Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\left|\frac{x + 4}{y} - \frac{x}{y} \cdot z\right|
\]
↓
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.15 \cdot 10^{+89}:\\
\;\;\;\;\left|\left(1 - z\right) \cdot \frac{x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;\left|\frac{\left(x + 4\right) - x \cdot z}{y}\right|\\
\end{array}
\]
(FPCore (x y z) :precision binary64 (fabs (- (/ (+ x 4.0) y) (* (/ x y) z)))) ↓
(FPCore (x y z)
:precision binary64
(if (<= x -1.15e+89)
(fabs (* (- 1.0 z) (/ x y)))
(fabs (/ (- (+ x 4.0) (* x z)) y)))) double code(double x, double y, double z) {
return fabs((((x + 4.0) / y) - ((x / y) * z)));
}
↓
double code(double x, double y, double z) {
double tmp;
if (x <= -1.15e+89) {
tmp = fabs(((1.0 - z) * (x / y)));
} else {
tmp = fabs((((x + 4.0) - (x * z)) / y));
}
return tmp;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = abs((((x + 4.0d0) / y) - ((x / y) * z)))
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8) :: tmp
if (x <= (-1.15d+89)) then
tmp = abs(((1.0d0 - z) * (x / y)))
else
tmp = abs((((x + 4.0d0) - (x * z)) / y))
end if
code = tmp
end function
public static double code(double x, double y, double z) {
return Math.abs((((x + 4.0) / y) - ((x / y) * z)));
}
↓
public static double code(double x, double y, double z) {
double tmp;
if (x <= -1.15e+89) {
tmp = Math.abs(((1.0 - z) * (x / y)));
} else {
tmp = Math.abs((((x + 4.0) - (x * z)) / y));
}
return tmp;
}
def code(x, y, z):
return math.fabs((((x + 4.0) / y) - ((x / y) * z)))
↓
def code(x, y, z):
tmp = 0
if x <= -1.15e+89:
tmp = math.fabs(((1.0 - z) * (x / y)))
else:
tmp = math.fabs((((x + 4.0) - (x * z)) / y))
return tmp
function code(x, y, z)
return abs(Float64(Float64(Float64(x + 4.0) / y) - Float64(Float64(x / y) * z)))
end
↓
function code(x, y, z)
tmp = 0.0
if (x <= -1.15e+89)
tmp = abs(Float64(Float64(1.0 - z) * Float64(x / y)));
else
tmp = abs(Float64(Float64(Float64(x + 4.0) - Float64(x * z)) / y));
end
return tmp
end
function tmp = code(x, y, z)
tmp = abs((((x + 4.0) / y) - ((x / y) * z)));
end
↓
function tmp_2 = code(x, y, z)
tmp = 0.0;
if (x <= -1.15e+89)
tmp = abs(((1.0 - z) * (x / y)));
else
tmp = abs((((x + 4.0) - (x * z)) / y));
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[Abs[N[(N[(N[(x + 4.0), $MachinePrecision] / y), $MachinePrecision] - N[(N[(x / y), $MachinePrecision] * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]
↓
code[x_, y_, z_] := If[LessEqual[x, -1.15e+89], N[Abs[N[(N[(1.0 - z), $MachinePrecision] * N[(x / y), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], N[Abs[N[(N[(N[(x + 4.0), $MachinePrecision] - N[(x * z), $MachinePrecision]), $MachinePrecision] / y), $MachinePrecision]], $MachinePrecision]]
\left|\frac{x + 4}{y} - \frac{x}{y} \cdot z\right|
↓
\begin{array}{l}
\mathbf{if}\;x \leq -1.15 \cdot 10^{+89}:\\
\;\;\;\;\left|\left(1 - z\right) \cdot \frac{x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;\left|\frac{\left(x + 4\right) - x \cdot z}{y}\right|\\
\end{array}
Alternatives Alternative 1 Accuracy 98.1% Cost 7108
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.15 \cdot 10^{+89}:\\
\;\;\;\;\left|\left(1 - z\right) \cdot \frac{x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;\left|\frac{\left(x + 4\right) - x \cdot z}{y}\right|\\
\end{array}
\]
Alternative 2 Accuracy 68.9% Cost 7381
\[\begin{array}{l}
t_0 := \left|z \cdot \frac{x}{y}\right|\\
\mathbf{if}\;x \leq -1.6 \cdot 10^{-22}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;x \leq 1.6 \cdot 10^{-55}:\\
\;\;\;\;\left|\frac{4}{y}\right|\\
\mathbf{elif}\;x \leq 2500000000 \lor \neg \left(x \leq 6.8 \cdot 10^{+31}\right) \land x \leq 1.45 \cdot 10^{+101}:\\
\;\;\;\;t_0\\
\mathbf{else}:\\
\;\;\;\;\left|\frac{x}{y}\right|\\
\end{array}
\]
Alternative 3 Accuracy 69.0% Cost 7381
\[\begin{array}{l}
t_0 := \left|z \cdot \frac{x}{y}\right|\\
\mathbf{if}\;x \leq -3.5 \cdot 10^{-14}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;x \leq 1.2 \cdot 10^{-56}:\\
\;\;\;\;\left|\frac{4}{y}\right|\\
\mathbf{elif}\;x \leq 1040000000:\\
\;\;\;\;\left|\frac{x \cdot z}{y}\right|\\
\mathbf{elif}\;x \leq 6.4 \cdot 10^{+31} \lor \neg \left(x \leq 9.5 \cdot 10^{+100}\right):\\
\;\;\;\;\left|\frac{x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;t_0\\
\end{array}
\]
Alternative 4 Accuracy 86.3% Cost 7113
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.65 \cdot 10^{-18} \lor \neg \left(x \leq 2.25 \cdot 10^{-57}\right):\\
\;\;\;\;\left|\left(1 - z\right) \cdot \frac{x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;\left|\frac{4}{y}\right|\\
\end{array}
\]
Alternative 5 Accuracy 86.2% Cost 6984
\[\begin{array}{l}
\mathbf{if}\;z \leq -2.5 \cdot 10^{+55}:\\
\;\;\;\;\left|\frac{x}{\frac{y}{z}}\right|\\
\mathbf{elif}\;z \leq 9.8 \cdot 10^{+79}:\\
\;\;\;\;\left|\frac{-4 - x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;\left|z \cdot \frac{x}{y}\right|\\
\end{array}
\]
Alternative 6 Accuracy 69.5% Cost 6857
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.5 \lor \neg \left(x \leq 4\right):\\
\;\;\;\;\left|\frac{x}{y}\right|\\
\mathbf{else}:\\
\;\;\;\;\left|\frac{4}{y}\right|\\
\end{array}
\]
Alternative 7 Accuracy 40.5% Cost 6592
\[\left|\frac{4}{y}\right|
\]