Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
\]
↓
\[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
\]
(FPCore (x y z t) :precision binary64 (- 1.0 (/ x (* (- y z) (- y t))))) ↓
(FPCore (x y z t) :precision binary64 (- 1.0 (/ x (* (- y z) (- y t))))) double code(double x, double y, double z, double t) {
return 1.0 - (x / ((y - z) * (y - t)));
}
↓
double code(double x, double y, double z, double t) {
return 1.0 - (x / ((y - z) * (y - t)));
}
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = 1.0d0 - (x / ((y - z) * (y - t)))
end function
↓
real(8) function code(x, y, z, t)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8), intent (in) :: t
code = 1.0d0 - (x / ((y - z) * (y - t)))
end function
public static double code(double x, double y, double z, double t) {
return 1.0 - (x / ((y - z) * (y - t)));
}
↓
public static double code(double x, double y, double z, double t) {
return 1.0 - (x / ((y - z) * (y - t)));
}
def code(x, y, z, t):
return 1.0 - (x / ((y - z) * (y - t)))
↓
def code(x, y, z, t):
return 1.0 - (x / ((y - z) * (y - t)))
function code(x, y, z, t)
return Float64(1.0 - Float64(x / Float64(Float64(y - z) * Float64(y - t))))
end
↓
function code(x, y, z, t)
return Float64(1.0 - Float64(x / Float64(Float64(y - z) * Float64(y - t))))
end
function tmp = code(x, y, z, t)
tmp = 1.0 - (x / ((y - z) * (y - t)));
end
↓
function tmp = code(x, y, z, t)
tmp = 1.0 - (x / ((y - z) * (y - t)));
end
code[x_, y_, z_, t_] := N[(1.0 - N[(x / N[(N[(y - z), $MachinePrecision] * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_, t_] := N[(1.0 - N[(x / N[(N[(y - z), $MachinePrecision] * N[(y - t), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
↓
1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
Alternatives Alternative 1 Accuracy 99.1% Cost 704
\[1 - \frac{x}{\left(y - z\right) \cdot \left(y - t\right)}
\]
Alternative 2 Accuracy 84.5% Cost 841
\[\begin{array}{l}
\mathbf{if}\;y \leq -3.5 \cdot 10^{-142} \lor \neg \left(y \leq 3.55 \cdot 10^{-178}\right):\\
\;\;\;\;1 - \frac{x}{y \cdot \left(y - z\right)}\\
\mathbf{else}:\\
\;\;\;\;1 - \frac{x}{z \cdot t}\\
\end{array}
\]
Alternative 3 Accuracy 88.7% Cost 841
\[\begin{array}{l}
\mathbf{if}\;z \leq -4.4 \lor \neg \left(z \leq 8.5 \cdot 10^{-230}\right):\\
\;\;\;\;1 - \frac{x}{z \cdot \left(t - y\right)}\\
\mathbf{else}:\\
\;\;\;\;1 - \frac{x}{y \cdot \left(y - t\right)}\\
\end{array}
\]
Alternative 4 Accuracy 86.6% Cost 840
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.15 \cdot 10^{-141}:\\
\;\;\;\;1 - \frac{x}{y \cdot \left(y - z\right)}\\
\mathbf{elif}\;y \leq 2.7 \cdot 10^{-101}:\\
\;\;\;\;1 - \frac{x}{z \cdot \left(t - y\right)}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 5 Accuracy 86.2% Cost 840
\[\begin{array}{l}
\mathbf{if}\;z \leq -2:\\
\;\;\;\;1 - \frac{x}{z \cdot \left(t - y\right)}\\
\mathbf{elif}\;z \leq 5.5 \cdot 10^{-234}:\\
\;\;\;\;1 - \frac{x}{y \cdot \left(y - t\right)}\\
\mathbf{else}:\\
\;\;\;\;1 + \frac{\frac{x}{t}}{y - z}\\
\end{array}
\]
Alternative 6 Accuracy 83.0% Cost 712
\[\begin{array}{l}
\mathbf{if}\;y \leq -2.8 \cdot 10^{-74}:\\
\;\;\;\;1\\
\mathbf{elif}\;y \leq 1.15 \cdot 10^{-142}:\\
\;\;\;\;1 - \frac{x}{z \cdot t}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 7 Accuracy 82.2% Cost 712
\[\begin{array}{l}
\mathbf{if}\;y \leq -4.9 \cdot 10^{-40}:\\
\;\;\;\;1 - \frac{x}{y \cdot y}\\
\mathbf{elif}\;y \leq 2.1 \cdot 10^{-142}:\\
\;\;\;\;1 - \frac{x}{z \cdot t}\\
\mathbf{else}:\\
\;\;\;\;1\\
\end{array}
\]
Alternative 8 Accuracy 74.8% Cost 64
\[1
\]