\[0 \leq e \land e \leq 1\]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\frac{e \cdot \sin v}{1 + e \cdot \cos v}
\]
↓
\[\begin{array}{l}
\\
\frac{e \cdot \sin v}{1 + e \cdot \cos v}
\end{array}
\]
(FPCore (e v) :precision binary64 (/ (* e (sin v)) (+ 1.0 (* e (cos v))))) ↓
(FPCore (e v) :precision binary64 (/ (* e (sin v)) (+ 1.0 (* e (cos v))))) double code(double e, double v) {
return (e * sin(v)) / (1.0 + (e * cos(v)));
}
↓
double code(double e, double v) {
return (e * sin(v)) / (1.0 + (e * cos(v)));
}
real(8) function code(e, v)
real(8), intent (in) :: e
real(8), intent (in) :: v
code = (e * sin(v)) / (1.0d0 + (e * cos(v)))
end function
↓
real(8) function code(e, v)
real(8), intent (in) :: e
real(8), intent (in) :: v
code = (e * sin(v)) / (1.0d0 + (e * cos(v)))
end function
public static double code(double e, double v) {
return (e * Math.sin(v)) / (1.0 + (e * Math.cos(v)));
}
↓
public static double code(double e, double v) {
return (e * Math.sin(v)) / (1.0 + (e * Math.cos(v)));
}
def code(e, v):
return (e * math.sin(v)) / (1.0 + (e * math.cos(v)))
↓
def code(e, v):
return (e * math.sin(v)) / (1.0 + (e * math.cos(v)))
function code(e, v)
return Float64(Float64(e * sin(v)) / Float64(1.0 + Float64(e * cos(v))))
end
↓
function code(e, v)
return Float64(Float64(e * sin(v)) / Float64(1.0 + Float64(e * cos(v))))
end
function tmp = code(e, v)
tmp = (e * sin(v)) / (1.0 + (e * cos(v)));
end
↓
function tmp = code(e, v)
tmp = (e * sin(v)) / (1.0 + (e * cos(v)));
end
code[e_, v_] := N[(N[(e * N[Sin[v], $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[(e * N[Cos[v], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[e_, v_] := N[(N[(e * N[Sin[v], $MachinePrecision]), $MachinePrecision] / N[(1.0 + N[(e * N[Cos[v], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{e \cdot \sin v}{1 + e \cdot \cos v}
↓
\begin{array}{l}
\\
\frac{e \cdot \sin v}{1 + e \cdot \cos v}
\end{array}
Alternatives Alternative 1 Accuracy 99.8% Cost 13376
\[\frac{e \cdot \sin v}{1 + e \cdot \cos v}
\]
Alternative 2 Accuracy 99.6% Cost 13248
\[\frac{\sin v}{\cos v + \frac{1}{e}}
\]
Alternative 3 Accuracy 98.7% Cost 6848
\[\frac{e \cdot \sin v}{e + 1}
\]
Alternative 4 Accuracy 97.9% Cost 6592
\[e \cdot \sin v
\]
Alternative 5 Accuracy 52.0% Cost 1344
\[\frac{e}{v \cdot \left(e \cdot -0.5 - \left(e + 1\right) \cdot -0.16666666666666666\right) + \left(\frac{e}{v} + \frac{1}{v}\right)}
\]
Alternative 6 Accuracy 52.0% Cost 1088
\[\frac{e}{\left(\frac{e}{v} + \frac{1}{v}\right) + v \cdot \left(e \cdot -0.5 - -0.16666666666666666\right)}
\]
Alternative 7 Accuracy 51.6% Cost 960
\[\frac{e}{\left(\frac{e}{v} + \frac{1}{v}\right) + v \cdot \left(e \cdot -0.3333333333333333\right)}
\]
Alternative 8 Accuracy 51.1% Cost 576
\[\frac{e}{\frac{1}{v} + v \cdot 0.16666666666666666}
\]
Alternative 9 Accuracy 50.4% Cost 448
\[e \cdot \left(v - e \cdot v\right)
\]
Alternative 10 Accuracy 50.9% Cost 448
\[e \cdot \frac{v}{e + 1}
\]
Alternative 11 Accuracy 50.9% Cost 448
\[\frac{e \cdot v}{e + 1}
\]
Alternative 12 Accuracy 50.0% Cost 192
\[e \cdot v
\]
Alternative 13 Accuracy 4.5% Cost 64
\[v
\]