\[\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
\]
↓
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.1 \cdot 10^{+127}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{elif}\;b_2 \leq 9.2 \cdot 10^{-58}:\\
\;\;\;\;\frac{\sqrt{b_2 \cdot b_2 - a \cdot c} - b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;{\left(\mathsf{fma}\left(0.5, \frac{a}{b_2}, -2 \cdot \frac{b_2}{c}\right)\right)}^{-1}\\
\end{array}
\]
(FPCore (a b_2 c)
:precision binary64
(/ (+ (- b_2) (sqrt (- (* b_2 b_2) (* a c)))) a))
↓
(FPCore (a b_2 c)
:precision binary64
(if (<= b_2 -1.1e+127)
(* -2.0 (/ b_2 a))
(if (<= b_2 9.2e-58)
(/ (- (sqrt (- (* b_2 b_2) (* a c))) b_2) a)
(pow (fma 0.5 (/ a b_2) (* -2.0 (/ b_2 c))) -1.0))))double code(double a, double b_2, double c) {
return (-b_2 + sqrt(((b_2 * b_2) - (a * c)))) / a;
}
↓
double code(double a, double b_2, double c) {
double tmp;
if (b_2 <= -1.1e+127) {
tmp = -2.0 * (b_2 / a);
} else if (b_2 <= 9.2e-58) {
tmp = (sqrt(((b_2 * b_2) - (a * c))) - b_2) / a;
} else {
tmp = pow(fma(0.5, (a / b_2), (-2.0 * (b_2 / c))), -1.0);
}
return tmp;
}
function code(a, b_2, c)
return Float64(Float64(Float64(-b_2) + sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c)))) / a)
end
↓
function code(a, b_2, c)
tmp = 0.0
if (b_2 <= -1.1e+127)
tmp = Float64(-2.0 * Float64(b_2 / a));
elseif (b_2 <= 9.2e-58)
tmp = Float64(Float64(sqrt(Float64(Float64(b_2 * b_2) - Float64(a * c))) - b_2) / a);
else
tmp = fma(0.5, Float64(a / b_2), Float64(-2.0 * Float64(b_2 / c))) ^ -1.0;
end
return tmp
end
code[a_, b$95$2_, c_] := N[(N[((-b$95$2) + N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / a), $MachinePrecision]
↓
code[a_, b$95$2_, c_] := If[LessEqual[b$95$2, -1.1e+127], N[(-2.0 * N[(b$95$2 / a), $MachinePrecision]), $MachinePrecision], If[LessEqual[b$95$2, 9.2e-58], N[(N[(N[Sqrt[N[(N[(b$95$2 * b$95$2), $MachinePrecision] - N[(a * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] - b$95$2), $MachinePrecision] / a), $MachinePrecision], N[Power[N[(0.5 * N[(a / b$95$2), $MachinePrecision] + N[(-2.0 * N[(b$95$2 / c), $MachinePrecision]), $MachinePrecision]), $MachinePrecision], -1.0], $MachinePrecision]]]
\frac{\left(-b_2\right) + \sqrt{b_2 \cdot b_2 - a \cdot c}}{a}
↓
\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.1 \cdot 10^{+127}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{elif}\;b_2 \leq 9.2 \cdot 10^{-58}:\\
\;\;\;\;\frac{\sqrt{b_2 \cdot b_2 - a \cdot c} - b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;{\left(\mathsf{fma}\left(0.5, \frac{a}{b_2}, -2 \cdot \frac{b_2}{c}\right)\right)}^{-1}\\
\end{array}
Alternatives
| Alternative 1 |
|---|
| Accuracy | 77.4% |
|---|
| Cost | 7368 |
|---|
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -1.35 \cdot 10^{+127}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{elif}\;b_2 \leq 1.5 \cdot 10^{-57}:\\
\;\;\;\;\frac{\sqrt{b_2 \cdot b_2 - a \cdot c} - b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\end{array}
\]
| Alternative 2 |
|---|
| Accuracy | 72.7% |
|---|
| Cost | 7176 |
|---|
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -4.8 \cdot 10^{-78}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{elif}\;b_2 \leq 4.6 \cdot 10^{-57}:\\
\;\;\;\;\frac{\sqrt{c \cdot \left(-a\right)} - b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\end{array}
\]
| Alternative 3 |
|---|
| Accuracy | 35.9% |
|---|
| Cost | 452 |
|---|
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{0}{a}\\
\end{array}
\]
| Alternative 4 |
|---|
| Accuracy | 60.3% |
|---|
| Cost | 452 |
|---|
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq 3.6 \cdot 10^{-292}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;-0.5 \cdot \frac{c}{b_2}\\
\end{array}
\]
| Alternative 5 |
|---|
| Accuracy | 60.3% |
|---|
| Cost | 452 |
|---|
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq 4.5 \cdot 10^{-291}:\\
\;\;\;\;-2 \cdot \frac{b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{c \cdot -0.5}{b_2}\\
\end{array}
\]
| Alternative 6 |
|---|
| Accuracy | 15.3% |
|---|
| Cost | 388 |
|---|
\[\begin{array}{l}
\mathbf{if}\;b_2 \leq -5 \cdot 10^{-310}:\\
\;\;\;\;\frac{-b_2}{a}\\
\mathbf{else}:\\
\;\;\;\;\frac{0}{a}\\
\end{array}
\]
| Alternative 7 |
|---|
| Accuracy | 11.0% |
|---|
| Cost | 192 |
|---|
\[\frac{0}{a}
\]