf{else}:\\
\;\;\;\;{a}^{4}\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if a < -0.97999999999999998 or 1.8999999999999999e-11 < a

    1. Initial program 42.6%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+42.6%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def42.6%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified47.2%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in a around inf 85.5%

      \[\leadsto \color{blue}{{a}^{4}} \]

    if -0.97999999999999998 < a < 1.8999999999999999e-11

    1. Initial program 100.0%

      \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
    2. Step-by-step derivation
      1. associate--l+100.0%

        \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
      2. fma-def100.0%

        \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
    3. Simplified100.0%

      \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
    4. Taylor expanded in b around 0 53.6%

      \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
    5. Step-by-step derivation
      1. associate--l+53.6%

        \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
      2. associate-*r*53.6%

        \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
      3. unpow253.6%

        \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
    6. Simplified53.6%

      \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
    7. Taylor expanded in a around 0 52.9%

      \[\leadsto \color{blue}{-1} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification69.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;a \leq -0.98:\\ \;\;\;\;{a}^{4}\\ \mathbf{elif}\;a \leq 1.9 \cdot 10^{-11}:\\ \;\;\;\;-1\\ \mathbf{else}:\\ \;\;\;\;{a}^{4}\\ \end{array} \]

Alternative 7: 25.0% accurate, 130.0× speedup?

\[\begin{array}{l} \\ -1 \end{array} \]
(FPCore (a b) :precision binary64 -1.0)
double code(double a, double b) {
	return -1.0;
}
real(8) function code(a, b)
    real(8), intent (in) :: a
    real(8), intent (in) :: b
    code = -1.0d0
end function
public static double code(double a, double b) {
	return -1.0;
}
def code(a, b):
	return -1.0
function code(a, b)
	return -1.0
end
function tmp = code(a, b)
	tmp = -1.0;
end
code[a_, b_] := -1.0
\begin{array}{l}

\\
-1
\end{array}
Derivation
  1. Initial program 70.6%

    \[\left({\left(a \cdot a + b \cdot b\right)}^{2} + 4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right)\right) - 1 \]
  2. Step-by-step derivation
    1. associate--l+70.6%

      \[\leadsto \color{blue}{{\left(a \cdot a + b \cdot b\right)}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right)} \]
    2. fma-def70.6%

      \[\leadsto {\color{blue}{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}}^{2} + \left(4 \cdot \left(\left(a \cdot a\right) \cdot \left(1 + a\right) + \left(b \cdot b\right) \cdot \left(1 - 3 \cdot a\right)\right) - 1\right) \]
  3. Simplified73.0%

    \[\leadsto \color{blue}{{\left(\mathsf{fma}\left(a, a, b \cdot b\right)\right)}^{2} + \left(4 \cdot \mathsf{fma}\left(a \cdot a, a + 1, \left(b \cdot b\right) \cdot \left(1 + -3 \cdot a\right)\right) - 1\right)} \]
  4. Taylor expanded in b around 0 52.7%

    \[\leadsto \color{blue}{\left({a}^{4} + 4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right)\right) - 1} \]
  5. Step-by-step derivation
    1. associate--l+52.7%

      \[\leadsto \color{blue}{{a}^{4} + \left(4 \cdot \left({a}^{2} \cdot \left(1 + a\right)\right) - 1\right)} \]
    2. associate-*r*52.7%

      \[\leadsto {a}^{4} + \left(\color{blue}{\left(4 \cdot {a}^{2}\right) \cdot \left(1 + a\right)} - 1\right) \]
    3. unpow252.7%

      \[\leadsto {a}^{4} + \left(\left(4 \cdot \color{blue}{\left(a \cdot a\right)}\right) \cdot \left(1 + a\right) - 1\right) \]
  6. Simplified52.7%

    \[\leadsto \color{blue}{{a}^{4} + \left(\left(4 \cdot \left(a \cdot a\right)\right) \cdot \left(1 + a\right) - 1\right)} \]
  7. Taylor expanded in a around 0 26.2%

    \[\leadsto \color{blue}{-1} \]
  8. Final simplification26.2%

    \[\leadsto -1 \]

Reproduce

?
herbie shell --seed 2023181 
(FPCore (a b)
  :name "Bouland and Aaronson, Equation (25)"
  :precision binary64
  (- (+ (pow (+ (* a a) (* b b)) 2.0) (* 4.0 (+ (* (* a a) (+ 1.0 a)) (* (* b b) (- 1.0 (* 3.0 a)))))) 1.0))