\[\left(\left(4.930380657631324 \cdot 10^{-32} < a \land a < 2.028240960365167 \cdot 10^{+31}\right) \land \left(4.930380657631324 \cdot 10^{-32} < b \land b < 2.028240960365167 \cdot 10^{+31}\right)\right) \land \left(4.930380657631324 \cdot 10^{-32} < c \land c < 2.028240960365167 \cdot 10^{+31}\right)\]
Math FPCore C Julia Wolfram TeX \[\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
\]
↓
\[\mathsf{fma}\left(-0.5, \frac{c}{b}, \mathsf{fma}\left(-0.375, \frac{c}{{b}^{3}} \cdot \left(c \cdot a\right), \mathsf{fma}\left(-0.5625, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \frac{{\left(c \cdot a\right)}^{4} \cdot -1.0546875}{a \cdot {b}^{7}}\right)\right)\right)
\]
(FPCore (a b c)
:precision binary64
(/ (+ (- b) (sqrt (- (* b b) (* (* 3.0 a) c)))) (* 3.0 a))) ↓
(FPCore (a b c)
:precision binary64
(fma
-0.5
(/ c b)
(fma
-0.375
(* (/ c (pow b 3.0)) (* c a))
(fma
-0.5625
(* (/ (* a a) (pow b 5.0)) (pow c 3.0))
(/ (* (pow (* c a) 4.0) -1.0546875) (* a (pow b 7.0))))))) double code(double a, double b, double c) {
return (-b + sqrt(((b * b) - ((3.0 * a) * c)))) / (3.0 * a);
}
↓
double code(double a, double b, double c) {
return fma(-0.5, (c / b), fma(-0.375, ((c / pow(b, 3.0)) * (c * a)), fma(-0.5625, (((a * a) / pow(b, 5.0)) * pow(c, 3.0)), ((pow((c * a), 4.0) * -1.0546875) / (a * pow(b, 7.0))))));
}
function code(a, b, c)
return Float64(Float64(Float64(-b) + sqrt(Float64(Float64(b * b) - Float64(Float64(3.0 * a) * c)))) / Float64(3.0 * a))
end
↓
function code(a, b, c)
return fma(-0.5, Float64(c / b), fma(-0.375, Float64(Float64(c / (b ^ 3.0)) * Float64(c * a)), fma(-0.5625, Float64(Float64(Float64(a * a) / (b ^ 5.0)) * (c ^ 3.0)), Float64(Float64((Float64(c * a) ^ 4.0) * -1.0546875) / Float64(a * (b ^ 7.0))))))
end
code[a_, b_, c_] := N[(N[((-b) + N[Sqrt[N[(N[(b * b), $MachinePrecision] - N[(N[(3.0 * a), $MachinePrecision] * c), $MachinePrecision]), $MachinePrecision]], $MachinePrecision]), $MachinePrecision] / N[(3.0 * a), $MachinePrecision]), $MachinePrecision]
↓
code[a_, b_, c_] := N[(-0.5 * N[(c / b), $MachinePrecision] + N[(-0.375 * N[(N[(c / N[Power[b, 3.0], $MachinePrecision]), $MachinePrecision] * N[(c * a), $MachinePrecision]), $MachinePrecision] + N[(-0.5625 * N[(N[(N[(a * a), $MachinePrecision] / N[Power[b, 5.0], $MachinePrecision]), $MachinePrecision] * N[Power[c, 3.0], $MachinePrecision]), $MachinePrecision] + N[(N[(N[Power[N[(c * a), $MachinePrecision], 4.0], $MachinePrecision] * -1.0546875), $MachinePrecision] / N[(a * N[Power[b, 7.0], $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]), $MachinePrecision]
\frac{\left(-b\right) + \sqrt{b \cdot b - \left(3 \cdot a\right) \cdot c}}{3 \cdot a}
↓
\mathsf{fma}\left(-0.5, \frac{c}{b}, \mathsf{fma}\left(-0.375, \frac{c}{{b}^{3}} \cdot \left(c \cdot a\right), \mathsf{fma}\left(-0.5625, \frac{a \cdot a}{{b}^{5}} \cdot {c}^{3}, \frac{{\left(c \cdot a\right)}^{4} \cdot -1.0546875}{a \cdot {b}^{7}}\right)\right)\right)
Alternatives Alternative 1 Accuracy 97.9% Cost 40832
\[\mathsf{fma}\left(-0.5, \frac{c}{b}, a \cdot \left(\frac{c \cdot \left(c \cdot -0.375\right)}{{b}^{3}} + -0.5625 \cdot \left(a \cdot \left(\left(c \cdot c\right) \cdot \left(c \cdot {b}^{-5}\right)\right)\right)\right)\right) + \frac{-1.0546875 \cdot {c}^{4}}{{b}^{7}} \cdot {a}^{3}
\]
Alternative 2 Accuracy 97.8% Cost 21760
\[\frac{c}{b} \cdot \left(-0.5 + \frac{c}{b \cdot b} \cdot \left(-0.375 \cdot a\right)\right) + \left(a \cdot a\right) \cdot \left(-0.5625 \cdot \left(\left(c \cdot c\right) \cdot \left(c \cdot {b}^{-5}\right)\right) + \frac{-1.0546875 \cdot {c}^{4}}{\frac{{b}^{7}}{a}}\right)
\]
Alternative 3 Accuracy 97.1% Cost 20928
\[\mathsf{fma}\left(-0.5, \frac{c}{b}, a \cdot \left(\frac{c \cdot \left(c \cdot -0.375\right)}{{b}^{3}} + -0.5625 \cdot \left(a \cdot \left(\left(c \cdot c\right) \cdot \left(c \cdot {b}^{-5}\right)\right)\right)\right)\right)
\]
Alternative 4 Accuracy 97.0% Cost 14528
\[\frac{c}{b} \cdot \left(-0.5 + \frac{c}{b \cdot b} \cdot \left(-0.375 \cdot a\right)\right) + \frac{-0.5625 \cdot \left(\left(a \cdot a\right) \cdot {c}^{3}\right)}{{b}^{5}}
\]
Alternative 5 Accuracy 95.5% Cost 7424
\[\left(-0.375 \cdot a\right) \cdot \left(c \cdot \left(c \cdot {b}^{-3}\right)\right) + -0.5 \cdot \frac{c}{b}
\]
Alternative 6 Accuracy 95.5% Cost 960
\[\frac{c}{b} \cdot \left(-0.5 + \frac{c}{b \cdot b} \cdot \left(-0.375 \cdot a\right)\right)
\]
Alternative 7 Accuracy 90.4% Cost 320
\[c \cdot \frac{-0.5}{b}
\]
Alternative 8 Accuracy 90.7% Cost 320
\[\frac{-0.5 \cdot c}{b}
\]