\[\left(\left(1.1102230246251565 \cdot 10^{-16} < a \land a < 9007199254740992\right) \land \left(1.1102230246251565 \cdot 10^{-16} < b \land b < 9007199254740992\right)\right) \land \left(1.1102230246251565 \cdot 10^{-16} < c \land c < 9007199254740992\right)\]
Math FPCore C Julia Wolfram TeX \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\]
↓
\[\mathsf{fma}\left(-0.5625, \frac{{c}^{3}}{\frac{{b}^{5}}{a \cdot a}}, \mathsf{fma}\left(-0.16666666666666666, \frac{{\left(c \cdot a\right)}^{4}}{{b}^{7}} \cdot \frac{6.328125}{a}, \mathsf{fma}\left(-0.5, \frac{c}{b}, -0.375 \cdot \frac{c \cdot c}{\frac{{b}^{3}}{a}}\right)\right)\right)
\]
(FPCore (a b c)
:precision binary64
(/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a))) ↓
(FPCore (a b c)
:precision binary64
(fma
-0.5625
(/ (pow c 3.0) (/ (pow b 5.0) (* a a)))
(fma
-0.16666666666666666
(* (/ (pow (* c a) 4.0) (pow b 7.0)) (/ 6.328125 a))
(fma -0.5 (/ c b) (* -0.375 (/ (* c c) (/ (pow b 3.0) a))))))) double code(double a, double b, double c) {
return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
↓
double code(double a, double b, double c) {
return fma(-0.5625, (pow(c, 3.0) / (pow(b, 5.0) / (a * a))), fma(-0.16666666666666666, ((pow((c * a), 4.0) / pow(b, 7.0)) * (6.328125 / a)), fma(-0.5, (c / b), (-0.375 * ((c * c) / (pow(b, 3.0) / a))))));
}
function code(a, b, c)
return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
↓
function code(a, b, c)
return fma(-0.5625, Float64((c ^ 3.0) / Float64((b ^ 5.0) / Float64(a * a))), fma(-0.16666666666666666, Float64(Float64((Float64(c * a) ^ 4.0) / (b ^ 7.0)) * Float64(6.328125 / a)), fma(-0.5, Float64(c / b), Float64(-0.375 * Float64(Float64(c * c) / Float64((b ^ 3.0) / a))))))
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
↓
code[a_, b_, c_] := N[(-0.5625 * N[(N[Power[c, 3.0], $MachinePrecision] / N[(N[Power[b, 5.0], $MachinePrecision] / N[(a * a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision] + N[(-0.16666666666666666 * N[(N[(N[Power[N[(c * a), $MachinePrecision], 4.0], $MachinePrecision] / N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision] * N[(6.328125 / a), $MachinePrecision]), $MachinePrecision] + N[(-0.5 * N[(c / b), $MachinePrecision] + N[(-0.375 * N[(N[(c * c), $MachinePrecision] / N[(N[Power[b, 3.0], $MachinePrecision] / a), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
↓
\mathsf{fma}\left(-0.5625, \frac{{c}^{3}}{\frac{{b}^{5}}{a \cdot a}}, \mathsf{fma}\left(-0.16666666666666666, \frac{{\left(c \cdot a\right)}^{4}}{{b}^{7}} \cdot \frac{6.328125}{a}, \mathsf{fma}\left(-0.5, \frac{c}{b}, -0.375 \cdot \frac{c \cdot c}{\frac{{b}^{3}}{a}}\right)\right)\right)
Alternatives Alternative 1 Accuracy 95.5% Cost 47104
\[\mathsf{fma}\left(-0.5, \frac{c}{b}, \mathsf{fma}\left(-0.16666666666666666, \frac{{\left(c \cdot a\right)}^{4}}{{b}^{7}} \cdot \frac{6.328125}{a}, a \cdot \left(\frac{-0.375 \cdot \left(c \cdot c\right)}{{b}^{3}} + \frac{-0.5625 \cdot {c}^{3}}{\frac{{b}^{5}}{a}}\right)\right)\right)
\]
