math.log10 on complex, real part

?

Percentage Accurate: 51.0% → 99.1%
Time: 13.5s
Precision: binary64
Cost: 38912

?

\[\frac{\log \left(\sqrt{re \cdot re + im \cdot im}\right)}{\log 10} \]
\[\begin{array}{l} t_0 := \sqrt{\log 10}\\ \frac{1}{t_0} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{t_0} \end{array} \]
(FPCore (re im)
 :precision binary64
 (/ (log (sqrt (+ (* re re) (* im im)))) (log 10.0)))
(FPCore (re im)
 :precision binary64
 (let* ((t_0 (sqrt (log 10.0)))) (* (/ 1.0 t_0) (/ (log (hypot re im)) t_0))))
double code(double re, double im) {
	return log(sqrt(((re * re) + (im * im)))) / log(10.0);
}
double code(double re, double im) {
	double t_0 = sqrt(log(10.0));
	return (1.0 / t_0) * (log(hypot(re, im)) / t_0);
}
public static double code(double re, double im) {
	return Math.log(Math.sqrt(((re * re) + (im * im)))) / Math.log(10.0);
}
public static double code(double re, double im) {
	double t_0 = Math.sqrt(Math.log(10.0));
	return (1.0 / t_0) * (Math.log(Math.hypot(re, im)) / t_0);
}
def code(re, im):
	return math.log(math.sqrt(((re * re) + (im * im)))) / math.log(10.0)
def code(re, im):
	t_0 = math.sqrt(math.log(10.0))
	return (1.0 / t_0) * (math.log(math.hypot(re, im)) / t_0)
function code(re, im)
	return Float64(log(sqrt(Float64(Float64(re * re) + Float64(im * im)))) / log(10.0))
end
function code(re, im)
	t_0 = sqrt(log(10.0))
	return Float64(Float64(1.0 / t_0) * Float64(log(hypot(re, im)) / t_0))
end
function tmp = code(re, im)
	tmp = log(sqrt(((re * re) + (im * im)))) / log(10.0);
end
function tmp = code(re, im)
	t_0 = sqrt(log(10.0));
	tmp = (1.0 / t_0) * (log(hypot(re, im)) / t_0);
end
code[re_, im_] := N[(N[Log[N[Sqrt[N[(N[(re * re), $MachinePrecision] + N[(im * im), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]], $MachinePrecision] / N[Log[10.0], $MachinePrecision]), $MachinePrecision]
code[re_, im_] := Block[{t$95$0 = N[Sqrt[N[Log[10.0], $MachinePrecision]], $MachinePrecision]}, N[(N[(1.0 / t$95$0), $MachinePrecision] * N[(N[Log[N[Sqrt[re ^ 2 + im ^ 2], $MachinePrecision]], $MachinePrecision] / t$95$0), $MachinePrecision]), $MachinePrecision]]
\frac{\log \left(\sqrt{re \cdot re + im \cdot im}\right)}{\log 10}
\begin{array}{l}
t_0 := \sqrt{\log 10}\\
\frac{1}{t_0} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{t_0}
\end{array}

Local Percentage Accuracy?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Derivation?

  1. Initial program 51.4%

    \[\frac{\log \left(\sqrt{re \cdot re + im \cdot im}\right)}{\log 10} \]
  2. Simplified99.1%

    \[\leadsto \color{blue}{\frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\log 10}} \]
    Step-by-step derivation

    [Start]51.4

    \[ \frac{\log \left(\sqrt{re \cdot re + im \cdot im}\right)}{\log 10} \]

    hypot-def [=>]99.1

    \[ \frac{\log \color{blue}{\left(\mathsf{hypot}\left(re, im\right)\right)}}{\log 10} \]
  3. Applied egg-rr99.1%

    \[\leadsto \color{blue}{\frac{1}{\sqrt{\log 10}} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\sqrt{\log 10}}} \]
    Step-by-step derivation

    [Start]99.1

    \[ \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\log 10} \]

    *-un-lft-identity [=>]99.1

    \[ \frac{\color{blue}{1 \cdot \log \left(\mathsf{hypot}\left(re, im\right)\right)}}{\log 10} \]

    add-sqr-sqrt [=>]99.1

    \[ \frac{1 \cdot \log \left(\mathsf{hypot}\left(re, im\right)\right)}{\color{blue}{\sqrt{\log 10} \cdot \sqrt{\log 10}}} \]

    times-frac [=>]99.1

    \[ \color{blue}{\frac{1}{\sqrt{\log 10}} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\sqrt{\log 10}}} \]
  4. Final simplification99.1%

    \[\leadsto \frac{1}{\sqrt{\log 10}} \cdot \frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\sqrt{\log 10}} \]

