ABCF->ab-angle angle

Average Accuracy: 54.0% → 80.4%

Time: 23.1s

Precision: binary64

Cost: 26628

Math

\[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]

↓

\[\begin{array}{l} \mathbf{if}\;C \leq 1.5 \cdot 10^{-8}:\\ \;\;\;\;{\left(\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)} \cdot 0.005555555555555556\right)}^{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

FPCore

(FPCore (A B C)
 :precision binary64
 (*
  180.0
  (/
   (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0))))))
   PI)))

↓

(FPCore (A B C)
 :precision binary64
 (if (<= C 1.5e-8)
   (pow
    (* (/ PI (atan (/ (- (- C A) (hypot B (- A C))) B))) 0.005555555555555556)
    -1.0)
   (/ (atan (/ (* B -0.5) C)) (* PI 0.005555555555555556))))

C

double code(double A, double B, double C) {
	return 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((pow((A - C), 2.0) + pow(B, 2.0)))))) / ((double) M_PI));
}

↓

double code(double A, double B, double C) {
	double tmp;
	if (C <= 1.5e-8) {
		tmp = pow(((((double) M_PI) / atan((((C - A) - hypot(B, (A - C))) / B))) * 0.005555555555555556), -1.0);
	} else {
		tmp = atan(((B * -0.5) / C)) / (((double) M_PI) * 0.005555555555555556);
	}
	return tmp;
}

Java

public static double code(double A, double B, double C) {
	return 180.0 * (Math.atan(((1.0 / B) * ((C - A) - Math.sqrt((Math.pow((A - C), 2.0) + Math.pow(B, 2.0)))))) / Math.PI);
}

↓

public static double code(double A, double B, double C) {
	double tmp;
	if (C <= 1.5e-8) {
		tmp = Math.pow(((Math.PI / Math.atan((((C - A) - Math.hypot(B, (A - C))) / B))) * 0.005555555555555556), -1.0);
	} else {
		tmp = Math.atan(((B * -0.5) / C)) / (Math.PI * 0.005555555555555556);
	}
	return tmp;
}

Python

def code(A, B, C):
	return 180.0 * (math.atan(((1.0 / B) * ((C - A) - math.sqrt((math.pow((A - C), 2.0) + math.pow(B, 2.0)))))) / math.pi)

↓

def code(A, B, C):
	tmp = 0
	if C <= 1.5e-8:
		tmp = math.pow(((math.pi / math.atan((((C - A) - math.hypot(B, (A - C))) / B))) * 0.005555555555555556), -1.0)
	else:
		tmp = math.atan(((B * -0.5) / C)) / (math.pi * 0.005555555555555556)
	return tmp

Julia

function code(A, B, C)
	return Float64(180.0 * Float64(atan(Float64(Float64(1.0 / B) * Float64(Float64(C - A) - sqrt(Float64((Float64(A - C) ^ 2.0) + (B ^ 2.0)))))) / pi))
end

↓

function code(A, B, C)
	tmp = 0.0
	if (C <= 1.5e-8)
		tmp = Float64(Float64(pi / atan(Float64(Float64(Float64(C - A) - hypot(B, Float64(A - C))) / B))) * 0.005555555555555556) ^ -1.0;
	else
		tmp = Float64(atan(Float64(Float64(B * -0.5) / C)) / Float64(pi * 0.005555555555555556));
	end
	return tmp
end

MATLAB

function tmp = code(A, B, C)
	tmp = 180.0 * (atan(((1.0 / B) * ((C - A) - sqrt((((A - C) ^ 2.0) + (B ^ 2.0)))))) / pi);
end

↓

function tmp_2 = code(A, B, C)
	tmp = 0.0;
	if (C <= 1.5e-8)
		tmp = ((pi / atan((((C - A) - hypot(B, (A - C))) / B))) * 0.005555555555555556) ^ -1.0;
	else
		tmp = atan(((B * -0.5) / C)) / (pi * 0.005555555555555556);
	end
	tmp_2 = tmp;
end

