Math FPCore C Java Python Julia MATLAB Wolfram TeX \[\frac{\log \left(\sqrt{re \cdot re + im \cdot im}\right)}{\log 10}
\]
↓
\[\begin{array}{l}
t_0 := \sqrt{\log 10}\\
\frac{1}{t_0} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{t_0}
\end{array}
\]
(FPCore (re im)
:precision binary64
(/ (log (sqrt (+ (* re re) (* im im)))) (log 10.0))) ↓
(FPCore (re im)
:precision binary64
(let* ((t_0 (sqrt (log 10.0)))) (* (/ 1.0 t_0) (/ (log (hypot re im)) t_0)))) double code(double re, double im) {
return log(sqrt(((re * re) + (im * im)))) / log(10.0);
}
↓
double code(double re, double im) {
double t_0 = sqrt(log(10.0));
return (1.0 / t_0) * (log(hypot(re, im)) / t_0);
}
public static double code(double re, double im) {
return Math.log(Math.sqrt(((re * re) + (im * im)))) / Math.log(10.0);
}
↓
public static double code(double re, double im) {
double t_0 = Math.sqrt(Math.log(10.0));
return (1.0 / t_0) * (Math.log(Math.hypot(re, im)) / t_0);
}
def code(re, im):
return math.log(math.sqrt(((re * re) + (im * im)))) / math.log(10.0)
↓
def code(re, im):
t_0 = math.sqrt(math.log(10.0))
return (1.0 / t_0) * (math.log(math.hypot(re, im)) / t_0)
function code(re, im)
return Float64(log(sqrt(Float64(Float64(re * re) + Float64(im * im)))) / log(10.0))
end
↓
function code(re, im)
t_0 = sqrt(log(10.0))
return Float64(Float64(1.0 / t_0) * Float64(log(hypot(re, im)) / t_0))
end
function tmp = code(re, im)
tmp = log(sqrt(((re * re) + (im * im)))) / log(10.0);
end
↓
function tmp = code(re, im)
t_0 = sqrt(log(10.0));
tmp = (1.0 / t_0) * (log(hypot(re, im)) / t_0);
end
code[re_, im_] := N[(N[Log[N[Sqrt[N[(N[(re * re), $MachinePrecision] + N[(im * im), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision] / N[Log[10.0], $MachinePrecision]), $MachinePrecision]
↓
code[re_, im_] := Block[{t$95$0 = N[Sqrt[N[Log[10.0], $MachinePrecision]], $MachinePrecision]}, N[(N[(1.0 / t$95$0), $MachinePrecision] * N[(N[Log[N[Sqrt[re ^ 2 + im ^ 2], $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision]]
\frac{\log \left(\sqrt{re \cdot re + im \cdot im}\right)}{\log 10}
↓
\begin{array}{l}
t_0 := \sqrt{\log 10}\\
\frac{1}{t_0} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{t_0}
\end{array}
Alternatives Alternative 1 Accuracy 99.0% Cost 32448
\[3 \cdot \log \left(\sqrt[3]{{\left(\mathsf{hypot}\left(re, im\right)\right)}^{\left(\frac{-1}{\log 0.1}\right)}}\right)
\]
Alternative 2 Accuracy 99.0% Cost 19584
\[\frac{1}{\frac{\log 10}{\log \left(\mathsf{hypot}\left(re, im\right)\right)}}
\]
Alternative 3 Accuracy 99.0% Cost 19520
\[\frac{-\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\log 0.1}
\]
Alternative 4 Accuracy 99.1% Cost 19456
\[\frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\log 10}
\]
Alternative 5 Accuracy 43.6% Cost 13844
\[\begin{array}{l}
t_0 := \frac{-\log im}{\log 0.1}\\
t_1 := \log \left(\frac{-1}{re}\right)\\
t_2 := \frac{-t_1}{\log 10}\\
\mathbf{if}\;im \leq 5.5 \cdot 10^{-149}:\\
\;\;\;\;\frac{t_1}{\log 0.1}\\
\mathbf{elif}\;im \leq 3.8 \cdot 10^{-109}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;im \leq 6.6 \cdot 10^{-92}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;im \leq 2.55 \cdot 10^{-50}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;im \leq 4 \cdot 10^{-39}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;\frac{\log im}{\log 10}\\
\end{array}
\]
Alternative 6 Accuracy 43.7% Cost 13844
\[\begin{array}{l}
t_0 := \frac{-\log im}{\log 0.1}\\
t_1 := \log \left(\frac{-1}{re}\right)\\
t_2 := \frac{-t_1}{\log 10}\\
\mathbf{if}\;im \leq 3.05 \cdot 10^{-148}:\\
\;\;\;\;\frac{1}{\frac{-\log 10}{t_1}}\\
\mathbf{elif}\;im \leq 4.2 \cdot 10^{-109}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;im \leq 4.3 \cdot 10^{-94}:\\
\;\;\;\;t_2\\
\mathbf{elif}\;im \leq 2.9 \cdot 10^{-50}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;im \leq 3.6 \cdot 10^{-39}:\\
\;\;\;\;t_2\\
\mathbf{else}:\\
\;\;\;\;\frac{\log im}{\log 10}\\
\end{array}
\]
Alternative 7 Accuracy 43.6% Cost 13780
\[\begin{array}{l}
t_0 := \frac{-\log im}{\log 0.1}\\
t_1 := \frac{\log \left(\frac{-1}{re}\right)}{\log 0.1}\\
\mathbf{if}\;im \leq 5.6 \cdot 10^{-148}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;im \leq 3.8 \cdot 10^{-109}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;im \leq 5.9 \cdot 10^{-92}:\\
\;\;\;\;t_1\\
\mathbf{elif}\;im \leq 2.55 \cdot 10^{-50}:\\
\;\;\;\;t_0\\
\mathbf{elif}\;im \leq 4.2 \cdot 10^{-39}:\\
\;\;\;\;t_1\\
\mathbf{else}:\\
\;\;\;\;\frac{\log im}{\log 10}\\
\end{array}
\]
Alternative 8 Accuracy 34.3% Cost 13124
\[\begin{array}{l}
\mathbf{if}\;im \leq 2.4 \cdot 10^{-305}:\\
\;\;\;\;101\\
\mathbf{else}:\\
\;\;\;\;\frac{\log im}{\log 10}\\
\end{array}
\]
Alternative 9 Accuracy 5.1% Cost 64
\[-3
\]
Alternative 10 Accuracy 11.3% Cost 64
\[1.5
\]
Alternative 11 Accuracy 11.6% Cost 64
\[3
\]
Alternative 12 Accuracy 12.0% Cost 64
\[6
\]
Alternative 13 Accuracy 12.2% Cost 64
\[9
\]
Alternative 14 Accuracy 12.3% Cost 64
\[11
\]
Alternative 15 Accuracy 12.8% Cost 64
\[20
\]
Alternative 16 Accuracy 14.4% Cost 64
\[81
\]
Alternative 17 Accuracy 14.7% Cost 64
\[100
\]
Alternative 18 Accuracy 14.7% Cost 64
\[101
\]