Compound Interest

?

Percentage Accurate: 27.6% → 99.2%
Time: 20.6s
Precision: binary64
Cost: 29388

?

\[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq -1 \cdot 10^{-18}:\\ \;\;\;\;100 \cdot \left(\frac{n}{i} \cdot 0 + \left(n \cdot \frac{t_0}{i} - \frac{n}{i}\right)\right)\\ \mathbf{elif}\;t_1 \leq 0:\\ \;\;\;\;\frac{100 \cdot \mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\ \mathbf{elif}\;t_1 \leq \infty:\\ \;\;\;\;n \cdot \frac{t_0}{\frac{i}{100}} + n \cdot \frac{-1}{\frac{i}{100}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \end{array} \]
(FPCore (i n)
 :precision binary64
 (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))
(FPCore (i n)
 :precision binary64
 (let* ((t_0 (pow (+ 1.0 (/ i n)) n)) (t_1 (/ (+ t_0 -1.0) (/ i n))))
   (if (<= t_1 -1e-18)
     (* 100.0 (+ (* (/ n i) 0.0) (- (* n (/ t_0 i)) (/ n i))))
     (if (<= t_1 0.0)
       (/ (* 100.0 (expm1 (* n (log1p (/ i n))))) (/ i n))
       (if (<= t_1 INFINITY)
         (+ (* n (/ t_0 (/ i 100.0))) (* n (/ -1.0 (/ i 100.0))))
         (* 100.0 (/ n (+ 1.0 (* i -0.5)))))))))
double code(double i, double n) {
	return 100.0 * ((pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
double code(double i, double n) {
	double t_0 = pow((1.0 + (i / n)), n);
	double t_1 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_1 <= -1e-18) {
		tmp = 100.0 * (((n / i) * 0.0) + ((n * (t_0 / i)) - (n / i)));
	} else if (t_1 <= 0.0) {
		tmp = (100.0 * expm1((n * log1p((i / n))))) / (i / n);
	} else if (t_1 <= ((double) INFINITY)) {
		tmp = (n * (t_0 / (i / 100.0))) + (n * (-1.0 / (i / 100.0)));
	} else {
		tmp = 100.0 * (n / (1.0 + (i * -0.5)));
	}
	return tmp;
}
public static double code(double i, double n) {
	return 100.0 * ((Math.pow((1.0 + (i / n)), n) - 1.0) / (i / n));
}
public static double code(double i, double n) {
	double t_0 = Math.pow((1.0 + (i / n)), n);
	double t_1 = (t_0 + -1.0) / (i / n);
	double tmp;
	if (t_1 <= -1e-18) {
		tmp = 100.0 * (((n / i) * 0.0) + ((n * (t_0 / i)) - (n / i)));
	} else if (t_1 <= 0.0) {
		tmp = (100.0 * Math.expm1((n * Math.log1p((i / n))))) / (i / n);
	} else if (t_1 <= Double.POSITIVE_INFINITY) {
		tmp = (n * (t_0 / (i / 100.0))) + (n * (-1.0 / (i / 100.0)));
	} else {
		tmp = 100.0 * (n / (1.0 + (i * -0.5)));
	}
	return tmp;
}
def code(i, n):
	return 100.0 * ((math.pow((1.0 + (i / n)), n) - 1.0) / (i / n))
def code(i, n):
	t_0 = math.pow((1.0 + (i / n)), n)
	t_1 = (t_0 + -1.0) / (i / n)
	tmp = 0
	if t_1 <= -1e-18:
		tmp = 100.0 * (((n / i) * 0.0) + ((n * (t_0 / i)) - (n / i)))
	elif t_1 <= 0.0:
		tmp = (100.0 * math.expm1((n * math.log1p((i / n))))) / (i / n)
	elif t_1 <= math.inf:
		tmp = (n * (t_0 / (i / 100.0))) + (n * (-1.0 / (i / 100.0)))
	else:
		tmp = 100.0 * (n / (1.0 + (i * -0.5)))
	return tmp
function code(i, n)
	return Float64(100.0 * Float64(Float64((Float64(1.0 + Float64(i / n)) ^ n) - 1.0) / Float64(i / n)))
end
function code(i, n)
	t_0 = Float64(1.0 + Float64(i / n)) ^ n
	t_1 = Float64(Float64(t_0 + -1.0) / Float64(i / n))
	tmp = 0.0
	if (t_1 <= -1e-18)
		tmp = Float64(100.0 * Float64(Float64(Float64(n / i) * 0.0) + Float64(Float64(n * Float64(t_0 / i)) - Float64(n / i))));
	elseif (t_1 <= 0.0)
		tmp = Float64(Float64(100.0 * expm1(Float64(n * log1p(Float64(i / n))))) / Float64(i / n));
	elseif (t_1 <= Inf)
		tmp = Float64(Float64(n * Float64(t_0 / Float64(i / 100.0))) + Float64(n * Float64(-1.0 / Float64(i / 100.0))));
	else
		tmp = Float64(100.0 * Float64(n / Float64(1.0 + Float64(i * -0.5))));
	end
	return tmp
end
code[i_, n_] := N[(100.0 * N[(N[(N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision] - 1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[i_, n_] := Block[{t$95$0 = N[Power[N[(1.0 + N[(i / n), $MachinePrecision]), $MachinePrecision], n], $MachinePrecision]}, Block[{t$95$1 = N[(N[(t$95$0 + -1.0), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision]}, If[LessEqual[t$95$1, -1e-18], N[(100.0 * N[(N[(N[(n / i), $MachinePrecision] * 0.0), $MachinePrecision] + N[(N[(n * N[(t$95$0 / i), $MachinePrecision]), $MachinePrecision] - N[(n / i), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, 0.0], N[(N[(100.0 * N[(Exp[N[(n * N[Log[1 + N[(i / n), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]] - 1), $MachinePrecision]), $MachinePrecision] / N[(i / n), $MachinePrecision]), $MachinePrecision], If[LessEqual[t$95$1, Infinity], N[(N[(n * N[(t$95$0 / N[(i / 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(n * N[(-1.0 / N[(i / 100.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(100.0 * N[(n / N[(1.0 + N[(i * -0.5), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]]]]
100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}}
\begin{array}{l}
t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\
t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\
\mathbf{if}\;t_1 \leq -1 \cdot 10^{-18}:\\
\;\;\;\;100 \cdot \left(\frac{n}{i} \cdot 0 + \left(n \cdot \frac{t_0}{i} - \frac{n}{i}\right)\right)\\