Wolfram

code[A_, B_, C_] := N[(180.0 * N[(N[ArcTan[N[(N[(1.0 / B), $MachinePrecision] * N[(N[(C - A), $MachinePrecision] - N[Sqrt[N[(N[Power[N[(A - C), $MachinePrecision], 2.0], $MachinePrecision] + N[Power[B, 2.0], $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]], $MachinePrecision] / Pi), $MachinePrecision]), $MachinePrecision]

↓

code[A_, B_, C_] := If[LessEqual[C, 1.5e-8], N[Power[N[(N[(Pi / N[ArcTan[N[(N[(N[(C - A), $MachinePrecision] - N[Sqrt[B ^ 2 + N[(A - C), $MachinePrecision] ^ 2], $MachinePrecision]), $MachinePrecision] / B), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] * 0.005555555555555556), $MachinePrecision], -1.0], $MachinePrecision], N[(N[ArcTan[N[(N[(B * -0.5), $MachinePrecision] / C), $MachinePrecision]], $MachinePrecision] / N[(Pi * 0.005555555555555556), $MachinePrecision]), $MachinePrecision]]

Derivation

1. Split input into 2 regimes

2. if C < 1.49999999999999987e-8

   1. Initial program 63.4%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]

   2. Simplified 80.3%

      \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)} \]
      Proof

      [Start] 63.4	\[ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      associate-*r/ [=>] 63.4	\[ \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      associate-*l/ [<=] 63.4	\[ \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)} \]
      associate-*l/ [=>] 63.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)} \]
      *-lft-identity [=>] 63.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right) \]
      sub-neg [=>] 63.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) + \left(-\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{B}\right) \]
      associate-+l- [=>] 62.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{C - \left(A - \left(-\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}{B}\right) \]
      sub-neg [=>] 62.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \color{blue}{\left(A + \left(-\left(-\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\right)}}{B}\right) \]
      remove-double-neg [=>] 62.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)}{B}\right) \]
      +-commutative [=>] 62.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}\right)}{B}\right) \]
      unpow2 [=>] 62.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}\right)}{B}\right) \]
      unpow2 [=>] 62.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}\right)}{B}\right) \]
      hypot-def [=>] 80.3	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \color{blue}{\mathsf{hypot}\left(B, A - C\right)}\right)}{B}\right) \]

   3. Applied egg-rr 85.4%

      \[\leadsto \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}}} \]
      Proof

      [Start] 80.3	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right) \]
      associate-*l/ [=>] 80.3	\[ \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}{\pi}} \]
      associate-/l* [=>] 80.3	\[ \color{blue}{\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)}}} \]
      associate--r+ [=>] 85.4	\[ \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}}{B}\right)}} \]

   4. Applied egg-rr 85.4%

      \[\leadsto \color{blue}{{\left(\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)} \cdot 0.005555555555555556\right)}^{-1}} \]
      Proof

      [Start] 85.4	\[ \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}} \]
      clear-num [=>] 85.4	\[ \color{blue}{\frac{1}{\frac{\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{180}}} \]
      inv-pow [=>] 85.4	\[ \color{blue}{{\left(\frac{\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}}{180}\right)}^{-1}} \]
      div-inv [=>] 85.4	\[ {\color{blue}{\left(\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)} \cdot \frac{1}{180}\right)}}^{-1} \]
      metadata-eval [=>] 85.4	\[ {\left(\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)} \cdot \color{blue}{0.005555555555555556}\right)}^{-1} \]

   if 1.49999999999999987e-8 < C

   1. Initial program 25.4%

      \[180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]

   2. Simplified 54.6%

      \[\leadsto \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \mathsf{hypot}\left(B, A - C\right)\right)}{B}\right)} \]
      Proof

