FRP.Yampa.Vector3:vector3Rho from Yampa-0.10.2

Percentage Accurate: 44.8% → 99.3%
Time: 2.5s
Alternatives: 4
Speedup: 111.0×

Specification

?
\[\begin{array}{l} \\ \sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \end{array} \]
(FPCore (x y z) :precision binary64 (sqrt (+ (+ (* x x) (* y y)) (* z z))))
double code(double x, double y, double z) {
	return sqrt((((x * x) + (y * y)) + (z * z)));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = sqrt((((x * x) + (y * y)) + (z * z)))
end function
public static double code(double x, double y, double z) {
	return Math.sqrt((((x * x) + (y * y)) + (z * z)));
}
def code(x, y, z):
	return math.sqrt((((x * x) + (y * y)) + (z * z)))
function code(x, y, z)
	return sqrt(Float64(Float64(Float64(x * x) + Float64(y * y)) + Float64(z * z)))
end
function tmp = code(x, y, z)
	tmp = sqrt((((x * x) + (y * y)) + (z * z)));
end
code[x_, y_, z_] := N[Sqrt[N[(N[(N[(x * x), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision] + N[(z * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z}
\end{array}

Sampling outcomes in binary64 precision:

Local Percentage Accuracy vs ?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Accuracy vs Speed?

Herbie found 4 alternatives:

AlternativeAccuracySpeedup
The accuracy (vertical axis) and speed (horizontal axis) of each alternatives. Up and to the right is better. The red square shows the initial program, and each blue circle shows an alternative.The line shows the best available speed-accuracy tradeoffs.

Initial Program: 44.8% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \end{array} \]
(FPCore (x y z) :precision binary64 (sqrt (+ (+ (* x x) (* y y)) (* z z))))
double code(double x, double y, double z) {
	return sqrt((((x * x) + (y * y)) + (z * z)));
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = sqrt((((x * x) + (y * y)) + (z * z)))
end function
public static double code(double x, double y, double z) {
	return Math.sqrt((((x * x) + (y * y)) + (z * z)));
}
def code(x, y, z):
	return math.sqrt((((x * x) + (y * y)) + (z * z)))
function code(x, y, z)
	return sqrt(Float64(Float64(Float64(x * x) + Float64(y * y)) + Float64(z * z)))
end
function tmp = code(x, y, z)
	tmp = sqrt((((x * x) + (y * y)) + (z * z)));
end
code[x_, y_, z_] := N[Sqrt[N[(N[(N[(x * x), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision] + N[(z * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
\begin{array}{l}

\\
\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z}
\end{array}

Alternative 1: 99.3% accurate, 1.1× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \mathsf{hypot}\left(z, x\right) \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z) :precision binary64 (hypot z x))
assert(x < y && y < z);
double code(double x, double y, double z) {
	return hypot(z, x);
}
assert x < y && y < z;
public static double code(double x, double y, double z) {
	return Math.hypot(z, x);
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	return math.hypot(z, x)
x, y, z = sort([x, y, z])
function code(x, y, z)
	return hypot(z, x)
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp = code(x, y, z)
	tmp = hypot(z, x);
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := N[Sqrt[z ^ 2 + x ^ 2], $MachinePrecision]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\mathsf{hypot}\left(z, x\right)
\end{array}
Derivation
  1. Initial program 44.8%

    \[\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \]
  2. Taylor expanded in y around 0 29.8%

    \[\leadsto \color{blue}{\sqrt{{z}^{2} + {x}^{2}}} \]
  3. Step-by-step derivation
    1. unpow229.8%

      \[\leadsto \sqrt{\color{blue}{z \cdot z} + {x}^{2}} \]
    2. unpow229.8%

      \[\leadsto \sqrt{z \cdot z + \color{blue}{x \cdot x}} \]
    3. hypot-def69.5%

      \[\leadsto \color{blue}{\mathsf{hypot}\left(z, x\right)} \]
  4. Simplified69.5%

    \[\leadsto \color{blue}{\mathsf{hypot}\left(z, x\right)} \]
  5. Final simplification69.5%

    \[\leadsto \mathsf{hypot}\left(z, x\right) \]