\mathbf{elif}\;t_1 \leq 0:\\
\;\;\;\;\frac{100 \cdot \mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\

\mathbf{elif}\;t_1 \leq \infty:\\
\;\;\;\;n \cdot \frac{t_0}{\frac{i}{100}} + n \cdot \frac{-1}{\frac{i}{100}}\\

\mathbf{else}:\\
\;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\


\end{array}

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Herbie found 20 alternatives:

AlternativeAccuracySpeedup

Accuracy vs Speed

The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Bogosity?

Bogosity

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original27.6%
Target33.6%
Herbie99.2%
\[100 \cdot \frac{e^{n \cdot \begin{array}{l} \mathbf{if}\;1 + \frac{i}{n} = 1:\\ \;\;\;\;\frac{i}{n}\\ \mathbf{else}:\\ \;\;\;\;\frac{\frac{i}{n} \cdot \log \left(1 + \frac{i}{n}\right)}{\left(\frac{i}{n} + 1\right) - 1}\\ \end{array}} - 1}{\frac{i}{n}} \]

Derivation?

  1. Split input into 4 regimes
  2. if (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n)) < -1.0000000000000001e-18

    1. Initial program 99.8%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Applied egg-rr100.0%

      \[\leadsto 100 \cdot \color{blue}{\left(\mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(-\frac{n}{i}, 1, \frac{n}{i} \cdot 1\right)\right)} \]
      Step-by-step derivation

      [Start]99.8%

      \[ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]

      div-sub [=>]99.8%

      \[ 100 \cdot \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{n}} - \frac{1}{\frac{i}{n}}\right)} \]

      associate-/r/ [=>]99.8%

      \[ 100 \cdot \left(\color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n} - \frac{1}{\frac{i}{n}}\right) \]

      clear-num [<=]100.0%

      \[ 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n - \color{blue}{\frac{n}{i}}\right) \]