Alternatives

Alternative 1
Accuracy99.0%
Cost32448
\[3 \cdot \log \left(\sqrt[3]{{\left(\mathsf{hypot}\left(re, im\right)\right)}^{\left(\frac{-1}{\log 0.1}\right)}}\right) \]
Alternative 2
Accuracy99.0%
Cost19584
\[\frac{1}{\frac{\log 10}{\log \left(\mathsf{hypot}\left(re, im\right)\right)}} \]
Alternative 3
Accuracy99.0%
Cost19520
\[\frac{-\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\log 0.1} \]
Alternative 4
Accuracy99.1%
Cost19456
\[\frac{\log \left(\mathsf{hypot}\left(re, im\right)\right)}{\log 10} \]
Alternative 5
Accuracy43.6%
Cost13844
\[\begin{array}{l} t_0 := \frac{-\log im}{\log 0.1}\\ t_1 := \log \left(\frac{-1}{re}\right)\\ t_2 := \frac{-t_1}{\log 10}\\ \mathbf{if}\;im \leq 5.5 \cdot 10^{-149}:\\ \;\;\;\;\frac{t_1}{\log 0.1}\\ \mathbf{elif}\;im \leq 3.8 \cdot 10^{-109}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;im \leq 6.6 \cdot 10^{-92}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;im \leq 2.55 \cdot 10^{-50}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;im \leq 4 \cdot 10^{-39}:\\ \;\;\;\;t_2\\ \mathbf{else}:\\ \;\;\;\;\frac{\log im}{\log 10}\\ \end{array} \]
Alternative 6
Accuracy43.7%
Cost13844
\[\begin{array}{l} t_0 := \frac{-\log im}{\log 0.1}\\ t_1 := \log \left(\frac{-1}{re}\right)\\ t_2 := \frac{-t_1}{\log 10}\\ \mathbf{if}\;im \leq 3.05 \cdot 10^{-148}:\\ \;\;\;\;\frac{1}{\frac{-\log 10}{t_1}}\\ \mathbf{elif}\;im \leq 4.2 \cdot 10^{-109}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;im \leq 4.3 \cdot 10^{-94}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;im \leq 2.9 \cdot 10^{-50}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;im \leq 3.6 \cdot 10^{-39}:\\ \;\;\;\;t_2\\ \mathbf{else}:\\ \;\;\;\;\frac{\log im}{\log 10}\\ \end{array} \]
Alternative 7
Accuracy43.6%
Cost13780
\[\begin{array}{l} t_0 := \frac{-\log im}{\log 0.1}\\ t_1 := \frac{\log \left(\frac{-1}{re}\right)}{\log 0.1}\\ \mathbf{if}\;im \leq 5.6 \cdot 10^{-148}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;im \leq 3.8 \cdot 10^{-109}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;im \leq 5.9 \cdot 10^{-92}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;im \leq 2.55 \cdot 10^{-50}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;im \leq 4.2 \cdot 10^{-39}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\frac{\log im}{\log 10}\\ \end{array} \]
Alternative 8
Accuracy34.3%
Cost13124
\[\begin{array}{l} \mathbf{if}\;im \leq 2.4 \cdot 10^{-305}:\\ \;\;\;\;101\\ \mathbf{else}:\\ \;\;\;\;\frac{\log im}{\log 10}\\ \end{array} \]
Alternative 9
Accuracy5.1%
Cost64
\[-3 \]
Alternative 10
Accuracy11.3%
Cost64
\[1.5 \]
Alternative 11
Accuracy11.6%
Cost64
\[3 \]
Alternative 12
Accuracy12.0%
Cost64
\[6 \]
Alternative 13
Accuracy12.2%
Cost64
\[9 \]
Alternative 14
Accuracy12.3%
Cost64
\[11 \]
Alternative 15
Accuracy12.8%
Cost64
\[20 \]
Alternative 16
Accuracy14.4%
Cost64
\[81 \]
Alternative 17
Accuracy14.7%
Cost64
\[100 \]
Alternative 18
Accuracy14.7%
Cost64
\[101 \]

Error

Reproduce?

herbie shell --seed 2023160 
(FPCore (re im)
  :name "math.log10 on complex, real part"
  :precision binary64
  (/ (log (sqrt (+ (* re re) (* im im)))) (log 10.0)))