Alternative 2: 78.4% accurate, 1.0× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;z \leq 1780000:\\ \;\;\;\;\mathsf{hypot}\left(y, x\right)\\ \mathbf{elif}\;z \leq 7.4 \cdot 10^{+22}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq 7.2 \cdot 10^{+111}:\\ \;\;\;\;\mathsf{hypot}\left(y, x\right)\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (if (<= z 1780000.0)
   (hypot y x)
   (if (<= z 7.4e+22) z (if (<= z 7.2e+111) (hypot y x) z))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double tmp;
	if (z <= 1780000.0) {
		tmp = hypot(y, x);
	} else if (z <= 7.4e+22) {
		tmp = z;
	} else if (z <= 7.2e+111) {
		tmp = hypot(y, x);
	} else {
		tmp = z;
	}
	return tmp;
}
assert x < y && y < z;
public static double code(double x, double y, double z) {
	double tmp;
	if (z <= 1780000.0) {
		tmp = Math.hypot(y, x);
	} else if (z <= 7.4e+22) {
		tmp = z;
	} else if (z <= 7.2e+111) {
		tmp = Math.hypot(y, x);
	} else {
		tmp = z;
	}
	return tmp;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	tmp = 0
	if z <= 1780000.0:
		tmp = math.hypot(y, x)
	elif z <= 7.4e+22:
		tmp = z
	elif z <= 7.2e+111:
		tmp = math.hypot(y, x)
	else:
		tmp = z
	return tmp
x, y, z = sort([x, y, z])
function code(x, y, z)
	tmp = 0.0
	if (z <= 1780000.0)
		tmp = hypot(y, x);
	elseif (z <= 7.4e+22)
		tmp = z;
	elseif (z <= 7.2e+111)
		tmp = hypot(y, x);
	else
		tmp = z;
	end
	return tmp
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z <= 1780000.0)
		tmp = hypot(y, x);
	elseif (z <= 7.4e+22)
		tmp = z;
	elseif (z <= 7.2e+111)
		tmp = hypot(y, x);
	else
		tmp = z;
	end
	tmp_2 = tmp;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := If[LessEqual[z, 1780000.0], N[Sqrt[y ^ 2 + x ^ 2], $MachinePrecision], If[LessEqual[z, 7.4e+22], z, If[LessEqual[z, 7.2e+111], N[Sqrt[y ^ 2 + x ^ 2], $MachinePrecision], z]]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
\mathbf{if}\;z \leq 1780000:\\
\;\;\;\;\mathsf{hypot}\left(y, x\right)\\

\mathbf{elif}\;z \leq 7.4 \cdot 10^{+22}:\\
\;\;\;\;z\\

\mathbf{elif}\;z \leq 7.2 \cdot 10^{+111}:\\
\;\;\;\;\mathsf{hypot}\left(y, x\right)\\

\mathbf{else}:\\
\;\;\;\;z\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if z < 1.78e6 or 7.3999999999999996e22 < z < 7.2000000000000004e111

    1. Initial program 48.8%

      \[\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \]
    2. Taylor expanded in z around 0 40.1%

      \[\leadsto \color{blue}{\sqrt{{y}^{2} + {x}^{2}}} \]
    3. Step-by-step derivation
      1. unpow240.1%

        \[\leadsto \sqrt{\color{blue}{y \cdot y} + {x}^{2}} \]
      2. unpow240.1%

        \[\leadsto \sqrt{y \cdot y + \color{blue}{x \cdot x}} \]
      3. hypot-def78.4%

        \[\leadsto \color{blue}{\mathsf{hypot}\left(y, x\right)} \]
    4. Simplified78.4%

      \[\leadsto \color{blue}{\mathsf{hypot}\left(y, x\right)} \]

    if 1.78e6 < z < 7.3999999999999996e22 or 7.2000000000000004e111 < z

    1. Initial program 23.6%

      \[\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \]
    2. Taylor expanded in z around inf 81.3%

      \[\leadsto \color{blue}{z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification78.8%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq 1780000:\\ \;\;\;\;\mathsf{hypot}\left(y, x\right)\\ \mathbf{elif}\;z \leq 7.4 \cdot 10^{+22}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq 7.2 \cdot 10^{+111}:\\ \;\;\;\;\mathsf{hypot}\left(y, x\right)\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \]