      *-un-lft-identity [=>]100.0%

      \[ 100 \cdot \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n - \color{blue}{1 \cdot \frac{n}{i}}\right) \]

      prod-diff [=>]100.0%

      \[ 100 \cdot \color{blue}{\left(\mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(-\frac{n}{i}, 1, \frac{n}{i} \cdot 1\right)\right)} \]
    3. Simplified100.0%

      \[\leadsto 100 \cdot \color{blue}{\left(\frac{n}{i} \cdot 0 + \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n - \frac{n}{i}\right)\right)} \]
      Step-by-step derivation

      [Start]100.0%

      \[ 100 \cdot \left(\mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(-\frac{n}{i}, 1, \frac{n}{i} \cdot 1\right)\right) \]

      +-commutative [=>]100.0%

      \[ 100 \cdot \color{blue}{\left(\mathsf{fma}\left(-\frac{n}{i}, 1, \frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right)} \]

      fma-udef [=>]100.0%

      \[ 100 \cdot \left(\color{blue}{\left(\left(-\frac{n}{i}\right) \cdot 1 + \frac{n}{i} \cdot 1\right)} + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right) \]

      distribute-lft-neg-in [<=]100.0%

      \[ 100 \cdot \left(\left(\color{blue}{\left(-\frac{n}{i} \cdot 1\right)} + \frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right) \]

      distribute-rgt-neg-in [=>]100.0%

      \[ 100 \cdot \left(\left(\color{blue}{\frac{n}{i} \cdot \left(-1\right)} + \frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right) \]

      metadata-eval [=>]100.0%

      \[ 100 \cdot \left(\left(\frac{n}{i} \cdot \color{blue}{-1} + \frac{n}{i} \cdot 1\right) + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right) \]

      distribute-lft-out [=>]100.0%

      \[ 100 \cdot \left(\color{blue}{\frac{n}{i} \cdot \left(-1 + 1\right)} + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right) \]

      metadata-eval [=>]100.0%

      \[ 100 \cdot \left(\frac{n}{i} \cdot \color{blue}{0} + \mathsf{fma}\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i}, n, -\frac{n}{i} \cdot 1\right)\right) \]

      fma-udef [=>]100.0%

      \[ 100 \cdot \left(\frac{n}{i} \cdot 0 + \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n + \left(-\frac{n}{i} \cdot 1\right)\right)}\right) \]

      *-rgt-identity [=>]100.0%

      \[ 100 \cdot \left(\frac{n}{i} \cdot 0 + \left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n + \left(-\color{blue}{\frac{n}{i}}\right)\right)\right) \]

      unsub-neg [=>]100.0%

      \[ 100 \cdot \left(\frac{n}{i} \cdot 0 + \color{blue}{\left(\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} \cdot n - \frac{n}{i}\right)}\right) \]

    if -1.0000000000000001e-18 < (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n)) < 0.0

    1. Initial program 25.7%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Applied egg-rr99.6%

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}} \]
      Step-by-step derivation

      [Start]25.7%

      \[ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]

      associate-*r/ [=>]25.7%

      \[ \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]

      *-commutative [=>]25.7%

      \[ \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]

      pow-to-exp [=>]25.7%

      \[ \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]

      expm1-def [=>]37.4%

      \[ \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]

      add-log-exp [=>]25.7%

      \[ \frac{\mathsf{expm1}\left(\color{blue}{\log \left(e^{\log \left(1 + \frac{i}{n}\right) \cdot n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

      pow-to-exp [<=]25.7%

      \[ \frac{\mathsf{expm1}\left(\log \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

      log-pow [=>]37.4%

      \[ \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

      log1p-udef [<=]99.6%

      \[ \frac{\mathsf{expm1}\left(n \cdot \color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

    if 0.0 < (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n)) < +inf.0

    1. Initial program 98.2%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Applied egg-rr78.2%

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}} \]
      Step-by-step derivation

      [Start]98.2%

      \[ 100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]

      associate-*r/ [=>]98.3%

      \[ \color{blue}{\frac{100 \cdot \left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right)}{\frac{i}{n}}} \]

