\[ \begin{array}{c}[x, y, z] = \mathsf{sort}([x, y, z])\\ \end{array} \]
Math FPCore C Fortran Java Python Julia MATLAB Wolfram TeX \[2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
\]
↓
\[\begin{array}{l}
\mathbf{if}\;y \leq -9.2 \cdot 10^{+36}:\\
\;\;\;\;2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-x\right) - z\right) - \log \left(\frac{-1}{y}\right)\right)}\right)}^{2}\\
\mathbf{elif}\;y \leq 8.5 \cdot 10^{-262}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right) + y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
(FPCore (x y z)
:precision binary64
(* 2.0 (sqrt (+ (+ (* x y) (* x z)) (* y z))))) ↓
(FPCore (x y z)
:precision binary64
(if (<= y -9.2e+36)
(* 2.0 (pow (exp (* 0.25 (- (log (- (- x) z)) (log (/ -1.0 y))))) 2.0))
(if (<= y 8.5e-262)
(* 2.0 (sqrt (+ (* z (+ y x)) (* y x))))
(* 2.0 (* (sqrt z) (sqrt y)))))) double code(double x, double y, double z) {
return 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
}
↓
double code(double x, double y, double z) {
double tmp;
if (y <= -9.2e+36) {
tmp = 2.0 * pow(exp((0.25 * (log((-x - z)) - log((-1.0 / y))))), 2.0);
} else if (y <= 8.5e-262) {
tmp = 2.0 * sqrt(((z * (y + x)) + (y * x)));
} else {
tmp = 2.0 * (sqrt(z) * sqrt(y));
}
return tmp;
}
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
code = 2.0d0 * sqrt((((x * y) + (x * z)) + (y * z)))
end function
↓
real(8) function code(x, y, z)
real(8), intent (in) :: x
real(8), intent (in) :: y
real(8), intent (in) :: z
real(8) :: tmp
if (y <= (-9.2d+36)) then
tmp = 2.0d0 * (exp((0.25d0 * (log((-x - z)) - log(((-1.0d0) / y))))) ** 2.0d0)
else if (y <= 8.5d-262) then
tmp = 2.0d0 * sqrt(((z * (y + x)) + (y * x)))
else
tmp = 2.0d0 * (sqrt(z) * sqrt(y))
end if
code = tmp
end function
public static double code(double x, double y, double z) {
return 2.0 * Math.sqrt((((x * y) + (x * z)) + (y * z)));
}
↓
public static double code(double x, double y, double z) {
double tmp;
if (y <= -9.2e+36) {
tmp = 2.0 * Math.pow(Math.exp((0.25 * (Math.log((-x - z)) - Math.log((-1.0 / y))))), 2.0);
} else if (y <= 8.5e-262) {
tmp = 2.0 * Math.sqrt(((z * (y + x)) + (y * x)));
} else {
tmp = 2.0 * (Math.sqrt(z) * Math.sqrt(y));
}
return tmp;
}
def code(x, y, z):
return 2.0 * math.sqrt((((x * y) + (x * z)) + (y * z)))
↓
def code(x, y, z):
tmp = 0
if y <= -9.2e+36:
tmp = 2.0 * math.pow(math.exp((0.25 * (math.log((-x - z)) - math.log((-1.0 / y))))), 2.0)
elif y <= 8.5e-262:
tmp = 2.0 * math.sqrt(((z * (y + x)) + (y * x)))
else:
tmp = 2.0 * (math.sqrt(z) * math.sqrt(y))
return tmp
function code(x, y, z)
return Float64(2.0 * sqrt(Float64(Float64(Float64(x * y) + Float64(x * z)) + Float64(y * z))))
end
↓
function code(x, y, z)
tmp = 0.0
if (y <= -9.2e+36)
tmp = Float64(2.0 * (exp(Float64(0.25 * Float64(log(Float64(Float64(-x) - z)) - log(Float64(-1.0 / y))))) ^ 2.0));
elseif (y <= 8.5e-262)
tmp = Float64(2.0 * sqrt(Float64(Float64(z * Float64(y + x)) + Float64(y * x))));
else
tmp = Float64(2.0 * Float64(sqrt(z) * sqrt(y)));
end
return tmp
end
function tmp = code(x, y, z)
tmp = 2.0 * sqrt((((x * y) + (x * z)) + (y * z)));
end
↓