      [Start] 25.4	\[ 180 \cdot \frac{\tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi} \]
      associate-*r/ [=>] 25.4	\[ \color{blue}{\frac{180 \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}{\pi}} \]
      associate-*l/ [<=] 25.4	\[ \color{blue}{\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{1}{B} \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)} \]
      associate-*l/ [=>] 25.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\frac{1 \cdot \left(\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}{B}\right)} \]
      *-lft-identity [=>] 25.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) - \sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}}{B}\right) \]
      sub-neg [=>] 25.4	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{\left(C - A\right) + \left(-\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)}}{B}\right) \]
      associate-+l- [=>] 24.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\color{blue}{C - \left(A - \left(-\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)}}{B}\right) \]
      sub-neg [=>] 24.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \color{blue}{\left(A + \left(-\left(-\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}\right)\right)\right)}}{B}\right) \]
      remove-double-neg [=>] 24.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \color{blue}{\sqrt{{\left(A - C\right)}^{2} + {B}^{2}}}\right)}{B}\right) \]
      +-commutative [=>] 24.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \sqrt{\color{blue}{{B}^{2} + {\left(A - C\right)}^{2}}}\right)}{B}\right) \]
      unpow2 [=>] 24.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \sqrt{\color{blue}{B \cdot B} + {\left(A - C\right)}^{2}}\right)}{B}\right) \]
      unpow2 [=>] 24.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \sqrt{B \cdot B + \color{blue}{\left(A - C\right) \cdot \left(A - C\right)}}\right)}{B}\right) \]
      hypot-def [=>] 54.6	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \left(A + \color{blue}{\mathsf{hypot}\left(B, A - C\right)}\right)}{B}\right) \]

   3. Taylor expanded in C around inf 34.5%

      \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{\left({B}^{2} + {A}^{2}\right) - {\left(-1 \cdot A\right)}^{2}}{C \cdot B} + -1 \cdot \frac{A + -1 \cdot A}{B}\right)} \]

   4. Simplified 49.2%

      \[\leadsto \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, 0 \cdot \left(A - \left(-A\right)\right)\right)}{B \cdot C}, \frac{0}{B}\right)\right)} \]
      Proof

      [Start] 34.5	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(-0.5 \cdot \frac{\left({B}^{2} + {A}^{2}\right) - {\left(-1 \cdot A\right)}^{2}}{C \cdot B} + -1 \cdot \frac{A + -1 \cdot A}{B}\right) \]
      fma-def [=>] 34.5	\[ \frac{180}{\pi} \cdot \tan^{-1} \color{blue}{\left(\mathsf{fma}\left(-0.5, \frac{\left({B}^{2} + {A}^{2}\right) - {\left(-1 \cdot A\right)}^{2}}{C \cdot B}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right)} \]
      *-commutative [=>] 34.5	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\left({B}^{2} + {A}^{2}\right) - {\left(-1 \cdot A\right)}^{2}}{\color{blue}{B \cdot C}}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      associate--l+ [=>] 40.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{{B}^{2} + \left({A}^{2} - {\left(-1 \cdot A\right)}^{2}\right)}}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      unpow2 [=>] 40.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{B \cdot B} + \left({A}^{2} - {\left(-1 \cdot A\right)}^{2}\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      fma-def [=>] 40.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\color{blue}{\mathsf{fma}\left(B, B, {A}^{2} - {\left(-1 \cdot A\right)}^{2}\right)}}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      unpow2 [=>] 40.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, \color{blue}{A \cdot A} - {\left(-1 \cdot A\right)}^{2}\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      mul-1-neg [=>] 40.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, A \cdot A - {\color{blue}{\left(-A\right)}}^{2}\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      unpow2 [=>] 40.9	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, A \cdot A - \color{blue}{\left(-A\right) \cdot \left(-A\right)}\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      difference-of-squares [=>] 49.2	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, \color{blue}{\left(A + \left(-A\right)\right) \cdot \left(A - \left(-A\right)\right)}\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      mul-1-neg [<=] 49.2	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, \left(A + \color{blue}{-1 \cdot A}\right) \cdot \left(A - \left(-A\right)\right)\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      distribute-rgt1-in [=>] 49.2	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, \color{blue}{\left(\left(-1 + 1\right) \cdot A\right)} \cdot \left(A - \left(-A\right)\right)\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      metadata-eval [=>] 49.2	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, \left(\color{blue}{0} \cdot A\right) \cdot \left(A - \left(-A\right)\right)\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      mul0-lft [=>] 49.2	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, \color{blue}{0} \cdot \left(A - \left(-A\right)\right)\right)}{B \cdot C}, -1 \cdot \frac{A + -1 \cdot A}{B}\right)\right) \]
      associate-*r/ [=>] 49.2	\[ \frac{180}{\pi} \cdot \tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, 0 \cdot \left(A - \left(-A\right)\right)\right)}{B \cdot C}, \color{blue}{\frac{-1 \cdot \left(A + -1 \cdot A\right)}{B}}\right)\right) \]