      *-commutative [=>]98.3%

      \[ \frac{\color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n} - 1\right) \cdot 100}}{\frac{i}{n}} \]

      pow-to-exp [=>]76.5%

      \[ \frac{\left(\color{blue}{e^{\log \left(1 + \frac{i}{n}\right) \cdot n}} - 1\right) \cdot 100}{\frac{i}{n}} \]

      expm1-def [=>]78.2%

      \[ \frac{\color{blue}{\mathsf{expm1}\left(\log \left(1 + \frac{i}{n}\right) \cdot n\right)} \cdot 100}{\frac{i}{n}} \]

      add-log-exp [=>]76.5%

      \[ \frac{\mathsf{expm1}\left(\color{blue}{\log \left(e^{\log \left(1 + \frac{i}{n}\right) \cdot n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

      pow-to-exp [<=]98.3%

      \[ \frac{\mathsf{expm1}\left(\log \color{blue}{\left({\left(1 + \frac{i}{n}\right)}^{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

      log-pow [=>]78.2%

      \[ \frac{\mathsf{expm1}\left(\color{blue}{n \cdot \log \left(1 + \frac{i}{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]

      log1p-udef [<=]78.2%

      \[ \frac{\mathsf{expm1}\left(n \cdot \color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right)}\right) \cdot 100}{\frac{i}{n}} \]
    3. Applied egg-rr78.1%

      \[\leadsto \color{blue}{1 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{\frac{i}{n}}{100}}} \]
      Step-by-step derivation

      [Start]78.2%

      \[ \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}} \]

      *-un-lft-identity [=>]78.2%

      \[ \color{blue}{1 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot 100}{\frac{i}{n}}} \]

      associate-/l* [=>]78.1%

      \[ 1 \cdot \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{\frac{i}{n}}{100}}} \]
    4. Simplified78.1%

      \[\leadsto \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{100 \cdot n}}} \]
      Step-by-step derivation

      [Start]78.1%

      \[ 1 \cdot \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{\frac{i}{n}}{100}} \]

      *-lft-identity [=>]78.1%

      \[ \color{blue}{\frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{\frac{i}{n}}{100}}} \]

      associate-/l/ [=>]78.1%

      \[ \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\color{blue}{\frac{i}{100 \cdot n}}} \]
    5. Applied egg-rr98.1%

      \[\leadsto \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{\frac{i}{100}}{n}} - \frac{1}{\frac{\frac{i}{100}}{n}}} \]
      Step-by-step derivation

      [Start]78.1%

      \[ \frac{\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{100 \cdot n}} \]

      expm1-udef [=>]76.5%

      \[ \frac{\color{blue}{e^{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)} - 1}}{\frac{i}{100 \cdot n}} \]

      div-sub [=>]76.7%

      \[ \color{blue}{\frac{e^{n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)}}{\frac{i}{100 \cdot n}} - \frac{1}{\frac{i}{100 \cdot n}}} \]

      *-commutative [=>]76.7%

      \[ \frac{e^{\color{blue}{\mathsf{log1p}\left(\frac{i}{n}\right) \cdot n}}}{\frac{i}{100 \cdot n}} - \frac{1}{\frac{i}{100 \cdot n}} \]

      log1p-udef [=>]76.7%

      \[ \frac{e^{\color{blue}{\log \left(1 + \frac{i}{n}\right)} \cdot n}}{\frac{i}{100 \cdot n}} - \frac{1}{\frac{i}{100 \cdot n}} \]

      exp-to-pow [=>]98.3%

      \[ \frac{\color{blue}{{\left(1 + \frac{i}{n}\right)}^{n}}}{\frac{i}{100 \cdot n}} - \frac{1}{\frac{i}{100 \cdot n}} \]

      associate-/r* [=>]98.0%

      \[ \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\color{blue}{\frac{\frac{i}{100}}{n}}} - \frac{1}{\frac{i}{100 \cdot n}} \]

      associate-/r* [=>]98.1%

      \[ \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{\frac{i}{100}}{n}} - \frac{1}{\color{blue}{\frac{\frac{i}{100}}{n}}} \]
    6. Simplified98.5%

      \[\leadsto \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{100}} \cdot n - \frac{1}{\frac{i}{100}} \cdot n} \]
      Step-by-step derivation

      [Start]98.1%

      \[ \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{\frac{i}{100}}{n}} - \frac{1}{\frac{\frac{i}{100}}{n}} \]

      associate-/r/ [=>]98.4%

      \[ \color{blue}{\frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{100}} \cdot n} - \frac{1}{\frac{\frac{i}{100}}{n}} \]

      associate-/r/ [=>]98.5%

      \[ \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{100}} \cdot n - \color{blue}{\frac{1}{\frac{i}{100}} \cdot n} \]

    if +inf.0 < (/.f64 (-.f64 (pow.f64 (+.f64 1 (/.f64 i n)) n) 1) (/.f64 i n))

