x / (x^2 + 1)

?

Percentage Accurate: 77.3% → 100.0%
Time: 2.6s
Precision: binary64
Cost: 7048

?

\[\frac{x}{x \cdot x + 1} \]
\[\begin{array}{l} \mathbf{if}\;x \leq -4 \cdot 10^{+36}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 10000:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x} - {x}^{-3}\\ \end{array} \]
(FPCore (x) :precision binary64 (/ x (+ (* x x) 1.0)))
(FPCore (x)
 :precision binary64
 (if (<= x -4e+36)
   (/ 1.0 x)
   (if (<= x 10000.0) (/ x (+ 1.0 (* x x))) (- (/ 1.0 x) (pow x -3.0)))))
double code(double x) {
	return x / ((x * x) + 1.0);
}
double code(double x) {
	double tmp;
	if (x <= -4e+36) {
		tmp = 1.0 / x;
	} else if (x <= 10000.0) {
		tmp = x / (1.0 + (x * x));
	} else {
		tmp = (1.0 / x) - pow(x, -3.0);
	}
	return tmp;
}
real(8) function code(x)
    real(8), intent (in) :: x
    code = x / ((x * x) + 1.0d0)
end function
real(8) function code(x)
    real(8), intent (in) :: x
    real(8) :: tmp
    if (x <= (-4d+36)) then
        tmp = 1.0d0 / x
    else if (x <= 10000.0d0) then
        tmp = x / (1.0d0 + (x * x))
    else
        tmp = (1.0d0 / x) - (x ** (-3.0d0))
    end if
    code = tmp
end function
public static double code(double x) {
	return x / ((x * x) + 1.0);
}
public static double code(double x) {
	double tmp;
	if (x <= -4e+36) {
		tmp = 1.0 / x;
	} else if (x <= 10000.0) {
		tmp = x / (1.0 + (x * x));
	} else {
		tmp = (1.0 / x) - Math.pow(x, -3.0);
	}
	return tmp;
}
def code(x):
	return x / ((x * x) + 1.0)
def code(x):
	tmp = 0
	if x <= -4e+36:
		tmp = 1.0 / x
	elif x <= 10000.0:
		tmp = x / (1.0 + (x * x))
	else:
		tmp = (1.0 / x) - math.pow(x, -3.0)
	return tmp
function code(x)
	return Float64(x / Float64(Float64(x * x) + 1.0))
end
function code(x)
	tmp = 0.0
	if (x <= -4e+36)
		tmp = Float64(1.0 / x);
	elseif (x <= 10000.0)
		tmp = Float64(x / Float64(1.0 + Float64(x * x)));
	else
		tmp = Float64(Float64(1.0 / x) - (x ^ -3.0));
	end
	return tmp
end
function tmp = code(x)
	tmp = x / ((x * x) + 1.0);
end
function tmp_2 = code(x)
	tmp = 0.0;
	if (x <= -4e+36)
		tmp = 1.0 / x;
	elseif (x <= 10000.0)
		tmp = x / (1.0 + (x * x));
	else
		tmp = (1.0 / x) - (x ^ -3.0);
	end
	tmp_2 = tmp;
end
code[x_] := N[(x / N[(N[(x * x), $MachinePrecision] + 1.0), $MachinePrecision]), $MachinePrecision]
code[x_] := If[LessEqual[x, -4e+36], N[(1.0 / x), $MachinePrecision], If[LessEqual[x, 10000.0], N[(x / N[(1.0 + N[(x * x), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(1.0 / x), $MachinePrecision] - N[Power[x, -3.0], $MachinePrecision]), $MachinePrecision]]]
\frac{x}{x \cdot x + 1}
\begin{array}{l}
\mathbf{if}\;x \leq -4 \cdot 10^{+36}:\\
\;\;\;\;\frac{1}{x}\\

\mathbf{elif}\;x \leq 10000:\\
\;\;\;\;\frac{x}{1 + x \cdot x}\\

\mathbf{else}:\\
\;\;\;\;\frac{1}{x} - {x}^{-3}\\


\end{array}

Local Percentage Accuracy?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original77.3%
Target99.9%
Herbie100.0%
\[\frac{1}{x + \frac{1}{x}} \]

Derivation?