   5. Taylor expanded in B around 0 49.2%

      \[\leadsto \color{blue}{180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, 0\right)}{C \cdot B}, 0\right)\right)}{\pi}} \]

   6. Simplified 64.9%

      \[\leadsto \color{blue}{\frac{\tan^{-1} \left(\frac{-0.5 \cdot B}{C}\right)}{\pi \cdot 0.005555555555555556}} \]
      Proof

      [Start] 49.2	\[ 180 \cdot \frac{\tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, 0\right)}{C \cdot B}, 0\right)\right)}{\pi} \]
      *-commutative [=>] 49.2	\[ \color{blue}{\frac{\tan^{-1} \left(\mathsf{fma}\left(-0.5, \frac{\mathsf{fma}\left(B, B, 0\right)}{C \cdot B}, 0\right)\right)}{\pi} \cdot 180} \]
      fma-udef [=>] 49.2	\[ \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{\mathsf{fma}\left(B, B, 0\right)}{C \cdot B} + 0\right)}}{\pi} \cdot 180 \]
      +-rgt-identity [=>] 49.2	\[ \frac{\tan^{-1} \color{blue}{\left(-0.5 \cdot \frac{\mathsf{fma}\left(B, B, 0\right)}{C \cdot B}\right)}}{\pi} \cdot 180 \]
      associate-/r* [=>] 54.4	\[ \frac{\tan^{-1} \left(-0.5 \cdot \color{blue}{\frac{\frac{\mathsf{fma}\left(B, B, 0\right)}{C}}{B}}\right)}{\pi} \cdot 180 \]
      associate-*r/ [=>] 54.3	\[ \frac{\tan^{-1} \color{blue}{\left(\frac{-0.5 \cdot \frac{\mathsf{fma}\left(B, B, 0\right)}{C}}{B}\right)}}{\pi} \cdot 180 \]
      fma-udef [=>] 54.3	\[ \frac{\tan^{-1} \left(\frac{-0.5 \cdot \frac{\color{blue}{B \cdot B + 0}}{C}}{B}\right)}{\pi} \cdot 180 \]
      +-rgt-identity [=>] 54.3	\[ \frac{\tan^{-1} \left(\frac{-0.5 \cdot \frac{\color{blue}{B \cdot B}}{C}}{B}\right)}{\pi} \cdot 180 \]
      associate-*r/ [<=] 59.0	\[ \frac{\tan^{-1} \left(\frac{-0.5 \cdot \color{blue}{\left(B \cdot \frac{B}{C}\right)}}{B}\right)}{\pi} \cdot 180 \]
      *-commutative [=>] 59.0	\[ \frac{\tan^{-1} \left(\frac{\color{blue}{\left(B \cdot \frac{B}{C}\right) \cdot -0.5}}{B}\right)}{\pi} \cdot 180 \]
      associate-*l/ [<=] 59.1	\[ \frac{\tan^{-1} \color{blue}{\left(\frac{B \cdot \frac{B}{C}}{B} \cdot -0.5\right)}}{\pi} \cdot 180 \]
      associate-*r/ [=>] 54.4	\[ \frac{\tan^{-1} \left(\frac{\color{blue}{\frac{B \cdot B}{C}}}{B} \cdot -0.5\right)}{\pi} \cdot 180 \]
      associate-/r* [<=] 49.2	\[ \frac{\tan^{-1} \left(\color{blue}{\frac{B \cdot B}{C \cdot B}} \cdot -0.5\right)}{\pi} \cdot 180 \]
      times-frac [=>] 64.8	\[ \frac{\tan^{-1} \left(\color{blue}{\left(\frac{B}{C} \cdot \frac{B}{B}\right)} \cdot -0.5\right)}{\pi} \cdot 180 \]
      metadata-eval [<=] 64.8	\[ \frac{\tan^{-1} \left(\left(\frac{B}{C} \cdot \frac{B}{B}\right) \cdot -0.5\right)}{\pi} \cdot \color{blue}{\frac{1}{0.005555555555555556}} \]

