Ian Simplification

?

Percentage Accurate: 6.7% → 9.6%
Time: 23.5s
Precision: binary64
Cost: 26436

?

\[\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right) \]
\[\begin{array}{l} \mathbf{if}\;x \leq -1.65 \cdot 10^{-162}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(0.5 - 0.5 \cdot x\right)}^{1.5}}\right)\\ \mathbf{elif}\;x \leq 1.65 \cdot 10^{-162}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \left(\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right) + -1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{1}{\sqrt{\frac{2}{1 - x}}}\right)\\ \end{array} \]
(FPCore (x)
 :precision binary64
 (- (/ PI 2.0) (* 2.0 (asin (sqrt (/ (- 1.0 x) 2.0))))))
(FPCore (x)
 :precision binary64
 (if (<= x -1.65e-162)
   (- (/ PI 2.0) (* 2.0 (asin (cbrt (pow (- 0.5 (* 0.5 x)) 1.5)))))
   (if (<= x 1.65e-162)
     (- (/ PI 2.0) (* 2.0 (+ (+ 1.0 (asin (sqrt 0.5))) -1.0)))
     (- (/ PI 2.0) (* 2.0 (asin (/ 1.0 (sqrt (/ 2.0 (- 1.0 x))))))))))
double code(double x) {
	return (((double) M_PI) / 2.0) - (2.0 * asin(sqrt(((1.0 - x) / 2.0))));
}
double code(double x) {
	double tmp;
	if (x <= -1.65e-162) {
		tmp = (((double) M_PI) / 2.0) - (2.0 * asin(cbrt(pow((0.5 - (0.5 * x)), 1.5))));
	} else if (x <= 1.65e-162) {
		tmp = (((double) M_PI) / 2.0) - (2.0 * ((1.0 + asin(sqrt(0.5))) + -1.0));
	} else {
		tmp = (((double) M_PI) / 2.0) - (2.0 * asin((1.0 / sqrt((2.0 / (1.0 - x))))));
	}
	return tmp;
}
public static double code(double x) {
	return (Math.PI / 2.0) - (2.0 * Math.asin(Math.sqrt(((1.0 - x) / 2.0))));
}
public static double code(double x) {
	double tmp;
	if (x <= -1.65e-162) {
		tmp = (Math.PI / 2.0) - (2.0 * Math.asin(Math.cbrt(Math.pow((0.5 - (0.5 * x)), 1.5))));
	} else if (x <= 1.65e-162) {
		tmp = (Math.PI / 2.0) - (2.0 * ((1.0 + Math.asin(Math.sqrt(0.5))) + -1.0));
	} else {
		tmp = (Math.PI / 2.0) - (2.0 * Math.asin((1.0 / Math.sqrt((2.0 / (1.0 - x))))));
	}
	return tmp;
}
function code(x)
	return Float64(Float64(pi / 2.0) - Float64(2.0 * asin(sqrt(Float64(Float64(1.0 - x) / 2.0)))))
end
function code(x)
	tmp = 0.0
	if (x <= -1.65e-162)
		tmp = Float64(Float64(pi / 2.0) - Float64(2.0 * asin(cbrt((Float64(0.5 - Float64(0.5 * x)) ^ 1.5)))));
	elseif (x <= 1.65e-162)
		tmp = Float64(Float64(pi / 2.0) - Float64(2.0 * Float64(Float64(1.0 + asin(sqrt(0.5))) + -1.0)));
	else
		tmp = Float64(Float64(pi / 2.0) - Float64(2.0 * asin(Float64(1.0 / sqrt(Float64(2.0 / Float64(1.0 - x)))))));
	end
	return tmp
end
code[x_] := N[(N[(Pi / 2.0), $MachinePrecision] - N[(2.0 * N[ArcSin[N[Sqrt[N[(N[(1.0 - x), $MachinePrecision] / 2.0), $MachinePrecision]], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
code[x_] := If[LessEqual[x, -1.65e-162], N[(N[(Pi / 2.0), $MachinePrecision] - N[(2.0 * N[ArcSin[N[Power[N[Power[N[(0.5 - N[(0.5 * x), $MachinePrecision]), $MachinePrecision], 1.5], $MachinePrecision], 1/3], $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision], If[LessEqual[x, 1.65e-162], N[(N[(Pi / 2.0), $MachinePrecision] - N[(2.0 * N[(N[(1.0 + N[ArcSin[N[Sqrt[0.5], $MachinePrecision]], $MachinePrecision]), $MachinePrecision] + -1.0), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], N[(N[(Pi / 2.0), $MachinePrecision] - N[(2.0 * N[ArcSin[N[(1.0 / N[Sqrt[N[(2.0 / N[(1.0 - x), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]]]
\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right)
\begin{array}{l}
\mathbf{if}\;x \leq -1.65 \cdot 10^{-162}:\\
\;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(0.5 - 0.5 \cdot x\right)}^{1.5}}\right)\\

