?

Average Accuracy: 76.8% → 99.4%
Time: 4.5s
Precision: binary64
Cost: 13184

?

\[\tan^{-1} \left(N + 1\right) - \tan^{-1} N \]
\[\tan^{-1}_* \frac{1}{\mathsf{fma}\left(N, 1 + N, 1\right)} \]
(FPCore (N) :precision binary64 (- (atan (+ N 1.0)) (atan N)))
(FPCore (N) :precision binary64 (atan2 1.0 (fma N (+ 1.0 N) 1.0)))
double code(double N) {
	return atan((N + 1.0)) - atan(N);
}
double code(double N) {
	return atan2(1.0, fma(N, (1.0 + N), 1.0));
}
function code(N)
	return Float64(atan(Float64(N + 1.0)) - atan(N))
end
function code(N)
	return atan(1.0, fma(N, Float64(1.0 + N), 1.0))
end
code[N_] := N[(N[ArcTan[N[(N + 1.0), $MachinePrecision]], $MachinePrecision] - N[ArcTan[N], $MachinePrecision]), $MachinePrecision]
code[N_] := N[ArcTan[1.0 / N[(N * N[(1.0 + N), $MachinePrecision] + 1.0), $MachinePrecision]], $MachinePrecision]
\tan^{-1} \left(N + 1\right) - \tan^{-1} N
\tan^{-1}_* \frac{1}{\mathsf{fma}\left(N, 1 + N, 1\right)}

Error?

Target

Original76.8%
Target99.4%
Herbie99.4%
\[\tan^{-1} \left(\frac{1}{1 + N \cdot \left(N + 1\right)}\right) \]

Derivation?

  1. Initial program 76.8%

    \[\tan^{-1} \left(N + 1\right) - \tan^{-1} N \]
  2. Applied egg-rr78.5%

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{N + \left(1 - N\right)}{\mathsf{fma}\left(N, N + 1, 1\right)}} \]
    Proof

    [Start]76.8

    \[ \tan^{-1} \left(N + 1\right) - \tan^{-1} N \]

    diff-atan [=>]78.5

    \[ \color{blue}{\tan^{-1}_* \frac{\left(N + 1\right) - N}{1 + \left(N + 1\right) \cdot N}} \]

    associate--l+ [=>]78.5

    \[ \tan^{-1}_* \frac{\color{blue}{N + \left(1 - N\right)}}{1 + \left(N + 1\right) \cdot N} \]

    +-commutative [=>]78.5

    \[ \tan^{-1}_* \frac{N + \left(1 - N\right)}{\color{blue}{\left(N + 1\right) \cdot N + 1}} \]

    *-commutative [=>]78.5

    \[ \tan^{-1}_* \frac{N + \left(1 - N\right)}{\color{blue}{N \cdot \left(N + 1\right)} + 1} \]

    fma-def [=>]78.5

    \[ \tan^{-1}_* \frac{N + \left(1 - N\right)}{\color{blue}{\mathsf{fma}\left(N, N + 1, 1\right)}} \]
  3. Simplified99.4%

    \[\leadsto \color{blue}{\tan^{-1}_* \frac{1}{\mathsf{fma}\left(N, 1 + N, 1\right)}} \]
    Proof

    [Start]78.5

    \[ \tan^{-1}_* \frac{N + \left(1 - N\right)}{\mathsf{fma}\left(N, N + 1, 1\right)} \]

    +-commutative [=>]78.5

    \[ \tan^{-1}_* \frac{\color{blue}{\left(1 - N\right) + N}}{\mathsf{fma}\left(N, N + 1, 1\right)} \]

    associate-+l- [=>]99.4

    \[ \tan^{-1}_* \frac{\color{blue}{1 - \left(N - N\right)}}{\mathsf{fma}\left(N, N + 1, 1\right)} \]

    +-inverses [=>]99.4

    \[ \tan^{-1}_* \frac{1 - \color{blue}{0}}{\mathsf{fma}\left(N, N + 1, 1\right)} \]

    metadata-eval [=>]99.4

    \[ \tan^{-1}_* \frac{\color{blue}{1}}{\mathsf{fma}\left(N, N + 1, 1\right)} \]

    +-commutative [=>]99.4

    \[ \tan^{-1}_* \frac{1}{\mathsf{fma}\left(N, \color{blue}{1 + N}, 1\right)} \]
  4. Final simplification99.4%

    \[\leadsto \tan^{-1}_* \frac{1}{\mathsf{fma}\left(N, 1 + N, 1\right)} \]

Alternatives

Alternative 1
Accuracy76.8%
Cost13120
\[\tan^{-1} \left(1 + N\right) - \tan^{-1} N \]

Error

Reproduce?

herbie shell --seed 2023152 
(FPCore (N)
  :name "2atan (example 3.5)"
  :precision binary64

  :herbie-target
  (atan (/ 1.0 (+ 1.0 (* N (+ N 1.0)))))

  (- (atan (+ N 1.0)) (atan N)))