?

Average Accuracy: 48.9% → 50.3%
Time: 6.6s
Precision: binary64
Cost: 64

?

\[x \cdot e^{y \cdot y} \]
↓
\[x \]
(FPCore (x y) :precision binary64 (* x (exp (* y y))))
↓
(FPCore (x y) :precision binary64 x)
double code(double x, double y) {
	return x * exp((y * y));
}
↓
double code(double x, double y) {
	return x;
}

real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = x * exp((y * y))
end function
↓
real(8) function code(x, y)
    real(8), intent (in) :: x
    real(8), intent (in) :: y
    code = x
end function

public static double code(double x, double y) {
	return x * Math.exp((y * y));
}
↓
public static double code(double x, double y) {
	return x;
}

def code(x, y):
	return x * math.exp((y * y))
↓
def code(x, y):
	return x

function code(x, y)
	return Float64(x * exp(Float64(y * y)))
end
↓
function code(x, y)
	return x
end

function tmp = code(x, y)
	tmp = x * exp((y * y));
end
↓
function tmp = code(x, y)
	tmp = x;
end

code[x_, y_] := N[(x * N[Exp[N[(y * y), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]
↓
code[x_, y_] := x

x \cdot e^{y \cdot y}
↓
x

Error?

Try it out?

Your Program's Arguments

Results

Enter valid numbers for all inputs

Target

Original48.9%
Target48.9%
Herbie50.3%
\[x \cdot {\left(e^{y}\right)}^{y} \]

Derivation?

  1. Initial program 53.1%

    \[x \cdot e^{y \cdot y} \]

  2. Taylor expanded in y around 0 54.5%

    \[\leadsto \color{blue}{x} \]

  3. Final simplification54.5%

    \[\leadsto x \]

Reproduce?

herbie shell --seed 2023157 
(FPCore (x y)
  :name "Data.Number.Erf:$dmerfcx from erf-2.0.0.0"
  :precision binary64

  :herbie-target
  (* x (pow (exp y) y))

  (* x (exp (* y y))))