function tmp_2 = code(x, y, z)
tmp = 0.0;
if (y <= -9.2e+36)
tmp = 2.0 * (exp((0.25 * (log((-x - z)) - log((-1.0 / y))))) ^ 2.0);
elseif (y <= 8.5e-262)
tmp = 2.0 * sqrt(((z * (y + x)) + (y * x)));
else
tmp = 2.0 * (sqrt(z) * sqrt(y));
end
tmp_2 = tmp;
end
code[x_, y_, z_] := N[(2.0 * N[Sqrt[N[(N[(N[(x * y), $MachinePrecision] + N[(x * z), $MachinePrecision]), $MachinePrecision] + N[(y * z), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_, z_] := If[LessEqual[y, -9.2e+36], N[(2.0 * N[Power[N[Exp[N[(0.25 * N[(N[Log[N[((-x) - z), $MachinePrecision]], $MachinePrecision] - N[Log[N[(-1.0 / y), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision], 2.0], $MachinePrecision]), $MachinePrecision], If[LessEqual[y, 8.5e-262], N[(2.0 * N[Sqrt[N[(N[(z * N[(y + x), $MachinePrecision]), $MachinePrecision] + N[(y * x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision], N[(2.0 * N[(N[Sqrt[z], $MachinePrecision] * N[Sqrt[y], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
2 \cdot \sqrt{\left(x \cdot y + x \cdot z\right) + y \cdot z}
↓
\begin{array}{l}
\mathbf{if}\;y \leq -9.2 \cdot 10^{+36}:\\
\;\;\;\;2 \cdot {\left(e^{0.25 \cdot \left(\log \left(\left(-x\right) - z\right) - \log \left(\frac{-1}{y}\right)\right)}\right)}^{2}\\
\mathbf{elif}\;y \leq 8.5 \cdot 10^{-262}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right) + y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
Alternatives Alternative 1 Accuracy 93.1% Cost 26564
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.05 \cdot 10^{+64}:\\
\;\;\;\;2 \cdot {\left(e^{0.25}\right)}^{\left(2 \cdot \left(\log \left(\left(-x\right) - z\right) - \log \left(\frac{-1}{y}\right)\right)\right)}\\
\mathbf{elif}\;y \leq 8.5 \cdot 10^{-262}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right) + y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 2 Accuracy 83.4% Cost 13508
\[\begin{array}{l}
\mathbf{if}\;y \leq 8.5 \cdot 10^{-262}:\\
\;\;\;\;2 \cdot \sqrt{\mathsf{fma}\left(z, y + x, y \cdot x\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 3 Accuracy 83.3% Cost 13252
\[\begin{array}{l}
\mathbf{if}\;y \leq 8.5 \cdot 10^{-262}:\\
\;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right) + y \cdot z}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \left(\sqrt{z} \cdot \sqrt{y}\right)\\
\end{array}
\]
Alternative 4 Accuracy 69.7% Cost 7104
\[2 \cdot \sqrt{x \cdot \left(y + z\right) + y \cdot z}
\]
Alternative 5 Accuracy 67.8% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;y \leq -1.65 \cdot 10^{-238}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 6 Accuracy 69.5% Cost 6980
\[\begin{array}{l}
\mathbf{if}\;y \leq -1 \cdot 10^{-275}:\\
\;\;\;\;2 \cdot \sqrt{x \cdot \left(y + z\right)}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{z \cdot \left(y + x\right)}\\
\end{array}
\]
Alternative 7 Accuracy 67.5% Cost 6852
\[\begin{array}{l}
\mathbf{if}\;y \leq -5 \cdot 10^{-310}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot x}\\
\mathbf{else}:\\
\;\;\;\;2 \cdot \sqrt{y \cdot z}\\
\end{array}
\]
Alternative 8 Accuracy 34.7% Cost 6720
\[2 \cdot \sqrt{y \cdot x}
\]