Alternative 3: 77.8% accurate, 13.6× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ \begin{array}{l} \mathbf{if}\;z \leq 2050000:\\ \;\;\;\;-x\\ \mathbf{elif}\;z \leq 2.6 \cdot 10^{+23}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq 3.5 \cdot 10^{+112}:\\ \;\;\;\;-x\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z)
 :precision binary64
 (if (<= z 2050000.0)
   (- x)
   (if (<= z 2.6e+23) z (if (<= z 3.5e+112) (- x) z))))
assert(x < y && y < z);
double code(double x, double y, double z) {
	double tmp;
	if (z <= 2050000.0) {
		tmp = -x;
	} else if (z <= 2.6e+23) {
		tmp = z;
	} else if (z <= 3.5e+112) {
		tmp = -x;
	} else {
		tmp = z;
	}
	return tmp;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (z <= 2050000.0d0) then
        tmp = -x
    else if (z <= 2.6d+23) then
        tmp = z
    else if (z <= 3.5d+112) then
        tmp = -x
    else
        tmp = z
    end if
    code = tmp
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	double tmp;
	if (z <= 2050000.0) {
		tmp = -x;
	} else if (z <= 2.6e+23) {
		tmp = z;
	} else if (z <= 3.5e+112) {
		tmp = -x;
	} else {
		tmp = z;
	}
	return tmp;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	tmp = 0
	if z <= 2050000.0:
		tmp = -x
	elif z <= 2.6e+23:
		tmp = z
	elif z <= 3.5e+112:
		tmp = -x
	else:
		tmp = z
	return tmp
x, y, z = sort([x, y, z])
function code(x, y, z)
	tmp = 0.0
	if (z <= 2050000.0)
		tmp = Float64(-x);
	elseif (z <= 2.6e+23)
		tmp = z;
	elseif (z <= 3.5e+112)
		tmp = Float64(-x);
	else
		tmp = z;
	end
	return tmp
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z <= 2050000.0)
		tmp = -x;
	elseif (z <= 2.6e+23)
		tmp = z;
	elseif (z <= 3.5e+112)
		tmp = -x;
	else
		tmp = z;
	end
	tmp_2 = tmp;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := If[LessEqual[z, 2050000.0], (-x), If[LessEqual[z, 2.6e+23], z, If[LessEqual[z, 3.5e+112], (-x), z]]]
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
\begin{array}{l}
\mathbf{if}\;z \leq 2050000:\\
\;\;\;\;-x\\

\mathbf{elif}\;z \leq 2.6 \cdot 10^{+23}:\\
\;\;\;\;z\\

\mathbf{elif}\;z \leq 3.5 \cdot 10^{+112}:\\
\;\;\;\;-x\\

\mathbf{else}:\\
\;\;\;\;z\\


\end{array}
\end{array}
Derivation
  1. Split input into 2 regimes
  2. if z < 2.05e6 or 2.59999999999999992e23 < z < 3.49999999999999997e112

    1. Initial program 48.8%

      \[\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \]
    2. Taylor expanded in x around -inf 24.7%

      \[\leadsto \color{blue}{-1 \cdot x} \]
    3. Step-by-step derivation
      1. mul-1-neg24.7%

        \[\leadsto \color{blue}{-x} \]
    4. Simplified24.7%

      \[\leadsto \color{blue}{-x} \]

    if 2.05e6 < z < 2.59999999999999992e23 or 3.49999999999999997e112 < z

    1. Initial program 23.6%

      \[\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \]
    2. Taylor expanded in z around inf 81.3%

      \[\leadsto \color{blue}{z} \]
  3. Recombined 2 regimes into one program.
  4. Final simplification33.5%

    \[\leadsto \begin{array}{l} \mathbf{if}\;z \leq 2050000:\\ \;\;\;\;-x\\ \mathbf{elif}\;z \leq 2.6 \cdot 10^{+23}:\\ \;\;\;\;z\\ \mathbf{elif}\;z \leq 3.5 \cdot 10^{+112}:\\ \;\;\;\;-x\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \]

Alternative 4: 50.9% accurate, 111.0× speedup?

\[\begin{array}{l} [x, y, z] = \mathsf{sort}([x, y, z])\\ \\ z \end{array} \]
NOTE: x, y, and z should be sorted in increasing order before calling this function.
(FPCore (x y z) :precision binary64 z)
assert(x < y && y < z);
double code(double x, double y, double z) {
	return z;
}
NOTE: x, y, and z should be sorted in increasing order before calling this function.
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    code = z
end function
assert x < y && y < z;
public static double code(double x, double y, double z) {
	return z;
}
[x, y, z] = sort([x, y, z])
def code(x, y, z):
	return z
x, y, z = sort([x, y, z])
function code(x, y, z)
	return z
end
x, y, z = num2cell(sort([x, y, z])){:}
function tmp = code(x, y, z)
	tmp = z;
end
NOTE: x, y, and z should be sorted in increasing order before calling this function.
code[x_, y_, z_] := z
\begin{array}{l}
[x, y, z] = \mathsf{sort}([x, y, z])\\
\\
z
\end{array}
Derivation
  1. Initial program 44.8%

    \[\sqrt{\left(x \cdot x + y \cdot y\right) + z \cdot z} \]
  2. Taylor expanded in z around inf 18.3%

    \[\leadsto \color{blue}{z} \]
  3. Final simplification18.3%

    \[\leadsto z \]

