Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
\]
↓
\[\frac{1}{\sin B} - \frac{x}{\tan B}
\]
(FPCore (B x)
:precision binary64
(+ (- (* x (/ 1.0 (tan B)))) (/ 1.0 (sin B)))) ↓
(FPCore (B x) :precision binary64 (- (/ 1.0 (sin B)) (/ x (tan B)))) double code(double B, double x) {
return -(x * (1.0 / tan(B))) + (1.0 / sin(B));
}
↓
double code(double B, double x) {
return (1.0 / sin(B)) - (x / tan(B));
}
real(8) function code(b, x)
real(8), intent (in) :: b
real(8), intent (in) :: x
code = -(x * (1.0d0 / tan(b))) + (1.0d0 / sin(b))
end function
↓
real(8) function code(b, x)
real(8), intent (in) :: b
real(8), intent (in) :: x
code = (1.0d0 / sin(b)) - (x / tan(b))
end function
public static double code(double B, double x) {
return -(x * (1.0 / Math.tan(B))) + (1.0 / Math.sin(B));
}
↓
public static double code(double B, double x) {
return (1.0 / Math.sin(B)) - (x / Math.tan(B));
}
def code(B, x):
return -(x * (1.0 / math.tan(B))) + (1.0 / math.sin(B))
↓
def code(B, x):
return (1.0 / math.sin(B)) - (x / math.tan(B))
function code(B, x)
return Float64(Float64(-Float64(x * Float64(1.0 / tan(B)))) + Float64(1.0 / sin(B)))
end
↓
function code(B, x)
return Float64(Float64(1.0 / sin(B)) - Float64(x / tan(B)))
end
function tmp = code(B, x)
tmp = -(x * (1.0 / tan(B))) + (1.0 / sin(B));
end
↓
function tmp = code(B, x)
tmp = (1.0 / sin(B)) - (x / tan(B));
end
code[B_, x_] := N[((-N[(x * N[(1.0 / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]) + N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
↓
code[B_, x_] := N[(N[(1.0 / N[Sin[B], $MachinePrecision]), $MachinePrecision] - N[(x / N[Tan[B], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\left(-x \cdot \frac{1}{\tan B}\right) + \frac{1}{\sin B}
↓
\frac{1}{\sin B} - \frac{x}{\tan B}
Alternatives Alternative 1 Accuracy 98.6% Cost 13316
\[\begin{array}{l}
\mathbf{if}\;x \leq -17000000000000:\\
\;\;\;\;\frac{\cos B}{\sin B} \cdot \left(-x\right)\\
\mathbf{elif}\;x \leq 2.9:\\
\;\;\;\;\frac{1}{\sin B} - \frac{x}{B}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{1}{x} + -1}{\tan B}\\
\end{array}
\]
Alternative 2 Accuracy 98.6% Cost 13316
\[\begin{array}{l}
\mathbf{if}\;x \leq -17000000000000:\\
\;\;\;\;\frac{\cos B \cdot \left(-x\right)}{\sin B}\\
\mathbf{elif}\;x \leq 2.6:\\
\;\;\;\;\frac{1}{\sin B} - \frac{x}{B}\\
\mathbf{else}:\\
\;\;\;\;x \cdot \frac{\frac{1}{x} + -1}{\tan B}\\
\end{array}
\]
Alternative 3 Accuracy 98.6% Cost 7241
\[\begin{array}{l}
\mathbf{if}\;x \leq -17000000000000 \lor \neg \left(x \leq 2.3\right):\\
\;\;\;\;x \cdot \frac{\frac{1}{x} + -1}{\tan B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B} - \frac{x}{B}\\
\end{array}
\]
Alternative 4 Accuracy 76.2% Cost 6921
\[\begin{array}{l}
\mathbf{if}\;x \leq -1.05 \lor \neg \left(x \leq 1.05\right):\\
\;\;\;\;\frac{-x}{\sin B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B}\\
\end{array}
\]
Alternative 5 Accuracy 75.0% Cost 6857
\[\begin{array}{l}
\mathbf{if}\;x \leq -0.0105 \lor \neg \left(x \leq 3.95 \cdot 10^{-7}\right):\\
\;\;\;\;\left(B \cdot 0.16666666666666666 + \frac{1}{B}\right) - \frac{x}{B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{\sin B}\\
\end{array}
\]
Alternative 6 Accuracy 77.1% Cost 6720
\[\frac{1 - x}{\sin B}
\]
Alternative 7 Accuracy 51.3% Cost 704
\[\left(B \cdot 0.16666666666666666 + \frac{1}{B}\right) - \frac{x}{B}
\]
Alternative 8 Accuracy 50.3% Cost 521
\[\begin{array}{l}
\mathbf{if}\;x \leq -0.01 \lor \neg \left(x \leq 1\right):\\
\;\;\;\;-\frac{x}{B}\\
\mathbf{else}:\\
\;\;\;\;\frac{1}{B}\\
\end{array}
\]
Alternative 9 Accuracy 51.2% Cost 320
\[\frac{1 - x}{B}
\]
Alternative 10 Accuracy 3.1% Cost 192
\[B \cdot 0.16666666666666666
\]
Alternative 11 Accuracy 26.5% Cost 192
\[\frac{1}{B}
\]