    1. Initial program 0.0%

      \[100 \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n} - 1}{\frac{i}{n}} \]
    2. Taylor expanded in n around inf 2.0%

      \[\leadsto \color{blue}{100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i}} \]
    3. Simplified84.6%

      \[\leadsto \color{blue}{\frac{n}{\frac{i}{\mathsf{expm1}\left(i\right)}} \cdot 100} \]
      Step-by-step derivation

      [Start]2.0%

      \[ 100 \cdot \frac{n \cdot \left(e^{i} - 1\right)}{i} \]

      *-commutative [=>]2.0%

      \[ \color{blue}{\frac{n \cdot \left(e^{i} - 1\right)}{i} \cdot 100} \]

      associate-/l* [=>]2.0%

      \[ \color{blue}{\frac{n}{\frac{i}{e^{i} - 1}}} \cdot 100 \]

      expm1-def [=>]84.6%

      \[ \frac{n}{\frac{i}{\color{blue}{\mathsf{expm1}\left(i\right)}}} \cdot 100 \]
    4. Taylor expanded in i around 0 100.0%

      \[\leadsto \frac{n}{\color{blue}{1 + -0.5 \cdot i}} \cdot 100 \]
    5. Simplified100.0%

      \[\leadsto \frac{n}{\color{blue}{1 + i \cdot -0.5}} \cdot 100 \]
      Step-by-step derivation

      [Start]100.0%

      \[ \frac{n}{1 + -0.5 \cdot i} \cdot 100 \]

      *-commutative [=>]100.0%

      \[ \frac{n}{1 + \color{blue}{i \cdot -0.5}} \cdot 100 \]
  3. Recombined 4 regimes into one program.
  4. Final simplification99.6%

