Graphics.Rendering.Plot.Render.Plot.Legend:renderLegendOutside from plot-0.2.3.4, C

Percentage Accurate: 99.9% → 100.0%

Time: 4.3s

Precision: binary64

Cost: 6848

• 21.1% of points produce a very large (infinite) output. You may want to add a precondition.

Math

\[x \cdot \left(y + z\right) + z \cdot 5 \]

↓

\[\mathsf{fma}\left(z, 5, x \cdot \left(z + y\right)\right) \]

FPCore

(FPCore (x y z) :precision binary64 (+ (* x (+ y z)) (* z 5.0)))

↓

(FPCore (x y z) :precision binary64 (fma z 5.0 (* x (+ z y))))

C

double code(double x, double y, double z) {
	return (x * (y + z)) + (z * 5.0);
}

↓

double code(double x, double y, double z) {
	return fma(z, 5.0, (x * (z + y)));
}

Julia

function code(x, y, z)
	return Float64(Float64(x * Float64(y + z)) + Float64(z * 5.0))
end

↓

function code(x, y, z)
	return fma(z, 5.0, Float64(x * Float64(z + y)))
end

Wolfram

code[x_, y_, z_] := N[(N[(x * N[(y + z), $MachinePrecision]), $MachinePrecision] + N[(z * 5.0), $MachinePrecision]), $MachinePrecision]

↓

code[x_, y_, z_] := N[(z * 5.0 + N[(x * N[(z + y), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]

Target

Original	99.9%
Target	98.1%
Herbie	100.0%

\[\left(x + 5\right) \cdot z + x \cdot y \]

Derivation

1. Initial program 99.9%

   \[x \cdot \left(y + z\right) + z \cdot 5 \]

2. Applied egg-rr 100.0%

   \[\leadsto \color{blue}{\mathsf{fma}\left(z, 5, x \cdot \left(y + z\right)\right)} \]
   Step-by-step derivation

   [Start] 99.9%	\[ x \cdot \left(y + z\right) + z \cdot 5 \]
   +-commutative [=>] 99.9%	\[ \color{blue}{z \cdot 5 + x \cdot \left(y + z\right)} \]
   fma-def [=>] 100.0%	\[ \color{blue}{\mathsf{fma}\left(z, 5, x \cdot \left(y + z\right)\right)} \]

3. Final simplification 100.0%

   \[\leadsto \mathsf{fma}\left(z, 5, x \cdot \left(z + y\right)\right) \]

Alternatives

Alternative 1
Accuracy	100.0%
Cost	6848

\[\mathsf{fma}\left(z, 5, x \cdot \left(z + y\right)\right) \]

Alternative 2
Accuracy	53.2%
Cost	588

\[\begin{array}{l} \mathbf{if}\;y \leq -2.6 \cdot 10^{+37}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;y \leq -3 \cdot 10^{-264}:\\ \;\;\;\;z \cdot 5\\ \mathbf{elif}\;y \leq 2.35 \cdot 10^{-73}:\\ \;\;\;\;z \cdot x\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]

Alternative 3
Accuracy	83.3%
Cost	585

\[\begin{array}{l} \mathbf{if}\;x \leq -2.75 \cdot 10^{-135} \lor \neg \left(x \leq 2 \cdot 10^{-17}\right):\\ \;\;\;\;x \cdot \left(z + y\right)\\ \mathbf{else}:\\ \;\;\;\;z \cdot \left(5 + x\right)\\ \end{array} \]

Alternative 4
Accuracy	75.2%
Cost	584

\[\begin{array}{l} \mathbf{if}\;y \leq -3.8 \cdot 10^{+43}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;y \leq 3 \cdot 10^{+21}:\\ \;\;\;\;z \cdot \left(5 + x\right)\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]

Alternative 5
Accuracy	99.9%
Cost	576

\[x \cdot \left(z + y\right) + z \cdot 5 \]

Alternative 6
Accuracy	60.3%
Cost	456

\[\begin{array}{l} \mathbf{if}\;x \leq -1.1 \cdot 10^{-135}:\\ \;\;\;\;x \cdot y\\ \mathbf{elif}\;x \leq 4 \cdot 10^{-16}:\\ \;\;\;\;z \cdot 5\\ \mathbf{else}:\\ \;\;\;\;x \cdot y\\ \end{array} \]

Alternative 7
Accuracy	36.7%
Cost	192

\[z \cdot 5 \]

Reproduce

herbie shell --seed 2023165 
(FPCore (x y z)
  :name "Graphics.Rendering.Plot.Render.Plot.Legend:renderLegendOutside from plot-0.2.3.4, C"
  :precision binary64

  :herbie-target
  (+ (* (+ x 5.0) z) (* x y))

  (+ (* x (+ y z)) (* z 5.0)))