3. Recombined 2 regimes into one program.

4. Final simplification 80.4%

   \[\leadsto \begin{array}{l} \mathbf{if}\;C \leq 1.5 \cdot 10^{-8}:\\ \;\;\;\;{\left(\frac{\pi}{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)} \cdot 0.005555555555555556\right)}^{-1}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternatives

Alternative 1
Accuracy	80.4%
Cost	20164

\[\begin{array}{l} \mathbf{if}\;C \leq 1.5 \cdot 10^{-8}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - A\right) - \mathsf{hypot}\left(B, A - C\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 2
Accuracy	80.2%
Cost	20164

\[\begin{array}{l} \mathbf{if}\;C \leq 1.06 \cdot 10^{-19}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(\frac{\left(C - \mathsf{hypot}\left(B, A - C\right)\right) - A}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 3
Accuracy	76.6%
Cost	20104

\[\begin{array}{l} \mathbf{if}\;C \leq -7.6 \cdot 10^{-140}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)\\ \mathbf{elif}\;C \leq 5.1 \cdot 10^{-12}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{\left(-A\right) - \mathsf{hypot}\left(B, A\right)}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 4
Accuracy	75.7%
Cost	20040

\[\begin{array}{l} \mathbf{if}\;A \leq -6.2 \cdot 10^{+132}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)}{\pi}\\ \mathbf{elif}\;A \leq 1.3 \cdot 10^{+53}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - \mathsf{hypot}\left(B, C\right)}{B}\right)\\ \mathbf{else}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(-1 + \frac{C - A}{B}\right)}{\pi}\\ \end{array} \]

Alternative 5
Accuracy	54.8%
Cost	14368

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\ t_1 := \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C + B}{B}\right)}}\\ \mathbf{if}\;A \leq -3 \cdot 10^{+101}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)}{\pi}\\ \mathbf{elif}\;A \leq -1.02 \cdot 10^{-57}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;A \leq -3.9 \cdot 10^{-95}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\ \mathbf{elif}\;A \leq -1.4 \cdot 10^{-133}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \mathbf{elif}\;A \leq -1.7 \cdot 10^{-206}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;A \leq -1.6 \cdot 10^{-248}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq 6.7 \cdot 10^{-227}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;A \leq 2.85 \cdot 10^{-8}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \end{array} \]

Alternative 6
Accuracy	54.8%
Cost	14368

\[\begin{array}{l} t_0 := \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C + B}{B}\right)}}\\ t_1 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\ \mathbf{if}\;A \leq -3 \cdot 10^{+101}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)}{\pi}\\ \mathbf{elif}\;A \leq -1.08 \cdot 10^{-57}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq -5.2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}}{0.005555555555555556}\\ \mathbf{elif}\;A \leq -1.5 \cdot 10^{-133}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \mathbf{elif}\;A \leq -2 \cdot 10^{-208}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq -1.22 \cdot 10^{-248}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;A \leq 1.5 \cdot 10^{-223}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq 8.2 \cdot 10^{-9}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \end{array} \]

Alternative 7
Accuracy	54.8%
Cost	14368

\[\begin{array}{l} t_0 := \tan^{-1} \left(\frac{C + B}{B}\right)\\ t_1 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\ \mathbf{if}\;A \leq -3 \cdot 10^{+101}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{0.5}{\frac{A}{B}}\right)}{\pi}\\ \mathbf{elif}\;A \leq -1 \cdot 10^{-57}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq -8.2 \cdot 10^{-95}:\\ \;\;\;\;\frac{\frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}}{0.005555555555555556}\\ \mathbf{elif}\;A \leq -2 \cdot 10^{-134}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \mathbf{elif}\;A \leq -6.2 \cdot 10^{-201}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq -1.55 \cdot 10^{-248}:\\ \;\;\;\;\frac{180}{\frac{\pi}{t_0}}\\ \mathbf{elif}\;A \leq 1.8 \cdot 10^{-227}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;A \leq 3.4 \cdot 10^{-8}:\\ \;\;\;\;\frac{180}{\pi} \cdot t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \end{array} \]