    \[\leadsto \begin{array}{l} \mathbf{if}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq -1 \cdot 10^{-18}:\\ \;\;\;\;100 \cdot \left(\frac{n}{i} \cdot 0 + \left(n \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{i} - \frac{n}{i}\right)\right)\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq 0:\\ \;\;\;\;\frac{100 \cdot \mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\ \mathbf{elif}\;\frac{{\left(1 + \frac{i}{n}\right)}^{n} + -1}{\frac{i}{n}} \leq \infty:\\ \;\;\;\;n \cdot \frac{{\left(1 + \frac{i}{n}\right)}^{n}}{\frac{i}{100}} + n \cdot \frac{-1}{\frac{i}{100}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy99.2%
Cost29388
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq -1 \cdot 10^{-18}:\\ \;\;\;\;100 \cdot \left(\frac{n}{i} \cdot 0 + \left(n \cdot \frac{t_0}{i} - \frac{n}{i}\right)\right)\\ \mathbf{elif}\;t_1 \leq 0:\\ \;\;\;\;\frac{100 \cdot \mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{\frac{i}{n}}\\ \mathbf{elif}\;t_1 \leq \infty:\\ \;\;\;\;n \cdot \frac{t_0}{\frac{i}{100}} + n \cdot \frac{-1}{\frac{i}{100}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \end{array} \]
Alternative 2
Accuracy98.3%
Cost29388
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq -1 \cdot 10^{-52}:\\ \;\;\;\;100 \cdot \left(\frac{n}{i} \cdot 0 + \left(n \cdot \frac{t_0}{i} - \frac{n}{i}\right)\right)\\ \mathbf{elif}\;t_1 \leq 0:\\ \;\;\;\;n \cdot \left(\mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right) \cdot \frac{100}{i}\right)\\ \mathbf{elif}\;t_1 \leq \infty:\\ \;\;\;\;n \cdot \frac{t_0}{\frac{i}{100}} + n \cdot \frac{-1}{\frac{i}{100}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \end{array} \]
Alternative 3
Accuracy98.5%
Cost29388
\[\begin{array}{l} t_0 := {\left(1 + \frac{i}{n}\right)}^{n}\\ t_1 := \frac{t_0 + -1}{\frac{i}{n}}\\ \mathbf{if}\;t_1 \leq -1 \cdot 10^{-52}:\\ \;\;\;\;100 \cdot \left(\frac{n}{i} \cdot 0 + \left(n \cdot \frac{t_0}{i} - \frac{n}{i}\right)\right)\\ \mathbf{elif}\;t_1 \leq 0:\\ \;\;\;\;n \cdot \frac{100 \cdot \mathsf{expm1}\left(n \cdot \mathsf{log1p}\left(\frac{i}{n}\right)\right)}{i}\\ \mathbf{elif}\;t_1 \leq \infty:\\ \;\;\;\;n \cdot \frac{t_0}{\frac{i}{100}} + n \cdot \frac{-1}{\frac{i}{100}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \end{array} \]
Alternative 4
Accuracy82.8%
Cost7628
\[\begin{array}{l} t_0 := 100 \cdot \frac{n}{\frac{i}{\mathsf{expm1}\left(i\right)}}\\ \mathbf{if}\;n \leq -2.75 \cdot 10^{-154}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;n \leq 1.45 \cdot 10^{-226}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 5.5 \cdot 10^{-10}:\\ \;\;\;\;100 \cdot \frac{n}{1 + \mathsf{fma}\left(i \cdot i, 0.08333333333333333, i \cdot -0.5\right)}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 5
Accuracy75.8%
Cost7244
\[\begin{array}{l} t_0 := 100 \cdot \frac{\mathsf{expm1}\left(i\right)}{\frac{i}{n}}\\ \mathbf{if}\;i \leq -5.4 \cdot 10^{-67}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;i \leq 1.55 \cdot 10^{-202}:\\ \;\;\;\;100 \cdot \left(n + \left(i \cdot n\right) \cdot \left(0.5 - \frac{0.5}{n}\right)\right)\\ \mathbf{elif}\;i \leq 2.8 \cdot 10^{-24}:\\ \;\;\;\;100 \cdot \frac{i \cdot n}{i}\\ \mathbf{else}:\\ \;\;\;\;t_0\\ \end{array} \]
Alternative 6
Accuracy79.9%
Cost7113
\[\begin{array}{l} \mathbf{if}\;n \leq -2.95 \cdot 10^{-154} \lor \neg \left(n \leq 1.15 \cdot 10^{-177}\right):\\ \;\;\;\;n \cdot \frac{100 \cdot \mathsf{expm1}\left(i\right)}{i}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 7
Accuracy80.0%
Cost7113
\[\begin{array}{l} \mathbf{if}\;n \leq -3.3 \cdot 10^{-154} \lor \neg \left(n \leq 8 \cdot 10^{-176}\right):\\ \;\;\;\;100 \cdot \left(n \cdot \frac{\mathsf{expm1}\left(i\right)}{i}\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 8
Accuracy79.9%
Cost7113
\[\begin{array}{l} \mathbf{if}\;n \leq -3.3 \cdot 10^{-154} \lor \neg \left(n \leq 8 \cdot 10^{-181}\right):\\ \;\;\;\;100 \cdot \frac{n}{\frac{i}{\mathsf{expm1}\left(i\right)}}\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 9