Alternative 2 Accuracy 93.9% Cost 27136
\[\mathsf{fma}\left(-0.5, \frac{c}{b}, a \cdot \left(\frac{-0.375 \cdot \left(c \cdot c\right)}{{b}^{3}} + \frac{-0.5625 \cdot {c}^{3}}{\frac{{b}^{5}}{a}}\right)\right)
\]
Alternative 3 Accuracy 89.6% Cost 26952
\[\begin{array}{l}
\mathbf{if}\;c \leq 54000000000000:\\
\;\;\;\;-0.375 \cdot \left(\left(c \cdot c\right) \cdot \left(a \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}\\
\mathbf{elif}\;c \leq 7.2 \cdot 10^{+15}:\\
\;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(3 \cdot a\right)} - b}{3 \cdot a}\\
\mathbf{else}:\\
\;\;\;\;{\left(\sqrt[3]{-0.3333333333333333 \cdot \mathsf{fma}\left(1.125, a \cdot \left(\left(c \cdot c\right) \cdot {b}^{-3}\right), \frac{c}{b} \cdot 1.5\right)}\right)}^{3}\\
\end{array}
\]
Alternative 4 Accuracy 89.7% Cost 14216
\[\begin{array}{l}
\mathbf{if}\;c \leq 54000000000000:\\
\;\;\;\;-0.375 \cdot \left(\left(c \cdot c\right) \cdot \left(a \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}\\
\mathbf{elif}\;c \leq 6.5 \cdot 10^{+15}:\\
\;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(3 \cdot a\right)} - b}{3 \cdot a}\\
\mathbf{else}:\\
\;\;\;\;-0.3333333333333333 \cdot \mathsf{fma}\left(1.125, \frac{a \cdot \left(c \cdot c\right)}{{b}^{3}}, \frac{1}{b \cdot \frac{0.6666666666666666}{c}}\right)\\
\end{array}
\]
Alternative 5 Accuracy 89.7% Cost 7880
\[\begin{array}{l}
\mathbf{if}\;c \leq 54000000000000:\\
\;\;\;\;-0.375 \cdot \left(\left(c \cdot c\right) \cdot \left(a \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}\\
\mathbf{elif}\;c \leq 6.5 \cdot 10^{+15}:\\
\;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(3 \cdot a\right)} - b}{3 \cdot a}\\
\mathbf{else}:\\
\;\;\;\;-0.3333333333333333 \cdot \mathsf{fma}\left(1.125, \frac{c \cdot c}{b} \cdot \frac{a}{b \cdot b}, \frac{c}{b} \cdot 1.5\right)\\
\end{array}
\]
Alternative 6 Accuracy 89.7% Cost 7689
\[\begin{array}{l}
\mathbf{if}\;c \leq 54000000000000 \lor \neg \left(c \leq 6.5 \cdot 10^{+15}\right):\\
\;\;\;\;-0.375 \cdot \left(\left(c \cdot c\right) \cdot \left(a \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}\\
\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{b \cdot b - 3 \cdot \left(c \cdot a\right)} - b}{3 \cdot a}\\
\end{array}
\]
Alternative 7 Accuracy 89.6% Cost 7689
\[\begin{array}{l}
\mathbf{if}\;c \leq 54000000000000 \lor \neg \left(c \leq 6.8 \cdot 10^{+15}\right):\\
\;\;\;\;-0.375 \cdot \left(\left(c \cdot c\right) \cdot \left(a \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}\\
\mathbf{else}:\\
\;\;\;\;\frac{\sqrt{b \cdot b - c \cdot \left(3 \cdot a\right)} - b}{3 \cdot a}\\
\end{array}
\]
Alternative 8 Accuracy 90.7% Cost 7424
\[-0.375 \cdot \left(\left(c \cdot c\right) \cdot \left(a \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}
\]
Alternative 9 Accuracy 10.2% Cost 320
\[-0.3333333333333333 \cdot \frac{b}{a}
\]
Alternative 10 Accuracy 80.9% Cost 320
\[c \cdot \frac{-0.5}{b}
\]
Alternative 11 Accuracy 81.1% Cost 320
\[\frac{c \cdot -0.5}{b}
\]