Math FPCore C Julia Wolfram TeX \[\frac{e^{x} - e^{-x}}{2}
\]
↓
\[\begin{array}{l}
t_0 := e^{x} - e^{-x}\\
\mathbf{if}\;t_0 \leq -\infty \lor \neg \left(t_0 \leq 4 \cdot 10^{-14}\right):\\
\;\;\;\;\frac{t_0}{2}\\
\mathbf{else}:\\
\;\;\;\;\frac{\mathsf{fma}\left(0.0003968253968253968, {x}^{7}, \mathsf{fma}\left(0.3333333333333333, {x}^{3}, \left(x + x\right) + 0.016666666666666666 \cdot {x}^{5}\right)\right)}{2}\\
\end{array}
\]
(FPCore (x) :precision binary64 (/ (- (exp x) (exp (- x))) 2.0)) ↓
(FPCore (x)
:precision binary64
(let* ((t_0 (- (exp x) (exp (- x)))))
(if (or (<= t_0 (- INFINITY)) (not (<= t_0 4e-14)))
(/ t_0 2.0)
(/
(fma
0.0003968253968253968
(pow x 7.0)
(fma
0.3333333333333333
(pow x 3.0)
(+ (+ x x) (* 0.016666666666666666 (pow x 5.0)))))
2.0)))) double code(double x) {
return (exp(x) - exp(-x)) / 2.0;
}
↓
double code(double x) {
double t_0 = exp(x) - exp(-x);
double tmp;
if ((t_0 <= -((double) INFINITY)) || !(t_0 <= 4e-14)) {
tmp = t_0 / 2.0;
} else {
tmp = fma(0.0003968253968253968, pow(x, 7.0), fma(0.3333333333333333, pow(x, 3.0), ((x + x) + (0.016666666666666666 * pow(x, 5.0))))) / 2.0;
}
return tmp;
}
function code(x)
return Float64(Float64(exp(x) - exp(Float64(-x))) / 2.0)
end
↓
function code(x)
t_0 = Float64(exp(x) - exp(Float64(-x)))
tmp = 0.0
if ((t_0 <= Float64(-Inf)) || !(t_0 <= 4e-14))
tmp = Float64(t_0 / 2.0);
else
tmp = Float64(fma(0.0003968253968253968, (x ^ 7.0), fma(0.3333333333333333, (x ^ 3.0), Float64(Float64(x + x) + Float64(0.016666666666666666 * (x ^ 5.0))))) / 2.0);
end
return tmp
end
code[x_] := N[(N[(N[Exp[x], $MachinePrecision] - N[Exp[(-x)], $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]
↓
code[x_] := Block[{t$95$0 = N[(N[Exp[x], $MachinePrecision] - N[Exp[(-x)], $MachinePrecision]), $MachinePrecision]}, If[Or[LessEqual[t$95$0, (-Infinity)], N[Not[LessEqual[t$95$0, 4e-14]], $MachinePrecision]], N[(t$95$0 / 2.0), $MachinePrecision], N[(N[(0.0003968253968253968 * N[Power[x, 7.0], $MachinePrecision] + N[(0.3333333333333333 * N[Power[x, 3.0], $MachinePrecision] + N[(N[(x + x), $MachinePrecision] + N[(0.016666666666666666 * N[Power[x, 5.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] / 2.0), $MachinePrecision]]]
\frac{e^{x} - e^{-x}}{2}
↓
\begin{array}{l}
t_0 := e^{x} - e^{-x}\\
\mathbf{if}\;t_0 \leq -\infty \lor \neg \left(t_0 \leq 4 \cdot 10^{-14}\right):\\
\;\;\;\;\frac{t_0}{2}\\
\mathbf{else}:\\
\;\;\;\;\frac{\mathsf{fma}\left(0.0003968253968253968, {x}^{7}, \mathsf{fma}\left(0.3333333333333333, {x}^{3}, \left(x + x\right) + 0.016666666666666666 \cdot {x}^{5}\right)\right)}{2}\\
\end{array}
Alternatives Alternative 1 Accuracy 99.5% Cost 46729
\[\begin{array}{l}
t_0 := e^{x} - e^{-x}\\
\mathbf{if}\;t_0 \leq -\infty \lor \neg \left(t_0 \leq 4 \cdot 10^{-14}\right):\\
\;\;\;\;\frac{t_0}{2}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot 2 + \left(0.3333333333333333 \cdot {x}^{3} + \left(0.016666666666666666 \cdot {x}^{5} + 0.0003968253968253968 \cdot {x}^{7}\right)\right)}{2}\\
\end{array}
\]
Alternative 2 Accuracy 99.5% Cost 39433
\[\begin{array}{l}
t_0 := e^{x} - e^{-x}\\
\mathbf{if}\;t_0 \leq -0.1 \lor \neg \left(t_0 \leq 4 \cdot 10^{-14}\right):\\
\;\;\;\;\frac{t_0}{2}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot 2}{2}\\
\end{array}
\]
Alternative 3 Accuracy 93.4% Cost 7049
\[\begin{array}{l}
\mathbf{if}\;x \leq -5.6 \lor \neg \left(x \leq 5.7\right):\\
\;\;\;\;\frac{0.0003968253968253968 \cdot {x}^{7}}{2}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot \left(2 + x \cdot \left(x \cdot 0.3333333333333333\right)\right)}{2}\\
\end{array}
\]
Alternative 4 Accuracy 88.2% Cost 1865
\[\begin{array}{l}
t_0 := x \cdot \left(x \cdot 0.3333333333333333\right)\\
\mathbf{if}\;x \leq -4 \cdot 10^{+154} \lor \neg \left(x \leq 2 \cdot 10^{+102}\right):\\
\;\;\;\;x \cdot \frac{1}{\frac{6}{x \cdot x}}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot \frac{t_0 \cdot \left(0.3333333333333333 \cdot \left(x \cdot x\right)\right) - 4}{t_0 - 2}}{2}\\
\end{array}
\]
Alternative 5 Accuracy 84.1% Cost 841
\[\begin{array}{l}
\mathbf{if}\;x \leq -2.5 \lor \neg \left(x \leq 2.4\right):\\
\;\;\;\;x \cdot \frac{1}{\frac{6}{x \cdot x}}\\
\mathbf{else}:\\
\;\;\;\;\frac{x \cdot 2}{2}\\
\end{array}
\]
Alternative 6 Accuracy 84.4% Cost 704
\[\frac{x \cdot \left(2 + x \cdot \left(x \cdot 0.3333333333333333\right)\right)}{2}
\]
Alternative 7 Accuracy 53.0% Cost 320
\[\frac{x \cdot 2}{2}
\]
Alternative 8 Accuracy 2.9% Cost 64
\[-1
\]
Alternative 9 Accuracy 3.5% Cost 64
\[0
\]