Developer target: 70.7% accurate, 1.0× speedup?

\[\begin{array}{l} \\ \begin{array}{l} \mathbf{if}\;z < -6.396479394109776 \cdot 10^{+136}:\\ \;\;\;\;-z\\ \mathbf{elif}\;z < 7.320293694404182 \cdot 10^{+117}:\\ \;\;\;\;\sqrt{\left(z \cdot z + x \cdot x\right) + y \cdot y}\\ \mathbf{else}:\\ \;\;\;\;z\\ \end{array} \end{array} \]
(FPCore (x y z)
 :precision binary64
 (if (< z -6.396479394109776e+136)
   (- z)
   (if (< z 7.320293694404182e+117) (sqrt (+ (+ (* z z) (* x x)) (* y y))) z)))
double code(double x, double y, double z) {
	double tmp;
	if (z < -6.396479394109776e+136) {
		tmp = -z;
	} else if (z < 7.320293694404182e+117) {
		tmp = sqrt((((z * z) + (x * x)) + (y * y)));
	} else {
		tmp = z;
	}
	return tmp;
}
real(8) function code(x, y, z)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    real(8), intent (in) :: z
    real(8) :: tmp
    if (z < (-6.396479394109776d+136)) then
        tmp = -z
    else if (z < 7.320293694404182d+117) then
        tmp = sqrt((((z * z) + (x * x)) + (y * y)))
    else
        tmp = z
    end if
    code = tmp
end function
public static double code(double x, double y, double z) {
	double tmp;
	if (z < -6.396479394109776e+136) {
		tmp = -z;
	} else if (z < 7.320293694404182e+117) {
		tmp = Math.sqrt((((z * z) + (x * x)) + (y * y)));
	} else {
		tmp = z;
	}
	return tmp;
}
def code(x, y, z):
	tmp = 0
	if z < -6.396479394109776e+136:
		tmp = -z
	elif z < 7.320293694404182e+117:
		tmp = math.sqrt((((z * z) + (x * x)) + (y * y)))
	else:
		tmp = z
	return tmp
function code(x, y, z)
	tmp = 0.0
	if (z < -6.396479394109776e+136)
		tmp = Float64(-z);
	elseif (z < 7.320293694404182e+117)
		tmp = sqrt(Float64(Float64(Float64(z * z) + Float64(x * x)) + Float64(y * y)));
	else
		tmp = z;
	end
	return tmp
end
function tmp_2 = code(x, y, z)
	tmp = 0.0;
	if (z < -6.396479394109776e+136)
		tmp = -z;
	elseif (z < 7.320293694404182e+117)
		tmp = sqrt((((z * z) + (x * x)) + (y * y)));
	else
		tmp = z;
	end
	tmp_2 = tmp;
end
code[x_, y_, z_] := If[Less[z, -6.396479394109776e+136], (-z), If[Less[z, 7.320293694404182e+117], N[Sqrt[N[(N[(N[(z * z), $MachinePrecision] + N[(x * x), $MachinePrecision]), $MachinePrecision] + N[(y * y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], z]]
\begin{array}{l}

\\
\begin{array}{l}
\mathbf{if}\;z < -6.396479394109776 \cdot 10^{+136}:\\
\;\;\;\;-z\\

\mathbf{elif}\;z < 7.320293694404182 \cdot 10^{+117}:\\
\;\;\;\;\sqrt{\left(z \cdot z + x \cdot x\right) + y \cdot y}\\

\mathbf{else}:\\
\;\;\;\;z\\


\end{array}
\end{array}

Reproduce

?
herbie shell --seed 2023171 
(FPCore (x y z)
  :name "FRP.Yampa.Vector3:vector3Rho from Yampa-0.10.2"
  :precision binary64

  :herbie-target
  (if (< z -6.396479394109776e+136) (- z) (if (< z 7.320293694404182e+117) (sqrt (+ (+ (* z z) (* x x)) (* y y))) z))

  (sqrt (+ (+ (* x x) (* y y)) (* z z))))