\mathbf{elif}\;x \leq 1.65 \cdot 10^{-162}:\\
\;\;\;\;\frac{\pi}{2} - 2 \cdot \left(\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right) + -1\right)\\

\mathbf{else}:\\
\;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{1}{\sqrt{\frac{2}{1 - x}}}\right)\\


\end{array}

Local Percentage Accuracy?

The average percentage accuracy by input value. Horizontal axis shows value of an input variable; the variable is choosen in the title. Vertical axis is accuracy; higher is better. Red represent the original program, while blue represents Herbie's suggestion. These can be toggled with buttons below the plot. The line is an average while dots represent individual samples.

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original6.7%
Target100.0%
Herbie9.6%
\[\sin^{-1} x \]

Derivation?

  1. Split input into 3 regimes
  2. if x < -1.65000000000000007e-162

    1. Initial program 14.7%

      \[\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right) \]
    2. Applied egg-rr14.8%

      \[\leadsto \frac{\pi}{2} - 2 \cdot \sin^{-1} \color{blue}{\left(\sqrt[3]{{\left(0.5 - x \cdot 0.5\right)}^{1.5}}\right)} \]
      Step-by-step derivation

      [Start]14.7

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right) \]

      add-cbrt-cube [=>]14.7

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \color{blue}{\left(\sqrt[3]{\left(\sqrt{\frac{1 - x}{2}} \cdot \sqrt{\frac{1 - x}{2}}\right) \cdot \sqrt{\frac{1 - x}{2}}}\right)} \]

      add-sqr-sqrt [<=]14.7

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{\color{blue}{\frac{1 - x}{2}} \cdot \sqrt{\frac{1 - x}{2}}}\right) \]

      pow1 [=>]14.7

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{\color{blue}{{\left(\frac{1 - x}{2}\right)}^{1}} \cdot \sqrt{\frac{1 - x}{2}}}\right) \]

      pow1/2 [=>]14.7

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(\frac{1 - x}{2}\right)}^{1} \cdot \color{blue}{{\left(\frac{1 - x}{2}\right)}^{0.5}}}\right) \]

      pow-prod-up [=>]14.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{\color{blue}{{\left(\frac{1 - x}{2}\right)}^{\left(1 + 0.5\right)}}}\right) \]

      div-sub [=>]14.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\color{blue}{\left(\frac{1}{2} - \frac{x}{2}\right)}}^{\left(1 + 0.5\right)}}\right) \]

      metadata-eval [=>]14.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(\color{blue}{0.5} - \frac{x}{2}\right)}^{\left(1 + 0.5\right)}}\right) \]

      div-inv [=>]14.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(0.5 - \color{blue}{x \cdot \frac{1}{2}}\right)}^{\left(1 + 0.5\right)}}\right) \]

      metadata-eval [=>]14.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(0.5 - x \cdot \color{blue}{0.5}\right)}^{\left(1 + 0.5\right)}}\right) \]

      metadata-eval [=>]14.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(0.5 - x \cdot 0.5\right)}^{\color{blue}{1.5}}}\right) \]

    if -1.65000000000000007e-162 < x < 1.65000000000000007e-162

    1. Initial program 3.3%

      \[\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right) \]
    2. Taylor expanded in x around 0 3.3%

      \[\leadsto \frac{\pi}{2} - 2 \cdot \sin^{-1} \color{blue}{\left(\sqrt{0.5}\right)} \]
    3. Applied egg-rr7.0%

      \[\leadsto \frac{\pi}{2} - 2 \cdot \color{blue}{\left(\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right) - 1\right)} \]
      Step-by-step derivation