Accuracy65.2%
Cost1484
\[\begin{array}{l} \mathbf{if}\;n \leq -2.35 \cdot 10^{+238}:\\ \;\;\;\;100 \cdot \frac{i \cdot n}{i}\\ \mathbf{elif}\;n \leq -2.55 \cdot 10^{-153}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \mathbf{elif}\;n \leq 1.4 \cdot 10^{-177}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;n \cdot \frac{100 \cdot \left(i + \left(i \cdot i\right) \cdot \left(0.5 - \frac{0.5}{n}\right)\right)}{i}\\ \end{array} \]
Alternative 10
Accuracy65.4%
Cost1228
\[\begin{array}{l} \mathbf{if}\;n \leq -2.2 \cdot 10^{+237}:\\ \;\;\;\;100 \cdot \frac{i \cdot n}{i}\\ \mathbf{elif}\;n \leq -1.22 \cdot 10^{-152}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \mathbf{elif}\;n \leq 7.6 \cdot 10^{-178}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;n \cdot \left(\left(i \cdot i\right) \cdot 16.666666666666668 + \left(100 + i \cdot 50\right)\right)\\ \end{array} \]
Alternative 11
Accuracy59.3%
Cost972
\[\begin{array}{l} \mathbf{if}\;n \leq -9.4 \cdot 10^{+47}:\\ \;\;\;\;100 \cdot \frac{i \cdot n}{i}\\ \mathbf{elif}\;n \leq -5.6 \cdot 10^{-293}:\\ \;\;\;\;100 \cdot \frac{i}{\frac{i}{n}}\\ \mathbf{elif}\;n \leq 3.2 \cdot 10^{-227}:\\ \;\;\;\;16.666666666666668 \cdot \left(n \cdot \left(i \cdot i\right)\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \left(n + \left(i \cdot n\right) \cdot 0.5\right)\\ \end{array} \]
Alternative 12
Accuracy65.2%
Cost972
\[\begin{array}{l} \mathbf{if}\;n \leq -1.05 \cdot 10^{+238}:\\ \;\;\;\;100 \cdot \frac{i \cdot n}{i}\\ \mathbf{elif}\;n \leq -1.1 \cdot 10^{-151}:\\ \;\;\;\;100 \cdot \frac{n}{1 + i \cdot -0.5}\\ \mathbf{elif}\;n \leq 2.1 \cdot 10^{-177}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \mathbf{else}:\\ \;\;\;\;n \cdot \left(100 + \left(i \cdot i\right) \cdot 16.666666666666668\right)\\ \end{array} \]
Alternative 13
Accuracy62.0%
Cost841
\[\begin{array}{l} \mathbf{if}\;n \leq -8 \cdot 10^{-153} \lor \neg \left(n \leq 8.8 \cdot 10^{-181}\right):\\ \;\;\;\;100 \cdot \left(n + \left(i \cdot n\right) \cdot 0.5\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 14
Accuracy63.6%
Cost841
\[\begin{array}{l} \mathbf{if}\;n \leq -9.5 \cdot 10^{-154} \lor \neg \left(n \leq 4 \cdot 10^{-177}\right):\\ \;\;\;\;n \cdot \left(100 + \left(i \cdot i\right) \cdot 16.666666666666668\right)\\ \mathbf{else}:\\ \;\;\;\;100 \cdot \frac{0}{\frac{i}{n}}\\ \end{array} \]
Alternative 15
Accuracy57.0%
Cost712
\[\begin{array}{l} \mathbf{if}\;i \leq -5 \cdot 10^{+159}:\\ \;\;\;\;100 \cdot \left(i \cdot \frac{n}{i}\right)\\ \mathbf{elif}\;i \leq 1.1 \cdot 10^{-56}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;16.666666666666668 \cdot \left(n \cdot \left(i \cdot i\right)\right)\\ \end{array} \]
Alternative 16
Accuracy57.3%
Cost712
\[\begin{array}{l} \mathbf{if}\;i \leq -1.1 \cdot 10^{+158}:\\ \;\;\;\;100 \cdot \frac{i}{\frac{i}{n}}\\ \mathbf{elif}\;i \leq 1.1 \cdot 10^{-56}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;16.666666666666668 \cdot \left(n \cdot \left(i \cdot i\right)\right)\\ \end{array} \]
Alternative 17
Accuracy58.1%
Cost712
\[\begin{array}{l} \mathbf{if}\;i \leq -2.45 \cdot 10^{-11}:\\ \;\;\;\;\frac{i \cdot 100}{\frac{i}{n}}\\ \mathbf{elif}\;i \leq 1.1 \cdot 10^{-56}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;16.666666666666668 \cdot \left(n \cdot \left(i \cdot i\right)\right)\\ \end{array} \]
Alternative 18
Accuracy54.5%
Cost580
\[\begin{array}{l} \mathbf{if}\;i \leq 1.1 \cdot 10^{-56}:\\ \;\;\;\;n \cdot 100\\ \mathbf{else}:\\ \;\;\;\;16.666666666666668 \cdot \left(n \cdot \left(i \cdot i\right)\right)\\ \end{array} \]
Alternative 19
Accuracy2.8%
Cost192
\[i \cdot -50 \]
Alternative 20
Accuracy49.6%
Cost192
\[n \cdot 100 \]

Reproduce?

herbie shell --seed 2023178 
(FPCore (i n)
  :name "Compound Interest"
  :precision binary64

  :herbie-target
  (* 100.0 (/ (- (exp (* n (if (== (+ 1.0 (/ i n)) 1.0) (/ i n) (/ (* (/ i n) (log (+ 1.0 (/ i n)))) (- (+ (/ i n) 1.0) 1.0))))) 1.0) (/ i n)))

  (* 100.0 (/ (- (pow (+ 1.0 (/ i n)) n) 1.0) (/ i n))))