  1. Split input into 3 regimes
  2. if x < -4.00000000000000017e36

    1. Initial program 61.8%

      \[\frac{x}{x \cdot x + 1} \]
    2. Taylor expanded in x around inf 100.0%

      \[\leadsto \color{blue}{\frac{1}{x}} \]

    if -4.00000000000000017e36 < x < 1e4

    1. Initial program 100.0%

      \[\frac{x}{x \cdot x + 1} \]

    if 1e4 < x

    1. Initial program 59.7%

      \[\frac{x}{x \cdot x + 1} \]
    2. Taylor expanded in x around inf 100.0%

      \[\leadsto \color{blue}{\frac{1}{x} - \frac{1}{{x}^{3}}} \]
    3. Applied egg-rr100.0%

      \[\leadsto \frac{1}{x} - \color{blue}{\left(0 + {x}^{-3}\right)} \]
      Step-by-step derivation

      [Start]100.0

      \[ \frac{1}{x} - \frac{1}{{x}^{3}} \]

      add-log-exp [=>]99.0

      \[ \frac{1}{x} - \color{blue}{\log \left(e^{\frac{1}{{x}^{3}}}\right)} \]

      *-un-lft-identity [=>]99.0

      \[ \frac{1}{x} - \log \color{blue}{\left(1 \cdot e^{\frac{1}{{x}^{3}}}\right)} \]

      log-prod [=>]99.0

      \[ \frac{1}{x} - \color{blue}{\left(\log 1 + \log \left(e^{\frac{1}{{x}^{3}}}\right)\right)} \]

      metadata-eval [=>]99.0

      \[ \frac{1}{x} - \left(\color{blue}{0} + \log \left(e^{\frac{1}{{x}^{3}}}\right)\right) \]

      add-log-exp [<=]100.0

      \[ \frac{1}{x} - \left(0 + \color{blue}{\frac{1}{{x}^{3}}}\right) \]

      pow-flip [=>]100.0

      \[ \frac{1}{x} - \left(0 + \color{blue}{{x}^{\left(-3\right)}}\right) \]

      metadata-eval [=>]100.0

      \[ \frac{1}{x} - \left(0 + {x}^{\color{blue}{-3}}\right) \]
    4. Simplified100.0%

      \[\leadsto \frac{1}{x} - \color{blue}{{x}^{-3}} \]
      Step-by-step derivation

      [Start]100.0

      \[ \frac{1}{x} - \left(0 + {x}^{-3}\right) \]

      +-lft-identity [=>]100.0

      \[ \frac{1}{x} - \color{blue}{{x}^{-3}} \]
  3. Recombined 3 regimes into one program.
  4. Final simplification100.0%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -4 \cdot 10^{+36}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 10000:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x} - {x}^{-3}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy100.0%
Cost712
\[\begin{array}{l} \mathbf{if}\;x \leq -4 \cdot 10^{+36}:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 100000000:\\ \;\;\;\;\frac{x}{1 + x \cdot x}\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 2
Accuracy99.0%
Cost456
\[\begin{array}{l} \mathbf{if}\;x \leq -1:\\ \;\;\;\;\frac{1}{x}\\ \mathbf{elif}\;x \leq 1:\\ \;\;\;\;x\\ \mathbf{else}:\\ \;\;\;\;\frac{1}{x}\\ \end{array} \]
Alternative 3
Accuracy53.1%
Cost64
\[x \]

Error

Reproduce?

herbie shell --seed 2023159 
(FPCore (x)
  :name "x / (x^2 + 1)"
  :precision binary64

  :herbie-target
  (/ 1.0 (+ x (/ 1.0 x)))

  (/ x (+ (* x x) 1.0)))