      [Start]3.3

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{0.5}\right) \]

      expm1-log1p-u [=>]3.3

      \[ \frac{\pi}{2} - 2 \cdot \color{blue}{\mathsf{expm1}\left(\mathsf{log1p}\left(\sin^{-1} \left(\sqrt{0.5}\right)\right)\right)} \]

      expm1-udef [=>]3.3

      \[ \frac{\pi}{2} - 2 \cdot \color{blue}{\left(e^{\mathsf{log1p}\left(\sin^{-1} \left(\sqrt{0.5}\right)\right)} - 1\right)} \]

      log1p-udef [=>]7.0

      \[ \frac{\pi}{2} - 2 \cdot \left(e^{\color{blue}{\log \left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right)}} - 1\right) \]

      add-exp-log [<=]7.0

      \[ \frac{\pi}{2} - 2 \cdot \left(\color{blue}{\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right)} - 1\right) \]

    if 1.65000000000000007e-162 < x

    1. Initial program 6.8%

      \[\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right) \]
    2. Applied egg-rr11.3%

      \[\leadsto \frac{\pi}{2} - 2 \cdot \sin^{-1} \color{blue}{\left(\frac{1}{\sqrt{\frac{2}{1 - x}}}\right)} \]
      Step-by-step derivation

      [Start]6.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right) \]

      clear-num [=>]6.8

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\color{blue}{\frac{1}{\frac{2}{1 - x}}}}\right) \]

      sqrt-div [=>]11.3

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \color{blue}{\left(\frac{\sqrt{1}}{\sqrt{\frac{2}{1 - x}}}\right)} \]

      metadata-eval [=>]11.3

      \[ \frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{\color{blue}{1}}{\sqrt{\frac{2}{1 - x}}}\right) \]
  3. Recombined 3 regimes into one program.
  4. Final simplification10.4%

    \[\leadsto \begin{array}{l} \mathbf{if}\;x \leq -1.65 \cdot 10^{-162}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt[3]{{\left(0.5 - 0.5 \cdot x\right)}^{1.5}}\right)\\ \mathbf{elif}\;x \leq 1.65 \cdot 10^{-162}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \left(\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right) + -1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{1}{\sqrt{\frac{2}{1 - x}}}\right)\\ \end{array} \]

Alternatives

Alternative 1
Accuracy8.2%
Cost26432
\[\frac{\pi}{2} + 2 \cdot \left(\cos^{-1} \left(\sqrt{0.5 - 0.5 \cdot x}\right) - \pi \cdot 0.5\right) \]
Alternative 2
Accuracy9.7%
Cost20232
\[\begin{array}{l} \mathbf{if}\;x \leq -1.65 \cdot 10^{-162}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right)\\ \mathbf{elif}\;x \leq 1.65 \cdot 10^{-162}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \left(\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right) + -1\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{1}{\sqrt{\frac{2}{1 - x}}}\right)\\ \end{array} \]
Alternative 3
Accuracy8.2%
Cost20105
\[\begin{array}{l} \mathbf{if}\;x \leq -2 \cdot 10^{-310} \lor \neg \left(x \leq 10^{-17}\right):\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{1}{\sqrt{2}}\right)\\ \end{array} \]
Alternative 4
Accuracy8.9%
Cost20105
\[\begin{array}{l} \mathbf{if}\;x \leq -1.65 \cdot 10^{-162} \lor \neg \left(x \leq 5.5 \cdot 10^{-17}\right):\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{\frac{1 - x}{2}}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \left(\left(1 + \sin^{-1} \left(\sqrt{0.5}\right)\right) + -1\right)\\ \end{array} \]
Alternative 5
Accuracy5.9%
Cost19844
\[\begin{array}{l} \mathbf{if}\;x \leq -2 \cdot 10^{-310}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{0.5}\right)\\ \mathbf{else}:\\ \;\;\;\;\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\frac{1}{\sqrt{2}}\right)\\ \end{array} \]
Alternative 6
Accuracy4.1%
Cost19584
\[\frac{\pi}{2} - 2 \cdot \sin^{-1} \left(\sqrt{0.5}\right) \]

Error

Reproduce?

herbie shell --seed 2023159 
(FPCore (x)
  :name "Ian Simplification"
  :precision binary64

  :herbie-target
  (asin x)

  (- (/ PI 2.0) (* 2.0 (asin (sqrt (/ (- 1.0 x) 2.0))))))