Alternative 8
Accuracy	46.9%
Cost	14236

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{-0.5}{\frac{C}{B}}\right)\\ t_1 := \frac{180 \cdot \tan^{-1} 1}{\pi}\\ t_2 := 180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\ \mathbf{if}\;B \leq -9 \cdot 10^{+18}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;B \leq -1.95 \cdot 10^{-7}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;B \leq -4.5 \cdot 10^{-63}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;B \leq -3.55 \cdot 10^{-230}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;B \leq 2.5 \cdot 10^{-293}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;B \leq 9.5 \cdot 10^{-193}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;B \leq 3.8 \cdot 10^{-62}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \end{array} \]

Alternative 9
Accuracy	46.9%
Cost	14236

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{-0.5}{\frac{C}{B}}\right)\\ t_1 := \frac{180 \cdot \tan^{-1} 1}{\pi}\\ t_2 := 180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\ \mathbf{if}\;B \leq -1.5 \cdot 10^{+16}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;B \leq -1.35 \cdot 10^{-8}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;B \leq -6.8 \cdot 10^{-63}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;B \leq -9.6 \cdot 10^{-231}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;B \leq 2.4 \cdot 10^{-293}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;B \leq 1.2 \cdot 10^{-196}:\\ \;\;\;\;t_2\\ \mathbf{elif}\;B \leq 4.2 \cdot 10^{-64}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \end{array} \]

Alternative 10
Accuracy	52.6%
Cost	14104

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\ t_1 := \frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{if}\;C \leq -6.4 \cdot 10^{-140}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq -2.95 \cdot 10^{-266}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{A \cdot -2}{B}\right)\\ \mathbf{elif}\;C \leq 2.3 \cdot 10^{-304}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 4.8 \cdot 10^{-229}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;C \leq 8 \cdot 10^{-181}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 4.2 \cdot 10^{-51}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \end{array} \]

Alternative 11
Accuracy	52.7%
Cost	14104

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\ t_1 := \frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{if}\;C \leq -1.45 \cdot 10^{-142}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq -2.45 \cdot 10^{-267}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \mathbf{elif}\;C \leq 4.8 \cdot 10^{-305}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 8 \cdot 10^{-227}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;C \leq 3.9 \cdot 10^{-185}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 9.4 \cdot 10^{-49}:\\ \;\;\;\;t_1\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \end{array} \]

Alternative 12
Accuracy	53.5%
Cost	14104

\[\begin{array}{l} t_0 := \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C + B}{B}\right)}}\\ \mathbf{if}\;C \leq -5.4 \cdot 10^{-98}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{C - B}{B}\right)\\ \mathbf{elif}\;C \leq -3.3 \cdot 10^{-226}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq -5.9 \cdot 10^{-266}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \mathbf{elif}\;C \leq 3.8 \cdot 10^{-234}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 2.3 \cdot 10^{-180}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 3.5 \cdot 10^{-45}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \end{array} \]

Alternative 13
Accuracy	53.4%
Cost	14104

\[\begin{array}{l} t_0 := \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C + B}{B}\right)}}\\ \mathbf{if}\;C \leq -3.6 \cdot 10^{-111}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C - B}{B}\right)}}\\ \mathbf{elif}\;C \leq -1.02 \cdot 10^{-224}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq -2.4 \cdot 10^{-268}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \mathbf{elif}\;C \leq 4.8 \cdot 10^{-230}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 7.6 \cdot 10^{-188}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 1.55 \cdot 10^{-51}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \end{array} \]

Alternative 14
Accuracy	53.6%
Cost	14104

\[\begin{array}{l} t_0 := \frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C + B}{B}\right)}}\\ \mathbf{if}\;C \leq -2.1 \cdot 10^{-98}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C - B}{B}\right)}}\\ \mathbf{elif}\;C \leq -2.6 \cdot 10^{-225}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq -1 \cdot 10^{-265}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{A \cdot -2}{B}\right)}}\\ \mathbf{elif}\;C \leq 4.4 \cdot 10^{-234}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 2 \cdot 10^{-181}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \mathbf{elif}\;C \leq 7.5 \cdot 10^{-52}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 15
Accuracy	60.3%
Cost	14100

\[\begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(-1 + \frac{C - A}{B}\right)}{\pi}\\ \mathbf{if}\;C \leq -2.7 \cdot 10^{-111}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq -1.8 \cdot 10^{-175}:\\ \;\;\;\;\frac{180}{\frac{\pi}{\tan^{-1} \left(\frac{C + B}{B}\right)}}\\ \mathbf{elif}\;C \leq 4.4 \cdot 10^{-185}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 1.5 \cdot 10^{-145}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{elif}\;C \leq 2.4 \cdot 10^{-29}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 16
Accuracy	47.6%
Cost	13972

\[\begin{array}{l} t_0 := 180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\ \mathbf{if}\;A \leq -1.4 \cdot 10^{-101}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;A \leq -1.6 \cdot 10^{-143}:\\ \;\;\;\;\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right) \cdot \frac{180}{\pi}\\ \mathbf{elif}\;A \leq -4.4 \cdot 10^{-308}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;A \leq 8.2 \cdot 10^{-228}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \mathbf{elif}\;A \leq 5.5 \cdot 10^{-10}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180}{\pi} \cdot \tan^{-1} \left(\frac{A \cdot -2}{B}\right)\\ \end{array} \]

Alternative 17
Accuracy	61.4%
Cost	13968

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\left(C + B\right) - A}{B}\right)\\ t_1 := 180 \cdot \frac{\tan^{-1} \left(-1 + \frac{C - A}{B}\right)}{\pi}\\ \mathbf{if}\;C \leq -6 \cdot 10^{-108}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;C \leq 5 \cdot 10^{-234}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 6.9 \cdot 10^{-186}:\\ \;\;\;\;t_1\\ \mathbf{elif}\;C \leq 2.5 \cdot 10^{-41}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 18
Accuracy	61.4%
Cost	13968

\[\begin{array}{l} t_0 := \frac{180}{\pi} \cdot \tan^{-1} \left(\frac{\left(C + B\right) - A}{B}\right)\\ t_1 := \tan^{-1} \left(-1 + \frac{C - A}{B}\right)\\ \mathbf{if}\;C \leq -1.6 \cdot 10^{-103}:\\ \;\;\;\;\frac{180}{\frac{\pi}{t_1}}\\ \mathbf{elif}\;C \leq 2.5 \cdot 10^{-231}:\\ \;\;\;\;t_0\\ \mathbf{elif}\;C \leq 9 \cdot 10^{-185}:\\ \;\;\;\;180 \cdot \frac{t_1}{\pi}\\ \mathbf{elif}\;C \leq 3.9 \cdot 10^{-44}:\\ \;\;\;\;t_0\\ \mathbf{else}:\\ \;\;\;\;\frac{\tan^{-1} \left(\frac{B \cdot -0.5}{C}\right)}{\pi \cdot 0.005555555555555556}\\ \end{array} \]

Alternative 19
Accuracy	45.6%
Cost	13576

\[\begin{array}{l} \mathbf{if}\;B \leq -7 \cdot 10^{-63}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.55 \cdot 10^{-209}:\\ \;\;\;\;180 \cdot \frac{\tan^{-1} \left(0.5 \cdot \frac{B}{A}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \end{array} \]

Alternative 20
Accuracy	44.8%
Cost	13448

\[\begin{array}{l} \mathbf{if}\;B \leq -4.5 \cdot 10^{-230}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{elif}\;B \leq 1.15 \cdot 10^{-59}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} \left(\frac{0}{B}\right)}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \end{array} \]

Alternative 21
Accuracy	41.1%
Cost	13188

\[\begin{array}{l} \mathbf{if}\;B \leq -6 \cdot 10^{-299}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} 1}{\pi}\\ \mathbf{else}:\\ \;\;\;\;\frac{180 \cdot \tan^{-1} -1}{\pi}\\ \end{array} \]

Alternative 22
Accuracy	21.5%
Cost	13056

\[\frac{180 \cdot \tan^{-1} -1}{\pi} \]

Reproduce

herbie shell --seed 2023153 
(FPCore (A B C)
  :name "ABCF->ab-angle angle"
  :precision binary64
  (* 180.0 (/ (atan (* (/ 1.0 B) (- (- C A) (sqrt (+ (pow (- A C) 2.0) (pow B 2.0)))))) PI)))